A van accelerates from a velocity of 2 m/s to a velocity of 20 m/s in 12 s.
Calculate the acceleration of the van.

The initial speed of the projectile launched at an angle of 30 above the horizontal from the top of a 10m high cliff is 34.2 m / s

According to equations of motion,

s = u t + 1 / 2 at²

s = Displacement

u = Initial velocity

t = Time

a = Acceleration

H = 10 m

t = 4 s

θ = 30°

g = 9.8 m / s²

Here the object is launched art an angle from a height. So,

s = - H = - 10 m

u = uy

While considering vertical motion,

a = - g = - 9.8 m / s²

- H = uy t - 1 / 2 g t²

- 10 = 4 uy - 1 / 2 * 9.8 * 4²

4 uy = 68.4

uy = 17.1 m / s

sin θ = uy / u

u = 17.1 / sin 30°

u = 34.2 m / s

Therefore, the initial speed of the projectile is 34.2 m / s

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Work done by the system is calculated to  - 456.863 J, when pressure and volume change is given.

For a gas, work is the product of the pressure and the volume during a volume change. Relationship between pressure and volume can be found out by Boyle's Law. As the pressure on a gas increases then the volume of the gas decreases because the gas particles are forced closer together.

W= -p ΔV

p is pressure and ΔV is volume change

Given that volume changes from 0.160 liters to 0.570 liters

ΔV = 0.570 - 0.160

= 0.41 L

Given p = 11 atm

Now, W = -11 * 0.41

As 1 atm L = 101.3 J

Hence W=  -11 * 0.41 * 101.3

Work = - 456.863 J (work done by system)

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More force is exerted by the table against her finger than she exerts against the surface.

Active power is the force behind motion or change that is exerted or brought to bear. the elements of nature

The term "force" has a clear definition in science. It is quite acceptable to refer to a force of this level as a push or a pull. An object does not "have in it" or "contain" a force. One thing is subject to a force from another. There is no distinction between living and non-living things in the concept of a force.

The newton  is the SI unit of force. As they relate to force, the base units are: The symbol for the length measurement known as the meter is m. The symbol for the kilogram, a unit of mass the sign s represents the second, a unit of time.

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a) in the z direction  he should  proceed in order to decrease the temperature most rapidly

b) The temperature decrease in the rate of  −2√14e2 if he proceeds in that direction.

Taking the gradient of TT yields ∇T(x,y,z)=⟨−2xe(−x2−2y2−3z2),−4ye(−x2−2y2−3z2),−6ze(−x2−2y2−3z2)⟩, where we get the direction of maximum increase of any point (x,y,z). As   we're at (1,1,1) so  the appropriate vector in order for the  maximum decrease is

−∇T(1,1,1)=⟨2e6,4e6,6e6⟩≈⟨0.0049575,0.00991501,0.0148725⟩

we normalize the upper result  giving us  :

⃗ =−∇T(1,1,1)∥−∇T(1,1,1)∥=⟨−1/√14,−√2/7, −3/√14⟩, here  we are getting the direction of and along with an angle

Now,  if r(t)  is a parametrized path, then d/dtT(r(t))= change in T(r(t)).r ′(t)), in order for heading to the direction of maximum decrease,  so UV =∥u∥ ∥v∥cosθ in here θ=0. So, the rate of decrease is ∥∇T(1,1,1)∥e8=2/√14e2 or -2/√14e2

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The temperature of the ship's hull when he is at location (x,y,z) will be given by T(x,y,z)=e−x2−2y2−3z2, where x,y, and z is measured in meters. He is currently at (1,1,1).

(A) In what direction should he proceed in order to decrease the temperature most rapidly?

(B) If the ship travels at e8 meters per second, how fast will the temperature decrease if he proceeds in that direction?

According to the idea behind active galactic nuclei, heated plasma in an accretion disc that revolves around the black hole is principally responsible for the active galactic nucleus' high luminosity.

An active galactic nucleus (AGN) is a compact area at the Centre of a galaxy that exhibits features that indicate the luminosity is not coming from stars and is substantially brighter than usual over at least some of the electromagnetic spectrum. Is called active galactic nucleus.

A light-emitting object's radiant power, which is measured in absolute terms as luminosity, is the electromagnetic power that it radiates out over time. The total quantity of electromagnetic energy released by a star, galaxy, or other celestial object in a given amount of time is measured as luminosity in astronomy.

