The temperature rises of in the block if the current flows for 10 minutes is, 34.78K.
To find the answer, we need to know about the power of the electric heater.
How to find the temperature rise of in the block if the current flows for 10 minutes?We have given with the variables,[tex]P=40 W\\m=1.5kg\\S=460\\t=10minutes=10*60s=600s[/tex]
We have an expression the heat given to the system as,[tex]P*t= mS[/tex]ΔT
We have to find the temperature rise ΔT,ΔT [tex]=\frac{P*t}{mS} =\frac{40*600}{1.5*460} =34.78K[/tex]
Thus, we can conclude that, the temperature rises in the block if the current flows for 10 minute is 34.78K.
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If the current flows for 10 minutes, the temperature in the block rises by 34.78 K.
We must understand the electric heater's power in order to determine the solution.
How can you determine the block's temperature increase if the current flows for ten minutes?With the variables that we have provided,[tex]P=40Watts\\m=1.5kg\\s=460\\t=10 min=600s[/tex]
The heat supplied to the system is referred to as,[tex]Pt=ms[/tex]ΔT
We must determine the increase in temperature, T.
ΔT[tex]=\frac{Pt}{ms} =34.78 K[/tex]
Thus, we can infer that if the current flows for 10 minutes at 34.78K, the temperature in the block will increase.
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Dalton's law of partial pressures states that for a mixture of gases, the pressure is the of the partial pressures of the individual gases. (assume that the gases do not react with each other.)
True. The partial pressure of gas that is made up of a mixture of gases is the sum of the individual pressure of the gases.
What is Dalton's law of partial pressure?Dalton's law of partial pressure of gases is one of the gas laws that take into consideration the fact that a gas can be made from a mixture of non-reacting gases.
According to him, if a gas is made as such, the pressure of the gas would be the sum of the individual pressure of the component gases. This means that each gas contributes partially to the overall pressure of the gas mixture.
Thus, if gas A is a mixture of gas B and gas C. The pressure, P, of gas A is given as:
P = Pb + Pc where Pb and Pc are the partial pressure of gases B and C respectively.
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Which element of a valid contract is established by getting the signatures of all parties?
The element of a valid contract which is established by getting the signatures of all parties is mutual agreement
What is an element of a valid contract?An element of a valid contract simply refers to that promise made between two or more parties that which allow the courts to make judgement.
Some elements of valid contract are:
OfferAcceptanceConsiderationIntention to create legal relationCertainty and capacity.So therefore, the element of a valid contract which is established by getting the signatures of all parties is mutual agreement
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A car goes around a curve at a constant speed. what is the direction of the net force on the car?
Answer:
The direction of the net force is at a tangent to the circle.
Your older brother approaches a stop sign at a velocity of 14 m/s [E] as the light turns amber, He applies the brakes to get the maximum stopping force while avoiding skidding. The car has a mass of 1500 kg, and the coefficient of friction between the tires and the road is 1.07. Ignoring your brother's reaction time, calculate:
a) The maximum deceleration of the car
b) The stopping distance
The maximum deceleration of the car is 10.5 m/[tex]s^{2}[/tex] approximately. While the stopping distance is 9.3 m
What is Stopping Force ?
Stopping force is the force required to stop the object in motion. Stopping force is tantamount to frictional force.
Given that a brother approaches a stop sign at a velocity of 14 m/s [E] as the light turns amber, He applies the brakes to get the maximum stopping force while avoiding skidding. The car has a mass of 1500 kg, and the coefficient of friction between the tires and the road is 1.07. Ignoring your brother's reaction time.
The given parameters are;
Velocity V = 14 m/sMass m = 1500 kgCoefficient of friction μ = 1.07Deceleration a = ?Stopping distance S = ?The normal reaction N = mg
N = 1500 x 9.8
N = 14700 N
The stopping force = μN = ma
1.07 x 14700 = 1500a
15729 = 1500a
a = 15729/1500
a = 10.486 m/[tex]s^{2}[/tex]
From 3rd equation of motion
[tex]V^{2}[/tex] = [tex]U^{2}[/tex] + 2aS
where U = 0
[tex]14^{2}[/tex] = 2 x 10.486 x S
196 = 20.972S
S = 196/20.972
S = 9.3 m
Therefore, the maximum deceleration of the car is 10.5 m/[tex]s^{2}[/tex] approximately. While the stopping distance is 9.3 m
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A proton exits the cyclotron 1. 0 ms after starting its spiral trajectory in the center of the cyclotron. How many orbits does the proton complete during this 1. 0 ms ?.
