Answer:
Approximately [tex]\$ 3.02[/tex].
Explanation:
Note that the electric rate in this question is in the unit dollar-per-[tex]{\rm kWh}[/tex], where [tex]1\; {\rm kWh}[/tex] is the energy to run an appliance of power [tex]1\; {\rm kW}[/tex] for an hour.
Number of minutes for which the air conditioner is running in that day: [tex]15 \times 24 = 360\; \text{minute}[/tex]. Apply unit conversion and ensure that this time is measured in hours (same as the unit of the electric rate.)
[tex]\begin{aligned} \text{time} &= 360\; \text{minute} \times \frac{1\; \text{hour}}{60\; \text{minute}} = 6\; \text{hour} \end{aligned}[/tex].
The power of this air conditioner is:
[tex]\begin{aligned} \text{power} &= \text{voltage} \times \text{current} \\ &= 240\; {\rm V} \times 21\; {\rm A} \\ &= 5040\; {\rm W} \\ &= 5.04\; {\rm kW} \end{aligned}[/tex].
Thus, the energy that this air conditioner would consume would be:
[tex]\begin{aligned}\text{energy} &= \text{power} \times \text{time} \\ &= 5.04\; {\rm kW} \times 6\; \text{hour} \\ &= 30.24\; {\rm kWh} \end{aligned}[/tex].
At a rate of [tex]0.1[/tex] dollar-per-[tex]{\rm kWh}[/tex], the cost of that much energy would be approximately [tex]3.02[/tex] dollars (rounded to the nearest cent.)
Chicago, il is currently in the e climate zone.
a) true
b) false
Answer:
false
Explanation:
an object has a mass of 50kg, a final height of 20m and an initial height of 8m. what is the amount of work done
amount of work done is 5880 J
Given:
mass of object = 50kg
Final height = 20m
initial height = 8m
To Find:
amount of work done
Solution:
work is done when a force acts upon an object to cause a displacement. You can calculate the energy transferred, or work done, by multiplying the force by the distance moved in the direction of the force.
The work done by gravity is given by the formula,
W = mgh
W = 50 x 9.8 x ( 20-8)
= 5880 J
So the work done is 5880 J
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A block is thrown with an initial velocity of 30.0 m/s at an angle of 25.0o above the horizontal. What is the highest elevation reached by the ball in its trajectory in meter
The highest elevation reached by the ball in its trajectory is 16.4 m.
To find the answer, we need to know about the maximum height reached in a projectile.
What's the mathematical expression of the maximum height reached in a projectile motion?
The maximum height= U²× sin²(θ)/gU= initial velocity, θ= angle of projectile with horizontal and g= acceleration due to gravityWhat's the maximum height reached by a block that is thrown with an initial velocity of 30.0 m/s at an angle of 25° above the horizontal?
Here, U = 30.0 m/s and θ= 25°Maximum height= 30²× sin²(25)/9.8= 16.4m
Thus, we can conclude that the highest elevation reached by the ball in its trajectory is 16.4 m.
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A CD has diameter of 110110 millimeters. When playing audio, the angular speed varies to keep the linear speed constant where the disc is being read. When reading along the outer edge of the disc, the angular speed is about 220220 RPM (revolutions per minute). Find the linear speed.
Answer: A CD has diameter of 110 millimeters. When playing audio, the angular speed varies to keep the linear speed constant where the disc is being read. When reading along the outer edge of the disc, the angular speed is about 220 RPM (revolutions per minute). Then, the linear speed of the disc will be 1.26 m/s.
Explanation: To find the answer we need to know about the uniform circular motion.
What is uniform circular motion?When a body moves in a circular path with a constant speed, it is said to be in uniform circular motion.The rate of change of angular displacement is called the angular velocity.Relation between angular velocity, linear velocity and the radius of revolution is given as,[tex]v=rw[/tex]
The relation between angular velocity and the frequency of revolution can be written as,[tex]w=2\pi f[/tex]
How to solve the problem?Given that the diameter of the disc as 110mm.Thus, the radius of the disc will be 55 mmThere are 220 revolutions per minute, thus the angular velocity w will be,[tex]w=2\pi f=2\pi *220 min^{-1}=1381.6 min^{-1}[/tex]
As we know that,[tex]1mm=10^{-3}m\\1min=60s\\thus,\\w=\frac{1381.6}{60} =23.02 s^{-1}.[/tex]
Thus, the linear speed will be,[tex]v=wr=23.02*55*10^{-3}=1.26 m/s[/tex]
Thus, we can conclude that the linear speed of the disc will be 1.26 m/s.
