An 80kg woman jumps from a wall and lands stiff-legged in soft sand. The woman's downward speed just as she touches the sand is 6m/s. She is stopped after sinking 0.05m into the sand. Calculate the net force on the woman while she is being stopped by the sand. Round to nearest whole number

The graph of the vertical component of the ball's velocity is in the attachment

Speed is the distance moved per unit time.

Velocity is the total displacement per unit time of an object.

Since a 0.1 kg ball is kicked from the edge of a cliff so that it attains a launch speed of 20 m/s at an angle of 37 to the horizontal, as shown above. To determine the vertical component of velocity,we use the equation of motion

v = u - gt where

So, substituting the values of the variables into the equation, we have

v = u - gt

v = u'sinФ - gt

v = (20 m/s)sin37° - (9.8 m/s²)t

v = (20 m/s) × 0.6018 - (9.8 m/s²)t

v = 12.04 m/s - (9.8 m/s²)t

So, for the first 3 seconds, we have

for t = 0 s

v = 12.04 m/s - (9.8 m/s²) × 0 s

v = 12.04 m/s - 0 m/s

v = 12.04 m/s

for t = 1 s

v = 12.04 m/s - (9.8 m/s²) × 1 s

v = 12.04 m/s - 9.8 m/s

v = 2.24 m/s

for t = 2 s

v = 12.04 m/s - (9.8 m/s²) × 2 s

v = 12.04 m/s - 19.6 m/s

v = -7.56 m/s

for t = 3 s

v = 12.04 m/s - (9.8 m/s²) × 3 s

v = 12.04 m/s - 29.4 m/s

v = -17.36 m/s

So, we plot the graph of the vertical component of the ball's velocity using the equation v = 12.04 m/s - (9.8 m/s²)t

Find the graph in the attachment

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The second student must push with a force greater than 150 N to cause the car to accelerate.

The net force on the car is the sum of all the forces acting on the car. The direction of the net force on the car will determine the direction of motion of the car.

According to Newton's second law of motion, the force applied to an object is directly proportional to the product of mass and acceleration of the object.

The net force on the car is calculated as follows;

F(net) = F - Ff

ma = F - Ff

where;

For the car to move, sum of the applied forces must be greater than the force of friction.

200 + F > 350

F > 350 - 200

F > 150

Thus, the second student must push with a force greater than 150 N before the car can accelerate.

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The atmosphere supports a column of mercury with a height of 760 mm. Supports a 32 m high water column. And, of course, that's why we fill the barometer with mercury instead of water or alcohol.

The vapor pressure of mercury is also minimal. Therefore, the pressure at the exit point is equal to atmospheric pressure. This pressure is therefore equal to 10 to the power of 5 times 1.1. The base area of ​​this water cube is 12" x 12" = 144 square inches. So, the pressure at the bottom of the water cube is 62.4 pounds / 144 square inches = 0.433 pounds per square inch (psi). The RCC column minimum size is 9" x 9" and incorporates four 12mm bars steel stiffeners and cleats of 8mm steel rings spaced 150mm center to center.

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To learn series and parallel circuits, to know the some appliances in your kitchen receive power while others do not.

What is series circuits?

A series circuit is an easy way for electrons to travel to one or more resistors. Anything that depends on a cell for power is a resistor. A bulb frequently serves as the resistor in a series circuit.

What is parallel circuit?

Branching is used in a parallel circuit so that the current is divided and only a portion of it passes through each branch. In a parallel circuit, the voltage, or potential difference, across each branch is the same, but the currents may differ.

While plugged in, a range of various electronic equipment and appliances, such as televisions, toasters, lamps, and more, can use electricity even when they're off.

Therefore, known the series and parallel circuits, the some appliances receive powers.

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Answer:

The airplane is heading away from us when we see a manned aircraft in the distance while flying our drone at night.

Distance is the length between two points or items, and it is directionless. Since distance is a scalar attribute, it only takes into account the overall magnitude and ignores the start and end locations. Being a scalar attribute, distance may only be positive or zero; it cannot be the opposite.

Although kilometers (km) and centimeters (cm) or millimeters (mm) can also be used to express shorter distances, the meter (m) is the most used unit of measurement for distance (mm). When calculating distance, the letter D is usually used to denote the distance traveled.

