An object that weighs exactly 1
pound is placed on a digital scale that measures weight in ounces.
If the scale is accurate and precise, what weight might be shown on the scale?

Answers

Answer 1
16 ounces= 1 pound.

Related Questions

<1 and <2 are vertical angles. If m<1 = (5x+12) and m<2 = (23x + 17) find m<2

Answers

Answer:

m∠2 = 10 11/18°

Step-by-step explanation:

Vertical angles are equal to one another.

[tex]5x+12=23x+17\\\\12=18x+17\\\\-5=18x\\\\-\frac{5}{18}=x[/tex]

Now substitute the value for the variable to find m∠2.

[tex]23(-\frac{5}{18})+17\\\\-\frac{115}{18}+17\\\\\frac{191}{18}=10\frac{11}{18}[/tex]

Find the values of θ in the range 0≤θ≤360° which satisfy: 2 sin^2 θ - sinθ -1= 0

Answers

Answer:

Step-by-step explanation:

Solving trig equations are just like solving "regular" equations. Let's get to it. First and foremost we are going to make a "u" substitution. You'll use that all the time in calculus, if you choose to go that route. Let

[tex]sin^2 \theta=u^2[/tex] and sinθ = u. Making the substitution, the equation becomes:

[tex]2u^2-u-1=0[/tex]

That looks like something that can be factored, right? If you throw it into the quadratic formula you get the factors:

(u - 1)(2u + 1) = 0

By the Zero Product Property, either u - 1 = 0 or 2u + 1 = 0, so we will solve those, but not until after we back-substitute!

Putting sinθ back in for u:

sinθ - 1 = 0 so

sinθ = 1 and in the other equation:

2sinθ + 1 = 0 so

2sinθ = -1 and

[tex]sin\theta=-\frac{1}{2}[/tex]

Get out the unit circle and look to where the sinθ has a value of 1. There's only one place in your interval, and it's at 90 degrees.

Now look to where the sinθ has a value of -1/2. There are 2 places within your interval, and those are at 210° and 330°. Now you're done!

The Cube root of 66 is between which two integers?

Answers

Answer:

4 and 5

Step-by-step explanation:

cube root of 66 is 4.041240021

Can someone please explain this to me? I don’t understand it at all.

Answers

Segment AB was added to segment BC to get segment AC

representing it as an equation,

AC = AB + BC.

Substitute the values in the equation which means you are going to find the value of x.

77 = x + 16 + 4x +11

77 = 5x + 27

(group like terms)

77 - 27 = 5x

50 = 5x

( divide both sides by 5 to make x stand alone)

50/5=5x/5

10 = x

therefore ,x = 10.

To prove that segment AB =26, place x in the statement

AB = x+16

AB=10+16

AB=26/

r/3 + 5 < 8

please help

Answers

Answer:

r<9

Step-by-step explanation:

r/3 + 5 < 8

Subtract 5 from each side

r/3 + 5-5 < 8-5

r/3 < 3

Multiply each side by 3

r/3 *3 <3*3

r<9

Find the value of x in this equation. 180-5x=140180−5x=140

Answers

Answer: 8

Step-by-step explanation:

Write the last 4 digits of a telephone number (each digit MUST be different--ex. 5237). List all the 4-digit numbers you can make using those 4 digits.

Answers

Answer:

5040

Step-by-step explanation:

All the possible Numbers that can be placed in the last for places =0,1,2,3,4,5,6,7,8,9

If all the digits  have be different , then

= 10 x 9 x 8 x 7

= 90 x 56

=  5040   are total no. of 4-digit numbers can be made using those 4 digits.

