An acid-base indicatior is a compound who's color is pH dependent. That is, it changes color depending upon whether it is in acid or base. This is because indicators are weak acids and undergo the following equilibrium. H-Ind ↔ H+1 + Ind-1 H-Ind = the indicator molecule that is protonated and predominates under acidic conditions. Ind-1 = the deprotonated indicator molecule (the conjugate base of the acid) and predominates under basic conditions. We are using the Acid-Base indicator, phenopthalein for this experiment. What is the color of this indicator in Acid? . What is the color of this indicator in Base

Answers

Answer 1

Phenolphthalein is pink in acid and colorles in base.

Substances called indicators are those whose solutions change colour as the pH changes. We refer to these as acid-base indicators. The conjugate base or acid versions of these typically weak acids or bases have various hues because of variations in their absorption spectra. When it comes into contact with an object that has a pH of 8.2, it turns pink. At a pH higher than that, it turns purple.

Additionally, ionisation, which modifies the charge and structure of the phenolphthalein molecule, is the cause of this shift in colour. If it comes into contact with an acid like vinegar or a neutral substance like water, it retains its colorlessness.

Therefore, Phenolphthalein is pink in acid and colorles in base.

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Related Questions

A gas company in Massachusetts charges $1.30 for 17.0ft³ of natural gas. Convert this rate to dollars
per liter of gas.

Answers

Answer:

See below

Explanation:

Conversion factor :  1 ft^3  = 28 .317  liters

$ 1.30 /( 17 ft^3 *  28.317 liters/ft^3)    =   $.0027  per liter  

convert ethene to propanamine​

Answers

STEP 1: ON TREATING CHLOROETHANE WITH KCN WE GET PROPANE - NITRILE . STEP 2: ON TREATING PROPANE - NITRILE WITH LiAlH4 WE GET PROPANAMINE.

Calculate the freezing point of a solution that contains 8.0 g of sucrose (C12H22O11) in 100 g of H2O. Kf for H2O = 1.86C/m
Group of answer choices

A. 0.44 degrees Celsius

B. 0.044 degrees Celsius

C. 0.39 degress Celsius

D. 0.22 degress Celsius

Answers

The freezing point of the sucrose solution is -0.435°C.

What is the freezing point of the solution?

The freezing point of the solution is determined from the freezing point depression formula below:

ΔT = mKf(H₂O)

Kf(H₂O) = 1.86 Cm

m is molality of solution = moles of solute/mass of solvent

moles of sucrose = 8.0/342.3 = 0.0233 moles

m = 0.0233/0.1 = 0.233 molal

ΔT = 0.233 m * 1.86°C/m.

ΔT = 0.435 °C.

Freezing point of sucrose solution = 0°C - 0.435°C

Freezing point of sucrose solution  = -0.435°C.

In conclusion, the freezing point of sucrose solution is determined from the freezing point depression.

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How many grams of Aspirin (acetylsalicylic acid) should we form in this reaction if we started with 2.08g of Salicyclic Acid?

Answers

Taking into account the reaction stoichiometry, 2.713 grams of aspirin are formed when 2.08 grams of salicyclic acid reacts.

Reaction stoichiometry

In first place, the balanced reaction is:

C₄H₆O₃ + C₇H₆O₃ (Salicyclic Acid) →C₉H₈O₄ (aspirin) + C₂H₄O₂

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

C₄H₆O₃: 1 moleC₇H₆O₃: 1 moleC₉H₈O₄: 1 moleC₂H₄O₂: 1 mole

The molar mass of the compounds is:

C₄H₆O₃: 102 g/moleC₇H₆O₃: 138 g/moleC₉H₈O₄: 180 g/moleC₂H₄O₂: 60 g/mole

Then, by reaction stoichiometry, the following mass quantities of each compound participate in the reaction:

C₄H₆O₃: 1 mole ×102 g/mole= 102 gramsC₇H₆O₃: 1 mole ×138 g/mole= 138 gramsC₉H₈O₄: 1 mole ×180 g/mole= 180 gramsC₂H₄O₂: 1  mole ×60 g/mole= 60 grams

Mass of aspirin formed

The following rule of three can be applied: if by reaction stoichiometry 138 grams of salicyclic acid form 180 grams of aspirin, 2.08 grams of salicyclic acid form how much mass of aspirin?

