a student walks 40 meters along a hallway that heads due north, then turns and walks 30 meters along another hallway that heads due east. what is the magnitude of the student's resultant displacement?
Answers
The magnitude of the student's resultant displacement is 50 m.
To find the magnitude of displacement we must make all the paths.
Pick the first point as a starting point.Pick the last point as a finished point.Then make a straight line from starting point to the finished point. This line is the displacement. If the path makes a right triangle we can use Pythagorean theory.Look at the picture
40 meters due northThen turns and walks 30 meters due east. The displacement line is the red line.The path makes a right triangle.d² = 40²+30²
d² = 1,600+900
d² = 2,500
[tex]d \:=\: \sqrt{2,500}[/tex]
d = 50 m
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Related Questions
For a force to do work on an object, some of the force must act in the________________
as the object moves.
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Answer:
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What is the condition for a force to do work on a body ?
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What is the condition for a force to do work on a body ?
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Solution
The condition of force to do some work is that the force should be along the direction of displacement.
work is done when the object moves through a certain distance in a particular direction after the force had been applied on it.
Work Done = Force x Distance x Cos theta
For work to be done, the force must be applied and must not be zero.
The body on which the force is applied must move in one direction or the other and hence the S must not be zero.
The force must not be applied at 90 degrees angle upon the object as Cos 90 equals zero.
Light travels approximately 982,080,000 ft/s, and one year has approximately 32,000,000 seconds. A light year is the distance light travels in one year.
State the speed in mi/s, using scientific notation. (1 mile = 5280 feet exactly, by definition; i.e., this is not a measurement.)
Answers
The speed of light in miles per second (mi/s) is 186,000 mi/s.
What is the distance travelled by light in a year?The distance travelled by light in a year is known as light-year. This distance travelled by light in a year depends on the speed of light.
The speed of light in a year is given as 982,080,000 ft/s. The unit of this speed of light in feet per seconds can be converted into miles per second.
The speed of light in miles per second (mi/s) is calculated by using the following conversion factor.
1 mile = 5280 feet
982,080,000 ft/s = 982,080,000 ft/s x 1 mile/5280 ft
982,080,000 ft/s = 186,000 miles/s
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later the car is traveling along a long straight road when it passes over a hill. the hill has a radius of 230 m. what is the minimum speed the car must have in order to become airborne as it crests the hill?
Answers
The minimum speed at which a car can leave the road at the top is 47.47 m/s
What is the minimum speed?Following are the calculations for the minimal speed at which a vehicle can veer off the road;
The hill has a radius of 230 m
Fc = Fn
[tex]\frac{mv^{2} }{r} = mg \\\frac{v^{2} }{r} =g\\v^{2} =rg \\v=\sqrt{rg}[/tex]
where;
The curving road's radius is 230 meters, and
the acceleration caused by gravity is 9.8 meters per second.
[tex]v = \sqrt{230* 9.8}[/tex]
r = 47.47
As a result, 47.47 m/s is the lowest speed at which a vehicle can exit the road at the top.
Find the approximate centripetal acceleration caused by gravity, g, in meters per second squared, and the radius of the vertical circular motion, r, in meters. Step 2: Using the formula vmin=rg v min = r g, get the object's minimum speed (the speed at the top of the circle).
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a nearsighted man has a far point of 300 cm. what kind of corrective lens should be prescribed for him?
Answers
The diverging lens/concave lens is used as a corrective lens is used for a nearsighted person
Nearsightedness is also known as myopia where the person with myopia will be able to see the near object but far objects will look blurry.
Myopia is corrected with lenses called "minus power lenses". They are concave in shape and help the eye to focus light properly. Myopia causes distant objects to appear blurry. Prescription glasses or contact lenses can usually correct this blurry distance vision. Myopic eyes have a stronger ability to focus than normal eyes. Focus in front of the retina, not on the retina. Lenses used to correct nearsightedness work by reducing the eye's ability to focus.
