Answer:
D. 10 seconds
Explanation:
All Houston Methodist Hospital buildings employs the use of EPSS(Emergency Power Supply System). This system employs the use of an emergency power generator that turns on to supply emergency power after normal power shuts down within 10 seconds during power outage.
Due to it being used in a hospital the importance of this emergency power system cannot be overemphasized as it is used to provide power supply to hospital equipment such as life support machines etc.
Two cars, C and D, travel in the same direction on a long, straight section of highway. During a particular time interval Ato, car D is ahead of car C and is speeding up while car C is slowing down. During the interval At, it is observed that car C gains on car D (i.e., the distance between the cars decreases). Explain how this is possible, and give a specific example of such a case.
Answer:
possibly because the car is running out of gas
Explanation:
15. Two like charges: A. Attract each other B. Repel each other C. Must be neutrons D. Neutralize each other
Answer:
B. Repel each other
Explanation:
Two like charges have the same sign. Example an electron with a negative charge (-e) and another electron with same charge(-e). Or a proton with a positive charge (+e) and another proton with same charge (+e). Since each of these pair charges have the same sign, they will repel each other.
On the other hand, if the charges are opposite, ie negative charge and positive charge, they will attract each other.
B. Repel each other
1st block
Worksheet: Metric Prefixes
A. Circle the larger unit:
1.millimeter, centimeter
2. kilogram, megagram
3. microsecond, millisecond
4.dL, mL
5.mg, kg
Answer:
2
Explanation:
kilogram and megagram is the larger unit
Why do scientists need creativity? What is gravity? Why are two objects with mass drawn to each other? List the two things that affect gravitational force. How are mass and weight different? Why does weight change depending on location? Explain in your own words the law of universal gravitation. Why does gravitational force vary between objects? How do we know how much gravitational force objects have? How does distance affect gravity? answer them all
Answer:
The strength of the gravitational force between two objects depends on two factors, mass and distance. the force of gravity the masses exert on each other.
the gravitational force is directly proportional to the mass of both interacting objects, more massive objects will attract each other with a greater gravitational force.
mass and distance.
The difference between mass and weight is that mass is the amount of matter in a material, while weight is a measure of how the force of gravity acts upon that mass.
A person can weigh differently at various place on Earth because of the fluctuations in Earth's gravity.
We call the gravitational force attractive because it always tries to pull masses together, it never pushes them apart. In fact, every object, including you, is pulling on every other object in the entire universe!
Since the gravitational force is directly proportional to the mass of both interacting objects, more massive objects will attract each other with a greater gravitational force
Its weight is determined by the degree to which gravitational force acts on it.
the force of gravity the masses exert on each other. increases, the force of gravity decreases
The mass of the objects and their separation from one another determine the gravitational force's strength. The gravitational pull of masses on one another.
What affect gravitational force?Mass is a measure of the quantity of substance in a material, whereas weight measures how the force of gravity acts upon a mass.
Because of variations in Earth's gravity, a person's weight might vary depending on where they are on the planet.
The gravitational force is referred to as attractive because it continually tries to pull masses together rather than push them apart. In truth, you and everything else in the universe are being pulled in different directions.
Therefore, Greater gravitational forces will pull more massive objects toward one another because gravitational force is directly proportional to the mass of both interacting objects.
Learn more about gravitational force here:
https://brainly.com/question/12528243
#SPJ2
Which observation is the most objective? a My frog died after 3 days in the aquarium. I will miss him. b My frog died after three days in the aquarium. We will test the temperature and water conditions to find out why. c Frogs tend to die in captivity. Ours did after three days.
Answer:
b
Explanation:
a looks so silly
What do civic heroes contribute to their society?
the quest for civic virtue
Explanation:
improving schools, the society....to help educators like yourself, the bill of rights institute has written a New classroom-friendly curriculum called Heroes and Villains....
A farmer lifts his hay bales into the top loft of his barn by walking his horse forward with a constant velocity of 8 ft/s. Determine the velocity and acceleration of the hay bale when the horse is 10 ft away from the barn.