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Answer:

[tex]\textsf{a)} \quad x=\dfrac{25(7-\sqrt{13})}{3}=28.2870727\; \sf mm[/tex]

[tex]\textsf{b)} \quad V=379037.8082\; \sf mm^3[/tex]

Explanation:

[tex]\boxed{\begin{minipage}{5 cm}\underline{Volume of a rectangular prism}\\\\$V=w\:l\:h$\\\\where:\\ \phantom{ww}$\bullet$ $w$ is the width of the base. \\ \phantom{ww}$\bullet$ $l$ is the length of the base. \\ \phantom{ww}$\bullet$ $h$ is the height.\\\end{minipage}}[/tex]

Given:

The dimensions of the rectangular prism in terms of x are:

Substitute these values into the formula for volume to create an equation in terms of x:

[tex]\begin{aligned}\implies V&=(150-2x)(200-2x)x\\&=(30000-700x+4x^2)x\\&=4x^3-700x^2+30000x\end{aligned}[/tex]

To find the value of x that will give the maximum volume, differentiate the equation for volume.

[tex]\begin{aligned}\implies \dfrac{\text{d}V}{\text{d}x}&=3 \cdot 4x^{3-1}-2 \cdot 700x^{2-1}+30000x^{1-1}\\&=12x^2-1400x+30000\end{aligned}[/tex]

Set the derivative to zero and solve for x using the quadratic formula:

[tex]\implies x=\dfrac{-(-1400) \pm \sqrt{(-1400)^2-4(12)(30000)}}{2(12)}[/tex]

[tex]\implies x=\dfrac{1400 \pm \sqrt{520000}}{24}[/tex]

[tex]\implies x=\dfrac{1400 \pm \sqrt{40000 \cdot 13}}{24}[/tex]

[tex]\implies x=\dfrac{1400 \pm \sqrt{40000}\sqrt{13}}{24}[/tex]

[tex]\implies x=\dfrac{1400 \pm 200\sqrt{13}}{24}[/tex]

[tex]\implies x=\dfrac{175\pm 25\sqrt{13}}{3}[/tex]

[tex]\implies x=\dfrac{25(7\pm\sqrt{13})}{3}[/tex]

To determine which value of x will give the maximum volume, differentiate again:

[tex]\begin{aligned}\implies \dfrac{\text{d}^2V}{\text{d}x^2}&=2 \cdot12x^{2-1}-1400x^{1-1}+0\\&=24x-1400\end{aligned}[/tex]

Substitute both values of x into the second derivative:

[tex]x=\dfrac{25(7+\sqrt{13})}{3} \implies \dfrac{\text{d}^2V}{\text{d}x^2}=721.1102551 > 0\implies \sf minimum[/tex]

[tex]x=\dfrac{25(7-\sqrt{13})}{3} \implies \dfrac{\text{d}^2V}{\text{d}x^2}=-721.1102551 < 0\implies \sf maximum[/tex]

Therefore, the value of x which will give the maximum volume is:

[tex]x=\dfrac{25(7-\sqrt{13})}{3}=28.2870727\; \sf mm[/tex]

To find the maximum volume of the box, substitute the found value of x into the equation for volume:

[tex]\begin{aligned}\implies V_{\sf max}&=4\left(\dfrac{25(7-\sqrt{13})}{3}\right)^3-700 \left(\dfrac{25(7-\sqrt{13})}{3}\right)^2+30000 \left (\dfrac{25(7-\sqrt{13})}{3}\right)\\\\&=379037.8082\; \sf mm^3\end{aligned}[/tex]

The dimensions of the box with maximum possible volume will be:

The force would have to work on the block till a distance of 15.66m farther to have 56 joules of kinetic energy.

The work done is given by the product of the force applied and the distance covered along the direction of force.

So we can write,

W = F.s

Where w is the work done if is the force and S is the distance covered.

According to work energy theorem, the work done is equal to the change in kinetic energy.

The force applied in this case is 3 Newton and the body has no till a distance of 3m. Let us assume that the block is moved till a distance x in order to achieve a kinetic energy of 56 joules.

So, it can be written,

3(3+x) = 56

Solving,

9+3x = 56

3x = 47

x = 15.66 m.

So, it is required to move the body by a distance of 15.66 m.

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The law that explains it is called the law of conservation of energy.

