add the different of 9/16 and 5/4

Answers

Answer 1

Adding the difference between [tex]$\frac{9}{16}[/tex] and [tex]$\frac{5}{4}[/tex] we get [tex]$1 \frac{13}{16}[/tex].

How to estimate the sum of 9/16 and 5/4?

Find the least common denominator or LCM of the two denominators:

LCM of 4 and 16 exist 16.

Subsequently, estimate the equivalent fraction of both fractional numbers with denominator 16.

For the 1st fraction, since 16 × 1 = 16,

9/16 = (9 × 1) / (16 × 1) = 9/16

For the 2nd fraction, since 4 × 4 = 16,

5/4 = (5 × 4) / (4 × 4) = 20/16

Add the two like fractions, then we get

(20/16) + (9/16) = (20 + 9)/16 = 29/16

So, [tex]$\frac{5}{4}+\frac{9}{16} =\frac{29}{16}[/tex]

In mixed form: [tex]$1 \frac{13}{16}[/tex].

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Related Questions

The graph of f(x) = x3 + x2 – 9x – 9 is shown.


Based on the graph, what are the solutions of x3 + x2 – 9x – 9 = 0?

x = –1, 3
x = –3, –1
x = –3, –1, 3
x = –9, –3, –1, 3

Answers

Answer:

the third option, x = –3, –1, 3

Step-by-step explanation:

If (x, 68, 85) form a Pythagorean Triple, what is the value of x?

Answers

Answer:

x = 51

Step-by-step explanation:

If (x, 68, 85) form a Pythagorean Triple, what is the value of x?

to solve we again use Pythagoras, x is the smallest number, so 68 is a cathetus and 85 the hypotenuse

x = √(85²- 68²)

x = (7225 - 4624)

x = √2601

x = 51

Answer:

  x = 51

Step-by-step explanation:

The missing value of the Pythagorean triple can be found using the Pythagorean theorem, or it can be found by comparing the values in the triple to known triples.

What are Pythagorean triples?

A Pythagorean triple is a set of integers {a, b, c} that satisfy the equation of the Pythagorean theorem:

  a² +b² = c²

The smallest such triple is {3, 4, 5}. It is also the only triple that is an arithmetic sequence. Other triples of small integers are ...

  {5, 12, 13}, {7, 24, 25}, {8, 15, 17}

There are an infinite number of "primitive" Pythagorean triples, ones that are not multiples of another triple.

What is this triple?

The given values of the triple have the ratio ...

  68/85 = (4·17)/(5·17) = 4/5

Only the values in the {3, 4, 5} triple and its multiples will have this ratio.

The value of x is 3·17 = 51, so the triple is {51, 68, 85}.

  x = 51

__

Additional comments

Any primitive triple will have two odd numbers.

The ratios of numbers in a primitive triple are unique to that triple. That is, the numbers are mutually prime.

For any pair of positive integers m > n, there is a Pythagorean triple {2mn, m²-n², m²+n²}. Such triples will not be primitive if m and n have the same parity.

__

The above triple can be verified using the Pythagorean theorem:

  51² +68² = 2601 +4624 = 7225 = 85²

Which is true regarding the system of equations?

6 x + 2 y = 46. 3 x + y = 23.
The system results in a false statement.
The system results in an intersection at one point.
The system results in parallel lines.
The system results in a true statement because they are the same line.

Answers

Answer:

they are the same line

Step-by-step explanation:

if you divide the first line by 2 you'll get:

2(3x)+2y=2(23)===> 3x+y=23

"The Survey of Study Habits and Attitudes (SSHA) is a psychological test that measures the motivation, attitude toward school, and study habits of students. Scores range from 0 to 200, with 200 being the highest level of motivation. The mean score for U.S. college students is about 115, and the standard deviation is about 30. A teacher who suspects that older students have better attitudes toward school gives the SSHA to 30 students who are at least 29 years of age, and their mean was 135.2"

Calculate the observed test statistic (Zobt or Tobt) for hypothesis test. Round up to the second decimal place.

Answers

Using the z-distribution, the observed test statistic is given as follows:

z = 3.69.

What are the hypothesis tested?