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According to the given statement 17.15 N force is exerted on the segment of wire in n.

Magnitude is essentially "distance or quantity" in the context of physics. In terms of motion, it shows the absolute and relative size, direction, or movement of an object. It is used to describe there is something volume or scope. Quantity in physics typically refers to a size or quantity.

The magnitude of the magnetic force on a conducting wire of length I carrying current II, and making an angle θ with a magnetic field of strength B is given by:

[tex]$|\vec{F}|$[/tex] = I l B sin 0

Rearranging to get the current:

I = [tex]$|\vec{F}|$[/tex]/ lB sin0

= 7 * 10⁻³ / 0.75 * (5.5 * 10⁻⁵)sin60

= 195.95 A

[tex]$|\vec{F}|$[/tex] = I l Bsin0

= (195.95)(0.05)(1.75)sin90

=17.15 N

I = 195.95 I

[tex]$|\vec{F}|$[/tex] = 17.15 N

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The pressure applied by the cube of mass 500 kg and side 50 cm on the floor is 200000 Pascal

The mass of the cube is 500 kg and the side of the cube is 50 cm.

Converting the side of the cube from cm to m.

The side of the cube is 0.5 m.

The pressure applied by any body is given by the force applied by the body divided by the area on which the force is applied.

Pressure = force/area

The force applied by the cube will be equal to the weight of the cube,

The weight of the cube is 5000 Newton.

The area of only one side of the cube is in contact with the floor so the area is,

Area = 0.025 m

Putting values,

P = 5000/0.025

P = 200000 Pascal.

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Largest-size vehicle (kg) it can lift if the diameter of the output and maximum gauge pressure is given is 0.455 * 10³ kg.

Pressure that is measured relative to ambient atmospheric pressure is called gauge pressure. Gauge pressure can be measured using a diaphragm sensor in which one side of the diaphragm is exposed to the pressure media that is to be measured and the other side gets exposed to ambient atmospheric pressure.

Given the diameter of the piston = 25.5 cm,

radius = 12.75 cm= 0.1275 m

Area of the piston is;

A=  πr²

= 3.14 * (0.1275)²

=0.051 m²

Given maximum pressure of the lift= 17 atm

p =1.72 * 10⁶ Pa

Maximum force that piston can lift:

F= p * A

=  1.72 * 10⁶ *( 0.051 )²

= 4.47 * 10³ N

Size of the vehicle :

m = F/g

=  4.47* 10³/ 9.81

mass = 0.455 * 10³ kg

Largest-size vehicle that it can lift is 0.455 * 10³ kg.

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It should travel at a speed of [tex]13.55[/tex] × [tex]10^{-3}[/tex] [tex]\frac{m}{s}[/tex] so that the two balls have the same momentum.

M = mass of the bowling ball = [tex]4.5 kg[/tex]

V = speed of bowling ball = [tex]3.98 \frac{m}{s}[/tex]

P = magnitude of momentum of bowling ball = ?

magnitude of momentum of bowling ball is given as

[tex]P = MV[/tex]

inserting the values

P = [tex]4.5 * 3.98[/tex]

P = [tex]17.91[/tex] [tex]\frac{kgm}{s}[/tex]

m = mass of ping-pong ball = [tex]1.322[/tex] [tex]g[/tex]= [tex]1.322[/tex] x [tex]10^{-3}[/tex] [tex]Kg[/tex]

v = speed of the ping-pong ball = ?

p = magnitude of momentum of ping-pong ball

Given that :

Magnitude of momentum of ping-pong ball  =  magnitude of momentum of bowling ball

[tex]p = P[/tex]

[tex]m v = 17.91[/tex]

([tex]1.322[/tex] x [tex]10^{-3}[/tex]) [tex]v[/tex] = [tex]17.91[/tex]

v = [tex]13.55[/tex] x [tex]10^{-3}[/tex] [tex]\frac{m}{s}[/tex]

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The drag force acting on the rocket is 80N.

The divergence in velocity between the fluid and the item, also known as drag, exerts a force on it. Between the liquid and the solid object, there should be motion. Drag is absent in the absence of motion.

The air molecules are more compressed (pushed together) on the surfaces that are facing the front while being more dispersed (spread out) on the surfaces facing the back. Turbulent flow, which occurs when air layers split from the surface and start to swirl, is what causes this.