(a) The diameter of the largest orbit just before the protons exit the cyclotron is 39 cm.
(b) The number of orbits completed by the proton during this 1.0 ms is 14000 revolutions.
What is kinetic energy?
The kinetic energy of an object is the energy that it possesses due to its motion.
It is defined as the work needed to accelerate a body of a given mass from rest to its stated velocity.
Formula of KE:
K.E = 1/2mv²
mv² = 2 K.E
v = sqrt( 2*KE / M)
Here,
(a)
The KE of the medical isotopes = 6.5 MeV
substituting the values,
v = sqrt( 2* 6.5* 1.6* 10^-13 / 1.67* 10^-27 )
v = 3.53 × 10⁷ m/s
Now the centripetal force:
mv² / R = qvB
r = q*v / mv²
r = ( 1.67* 10^-27 * 3.53 × 10⁷ ) / ( 1.9* 1.6* 10^-19 )
r = 0.19415 m
diameter d = 2r,
d= 2(0.19415 m)
d= 0.39 m ≅ 39 cm
(b)
The time period to complete a revolution around the spiral trajectory is:
T = 2πr / v
T = 2*3.14* 0.1941 / 3.53*10^7
T = 0.7 × 10⁻⁷ s
Thus, the number of orbits that the proton does to complete the revolution in 1 ms is:
n = t / T
n = 10^-3 / (0.7*10^-7)
n = 14285.71 ≅ 14000 revolutions
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Your question is incomplete, but most probably full question was:
A medical cyclotron used in the production of medical isotopes accelerates protons to 6.5 MeV. The magnetic field in the cyclotron is 1.9 T.
(a) What is the diameter of the largest orbit, just before the protons exit the cyclotron? Express your answer with the appropriate units. d = 57 cm Previous
(b) A proton exits the cyclotron 1.0 ms after starting its spiral trajectory in the center of the cyclotron. How many orbits does the proton complete during this 1.0 ms?
The Effect of the Light Intensity and Light Distances of LED and QTH Curing Devices on the Hardness of Two Light-Cured Nano-Resin Composites
Effective polymerization of the composite resin is essential to obtain long term clinical success and has a great importance obtaining improved mechanical properties.
What is the purpose of Effective polymerization of the composite resin ?The purpose of this study was to measure the effect of the light intensity of LED and QTH curing devices in relation to the light distances, on the hardness (KHN) of two light cure nano-resin composite.
Material and Methods: The top and bottom surfaces of the two nanofill composite specimens were evaluated. Two LED and two QTH light curing devices were used at nine different distances. Light intensity was measured with two radiometers placed at these same distances from the curing tip.Learn more about Light intensity here:
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A block with a mass of 2kg is pushed 20cm and a constant speed up an incline that makes a 40 degree angle with the floor. how much work is done by gravity on the block ? let d be the displacement of the block.
work done will be 2.5872 J
Given :
mass of block = 2kg
distance travelled by block = 20cm
angle of inclination = 40°
To Find :
Work done by gravity
Solution :
Gravity is defined as the force that attracts a body towards the earth or towards any other physical body having mass.
work done by gravity is mgh
If θ is the angle made when the body falls, the work done by gravity is given by,
W = m g h cosθ
W = 2 x 9.8 x 0.2 x cos40°
= 2.5872 J
So work done will be 2.5872 J
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A uniform ladder 5.0 m long rests against a frictionless, vertical wall with its lower end 3.0 m from the wall. The ladder weighs 160 N. The coefficient of static friction between the foot of the ladder and the ground is 0.40. A man weighing 740 N climbs slowly up the ladder.
The only vertical forces acting on the wall are the weights of the man and the ladder as well as the normal force because the wall has no friction.
The maximal frictional forces are μsN2=(0.40)(900N)=360N, and N1=w1+wm=160N+740N=900N for the vertical forces to balance. At a height of 4.0 meters above the ground, the ladder makes contact with the wall. about the point of contact with the ground, balancing torques.