The law of conservation of energy states that in an isolated system, the total energy remains constant, i.e., the total energy is conserved over time. Therefore, the initial energy of an isolated system is equal to the final energy of the system. As a result, energy can neither be destroyed nor created. Energy can only be transferred or transformed from one from to another.

The law of conservation of energy can be mathematically expressed as K₁ + U₁ = K₂ + U₂ where K₁ is the initial kinetic energy, U₁ is the initial potential energy, K₂ is the final kinetic energy and U₂ is the final potential energy.

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My experiment disagreed with Galileo because Galileo's explanation for the tides was incorrect; the hypothesis that Earth orbits the Sun is right.

Galileo discovered evidence in 1595 that he believed supported the idea that Earth orbits the Sun. Galileo believed that the irregular motion of Earth around the Sun was the primary cause of the tides. Galileo's explanation for the tides was incorrect, even though the idea that Earth orbits the Sun is true.

Galileo presents his three top justifications for his contention that the earth revolves around the sun. One of these is his claim that "the ebbing and flowing of the ocean tides" supports his position.

There are high and low tides. Galileo thought that the earth's rotation was what created the tides. One of his absolute worst theories is this one.

The sun and moon's actions cause "the ebb and flow of the sea," as we now understand. That is the correct explanation for the tides, as stated by Newton. They result from gravitational forces, as Newton demonstrated.

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The number of electrons transported is 8.1 x 10²² electrons.

The variety of electrons in a neutral atom is identical to the number of protons. The mass wide variety of the atom is the same as the sum of the range of protons and neutrons inside the nucleus. The number of neutrons is equal to the difference between the mass number of the atom and the atomic wide variety. The reduction half-response includes a -electron gain.

The LCM is consequently 6. The net equation is a six-electron transfer. The wide variety of electrons in an atom is identical to the atomic quantity of an element for neutrally charged species. this means the number of electrons and the number of protons in an element are identical. consequently, the variety of electrons in oxygen is 8. Ionic bonds are shaped among or extra atoms by using the switch of one or extra electrons among atoms.

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Answer:

Radius 20 m.

Explanation:

Given:

aₙ = 1.4 m/s²

V = 5.3 m/s

___________

R - ?

Centripetal acceleration:

aₙ = V² / R

Radius:

R = V² / aₙ

R = 5.3² / 1.4 ≈ 20 m

Wavelength is (c) the distance between two neighboring troughs in a wave.

Wavelength is the separation between identical points (adjacent crests) in successive cycles of a waveform signal travelling through space or over a wire. Si unit of wavelength is meter. In wave motion, velocity of wave = wave length × frequency.

Hence, wavelength is a distance between two neighboring identical points such as troughs of a wave. so, option (c) is current answer.  

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The maximum height travelled by the ball before returning to the ground is 8.62 m.

The maximum height travelled by the ball before returning to the ground is calculated by applying the following kinematic equation as shown below.

H = (u²sin²θ) / 2g

where;

H = (26² (sin 30)²) / (2 x 9.8)

H = 8.62 m

Thus, the maximum height travelled by a projectile depends on the initial velocity and angle of projection.

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To find the collision rate, known the magnitude.

What is magnitude?

Magnitude typically refers to size or distance. By comparing the size and motion speed of the thing, we can relate magnitude to movement. The object's or quantity's size determines its magnitude.

What is mean by collision rate?

The frequency of collisions between a single particle of radius m and particles with masses ranging from (m1, m1 + m1) to (m, m1) is proportional to their concentration, n(m1) m1, where (m, m1) is the rate constant for collisions between the two particles of masses m and m1 and depends on the process. 

u=140kmph

t=7.oms

v=0

E=M(V-U)/t

⇒m(0-140)/0.007×5/18m/s

⇒5555.55 (m) N

E=(5555.55) (mass) N

Therefore, the collision lasts is 5555.55(m) N.

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The time taken for the train of mass 1.4 107 kg to reach the speed of 60 km/h is  362.39 seconds

Acceleration is the rate of change of the velocity of an item with appreciation to time. Accelerations are vector portions. The orientation of an item's acceleration is given by the orientation of the net pressure appearing on that object.

