Answer:
correct option is C) 2.8
Step-by-step explanation:
given data
string vibrates form = 8 loops
in water loop formed = 10 loops
solution
we consider mass of stone = m
string length = l
frequency of tuning = f
volume = v
density of stone = [tex]\rho[/tex]
case (1)
when 8 loop form with 2 adjacent node is [tex]\frac{\lambda }{2}[/tex]
so here
[tex]l = \frac{8 \lambda _1}{2}[/tex] ..............1
[tex]l = 4 \lambda_1\\\\\lambda_1 = \frac{l}{4}[/tex]
and we know velocity is express as
velocity = frequency × wavelength .....................2
[tex]\sqrt{\frac{Tension}{mass\ per\ unit \length }}[/tex] = f × [tex]\lambda_1[/tex]
here tension = mg
so
[tex]\sqrt{\frac{mg}{\mu}}[/tex] = f × [tex]\lambda_1[/tex] ..........................3
and
case (2)
when 8 loop form with 2 adjacent node is [tex]\frac{\lambda }{2}[/tex]
[tex]l = \frac{10 \lambda _1}{2}[/tex] ..............4
[tex]l = 5 \lambda_1\\\\\lambda_1 = \frac{l}{5}[/tex]
when block is immersed
equilibrium eq will be
Tenion + force of buoyancy = mg
T + v × [tex]\rho[/tex] × g = mg
and
T = v × [tex]\rho[/tex] - v × [tex]\rho[/tex] × g
from equation 2
f × [tex]\lambda_2[/tex] = f × [tex]\frac{1}{5}[/tex]
[tex]\sqrt{\frac{v\rho _{stone} g - v\rho _{water} g}{\mu}} = f \times \frac{1}{5}[/tex] .......................5
now we divide eq 5 by the eq 3
[tex]\sqrt{\frac{vg (\rho _{stone} - \rho _{water})}{\mu vg \times \rho _{stone}}} = \frac{fl}{5} \times \frac{4}{fl}[/tex]
solve irt we get
[tex]1 - \frac{\rho _{stone}}{\rho _{water}} = \frac{16}{25}[/tex]
so
relative density [tex]\frac{\rho _{stone}}{\rho _{water}} = \frac{25}{9}[/tex]
relative density = 2.78 ≈ 2.8
so correct option is C) 2.8
Adding Fractions: What is 9/8 + 5/6? I would like an explanation for mebecause I am confused about this problem, it will be nice if someone explained it to me. Thanks!
Answer:
4/3
Step-by-step explanation:
just do the lcm of denomination and after that start solving
9514 1404 393
Answer:
1 23/24
Step-by-step explanation:
Fractions can be added when they have the same denominator. Then the addition is performed by adding the numerators, and expressing the sum over the common denominator.
Here, your fractions have denominators of 8 and 6. Usually, we want to find a "least common denominator" to use to express the fractions. There are various ways to find that value. One of the easiest is to consult your memory of multiplication tables to find the smallest number that both a multiple of 8 and a multiple of 6. That number is 24.
An equivalent fraction is one that has the same value, but a different denominator than the one it is being compared to. Equivalent fractions can be made by multiplying by "1" in the form of "a/a" where "a" is any non-zero value. Here, it is useful to multiply 9/8 by 3/3 to make the equivalent fraction 27/24, which has a denominator of 24.
Similarly, we can multiply 5/6 by 4/4 to get the equivalent 20/24, which also has a denominator of 24.
These two fractions can now be added:
[tex]\dfrac{9}{8}+\dfrac{5}{6}=\dfrac{27}{24}+\dfrac{20}{24}=\dfrac{27+20}{24}=\dfrac{47}{24}[/tex]
If you want to turn this into a "mixed number", you need to find how many times 24 goes into 47: 47÷24 = 1 remainder 23. The quotient is the integer part of the mixed number; the remainder is the numerator of the fractional part. Then the mixed number value of the sum is ...
[tex]\dfrac{47}{24}=1\dfrac{23}{24}[/tex]
_____
Additional comments
The product of the denominators can always serve as a common denominator. That may not be the "least" common denominator. If you use that here, you would have ...
[tex]\dfrac{9}{8}+\dfrac{5}{6}=\left(\dfrac{9}{8}\cdot\dfrac{6}{6}\right)+\left(\dfrac{5}{6}\cdot\dfrac{8}{8}\right)=\dfrac{54+40}{48}=\dfrac{94}{48}[/tex]
This result can be reduced by removing a factor of 2 from numerator and denominator to give 47/24, the sum we had above.