Choose all answers that apply
A -x + (-x) = 0
B x - (-x) = 0
C none of the above

Answers

Answer:

c

Step-by-step explanation:

none of the above

C none of the above

because x-(-x)=x+x=2xand

-x+(-x)= -x-x=-2x

so answer is 'C' none of the above

explanation please! thx!​

Answers

Answer:

63°

Step-by-step explanation:

complement means that the two angles add to 90°

90 - 27 = 63°

Answer:

Step-by-step explanation:

complement angles have sum of angles=90°

∠AOC=27

∠BOC=90-27=63°

hey i suck at math can someone help me with this question

Answers

we can subtract the trapezium (white part) formed after from the trapezium (including white and grey) to get area of striped part

area of trapezium is [tex]\frac H2(a+b)[/tex] where $a$ and $b$ are parallel sides.

for bigger trapezium, $h=4$ parallel sides are $5$ and $5$

hence area is $\frac{4(5+5)}{2}=20$

similarily area of white trapezium, $\frac{4(3+3)}{2}=12$

and area of striped part is $20-12=8$

A cylindrical tank whose diameter is 1.4 metres and height 80 cm is initially empty. Water whose volume is 492.8 litres is poured into the tank. Determine the fraction of the tank filled with water. (4 marks

Answers

Answer:

7/40 is the fraction filled with water

Step-by-step explanation:

Here we start by calculating the volume of the cylindrical tank.

Mathematically, that would be;

V = π * r^2 * h

From the question

r = 80 cm = 80/100 = 0.8 meters

h = 1.4 meters

π = 22/7

Plugging these values into the volume equation, we have;

V = 22/7 * 0.8 * 0.8 * 1.4 = 2.816 m^3

But mathematically;

1 m^3 = 1000 liters

So 2.816 m^3 = 2.816 * 1000 = 2816 liters

So the fraction filled with water will be;

492.8/2816 = 0.175 = 175/1000 = 7/40

subtract c from 7, then divide b by the result

Answers

Answer:

[tex]\frac{7-c}{b}[/tex]

Answer:

[tex]\frac{7 -c}{b}[/tex]

Step-by-step explanation:

Subtract c from 7 : 7 - c

Then the result is divide by b :  [tex]\frac{7 -c}{b}[/tex]

Which of the two functions below has the largest maximum y-value?
f(x) = -x4- 2
g(x) = -3x3 + 2

Answers

Answer:

g(x)=-3x^{3}+2

Step-by-step explanation:

g(x) has a range that of (-infinity, +infinity), whereas f(x) has a range of (-infinity, -2].

Answer:

Step-by-step explanation:

● f(x) = -x^4 -2

● g(x) = -3x^3 + 2

Derivate both functions:

● f'(x) = -4x^3

● g'(x) = -9x^2

Solve the equations f'(x) =0 and g'(x) =0

● f'(x) = 0

● -4x^3 = 0

● x^3 = 0

● x =0

● g'(x) = 0

● -9x^2 = 0

● x^2 =0

● x = 0

So both functions f and g reach their maximum at 0.

● f(0) = 0^4-2 = -2

● g(0) = -3×0^3 +2 = 2

So g(0)>f(0)

So g has the largest maximum value.

Ken has 86 feet of fencing , to make a vegetable garden . Which design below will give ken the largest garden ?

Answers

Answer:it’s the top right box

Step-by-step explanation: what I did was I added 24+24 and 19+19 which gives you 86ft

Answer:It is left side 21ft and top 22ft Step-by-step explanation:

1) UN MOVIL A SE MUEVE DESDE UN PUNTO CON VELOCIDAD CONSTANTE DE 20m/s EN EL MISMO INSTANTE A UNA DISTANCIA DE 1200m, OTRO MOVIL B SALE Y PERSIGUE AL MOVIL A CON VELOCIDAD CONSTANTE DE 40m/s.¿ EN QUE TIEMPO Y A QUE DISTANCIA B ALCANZA a

Answers

Answer:

El móvil B necesita 60 segundos para alcanzar al móvil A y le alcanza una distancia de 2400 metros con respecto al punto de referencia.