[tex]mass of aspirin=\frac{2.08 grams of salicyclic acidx 180 grams of aspirin}{138 grams of salicyclic acid}[/tex]

mass of aspirin= 2.713 grams

Then, 2.713 grams of aspirin are formed when 2.08 grams of salicyclic acid reacts.

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A solution is prepared by mixing 200.0 g of water, H2O, and 300.0 g of
ethanol, C2H5OH. Determine the mole fractions of each substance.

Answers

Answer:

Mole Fraction (H₂O)  =  0.6303

Mole Fraction (C₂H₅OH)  =  0.3697

Explanation:

(Step 1)

Calculate the mole value of each substance using their molar masses.

Molar Mass (H₂O): 2(1.008 g/mol) + 15.998 g/mol

Molar Mass (H₂O): 18.014 g/mol

200.0 g H₂O            1 mole
---------------------  x  ------------------  =  11.10 moles H₂O
                                 18.014 g

Molar Mass (C₂H₅OH): 2(12.011 g/mol) + 6(1.008 g/mol) + 15.998 g/mol

Molar Mass (C₂H₅OH): 46.068 g/mol

300.0 g C₂H₅OH              1 mole
----------------------------  x  --------------------  =  6.512 moles C₂H₅OH
                                         46.068 g

(Step 2)

Using the mole fraction ratio, calculate the mole fraction of each substance.

                                            moles solute
Mole Fraction  =  ------------------------------------------------
                               moles solute + moles solvent

                                                  11.10 moles H₂O
Mole Fraction  =  -------------------------------------------------------------
                               11.10 moles H₂O + 6.512 moles C₂H₅OH

Mole Fraction (H₂O)  =  0.6303

                                             6.512 moles C₂H₅OH
Mole Fraction  =  -------------------------------------------------------------
                               11.10 moles H₂O + 6.512 moles C₂H₅OH

Mole Fraction (C₂H₅OH)  =  0.3697

PLEASE ANSWER NEED BY MIDNIGHT TONIGHT!!!!!!
Radium-223 nuclei usually decay by alpha emission. Once in every billion decays, a radium-223 nucleus emits a carbon-14 nucleus.

Write a balanced nuclear equation for carbon-14 emission.

Answers

The equation for carbon-14 emission by Radium-223 nuclei is given below:

[tex]^{223}_{88}Ra \rightarrow\: ^{209}_{82}Pb + \:^{14}_{6}C[/tex]

What is radioactivity?

Radioactivity is the spontaneous decay of a substance with emission of radiation.

The equation for carbon-14 emission by Radium-223 nuclei is given below:

[tex]^{223}_{88}Ra \rightarrow\: ^{209}_{82}Pb + \:^{14}_{6}C[/tex]

In conclusion, the emission of carbon-14 by Radium-223 nuclei produces Lead-209 nuclei.

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15) The average human is ~60% water, which translates to ~44.3 kg of water. If you eat a Reece's peanut butter cup (105 Calories or 4.39 x 105J), how many degrees Celsius (°C) should the 44.3kg of water rise. The specific heat of water is 4.184 J/g.°C. A) 2.37 x 103°C B) 5.66 x 104°C C) 41.5°C D) 2.37°C E) 0.566°C 4.39x1055 0.043 y 4.18488.0​

Answers

Answer: D) 2.37°C

Explanation:

[tex]4.39x10^5J(\frac{g°C}{4.184J} )(\frac{kg}{1000g})(\frac{1}{44.3kg} )[/tex] [tex]=2.37°C[/tex]

please help me with this question as soon as possible

Answers

Answer:

nah what questionExplanation:

What color does red cabbage juice make when mixed with a citrus cleaner?
What color does red cabbage juice make when mixed with a dishwasher soap?
(WILL MARK BRAINLIEST!!!)

Answers

Answer:

Explanation:

green

When 50 electrons drop from energy level 4 to energy level 2, how many photons of light are given off?

1 photon

100 photons

2 photons

50 photons

Answers

The number of photons given off will be 50 photons.

To find the answer, we need to know about the plank's equation.