Answer:
Velocity = 8 ft/s
Acceleration = 0 m/s²
Explanation:
Since, the horse is moving with a constant velocity, whose magnitude is given as equal to 8 ft/s. Therefore, it will have the same velocity when it is 10 ft away from the barn. And the velocity of hay bale will be same as the velocity of horse, as the horse is carrying the bales. Therefore:
Velocity = 8 ft/s
Coming to the second part of the question, which relates to the acceleration of the hay bale, when horse is 10 ft away from the barn. The formula for acceleration is given as:
Acceleration = Change in Velocity/ Time
But, the velocity of the horse in constant, which means there is no change in velocity. Hence,
Change in Velocity = 0
Therefore,
Acceleration = 0/Time
Acceleration 0 m/s²
Density is calculated by dividing
Answer:
Density is the mass of an object divided by its volume. Density often has units of grams per cubic centimeter (g/cm3). Remember, grams is a mass and cubic centimeters is a volume (the same volume as 1 milliliter).
Explanation:
Hey, there!
Density is defined as mass per unit volume. so, when we keep is as a formula we get like,
[tex]density = \frac{mass}{volume} [/tex]
So, you can state that density is calculated by dividing mass by its unit volume.
Hope it helps...
(a) A narrow beam of light containing yellow (580 nm) and green (550 nm) wavelengths goes from polystyrene to air, striking the surface at a 30.0°30.0° incident angle. What is the angle between the colors when they emerge?
Answer:
0.043°
Explanation:
Snell's law States that the ratio of the angle of incidence to angle of refraction is a constant for a given pair of media.
n = sin(i)/sin(r)
n1/n2 = sin(i)/sin(r)
For the green polystyrene
n2 = refractive index of green polystyrene = 1.493
n1 = refractive index of air = 1
1/1.493= sin30°/sin(r1)
sin(r1) = sin30°×1.493
sin(r1) = 0.5×1.493
sin(r1) = 0.7465
r1 = sin^-1(0.7465)
r1 = 48.288°
For the yellow polystyrene
n2 = refractive index of yellow polystyrene = 1.492
n1 = refractive index of air = 1
1.492/1= sin30°/sin(r2)
sin(r2) = sin30°×1.492
sin(r2) = 0.5×1.492
sin(r2) = 0.746
r2 = sin^-1(0.746)
r2 = 48.245°
The angle between the colors when they emerge = r1-r2
angle between the colors when they emerge = 48.288°-48.245°
angle between the colors when they emerge = 0.043°
You drop a ball from a height of 1.7 m, and it bounces back to a height of 1.2 m.
Part A) What fraction of its initial energy is lost during the bounce? Express your answer using two significant figures.
Part B) What is the ball's speed just before the bounce? Express your answer to two significant figures and include the appropriate units.
Part C) What is the ball's speed just after the bounce? Express your answer to two significant figures and include the appropriate units.
Part D) Where did the energy go?
1. The energy "lost" was changed primarily into chemical energy.
2. The energy "lost" was changed primarily into acoustic energy.
3. The energy "lost" was changed primarily into thermal energy due to friction.
4. The energy "lost" was changed primarily into heat energy.
Answer:
A) ΔEm = 0.29, B) v₁ = 5.8 m/s, c) v₂= 4.9 m / s D) the correct answer from 4
Explanation:
For this exercise we will use conservation of energy, taking care of how to choose our system
A) For this case we take two instants
starting point. When the ball goes out
Em₀ = U = m g y₁
Final point. When the ball reaches its maximum height
[tex]Em_{f}[/tex] = U = m g y₂
In this case we see that there is a loss of mechanical energy at the moment of rebound, therefore the fraction of energy lost is
ΔEm = Em_{f} / Em₀
ΔEm = mg y₂ / mg y₁
ΔEm = y₂ / y₁
ΔEm = 1.2 / 1.7
the lost part of energy
ΔEm = 1 -0.706
ΔEm = 0.29
B) the velocity just before the bounce
starting point. When the ball is released
Em₀ = U = m g y₁
final punot. Just wide of the bounce
Em_{f} = K = ½ m v₁²
As it has not yet rebounded, it has no energy loss, therefore the mechanical energy is conserved
Em₀ = Em_{f}
m g y₁ = ½ m v₁²
v₁ = √ 2 g y₁
let's calculate
v₁ =√ (2 9.8 1.7)
v₁ = 5.77 m / s
v₁ = 5.8 m/s
C) the velocity just after the bounce
starting point, after bounce
Em₀ = K = ½ m v₂²
final point. Maximum height after bounce
Em_{f} = U = m g y₂
as it already bounced, the energy is conserved in this interval
Em₀ = Em_{f}
½ m v₂² = m g y₂
v₂ = √ (2 g y₂)
v₂ = √ (2 9.8 1.2)
v₂ = 4.85 m / s
v₂= 4.9 m / s
D) during the time that the bounce lasts, there is a strong change in energy, part of it is transformed into thermal energy, due to several processes: friction, change in the potential energy of the molecules of the ball, change in the internal energy of the balls. molecules.