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A 85 kg firefighter needs to climb the stairs of a 20-m-tall building while carrying a 45 kg backpack filled with gears. How much power does he need to reach the top in 55 s?
Answers
The power that firefighter needed to reach the top of the building in 55s is equal to 463.3 Watts.
What is power?Power can be described as the rate of doing work and is also defined as the work done in unit time. The S.I. unit of power is Joule/second or Watt (W). The mathematical expression for power is mentioned below.
Power = work/ time
P = W/ t
Given, the height of the building, h = 20 m
The total mass of the firefighter and backpack, m = 85 + 45 = 130 Kg
The time taken to reach the top, t = 55 sec
The power that will be needed can be determined as:
[tex]{\displaystyle {P = \frac{m\times g\times h}{t}[/tex]
[tex]{\displaystyle {P = \frac{130\times 9.8\times 20}{55}[/tex]
P = 463.3 Watt
Therefore, with the power of 463.3 Watts, a firefighter will reach the top in 55s.
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Moving a charge from point A
A
, where the potential is 350 V
V
, to point B
B
, where the potential is 130 V
V
, takes 4.7×10−4 J
J
of work.
Answers
Answer:
Explanation:
Given:
φ₁ = 350 V - potential of point A
φ₂ = 130 V - potential of point B
A = 4.7·10⁻⁴ J - Work of the electric field
______________________
Q - ?
The magnitude of the electric charge:
Q = J / Δφ
Potential difference:
Δφ = φ₁ - φ₂ = 350 - 130 = 120 V
Then:
Q = J / Δφ = 4.7·10⁻⁴ / 120 ≈ 3.9·10⁻⁶ C or Q
Q = 3.9 mkC
what is the fundamental resolution limit (diffraction limit) for a telescope with a mirror that is 30 meters in diameter at a wavelength of 500 nanometers (green light)? give your answer in degrees or radians.
Answers
By using Rayleigh criterion principle, we can calculate the Fundamental resolution limit would be 20.33 x [tex]10^{-9}[/tex] radians
The Rayleigh criterion for the diffraction limit to resolution states that two images are just resolvable when the center of the diffraction pattern of one is directly over the first minimum of the diffraction pattern of the other.
According to the Rayleigh criterion principle, we have
Ф = 1.22 λ/D
where Ф is the resolution limit in radians
λ = wavelength of the light
D = diameter of the lens or the telescope
putting the appropriate values, we get
Ф = 1.22 x 500 x [tex]10^{-9}[/tex] / 30
Ф = 20.33 x [tex]10^{-9}[/tex] radians
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why does saturn radiate even more excess energy than jupiter? why does saturn radiate even more excess energy than jupiter? saturn can fuse hydrogen into helium in its core, like the sun. helium rain gives off heat as it differentiates toward saturn's center. saturn's atmosphere contains much methane, creating a large greenhouse effect. saturn's thick cloud layer contributes to a larger greenhouse effect. saturn is still radiating heat left over from its formation.
Answers
Saturn radiates even more excess energy than Jupiter Helium rain gives off heat as it differentiates toward Saturn's center. Option B.
Its density is so low that it floats on water. Like Jupiter, Saturn emits almost twice as much energy as it receives from the Sun. This is because it has its own internal heat source driven by the slow gravitational collapse that began with the planet's formation. The Jupiter planet draws heat from the Sun and from within.
Jupiter produces a lot of internal heat and emits thermal radiation to release this heat. In fact, Jupiter produces so much internal heat that it emits almost twice as much energy as it receives from the Sun. Hydrogen exists in a liquid metallic state around the central rocky core and surrounds the inner half of the planet. Compared to Jupiter, Saturn's mass and volume consist of this conductive metallic liquid which may partly explain why Saturn's magnetic field is much weaker.
