Answer:
0
Step-by-step explanation:
Please help soon as possible! This is urgent! Match each expression with the correct description.
Answer:
Hey there!
q is 1, and n=-2.
q-n=1-(-2), which is 3.
n-q=-2=1, which is -3.
q is 1.
Thus, the least value is n-q, and the greatest value is q-n. Closest to zero would be q.
Let me know if this helps :)
Answer:
Least: n-q
Greatest: q-n
Closest to zero: q
Suppose babies born in a large hospital have a mean weight of 3316 grams, and a standard deviation of 324 grams. If 83 babies are sampled at random from the hospital, what is the probability that the mean weight of the sample babies would differ from the population mean by greater than 54 grams?
Answer: 0.129
Step-by-step explanation:
Let [tex]\overline{X}[/tex] denotes a random variable that represents the mean weight of babies born.
Population mean : [tex]\mu= \text{3316 grams,}[/tex]
Standard deviation: [tex]\text{324 grams}[/tex]
Sample size = 83
Now, the probability that the mean weight of the sample babies would differ from the population mean by greater than 54 grams will be :
[tex]P(|\mu-\overline{X}|>54)=1-P(\dfrac{-54}{\dfrac{324}{\sqrt{83}}}<\dfrac{\overline{X}-\mu}{\dfrac{\sigma}{\sqrt{n}}}<\dfrac{-54}{\dfrac{324}{\sqrt{83}}})\\\\=1-[P(-1.518<Z<1.518)\ \ \ [Z=\dfrac{\overline{X}-\mu}{\dfrac{\sigma}{\sqrt{n}}}]\\\\=1-[P(Z<1.518)-P(z<-1.518)]\\\\=1-[P(Z<1.518)-(1-P(z<1.518))]\\\\=1-[2P(Z<1.518)-1]=2-2P(Z<1.518)\\\\=2-2(0.9355)\ [\text{By z-table}]\\\\=0.129[/tex]
hence, the required probability = 0.129
Which line is parallel to the line 8x + 2y = 12? On a coordinate plane, a line goes through (negative 2, negative 4) and (0, 4). On a coordinate plane, a line goes through (negative 1, 1) and (3, 0). On a coordinate plane, a line goes through (negative 2, 2) and (negative 1, negative 2). On a coordinate plane, a line goes through (negative 3, 2) and (1, 3).
Answer:
C.
On a coordinate plane, a line goes through (negative 2, 2) and (negative 1, negative 2).
The line parallel to the line 8x + 2y = 12 will be a line that goes through (-2, 2) and (-1, -2). The correct option is C.
What is an equation of the line?An equation of the line is defined as a linear equation having a degree of one. The equation of the line contains two variables x and y. And the third parameter is the slope of the line which represents the elevation of the line.
Given that the equation of the line is 8x + 2y =12. First, calculate the slope of the line if the slope of the line is the same as the equation of the given line then the two lines will be parallel.
8x + 2y = 12
2y = -8x + 12
y =-4x + 6
Take points (-2, 2) and (-1, -2) and find the slope of the line.
Slope = ( y₂ - y₁ ) / ( x₂ - x₁ )
Slope = ( -2 - 2 ) / ( -1 + 2 )
Slope = -4
Therefore, the line parallel to the line 8x + 2y = 12 will be a line that goes through (-2, 2) and (-1, -2). The correct option is C.
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Johnny was able to drive an average of 31 miles per hour faster in his car after the traffic cleared. He drove 16 miles in traffic before it cleared and then drove another 47 miles. If the total trip took 2 hours, then what was his average speed in traffic?
9514 1404 393
Answer:
16 mi/h
Step-by-step explanation:
The time for a given leg of the trip is the distance divided by the speed. If t is the speed in traffic, the total trip time is ...
16/t +47/(t+31) = 2
Multiplying by t(t+31), we get ...
16(t +31) +47t = 2(t)(t+31)
2t^2 -t -496 = 0 . . . . put in standard form
(2t +31)(t -16) = 0 . . . . factor
The positive solution is t = 16.
Johhny's average speed in traffic was 16 mph.
writie any assay about challenges of teaching mathematics on 21st century
pls what is the nearest 100 of 49
Answer:
the nearest hundred is 50
Find the indicated area under the curve of the standard normal distribution, then convert it to a percentage and fill in the blank.
About_____% of the area is between z = 2.2 and z = 2.2 (or within 2.2 standard deviations of the mean).
About_____% of the area is between z = 2.2 and z = 2.2 (or within 2.2 standard deviations of the mean).