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Disclaimer: The question was given wrong in the given portal. Here is the correct question.
Question: A CD has diameter of 110 millimeters. When playing audio, the angular speed varies to keep the linear speed constant where the disc is being read. When reading along the outer edge of the disc, the angular speed is about 220 RPM (revolutions per minute). Find the linear speed.
A standard rum and cola will be absorbed faster than a 5-ounce glass of wine because.
Absorption of Rum and cola:
A standard rum and cola absorb faster than a 5-ounce glass of wine because carbonation causes the pyloric valve to relax.
What are Rum and Cola:
The second-most common alcoholic beverage in the world is rum and coke, which is very well-liked. Its widespread availability, low cost, and ease of preparation are what contribute to its appeal. It is easy to prepare and challenging to destroy because it can be produced with any quantity or type of rum. Due to the pyloric valve's relaxation caused by carbonation, alcohol like rum and coke is often absorbed more quickly than 5 ounces of wine.Absorption is accelerated by carbonation. Alcohol will enter the bloodstream more quickly when combined with carbonated drinks like Coca-Cola or tonic water.Learn more about the alcoholic beverages here,
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Why do we tallk about radio waves as a group and not the frequeny of radio waves
A car goes around a curve at a constant speed. what is the direction of the net force on the car?
Answer:
The direction of the net force is at a tangent to the circle.
A billiard ball at rest is struck by another billiard ball of the same mass whose speed is 6.0 m/s. After an elastic collision the striking ball goes off at an angle of 25° with respect to its original direction of motion. Find the angle the struck ball makes with this direction and the final speeds of both balls.
The angle that the stuck ball makes with the direction of motion and the velocity of both the billiard balls are 65°, 2.6 m/s and 5.5m/s respectively.
To find the answer, we need to know about the linear momentum and angle made in elastic 2 dimensional collision.
What's the angle made by the struck billiard ball with the direction of motion of the 1st ball?In the two dimensional elastic collision between two objects, the scattered objects make 90° angle between them.So, here the angle between the two billiard balls after collision is 90°.As the one billiard ball is making 25° with the initial direction of motion, so the another struck billiard ball makes 90°-25°= 65°.What's the conservation of linear momentum along vertical direction?Let m = mass of each billiard balls, v = velocity of scattered billiard ball, u = velocity of struck billiard ballBefore collision there's no vertical component of momentum. So it's zero.From figure, the total momentum along vertical direction is m×v×sin25°-m×u×sin65°From conservation of linear momentum,0= m×v×sin25°-m×u×sin65°
v×sin25°=u×sin65°
v= 2.1u
What's the conservation of momentum along horizontal direction as shown in figure?Total momentum before the collision along horizontal direction = m × 6 m/sFrom the figure, total momentum after collision is m×v×cos25° + m×u×cos65°So, m×6 = m×v×cos25° + m×u×cos65°6= 2.1u× cos25° +u×cos65°
= 2.33u
u = 6/2.33 = 2.6 m/sAnd v= 2.1×2.6= 5.5 m/sThus, we can conclude that the angle that the stuck ball makes with the direction of motion and the velocity of both the billiard balls are 65°, 2.6 m/s and 5.5m/s respectively.
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State Newton's second law of motion and establish the relation F = m x a
F = ma is the formula of Newton's Second Law of Motion. Newton's Second Law of Motion is described as Force is equal to the rate of change of momentum. For a constant mass, force equals mass duration acceleration.
What is the significance of Newton's second law of motion explain?
Newton's Second Law of Motion F=ma is very significant because it indicates the relationship between forces and motion. It permits you to calculate the acceleration (and therefore velocity and position) of an object with known forces. This is extremely helpful for scientists, engineers, inventors, etc.