N2 = 174.0N because (4.0m)2 = (1.5m)(160N) + (1.0m)(35)(740N) =684N.m. It is necessary for the frictional force to counteract this horizontal force. Setting the frictional fore and n1 to a maximum of 360N and solving for the distance x along the ladder (0.4m)(360N)=(1.50m)(160N)+x(35)(740N) yields x=2.70m
Friction
When two sliding solid surfaces, fluid layers, or material components come into contact with one another, friction acts as a force to stop them from moving in the same direction. Friction comes in several forms:
The relative lateral motion of two solid surfaces in contact is opposed by dry friction. Between moving surfaces, there is kinetic friction, which is different from static friction. With the exception of atomic or molecule friction, asperities on the surface interact to produce dry friction.
When layers of a viscous fluid move in relation to one another, there is friction between them. This is known as fluid friction.
When a lubricant fluid separates two solid surfaces, it is called lubricated friction.
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A sound wave traveling through dry air has a frequency of 16 hz, a
wavelength of 22 m, and a speed of 350 m/s. when the sound wave passes
through a cloud of methane, its wavelength changes to 28 m, while its
frequency remains the same. what is its new speed? (the equation for the
speed of a wave is v= f * 1.)
Answer:
[tex]\huge\boxed{\sf v = 448\ m/s}[/tex]
Explanation:
Given data:Frequency = f = 16 Hz
Wavelength = λ = 28 m
Required:Speed = v = ?
Formula:v = fλ
Solution:Put the givens.
v = (16)(28)
v = 448 m/s
[tex]\rule[225]{225}{2}[/tex]
The position of a car at time t is given by the function p(t)=t2 2t−4. What is the velocity when p(t)=11? assume t≥0
The velocity when function p(t)=11 is 8 .
According to the question
The position of a car at time t represented by function :
[tex]p(t)=t^{2} +2t-4[/tex]
Now,
When function p(t) = 11 , t will be
[tex]p(t)=t^{2} +2t-4[/tex]
11 = t²+2t-4
0 = t² + 2t - 15
or
t² +2t-15 = 0
t² +(5-3)t-15 = 0
t² +5t-3t-15 = 0
t(t+5)-3(t+5) = 0
(t-3)(t+5) = 0
t = 3 , -5
as t cannot be -ve as given ( t≥0)
so,
t = 3
Now,
the velocity when p(t)=11
As we know velocity = [tex]\frac{position}{time}[/tex]
therefore to get the value of velocity from function p(t)
we have to differentiate the function with respect to time
[tex]\frac{d(p(t))}{dt} =\frac{d}{dt} (t^{2} +2t-4)[/tex]
v(t) = 2t + 2
where v(t) = velocity at that time
as t = 3 for p(t)=11
so ,
v(t) = 2t + 2
v(t) = 2*3 + 2
v(t) = 8
Hence, the velocity when function p(t)=11 is 8 .
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Which type of fire suppression system is designed to work in areas where electrical equipment is used and contains pressurized air?
In a dry pipe sprinkler system, pressurized air or nitrogen, rather than water, is used to fill the pipes. This air maintains the closed position of a remote valve, also referred to as a dry pipe valve.
The dry-pipe valve, which is situated in a hot area, keeps water from flowing into the pipe until a fire triggers the operation of one or more sprayer. When this occurs, the dry pipe valve releases and the air leaves. After that, water enters the pipe and pours onto the flames through open sprinklers.
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A CD has diameter of 110110 millimeters. When playing audio, the angular speed varies to keep the linear speed constant where the disc is being read. When reading along the outer edge of the disc, the angular speed is about 220220 RPM (revolutions per minute). Find the linear speed.
Answer: A CD has diameter of 110 millimeters. When playing audio, the angular speed varies to keep the linear speed constant where the disc is being read. When reading along the outer edge of the disc, the angular speed is about 220 RPM (revolutions per minute). Then, the linear speed of the disc will be 1.26 m/s.
Explanation: To find the answer we need to know about the uniform circular motion.