At the null hypothesis, it is tested if older students have the same mean as the general population, that is:

[tex]H_0: \mu = 115[/tex]

At the alternative hypothesis, it is tested if they have a greater mean, that is:

[tex]H_0: \mu > 115[/tex]

What is the test statistic?

The test statistic is:

[tex]z = \frac{\overline{x} - \mu}{\frac{\sigma}{\sqrt{n}}}[/tex]

In which:

[tex]\overline{x}[/tex] is the sample mean.[tex]\mu[/tex] is the value tested at the null hypothesis.[tex]\sigma[/tex] is the standard deviation of the population.n is the sample size.

For this problem, the parameters are:

[tex]\overline{x} = 135.2, \mu = 115, \sigma = 30, n = 30[/tex]

Hence the test statistic is:

[tex]z = \frac{\overline{x} - \mu}{\frac{\sigma}{\sqrt{n}}}[/tex]

[tex]z = \frac{135.2 - 115}{\frac{30}{\sqrt{30}}}[/tex]

z = 3.69.

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Which of the following similarity statements about the triangles in the figure is true?

Right triangle P Q R has angle Q marked as a right angle. A segment is drawn from point Q to side P R. The point where the segment intersects side PR is point S. Angle P S Q is marked as a right angle.

A. Triangle P Q R is similar to triangle P S Q, which is similar to triangle Q S R.
B. Triangle R Q P is similar to triangle S Q P, which is similar to triangle R S Q.
C. Triangle Q R P is similar to triangle Q S P, which is similar to triangle Q S R.
D. Triangle P R Q is similar to triangle Q P S, which is similar to triangle R Q S.

Answers

Answer:

Answer B is correct

A. Reflection around the x-axis:
1. A (5, 1)→ A'
2. B (1, 3) B¹.
3. C (-2, 2)→ C'.
4. D (-5, 4) D'
B. Reflection around the y-axis:
1. A (5, 1)→ A'
2. B (1, 3) B¹.
3. C (-2, 2)→ C'_
4. D (-5, 4) D'

Answers

Part A

1) (5, -1)

2) (1, -3)

3) (-2, -2)

4) (-5, -4)

Part B

1) (-5, 1)

2) (-1, 3)

3) (2, 2)

4) (5, 4)

Translate to a proportion and solve.
148.5 is 59 1/5% of​ what?

Answers

The actual value is 250.

Applying simple percentage formula here,

let x be the whole value

x=148.5/ 59 2/5%

x= 148.5/0.594

x=250.

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The actual value is 250.

Applying percentage formula here,

let x be the value:

x=148.5/ 59 2/5%

x= 148.5/0.594

x=250

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Please answer the questions below.

Answers

The volumes of the right prisms are listed below:

1 / 9 ft³39 / 512 in³7 / 384 cm³1 / 12 cm³3 / 25 m³3 / 8 yd³What is the volume of the prisms?

In this problem we have six cases of right prisms with rectangular bases, the volume of right prisms (V), in cubic length units, is equal to the product of the area of the base (A), in square length units, and the height (h), in length units. The equation of the volume of the right prism is shown below:

V = w · l · h     (1)

Where:

w - Width of the base, in length units.l - Length of the base, in length units.h - Height of the prism, in length units.

Now we proceed to calculate each volume:

Prism 1 (w = 2 / 3 ft, l = 1 / 3 ft, h = 1 / 2 ft)

V = (2 / 3 ft) · (1 / 3 ft) · (1 / 2 ft)

V = 1 / 9 ft³

Prism 2 (w = 1 / 8 in, l = 3 / 4 in, h = 13 / 16 in)

V = (1 / 8 in) · (3 / 4 in) · (13 / 16 in)

V = 39 / 512 in ³

Prism 3 (w = 7 / 8 cm, l = 1 / 4 cm, h = 1 / 12 cm)

V = (7 / 8 cm) · (1 / 4 cm) · (1 / 12 cm)

V = 7 / 384 cm³

Prism 4 (w = 1 / 7 cm, l = 7 / 8 cm, h = 2 / 3 cm)

V = (1 / 7 cm) · (7 / 8 cm) · (2 / 3 cm)

V = 1 / 12 cm³

Prism 5 (w = 9 / 10 m, l = 2 / 3 m, h = 1 / 5 m)

V = (9 / 10 m) · (2 / 3 m) · (1 / 5 m)

V = 3 / 25 m³

Prism 6 (w = 7 / 8 yd, l = 6 / 7 yd, h = 1 / 2 yd)

V = (7 / 8 yd) · (6 / 7 yd) · (1 / 2 yd)

V = 3 / 8 yd³

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A tape manufacturer reduces the price of its Heavy Duty tape from $40 to $38 a reel and the price of Regular tape from $32 to $31 a reel. A computing center normally spends $1600 a month for tapes and 3/5 of this is for Heavy Duty tapes. How much will they save a month under the new prices?