Therefore we cannot specify a single process, consequently the correct answer from 4
Martin is conducting an experiment. His first test gives him a yield of 5.2 grams. His second test gives him a yield of 1.3 grams. His third test gives him a yield of 8.5 grams. On average, his yield is 5.0 grams, which is close to the known yield of 5.1 grams of substance. Which of the following are true?
Complete Question
Martin is conducting an experiment. His first test gives him a yield of 5.2 grams. His second test gives him a yield of 1.3 grams. His third test gives him a yield of 8.5 grams. On average, his yield is 5.0 grams, which is close to the known yield of 5.1 grams of substance. Which of the following are true?
A His results are accurate but not precise.
B His results are neither accurate nor precise.
C His results are both accurate and precise
D His results are precise but not accurate.
Answer:
Correct option is A
Explanation:
From the question we are told that
The yield of the first test [tex]k = 5.2 \ g[/tex]
The yield of the second is [tex]u = 1.3 \ g[/tex]
The third yield is [tex]p = 8.5 \ g[/tex]
The average yield [tex]A = 5.0 \ g[/tex]
The know yield is [tex]A_S = 5.1 \ g[/tex]
From the data given we see that
[tex]A_S \ne A[/tex]
Since his average yield is closer to the known yield then the answer is accurate
But since the yield for each test are not repeated the answer is not precise
So the answer is accurate but not precise
His results are accurate but not precise.
Your question is not complete, it seems to be missing the following information;
"A His results are accurate but not precise.
B His results are neither accurate nor precise.
C His results are both accurate and precise.
D His results are precise but not accurate."
The given parameters;
first measurement = 5.2 gsecond measurement = 1.3 gthird measurement = 8.5 gaverage measurement = 5.0known substance average yield = 5.1 gEach of the measurement is far from each other. That is 5.2 grams, 1.3 grams and 8.5 grams are all far apart. So this measurement is not precise.
The known average (5.1 g) and the measured average (5.0 g) are close to each other, so the measurement is accurate.
Thus, we can conclude that his results are accurate but not precise.
Learn more here: https://brainly.com/question/13377944
A 50 kg child is riding on a carousel (merry-go-round) at a constant speed of 5 m/s. What is the magnitude of the change in the child's momentum ∣Δp⃗ ∣∣ in going all the way around (360∘)?In going halfway around (180∘)? It is very helpful to draw a diagram, and to do the vector subtraction graphically.
Answer:
a) [tex]\mathbf{|\Delta p^{\to}_{11}| = 0 \ kg.m/s}[/tex]
b) [tex]\mathbf{|\Delta p^{\to}_{12}| = 500 \ kg.m/s}[/tex]
Explanation:
From the image attached below.
Suppose the child goes all the way around, i.e., 360, the child will execute a movement of 1 complete revolution and be at his starting point. At that point, the velocity vector is towards the y-direction.
Thus, the velocity of the child is:
[tex]v_1^{\to} = v \hat _v_1} \\ \\ v_1^{\to} = (5)(0,1,0)\\ \\ v_1^{\to} = (0,5,0) \ m/s[/tex]
the momentum will be:
[tex]p_1^{\to} = m v_1^{\to} \\ \\ p_1^{\to} = (50)(0,5,0) \\ \\ p_1^{\to} = (0,250,0) \ kg.m/s[/tex]
the change in momentum now is [tex]\Delta p = p_1^{\to} -p_1^{\to}[/tex] since that is the child's momentum initially.
∴ [tex]\Delta p =(0,250,0) - (0,250,0)[/tex]
[tex]\mathbf{\Delta p =(0,0,0) \ kg.m/s}[/tex]
By subtracting the two vector graphically as being asked in the question, we have :
[tex]|\Delta p^{\to}_{11}| = \sqrt{(0)^2+(0)^2 +(0)^2 }[/tex]
[tex]\mathbf{|\Delta p^{\to}_{11}| = 0 \ kg.m/s}[/tex]
b) In going halfway around (180°), the child will be opposite with respect to the starting point. Hence, the velocity vector will be in the negative y-direction.