The "least common denominator" (LCD) is the Least Common Multiple (LCM) of the denominators. It can be found by forming the product of the unique factors of the denominators. Here, we have 8 = 2·2·2 and 6 = 2·3. The LCD is the product 2·2·2·3. We recognize that 2³ and 3 are unique factors that need to contribute to the LCD. 2 is subsumed by 2³.
As you can see from the factoring, 2 is a common factor of both numbers. Another way to find the LCD (or LCM of the denominators) is to form their product (8×6 = 48) and divide that by the greatest common factor (GCF), which is 2. (48/2 = 24, the LCD) Sometimes it is easier to find the GCF and compute (product/GCF) than to find the LCM using factoring.
__
If you don't mind the possibility of having to reduce the resulting fraction, the sum of fractions can always be computed as ...
[tex]\dfrac{a}{b}+\dfrac{c}{d}=\dfrac{ad+bc}{bd}[/tex]
This formula computes 94/48 as the sum of these fractions, effectively leaving out the middle step (9/8×6/6 +...) shown in the work above. I find this especially useful for adding rational expressions, not just numerical fractions.
What is the equation of the line?
The line cuts the X axis at [tex]x=3[/tex] and is parallel to the Y axis.
Thus the equation of the line is $\boxed{x=3}$
Answer:
The equation of the line is x = 3.
Step-by-step explanation:
When a line is parallel to the y-axis, its gradient will be undefined. There is no y-intercept and the line touches x-axis so the equation is x = 3.
Answer two questions about Equations A and B:
A. 2x-1=5x
B. -1=3x
1) How can we get Equation B from Equation A?
Choose 1 answer:
Add/subtract the same quantity to/from both sides
Add/subtract a quantity to/from only one side
Rewrite one side (or both) by
combining like terms
Rewrite one side (or both) using the distributive property
NEXT QUESTION
based on the previous answer, are the equations equivalent? In other words, do they have the same solution?
A. Yes
B. No
Answer:
B: Add/subtract the same quantity to/from both sides
Next Question: Yes
Step-by-step explanation:
thats what the answer is dunno what else to tell you lol
Algebraic equations are mathematical equations that contain unknown variables.
To get Equation B from Equation A, we add/subtract the same quantity to/from both sides. Option A is the correct option. Equation A is equivalent to Equation BQuestion 1: We are given equation A as:2x - 1 = 5x .............Equation A
To get Equation B from A, we would subtract 2x from both sides of the equation.
2x - 2x - 1 = 5x - 2x
- 1 = 3x This is Equation B
Question 2: Based on the previous answer,2x - 1 = 5x is equal to -1 = 3x.
Hence, both Equation A and Equation B are equivalent expressions.
Therefore,
To get Equation B from Equation A, we add/subtract the same quantity to/from both sides. Option A is the correct option.Equation A is equivalent to Equation BTo learn more, visit the link below:
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The numbers of words defined on randomly selected pages from a dictionary are shown below. Find the mean, median, mode of the listed numbers. 72 58 62 38 44 66 42 49 76 52 What is the mean? Select the correct choice below and ,if necessary ,fill in the answer box within your choice.(around to one decimal place as needed)
Answer:
Mean: 55.9
Median: 55
Mode: None
Step-by-step explanation:
First, find the mean by dividing the sum by the number of elements:
(72 + 58 + 62 + 38 + 44 + 66 + 42 + 49 + 76 + 52) / 10
= 55.9
Next, find the median by putting the numbers in order and finding the middle one:
38, 42, 44, 49, 52, 58, 62, 66, 72, 76
There is no middle number, so we will take the average of 52 and 58, which is 55.
Lastly, to find the mode, we have to find the number that occurs the most.
All of the numbers occur one time, so there is no mode.
A chemical company makes two brands of antifreeze. The first brand is
55%
pure antifreeze, and the second brand is
80%
pure antifreeze. In order to obtain
130
gallons of a mixture that contains
70%
pure antifreeze, how many gallons of each brand of antifreeze must be used?
9514 1404 393
Answer:
52 gallons of 55%78 gallons of 80%Step-by-step explanation:
Let x represent the quantity of 80% solution. Then the quantity of 55% solution is (130-x) and the total amount of antifreeze in the mix is ...
