the final velocity of the car (in m/s) after the collision is 6.25 m/s
12.5 m/s is moving in the initial direction of the car
1. A car of mass 1500 kg moving at a speed of 25.0 m/s collides with a truck of mass 4500 kg at rest. the bumpers of both vehicles lock on impact.
A. Compare the force exerted by the car on the truck with the force exerted by the truck on the car during the collision. Is one force greater than the other, or are they equal in magnitude?
the force exerted by the car on the truck and the force exerted by the truck in the collision.
creates a pair of actions and reactions
are equal in magnitude and opposite in direction according to Newton's third law
b. What is the final speed of the car and the truck just after the collision? show your calculations.
v=m1u1+m2u2/m1+m2=1500*25+0/1500+4500=6.25 m/s
2. the same collision as in the above question occurs, but this time the car and truck bounce off each other completely elastically.
C. Compare the force exerted by the car on the truck with the force exerted by the truck on the car in the collision. is one force greater than the other or are they equal?
the force exerted by the car on the truck and the force exerted by the truck in the collision.
creates a pair of actions and reactions
are equal in magnitude and opposite in direction according to Newton's third law
d. what is the final speed of the car and truck just after the collision?
view the calculation
v1=[m1-m2/m1+m2]u1+[2m2/m1+m2]u2=[1500-4500/6000]*25+[9000/6000]*0=-12.5 m/s
a negative sign means the car is moving backwards at 12.5 m/s
v2=[m2-m1/m1+m2]u2+[2m1/m1+m2]u1=[4500-1500/6000]*0+[3000/6000]25=12.5 m/s
moves in the original direction of the car
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a sample of gas is confined in a cylinder with a moveable piston of mass m that is initially held fixed. there is a block of mass 2m on top of the piston, as shown in the figure. a free-body diagram for the block is also shown, which includes the normal force fn exerted on the block by the piston and the weight wb of the block. the upward force that the gas exerts on the piston has magnitude fgas. what is the acceleration of the block immediately after the piston is released?
To draw a free body diagram, draw the object of interest, plot all the forces acting on it, and decompose all force vectors into their x and y components.
A separate free body diagram must be drawn for each object in question. There are not always four forces acting on an object. The number of forces represented in the free body diagram can be one, two, or three. External forces acting on an object include friction, gravity, normal forces, drag, tension, or human force by pushing or pulling. In non-inertial frames (see Frames below), conceptual forces such as centrifugal pseudo-forces are appropriate.
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which combination of neurological imaging techniques contains two methods that utilize magnetic imaging?
MRI and FMRI are the combination of neurological imaging techniques contains two methods that utilize magnetic imaging.
A magnetic field and radio waves produced by a computer are used in the magnetic resonance imaging (MRI) medical imaging procedure to provide precise images of the organs and tissues inside your body.
Large, magnetized tubes are the common shape of MRI equipment. The magnetic field briefly realigns water molecules in your body as you lie within the MRI machine. To produce cross-sectional MRI pictures, which resemble the slices of a loaf of bread, radio waves induce these aligned atoms to emit tiny signals.
Your doctor can evaluate your organs, tissues, and skeletal system with an MRI without performing any intrusive procedures. It generates detailed images of the body's.
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an object of mass 10.0 kg is initially at rest. a 100 n force causes it to movehorizontally through a distance of 6.00 m along a frictionless surface. what is the changein the kinetic energy of this object?
The change in the kinetic energy of this object is 600 J, when an object of mass 10 kg is initially at rest, and 100 N force cause it move horizontally at a distance of 6 m.
Mass of the object = 10kg
Force = 100N
Distance = 6m
Change in kinetic energy of this object =Δ KE
Expression for the change in the kinetic can be given as follows:
Δ Kinetic Energy = W
,W is the workdone on the object.