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At rest, a car's horn has a frequency of 395 Hz. Car A passes car B on the street in the same direction. If car A is traveling at 22.0 m/s and car B is traveling at 19.5 m/s, what frequency does car B hear when car A honks? (speed of sound =343 m/s) (Unit=Hz) please help I'll give 100 points
Answers
Car A's frequency is determined to be 398.4 Hz.
What is the frequency heard by car A?The frequency heard by car A is calculated using the following equation.
f = fs(v - v₀) / (v - vs)
where;
v is the speed of sound = 343 m/s
v₀ is the speed car B = 19.2 m/s
vs is the speed of car A = 22 m/s
fs is the frequency of car A = 395 Hz
f is the frequency of car B = ?
f = 395(343 - 19.2) / (343 - 22)
The frequency will be calculated as below,
f = 395(1.0087)
f = 398.4 Hz
Therefore, car A's frequency is determined to be 398.4 Hz.
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A plane starting at rest at the south end of a runway undergoes a uniform acceleration of 1.60 m/s to the north. At takeoff, the plane's velocity is 72.0 m/s to the north. How far does the plane travel across the runway
Answers
The distance travelled by the plane across the runway is determined as 1,620 m.
What is the distance travelled by the plane across the runway?The distance travelled by the plane across the runway is calculated by applying the following equation.
v² = u² + 2as
where;
v is the final velocity of the planeu is the initial velocity of the planea is the acceleration of the planes is the distance travelled by the planeThe initial velocity of the plane, u = 0, since it started from rest.
v² = 0 + 2as
s = v²/2a
The given parameters;
acceleration of the plane, a = 1.6 m/s²final velocity of the plane = 72 m/ss = (72²)/(2 x 1.6)
s = 1,620 m
Thus, the distance travelled by the plane along or across the runway depends on the final velocity of the plane and the acceleration of the plane.
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1. Imagine you rubbed just one side of a thick piece of Styrofoam.
What do you think you would observe if you brought the rubbed side of the Styrofoam up to a neutral object?
2. What do you think you would observe if you brought the unrubbed side of the Styrofoam up to a neutral object?
Answers
The answers include the following:
The observation if you brought the rubbed side of the Styrofoam up to a neutral object is that the both of them will become negatively charged and repel.The observation if you brought the unrubbed side of the Styrofoam up to a neutral object is that they will be repulsion because it involves two neutral charges.What is Charge?Thus is referred to as the physical property of matter that causes it to experience a force when placed in an electromagnetic field. We should also note that like poles repel and unlike poles attract.
When the styrofoam is rubbed, it becomes negatively charged which when placed in contact with another neutral charge will result in the repulsion. In the case in which the unrubbed side of the styrofoam is placed near a neutral charge there will also be repulsion.
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two identical, parallel-plate capacitors are connected to identical batteries and allowed to charge fully. a dielectric is placed between the plates of one of the capacitors while still connected to the battery and allowed to reach a steady state. discuss whether the capacitance, charge, and electric potential of the capacitor with the dielectric are greater than, less than, or equal to the capacitor without the dielectric.
Answers
Capacitance, charge and electric potential will be greater than the capacitor without the dielectric.
Capacitance is the a property of an electric conductor or set of conductors that is measured by the amount of separate electric charge that can be stored on it per unit change in electric potential.
The value of capacitance for the parallel plate is C = (3∈0AK)/d
Since two identical, parallel-plate capacitors are connected
therefore the value of capacitance for both the plate is C
Ceq. = (C1*C2) / C1 + C2 = C*C / C+C = C2
When the battery remains connected, the potential difference [V] remains constant
Q=CV
∴Cafter>Cbefore [C increased]
∴Qafter>QBefore [Q increased]
Potential difference and charge across the capacitor before the dielectric:
Qbefore = [tex]\frac{CV}{2}[/tex]
Vbefore = Vafter = V
Potential difference and charge on the capacitor after inserting the dielectric:
Qafter = Ceq*V = [tex]\frac{kCV}{k+1}[/tex]
Vafter = Q*After / KC = [tex]\frac{\frac{kCV}{k+1}}{kc}[/tex]
Vafter= [tex]\frac{V}{k+1}[/tex] [K>1]
[Hence V decreases]
Vbefore > Vafter
Also, E = [tex]\frac{V}{d}[/tex]
therefore [E]before > [E]after [E decreases]
Energy stored in the capacitor:-
U=[tex]\frac{1}{2} CV^{2}[/tex]
As V= constant
Cafter > Cbefore .