Thus, the velocity of the child is:
[tex]v_2^{\to} = v \hat _v_2} \\ \\ v_2^{\to} = (5)(0,-1,0)\\ \\ v_2^{\to} = (0,-5,0) \ m/s[/tex]
the momentum will be:
[tex]p_2^{\to} = m v_2^{\to} \\ \\ p_2^{\to} = (50)(0,-5,0) \\ \\ p_2^{\to} = (0,-250,0) \ kg.m/s[/tex]
the change in momentum now is [tex]\Delta p = p_2^{\to} -p_1^{\to}[/tex] since that is the child's momentum initially.
∴ [tex]\Delta p =(0,-250,0) - (0,250,0)[/tex]
[tex]{\Delta p =(0,-500,0) \ kg.m/s[/tex]
By subtracting the two vector graphically as being asked in the question, we have :
[tex]|\Delta p^{\to}_{12}| = \sqrt{(0)^2+(-500)^2 +(0)^2 }[/tex]
[tex]|\Delta p^{\to}_{12}| = \sqrt{250000}[/tex]
[tex]\mathbf{|\Delta p^{\to}_{12}| = 500 \ kg.m/s}[/tex]
Anyone able to also give me the working to how they figured it out?
Answer:
Lamp 1: 4 Volts, and 0.2 Amps
Lamp 2 : 4 Volts, and 0.2 Amps
Explanation:
Considering that the three lamps are equal (they have the same resistance R), we can find the actual resistance of the lamps with the information they provide that the potential difference measured across lamp 3 is 8 volts, using Ohm's Law:
[tex]V = I\,*\,R\\R = \frac{V}{I}\\R= \frac{8}{0.4} \\R = 20\,\,\Omega[/tex]
We can also estimate the potential difference across the lamps 1 and 2 (which are connected in parallel) using Kirchhoff's loop law, which tells us that the 12 volts provided by the battery should equal the addition of voltage drops in lamp 3 plus the drop in the parallel combination of lamps 1 and 2 (call that X):
12 V = 8 V + X
X = 12 - 8 = 4 V
Now, the current circulating through lamp 1 should be given by Ohm's Law:
[tex]V = I\,*\,R\\I = \frac{V}{R} \\I = \frac{4}{20}\\I = 0.2 \,\,Amps[/tex]
Notice that lamp 2 is equal to lamp 1 so the current value should be the same: 0.2 Amps
The presence of dwarf galaxies around the Milky Way supports what picture of our galaxy’s formation?
Answer:
The presence of dwarf galaxies around the Milky Way supports what picture that our galaxy was formed by a coming together or combination of smaller systems
while working out a man performed 375J of work in 11 seconds what was his power
Answer:
power=work done /time taken
therefore..375/11
=34.09
there he used 34.1
You drive your car in a straight line at 15 m/s for 10 kilometers, then at 25 m/s for another 10 kilometers.
a. What is your average speed?
b. Choose the best explanation from among the following:
1) More time is spent at 15 m/s than at 25 m/s.
2) The average of 15 m/s and 25 m/s is 20 m/s.
3) Less time is spent at 15 m/s than at 25 m/s.
Answer:
A) Average speed = 18.75 m/s
B) More time is spent at 15 m/s than at 25 m/s.
Explanation:
Let the first distance be d1 and the second distance be d2.
We are given;
d1 = 10 km = 10000 m
d2 = 10 km = 10000 m
Speed; v1 = 15 m/s
Speed; v2 = 25 m/s
Now, the formula for distance is; Distance = speed x time
Thus:
d1 = v1 x t1
t1 = d1/v1 = 10000/15 = 666.67 seconds
Also,
d2 = v2 x t2
t2 = d2/v2 = 10000/25 = 400 seconds
Average speed = total distance/total time = (10000 + 10000)/(666.67 + 400) = 18.75 m/s
From earlier, since t1 = 666.67 seconds and t2 = 400 seconds, then;
More time at 15 m/s than at 25 m/s.