What is uniform circular motion?When a body moves in a circular path with a constant speed, it is said to be in uniform circular motion.The rate of change of angular displacement is called the angular velocity.Relation between angular velocity, linear velocity and the radius of revolution is given as,[tex]v=rw[/tex]
The relation between angular velocity and the frequency of revolution can be written as,[tex]w=2\pi f[/tex]
How to solve the problem?Given that the diameter of the disc as 110mm.Thus, the radius of the disc will be 55 mmThere are 220 revolutions per minute, thus the angular velocity w will be,[tex]w=2\pi f=2\pi *220 min^{-1}=1381.6 min^{-1}[/tex]
As we know that,[tex]1mm=10^{-3}m\\1min=60s\\thus,\\w=\frac{1381.6}{60} =23.02 s^{-1}.[/tex]
Thus, the linear speed will be,[tex]v=wr=23.02*55*10^{-3}=1.26 m/s[/tex]
Thus, we can conclude that the linear speed of the disc will be 1.26 m/s.
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Disclaimer: The question was given wrong in the given portal. Here is the correct question.
Question: A CD has diameter of 110 millimeters. When playing audio, the angular speed varies to keep the linear speed constant where the disc is being read. When reading along the outer edge of the disc, the angular speed is about 220 RPM (revolutions per minute). Find the linear speed.
an object has a mass of 50kg, a final height of 20m and an initial height of 8m. what is the amount of work done
amount of work done is 5880 J
Given:
mass of object = 50kg
Final height = 20m
initial height = 8m
To Find:
amount of work done
Solution:
work is done when a force acts upon an object to cause a displacement. You can calculate the energy transferred, or work done, by multiplying the force by the distance moved in the direction of the force.
The work done by gravity is given by the formula,
W = mgh
W = 50 x 9.8 x ( 20-8)
= 5880 J
So the work done is 5880 J
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17% Part (a) Calculate the x-component of the electric field at point P due to charge Q1. Write your answer in units of N/C.
The x component would be Ex = 412 x cos 49° = 270 N/C
Assume there is a small positive charge located at point P. By definition the magnitude of the electric field at point P due to charge Q1 is
E = kQ1/d2
where k is the coulomb constant and d is the straight line distance from Q1 to P.
The distance is the hypotenuse of the triangle formed by Q1, Q2, and P.
d = √0.065^2 + 0.075^2 = 0.099 m at an angle of θ = arctan 7.5/6.5 = 49°.
|E| = 8.99 x 10^9 Nm^2 C^-2 x 0.45 x 10^-9 C/ 0.099^2 m^2 = 412 n/C
The x component would be Ex = 412 x cos 49° = 270 N/C
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Which of the following objects is composed mostly of wood?
A. Sweater
B. Tile
C. Pencil
D. Brick
❄ Hi there.
a pencil is composed mostly of wood.
Let's check if the other choices are right.
A. Sweaters are not made of wood
B. Tiles are not made of wood
C. Pencils are made of wood
D. Bricks are not made of wood
∴ the right choice is C.
❄
A bodybuilder deadlifts a 215 kg weight to a height of 0.90 m above the ground. If he deadlifts this weight 10 times in a span of 45 seconds, how much power has he exerted?
Group of answer choices
a. 8,530 W
b. 421 W
c. 853 W
d. 4,210 W
A bodybuilder deadlifts 215 kg to a height of 0.90 m. If he deadlifts this weight 10 times in 45 s, the power exerted is 421 W (b.)
What is power?In physics, power (P) is the work (W) done over a period of time.
Step 1. Calculate the work done by the bodybuilder each time.The bodybuilder lifts a 215 kg (m) weight to a height of 0.90 m (h). Being the gravity (g) of 9.81 m/s², we can calculate the work done in each lift using the following expression.
W = m × g × h = 215 kg × 9.81 m/s² × 0.90 m = 1.9 × 10³ N
Step 2. Calculate the work done by the bodybuilder over 10 times.W = 10 × 1.9 × 10³ N = 1.9 × 10⁴ N
Step 3. Calculate the power exerted by the bodybuilder.The bodybuilder does a work of 1.9 × 10⁴ N in a 45-s span.
P = 1.9 × 10⁴ N/45 s = 421 W
A bodybuilder deadlifts 215 kg to a height of 0.90 m. If he deadlifts this weight 10 times in 45 s, the power exerted is 421 W (b.)
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Read the following questions and answer them using complete sentences. Be sure to fully explain your answers.
What can be the challenges of wave power? Is it a reliable source of energy?
Wave power can be regarded as a reliable source of energy because the ocean currents are always moving.
What can be the challenges of wave power?Wave power is a device that can be used to convert the mechanical energy of the ocean waves into electrical energy based on the principle of conservation of energy.