Answers

Answer:

68

Step-by-step explanation:

Lets first find the quantity of tape the computing center is purchasing/month.

3/5 Of their 1600 dollar spending is on the heavy duty tapes, meaning they are spending 960 dollars/month on heavy duty tape, if we divide that by the original price, 40, it will give us the original quantity of heavy tape they are purchasing, 24/month.

The other 2/5 of their money, 640 dollars, are spent on regular tape, meaning they purchase 20 rolls of regular tape/month.

Given they are purchasing 24 rolls of heavy tape and 20 rolls of regular tape every month, we can simply multiple those by the new prices and sum the results.

24*38=912

20*31=620

912+620=1532

Then to find the money they are saving we subtract the new price from the original price.

1600-1532=68

Find the slope and​ y-intercept of the line whose equation is y=6x=5

Answers

Answer:

the slope is 5 and the y intercept is 5

Step-by-step explanation:

I think that you meant to write y = 6x + 5.

y = mx + b

The number in in the m spot is the slope and the number in the b spot is the y intercept.

Primer numbers list maths

Answers

Answer:

1 - 100 primes numbers

Step-by-step explanation:

2,3,5,7,11,13,17,19,23,29,31,37,41,47,57,59,61,67,71,79,83,8797

The transformation from parallelogram LMNO to parallelogram L'M'N'O' was carried out as shown in the coordinate plane below.

Answers

The transformation from parallelogram LMNO to parallelogram L'M'N'O' is a reflection across the x-axis

How to determine the transformation?

The complete question is added as an attachment

From the graph, we have the following highlights:

Parallelogram LMNO and parallelogram L'M'N'O' are on either sides of the x-axisThey are equidistant from the x and y axesThey have equal dimensions

This means that parallelogram LMNO is reflected across the x-axis to get parallelogram L'M'N'O'

Hence, the transformation from parallelogram LMNO to parallelogram L'M'N'O' is a reflection across the x-axis

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If the function is:

What is f(-4)?

Answers

Answer:

D.  -11

Step-by-step explanation:

Piecewise functions have multiple pieces of curves/lines where each piece corresponds to its definition over an interval.

Given piecewise function:

[tex]f(x)=\begin{cases}2x-3 & \textsf{if }x \leq -4\\x^2 & \textsf{if }-4 < x < 0\\x+5 & \textsf{if }x \geq 0\end{cases}[/tex]

Therefore, the function has three definitions:

[tex]f(x)=2x-3 \quad \textsf{ when x is equal to or less than -4}[/tex]

[tex]f(x)=x^2 \quad \textsf{ when x is greater than -4 or less than zero}[/tex]

[tex]f(x)=x+5 \quad \textsf{ when x is greater than zero}[/tex]

f(-4) means to substitute x = -4 into the function.

As x = -4 satisfies the interval of the first piece of the function, substitute x = -4 into f(x) = 2x - 3:

[tex]\begin{aligned}\implies f(-4) & =2(-4)-3\\& = -8 -3\\& = -11\end{aligned}[/tex]

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Answer is D. -11

Answer:

Solution Given:

f(-4) depends on the condition x≤-4,

so

f(-4)=2*-4-3=-8-3=-11

Let a and b be real numbers where a b 0. Which of the following functions could represent the graph below?

Answers

A function which could represent the graph is: C. f(x) = x⁴(x - a)(x - b)².

How to interpret the graph?

The nature of the intercept on a polynomial graph highlights the nature of its multiplicity. Also, the polynomial graph has no single zero (factor) but bounced off the x-axis at three (3) different locations.

This ultimately implies that the polynomial graph has an even multiplicity at these three (3) points:

x⁴

x - a

(x - b)²

In conclusion, a function which could represent the graph is f(x) = x⁴(x - a)(x - b)².