How to find the number of photons emitted?We have the expression for energy of a single electron in eV as,

                     [tex]E=-13.6(\frac{1}{(n_f)^2}- \frac{1}{(n_i)^2})eV\\[/tex]

We have,

                     [tex]n_f=4\\n_i=2\\N=50[/tex]

Substituting values, we get,

                  [tex]E=-13.6(\frac{1}{(4)^2}- \frac{1}{(2)^2})eV\\\\E=-13.6*-0.188=2.55eV[/tex]

For N electrons,

                [tex]E=50*2.55eV=127.5eV[/tex]

We have the plank's equation,

                            E=nhf

From this, the number of photons emitted from 50 electrons will be,

                    [tex]n=\frac{E}{h*f} =\frac{127.5*1.67*10^{-19}J}{(6.63*10^-34)Js} \\[/tex]

To find n, we have to find the frequency f. For that, we have the equation,

                       [tex]\frac{1}{wave length}=R_H(\frac{1}{(n_i)^2}- \frac{1}{(n_f)^2})\\\\1/wv= 1.1*10^5(\frac{1}{(2)^2}- \frac{1}{(4)^2})=20625cm^{-1}.\\wavelength=486nm.[/tex]

Thus, frequency will be,

                 [tex]f=\frac{c}{wavelength} =\frac{3*10^8}{486*10^{-9}} =6.172*10^{14}s{-1}[/tex]

Then, the number of photons will be,

                       [tex]n=\frac{E}{h*f} =\frac{127.5*1.67*10^{-19}J}{(6.63*10^-34)Js*6.17*10^{14} s^{-1}} \\\\n=52.05 photons[/tex]

Thus, we can conclude that, the number of photons given off will be 50 photons.

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I need help with my work

Answers

Answer: D. 3Ag+ + PO43- = Ag3PO4

Explanation:

Overall Chemical Equation:

Ensure that the elements on both sides of the equation are balanced.

3C2H3AgO2 + Na3O4P = Ag3PO4 + 3C2H3NaO2

Solubility Equation:

Determine the state or phase of each substance (gas=g, liquid=l, solid/non-soluble=s, aqueous/soluble=aq) in its undissociated form.

3C2H3AgO2(aq) + Na3O4P(aq) = Ag3PO4(s) + 3C2H3NaO2(aq)

Complete Ionic Equation:

The complete ionic equation includes spectator ions. Write it by breaking all the soluble ionic compounds into their respective ions.

3Ag+(aq) + 3CH3COO-(aq) + 3Na+(aq) + PO43-(aq) = Ag3PO4(s) + 3Na+(aq) + 3CH3COO-(aq)

Net Ionic Equation:

The balanced net ionic equation includes only species that are involved in the reaction. It can be found by removing ions that occur on both the reactant and product side of the complete ionic equation.

3Ag+(aq) + PO43-(aq) = Ag3PO4(s)

What classifies a substance as an element?
What classifies a substance as a compound?

Actually, answer what the question is asking and give a short answer. No copying and pasting.

Answers

The difference between an element and a compound is that an element is a substance made of same type of atoms, whereas a compound is made of different elements in definite proportions.Examples of elements include iron, copper, hydrogen and oxygen. Examples of compounds include water (H2O) and salt (Sodium Chloride - NaCl).

Using the balanced equation below.
how many grams of cesium fluoride
would be required to make 73.1 g
of
cesium xenon heptafluoride?
CSF + XeF6 - CsXeF7
A

Answers

Answer:

28.0 grams CsF

Explanation:

To find the mass of CsF, you need to (1) convert grams CsXeF₇ to moles CsXeF₇ (via molar mass), then (2) convert moles CsXeF₇ to moles CsF (via mole-to-mole ratio from equation coefficients), and then (3) convert moles CsF to grams CsF (via molar mass). It is important to arrange the ratios/conversions in a way that allows for the cancellation of units. The final answer should have 3 sig figs to match the sig figs of the given value.

Molar Mass (CsF): 132.91 g/mol + 18.998 g/mol

Molar Mass (CsF): 151.908 g/mol

Molar Mass (CsXeF₇): 132.91 g/mol + 131.29 g/mol + 7(18.998 g/mol)

Molar Mass (CsXeF₇): 397.186 g/mol

1 CsF + XeF₆ -----> 1 CsXeF₇

73.1 g CsXeF₇             1 mole                 1 mole CsF              151.908 g
----------------------  x  --------------------  x  ------------------------  x  ------------------  =
                                  397.186 g           1 mole CsXeF₇             1 mole

=  27.958 g CsF

=  28.0 g CsF

What volume would 20.0 moles of sulfur
dioxide occupy at 75.3 °C with a pressure of
3.50 atm? Answer is in L

Answers

Answer:

163 L

Explanation:

To find the volume, you need to use the Ideal Gas Law. The equation looks like this:

PV = nRT

In this equation,

-----> P = pressure (atm)

-----> V = volume (L)

-----> n = moles

-----> R = constant (0.0821 L*atm/mol*K)

-----> T = temperature (K)

Before you can plug the given values into the equation, you first need to convert Celsius to Kelvin.