Hence Uafter > Ubefore
Thus, the electrostatic potential increases.
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You land on an unexplored foreign planet, and have with you a 2.5 tool. You determine that the force of gravity acting on the tool
is 19.5. What is the gravitational acceleration of the planet?
Answers
Based on the value of the mass of the tool and the force of gravity on that planet, the gravitational acceleration of the planet is 7.8 m/s².
What is the gravitational acceleration of that planet?The mass and force of gravity acting on a body are related by the formula given below:
Force of gravity = mass * gravitational acceleration
The mass of a body is constant but the force of gravity acting on a body or the weight of the body varies depending on the value of the gravitational acceleration.
Considering the given values:
Mass of tool = 2.5 kg
Force of gravity acting on the tool = 19.5
gravitational acceleration = force of gravity / massgravitational acceleration = 19.5 / 2.5
gravitational acceleration = 7.8 m/s²
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what is one major difference between federal and unitary governments
Answers
Answer:
In a unit government, all the powers of government are moved around in the central government where in turn in a federal government, the powers of government are divided between the center and the units.
Explanation:
I hope this helps.
ignoring air resistance a projectiles vertical speed will what?
Answers
In the absence of air resistance, the only force acting on both objects would be gravity. Both objects would experience the same 9.8 m/s² acceleration toward the ground.
Since the initial conditions of both projectiles are identical, the velocities of both projectiles will be the same at all times. Therefore, both projectiles will attain a zero vertical velocity at the same time, and it is at this point that they simultaneously reach their respective maximum heights.
The maximum heights will not be the same, and they will differ by precisely the amount of height difference between the launch points.
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what must be the magnitude of the current in the outer wire so that the net magnetic field due to this combination of wires is zero at the common center of the wires?
Answers
magnetic field caused by the combination of wires to cancel out, the current will flow in a direction . The current will therefore move in the other direction,. The outside wire is experiencing a 15.83 A current.
The electric current formula, I=V/R, can be used to determine how much current is flowing. The "current equation," as it is commonly known, is derived from Ohm's Law. The variable "I" denotes current, "V" denotes voltage, and "R" denotes resistance.
What do current and electron actually mean?Electron movement is referred to as electron current. The positive terminal receives electrons that are released by the negative terminal. Traditional current, usually referred to as just current, exhibits behavior consistent with positive charge carriers being the source of current flow. A positive terminal receives normal current, which then travels to a negative terminal.
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he coefficient of the restitution of an object is defined as the ratio of its outgoing to incoming speed when the object collides with a rigid surface. for an object with a coefficient of 0.76, what fraction of the object's kinetic energy is lost during a single collision? the coefficient of the restitution of an object is defined as the ratio of its outgoing to incoming speed when the object collides with a rigid surface. for an object with a coefficient of 0.76, what fraction of the object's kinetic energy is lost during a single collision? 42% 58% 17% 51%
Answers
A single collision results in a loss of 42% of the object's kinetic energy.
How to calculate coefficient of restitution?Kinetic energy is equal to 0.5 x mass x v2.
kinetic energy coming in = 0.5 x m x v2
v/u = Coefficient of restitution
0.76 = v/u
v = 0.76u
Kinetic energy expended = 0.5 x m x 0.76²
Kinetic energy expended = 0.5 x m x 0.5776
Kinetic energy expended = 0.5776 (0.5 x m x )
The kinetic energy that is coming in is 0.5 x m x x2.
kinetic energy expended = 0.5776 x (incoming kinetic energy)
The entering kinetic energy is equal to 57.76% of the exiting kinetic energy, as can be seen from the above.