The major challenges that face the use of wave power in electricity generation is the unreliability of the waves which leads to uncertainty in the quantity of power generated Also, the wave direction and direction of ocean currents all limit the amount of power generated by this method. However, in spite of challenges, it can be regarded as a reliable source of energy because the ocean currents are always moving.
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Provided following are four different ranges of stellar masses. Rank the stellar mass ranges based on how many stars in each range you would expect to be born in a star cluster, from highest number to lowest number.
Highest to lowest number:
-less than 1 solar mass
-between 1 and 10 solar masses
-between 10 and 30 solar masses
-between 30 and 60 solar masses
What is Stellar masses ?Stellar mass is a phrase that is used by astronomers to describe the mass of a star.
It is usually enumerated in terms of the Sun's mass as a proportion of a solar mass ( M ☉). Hence, the bright star Sirius has around 2.02 M ☉.Stellar masses are not fixed, although they change for single stars only on long periods.Learn more about Stellar masses here:
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State Newton's second law of motion and establish the relation F = m x a
F = ma is the formula of Newton's Second Law of Motion. Newton's Second Law of Motion is described as Force is equal to the rate of change of momentum. For a constant mass, force equals mass duration acceleration.
What is the significance of Newton's second law of motion explain?
Newton's Second Law of Motion F=ma is very significant because it indicates the relationship between forces and motion. It permits you to calculate the acceleration (and therefore velocity and position) of an object with known forces. This is extremely helpful for scientists, engineers, inventors, etc.
Force is directly proportional to Shift in momentum ÷ Time taken.Therefore : F is directly proportional to m×a. This relation F is directly proportional to m×a can be turned into an equation by placing in a constant k.
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A 1436. 32' line has an azimuth of 178 52 13. What is the latitiude and departure of the line?
Latitude of the line will be = 1436.033
Departure of the line will be = 28.152
Given
let line be = a = 1436. 32
azimuthal be = x = 178° 52' 13''
This line must have two components , one is horizontal component which is its latitude and other will be vertical component which is departure . Resolving both the components we get,
latitude = a*cos(178° 52' 13'')
= 1436. 32 * cos(178° 52' 13'')
= 1436. 32 * (- 0.9998)
latitude = 1436.033
departure = a * sin (178° 52' 13'')
= 1436. 32 * 0.0197
departure = 28.152
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If the platinum-based engine is run continuously at 300 k for 1 hour with 0.50 atm of h2 and 0.50 atm of o2 injected for each reaction, approximately what mass of water will be produced?
About 4.5 mol of water will be created when the platinum-based engine is run continuously at 300 K for an hour with 0.5 atm of H2 and 0.5 atm of O2 injected for each reaction.
For fuel cell engines' electrodes, platinum is a requirement. It acts as an electrocatalyst to speed up the electrochemical reactions needed to induce H2 to release electrons and form H2 ions when it is placed on porous electrodes.
Platinum is particularly well suited as a fuel cell catalyst because it makes it possible for the hydrogen and oxygen reactions to occur at an ideal rate and because it is stable enough to withstand both the intense electrical current density and the complex chemical environment found inside a fuel cell. This allows platinum to function effectively over an extended period of time.
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White lights can sometimes be found on what kind of buoys?
a. daytime buoys
b. green buoys
c. red buoys
White lights can sometimes be found on red buoys.
Hence, Option C is correct answer.
How can we understand that White lights can sometimes be found on red buoys?Buoys consist of a float, mooring chain and anchor. They may be equipped with lights and/or sound signals such as bells, gongs, or whistles.We know that, Red buoys are found on the starboard side of a channel when entering from seaward and can be lighted buoys, nuns, or triangular daymarks. Red buoys, if lit, have red or white lights, and the light pattern can be fixed, flashing, occulting, quick–flashing, or of equal intervals.Thus from the above conclusion we can say that White lights can sometimes be found on red buoys.
Hence, Option C is correct answer.
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Why do we tallk about radio waves as a group and not the frequeny of radio waves
How does enormous energy get released from the sun?
Enormous energy get released from the sun due to fusion reaction.
How does enormous energy get released from the sun?
Sun can generate enormous energy due to nuclear fusion. In this process, high temperature and pressure in the core of the sun force the nuclei to separate from their electrons which results in the formation of one Helium atom releasing a large amount of energy.
So we can conclude that enormous energy get released from the sun due to fusion reaction.