The drag force acting on the rocket F = ma

Given,

m = 4kg, a = 20ftm/s²

Substituting m and a values in the above formula,

The drag force acting on the rocket F = 4×20

The drag force acting on the rocket F = 80N.

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The flow rate and the volume that passes through the artery in a period of 20 s is Q= 4.1448cm³/s and V= 82.896cm³.

We must define both the volume V and the instant in time it is flowing past represented by t in order to determine the Flow Rate denoted by Q, which is equal to V/t. In addition, the relationship between flow rate and velocity can be seen in the equation Q = Av, where A is the flow's cross-sectional area and v is its average velocity.

We must utilize the equation Q=V x A, where Q is the flow rate, V is the velocity, and A is the area, to determine the flow rate.

We must apply this formula to determine the volume. V = Q x t, where Q is the flow rate, t is the time, and V is the volume.

Converting 2mm to cm is the first thing we must accomplish.

2mm x 0.1= 0.2 cm

Currently, we utilize the calculation Q=V x A, but we must keep in mind that the area of an artery is circular, therefore we swap out A with the formula π r2.

Q= 33 cm/s x 3,14x (0.2cm)²

Q= 33cm/s x 0.1256cm²/s

Q= 4.1448cm³/s.

There is a flow at 4.1448cm³/s.

Now, using the flow rate (Q), we may

V=  4.1448 cm³/s x 20s

V= 82.896cm³.

82.896cm3 of fluid travels through the artery every 20 seconds.

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Answer:

The answer is photons.

Mental A has the smaller density. An object's density is defined as its mass divided by its volume.. Density is commonly expressed in grams per cubic centimeter (g/cm3).

Density is the amount of "stuff" in a given amount of space. A block of the heavier element lead (Pb), for example, will be denser than a block of the softer, lighter element gold (Au). A Styrofoam block is less dense than a brick. It is expressed in terms of mass per unit volume.

An object's density is defined as its mass divided by its volume. Density is commonly expressed in grams per cubic centimeter (g/cm3). Remember that grams are a unit of mass and cubic centimeters are a unit of volume (the same volume as 1 milliliter).

The SI density unit is m3kg. Volume Mass Density = m3kg

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To draw a free body diagram, draw the object of interest, plot all the forces acting on it, and decompose all force vectors into their x and y components.

A separate free body diagram must be drawn for each object in question. There are not always four forces acting on an object. The number of forces represented in the free body diagram can be one, two, or three. External forces acting on an object include friction, gravity, normal forces, drag, tension, or human force by pushing or pulling. In non-inertial frames (see Frames below), conceptual forces such as centrifugal pseudo-forces are appropriate.

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480 W  is the power output of the secondary coil.

primary  coil current = ip = 4A

primary coil  voltage = vp = 120v

power out put of secondary coil

p = vi

   = 120v * 4A = 480W.

Power is the amount of work completed in a given amount of time. Watt (W), which is derived from joules per second (J/s), is the SI unit of power. Horsepower (hp), which is roughly equivalent to 745.7 watts, is a unit of measurement sometimes used to describe the power of motor vehicles and other devices.

The rate at which work is performed on an object is referred to as its power. Power is a temporal concept. It has to do with how quickly a task gets completed. The power equation is described below.

Power = Time + Work

P = W / t

The standard metric unit for power is a Joule/second, which is defined as the product of the standard metric units of work (the Joule) and time (the second).

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The top speed of the car is 34.34 m/s and the total time of the run is 11.65 seconds.

The top speed of the car is the final or maximum speed of the car and can be determined by applying the following kinematic equation.

v = u + at

where;

The initial velocity of the car = 0, since the car started from rest.

The final equation for the top speed of the car becomes;

v = 0 + at

v = at

The given parameters include the following;

v = 5.89 m/s²  x   5.83 s

v = 34.34 m/s

The total time of the run is calculated as follows;

s = ut + ¹/₂at²

where;

s = 0 + ¹/₂at²

s = ¹/₂at²

t = √(2s/a)

t = √(2 x 400 / 5.89)

t = 11.65 seconds

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Using the concepts of angular displacement, we got that 0.241 rad/s is the angular velocity of track star which runs a 230 m race on a 230 m circular track in 26 s.

We know very well that angular velocity is given by change in angular displacement per unit time.