Force is directly proportional to Shift in momentum ÷ Time taken.Therefore : F is directly proportional to m×a. This relation F is directly proportional to m×a can be turned into an equation by placing in a constant k.
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The Effect of the Light Intensity and Light Distances of LED and QTH Curing Devices on the Hardness of Two Light-Cured Nano-Resin Composites
Effective polymerization of the composite resin is essential to obtain long term clinical success and has a great importance obtaining improved mechanical properties.
What is the purpose of Effective polymerization of the composite resin ?The purpose of this study was to measure the effect of the light intensity of LED and QTH curing devices in relation to the light distances, on the hardness (KHN) of two light cure nano-resin composite.
Material and Methods: The top and bottom surfaces of the two nanofill composite specimens were evaluated. Two LED and two QTH light curing devices were used at nine different distances. Light intensity was measured with two radiometers placed at these same distances from the curing tip.Learn more about Light intensity here:
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Aluminum and copper wires of equal length are found to have the same resistance. What is the ratio of their radii
Answer:
R = ρ L / A resistance of wire
ρC / ρA = [RC AC/ LC] / [RA AA/ LA} = AC / AA
Since resistance and length are the same for both wires where A is the area of the wire
ρC / ρA = rC^2 / rA^2 where r is the radius of the wire
(ρC / ρA)^1/2 = rC / rA
rC / rA = (1.72 / 2.83)^1/2
rC / rA = .780 radius of copper wire is .780 of aluminum wire
A bodybuilder deadlifts a 215 kg weight to a height of 0.90 m above the ground. If he deadlifts this weight 10 times in a span of 45 seconds, how much power has he exerted?
Group of answer choices
a. 8,530 W
b. 421 W
c. 853 W
d. 4,210 W
A bodybuilder deadlifts 215 kg to a height of 0.90 m. If he deadlifts this weight 10 times in 45 s, the power exerted is 421 W (b.)
What is power?In physics, power (P) is the work (W) done over a period of time.
Step 1. Calculate the work done by the bodybuilder each time.The bodybuilder lifts a 215 kg (m) weight to a height of 0.90 m (h). Being the gravity (g) of 9.81 m/s², we can calculate the work done in each lift using the following expression.
W = m × g × h = 215 kg × 9.81 m/s² × 0.90 m = 1.9 × 10³ N
Step 2. Calculate the work done by the bodybuilder over 10 times.W = 10 × 1.9 × 10³ N = 1.9 × 10⁴ N
Step 3. Calculate the power exerted by the bodybuilder.The bodybuilder does a work of 1.9 × 10⁴ N in a 45-s span.
P = 1.9 × 10⁴ N/45 s = 421 W
A bodybuilder deadlifts 215 kg to a height of 0.90 m. If he deadlifts this weight 10 times in 45 s, the power exerted is 421 W (b.)
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If the platinum-based engine is run continuously at 300 k for 1 hour with 0.50 atm of h2 and 0.50 atm of o2 injected for each reaction, approximately what mass of water will be produced?
About 4.5 mol of water will be created when the platinum-based engine is run continuously at 300 K for an hour with 0.5 atm of H2 and 0.5 atm of O2 injected for each reaction.
For fuel cell engines' electrodes, platinum is a requirement. It acts as an electrocatalyst to speed up the electrochemical reactions needed to induce H2 to release electrons and form H2 ions when it is placed on porous electrodes.
Platinum is particularly well suited as a fuel cell catalyst because it makes it possible for the hydrogen and oxygen reactions to occur at an ideal rate and because it is stable enough to withstand both the intense electrical current density and the complex chemical environment found inside a fuel cell. This allows platinum to function effectively over an extended period of time.
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Electric forces can be explained using fields that extend through space. We can think of these fields as surrounding any charged object. What is one advantage of thinking about the electric force as a field?
Electric forces can be explained using fields that extend through space. We can think of these fields as surrounding any charged object. The force acting on a charged particle at a spot may be calculated by knowing the electric field there. This is further explained below.
What is one advantage of thinking about the electric force as a field?The electric force is the term used to describe the repulsion or attraction between two charged things. Newton's rules of motion define how a force interacts with a particular body.
In conclusion, Space-spanning fields may be used to explain electric forces. These fields may be thought of as enclosing any charged object. Knowing the electric field at a certain location will allow one to compute the force acting on a charged particle there.