This is given by the formula below,
W= F *d
Hence,
Δ KE = F × d
Δ K.E= (100N × 6m)
Δ K.E. = 600Nm
Δ K.E. = 600 Joule
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a race car traveling at a constant speed of 50 m/s drives around a circular track that is 500 m in diameter. what is the magnitude of the acceleration of the car
The magnitude of the acceleration of the car was 10m/s^2
what is magnitude?
Magnitude is defined in physics as an object's maximal size and direction. Magnitude is utilised in vector and scalar variables as a common factor. Scalar quantities, by definition, are those with only magnitude. Whereas vector quantities have both magnitude and direction.
Magnitude can be used in a variety of contexts. Some of them include
The magnitude of the earthquake
Charge magnitude on an electron
Force magnitude
The magnitude of the displacement
Gravitational force magnitude
acceleration (a)= v^2/r
v=speed
r=radius
d=diameter=500
r=d/2=500/2=250
a= 50^2/250
=10 m/s^2
Therefore the acceleration was found to be 10m/s^2
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consider a neutron star with a mass equal to the sun, a radius of 11 km , and a rotation period of 1.0 s . what is the speed of a point on the equator of the star?express your answer with the appropriate units.
At equator line the speed of the star is 69115 m/s
When a big star runs out of heat and collapses, neutron stars are created. Every proton and electron in the star's core, or most central region, fuse into neutrons as it falls. These freshly generated neutrons can stop the collapse, leaving a neutron star behind, if the core of the collapsing star is between one and three solar masses.
Radius is 11 km
Period of rotation is 1 second
Converting radius to meters:
11 km = 11 x 10^3 = 11000m
We know that the velocity relation is v = 2πr/T
v = 2 x π x r / 1
v = 2π x 11000
v = 69115 m/s
Hence the speed of the star at the equator is 69115 m/s
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a track star runs a 230 m race on a 230 m circular track in 26 s. what is his angular velocity (in rad/s) assuming a constant speed? (enter the magnitude.)
Using the concepts of angular displacement, we got that 0.241 rad/s is the angular velocity of track star which runs a 230 m race on a 230 m circular track in 26 s.
We know very well that angular velocity is given by change in angular displacement per unit time.
Here, we can see that a truck distance covered and length of circular track is same.
Perimeter of circular track is equal to the distance covered by the truck.
It means, truck rounds a full circle in 26 sec
So, the angle covered by truck is 360° or 2π radian.
Initially angle is 0 radian and final angle is 2π radian
Therefore, angular velocity =(θ[tex]_f_i_n_a_l[/tex] -θ[tex]_i_n_i_t_i_a_l[/tex])/time
=> ω=(2π-0)/26
=>w=(2π/26)
=>w=(2×3.14)/26
=>ω=6.28/26
=>w=0.241 rad/sec.
Hence, when a track star runs a 230 m race on a 230 m circular track in 26 s, the angular velocity assuming a constant speed is 0.241 rad/sec.
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a 15 kg block slides on a horizontal, frictionless surface until it encounters a spring with a spring constant of 3600 n/m. the block comes to rest after compressing the spring a distance of 0.052 m. what is the initial speed of the block?
The initial speed of the block is 0.648 m/s
Define distance?
Distance is a quantitative or qualitative measurement of the distance between two objects or places. Distance can refer to a physical length or an estimation based on other factors in physics or common use (e.g. "two counties over"). Because spatial cognition is a rich source of conceptual metaphors in human thought, the term is also used metaphorically to mean an estimation of the amount of difference between two similar objects (such as statistical distance between probability distributions or edit distance among strings of text) or a degree of separation (as exemplified by distance between people in a social network). The concept of a metric space is used to codify most such conceptions of distance, both physical and metaphorical.
Given;
mass of block, m = 15 kg
force constant k = 3600 N/m
compression , x = 0.052 m
kinetic energy = elastic potential
¹/₂mv² = ¹/₂kx²
mv² = kx²
v=√Kx^2/m
where;
v=initial speed of the block
x=compression of the spring
v=√3600 x (0.052)^2/15
v=0.648m/s
the initial speed of the block was 0.648 m/s
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which layer of the atmosphere is the hottest due to the large amount of kinetic energy of it's molecules
The hottest part of the atmosphere is called the thermosphere.