Complete Question
Find the indicated area under the curve of the standard normal distribution, then convert it to a percentage and fill in the blank.
About_____% of the area is between z = - 2.2 and z = 2.2 (or within 2.2 standard deviations of the mean).
About_____% of the area is between z = - 2.2 and z = 2.2 (or within 2.2 standard deviations of the mean).
Answer:
About 97.219% of the area is between z = - 2.2 and z = 2.2 (or within 2.2 standard deviations of the mean).
Step-by-step explanation:
From the question given we can see that they both are the same so 1 will just solve one
Now the area under this given range can be represented mathematically as
[tex]P ( -2.2 < z < 2.2) = P(z < 2.2 ) - P(z < -2.2 )[/tex]
Now from the z-table
[tex]p(z < 2.2 ) = 0.9861[/tex]
and
[tex]p(z < - 2.2 ) = 0.013903[/tex]
So
[tex]P ( -2.2 < z < 2.2) = 0.9861 - 0.013903[/tex]
[tex]P ( -2.2 < z < 2.2) = 0.97219[/tex]
So converting to percentage
[tex]P ( -2.2 < z < 2.2) = 0.97219 * 100[/tex]
[tex]P ( -2.2 < z < 2.2) = 97.219 \%[/tex]
Each cylinder is 12 cm high with a diameter of 8 cm.
Calculate the volume of each cylinder.
Use 3 as a value for π
Give your answer using the correct units.
Answer:
Volume = 576cm^3Step-by-step explanation:
[tex]h = 12 cm\\d = 8cm\\r =d/2 = 8/2 =4\\V = ?\\V =\pi r^2h\\\\V= 3 \times 4^2\times12\\V = 576 cm^3[/tex]
Transform the given parametric equations into rectangular form. Then identify the conic.
Answer:
Solution : Option B
Step-by-Step Explanation:
We have the following system of equations at hand here.
{ x = 5 cot(t), y = - 3csc(t) + 4 }
Now instead of isolating the t from either equation, let's isolate cot(t) and csc(t) --- Step #1,
x = 5 cot(t) ⇒ x - 5 = cot(t),
y = - 3csc(t) + 4 ⇒ y - 4 = - 3csc(t) ⇒ y - 4 / - 3 = csc(t)
Now let's square these two equations. We know that csc²θ - cot²θ = 1, so let's subtract the equations as well. --- Step #2
( y - 4 / - 3 )² = (csc(t))²
- ( x - 5 / 1 )² = (cot(t))²
___________________
(y - 4)² / 9 - x² / 25 = 1
And as we are subtracting the two expressions, this is an example of a hyperbola. Therefore your solution is option b.
solve for x . please help also don’t forget to show work
Answer:
X-4x+11=8
-3x+12-8=0
-3x+4=0
3x=4
X=4/3
Answer:
x = 4/3 or 1.3
Step-by-step explanation:
Combine like terms
8 = -3x + 12
Move the terms
3x = 12 - 8
Calculate
3x = 4
Divide both sides by 3
x = 4/3
or
x = 1.3
What are the coordinates of point S"?
Answer:
point s: (-2,6)
-2 is the x coordinate
6 is the y coordinate
Which equation will solve the following word problem? Jared has 13 cases of soda. He has 468 cans of soda. How many cans of soda are in each case? 13(468) = c 468c = 13 468/13 = c 13 = c/468
Answer:
c = 468 / 13
Step-by-step explanation:
If c is the number of cans of soda in each case, we know that the number of cans in 13 cases is 13 * c = 13c, and since the number of cans in 13 cases is 468 and we know that "is" denotes that we need to use the "=" sign, the equation is 13c = 468. To get rid of the 13, we need to divide both sides of the equation by 13 because division is the opposite of multiplication, therefore the answer is c = 468 / 13.
Answer:
468/13 = c
Step-by-step explanation: Further explanation :
[tex]13 \:cases = 468\:cans\\1 \:case\:\:\:\:= c\: cans\\Cross\:Multiply \\\\13x = 468\\\\\frac{13x}{13} = \frac{468}{13} \\\\c = 36\: cans[/tex]
fill in each balance???