Step-by-step explanation:

Supóngase que cada movil viaja en el mismo plano y que el móvil B se localiza inicialmente en la posición [tex]x = 0\,m[/tex], mientras que el móvil A se encuentra en la posición [tex]x = 1200\,m[/tex]. Ambos móviles viajan a rapidez constante. Si el móvil B alcanza al móvil A después de cierto tiempo, el sistema de ecuaciones cinemáticas es el siguiente:

Móvil A

[tex]x_{A} = 1200\,m+\left(20\,\frac{m}{s} \right)\cdot t[/tex]

Móvil B

[tex]x_{B} = \left(40\,\frac{m}{s} \right)\cdot t[/tex]

Donde:

[tex]x_{A}[/tex], [tex]x_{B}[/tex] - Posiciones finales de cada móvil, medidas en metros.

[tex]t[/tex] - Tiempo, medido en segundos.

Si [tex]x_{A} = x_{B}[/tex], el tiempo requerido por el móvil B para alcanzar al móvil A es:

[tex]1200\,m+\left(20\,\frac{m}{s} \right)\cdot t = \left(40\,\frac{m}{s} \right)t[/tex]

[tex]1200\,m = \left(20\,\frac{m}{s} \right)\cdot t[/tex]

[tex]t = \frac{1200\,m}{20\,\frac{m}{s} }[/tex]

[tex]t = 60\,s[/tex]

El móvil B necesita 60 segundos para alcanzar al móvil A.

Ahora, la distancia se obtiene por sustitución directa en cualquiera de las ecuaciones cinemáticas:

[tex]x_{B} = \left(40\,\frac{m}{s} \right)\cdot (60\,s)[/tex]

[tex]x_{B} = 2400\,m[/tex]

El móvil B alcanza al móvil A a una distancia de 2400 metros con respecto al punto de referencia.

define space in detail.​

Answers

Answer:

space is the capacity that an object or shape weigh

Which number is equal to 10^-3?
-1,000
-30
0.001
0.003

Answers

Answer: Choice C) 0.001

Work Shown:

10^(-3) = 1/( 10^3 ) = 1/1000 = 0.001

The rule used here is x^(-k) = 1/( x^k )

Answer:

C. O.001

Step-by-step explanation:

10^-3 = (1)/(10^3)

move the negative exponent to the denominator

(1)/(1000)

simplify 10^3 in the denominator

(1)/(1000) = 0.001

Victor fue al mercado para comprar manzanas, naranjas y platanos; las naranjas costaron el doble de lo 1ue pago por las manzanas y los platanos costaron 8 pesos menos que pas manzanas, en total gasto 100 pesos. Determina el precio de las manzanas, naranjas y platanos

Answers

Answer:

El precio de las manzanas = 27 pesos

El precio de las naranjas = 54 pesos

El precio de las bananas = 19 pesos

Step-by-step explanation:

Los parámetros dados son;

El monto total gastado = 100 pesos

Sea el precio de las naranjas = x

Sea el precio de las manzanas = y

Sea el precio de los plátanos = z

La cantidad pagada por las naranjas = 2 · y = x

La cantidad pagada por los plátanos = y - 8 = z

Por lo tanto, tenemos;

La cantidad total gastada = La cantidad pagada por las naranjas + La cantidad pagada por las bananas + La cantidad pagada por las manzanas

∴ El monto total gastado = 100 pesos = 2 · y + y - 8 + y

100 = 4 · años - 8

4 · y = 100 + 8 = 108

y = 108/4 = 27

y = 27

De

z = y - 8 tenemos;

z = 27 - 8 = 19

De 2 · y = x, tenemos;

2 × 27 = x

x = 54

Por lo tanto;

El precio de las naranjas = 54 pesos

El precio de las manzanas = 27 pesos

El precio de los plátanos = 19 pesos.

Your mother has left you in charge of the annual family yard sale. Before she leaves you to your entrepreneurial abilities, she explains that she has made the job easy for you: everything costs either $1.50 or $3.50. She asks you to keep track of how many of each type of item is sold, and you make a list, but it gets lost sometime throughout the day. Just before she’s supposed to get home, you realize that all you know is that there were 150 items to start with (your mom counted) and you have 41 items left. Also, you know that you made $227.50. Write a system of equations that you could solve to figure out how many of each type of item you sold.