A loss of energy of 100 - 57.76 = 42.24%
Therefore, a single collision results in a loss of 42.24% of the object's kinetic energy.
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Finding displacement on a velocity time graph
Answers
Answer:
To find the displacement when the velocity is changing, a velocity-time graph is needed. Normally, velocity is plotted on the y-axis (the vertical axis) and time is plotted on the x-axis (the horizontal axis). The area under the line on a velocity-time graph is equal to the displacement of the object.
Explanation:
I hope this helps
It takes 6 people pulling with a force of 500. N each to begin moving the opposing team which was pulling with a combined force of 2500. N during a match of tug-of -war. If the total mass of both teams was 2000. kg, what was the force due to static friction? HELP ME .
Answers
From the calculations, we have the coefficient of friction as 0.026.
What is the coefficient of static friction?We know that friction has to do with the force that tends to oppose the motion of an object. As such, the point where the force of friction acts is actually the surface that lies between two bodies.
Now, we can see that It takes 6 people pulling with a force of 500 N each to begin moving the opposing team which was pulling with a combined force of 2500 N. This implies that the total force of the people that are pulling from this other side is 6 (500N) = 3000 N
Now we have the net force that is acting on the the rope as; 3000 N - 2500 N = 500 N
Then;
Coefficient of friction = Net force/ Normal reaction
= 500 N/(2000 * 9.8) N
= 0.026
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Which has the most kinetic energy from its motion?
Multiple choice question.
cross out
A)
a 1,100-kg car traveling 60 km/h
cross out
B)
a 2,000-kg truck traveling 50 km/h
cross out
C)
a 900-kg car traveling 80 km/h
cross out
D)
a 300-kg motorcycle traveling 100 km/h
Answers
Among the given options the vehicle that has the most kinetic energy is a 900-kg car traveling 80 km/h
KE = 1 / 2 m v²
KE = Kinetic energy
m = Mass
v = Velocity
For A,
m = 1100 kg
v = 60 km / h
KE = 1 / 2 * 1100 * 60²
KE = 1980000 J
KE = 1980 KJ
For B,
m = 2000 kg
v = 50 km / h
KE = 1 / 2 * 2000 * 50²
KE = 2500000 J
KE = 2500 KJ
For C,
m = 900 kg
v = 80 km / h
KE = 1 / 2 * 900 * 80²
KE = 2880000 J
KE = 2880 KJ
For D,
m = 300 kg
v = 100 km / h
KE = 1 / 2 * 300 * 100²
KE = 1500000 J
KE = 1500 KJ
KEc > KEb > KEa > KEd
Therefore, the 900-kg car traveling 80 km/h has the most kinetic energy
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How many g are in a pack containing 10 tablets of 500 mg each? *
5g
50g
100g
500g
Answers
Answer:
5 g
Explanation:
500 mg x 10 = 5000 mg
5000 x 10^-3 g = 5 g
Hello..!
To solve the problem and calculate the number of pills in the package, we will use the conversion factor.
The conversion factor or unit factor is a conversion method that is based on multiplying by one or more fractions where the numerator and denominator are equal quantities expressed in different units of measure, so that each fraction is equivalent to the unit.
Find out that 1 gram has a total of 1000 mg.
Problem:
How many g are in a carton containing 10 tablets of 500 mg each?
According to the previous text we can say that the conversion factor would be:
[tex] \: \: \: \: \: \qquad \qquad \large \sf\dfrac{1\ g}{1000\ mg}[/tex]
Now we must find out that the box has a total of 10 pills of 500 mg, so to know how many grams the box has we must know how many grams only one pill weighs:
[tex] \sf \qquad\boxed{\boxed{ \sf\large 500\ mg*\dfrac{1\ g}{1000\ mg}= 0.5\ g}}[/tex]
We know that a pill weighs 0.5 grams, now to calculate how many grams the box weighs we must multiply the total pills by the weight of just one pill:
[tex]\qquad \boxed{\boxed{ \sf\large 0.5\ g\times 10= 5\ g}}[/tex]
We conclude that one box contains 5 grams of tablet, option 1.