Calculation:-

mass of the train = 1.4 × 10⁷ kg

constant force F = 6.5  × 10⁵ N

Using Newton's second law

F = ma

a = F/m

  = 6.5  × 10⁵ N /1.4 × 10⁷ kg

  =  0.046 m/s²

This acceleration accelerates from

initial velocity u = 0

Final velocity v = 60 km/hr = 16.67 m/s

Using,

V = U + at

t = V - U/a

 = 16.67 / 0.046

 =  362.39 seconds

Acceleration is the charge at which velocity modifications with time, in terms of each speed and route. A factor or an object moving in a straight line is accelerated if it quickens or slows down. movement on a circle is extended despite the fact that the rate is consistent because the course is continually changing.

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Yes, a spectrophotometer could be used to measure the absorption of a particular wavelength of light that is not visible to a normal human eye.

Although we cannot directly observe the absorption of this light, it is quantifiable. A spectrophotometer, which measures the absorption of light at certain wavelengths (whether visible or not) by a solution, may be used to compute the concentration. The popular and accessible technique of spectrophotometry may be used to determine the concentration of compounds in a solution or the degree of light absorption.

 When a light beam is focused through the sample, each component either absorbs or transmits light of a certain wavelength. They are combined with quantifiable and visible colored byproducts. Another is that, as observed by a spectrophotometer, colorless substances generally absorb light from the region of the spectrum that is imperceptible to the human eye.

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Mv is equal to m - 2.5 log(d/10)2. There is a minus sign in the expression because stars distant than 10 pc have Mv that is more negative than m. Make careful you provide the star's given distance in parsecs (1 pc = 3.26 ly = 206265 AU) if you use this formula.

The moon can appear to be nearly -13 magnitude bright, the moon can appear to be -6 magnitude bright, and stars can get as bright as nearly -1.5 magnitude.

The star's actual magnitude is determined by subtracting its apparent magnitude by five times the trigonometric parallax of its distance from the star.

First-magnitude stars have apparent magnitudes less than +1.50, making them the brightest stars in the night sky. In the first century B.C., Hipparchus invented the magnitude scale. He assigned first magnitude to the 20 brightest stars and sixth magnitude to the stars that are faint enough to be seen with the unaided eye.

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The heated (brown) air is separated from the cold (blue) air bubble on the left. A(n) is the term used to describe

"Fronts" are the borders that are formed when air masses converge. Cold front in three dimensions. Temperature changes caused by a front's motion can be used to identify it. A cold front causes a warmer air mass to be replaced by a colder one. Another name for it is a "dryline" or "dry front." a line or zone between two air masses that have different densities and, as a result, are typically at different temperatures. A moving front is given a name based on the air mass that is advancing; for example, a cold front if colder air is going forward. The front is the line separating two air masses. A front typically has overcast, stormy weather. Four separate fronts exist: the Cold, Warm, Stationary, and Occluded fronts. A cold front arises when two cold air masses collide with warm air masses.

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Knowing the kinetic static force coefficient.

What is oscillation ?

Oscillation is the process by which a quantity or measure varies in time around its equilibrium value. Another definition of oscillation is the periodic variation of a substance between two values or around its central value.

What is kinetic force?

A force that acts between moving surfaces is referred to as "kinetic friction." A force acting in opposition to the direction of a moving body on the surface is felt. The two materials' coefficients of kinetic friction will determine how much force is applied.

For both blocks to oscillate together w^2=K/((M+M))

Maximum accelartion =a_(n= w^2 ) A= K/((M+M))A

For ⏊ kg block, μmg = 〖ma〗(n= )  μg

μg =K/((M+M))A

= 0.45×9.8 = 150/((2.1+1)) A

A=0.0914m

Max speed, vm=wA=  √(k/(M+M)) A

=√(150/((2.1+1))) × 0.0914

= v(m=) 0.636 m/s

Therefore, the maximum speed is  0.636 m/s.

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acceleration of the earth due to jupiter's gravitational attraction at their average separation Is 246590.053 metre/sec²

Acceleration due to gravity is the acceleration gained by an object due to gravitational force. Its SI unit is m/s 2. It has both magnitude and direction, hence, it’s a vector quantity. Acceleration due to gravity is represented by g.

Enter the mass, radius and “x” for the unknown value in the respective input field

Now click the button “Calculate the Unknown” to get the acceleration due to gravity

Finally, the gravitational acceleration will be displayed in the output field.

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The relationship between the generator and the energy input is the fact that the generator uses mechanic energy as input to produce electricity.

An electrical generator device is any instrument capable of generating electrical activity using any source of energy as a source for such purpose, such as the movement (motion of mechanical energy) of a turbine.