This region is the hottest because UV rays cause ionization, and because solar radiation is absorbed here, temperature rises with altitude.
What are the atmospheric layers?The troposphere, stratosphere, mesosphere, and thermosphere are the four principal layers of the atmosphere. Depending on how it is defined, the atmosphere's thickness ranges from 100 to 10,000 kilometers.The troposphere is generally warm at the base and cools as it rises. At its base, the stratosphere is quite cool, but as you ascend, it becomes hotter.Ozone generation generates heat, which causes temperatures to rise from an average of -60°F (-51°C) at the tropopause to a maximum of roughly 5°F (-15°C) at the top of the stratosphere. Because of the temperature gradient with height, warmer air is found above cooler air.To learn more about atmospheric layers refer to:
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If the force on a cart is doubled, what happens to the acceleration of the cart?.
Answer:
It will be doubled
Explanation:
F = ma
Let's consider m = 1 (the mass of the cart is not changing so it is constant),
F = 2, and a = 4.
2 = 1 x 4
When doubling force we need to maintain equality so acceleration should double too. To understand it better find the ratio of force and acceleration 2/4 = 1/2. The ratio of force to acceleration should always equal half in all scenarios, this way we can see how equality is maintained.
2x2 = 1 x (4x2)
4 = 1 x 8, and the ratio of force to acceleration is 4/8 = 1/2.
When a solid becomes a liquid, the particles
slip and slide past each other
are vibrating
are in a lattice structure
bounce off each other
solid particles vibrate and slip past each other when they become liquid.
a bowling ball of mass 4.5 kg moves in a straight line at 3.98 m/s. how fast must a ping-pong ball of mass 1.322 g move in a straight line so that the two balls have the same momentum? answer in units of m/s.
It should travel at a speed of [tex]13.55[/tex] × [tex]10^{-3}[/tex] [tex]\frac{m}{s}[/tex] so that the two balls have the same momentum.
M = mass of the bowling ball = [tex]4.5 kg[/tex]
V = speed of bowling ball = [tex]3.98 \frac{m}{s}[/tex]
P = magnitude of momentum of bowling ball = ?
magnitude of momentum of bowling ball is given as
[tex]P = MV[/tex]
inserting the values
P = [tex]4.5 * 3.98[/tex]
P = [tex]17.91[/tex] [tex]\frac{kgm}{s}[/tex]
m = mass of ping-pong ball = [tex]1.322[/tex] [tex]g[/tex]= [tex]1.322[/tex] x [tex]10^{-3}[/tex] [tex]Kg[/tex]
v = speed of the ping-pong ball = ?
p = magnitude of momentum of ping-pong ball
Given that :
Magnitude of momentum of ping-pong ball = magnitude of momentum of bowling ball
[tex]p = P[/tex]
[tex]m v = 17.91[/tex]
([tex]1.322[/tex] x [tex]10^{-3}[/tex]) [tex]v[/tex] = [tex]17.91[/tex]
v = [tex]13.55[/tex] x [tex]10^{-3}[/tex] [tex]\frac{m}{s}[/tex]
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you see a manned aircraft in the distance while flying your drone at night. on the left, you're seeing a green light. on the right, you're seeing a red light. which direction is the aircraft headed?
The airplane is heading away from us when we see a manned aircraft in the distance while flying our drone at night.
Distance is the length between two points or items, and it is directionless. Since distance is a scalar attribute, it only takes into account the overall magnitude and ignores the start and end locations. Being a scalar attribute, distance may only be positive or zero; it cannot be the opposite.
Although kilometers (km) and centimeters (cm) or millimeters (mm) can also be used to express shorter distances, the meter (m) is the most used unit of measurement for distance (mm). When calculating distance, the letter D is usually used to denote the distance traveled.