P = 3.50 atm                         R = 0.0821 L*atm/mol*K

V = ? L                                   T = 75.3 °C + 273.15 = 348.45 K

n = 20.0 moles

PV = nRT

(3.50 atm)V = (20.0 moles)(0.0821 L*atm/mol*K)(348.45 K)

(3.50 atm)V = 572.1549

V = 163 L

How many moles of Chromium is in 4.41 ×10^24 atoms

Answers

7.32 moles of Chromium is present in 4.41 × 10²⁴ atoms.

How to find the number of moles ?

Number of moles = [tex]\frac{\text{Given number of atoms}}{\text{Avogadro's Number}}[/tex]

     

What is Avogadro's Number ?

Avogadro's number is the number of particles in one mole of substance. 6.022 × 10²³ is known as Avogadro's Constant / Avogadro's Number.

Avogadro's Number = 6.022 × 10²³

Now put the values in above formula we get

Number of moles = [tex]\frac{\text{Given number of atoms}}{\text{Avogadro's Number}}[/tex]

                             = [tex]\frac{4.41 \times 10^{24}}{6.022 \times 10^{23}}[/tex]

                             = 7.32 moles

Thus from the above conclusion we can say that 7.32 moles of Chromium is present in 4.41 × 10²⁴ atoms.

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Analysis of a sample of hydrated salt shows that it contains 4.86 g Mg, 6.20 g P, 11.20 g O, and 5.40 g H2O. What is the formula of the hydrated salt?

Answers

Answer:

Mg₂P₂O₇ · 3 H₂O

Explanation:

(Step 1)

First, you need to convert each mass to moles via the molar masses of each element/compound.

Molar Mass (Mg): 24.305 g/mol

4.86 grams Mg              1 mole
------------------------  x  ------------------------  = 0.200 moles Mg
                                   24.305 grams

Molar Mass (P): 30.974 g/mol

6.20 grams P              1 mole
---------------------  x  ------------------------  =  0.200 moles P
                                30.974 grams

Molar Mass (O): 15.998 g/mol

11.20 grams O               1 mole
-----------------------  x  -----------------------  =  0.700 moles O
                                  15.998 grams

Molar Mass (H₂O): 2(1.008 g/mol) + 15.998 g/mol

Molar Mass (H₂O): 18.014 g/mol

5.40 grams H₂O               1 mole
--------------------------  x  -----------------------  =  0.300 moles H₂O
                                     18.014 grams

(Step 2)

To find the amount of each element/compound in the formula, you need to divide each molar value by the smallest molar value. This allows you to determine the accurate molar ratio the hydrated salt should have. In this case, 0.200 moles is the smallest value.

0.200 moles Mg / 0.200  =  1 mole Mg

0.200 moles P / 0.200  =  1 mole P

0.700 moles O / 0.200  =  3.5 moles O

0.300 moles H₂O / 0.200  =  1.5 moles H₂O

There can only be whole number amounts of each element/compound in the formula. Therefore, you need to multiply each amount by 2.

1 mole Mg x 2 = 2 moles Mg

1 mole P x 2 = 2 moles P

3.5 moles O x 2 = 7 moles O

1.5 moles H₂O x 2 = 3 moles H₂O

(Step 3)

Now that we know the amount of each element/compound, we can build the formula. The amount of each element is represented by subscripts and the amount of each compound (H₂O) is represented by coefficients.

Mg₂P₂O₇ · 3 H₂O

Which of the following rules is applicable for balancing a chemical equation?
Change only the coefficients
Add the coefficients and change the subscripts
Change only the subscripts
Change the coefficients and the subscripts

Answers

Answer:

A.) Change only the coefficients

Explanation:

An equation is balanced when there is an equal quantity of each type of element on both sides of a reaction. When balancing an equation, the only way to manipulate the amounts of each element is by changing the coefficient values. The coefficients alter the amount of each molecule in the reaction.

The subscripts cannot be altered. If you were to change the subscripts, you would be altering the amount of atoms in a particular molecule.