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A standard rum and cola will be absorbed faster than a 5-ounce glass of wine because.
Absorption of Rum and cola:
A standard rum and cola absorb faster than a 5-ounce glass of wine because carbonation causes the pyloric valve to relax.
What are Rum and Cola:
The second-most common alcoholic beverage in the world is rum and coke, which is very well-liked. Its widespread availability, low cost, and ease of preparation are what contribute to its appeal. It is easy to prepare and challenging to destroy because it can be produced with any quantity or type of rum. Due to the pyloric valve's relaxation caused by carbonation, alcohol like rum and coke is often absorbed more quickly than 5 ounces of wine.Absorption is accelerated by carbonation. Alcohol will enter the bloodstream more quickly when combined with carbonated drinks like Coca-Cola or tonic water.Learn more about the alcoholic beverages here,
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The watermark can be of different types depending on the application. A watermark will resist manipulations of the media. However, a watermark will not resist tampering.
The first blank is robust watermark; a robust watermark will not resist tampering.
The second blank is fragile watermark; a fragile watermark will resist manipulations of the media.
What is a watermark?A watermark is a faint design made in paper during manufacture that is visible when held against the light and clearly identifies the maker.
The watermark can be of different types depending on the application and they include:
A robust watermark will not resist tampering.A fragile watermark will resist manipulations of the media.Thus, The first blank is robust watermark; a robust watermark will not resist tampering.
The second blank is fragile watermark; a fragile watermark will resist manipulations of the media.
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Chicago, il is currently in the e climate zone.
a) true
b) false
Answer:
false
Explanation:
There are many muscles in our body. our body uses muscles to move parts of our body. a part that needs to move a lot will have a higher number of muscles. which of the following parts is most likely to have the most muscles? a. ear lobe b. stomach c. teeth d. brain
Option b) Stomach is most likely to have the most muscles.
There are five main muscles in stomach pyramidalis, rectus abdominus, external obliques, internal obliques, and transversus abdominis.
Muscles circulate frame parts by contracting after which relaxing. muscular tissues can pull bones, however, they cannot push them to return to their unique role. so they paintings in pairs of flexors and extensors. The flexor contracts to bend a limb at a joint.
The muscle groups that circulate our frame elements are called skeletal muscles, and they're a form of striated muscle. We will actively manipulate those with our brains. another sort of striated muscle is those that maintain our hearts pumping, which we are not able to actively control.
Muscles pull at the joints, allowing us to move. a couple of muscular tissues are used for any sort of motion of a bone. Although we are sitting flawlessly nevertheless, muscle tissues at some point in the frame are constantly shifting.
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Tuning forks with a frequency of 500 to 1000 hz are most commonly used to measure:________
Tuning forks with a frequency of 500 to 1000 hz are most commonly used to measure: hearing loss
A person is said to have hearing loss if they are not able to hear as well as someone with normal hearing, meaning hearing thresholds of 20 dB or better in both ears. It can be mild, moderate, moderately severe, severe or profound, and can affect one or both ears.
High-pitched tuning fork with frequency of 500 to 1000 hertz (Hz) should be used to estimate hearing loss in range of normal speech (300 to 3000 Hz).
The 512-Hz Rinne tuning fork test could be very effective at detecting conductive hearing losses when performed by an experienced tester and when masking was used . Tuning forks are used to carry Rinne and Weber tests. These tests provide a quick easy method of determining whether a hearing loss is situated in the middle ear or inner ear
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A mass m is attached to an ideal massless spring. When this system is set in motion, it has a period t. What is the period if the mass is doubled to 2m?.
The period is √2 *T if the mass is doubled to 2m.
What is the time period?
The time period is the length of time during which an activity occurs or a condition remains.
The equation for the period T is given as:
[tex]T = 2\pi \sqrt{\frac{m}{k} }[/tex]
where k is the spring constant
mass of the system = m
Here,
If the mass id doubled to 2m for the system that is set in motion,
new mass is now 2m
So the equation for time period becomes,
[tex]T' = 2\pi \sqrt{\frac{2m}{k} }[/tex]
[tex]T' = \sqrt{2} * 2\pi \sqrt{\frac{m}{k} }[/tex]
[tex]T' = \sqrt{2}* T[/tex]
Hence,
The period is √2 *T if the mass is doubled to 2m.
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