aldehydes plus potassium permanganate with explanation
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Answer: improvements in nutrition

Explanation:

Answer:Look at the graph above. Human population increased dramatically at certain times. The graph begins 10,000 BC, although you can't really see the line. Population starts to rise perceptibly at around 1800 BC. The numbers begin to rise dramatically about 200 years ago. What causes these changes

Explanation:

Answer:

A.

Explanation:

because it is the only logical answer

Based on the bond length, the molecular weight of the unknown metal X is 23.

Ionic compounds are compounds which are formed between oppositely charged ions.

When hydrogen combines with the group 1 metals, they form ionic compounds.

The group one metals that combine with hydrogen to firm ionic bonds include:

The molecular weight of lithium is 7 g

The molecularweight of sodium is 23

The molecular weight of Potassium is 39.

Therefore, based on the equilibrium bond length, the molecular weight of the unknown metal X is 23.

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The standard for chromium VI in a sample is 0.1 milligrams per liter (mg/l) or 100 parts per billion (ppb).

EPA is an acronym that stands for Environmental Protection Agency. The major concern of the agency is to ensure that the level of contaminants released into the environment does not exceed the set standards.

The standard for chromium VI in a sample is 0.1 milligrams per liter (mg/l) or 100 parts per billion (ppb), Since the question is incomplete, we can't ascertain if the chromium (VI) concentration exceeds this standard.

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Look at the reaction

More than 1mol of HC2H3O2 is required so the mols will be doubled atleast

Now

NaHCO_3 is less

In the given query, the limiting reagent in provided chemical reaction is: [tex]\rm NaHCO_3(s) + HC_2H_3O_2(aq) \rightarrow C_2H_3O_2Na(aq) +H_2CO_3(aq)+ H_2O(l) +CO_2(g)[/tex] is [tex]\rm HC_2H_3O_2[/tex].

In a reaction, limiting reagent is a chemical substance that is completed used or is totally consumed resulting into limiting the formation of further products.

In the provided reaction:

[tex]\rm NaHCO_3(s) + HC_2H_3O_2(aq) \rightarrow C_2H_3O_2Na(aq) +H_2CO_3(aq)+ H_2O(l) +CO_2(g)[/tex]

Given: 0.00516 mol [tex]\rm HC_2H_3O_2[/tex] and 0.00585 mol [tex]\rm NaHCO_3[/tex].

Using balanced equation, the stoichiometric ratio of  [tex]\rm HC_2H_3O_2[/tex] to  [tex]\rm NaHCO_3[/tex] is 1:1. Meaning that, for every 1 mole of  [tex]\rm HC_2H_3O_2[/tex], we need 1 mole of  [tex]\rm NaHCO_3[/tex].

Therefore, the number of moles of  [tex]\rm NaHCO_3[/tex] needed to react with 0.00516 mol of  [tex]\rm HC_2H_3O_2[/tex] is:

0.00516 mol  [tex]\rm HC_2H_3O_2[/tex] × (1 mol  [tex]\rm NaHCO_3[/tex]/ 1 mol  [tex]\rm HC_2H_3O_2[/tex])

= 0.00516 mol [tex]\rm NaHCO_3[/tex].

Since we have 0.00585 mol of [tex]\rm NaHCO_3[/tex], which is greater than the amount needed (0.00516 mol), [tex]\rm NaHCO_3[/tex] is not the limiting reactant.

Calculate the number of moles of [tex]\rm HC_2H_3O_2[/tex]needed to react with 0.00585 mol of [tex]\rm NaHCO_3[/tex]:

0.00585 mol [tex]\rm NaHCO_3[/tex] × (1 mol [tex]\rm HC_2H_3O_2[/tex]/ 1 mol  [tex]\rm NaHCO_3[/tex]) = 0.00585 mol  [tex]\rm HC_2H_3O_2[/tex]

As we see, only 0.00516 mol of  [tex]\rm HC_2H_3O_2[/tex] are present, which is less than the amount needed (0.00585 mol),  [tex]\rm HC_2H_3O_2[/tex] is the limiting reactant.

Therefore,  [tex]\rm HC_2H_3O_2[/tex]is the limiting reactant in the provided chemical reaction.