Chemical reaction when chromium metal is immersed in an aqueous solution of cobalt(II)

Answers

The chemical equation for the reaction is [tex]2Cr (s) + 3CoCl_2 (aq) --- > 2CrCl_3 (aq) + 3Co (s)[/tex]

Chemical reaction

Chromium metal is higher in the reactivity series than cobalt. Thus, chromium will displace cobalt from solutions.

Therefore, the equation for the reaction between chromium metal and cobalt (II) chloride will be written as:

[tex]2Cr (s) + 3CoCl_2 (aq) --- > 2CrCl_3 (aq) + 3Co (s)[/tex]

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Chromium metal is immersed in an aqueous solution of cobalt(II) chloride. Express your answer as a chemical equation. Identify all of the phases in your answer. Enter no reaction if no reaction occurs.

Given the reaction below, how many liters of oxygen are formed if 77.37 L of water are produced at STP? (4pts)

2C4H10 (g) + 13O2 (g) → 8CO2 (g) + 10H2O (g)

Round your answer to two decimal places.

Answers

1.2 x 10² L of oxygen is formed if 77.37 L of water is produced.

The density of water at STP = 0.99 g/ ml but we will assume 1 g/ml

Determine the mass of water ([tex]H_{2}[/tex]o) = 77.37 L × [tex]\frac{1000 ml}{1l}[/tex] × [tex]\frac{1g}{ml}[/tex]

The mass of water = 77370 g

Convert mass into moles = 77370 [tex]H_{2}[/tex]o × [tex]\frac{1mol}{18.01528} H _{2}O[/tex]

= 4294.6876 mol of [tex]H_{2} O[/tex]

Use stoichiometry to find how many mols of oxygen [tex]o_{2}[/tex] were used:

= 4294.6876 mol of [tex]H_{2} O[/tex] × [tex]\frac{13 mol }{10 mol}[/tex]

= 5583.0939 mol [tex]o_{2}[/tex]

Convert mols to mass = 5583.0939 mol ×[tex]\frac{32 g}{mol }[/tex]

= 178659.0059 g [tex]o_{2}[/tex]

Convert mass into liters

The density of [tex]o_{2}[/tex] at STP = [tex]\frac{1.439}{ml}[/tex]

Density of [tex]o_{2}[/tex] = 1.2 × [tex]10^{2}[/tex]

Hence,1.2 x 10² L of oxygen is formed if 77.37 L of water is produced.

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1.2 x 10² L of oxygen is formed  if 77.37 L of water are produced at STP. The term is derived from the Greek word "oxy genes," which means "forms acid." a periodic table column that is vertical.

What is oxygen ?

The chemical element oxygen has an atomic number of 8. At normal temperatures and pressures, oxygen transforms into the chemical compound (O2) of two atoms, which is a colorless gas.

The density of H₂O at STP = 0.99 g ÷ ml, but we will assume 1 g/ml

The mass of  H₂O = 77370 g

Use stoichiometry to find  moles of oxygen given by

= 4294.6876 mol of X

= 5583.0939 mol

Convert moles into mass = 5583.0939 mol X

= 178659.0059 g

Then convert it into liter. 1.2 x 10² L of oxygen is formed  if 77.37 L of water.

Thus, 1.2 x 10² L of oxygen is formed  if 77.37 L of water are produced at STP.

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Which of the following was an incentive for profit to settle the Mississippi Valley region?

Availability of fish and furs
Abundance of Native Americans to convert to Catholicism
Mildness of the temperature of the region
Excitement of the wilderness

Answers

The correct option is (a) Availability of fish and furs. An incentive for profit to settle the Mississippi Valley region

Arkansas, Illinois, Iowa, Kentucky, Louisiana, Michigan, Minnesota, Mississippi, Missouri, North Dakota, Tennessee, Wisconsin, and South Dakota are among the 13 states that are either entirely or partially included in the division of Mississippi Valley region

The canoe was the first ferry to travel on the Mississippi River. Long before the white settlers ventured as far west as the Mississippi, it provided the Indians with a means of crossing. It is also one of the most significant commercial waterways in the world and a key fish and bird migration route in North America. Native Americans used the river for transportation and food while they lived along its banks.

Therefore, The correct option is (a) Availability of fish and furs. An incentive for profit to settle the Mississippi Valley region.

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An analyst prepared a sucrose solution by weighing 1kg of water and add 1.5kg of sucrose. what is the concentration of the resultant solution in mass percent

Answers

The concentration of solution in mass percent is 60%.