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The xylem tube which transports sap to the top of a tree can be considered as uniform cylinders if the transport of sap is entirely due to capillarity determine the diameter of the tube which will move the sap up a tree which is 25m tall.take the surface tension of sap to be 5*10^-2 s.g is 1 g is 9.8 an
The wide wood pores that link to the tree's roots allow sap to be drawn up into the maple tree when it starts to freeze. The tree is really replenishing itself with fluids at this time from its roots.
As long as the temperature is below freezing and the sap is increasing, the process continues.
How does the xylem sap of tall trees go from the roots to the top?Water is drawn up from the roots to the top of the plant according to the cohesion-tension hypothesis of sap ascent. Water and minerals travel upward from the roots through the xylem due to a negative water potential gradient created by the evaporation of mesophyll cells in the leaves.
The water potential gets increasingly negative as you climb the tree, and these variations provide a pull or tension that causes the water to ascend the tree. The loss of water from the leaves through a process called transpiration is a crucial element in the draw of water up the tree.
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The parachutist’s mass is 70kg. The plane is 12km above the ground. How much GPE does the parachutist have?
Answer:
8.2x10^2 Joules
Explanation:
Assuming that GPE means potential energy of the parachutist, and he/she is doing this on Earth, we can find their potential energy, (PE) with the equation:
PE = mgh, where m is the mass of the parachutist in kilograms, g is the acceleration due to gravity [9.8 m/s2 for Earth (near surface)] and h is the height in meters.
m = 9.8 m/s^2
h = 12,000 meters (12 km)
m = 70 kg
PE = (70kg)(9.8 m/s^2)(12,000 m)
PE = 823,200 kg*m^2/s^2
PE = 8.2 x 10^2 kg*m^2/s^2
(1 kg*m^2/s^2) is the SI equivalent to a Joule.
The potential energy is 8.2x10^2 Joules
what is the maximum mass that can hang without sinking from a 50.0- cm -diameter styrofoam sphere in water? assume the volume of the mass is negligible compared to that of the sphere.
One form of StyrofoamTM product, commonly used in craft projects, is Styrofoam balls. The spherical polystyrene foam objects known as Styrofoam balls range in diameter from one inch (2.54 cm) to eight inches (20.3 cm). The uses for Styrofoam balls in crafts are incredibly diverse.
Calculating the ball's volume using
V = 4/3 * pi * r3
r = 10 cm = 0.10 m.
V = 0.00418 m^3
The mass of the water with a volume of 0.0446 m3 is equal to m =??
V = 0.00418 m3,
and d = 1000 kg/m3.
m=V*dm=0.00418*1000=4.18 kg
then determining the styrofoam ball's mass.
V = 0.00418 m3
d = 32 kg per m3, which equals m = 0.00418 * 32 m = 0.1337 kg.
Finding the necessary mass to place on the ball's surface.
The distinction is what you'll need to put on the ball.
4.18 - 0.1337 = 4.046 kg ans.
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a car weighing 13,000 n starts from rest and accelerates to 84.0 km/h in 5.00 s. the friction force is 1,500 n. find the applied force (in n) produced by the engine.
The applied force is 7.68 × 10³N.
What does applied force mean?A force that is applied is one that one object applies to one or more other objects. Applied forces have the power to alter an object's shape, size, state of motion, direction of motion, and other properties.
W = 1.3 × 10⁴
v₁ = 0
v (friction) = 84km/h = 23.3 m/s
t = 5s
f = 1500N
Mass of body = W / g
Mass of body = 1.3 × 10⁴ / 9.8
Mass of body = 1327 kg
v(friction) = v + at
23.3 = 5a
a = 4.66 m/s
Force Net = F₁ + F₂ + F₃ = ma
F (engine) = ma + F
F = 1327 (4.66) + 1500
F = 768.382
F = 7.68 × 10³N.