A jet makes a landing traveling due east with a speed of 115 m/s. If the jet comes to rest in 13.0 s, what is the magnitude of its average acceleration
Answer:
8.846 m/s²
Explanation:
From the question,
The magnitude of the average acceleration is given as,
a = (v-u)/t.................. Equation 1
Where a = acceleration of the jet, v = final velocity of the jet, u = initial velocity of the jet, t = time taken for the jet to come to rest.
Given: v = 115 m/s, u = 0 m/s( from rest), t = 13.0 s
Substitute these values into equation 1
a = (115-0)/13.0
a = 115/13
a = 8.846 m/s²
Hence the magnitude of the average acceleration of the jet is 8.846 m/s²
Answer:
The value is [tex]a = 8.85 \ m/s^2[/tex]
Explanation:
From the question we are told that
The speed is [tex]v = 115\ m/s[/tex]
The time taken is t = 13.0
The initial speed is [tex]u = 0 \ m/s[/tex]
Generally the magnitude of the average acceleration is mathematically represented as
[tex]a = \frac{v-u}{ t}[/tex]
=> [tex]a = \frac{ 115 -0}{ 13}[/tex]
=> [tex]a = 8.85 \ m/s^2[/tex]
Industrial espionage is the use of spying techniques to find out key information that is of economic value.
a) true
b) false
Answer:
The given statement is "True".
Explanation:
Industrial spying or espionage seems to be the surreptitious but sometimes unconstitutional method of trying to investigate competition in the market to gain a competitive advantage throughout the commercial enterprise. The investigation's goal may be a closely guarded secret including a patented product design or formulation, or growth strategy details.Nina and Jon are practicing an ice skating routine. Nina is standing still. Jon, who is twice as heavy as Nina, skates toward her, pushing Nina away with force f. Assuming the system is closed, which statement is correct about this system? a. Nina experiences a force equal to f/2. b. Nina experiences a force equal to f^2. c. Nina experiences a force equal to 2f. d. Nina experiences a force equal to f.
Answer:
A
Explanation:
• Nina experiences a force equal to f.
Answer:
Nina experiences a force equal to f
Explanation:
got to get that 2nd answer slot correct too before an abusive expert verifier with an alt comes in and purposely verifies the wrong answer
What linear speed must an Earth satellite have to be in a circular orbit at an altitude of 203 km above Earth's surface
Answer:
7,790.38 m/s
Explanation:
Given the following :
What linear speed must an Earth satellite have to be in a circular orbit at an altitude of 203 km above Earth's surface
Altitude = 203 km
Using the formula :
V = √GM/r
Where G = gravitational constant =6.67×10^-11
Kindly check attached picture for detailed explanation.
1. An insect inside a bus flies from the back toward the front at 2 m/s. The bus is moving in a
straight line at 20 m/s. What is the total speed of the insect as seen by a person standing
side of the road?
A lens that is "optically perfect" is still limited by diffraction effects. Suppose a lens has a diameter of 150 mm and a focal length of 620 mm. A. Find the angular width (that is, the angle from the bottom to the top) of the central maximum in the diffraction pattern formed by this lens when illuminated with 520 nm light.B. What is the linear width (diameter) of the central maximum at the focal distance of the lens?
Answer:
a
w = 8.46 *10^{-6} \ rad
b
D =5.24 *10^{-6}
Explanation:
From the question we are told that
The diameter of the lens is [tex]d = 150 \ mm = 150*10^{-3} \ m[/tex]
The focal length is [tex]f = 620 mm = 620 *10^{-3} \ m[/tex]
The wavelength is [tex]\lambda = 520 \ nm = 520 *10^{-9} \ m[/tex]
Generally the angular width is mathematically represented as
[tex]w = 2 \theta[/tex]
Here [tex]\theta[/tex] is the angular radius of the central maxima which is mathematically represented as
[tex]\theta = \frac{1.22* \lambda }{ d}[/tex]
=> [tex]\theta = \frac{1.22 * 520 *10^{-9}}{ 150 *10^{-3}}[/tex]
=> [tex]4.23 *10^{-6} \ rad[/tex]
Hence
[tex]w = 2 * 4.23 *10^{-6}[/tex]
=> [tex]w = 8.46 *10^{-6} \ rad[/tex]
Generally linear diameter is mathematically represented as
[tex]D = 2 * R[/tex]
Where [tex]R[/tex] is the linear radius which is mathematically represented as
[tex]R = \frac{1.22 * f * \lambda }{ d}[/tex]
=> [tex]R= \frac{1.22 * 620 *10^{-3} * 520 *10^{-9}}{150 *10^{-3}}[/tex]
=> [tex]R = 2.62*10^{-6} \ m[/tex]
Thus
[tex]D = 2 * 2.62 *10^{-6}[/tex]
[tex]D =5.24 *10^{-6}[/tex]
A large magnetic flux change through a coil must induce a greater emf in the coil than a small flux change. A) True B) False
Answer:
False
Explanation:
Faraday's law gives the relationship between the induced emf and the rate of change of magnetic flux i.e.