What is mass percentage?

Mass percentage refer to the percentage of solute present in solution.

The concentration of substance can be expressed in mass percent.

So, we can write,

Mass percent = mass of solute / mass of solution x 100.

Mass of solution = mass of solute + solvent.

Here, sucrose is the solute and water is solvent.

Mass of solute is 1.5Kg and mass of solvent is 1Kg.

Mass of solution = 1.5 + 1 = 2.5 Kg.

Mass percent = 1.5/2.5x100

So, Concentration of solution in mass percent = 60%.

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can someone please fill this out for me

Answers

Filling out the table of elements below following the outlined order:

Calcium - symbol = Ca; Group =2; Period = 4; Ar = 134; Am =40.078u; Ph = solid; Density = 1.55; Bp = 1757K; Mp = 1115K.Vanadium - symbol = V; Group =5; Period = 4; Ar = 197; Am =50.9415u; Ph = solid; Density = 6.11; Bp = 3680K; Mp = 2183K.Manganese - symbol = Mn; Group =7; Period = 4; Ar = 127; Am = 54.938044u; Ph = solid; Density = 7.21; Bp = 2334K; Mp = 1519K.Cobalt: - symbol = Co; Group =9; Period = 4; Ar = 125; Am =58.933195 u; Ph = solid; Density = 8.90; Bp = 3200K; Mp = 1768K.Zinc: - symbol = Zn; Group = 12; Period = 4; Ar = 134; Am =65.38 u; Ph = solid; Density = 7.14; Bp = 1180K; Mp = 692.68K.Arsenic: - symbol = As; Group = 15; Period = 4; Ar = 197; Am = 74.9216 u; Ph = solid; Density = 5.75; Bp = 889K; Mp = 889K.Bromine: - symbol = Br; Group =17; Period = 4; Ar = 120; Am = 79.904 u; Ph = Liquid; Density = 3.1028; Bp = 332K; Mp = 265K.

Meaning of Element

An element can be defined as a substance that can not be broken down into simpler substances.

An element serves as a building blocks for compounds and mixtures.

In conclusion, each element and its property as requested in the table are given above.

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Determine the mass of CO2 produced when 51.2 g of CaO is reacted with 50.0 g of C according to the unbalanced chemical equation:

CaO (s) + C (s) ---> CaC2 (s) + CO2 (g)

Hint: You will need to balance the equation first.

Answers

The mass of CO2 produced will be 8.01 grams

Stoichiometric problem

The balanced equation of the reaction is written as:

[tex]2CaO (s) + 5C (s) --- > 2CaC_2 (s) + CO_2 (g)[/tex]

The mole ratio of CaO and C is 2:5 from the balanced equation.

Mole of 51.2 g CaO = mass/molar mass = 51.2/56 = 0.91 moles

Mole of 50.0 g C = 50/12 = 4.17 moles

From the mole ratio, 0.91 mole CaO will require 5/2 x 0.91 = 2.28 moles C.

This means 4.17 moles carbon is excessive. In other words, C is the limiting reagent.

The mole ratio of C and CO2 is 5:1. Thus, the equivalent mole of CO2 that will be produced from 0.91 moles C will be:

                                  0.91/5 = 0.182 moles.

Mass of 0.182 moles CO2 = mole x molar mass = 0.182 x 44 = 8.01 grams

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The protons of a __________ acid would be completely transferred to the solvent when dissolved.

Group of answer choices

inert

neutral

strong

weak

Answers

The protons of a strong acid would be completely transferred to the solvent when dissolved.

What is an acid?

An acid is defined as a substance that contains hydrogen that it can donate when reacting with another substance.

There are two main types of an acid which include:

weak acids and

strong acids.

A strong acid is a type of acid that has the ability to donate it's hydrogen/ protons completely in a chemical reaction.

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1. Based on the observed performance of the air bag models and the amounts of sodium bicarbonate and acetic acid (vinegar) needed for an automotive air bag of 80 or 160 L, are these reactants a good substitute for sodium azide? One additional note regarding sodium azide: the rate of inflation after a triggering impact is 40 milliseconds (0.04 s).

Answers

Sodium bicarbonate and acetic acid are not good substitute for sodium azide in airbags since the require more mass and produce less gas.

Which is the better chemical for an airbag?