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you are designing a symmetric double convex lens that is made of glass with index of refraction equal to 1.33 and has a focal length of 0.165 m. what curvature radius of the lens surface should you use (in m; answer a positive number)?
The curvature radius of the lens surface is 0.1089 meters.
The convex lens is a lens that converges rays of light that convey parallel to its fundamental axis (i.e. converges the incident rays toward the main axis) which is highly thick throughout the middle and skinny at the decrease and higher edges. the edges are curved outward in preference to inward.
Calculation:-
Since the double convex is symmetric in nature,
R₁ = R
R₂ = - R
Given, Refractive index (n) = 1.33
The focal length of the double convex lens (l) = 0.156
Now,
1/f = (n-1) (1/R₁ - 1/R₂)
1/f = (n-1) (1/R + 1/R)
1/f = (n-1) × (2/R)
R = 2(n-1)f
= 2 × (1.33 - 1) × 0.165 meter
= 0.1089 meter
Hence, the radius of curvature of the lens surface is = 0.1089 meter
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If you drive at 120km/hr for 5 hours, how far will you go?
Distance:
Speed:
Time:
The distance of the travel covered within 5 hours with a speed of 120km/hr is the product of time and this speed and it is 600 km.
What is velocity?Velocity of a substance is the measure of distance travelled per unit time. Thus it is the ratio of distance to time.In physics, velocity is the rate of speed.
Velocity = distance/time.
Hence, as the time taken for the travel increases velocity will decreases. The time given here is 5 hours and the speed of the vehicle is 120 km/hr. Hence, the distance can be calculated as follows:
Distance = time × speed
= 5 hr × 120 km/hr
= 600 km.
Hence, if you drive at a speed of 120 km/hr for 5 hours you will cover a distance of 600 km.
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a rotating wheel requires s to rotate revolutions. its angular velocity at the end of the -s interval is rad/s. what is the constant angular acceleration (in ) of the wheel?
The angular acceleration of the wheel is -20.25 rad/sec^2
Angular acceleration is defined as the rate of change of angular velocity over time.
It is usually expressed in radians per second.It is also known as rotational acceleration.Mathematically, θ = ωo t + 1/2*α*t^2so, α = 2*(θ - ωo t ) / t^2
angular velocity of the wheel = ωo = 96.0 rad/sec
time taken by the wheel to rotate = t = 7 sec
angular distance travelled by the wheel = θ 28 rev
As we know that,
In one revolution the wheel completes 360 degrees which is equals to 6.28319 rad
therefore angular distance traveled = 28 rev * 6.28319 rad
So, the angular acceleration = 2*(28*6.28 - 96*7) / 7^2 = -20.25 rad/sec^2
The question is incomplete, the complete question is 'A rotating wheel requires 7.00 s to rotate 28.0 revolutions. its angular velocity at the end of the 7.00-s interval is 96.0 rad/s. what is the constant angular acceleration (in rad/s) of the wheel?'
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the sum of all the underlying causes can push a slope to the brink of failure, and then an immediate cause may trigger the movement. triggers for mass movements include:
For mass movements, gravity is the primary driving force. A trigger is frequently present in mass-wasting occurrences.
It could be caused by human operations like grading a new road, quake shaking, super volcano, storm waves, or storm-related waves. Mass-wasting is most frequently caused by an increase in water content in the slope. Rapidly dissolving snow or ice, as well as a heavy downpour, can cause the water content to rise. The force of gravity pulls everything towards to the Earth’s centre from every point on its surface. Gravity pulls downward on a level surface that is also parallel to the surface of the Earth. The stability of the consolidated and poorly consolidated earth materials can be compromised by gravity, increasing moisture content, and seismic events. The earth material slides down slope due to the compromised stability, a process known as mass wasting.