0.55(130 -x) +0.80(x) = 0.70(130)
0.25x +71.5 = 91 . . . simplify
0.25x = 19.5 . . . . . . subtract 71.5
x = 78 . . . . . . . . . . . divide by 0.25; amount of 80%
130-78 = 52 . . . . amount of 55%
52 gallons of the 55% brand, and 78 gallons of the 80% brand must be used.
What is the area of a parallelogram if the coordinates of its vertices are (0, -2), (3,2), (8,2), and (5, -2)?
Answer: 20 sq. units .
Step-by-step explanation:
Let A(0, -2), B(3,2), C(8,2), and D(5, -2) are the points for the parallelogram.
First we plot these points on coordinate plane, we get parallelogram ABCD.
By comparing the y-coordinate of B and C with A and D , we get
height = 2+2 = 4 units
Also by comparing the x coordinates of A and D, we get base = 5-0= 5 units
Area of parallelogram = Base x height
= 5 x 4 = 20 sq. units
Hence, the area of a parallelogram ABCD is 20 sq. units .
Jamal and Sean plan to make T-shirts to sell at a fair. Jamal plans to make 6 T-shirts
each day and Sean plans to make 4 T-shirts each day. On which day will Jamal have
made 12 more T-shirts than Sean?
Answer:
Jamal will have made 12 more T-shirts than Sean on the 6th day.
Step-by-step explanation:
1 day for Jamal - 6 T-shirts. 1 day for Sean - 4 T-shirts. 2 day for Jamal - 12 T-shirts. 2 day for Sean - 8 T-shirts. 3 day for Jamal - 18 T-shirts. 3 day for Sean - 12 T-shirts. 4 day for Jamal - 24 T-shirts. 4 day for Sean - 16 T-shirts. 5 day for Jamal - 30 T-shirts. 5 day for Sean - 20 T-shirts. 6 day for Jamal - 36 T-shirts. 6 day for Sean - 24 T-shirts. Number between 24 and 36 = 12.
The number line shows the record low temperatures for four states.. what is the difference, between the low temperature in Hawaii and the low temperatures In south Dakota
A -70°F
B -46°F
C 46°F
D 70°F
Answer:
D 70°F
Step-by-step explanation:
Difference between temperature in Hawaii and in South Dakota is 12°F - (-58°F) = 12°F + 58°F = 70 °F
Using the identity. (a - b) ²= (a² - 2ab + b²), evaluate 699²
Step-by-step explanation:
hope it helps you.......
[tex]\\ \sf\longmapsto 699^2[/tex]
[tex]\\ \sf\longmapsto (700-1)^2[/tex]
[tex]\\ \sf\longmapsto 700^2-2(700(1)+(1)^2[/tex]
[tex]\\ \sf\longmapsto 490000-1400+1[/tex]
[tex]\\ \sf\longmapsto 488600+1[/tex]
[tex]\\ \sf\longmapsto 488601[/tex]
What is the x-value of point A?
━━━━━━━☆☆━━━━━━━
▹ Answer
x = 5
▹ Step-by-Step Explanation
The x-axis and y-axis are labeled on the graph. The x-axis is the horizontal axis. Between 4 and 6, there is a missing number. That number should be 5, leaving us with an x-value of 5 for Point A.
Hope this helps!
CloutAnswers ❁
━━━━━━━☆☆━━━━━━━
Answer:
The x value is 5
Step-by-step explanation:
The x value is the value going across
Starting where the two axis meet, we go 5 units to the right
That is the x value
List the sides of ΔRST in ascending order (shortest to longest). m∠R=2x+11°, m∠S=3x+23°, and m∠T=x+42°
Answer:
ST, RS, RT
Step-by-step explanation:
Angles of a triangle add up to 180°.
2x + 11° + 3x + 23° + x + 42° = 180°
6x + 76° = 180°
x = 17⅓
m∠R = 2x+11° = 45⅔°
m∠S = 3x+23° = 75°
m∠T = x+42° = 59⅓°
The shortest side is opposite the smallest angle, and the longest side is opposite the largest angle.
ST, RS, RT
Determine the type of sampling used. A De Anza English instructor randomly selects three EWRT 1A classes and then interviews all students in those three classes to determine the average number of required books for EWRT 1A classes carried by EWRT 1A students at De-Anza College.
this is a random sample because the instructor randomly selected the classes that she wants to use for her interview.
The sampling method used is random sample.