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do you have a picture of what the graph would look like?

Answers

The attached graph represents the piecewise function.

How to determine the graph of the equation?

The piecewise function is given as:

f(x) = 3x - 5, x ≤ -1

      = -2x + 3, -1 < x < 4

      = 2, x ≥ 4

To plot the graph, we simply plot the equations together with their domains

i.e.

3x - 5 with the domain of x ≤ -1,  -2x + 3 with the domain of -1 < x < 4 and 2 with the domain of x ≥ 4

See attachment for the graph of the function

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Which expression is equivalent to
xay
8
700
8√√√x
y
8√√y
Mark this and return
128x56
√ 2x75
? Assume x > 0 and y> 0.
Save and Exit

Answers

The equivalent expression of [tex]\sqrt{\frac{128x^5y^6}{2x^7y^5}}[/tex] is [tex]\frac{8\sqrt y}{x}[/tex]

How to determine the equivalent expression?

The expression is given as:

[tex]\sqrt{\frac{128x^5y^6}{2x^7y^5}}[/tex]

Divide 128 by 2

[tex]\sqrt{\frac{64x^5y^6}{x^7y^5}}[/tex]

Apply the law of indices to the variables

[tex]\sqrt{\frac{64y^{6-5}}{x^{7-5}}}[/tex]

Evaluate the differences

[tex]\sqrt{\frac{64y}{x^2}}[/tex]

Take the square root of 64

[tex]8\sqrt{\frac{y}{x^2}}[/tex]

Take the square root of x^2

[tex]\frac{8\sqrt y}{x}[/tex]

Hence, the equivalent expression of [tex]\sqrt{\frac{128x^5y^6}{2x^7y^5}}[/tex] is [tex]\frac{8\sqrt y}{x}[/tex]

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please help I've been trying to figure it out but I can't​

Answers

answer : 2 1/2

divide y by x

divide  2 1/2 by 1

its 2 1/2

10 divided by 4 is also

2 1/2

17 1/2 divided by 7 is also

2 1/2

3. A rare species of aquatic insect was discovered in the Amazon rainforest. To protect the species, environmentalists declared the insect endangered and transplanted the insect to protected area. The population P(t) (in thousands) of insects in t months after being transplanted is

a. [3 pts] Determine the number of months until the insect population reaches 40 thousand (round to 2 decimal places).

b. [3 pts] What is the limiting factor on the insect population as time progresses? Explain your answer.

c. [3 pts] Sketch a graph of the function using the window and. Be sure to indicated the scale on the graph, label the axes, at least 2 points on the graph, and any asymptotes.​

Answers

The number of months until the insect population reaches 40 thousand is 14.29 months and the limiting factor on the insect population as time progresses is 250 thousands.

Given that population P(t) (in thousands) of insects in t months after being transplanted is P(t)=(50(1+0.05t))/(2+0.01t).

(a) Firstly, we will find the number of months until the insect population reaches 40 thousand by equating the given population expression with 40, we get

P(t)=40

(50(1+0.05t))/(2+0.01t)=40

Cross multiply both sides, we get

50(1+0.05t)=40(2+0.01t)

Apply the distributive property a(b+c)=ab+ac, we get

50+2.5t=80+0.4t

Subtract 0.4t and 50 from both sides, we get

50+2.5t-0.4t-50=80+0.4t-0.4t-50

2.1t=30

Divide both sides with 2.1, we get

t=14.29 months

(b) Now, we will find the limiting factor on the insect population as time progresses by taking limit on both sides with t→∞, we get

[tex]\begin{aligned}\lim_{t \rightarrow \infty}P(t)&=\lim_{t \rightarrow \infty}\frac{50(1+0.05t)}{2+0.01t}\\ &=\lim_{t \rightarrow \infty}\frac{50(\frac{1}{t}+0.05)}{\frac{2}{t}+0.01}\\ &=50\times \frac{0.05}{0.01}\\ &=250\end[/tex]

(c) Further, we will sketch the graph of the function using the window 0≤t≤700 and 0≤p(t)≤700 as shown in the figure.