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Answer:
(Choice B, Checked, Correct) A field helps predict how electric forces will affect any charge at any location in the field.
Explanation:
CORRECT (SELECTED)
A field helps predict how electric forces will affect any charge at any location in the field.
Modeling the electric force as a field can help us understand electric forces. For instance, we know that any charge in an electric field will experience an electric force. We don’t need to measure the force on each charge to know its direction.
A carnival Ferris wheel has a 15-m radius and completes five turns about its horizontal axis every minute. What is the acceleration of a passenger at his lowest point during the ride
If a Ferris wheel has a 15-m radius and completes five turns about its horizontal axis every minute then the acceleration of a passenger at his lowest point during the ride is 4.11 [tex]\text{m/s}^{2}[/tex].
Calculation:
Step-1:
It is given that the radius of the Ferris wheel is r=15 m, and the angular speed of the wheel is [tex]\omega[/tex]=5rev/min.
It is required to find the angular acceleration of a passenger at his lowest point during the ride.
The formula required to calculate the angular acceleration is, [tex]a=\omega ^2 r[/tex].
Step-2:
Now substituting the given values into the equation to get the value of the angular acceleration.
[tex]\begin{aligned}a &=\omega^{2} r \\&=(5 \mathrm{rev} / \mathrm{min})^{2}(15 \mathrm{~m}) \\&=\left(5 \mathrm{rev} / \mathrm{min} \times \frac{\left(\frac{2 \pi}{60}\right) \mathrm{rad} / \mathrm{sec}}{1 \mathrm{rev} / \mathrm{min}}\right)^{2}(15 \mathrm{~m}) \\&=(0.2741 \times 15) \mathrm{m} / \mathrm{s}^{2} \\&=4.11 \mathrm{~m} / \mathrm{s}^{2}\end{aligned}[/tex]
The acceleration is towards upwards that means towards the center of the wheel.
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When operating an aircraft at cabin pressure altitudes above 12,500 feet msl up to and including 14,000 feet msl, supplemental oxygen shall be used during?
Supplemental oxygen shall be used in that flight time in excess of 30 minutes at those altitudes.
Most plane cabins are pressurized to 8,000 feet above sea level, an altitude that lowers the amount of oxygen inside the blood by approximately 4 percentage points, researchers say.
The higher the altitude, the less oxygen there is in the air and the lower the overall air pressure is. If flights were not pressurized, passengers could be prone to various physiological illnesses. Because of this, federal policies require that all commercial flights over 8,000 feet be pressurized.
The flight crew must use supplemental oxygen for the entire duration of flight operations above a cabin pressure altitude of 14,000 feet MSL.
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The lion has a kinetic energy of 5000 j. What is the speed of the lion?
The lion has a kinetic energy of 5000 j, the speed of the lion is v = 100 / [tex]\sqrt{M1}[/tex] m/s
What is kinetic energy ?Kinetic energy is a form of energy that an object or a particle has by reason of its motion. If work, which transfers energy, is done on an object by applying a net force, the object speeds up and thereby gains kinetic energy or Kinetic energy is the energy that an object possesses due to its motion. It is basically the energy of mass in motion. Kinetic energy can never be negative and it is a scalar quantity i.e. it provides only the magnitude and not the direction.
given
kinetic energy = 5000 J
speed = ?
since , mass is not given in the question
Let mass of lion will be = M1
kinetic energy = 1/2 * M1 * [tex]v^{2}[/tex]
5000 J = 1/2 * M1 * [tex]v^{2}[/tex]
[tex]v^{2}[/tex] = [tex]\sqrt{10,000 / M1}[/tex] m/s
v = 100 / [tex]\sqrt{M1}[/tex] m/s
The speed of the lion = v = 100 / [tex]\sqrt{M1}[/tex] m/s
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Two 1-d waves of amplitude a and period t and constant phase 0 are superposed. If wave 1 travels 13. 5 wavelengths farther than wave 2, will the interference be:________
Two 1-d waves of amplitude a and period t and constant phase 0 are superposed. If wave 1 travels 13. 5 wavelengths farther than wave 2, the interference is 3/2π.