The chemical equation for the production of nitrogen gas from sodium azide is given below:

NaN₃ → 2 Na + 3 N₂

1 mole or 66 go of sodium azide produces 3 moles or 67.2 L of nitrogen gas.

The equation for the production of carbon dioxide from sodium bicarbonate and acetic acid is given below:

Na₂CO₃ + CH₃COOH → CH₃COONa + CO₂ + H₂O

1 mole, 106 g of Na₂CO₃ and 1 mole, 82 g of CH₃COOH are required to produce 1 mole or 22.4 L of CO₂.

The mass of sodium azide required is less than that of sodium bicarbonate and acetic acid required. Also, sodium azide produces a greater volume of gas. Therefore, sodium bicarbonate and acetic acid are not good substitute for sodium azide in airbags.

In conclusion, sodium azide is a better choice in airbags.

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significant use of boiling point in daily life

Answers

Answer:

boiling point can be used to tell how long something I.e water would take to boil.

boiling point can also tell us the amount if heat needed to be applied for the substance to boil

In manufacturing, if you are trying to heat up a plastic material without it boiling, it would be helpful to know the boiling point as to not heat it up too much but heat it up enough to melt it.

The atom is sometimes said to be similar to a miniature planetary system, with electrons orbiting the nucleus. What does the uncertainty principle have to say about this view of the atom?

Answers

Answer:

The uncertainty principle says this view is only a guess, a snapshot of what the electrons around the nucleus could possibly look like. Specifically, the uncertainty principle says that we cannot know the exact location and speed of the electrons. Therefore, the planetary-like arrangement of the electrons around the nucleus is rarely ever assumed.

a saline solution begins to freeze at -1.13 degrees. Express the concentration of NaCl in this solution in mass%. Kf for water is 1.86C degree/m.

Answers

The Percentage mass of NaCl is 1.78%.

What is the percent mass concentration of the NaCl in saline solution.

The percent mass concentration of NaCl in the saline solution is determined from the molality of the solution.

The molality of the solution is further obtained from the freezing point depression formula.

The freezing point depression formula is given as follows:

ΔT = Kf * m * i

where;

ΔT is the freezing point changeKf is a constantm is the molality of the solutioni is the van't Hoff factor

For the solution of NaCl;

ΔT = 0 - (-1.13) = 1.13

Kf = 1.86 °/m

i = 2

m = ΔT/(Kf * i)

m = 1.13/(1.86 * 2)

m = 0.3038 mol/kg

molar mass of NaCl = 58.5 g/mol

Mass of NaCl = 0.3038 * 58.5 = 17.8 g in

Percentage mass of NaCl = (17.8/1000) * 100

Percentage mass of NaCl = 1.78%

In conclusion, the percent mass of NaCl is obtained from the molality of the solution.

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How many molecules are in 120.0 g of oxygen gas?

Answers

1.506 × 10²³ molecules in  120.0 g of oxygen gas.

What are molecules?

The slightest particle of importance contains all of the physical and chemical properties of that substance. Molecules are made up of one or more atoms.

If they include more than one atom, the particles can be the same (an oxygen molecule has two oxygen atoms) or additional (a wetness molecule contains two hydrogen particles and one oxygen atom). Natural molecules, such as proteins and DNA, can be created up of many thousands of atoms.Particles are the introductory unit of an element. They consist of a nucleus and cover electrons. When an atom has an insufficient electron shell, it is said to have valence electrons. When two or more additional atoms come concurrently to share outer surface valence electrons, a chemical (covalent) bond is formed, and they join a lower power state. When atoms bond, significance is released in an exothermic response. If the covalent bond is broken and the molecule is split separated, it needs energy information and is thereby endothermic.

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3 Br2 + 6 OH1- → 5 Br1- + BrO31- + 3 H2O
If 8.5 moles of Br2 are reacted with an unlimited supply of OH1-, how many moles of BrO31- can be formed?

Answers

Answer:

2.8 moles BrO₃⁻

Explanation:

To find the amount of moles, you need to convert moles Br₂ to moles BrO₃⁻ using the mole-to-mole ratio. This ratio is made up of the balanced equation coefficients in front of the relevant molecules.

3 Br₂ + 6 OH⁻ -----> 5 Br⁻ + 1 BrO₃⁻ + 3 H₂O

8.5 moles Br₂           1 mole BrO₃⁻
-----------------------  x  ----------------------  =  2.8 moles BrO
                                  3 moles Br₂

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