What are sampling methods?To reach substantial inferences from your outcomes, you need to painstakingly conclude how you will choose an example that is illustrative of the gathering in general. A sampling method is the name for this. You can use one of two primary types of sampling methods in your research:
By using random selection in probability sampling, you can draw solid statistical inferences about the entire group.
You can easily collect data with non-probability sampling, which uses non-random selection based on convenience or other criteria.
Given English instructor randomly select 3 classes,
and then interviews all students in those three classes to determine the average number,
Every member of the population has the same chance of being chosen in a straightforward random sample. The entire population should be included in your sampling frame.
You can use techniques that are entirely based on chance or tools like random number generators to carry out this kind of sampling.
The method used is Random sample method.
Hence, Random sample sampling is used.
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What is the difference? Complete the equation. -1 2/5 - (-4/5) = ?
Answer:
First convert them which will be
-7/5 - (-4/5)
so when you subtract a negative number from negative number they actually subtract ex = -4-(-2) = -2
so its simply 7/5-4/5 then add a negative sign
so
3/5
now add negative sign so
-3/5
When two resistors with resistances of A ohms and
B ohms are in a parallel-series circuit, the total
resistance, R, in ohms, is given by the equation above.
According to this equation, which of the following
resistances of the two resistors would yield the greatest
total resistance?
A) 1 ohm and 1 ohm
B) 1 ohm and 2 ohms
C) 1 ohm and 4 ohms
D) 2 ohms and 2 ohms
Step-by-step explanation:
Answer: D) 2 ohms and 2 ohms
If 30 percent of the people surveyed use both of the methods "exercise near home or work" and "exercise outdoors", what percent of people surveyed use at least one of the two methods?
A 26%
B 52%
C 56%
D 74%
E 86%
A. 26%
There are 30% people who use both methods, Exercise near home or work and Exercise outdoor.
There are 46% people who prefer exercise near home or office rather than outdoor.
There are 40% people who prefer exercise outdoor rather than near home or office.
Then there are 30% people among them who use both methods. The remaining 26% people use one of the method.
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What is the equation of a circle with center (-4,7) and a radius 6
Answer:
( x +4)^2 + ( y-7)^2 = 36
Step-by-step explanation:
We can write the equation of a circle as
( x-h)^2 + ( y-k)^2 = r^2
where ( h,k) is the center and r is the radius
( x- -4)^2 + ( y-7)^2 = 6^2
( x +4)^2 + ( y-7)^2 = 36
Answer:
(x+4)[superscript]2 + (y-7)[superscript]2 = 36
solve for x: -3(x + 1)= -3(x + 1) - 5
Answer:
No solution : 0= -5Step-by-step explanation:
[tex]-3\left(x+1\right)=-3\left(x+1\right)-5\\\\\mathrm{Add\:}3\left(x+1\right)\mathrm{\:to\:both\:sides}\\\\-3\left(x+1\right)+3\left(x+1\right)=-3\left(x+1\right)-5+3\left(x+1\right)\\\\\mathrm{Simplify}\\\\0=-5\\\\\mathrm{The\:sides\:are\:not\:equal}\\\\\mathrm{No\:Solution}[/tex]
7 (w+8) = 2w+10
What is the value of w makes the equation true? Enter the answer in the box.
Test.mapnwea.org.
Answer:
w = -46/5
Step-by-step explanation:
Answer:
w=-9.2
Step-by-step explanation:
7(w+8)=2w+10
7w+56=2w+10
7w-2w=10-56
5w=-46
w=-9.2
Venn diagrams: unions, intersections, and complements
Attached is the photo reference
Answer:
a) 0
b) 2,3,4,5,6,7
c)3,4,6,7
Step-by-step explanation:
I need help with this I will appreciate if I get an answer for this problem
Answer:
what's the problem!?......
angle CDT is the opposite angle of ADN
and the segment DF=FN, so AD= AN
and thats why angle FAN= angle FAD
here, Angle FAN =60,
therefore, FAD=60, and AFD = 90 so angle ADN must be 30 degree
and the opposite of ADN is CDT, and the opposite angles are equal.
Hope u got it.
Evaluate the double integral ∬Ry2x2+y2dA, where R is the region that lies between the circles x2+y2=16 and x2+y2=121, by changing to polar coordinates.