[tex]\begin{gathered}\rule{7cm}{0.01mm}\\\texttt{Good studies! :D}\\\rule{7cm}{0.01mm}\end{gathered}[/tex]
asasdcdcesasxxassxaasdddfdsas
Answers
Answer: That is not a question.
Explanation: It is a random jumble of letters. It also has no question mark.
a 70kg skater from side to side on a curved ramp they start at a height of 5m
at the boot on of the ramp they have the speed of 9.5m/s
on the opposite side of the ramp they only reach a maximum height of 4cm
describe the energy stores and transfers that take place as the skater moves form side to side on the ramp
Answers
The velocity of the skater will increase as he moves towards the center of the ramp and consequently the kinetic energy will increase. The kinetic energy will converted into potential energy as he moves towards the maximum height.
What is law of conservation of energy?The law of conservation of energy states that energy can neither be created nor destroyed but can be converted from one form to another.
As the skater move from side to side on the curved ramp, his kinetic energy will be converted into potential energy.
Mathematically, it be written as;
K.E = P.E
¹/₂mv² = mgh
where;
m is the mass of the skaterv is the speed of the skater at the lowest pointh is the maximum height attainedg is acceleration due to gravityAs the skater moves from the highest point with zero velocity, he will have maximum potential energy which decreases as he moves towards the center of the ramp. The velocity will increase as he moves towards the center of the ramp and consequently the kinetic energy will increase.
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if there is no air resistance, what is the net if there is 10 n of air resistance, what is the net force? what is the acceleration?? what is the acceleration?
Answers
If there is no air resistance, what is the net if there is 10 n of air resistance, what is the net force,the net force of an object is 0N and acceleration is 6N.
When compared to displacement and velocity, acceleration is like the wrathful, flaming dragon of motion variables. People may be terrified of it, it might be harmful, and if it's enormous, it draws your attention. When you're in a fast-turning corner in a car or go-kart or when you're in a plane during takeoff, you can feel your own acceleration.
Since velocity depends on both speed and direction, you can only accelerate by changing either one or the other, if not both. The object will be moving faster if the acceleration is pointing in the same direction as the velocity. Additionally, the item will slow down if the acceleration is pointing in the opposite direction from the direction of the velocity.
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you pull a box with a constant force of 250 n. it takes you 20 s to move the box 10 m along a rough surface at a constant speed. what power are you transferring to the system of the box and the rough surface?
Answers
Your power usage when pulling the box is 125 Watts. It takes 20 seconds to move a box 10 meter's along a rough surface when applying a continuous 250 n force.
Given: force = 250 N; distance = 10 m; speed = distance/time (10/20); speed = 0.5 m/s
W = work completed, where W = 250*10 = 2500 Joules.
Your labour of 2500 J by pulling the box
Thermal energy produced—considering that the box's surface and interior are both made of wood. Therefore, the kinematic friction coefficient is 0.3.
The thermal energy is therefore 75 N
thermal energy = 75*10 = 750 Joules, or thermal energy = force*d
force = mu
force= 0.3*250.
So pulling the Box produces 750 Joules of thermal power.
Power exerted = force* v
= 250*0.5
=125 Watts
so, The power exerted by you while pulling box is 125 Watts.
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which answer would you choose if the rocks fall out through a hole in the floor of the car, one at a time?
Answers
The car speeds remains constant.
Using the following equation for momentum:
Pi=Pf
(c=car and r=rock)
McVc + MrVr = McV'c + MrV'r
Initially
Vc=Vr=Vi
and since rocks are being dropped directly downward, final momentum of the rocks (being dropped one at a time) should be zero because their falling down, out of the railroad car.