Here, we can see that a truck distance covered and length of circular track is same.

Perimeter of circular track is equal to the distance covered by the truck.

It means, truck rounds a full circle in 26 sec

So, the angle covered by truck is 360° or 2π radian.

Initially angle is 0 radian and final angle is 2π radian

Therefore, angular velocity =(θ[tex]_f_i_n_a_l[/tex] -θ[tex]_i_n_i_t_i_a_l[/tex])/time

                               => ω=(2π-0)/26

                               =>w=(2π/26)

                                =>w=(2×3.14)/26

                                =>ω=6.28/26

                                =>w=0.241 rad/sec.

Hence, when a track star runs a 230 m race on a 230 m circular track in 26 s, the angular velocity assuming a constant speed is 0.241 rad/sec.

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MRI and FMRI are the  combination of neurological imaging techniques contains two methods that utilize magnetic imaging.

A magnetic field and radio waves produced by a computer are used in the magnetic resonance imaging (MRI) medical imaging procedure to provide precise images of the organs and tissues inside your body.

Large, magnetized tubes are the common shape of MRI equipment. The magnetic field briefly realigns water molecules in your body as you lie within the MRI machine. To produce cross-sectional MRI pictures, which resemble the slices of a loaf of bread, radio waves induce these aligned atoms to emit tiny signals.

Your doctor can evaluate your organs, tissues, and skeletal system with an MRI without performing any intrusive procedures. It generates detailed images of the body's.

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The moment of inertia of the boxer's forearm that has an angular acceleration of 125.0 rad / s² is 0.25 kg m²

τ = F * ⊥d

τ = Torque

F = Force

⊥d = Perpendicular distance

F = 1495 N

⊥d = 2.1 cm = 0.021 m

τ = 1495 * 0.021

τ = 31.395 N m

τ = I α

I = Moment of inertia

α = Angular acceleration

α = 125 rad / s²

I = τ / α

I = 31.395 / 125

I = 0.25 kg m²

Therefore, the moment of inertia of the boxer's forearm is 0.25 kg m²

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The rock's impact velocity with the river is - 98.1 m/s. At the time of impact, the  rock was traveling at a speed of 42.14 m/s.

G = -9.81 m/s2 is the acceleration of gravity close to the earth. Simply multiply the acceleration of gravity by the period of time since the object was released to determine the object's speed (or velocity).

In other words, velocity is equal to -9.81 m/s2 * time, or V = gt.

The rock was traveling at 42.14 m/s when it impacted the ocean.

Then V = -9.81 * 10 = -98.1.

There for,

The rock's impact velocity with the river is -98.1m/s .

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The applied force is 7.68 × 10³N.

A force that is applied is one that one object applies to one or more other objects. Applied forces have the power to alter an object's shape, size, state of motion, direction of motion, and other properties.

W = 1.3 × 10⁴

v₁ = 0

v (friction) = 84km/h = 23.3 m/s

t = 5s

f = 1500N

Mass of body = W / g

Mass of body = 1.3 × 10⁴ / 9.8

Mass of body = 1327 kg

v(friction) = v + at

23.3 = 5a

a = 4.66 m/s

Force Net = F₁ + F₂ + F₃ = ma

F (engine) = ma + F

F = 1327 (4.66) + 1500

F = 768.382

F = 7.68 × 10³N.

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A passenger on a train traveling at a ground speed of 18.0 m/s in the opposite direction of the first train can hear the frequency approach at 302.05 Hz.

The number of waves that pass a fixed place in a unit of time is referred to as frequency in physics. It also indicates how many vibrations or cycles a body in periodic motion makes in a given amount of time.

Speed is 18.0 m/s.

Consider a train moving through still air at a speed of 30.0 m/s. The train whistle produces a note with a 262 Hz frequency.

We must determine the periodicity.

Using the frequency formula

f' = f(v + [tex]v_{p}[/tex]/v - [tex]v_{s}[/tex])

Fill out the formula with the value,

f' = 262(3441+18/344-30)

f' = 302.05Hz

Thus, 302.05 Hz is the frequency.

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The correct statements which describes current theories about dark energy and dark matter among the choices above are given below:

The answers are options a, b, and d.