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a concave mirror of focal length 10 cm forms an upright and diminished image of a real object placed at a distance of 5 cm from the mirror. question 17 options: true false
Answer:The correct statement regarding single convicts made A is false if we don't choose the correct statement. Okay, which is not true. The image is always a virtual coma, erect and small in size, for the single mirror. Real objects regardless of traditions are small. Is it okay? The enemy's position needs to be smaller than the object position if the image is virtual erect. The third option will become the false statement that it will be the answer and the fourth option will give us a virtual object that will give us a real image. We can use a virtual object to give us a real image. It is a real image. The answer to the problem is the option three. Thank you for taking the time to thank me.
Explanation:
if you run the wire through a strong horseshoe magnet, subjecting 5.00 cm of it to a perpendicular 1.75 t field, what force is exerted on the segment of wire in n?
According to the given statement 17.15 N force is exerted on the segment of wire in n.
How would you define magnitude?Magnitude is essentially "distance or quantity" in the context of physics. In terms of motion, it shows the absolute and relative size, direction, or movement of an object. It is used to describe there is something volume or scope. Quantity in physics typically refers to a size or quantity.
Briefing:The magnitude of the magnetic force on a conducting wire of length I carrying current II, and making an angle θ with a magnetic field of strength B is given by:
[tex]$|\vec{F}|$[/tex] = I l B sin 0
Rearranging to get the current:
I = [tex]$|\vec{F}|$[/tex]/ lB sin0
= 7 * 10⁻³ / 0.75 * (5.5 * 10⁻⁵)sin60
= 195.95 A
[tex]$|\vec{F}|$[/tex] = I l Bsin0
= (195.95)(0.05)(1.75)sin90
=17.15 N
I = 195.95 I
[tex]$|\vec{F}|$[/tex] = 17.15 N
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Element E is in group 1A and element D is in group 6A they form an ionic compound. What is the formula for this compound
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catia when looking at an image of an object, what enables you to notice the surfaces and edges more clearly?
Orthographic projection enables you to notice the surfaces and edges more clearly.
What helps you to notice the surfaces and edges more clearly?Means of representing three-dimensional objects in two dimensions is called Orthographic projection.
Orthographic views helps us to represent a 3D object in 2D on a drawing. It can show an object viewed from each direction.
An orthographic projection has three views: front view, top view and side view. The right side is used for the side view but if the left side is used then it will be clearly labeled in the drawing. The final drawing is known as a 3 view drawing.
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consider the boyle's law apparatus. suppose that the volume of the gas is 25 cc and the pressure is 30.0 lbs/in2. show answer no attempt if the plunger is depressed so that the volume is decreased to 10.0 cc, what will the pressure be in lbs/in2?
75 lbs/in^2 is the value of pressure. The force delivered perpendicularly to an object's surface per unit area across which that force is dispersed is known as pressure.
What is pressure?In the physical sciences, pressure is defined as the stress at a point within a confined fluid or the perpendicular force per unit area.
The force delivered perpendicularly to an object's surface per unit area across which that force is dispersed is known as pressure. In comparison to the surrounding pressure, gauge pressure is the pressure. Pressure is expressed using a variety of units.
P1V1=P2V2
The amount of force applied to a certain region is referred to as pressure. Absolute pressure, gauge pressure, and differential pressure are the three categories into which pressure is divided.
The distance between that point and the surface, the liquid's density. Gravitational acceleration are the factors of pressure.
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Rank the following configurations according to the magnitude of the force felt at point P
— strongest force = top
— weakest force = bottom
**20 points!!**
Spam/unrelated content= reporting
Answer:
3, 4, 1, 2
Explanation:
A science class is observing how heat flows from one
object to another by melting ice and boiling water.
Which statements correctly describe how heat flows?
Choose the two statements that apply.
The coolness of the ice is flowing into the warm
water and decreasing its temperature.
The coolness of the water is flowing to the burner
and cooling it.
The warmth from the water is flowing to the ice
and melting it.
The warmth from the burner is flowing to the cold
water and increasing its temperature.
The warmth from the water is flowing to the ice and melting it and The warmth from the burner is flowing to the cold water and increasing its temperature.