Interference of light is the phenomena of multiple light waves interfering with each other under certain circumstances, causing the mixed amplitudes of the waves to both boom or lower.one of the exceptional examples of interference is demonstrated by the light contemplated from a film of oil floating on water.
The phenomenon of addition or superposition of mild waves which produces an increase in intensity at some factors and a decrease in depth at a few other points are known as interference of light.
The intensities of light at exceptional factors of the medium are distinctive. At a few factors of the medium, depth is most and at a few different points intensity is maximum ( about 0) This phenomenon is called the interference of mild waves, the interference is known as negative interference.
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A mass m is attached to an ideal massless spring. When this system is set in motion with amplitude a, it has a period t. What is the period if the amplitude of the motion is increased to 2a?.
Time period is T if increasing the amplitude to 2A
What is Time period?
The length of time during which an activity occurs or a condition remains.
The period of a spring-mass system is proportional to the square root of the mass and inversely proportional to the square root of the spring constant.
Formula of Time period, T:
[tex]T = 2\pi \sqrt{\frac{M}{k} }[/tex]
Where,
k is the spring constant
mass of system = M
Amplitude = A
Time period = T
Here,
The amplitude is doubled = 2A
Since from the formula we can say that, The Time period is not dependent on amplitude.
Increasing the amplitude implies increase in the restoring force. An increase in the restoring force means the mass is now accelerated to cover more distance in the same period.
So the restoring force cancels the effect of the increase in amplitude.
Hence,
Time period is T if increasing the amplitude to 2A
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The _______________ is the point in an object where there is as much weight on one side as on the other side. This is also called the center of balance.
The center of gravity is the point in an object where there is as much weight on one side as on the other side. This is also called the center of balance.
what do you mean by center of balance and center of gravity ?
A location where an object is balanced in relation to applied forces is known as the center of balance (COB).
The average location of an object's weight is known as its center of gravity. Any object's travel through space may be completely explained in terms of how its center of gravity moves from one location to another and, if it is free to spin, how it rotates around that center of gravity.
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Josie ran at an average speed of 16 m/s. if her mass 10 kg, what was her kinetic energy as she crosses her finish line?
Answer: 1280 J
[tex]KE=\frac{1}{2}mv^{2} \\\\KE= \frac{1}{2} (10 kg)(16 m/s)^2\\=1280 J[/tex]
I have to be honest with you . . . It's not possible to determine the answer with only the information given in the question.
Kinetic energy = (1/2) (mass) (speed squared).
Josie's Kinetic energy as she crosses the finish line is
(1/2) (her mass) (her speed as she crosses the finish line)².
That's (5 kg) x (her speed as she crosses the finish line)² .
But read the question again.
WE DON'T know her speed as she crosses the finish line.
The question only tells us her average speed for the whole race.
We can be confident that her Average Kinetic Energy was
(5 kg) (16 m/s)² = 1,280 Joules.
But we can't tell what her kinetic energy was as she crossed the finish line, beause we don't know what her speed was at that instant.
Your older brother approaches a stop sign at a velocity of 14 m/s [E] as the light turns amber, He applies the brakes to get the maximum stopping force while avoiding skidding. The car has a mass of 1500 kg, and the coefficient of friction between the tires and the road is 1.07. Ignoring your brother's reaction time, calculate:
a) The maximum deceleration of the car
b) The stopping distance
The maximum deceleration of the car is 10.5 m/[tex]s^{2}[/tex] approximately. While the stopping distance is 9.3 m
What is Stopping Force ?
Stopping force is the force required to stop the object in motion. Stopping force is tantamount to frictional force.
Given that a brother approaches a stop sign at a velocity of 14 m/s [E] as the light turns amber, He applies the brakes to get the maximum stopping force while avoiding skidding. The car has a mass of 1500 kg, and the coefficient of friction between the tires and the road is 1.07. Ignoring your brother's reaction time.