Therefore, with this data, we can see that an electricity generator device is a given instrument used to generate electricity by exploiting the mechanical energy generated through a particular process.

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The submerged fraction of a person when floating gently in fresh water is 0.989. The fraction of a person is submerged when floating gently in salt water with a density of 1027 kg/m³ is 0.963

fs = ρo / ρf

fs = Submerged fraction

ρo = Density of object

ρf = Density of fluid.

a ) For fresh water,

ρo = ρp = 989 kg / m³

ρf = ρw = 1000 kg / m³

fs = 989 / 1000

fs = 0.989

b ) For salt water,

ρo = ρp = 989 kg / m³

ρf = ρs = 1027 kg / m³

fs = 989 / 1027

fs = 0.963

Therefore,

a ) In fresh water, the submerged fraction is 0.989

b ) In salt water, the submerged fraction is 0.963

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When you hear a loud sounds at 900 Hz and look up to see a bird diving frequency you, the bird is moving at a speed of 38.12 meter's per second (m/s). Knowing the species of bird and that their frequency.

When this frequency range is overused, the result might be honky or nasal. The teacher from the Charlie B. series serves as this range's audio guide.

Auditory identification of birds can be done by birders who are familiar with the various bird speed. A keen birder might start looking for nearby birds of prey after hearing an alarm cry, whereas someone who hears speed a begging call would start looking for a nest that is well-hidden.

f1=f(V+Vo/V-Vs)\s900/800=(343/343-Vs)

V=38.12 m/s

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The magnitude of its acceleration is a= g ([tex]W_{B}[/tex])/( 2[tex]W_{A}[/tex] +[tex]W_{B}[/tex] )

The length of the vector is all there is to an acceleration's magnitude. To put it another way, writing the magnitude of acceleration indicates how quickly velocity varies. In the standard international (SI) system, the acceleration is measured in units of meters per second square.

Let T be the rope's tension, assuming it has no mass.

T =( 2[tex]W_{A}[/tex])a/g ------- 1

([tex]W_{B}[/tex]) - T = ([tex]W_{B}\\[/tex])a/g ------- 2

Add 1 and 2

[tex]W_{B}[/tex] =(a/g)( 2[tex]W_{A}[/tex]+ [tex]W_{B}[/tex])

a= g ([tex]W_{B}[/tex])/( 2[tex]W_{A}[/tex] +[tex]W_{B}[/tex] ).

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The average acceleration of the dragster during this time interval is 44.57 m/s² and the average net force on the dragster during this time is 38915N.

The initial speed U of the dragster is zero while the final speed V of the dragster is 26.3m/s. The director runs for a total of time t of 0.59 seconds.

According to the equation of motion,

V = U+at

Putting values,

26.3 = 0.59a

a = 44.57 m/s².

So, the acceleration of the dragster is 44.57 m/s².

The force on the director is given by,

F = ma

m mass of the dragster and a is the acceleration of the dragster.

F = 873×44.57

F = 38915N.

So, the net average force on the dragster during this time is 38915 Newton.

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1)

Circular Motion

2)

No; the direction changes.

3)

Velocity. Gravitational Pull. Force/Twist. Acceleration.

4)

The weight of the object, gravity pulling on it. The kinetic energy produced by you which caused acceleration in a certain vector direction. Location of the object.

The value of the spring constant of the ideal spring is 106.9 N/m.

The mass suspended by the student is 0.3 kg from the ideal soring and the equilibrium displacement is 5.5 cm or 0.055 cm.

The work done by the gravity will be equal to the work done by the spring,

Mgx = 1/2Kx²

Where,

x is the equilibrium displacement,

K is the spring constant,

M is the mass,

g is acceleration due to gravity,

Putting values,

0.3 x 9.8 x 0.055 = 0.5 x K x 0.055 x 0.055

K = 106.9 N/m.

The spring constant is 106.9 N/m.

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The average acceleration vector of the ball is - 9.78 m/s².

When you throw a ball upward with an initial speed, it will go up until reaching its highest peak then it will go down. So the ball doing non-uniform motion. The formula for non-uniform motion including initial speed, and final speed with time is

v = u+at

v-u = at

[tex]a = \frac{v - u}{t}[/tex]

[tex]a = \frac{- 4.5 - 4.5}{0.92}[/tex]

[tex]a = \frac{- 9.0}{0.92}[/tex]

a = 9.78 m/s²

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