Answer:
Step-by-step explanation:
Take the beginning number and add or subtract each transaction to get a new balance. For example,
349.45
- 23.42 = 326.03
- 14.95 = 311.08
+ 276.50 = 587.58
- 219.93 = 367.65
- 76.84 = 290.81
pls answer and you will be blessed :)
Answer:
2
Step-by-step explanation:
It is the only one that makes sense
The differential equation of a certain system is 20y′′+cy′+80y=0
, where c is called damping constant for what value of c critical damping hapens
Options:
110
64
50
60
Answer:
c=80
Step-by-step explanation:
Based on my reading the critical damping occurs when the discriminant of the quadratic characteristic equation is 0.
So let's see that characteristic equation:
20r^2+cr+80=0
The discriminant can be found by calculating b^2-4aC of ar^2+br+C=0.
a=20
b=c
C=80
c^2-4(20)(80)
We want this to be 0.
c^2-4(20)(80)=0
Simplify:
c^2-6400=0
Add 6400 on both sides:
c^2=6400
Take square root of both sides:
c=80 or c=-80
Based on further reading damping equations in form
ay′′+by′+Cy=0
should have positive coefficients with b also having the possibility of being zero.
in the factory 25 men working 26 hour can produce 1300 radios . how manny hours must the same group of men work to produce 450 radios
Answer:
9 hours
Step-by-step explanation:
Since the group of men remains the same, number of hours is proportional to number of radios.
1300/26 = 450/h
h = 26 * 450 / 1300 = 9 hours
15 more than 2 times a number is equal to -14. Find the number.
please help asap and thank you in advance!
Answer:
The number is - 14.5
Step-by-step explanation:
Let the number be x.
ATQ, 15+2x=-14, x=-29/2=-14.5
Does the function satisfy the hypotheses of the Mean Value Theorem on the given interval? f(x) = 4x2 − 3x + 2, [0, 2]
Answer:
Yes , it satisfies the hypothesis and we can conclude that c = 1 is an element of [0,2]
c = 1 ∈ [0,2]
Step-by-step explanation:
Given that:
[tex]f(x) = 4x^2 -3x + 2, [0, 2][/tex]
which is read as the function of x = 4x² - 3x + 2 along the interval [0,2]
Differentiating the function with respect to x is;
f(x) = 8x - 3
Using the Mean value theorem to see if the function satisfies it, we have:
[tex]f'c = \dfrac{f(b)-f(a)}{b-a}[/tex]
[tex]8c -3 = \dfrac{f(2)-f(0)}{2-0}[/tex]
since the polynomial function is differentiated in [0,2]
[tex]8c -3 = \dfrac{(4(2)^2-3(2)+2)-(4(0)^2-3(0)+2)}{2-0}[/tex]
[tex]8c -3 = \dfrac{(4(4)-3(2)+2)-(4(0)-3(0)+2)}{2-0}[/tex]
[tex]8c -3 = \dfrac{(16-6+2)-(0-0+2)}{2-0}[/tex]
[tex]8c -3 = \dfrac{(12)-(2)}{2}[/tex]
[tex]8c -3 = \dfrac{10}{2}[/tex]
8c -3 = 5
8c = 5+3
8c = 8
c = 8/8
c = 1
Therefore, we can conclude that c = 1 is an element of [0,2]
c = 1 ∈ [0,2]
Charlie needs a $275,000 mortgage and he'd like to pay it off in 30 years. He is considering two banks. Bank A: 3.5% with monthly payments of $1234.87 Bank B: 4% with monthly payments of $1312.89 Charlie doesn't think a 0.5% difference is that much. What is the difference between these two bank loans with total interest paid over the life of the loan?
Answer:
Difference in interest= $41,250
Step-by-step explanation:
To calculate the interest paid on each bank loan we use the following formula
Interest = Principal * Rate * Time
For Bank A
Interest = 275,000 * 0.035 * 30
Interest = $288,750
For Bank B
Interest = 275,000 * 0.04 * 30
Interest = $330,000
Therefore
Difference in interest= 330,000 - 288,750
Difference in interest= $41,250
Therefore if the mortgage is taken from Bank B he will pay an extra $41,250 on the loan.
The 0.5% difference in rates has a large impact over the 30 year term loan
micah drove 4 1/4 miles on Monday and 2 2/3 miles on Tuesday. On Wednesday, he drove 1 1/3 fewer miles than he had driven on Monday. How many miles did they drive in total
Answer:
9.5
Step-by-step explanation:
Monday: [tex]4\frac{1}{4}[/tex]
Tuesday: [tex]2\frac{2}{3}[/tex]
Wednesday: [tex]4\frac{1}{4} - 1\frac{1}{3}[/tex]
Total: [tex]4\frac{1}{4} + 2\frac{2}{3} + (4\frac{1}{4} - 1\frac{1}{3})[/tex]
Start by subtracting [tex]4\frac{1}{4} and[/tex] [tex]1\frac{1}{3}:[/tex] [tex]\frac{35}{12}[/tex]
Now, add them all up: [tex]4\frac{1}{4} + 2\frac{2}{3} + \frac{35}{12} = 9.5[/tex]
Therefore, Micah drove 9.5 miles in total.