Hence, when the population P(t) (in thousands) of insects in t months after being transplanted by P(t)=(50(1+0.05t))/(2+0.01t) then the number of months until the insect population reaches 40 thousand 14.29 months and the limiting factor on the insect population is 250 thousand and the graph is shown in the figure.

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Please help ASAP
What of the secants below is a secant?

Answers

The secant in the diagram is [tex]\overline{AD}[/tex]

Segment AD intersect the circle at two points. So it can be a secant.

We have been given that a circle of center O. We have to find the segment that is secant.

What is Secant?

Secant : If a line which intersect the circle at two points.Then the line segment  is called  secant.

If the ray lies onto the considered line segment(overlapping), then it can be said belonging to the considered line segment.

(line segment has 2 fixed ends, whereas a ray has one end only, other end is not fixed)

Segment OB intersect the circle at one point B only. so OB cannot be a Secant.

Segment AD intersect the circle at two points. So it can be a secant.

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A recent tax bill proposed raising the income-tax rate on families earning at least $200,000 a year by 25%, to 25%. What was the previous tax rate ?

Answers

The previous tax rate was 20%

What is tax rate?

Tax rate is the percentage of the earnings tax payers would pay to the government from their earnings as taxes.

It should be borne in mind that the new tax rate is 25% which has increased by 25% compared to the previous tax rate, which is the unknown.

The mathematical relationship between the current and prior tax rates is as shown below:

Current tax rate=previous tax rate*(1+% increase in tax rate)

Current tax rate=25%

previous tax rate=X

% increase in tax rate=25%

25%=X*(1+25%)

25%=X*1.25

X=25%/1.25

X=previous tax rate=20%

Technically speaking, an increase of 25% in 20% is 5%(i.e. 20%*25%=5%), which when added to the original 20% would give a tax rate of 25%.That the shortcut to affirming that the new tax rate of 25% is correct

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f r(x) = 3x – 1 and s(x) = 2x + 1, which expression is equivalent to (StartFraction r Over s EndFraction) (6)?

Answers

The equivalent expression to [tex]\mathbf{(\dfrac{r}{s})(6)= \dfrac{17}{13}}[/tex]

What are the equivalent expressions?

Equivalent expressions are similar expressions that may have different forms but when a value is replaced with the variables in the same form provides the same answer.

From the information given, If:

r(x) = 3x - 1s(x) = 2x + 1

Then the fractional form can be an expression as:

[tex]\mathbf{(\dfrac{r}{s})(x)= \dfrac{3x-1}{2x+1}}[/tex]

where;

x = 6

[tex]\mathbf{(\dfrac{r}{s})(6)= \dfrac{3(6)-1}{2(6)+1}}[/tex]

[tex]\mathbf{(\dfrac{r}{s})(6)= \dfrac{18-1}{12+1}}[/tex]

[tex]\mathbf{(\dfrac{r}{s})(6)= \dfrac{17}{13}}[/tex]

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Polygon ABCD is rotated 90º counterclockwise about the origin to create polygon A′B′C′D′. Match each set of coordinates to the vertices of polygon A′B′C′D′. (-1, 3)
B′
(-2, 2)
C′
(-2, 1)
D′
(-1, 1)

Answers

Answer:Rules for rotating points about the origin

1. The point (a,b) rotated 90° counterclockwise about the origin

becomes (-b,a).

A′ (-1, 3) B′ (-2, 2) C′ (-2, 1) D′ (-1, 1)

A (a,b)-----------------A′ (-b,a)=(-1, 3)----------->A( 3,1)

B (a,b)-----------------B′ (-b,a)=(-2, 2)----------->B( 2,2)

C (a,b)-----------------C′ (-b,a)=(-2, 1)----------->C( 1,2)

D (a,b)-----------------D′ (-b,a)=(-1, 1)----------->D( 1,1)

Step-by-step explanation:

find p + q

someone pls help

Answers

Answer:

70

Step-by-step explanation:

45+90=135

180-45=45

q=45

45+65=110

180-110=70

70-45=25

p=25

45+25=70

Answer: 70°

Step-by-step explanation:

We know that the sum of all 3 angles in a triangle is 180°. Hence, we can just set all measures to be equal to 180° and solve for the variables.

Left Triangle

[tex]p+65+90=180\\p+155=180\\p=25[/tex]

Right Triangle

[tex]45+90+q=180\\135+q=180\\q=45[/tex]

Sum

[tex]p+q=25+45=70[/tex]

The sum of p and q is 70°.