So:
Vi( Mc+Mr) = McV'c V'c = [Vi(Mr+Mc)] / Mc
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How long does it take a car to travel 330 m at a speed of 30.0 m/s
Answers
330/30=11
It will take 11 seconds for a car to travel 330 m at a speed of 30.0 m/s
By going through the formula of calculating the speed of the vehicle
that is, S=D/T
We get the equation T=D/S.........(i)
Where T stands for Time
D stands for Distance
S stands for Speed
Now, as per the given question
Distance(D)= 330 meters
Speed(S)= 30.0 meters per second
Time(T)= ?
Putting the values in equation (i),
T=330 meters/30 meters per second
T = 11 seconds.
Therefore, A car moving at a speed of 30.0 meters per second will traverse 330 meters in 11 seconds.
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The ball is about to hit the ground.
It has a kinetic energy store of 110 J.
Ignoring the effects of friction, what is the maximum elastic potential energy store of the ball when it is fully compressed after hitting the ground?
Answers
The maximum elastic potential energy store of the ball when it is fully compressed after hitting the ground is 110 J
Since the effects of friction is ignored, there is no loss of energy as heat. So the entire elastic potential energy store of the ball is converted into kinetic energy store.
Elastic potential energy = Kinetic energy
Kinetic energy = 110 J
Elastic potential energy = 1 / 2 k x²
Kinetic energy = 1 / 2 m v²
k = Spring constant
x = Displacement
m = Mass
v = Velocity
If friction is ignored,
1 / 2 k x² = 1 / 2 m v²
v / x = √ ( k / m )
Therefore, the maximum elastic potential energy store of the ball is 110 J
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To become familiar with the order of magnitude of magnetic effects, consider the situation in a television cathode ray tube (not a flat-panel TV). In order to bend the electron trajectory so that the electron hits the top of the screen rather than going straight through to the center of the screen, you need a radius of curvature in the magnetic field of about 20cm20cm (Figure 20.95 ). If the electrons are accelerated through a 15,000 VV potential difference, they have a speed of 0.7×108m/s0.7×108m/s Calculate the magnitude of the magnetic field required to make the electrons hit the top of the screen. Is the magnetic field into or out of the page?
Answers
4.1510^-3 tesla the magnitude of the magnetic field required to make the electrons hit the top of the screen
v=0.7×10^8m/s
q=1.6×10^-19 C
B= ?
Voltage= 15,00 V
r= 20cm= 0.2 m
r=mVqB
B=mv/qr
B=4.1510^-3 tesla
To observe magnetic forces, one can utilize a magnetic field, an electric current, a changing electric field, or a vector field surrounding a magnet. Magnetic compass needles and other permanent magnets point in the general direction of magnetic fields resembling those on Earth. Electrically charged particles move in a helical or circular pattern in magnetic fields. Electric motors operate on this force, which is applied to electric currents in wires in a magnetic field.
Magnetic fields can be visualized as continuous lines of force or magnetic flux that travel from south to north magnetic poles. The lines' density reveals the magnetic field's strength. One or more of a magnet's poles are
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2. Hot-air balloons are a fun way to travel around the globe.
A. In what layer can a hot-air balloon travel?
B. Why can't a hot-air balloon go to higher layers?
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Answers
The layer that the hot-air balloon can travel to, in the layer of the atmosphere is troposphere. its can't a go to higher layers because it would be affected by density.
What is troposphere?The troposphere servesv as the lowest layer of Earth's atmosphere however it has the mass (about 75-80%) of the atmosphere and most of tthe types of clouds can be seen in the troposphere, then the weather occurs within this layer.
It should be noted that the troposphere has the highest density, as well as the greatest air pressure, however the water vapor, and a temperature range from 62, layer that the hot-air balloon can travel to, in the layer of the atmosphere is troposphere.
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