Answer gets BRAINLIEST If q varies inversely as r, and g = 10 when r = 2.5, find the equation that connects a
and r.
Answer:
D.
Step-by-step explanation:
In direct variations, we would have:
[tex]q=kr[/tex]
Where k is some constant.
Since this is indirect variation, instead of that, we would have:
[tex]q=\frac{k}{r}[/tex]
To determine the equation, find k by putting in the values for q and r:
[tex]10=\frac{k}{2.5}\\k=2.5(10)=25[/tex]
Now plug this back into the variation:
[tex]q=\frac{25}{r}[/tex]
The answer is D.
Solve the following system of equations for x to the nearest hundredth : y + 2x + 1 = 0; 4y - 4x ^ 2 - 12x = - 7
Answer:
+3.464; -3.464
Step-by-step explanation:
call A = y + 2x + 1 = 0 => y = (1 - 2x)
call B: 4y - 4(x^2) - 12x = -7
=> replace y from A to B =>
4(1 - 2x) - 4(x^2) - 12x = -74 - 8x - 4(x ^ 2) - 12x = -7-8x - 4(x ^ 2) - 12x = -7 - 4 = -11-4(x^2) - (8x - 12x) = -11-4(x^2) + 4x = -11-4(x^2) + 4x + 11 = 0=> get delta Δ = (-4^2) - 4*(-4 * 11) = 192
=> Δ > 0 => got 2 No
=> x1 = [tex]\frac{-4 + \sqrt{192} }{2 * -4}[/tex] = [tex]\frac{1 - 2\sqrt{3} }{2}[/tex] = -1.232
=> x2 = [tex]\frac{-4 - \sqrt{192} }{2 * -4}[/tex]=[tex]\frac{1 + 2\sqrt{3} }{2}[/tex]= 2.232
=> replace x from B into A
=> y1 = (1 - 2x) = (1 - 2 * -1.232) = 3.464
=> y2 = (1 - 2x) = (1 - 2 * 2.232) = - 3.464
X-3y=-3; ( ,4), (12, ) complete each ordered pair
Answer:
(9,4) and (12,5)
Step-by-step explanation:
x-3y=-3
y=4, x-3*4=-3, x=9. (9,4)x=12, 12-3y=-3, y=5. (12,5)Please help! Find the equation of the line (graph provided in attached picture) Use exact numbers. y =_ x+_ ( _ represent blanks in the equation)
Answer:
[tex] y = \frac{3}{4}x - 2 [/tex]
Step-by-step explanation:
Equation of a line is given as [tex] y = mx + b [/tex]
Where,
m = slope of the line = [tex] \frac{y_2 - y_1}{x_2 - x_1} [/tex]
b = y-intercept, which is the value at the point where the line intercepts the y-axis. At this point, x = 0.
Let's find m and b to derive the equation for the line.
[tex] m = \frac{y_2 - y_1}{x_2 - x_1} [/tex]
Use the coordinate pair of any two points on the line. Let's use the following,
[tex] (0, -2) = (x_1, y_1) [/tex] => on the line, when x = 0, y = -2
[tex] (4, 1) = (x_2, y_2) [/tex] => on the line, when x = 4, y = 1
Plug in the values and solve for m
[tex] m = \frac{1 - (-2)}{4 - 0} [/tex]
[tex] m = \frac{1 + 2}{4} [/tex]
[tex] m = \frac{3}{4} [/tex]
b = -2 (the line intercepts the y-axis at this point)
Our equation would be =>
[tex] y = mx + b [/tex]
[tex] y = \frac{3}{4}x + (-2) [/tex]
[tex] y = \frac{3}{4}x - 2 [/tex]
A father is three times as old as his son. After fifteen years the father will be twice as old as his son's age at that time. Hence the father's present age is
Answer:
Step-by-step explanation:
let present age of father=y
present age of son=x
then y=3x
after 15 years age of father=y+15
and age of son=x+15
∴y+15=2(x+15)
y+15=2x+30
y-2x=30-15
y-2x=15
∴3x-2x=15
x=15
y=3x=15×3=45
father's present age=45 years
(07.03. 07.04 MC)
Part A: The area of a square is (4x2 + 20x + 25) square units. Determine the length of each side of the square by factoring the area expression completely. Show
your work (5 points)
Part B: The area of a rectangle is (4x2 - 9y2) square units. Determine the dimensions of the rectangle by factoring the area expression completely. Show your work
(5 points)
Answer:
A) 4x^2+20x+25=(2x)^2+2*(2x)*5+5^2=(2x+5)^2
Area=(side)^2, side=sqrt(area)=sqrt((2x+5)^2)=2x+5
B) 4x^2-9y^2=(2x-3y)(2x+3y), these are the dimensions of the rectangle
A) The length of each side of the square is (2x + 5).