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Answer:

An exothermic process releases heat, causing the temperature of the immediate surroundings to rise. An endothermic process absorbs heat and cools the surroundings.”

Explanation:

hope this helps

i did this for hw

With a Ksp of 4.30*10−11 and a molar mass of 274 g / mol the solubility (in g / L) of the generic salt is mathematically given as

S=0.0604g/l

Generally, the Ksp   is mathematically given as

Ksp=4s^3

Therefore

s=(\frac{4.30 × 10−11}{4})^{1/3}

s=2.207×10^{−4]

In conclusion, solubility is

S=2.207×10^{−4]*274

S=0.0604g/l

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It means to not favor either side of an argument, even if you believe one side may be right.

Answer:

3

Explanation:

Important concept! The little number after an element represents the number of atoms in the substance. Eg. SF6. The 6 after the F tell us that there are 6 atoms of Fluorine in SF6. The coefficient or big number before a substance tells us how many of that substance there is in the equation. TO find the number of atoms in a substance with a coefficient we simply multiply the coefficient by the subscript or small number. Eg. 4SF6. The number of fluorine atoms in 4SF6 can be found my multiplying 4 and 6. 4 * 6 = 24 so there are 24 atoms of fluorine in 4SF6

Balancing the equation!

First lets list the number of atoms of each element on each side so we can see what we need to balance

SF6 + SO3 --> O2SF2

               2  S   1

               6  F  2

               3  O  2

First lets balance the number of oxygen atoms. We can do this by adding a coefficient of 2 to SO3 and a 3 to O2SF2. After doing so lets count the number of atoms of each element again as some of them may have changed.

SF6 + 2SO3 --> 3O2SF2

                3  S   3

                6  F  6

                6  O  6                

It appears that the each element in the reaction is now balanced after adding a 2 to SO3 and a 3 to O2SF2 so the equation is now balanced.

The answer would be 3 as 3 was added to O2SF2 to balance the reaction.

Answer:

i think the answer is 12.0

Answer:

Any device that contains electronic parts

Answer:

the difference between model A and model B is the fact that model A has more atoms in it, and they are smaller and all the same type while model B has less atoms, they are bigger and there are different types of atoms.

Explanation:

mr clean

Answer: 163.6g H2O

Explanation:

The balanced chemical equation for the combustion of propane is:

C3H8(g) + 5O2(g) → 3CO2(g) + 4H2O(g)

This means 1 molecule of C3H8 react with 5 molecules of O2 to produce 3 molecules of CO2 and 4 molecules of H2O.

Molar mass C3H8 = 44 g/mol
According to the stochiometric coefficients 1 mol C3H8 will form 4H2O

100g C3H8 to mol = 100 g / 44 g/mol = 2.273 mol
This will produce 2.273*4 H2O = 9.09 mol H2O

Molar mass H2O = 18 g/mol
Mass of 9.09 mol H2O = 9.09 mol * 18 g/mol = 163.6 g H2O

Therefore, 163.6g of H2O will be formed from the combustion of 100g of C3H8

heat water 1 = heat water 2

mass of water = density x volume

because density = 1 g/ml then:

mass water 1 = 100 g

mass water 2= 390 g

Input the equation:

mcΔt 1 = mcΔt 2

100 . c . (95 - T) = 390 . c . (T - 25)

9500 - 100T = 390T - 9750

9500+9750 = 390T+100T

19250=490T

T=39.29 °C

Explanation 2Al2O3(s)-->4Al(s)+302(g)What is the total number of moles of O2 that are produced when 8.0 mol of Al2O3(s)are totally decomposed ? 

The energy in a single Carbon - Hydrogen (C-H) bond of methane is 413 kJ

From the question, we are to determine the Carbon - Hydrogen bond energy in methane

From the given information,

The total bond energy in a molecule of methane is 1652 kJ

C-H bond energy = [tex]\frac{Total\ bond\ energy\ in\ methane}{number\ of \ C-H \ bonds}[/tex]

Number of C-H bonds in methane = 4

Therefore,

C-H bond energy = [tex]\frac{1652}{4}[/tex]

C-H bond energy = 413 kJ

Hence, the energy in a single Carbon - Hydrogen (C-H) bond of methane is 413 kJ

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Answer:

0.2553669915026199 BaSO4

Explanation:

hi, give brainliest?