The given parameters are;
Velocity V = 14 m/sMass m = 1500 kgCoefficient of friction μ = 1.07Deceleration a = ?Stopping distance S = ?The normal reaction N = mg
N = 1500 x 9.8
N = 14700 N
The stopping force = μN = ma
1.07 x 14700 = 1500a
15729 = 1500a
a = 15729/1500
a = 10.486 m/[tex]s^{2}[/tex]
From 3rd equation of motion
[tex]V^{2}[/tex] = [tex]U^{2}[/tex] + 2aS
where U = 0
[tex]14^{2}[/tex] = 2 x 10.486 x S
196 = 20.972S
S = 196/20.972
S = 9.3 m
Therefore, the maximum deceleration of the car is 10.5 m/[tex]s^{2}[/tex] approximately. While the stopping distance is 9.3 m
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A 1436. 32' line has an azimuth of 178 52 13. What is the latitiude and departure of the line?
Latitude of the line will be = 1436.033
Departure of the line will be = 28.152
Given
let line be = a = 1436. 32
azimuthal be = x = 178° 52' 13''
This line must have two components , one is horizontal component which is its latitude and other will be vertical component which is departure . Resolving both the components we get,
latitude = a*cos(178° 52' 13'')
= 1436. 32 * cos(178° 52' 13'')
= 1436. 32 * (- 0.9998)
latitude = 1436.033
departure = a * sin (178° 52' 13'')
= 1436. 32 * 0.0197
departure = 28.152
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A proton exits the cyclotron 1. 0 ms after starting its spiral trajectory in the center of the cyclotron. How many orbits does the proton complete during this 1. 0 ms ?.
(a) The diameter of the largest orbit just before the protons exit the cyclotron is 39 cm.
(b) The number of orbits completed by the proton during this 1.0 ms is 14000 revolutions.
What is kinetic energy?
The kinetic energy of an object is the energy that it possesses due to its motion.
It is defined as the work needed to accelerate a body of a given mass from rest to its stated velocity.
Formula of KE:
K.E = 1/2mv²
mv² = 2 K.E
v = sqrt( 2*KE / M)
Here,
(a)
The KE of the medical isotopes = 6.5 MeV
substituting the values,
v = sqrt( 2* 6.5* 1.6* 10^-13 / 1.67* 10^-27 )
v = 3.53 × 10⁷ m/s
Now the centripetal force:
mv² / R = qvB
r = q*v / mv²
r = ( 1.67* 10^-27 * 3.53 × 10⁷ ) / ( 1.9* 1.6* 10^-19 )
r = 0.19415 m
diameter d = 2r,
d= 2(0.19415 m)
d= 0.39 m ≅ 39 cm
(b)
The time period to complete a revolution around the spiral trajectory is:
T = 2πr / v
T = 2*3.14* 0.1941 / 3.53*10^7
T = 0.7 × 10⁻⁷ s
Thus, the number of orbits that the proton does to complete the revolution in 1 ms is:
n = t / T
n = 10^-3 / (0.7*10^-7)
n = 14285.71 ≅ 14000 revolutions
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Your question is incomplete, but most probably full question was:
A medical cyclotron used in the production of medical isotopes accelerates protons to 6.5 MeV. The magnetic field in the cyclotron is 1.9 T.
(a) What is the diameter of the largest orbit, just before the protons exit the cyclotron? Express your answer with the appropriate units. d = 57 cm Previous
(b) A proton exits the cyclotron 1.0 ms after starting its spiral trajectory in the center of the cyclotron. How many orbits does the proton complete during this 1.0 ms?
There are many muscles in our body. our body uses muscles to move parts of our body. a part that needs to move a lot will have a higher number of muscles. which of the following parts is most likely to have the most muscles? a. ear lobe b. stomach c. teeth d. brain
Option b) Stomach is most likely to have the most muscles.
There are five main muscles in stomach pyramidalis, rectus abdominus, external obliques, internal obliques, and transversus abdominis.
Muscles circulate frame parts by contracting after which relaxing. muscular tissues can pull bones, however, they cannot push them to return to their unique role. so they paintings in pairs of flexors and extensors. The flexor contracts to bend a limb at a joint.
The muscle groups that circulate our frame elements are called skeletal muscles, and they're a form of striated muscle. We will actively manipulate those with our brains. another sort of striated muscle is those that maintain our hearts pumping, which we are not able to actively control.