B) The dimensions of the rectangle are (2x - 3y) and (2x + 3y).
Used the concept of a quadratic equation that states,
An algebraic equation with the second degree of the variable is called a Quadratic equation.
Given that,
Part A: The area of a square is [tex](4x^2 + 20x + 25)[/tex] square units.
Part B: The area of a rectangle is [tex](4x^2 - 9y^2)[/tex] square units.
A) Now the length of each side of the square is calculated by factoring the area expression completely,
[tex](4x^2 + 20x + 25)[/tex]
[tex]4x^2 + (10 + 10)x + 25[/tex]
[tex]4x^2 + 10x + 10x + 25[/tex]
[tex]2x (x + 5) + 5(2x + 5)[/tex]
[tex](2x + 5) (2x+5)[/tex]
Hence the length of each side of the square is (2x + 5).
B) the dimensions of the rectangle are calculated by factoring the area expression completely,
[tex](4x^2 - 9y^2)[/tex]
[tex](2x)^2 - (3y)^2[/tex]
[tex](2x - 3y) (2x + 3y)[/tex]
Therefore, the dimensions of the rectangle are (2x - 3y) and (2x + 3y).
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1. A tank is 3/5 full of water. After 330 litres of water is drawn out, it becomes 2/7 full. Find the capacity of the tank in litres.
Answer:
1050
Step-by-step explanation:
Let x = full capacity
[tex]\frac{3}{5} x=\frac{2}{7} x+330[/tex]
Move the variable to the left side by subtracting both sides by [tex]\frac{2}{7} x[/tex]
[tex]\frac{3}{5} x-\frac{2}{7}x=\frac{2}{7} x+330 -\frac{2}{7}x[/tex]
[tex]\frac{3}{5} x-\frac{2}{7} x=330[/tex]
Combine the like terms (don't forget about common denominator)
[tex]\frac{21}{35} x-\frac{10}{35} x=330[/tex]
[tex]\frac{11}{35} x=330[/tex]
Multiply both sides by [tex]\frac{35}{11}[/tex] to isolate the x
[tex](\frac{35}{11})\frac{11}{35} x=330(\frac{35}{11})[/tex]
[tex]x = 1050[/tex]
A sports stadium has a capacity of 42,000. On a
particular night, 35,000 spectators attend an event. At
the end of the event, spectators leave the stadium at a rate
of 320 spectators every minute. If m represents the
number of minutes after spectators begin to leave the
stadium, which of the following inequalities describes
the times when there are still spectators in the stadium?
A) 42,000 - 35,000m < 320
B) 35,000 - 320m > 0
C) 35,000 + 320m < 42,000
D) 320m < 87,000
Answer:
B
Step-by-step explanation:
The inequality will be 35000-320m>0
find the surface area of the prism
Answer:
Base area=5*12=60
Height is 4
Perimeter or the base is 2*(12+5)=34
Surface area is 2B+Ph=120+136=256
The times to complete an obstacle course is normally distributed with mean 87 seconds and standard deviation 7 seconds. What is the probability that a randomly selected finishing time is greater than 80 seconds? Use the empirical rule
The probability that a randomly selected finishing time is greater than 80 seconds is 0.84.
How to calculate the probability?Mean = 87
Standard deviation = 7
We convert this to standard normal as
P( X < x) = P( Z < x - Mean / SD)
Since, 80 = 87 - 7
80 is one standard deviation below the mean.
Using the empirical rule, about 68% of data falls between 1 standard deviation of the mean. So, 32% is outside the 1 standard deviation of the mean, and 16% is outside to either side.
We have to calculate P( X > 80) = ?
That is probability of all values excluding lower tail of the distribution.
P(X > 80) = 68% + 16%
= 84%
= 0.84
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