Graph the following inequality. y ≤ 3x +5 Use the graphing tool to graph the inequality Click to enlarge graph​

Answers

Please see the graph below

I can't find the answer for 46.3 divided by 1.5 Help!

Answers

46.3/1.5 = 30.87 or 1.5/46.3 = 0.034
Is that what your looking for??

The solution to the problem when [tex]46.3[/tex] divided by [tex]1.5[/tex]  the result of the division is [tex]30.8666667[/tex] in decimal form.

When a large number is distributed into small numbers of equal parts is called division.

The number [tex]1.5[/tex] is not a factor of [tex]46.3[/tex] ,  on dividing them the remainder is not zero.

Therefore,  first convert [tex]1.5[/tex] it into a whole number by multiplying it  [tex]10[/tex] so it becomes [tex]15[/tex] .

Then convert [tex]46.3[/tex]  it into a whole number by multiplying it by [tex]10[/tex] so it becomes [tex]463[/tex]

Here,  [tex]\dfrac{463 \times 10}{15 \times 10}[/tex] which results in [tex]\dfrac{463}{15}[/tex].

Now, divide [tex]\dfrac{463}{15}[/tex] ,  the result will be [tex]30.8666667[/tex].

The solution to the problem when [tex]46.3[/tex] divided by  [tex]1.5[/tex] the result is [tex]30.8666667[/tex].

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WHAT TWO EQAUL NUMBERS ADD TO THE EVEN NUMER 40

Answers

Answer:

20

Step-by-step explanation:

20+20=40

The final result after substituting a value into an equation is the output.
A. true
B. false

Answers

The question is true
the answer is true also letter “a”

Sets A,B , and C are subsets of the universal set U.

These sets are defined as follows.

U= {f,g,h,p.q.r.x.y.z}

A={f,h,p.q.r}

B={q,r,y,z}

C={g,h,p,q,y}


Find (B' U A) ∩ C.

Write your answer in roster form or as Ø.

Answers

[tex]B'=\{f,g,h,p,x\}\\B'\cup A=\{f,g,h,p,q,r,x\}\\(B'\cup A)\cap C=\{g,h,p,q\}[/tex]

Which is the statement is true about f(x)=-2/3|x+4|-6

Answers

Answer: The graph of f(x) is horizontally stretched

By eating 1​ egg, 1​ cupcake, and 1 slice of​ pizza, a child consumes 303 mg of cholesterol. If the child eats 3 cupcakes and 4 slices of​ pizza, he or she takes in 90 mg of cholesterol. By eating 2 eggs and 1​ cupcake, a child consumes 570 mg of cholesterol. How much cholesterol is in each​ item?

Answers

Using a system of equations, the amounts of cholesterol in each item are given as follows:

Egg: 278 mg.Cupcake: 14 mg.Slice of pizza: 11 mg.

What is a system of equations?

A system of equations is when two or more variables are related, and equations are built to find the values of each variable.

The variables for this problem are given as follows:

Variable x: Amount of cholesterol in an egg.Variable y: Amount of cholesterol in a cupcake.Variable z: Amount of cholesterol in a slice of pizza.

By eating 1​ egg, 1​ cupcake, and 1 slice of​ pizza, a child consumes 303 mg of cholesterol, hence:

x + y + z = 303.

3 cupcakes and 4 slices of​ pizza, he or she takes in 90 mg of cholesterol, hence:

3y + 4z = 90

y + 1.33z = 30.

By eating 2 eggs and 1​ cupcake, a child consumes 570 mg of cholesterol, hence:

2x + y = 570.

Then, writing y and z as functions of x:

y = 570 - 2x.z = (30 - y)/1.33 = (30 - 570 + 2x)/1.33 = 1.5x - 406.

Then, replacing on the first equation:

x + y + z = 303.

x + 570 - 2x + 1.5x - 406 = 303.

0.5x + 164 = 303.

x = (303 - 164)/0.5

x = 278.

The amounts for the cupcake and the slice of pizza are given as follows:

y = 570 - 2(278) = 14 mg.z = 1.5x - 406 = 1.5(278) - 406 = 11 mg.

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