Muscles pull at the joints, allowing us to move. a couple of muscular tissues are used for any sort of motion of a bone. Although we are sitting flawlessly nevertheless, muscle tissues at some point in the frame are constantly shifting.
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17% Part (a) Calculate the x-component of the electric field at point P due to charge Q1. Write your answer in units of N/C.
The x component would be Ex = 412 x cos 49° = 270 N/C
Assume there is a small positive charge located at point P. By definition the magnitude of the electric field at point P due to charge Q1 is
E = kQ1/d2
where k is the coulomb constant and d is the straight line distance from Q1 to P.
The distance is the hypotenuse of the triangle formed by Q1, Q2, and P.
d = √0.065^2 + 0.075^2 = 0.099 m at an angle of θ = arctan 7.5/6.5 = 49°.
|E| = 8.99 x 10^9 Nm^2 C^-2 x 0.45 x 10^-9 C/ 0.099^2 m^2 = 412 n/C
The x component would be Ex = 412 x cos 49° = 270 N/C
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Tuning forks with a frequency of 500 to 1000 hz are most commonly used to measure:________
Tuning forks with a frequency of 500 to 1000 hz are most commonly used to measure: hearing loss
A person is said to have hearing loss if they are not able to hear as well as someone with normal hearing, meaning hearing thresholds of 20 dB or better in both ears. It can be mild, moderate, moderately severe, severe or profound, and can affect one or both ears.
High-pitched tuning fork with frequency of 500 to 1000 hertz (Hz) should be used to estimate hearing loss in range of normal speech (300 to 3000 Hz).
The 512-Hz Rinne tuning fork test could be very effective at detecting conductive hearing losses when performed by an experienced tester and when masking was used . Tuning forks are used to carry Rinne and Weber tests. These tests provide a quick easy method of determining whether a hearing loss is situated in the middle ear or inner ear
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White lights can sometimes be found on what kind of buoys?
a. daytime buoys
b. green buoys
c. red buoys
White lights can sometimes be found on red buoys.
Hence, Option C is correct answer.
How can we understand that White lights can sometimes be found on red buoys?Buoys consist of a float, mooring chain and anchor. They may be equipped with lights and/or sound signals such as bells, gongs, or whistles.We know that, Red buoys are found on the starboard side of a channel when entering from seaward and can be lighted buoys, nuns, or triangular daymarks. Red buoys, if lit, have red or white lights, and the light pattern can be fixed, flashing, occulting, quick–flashing, or of equal intervals.Thus from the above conclusion we can say that White lights can sometimes be found on red buoys.
Hence, Option C is correct answer.
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Barry slides across an icy pond. The coefficient of kinetic friction between his
shoes and the ice is 0.15. If his mass is 83 kg, what is the force of friction
acting on him?
OA. 813 N
B. 1150 N
C. 122 N
D. 352 N
The force of friction acting on him is 122 N. The correct answer is option C
What is Friction ?Friction is a force that opposes the motion of a static or a moving object.
Given that Barry slides across an icy pond. The coefficient of kinetic friction between his shoes and the ice is 0.15. If his mass is 83 kg
The given parameters are;
Mass m = 83 kgCoefficient of kinetic friction μ = 0.15Frictional force [tex]F_{r}[/tex] = ?The normal reaction N on the body = mg
N = 83 x 9.8
N = 813.4 N
The Frictional force formula is [tex]F_{r}[/tex] = μN
[tex]F_{r}[/tex] = 0.15 x 813.4
[tex]F_{r}[/tex] = 122.01 N
Therefore, the force of friction acting on him is 122 N approximately.
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Read the following questions and answer them using complete sentences. Be sure to fully explain your answers.
What can be the challenges of wave power? Is it a reliable source of energy?
Wave power can be regarded as a reliable source of energy because the ocean currents are always moving.
What can be the challenges of wave power?Wave power is a device that can be used to convert the mechanical energy of the ocean waves into electrical energy based on the principle of conservation of energy.
The major challenges that face the use of wave power in electricity generation is the unreliability of the waves which leads to uncertainty in the quantity of power generated Also, the wave direction and direction of ocean currents all limit the amount of power generated by this method. However, in spite of challenges, it can be regarded as a reliable source of energy because the ocean currents are always moving.
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