Answer:
See answer and graph below
Step-by-step explanation:
∬Ry2x2+y2dA
=∫Ry.2x.2+y.2dA
=A(2y+4Ryx)+c
=∫Ry.2x.2+y.2dA
Integral of a constant ∫pdx=px
=(2x+2.2Ryx)A
=A(2y+4Ryx)
=A(2y+4Ryx)+c
The graph of y=A(2y+4Ryx)+c assuming A=1 and c=2
The evaluation of the double integral is [tex]\mathbf{ \dfrac{105}{2}\pi }[/tex]
The double integral [tex]\mathbf{\int \int _R\ \dfrac{y^2}{x^2+y^2} \ dA}[/tex], where R is the region that lies between
the circles [tex]\mathbf{x^2 +y^2 = 16 \ and \ x^2 + y^2 = 121}[/tex].
Let consider x = rcosθ and y = rsinθ because x² + y² = r²;
Now, the double integral can be written in polar coordinates as:
[tex]\mathbf{\implies \int \int _R\ \dfrac{y^2}{x^2+y^2} \ dxdy}[/tex]
[tex]\mathbf{\implies \int \int _R\ \dfrac{r^2 \ sin^2 \theta}{r^2} \ rdrd\theta}[/tex]
[tex]\mathbf{\implies \int \int _R\ \ sin^2 \theta \ r \ drd\theta}[/tex]
Thus, the integral becomes:
[tex]\mathbf{=\int^{2 \pi}_{0} sin^2 \theta d\theta \int ^{11}_{4} rdr }[/tex]
since 2sin² = 1 - cos2θ∴
[tex]\mathbf{=\int^{2 \pi}_{0} \dfrac{1-cos 2 \theta }{2} \ \theta \ d\theta\dfrac{r}{2} \Big|^{11}_{4}dr }[/tex]
[tex]\mathbf{\implies \dfrac{1}{2} \Big[\theta - \dfrac{sin \ 2 \theta}{2}\Big]^{2 \pi}_{0} \ \times\Big[ \dfrac{11^2-4^2}{2}\Big]}[/tex]
[tex]\mathbf{\implies \dfrac{\pi}{2} \times\Big[ 121-16\Big]}[/tex]
[tex]\mathbf{\implies \dfrac{105}{2}\pi }[/tex]
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What is the answer, what are the steps to solve this, and what do the parts of the equation represent?
Step-by-step explanation:
Just sub 4 into where n is
GIVING OUT BRAINLIEST TO THE FIRST PERSON TO ANSWER!!
One circle has a diameter of 6 inches. A second, larger circle has a diameter that is four times the diameter of the first circle. What is the ratio of the area of the smaller circle to the larger circle?
A. 2:3
B. 1:6:4
C. 1:16
D. 1:64
Please include ALL work! <3
Answer:
The answer is option CStep-by-step explanation:
To find the ratio first find the diameter of the larger circle
Diameter of first circle = 6 inches
Diameter of second circle = 4 × diameter of the first circle
Which is
Diameter of second circle
= 4 × 6 = 24 inches
Area of a circle = πr²
r is the radius
Area of smaller circle
Diameter = 6 inches
Radius = 6 / 2 = 3 inches
Area = (3)² π = 9π in²
Area of larger circle
Diameter = 24 inches
Radius = 24 / 2 = 12 inches
Area = (12)²π = 144π in²
The ratio of the smaller circle to the larger circle is
[tex] \frac{9\pi}{144\pi} [/tex]
Reduce the fraction by 9π
That's
[tex] \frac{1}{16} [/tex]
We have the final answer as
1 : 16Hope this helps you
Answer:
C. 1:16
Step-by-step explanation:
Area of a circle is:
[tex]\pi \times {r}^{2} [/tex]
Small circle Area:
radius = diameter/2
radius = 6/2 = 3
[tex]area \: of \: a \: circle \: = \pi {3}^{2} [/tex]
a = 28.27
Large circle 4 times larger diameter
6*4 = 24
diameter = 24
r = 24/2
r = 12
[tex]a \: = \pi {12}^{2} [/tex]
a = 452.39
area of large circle/ area of small circle
452.39/28.27 = 16.00
ratio is 1:16
Answer the question you hopeless heathens
Monico recently hired a roofer to do some necessary work. On the final bill, Monico was charged a total of $605. The amount listed for parts was $285 and the rest of the bill was for labor. If the hourly rate for labor was $64, how many hours of labor was needed to complete the job?