Dark energy refers to that energy which acts against gravity, thereby resulting in the expansion of the universe. It's major constituent is current characterized with vacuum fluctuation. It is on this premise that dark energy was theorized to be causing the expansion of the universe to accelerate and itself including dark matter is filled in empty space.

So therefore, from the simple note above, it can be deduced that this type of energy does not produce electromagnetic radiation.

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Answer:

a b d

Explanation:

Which statements explain current theories about dark energy and dark matter? Check all that apply.

Space that appears empty actually contains dark energy and dark matter.

Dark matter does not emit electromagnetic radiation.

Scientists believe dark energy will cause the universe to collapse inward to a single point.

Scientists theorize that dark energy is causing the expansion of the universe to accelerate.

Dark matter includes all of the dust, ice, and debris that scientists observe in black holes.

The overall momentum of a system is constant.

Hence, The time taken to get to the shuttle is  4.49  min.

according to  the linear momentum conservation theorem, we have:

M1 V1 + M2 V2 =M1 V[tex]_0[/tex]1 + M2 V[tex]_0[/tex]2.

the initial velocity is Zero

then,

M1 V1 = - M2 V2

V1 = ( - M2 V2)/ M1

V1 = -  [tex]\frac{0.767 *12}{54.8}[/tex] = - 0.168 m/s

That is 0.168 m/s in the opposite direction of the camera.

the time taken to get to the shuttle is given by:

t = d/v

t = [tex]\frac{45.3}{0.168}[/tex] = 269.64 s

[tex]t_{min} =\frac{269.64}{60}[/tex] = 4.49 min.

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Work done when a 125 g tomato is lifted 13.6 m is calculated as 16.66 J .

The product of the component of force in the direction of the displacement and the magnitude is called work done by force and energy is defined as the ability to do work.

Work can be calculated by multiplying force with distance in the direction of force , and can be written as :

W = F × d

Given m= 125g = 0.125 kg

h= 13.6 m

W= P E

= m *g *h

= 0.125 * 9.8 * 13.6

Work done = 16.66 J

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Area in physics can be found by division of the area into simple figures such as triangles, rectangles and trapezoids and offsets from a straight line.

Area is a measure of how much space is there inside a shape and calculating the area of a shape or surface can be useful in everyday life.

The amount of surface a two-dimensional shape can cover which is measured in square units is called area and the SI unit of area is the square meter.

Area = length x breadth and  Area = π × radius × radius - formulas can be used for finding area of different quadrilaterals.

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Answer:

3, 4, 1, 2

Explanation:

(1) The ball is in the air for 1.4 seconds.

(2) The horizontal velocity of the ball as it rolls off the table is 6.32 m/s.

(3) The vertical velocity of the ball right before it hits the ground is 13.72 m/s.

(4) The horizontal velocity of the ball right before it hits the ground is 6.32 m/s.

(5) The initial vertical velocity as soon as the ball comes of the cliff is 13.72 m/s​.

The time of motion of the ball is calculated by applying the following equation.

t = √(2h/g)

where;

t =  √(2h/g)

t = √(2 x 9.63 / 9.8)

t = 1.4 seconds

The horizontal velocity of the ball is calculated as follows;

v = d/t

where;

v = 8.85 m / 1.4 s

v = 6.32 m/s

The vertical velocity of the ball before it hits the ground is calculated as;

vf = vi + gt

vf = 0 + 9.8 x 1.4

vf = 13.72 m/s

The horizontal velocity of the ball right before it hits the ground is calculated as;

the initial velocity of a projectile = final horizontal velocity

vxf = vxi = 6.32 m/s

The initial vertical velocity as soon as the ball comes off the cliff = final vertical velocity = 13.72 m/s

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The braking distance does not change. Because both the kinetic energy and the frictional force are doubled.

We found that the stopping distance of a car is proportional to its kinetic energy. Energy is dissipated as heat in the brakes tires and road surface. More energy required means more stopping distance. This explains why the braking distance increases in proportion to the square of the car's speed. The kinetic energy of a car is equal to the braking force multiplied by the stopping distance.

Braking distance also depends on car speed car mass brake and tire wear and road surface. A fast heavy car with worn tires and brakes will have a longer stopping distance on wet or icy roads. Friction forces act in the opposite direction of movement, making it harder to move slowing the car down the ramp and slowing it down, thus reducing the distance covered.

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