A) x + y = 109
(1.5)x + 227.50 = (3.5)y
B) x + y = 109
(3.5)x + 227.50 = (1.5)y
C) x + y = 41
(1.5)x + 227.50 = (3.5)y
D) x + y = 109
(1.5)x + (3.5)y = 227.50
E) x + y = 150
(1.5)x + (3.5)y = 227.50
F) x + y = $3.50
(1.5)x + (3.5)y = 227.50

Answers

Answer:

[tex]D)\ x + y = 109\\(1.5)x + (3.5)y = 227.50[/tex]

Step-by-step explanation:

Let the items sold with price $1.5 = [tex]x[/tex]

Let the items sold with price $3.5 = [tex]y[/tex]

Initially, total number of items = 150

Items left at the end of the day = 41

So, number of items sold throughout the day = Total number of items - Number of items left

Number of Items sold = 150 - 41 = 109

So, the first equation can be written as:

[tex]\bold{x+y = 109} ....... (1)[/tex]

Now, let us calculate the sales done by each item.

Sales from item with price $1.5 = Number of items sold [tex]\times[/tex] price of each item

= (1.5)[tex]x[/tex]

Sales from item with price $3.5 = Number of items sold [tex]\times[/tex] price of each item

= (3.5)[tex]y[/tex]

Total sales = [tex]\bold{(1.5)x+(3.5)y = 227.50} ....... (2)[/tex]

So, the correct answer is:

[tex]D)\ x + y = 109\\(1.5)x + (3.5)y = 227.50[/tex]

An ant needs to travel along a 20cm × 20cm cube to get from point A to point B. What is the shortest path he can take, and how long will it be (in cm)?

Answers

Each edge of the cube is 20cm. If it stayed on the edges it would need to walk on 3 edges for a total distance of 3 x 20 = 60 cm.

If it walked diagonally across the front face and then one edge it would travel:

Diagonal = sqrt(20^2 + 20^2) = 28.28

Total distance waling a diagonal and then an edge = 28.28 + 20 = 48.28 cm

The shortest distance would be diagonally across the front face then the edge to point B and the distance would be 48.28 cm.

Jameel drew circle A and found that the measure of the is 58°. He knows that he can use this measure to determine the measure of many of the other angles shown in the circle. Enter the measure of ∠ADB.

Answers

The  measure of many of the other angles shown in the circle is: measure of ∠ADB=29°.

Measure of angle ADB

Given:

∠CAD=58°

Hence:

∠BAD=180°-58°

∠BAD=122°

Since ∠ABD is isosceles, thus:

∠ADB-∠ABD

180°-122°=58°

2∠ADB=58°/2

∠ADB=29°

Therefore the  measure of many of the other angles shown in the circle is: measure of ∠ADB=29°.

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If a is an arbitrary nonzero constant, what happens to a/b as b approaches 0

Answers

It depends on how b approaches 0

If b is positive and gets closer to zero, then we say b is approaching 0 from the right, or from the positive side. Let's say a = 1. The equation a/b turns into 1/b. Looking at a table of values, 1/b will steadily increase without bound as positive b values get closer to 0.

On the other side, if b is negative and gets closer to zero, then 1/b will be negative and those negative values will decrease without bound. So 1/b approaches negative infinity if we approach 0 on the left (or negative) side.

The graph of y = 1/x shows this. See the diagram below. Note the vertical asymptote at x = 0. The portion to the right of it has the curve go upward to positive infinity as x approaches 0. The curve to the left goes down to negative infinity as x approaches 0.

Simplifying Please Help!

Answers

Answer: C. 6x+18

Step-by-step explanation:

Use the distributive property

First multiply 6 times x which is 6x

Then multiply 6 times 3 which is 18

Keep the sign the same

Therefore, this should give you 6x+18

What is the additive identity of -17?

Answers

Answer:

The additive identity is 0. The sum of any number with the additive identity is the number itself.