[tex]\epsilon=\dfrac{-d\phi}{dt}[/tex]
The given statement "A large magnetic flux change through a coil must induce a greater emf in the coil than a small flux change" is false. The reason is that if the rate of change of magnetic flux is greater, then its will induce more emf. It would mean it does not say about emf.
Hence, it is false.
43 Points For Answering & +22 for Brainliest
Question 1
A student conducts an experiment to test how the temperature of a ball affects its bounce height. The same ball is used for each test, and the ball is dropped from the same height each time. What is the dependent variable?
A.The type of ball
B.The temperature of the ball
C.The drop height of the ball
D.The bounce height of the ball
Question 2
A student conducts an experiment to test how the temperature affects the amount of sugar that can dissolve in water. In the experiment, she uses 100 millilitres of water in each trial and stirs for five minutes each time. What is the independent variable?
A.The amount of water
B.The temperature of the water
C.The amount of sugar
D The time stirred
Question 3
Which of the following is a way for scientists to limit the amount of errors in their experimentation?
A.Using controls
B.Only completing an experiment once
C.Using equipment to measure the experiment that has been damaged
D.There is no need to record data from an experiment
Answer:
Question 1: D because the height the ball bounces depends on all the other factors in the experiment.
Question 2: B because the the temperature of the water is not affected by the other variables.
Question 3: A because the more that they can control in the experiment, the more accurate the results will be.
Hopefully this helps :)
1:D 2:B 3:A
just took the test
1. A particle is moving along the x-axis. Its position as a function of time is given as x = bt − ct 2 . a) What must be the units of the constants b and c, if x is in meters and t in seconds?
Answer:
Given x = bt-c²
We know that t= time (s)
x= distance (m)
So
bxt= meters
m/s x s= m
And then c= m/s²
And b= m/s
Which term describes a quantity that has both magnitude and direction?
Vector explanation is apex and I got 100 on the test and it’s the definition
Which of the following are subjects of scientific laws?a. gravityb. motionc. thermodynamics
an Alpha particle moving in north direction give reasons
Your question has been heard loud and clear.
An alpha particle , can move in any direction randomly. But with a magnetic field , we can deflect the alpha particle in any direction we want.
So , the magnetic field must be placed to the west of the alpha particle , so that the particle gets deflected and moves towards the north direction.
Thank you.
Like AL2006 said reasons for what
What is the average power output (in W) of a heart defibrillator that dissipates 435 J of energy in 10.5 ms?
Answer:
The power is [tex]P = 41429 \ W[/tex]
Explanation:
From the question we are told that
The energy is [tex]E = 435 \ J[/tex]
The time taken is [tex]t = 10.5 \ ms = 10.5 *10^{-3} \ s[/tex]
Generally the the average power is mathematically represented as
[tex]P = \frac{E}{t}[/tex]
=> [tex]P = \frac{ 435}{ 10.5*10^{-3}}[/tex]
=> [tex]P = 41429 \ W[/tex]
The siren of a fire engine that is driving northward at 31.0 m/s emits a sound of frequency 2020 Hz. A truck in front of this fire engine is moving northward at 19.0 m/s.
a) What is the frequency of the siren's sound that the fire engine's driver hears reflected from the back of the truck?
b) What wavelength would this driver measure for these reflected sound waves?
Answer:
A. Using
Fl= ( v+vl/v+vz)fz
= (340+19/340+31) x 2020
= 1954.7Hz
Then to find the frequency of sound when reflected from the truck such that the driver becomes the listener
we use
F"= ( v+vz/v+vl) fz
= 340+31/340+19 x 2020
2087.5Hz
B to find the wavelength of sound we use
Wavelength= V+vl/ F"
= 340+31/2087.5= 0.18m