(A) First write an equation you can use to answer this question. Use x as your variable. The equation is ___________________
(B) Solve your equation in part (A) to find the number of labor hours needed to do the job. Answer: The number of labor hours was ________________
Answer:
A) 64x + 285 = 605
B) 5 hours
Step-by-step explanation:
64x + 285 = 605
64x + 285-285 = 605 - 285
64x = 320
64x/64 = 320/64
x = 5
Double check
($605 Total - $285 parts) / $64 Hourly rate = Labor per hour
$320 Labor / $64 Hour = 5 hours
or 64x
A baseball player's batting average is equal to the number of hits divided by the number of at-bats.
[tex]\frac{hits}{at-bats}[/tex]
A professional player had 123 hits and 501 at-bats in 2010. In 2011, he had 131 hits and 515 at-bats. How many more consecutive hits would he have needed in order to raise his 2010 batting average to that of 2011?
he would need about 5 more hits to make his average equal to that in 2021
128/501 = .255
The player needs 5 consecutive hits in order to raise his 2010 batting average to that of 2011.
What is average ?An average of a list of data is the expression of the central value of a set of data. It is also defined as the ratio of summation of all the data to the number of units present in the list.
How to find the number of hits in order to raise the batting average ?It is given that a professional player had 123 hits and 501 at-bats in 2010 and in 2011, he had 131 hits and 515 at-bats.
Also, the baseball player's batting average is equal to the number of hits divided by the number of at-bats.
Average in 2010 - 123/501 = 0.245 .
Average in 2011 - 131/515 = 0.254 .
Thus if he increases the number of shots to 5 then we have the total number of shots as 123 + 5 = 128 .
Therefore the batting average for 2010 becomes - 128/501 = 0.255 which matches the batting average of 2011.
Thus, the player needs 5 consecutive hits in order to raise his 2010 batting average to that of 2011.
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if it can be assumed that the population is normal, then what is the probability that one man sampled from this population has a weight between 72kg and 88kg
Answer:
The probability that one man sampled from this population has a weight between 72kg and 88kg is 0.6826.
Step-by-step explanation:
The complete question has the data of mean = 80 kg and standard deviation = 8kg
We have to find the probability between 72 kg and 88 kg
Since it is a normal distribution
(x`- u1 / σ/ √n) < Z >( x`- u2 / σ/ √n)
P (72 <x>88) = P ( 72-80/8/√1) <Z > ( 88-80/8/√1)
= P (-1<Z> 1) = 1- P (Z<1) - P (Z<-1)
= 1- 0.8413- (- 0.8413)= 1- 1.6826= 0.6826
So the probability that one man sampled from this population has a weight between 72kg and 88kg is 0.6826.
Which one of the following graphs is the graph of f(x) = 1∕4x2 + 3?
Answer:
A
f(x) = 1/4 x^2 + 3
Resultado
f(x) = x^2/4 + 3
x^2 + 12 = 4 f(x)
Forma alternativa
f(x) = 1/4 (x^2 + 12)
Raíces complejas
x = -2 i sqrt(3)
x = 2 i sqrt(3)
Can you please me with the word problem thank you so much
Answer:
4. 53
5. 66
6. 89
7. 31
Step-by-step explanation:
4. 14 + 18 + 21
^ ^
33 + 21
53
5. 86 - 20
66
6. 34 + 55
89
7. 14 + 11 + 6
^ ^
25 + 6
31
Find the values of x which satisfy the following inequation:
x3 – x² <12x
Answer:
x< -3 and 0 < x < 4
Step-by-step explanation:
x^3 – x² <12x
Subtract 12x from each side
x^3 -x^2 - 12x< 0
Factor
x( x^2 -x-12) <0
Factor
x( x-4) ( x+3) < 0
Using the zero product property
x=0 x=4 x=-3
We have to check the signs regions
x < -3
-( -) (-) < 0 True
-3 to 0
-( -) (+) < 0 False
0 to 4
+( -) (+) < 0 True
x>4
+( +) (+) < 0 False
The regions this is valid is
x< -3 and 0 < x < 4
The length and width of a rectangle are measured as 58 cm and 45 cm, respectively, with an error in measurement of at most 0.1 cm in each. Use differentials to estimate the maximum error in the calculated area of the rectangle.
Answer:
Error in calculated area = [tex]\pm 10.3 cm^2[/tex]
Step-by-step explanation:
x = 58 cm
y = 45 cm
A = x*y
delta A
= delta (x*y)
= y delta x + x delta y (neglecting small qty delta x * delta y = 0.01)
= 45(0.1) + 58(0.1)
= 103(0.1)
= 10.3 cm^2