I HOPE ITS RIGHT IF NOT THEN SORRY

HAVE A GREAT DAY :)

It’s always has to be 0

ANSWER QUICKLY PLZZZZZZ
ANSWER QUESTION C​

Answers

Answer:

[tex] \boxed{12}[/tex]

Step-by-step explanation:

E is 5 more than d

f is 7 less than d

a) e = d + 5

b) f = d - 7

c) plug the values of e and f

[tex] = d + 5 - (d - 7)[/tex]

When there is a ( - ) in front of an expression in parentheses, change the sign of each term in the expression

[tex] = d + 5 - d + 7[/tex]

Since, two opposites add up to zero , remove them from the expression

[tex] = 5 + 7[/tex]

Add the numbers

[tex] = 12[/tex]

Hope I helped!

Best regards!

Suppose that F(x) = x? and g(x) = -3x? Which statement best compares the
graph of G(x) with the graph of F(x)?

Answers

Answer:

flipped over the x-axis and stretched vertically

Step-by-step explanation:

Multiplying y by a value greater than 1 results in a vertical stretch. When the sign of it is negative there is a reflection over the x-axis. The appropriate choice is shown below.

__

The second attachment shows how the graph is flipped and stretched.

Plot the image of quadrilateral ABCD under a reflection across the x-axis.

Answers

Answer:

The points for this will be:

A: (1, -4)

B: (-4, -2)

C: (-5, 4)

D: (-2, 1)

Step-by-step explanation:

If we reflect a shape over the x-axis, all of it’s points y values will be negated.

So, (1, 4) becomes (1, -4)

(-4, 2) becomes (-4, -2)

(-5, -4) becomes (-5, 4)

and (-2, -1) becomes (-2, 1)

Hope this helped!

New coordinates of the quadrilateral are A' is (1, -4), B' is (-4, -2), C' is (-5, 4) and D' is (-2, 1)

What is Graph?

Graph is a mathematical representation of a network and it describes the relationship between lines and points.

The coordinates of quadrilateral ABCD are A is (1, 4), B is (-4, 2), C is (-5, -4) and D is (-2, -1)

After reflecting across the x-axis , the x-coordinates of the vertices will remain the same, but the signs of their y-coordinates will change.

Therefore, the new coordinates of the vertices will be:

A' is (1, -4)

B' is (-4, -2)

C' is (-5, 4)

D' is (-2, 1)

Hence,  new coordinates of the quadrilateral are A' is (1, -4), B' is (-4, -2), C' is (-5, 4) and D' is (-2, 1)

To learn more on Graph click:

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Help I don’t know the answer

Answers

Answer:

(D) 6

Step-by-step explanation:

We can substitute the values of a (7) and b (-4) into the equation to find it's result.

[tex]\frac{|2a| -b}{3} \\\\\\\frac{|2\cdot7|-(-4)}{3}\\\\\frac{|14|+4}{3}\\\\\frac{14+4}{3}\\\\\frac{18}{3}\\\\ 6[/tex]

So 6 is the value of this expression when a is 7 and b is -4.

Hope this helped!

6.3 covert to fractional form like a fraction and get a like and brainiest !

Answers

Fractional form: 63/10 or 6 3/10.

Describe the relationship between quartiles and percentiles. ▼ are special cases of ▼ ▼ Upper Q 2 Upper Q 3 Upper Q 1 is the 25th​ percentile, ▼ Upper Q 2 Upper Q 1 Upper Q 3 is the 50th ​percentile, and ▼ Upper Q 2 Upper Q 3 Upper Q 1 is the 75th percentile.

Answers

Answer:

Q1 is the 25th percentile

Step-by-step explanation:

Quartiles are known to be one-fourth of an entity, that is, 1/4th with the whole evaluating to 1. The numerator cannot exceed four, as the division compares an item in an entity to the whole of the entity or sample.

Percentiles represents a whole entity as a 100 with the symbol "%" which denote its use.

The first quartile is 25th percentile, the second is the 50th percentile, the third is the 75th percentile while the fourth quartile which is 4/4 is the 100th percentile mark.

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