What is the flow of heat called?Convection, which is essentially the mass transfer of heat, is the process by which heat is moved from one place to another by the movement of fluids. The transport of heat into the atmosphere involves one of three processes: radiation, conduction, or convection.
What happens during heat flow?Heat flow occurs when a hot object transmits its heat through a conductors to a cooler, similar to how high-energy objects impart their power to low-energy objects. How well a conductor transfers heat will impact how quickly and how much heat is transported.
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a block of mass m starts from rest and slides down a frictionless semi-circular track from a height h as shown below. when it reaches the lowest point of the track, it inelastically collides with a stationary piece of putty also having mass 2m . the block and the putty stick together and continue to slide. what is the maximum height that the block-putty system could reach?
The maximum height of that block-putty system is h/4.
Whtat is inelastic collision?
A collision in which a portion of the kinetic energy of the colliding particles is converted into another type of energy.
What is velocity?
The primary determinant of an object's position and rate of motion is its velocity. It can be explained as the distance an object travels in one unit of time. The object's displacement in a given amount of time is called velocity.
The velocity of block just before hitting the putty (by energy conservation)
K.Ei+P.Ei=K.Ef+P.Ef
⇒0+mgh=21mv2
⇒v=[tex]\sqrt{2}[/tex]gh
Let the common velocity of both block and putty be v'
At collision momentum balance:
mv=mv′+mv′
⇒[tex]\sqrt{2}[/tex]gh=2v′
⇒v′=[tex]\sqrt{g/h}[/tex]
Again applying energy conservation (both block and putty at max height)
K.Ei+P.Ei=K.Ef+P.Ef
⇒1/2 2mv²=2mgh′
⇒1/2 gh/2=gh′
⇒h′=h/4
Therefore, the maximum height is h/4.
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a hybrid electric vehicle is submerged under water. a rescue squad member consults automotive technicians for information regarding safety precautions. technician a says that there is no danger of electrical shock from touching the body of the vehicle or the frame in or out of the water. technician b says that the vehicle will detect a ground fault and open the hv relays. which technician is correct?
All lines carrying current to and from a motor are passed through the window of a specialized current transformer known as a ground fault sensor in order to detect ground fault current.
Explain about the ground fault detected?Ground fault relays (or sensors) are used to detect ground faults with low magnitude. The control system instructs the circuit disconnect to open when the G.F. relay pick up setting is reached by the ground fault current magnitude and time.
An overvoltage relay can therefore be fitted to either directly monitor the voltage at the wye point or to detect the secondary voltage of a transformer that has been installed between the wye point and ground in order to identify the fault
No appreciable current will be created in the sensor secondary if all of the current to the motor returns through the lines in the sensor window.
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the maximum gauge pressure in a hydraulic lift is 17.0 atm. what is the largest-size vehicle (kg) it can lift if the diameter of the output line is 25.5 cm?
Largest-size vehicle (kg) it can lift if the diameter of the output and maximum gauge pressure is given is 0.455 * 10³ kg.
What is gauge pressure?Pressure that is measured relative to ambient atmospheric pressure is called gauge pressure. Gauge pressure can be measured using a diaphragm sensor in which one side of the diaphragm is exposed to the pressure media that is to be measured and the other side gets exposed to ambient atmospheric pressure.
Given the diameter of the piston = 25.5 cm,
radius = 12.75 cm= 0.1275 m
Area of the piston is;
A= πr²
= 3.14 * (0.1275)²
=0.051 m²
Given maximum pressure of the lift= 17 atm
p =1.72 * 10⁶ Pa
Maximum force that piston can lift:
F= p * A
= 1.72 * 10⁶ *( 0.051 )²
= 4.47 * 10³ N
Size of the vehicle :
m = F/g
= 4.47* 10³/ 9.81
mass = 0.455 * 10³ kg
Largest-size vehicle that it can lift is 0.455 * 10³ kg.
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