Answer:

get it back to me by tomorrow

Explanation:

I am currently in life generally but will be perfect

Answer:

As Per Given Information

Number of moles SO₂ ( Sulphur dioxide ) is 0.30

We 've been asked to find the number of atoms in given moles of Sulphur dioxide .

Value of Avogadro Number is 6.022 × 10²³ mol⁻¹

For finding the number of atoms we will use formale

[tex]\underline{\boxed{\textbf{\textsf{ Number \: of \: atoms \: = Given \: moles \: . Avogadro \: number}}}}[/tex]

Putting the given value we obtain

[tex] \sf \twoheadrightarrow \: Number \: of \: atoms \: = 0.30 \times 6.022 \times {10}^{ 23} \\ \\ \sf \twoheadrightarrow \: Number \: of \: atoms \: = \: 1.8066 \times {10}^{ 23} atoms[/tex]

So, the number of atoms in sulphur dioxide is 1.8066 × 10²³

No of atoms

The molar mass of the element M is mathematically given as

M=91.927g/mol

Question Parameters:

A 35.3 g of element M is reacted with nitrogen to produce 43.5 g of compound M3N2.

Generally, the equation for the Chemical Reaction  is mathematically given as

3M+N2=M3N2

Therefore

moles of N2 is given as

[tex]m=\frac{mass of N2}{molar mass}[/tex]

Where

mass of N2=43.5-35.3

mass of N2=8.2

Therefore

[tex]m=\frac{8.2}{32}[/tex]

m=0.25625mole

Since 2 moles of N2 reacts with 3mols of M

Hence, 0.25625 mole of N2 reacts with 3mole of M

x=3/2*0.256

x=0.384mol

In conclusion, the molar mass of M

[tex]M=\frac{mass of x}{moles of x}\\\\M=\frac{35.3}{0.384}[/tex]

M=91.927g/mol

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The measure of the sum of the interior angles of a convex polygon with n sides is given by [tex]S=(n-2)180[/tex]

A polygon can be defined as a two-dimensional geometric figure that consists of straight line segments and finite number of sides.

A quadrilateral can be defined as a type of polygon that is made up of four (4) sides, four (4) vertices, four (4) edges and four (4) angles.

Mathematically, the measure of the sum of the interior angles of a convex polygon with n sides is given by:

[tex]S=(n-2)180[/tex]

In Geometry, the measure of the sum of the angles of a convex quadrilateral, pentagon, and a nonagon is equal to 360 degrees.

For a regular polygon:

Mathematically, the measure of an interior angle with n sides is given by;

[tex]A=(2n-4)90[/tex]

For a regular octagon:

Mathematically, the measure of an interior angle is equal to 135 degrees.

Lastly, the sum of the measure of the exterior angles, one at each vertex of a convex polygon is equal to 360 degrees.

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[tex]\Large \text{1)}[/tex]

[tex]\textbf{Use the formula and substitute the values}[/tex]

[tex]\displaystyle 0.3\ mol/L = \frac{n \ mol}{10 \times 10^{-3}\ L}[/tex]

[tex]\textbf{Solve for the number of moles}[/tex]

[tex]n = 0.003\ mol[/tex]

[tex]\textbf{Calculate final volume }[/tex]

[tex]40+10=50\ mL[/tex]

[tex]\textbf{Number of moles remains same. Solve for concentration}[/tex]

[tex]\displaystyle C=\frac{0.003\ mol}{50 \times 10^{-3}\ L} =0.06\ mol/L[/tex]

[tex]\Large \text{2)}[/tex]

[tex]\displaystyle DF=\frac{V_f}{V_i}[/tex]

[tex]\displaystyle DF=\frac{50}{10}=5[/tex]

Answer:

Balanced reaction:

3 H2 (g)  + N2 (g)  → 2 NH3 (g)

Use stoichiometry to convert g of H2 to g of NH3.  The process would be:

g H2 → mol H2 → mol NH3 → g NH3

12.0 g H2 x (1 mol H2 / 2.02 g H2) x (2 mol NH3 / 3 mol H2) x (17.03 g NH3 / 1 mol NH3) = 67.4 g NH3

Explanation: See above

Hope this helps, friend.

Answer:

More information so I can answer please.

Explanation: