Answer:
A. Multiplying by One
Step-by-step explanation:
semoga membantu
6. Find the focus for the parabola.
2x=(y+3)^2+14
Focus: (x,y) =
Answer: Focus = (7.5, -3)
Step-by-step explanation:
The Vertex form of a horizontal parabola is: x = a(y - k)² + h where
a is the vertical stretch; [tex]a=\frac{1}{4p}[/tex]p is the distance from the vertex to the focus(h, k) is the vertexRewrite the equation in Vertex form to identify a, h, & k:
2x = (y + 3)² + 14
[tex]x=\dfrac{(y+3)^2+14}{2}\\\\x=\dfrac{1}{2}(y+4)^2+7[/tex]
Vertex: (h, k) = (7, -3)
[tex]a=\dfrac{1}{2}[/tex]
Find p and then find the focus: Focus = (h + p, k)
[tex]a=\dfrac{1}{4p}\quad \rightarrow \quad \dfrac{1}{2}=\dfrac{1}{4p}\quad \rightarrow \quad 4p=2\quad \rightarrow \quad p=\dfrac{2}{4}\quad \rightarrow p=\dfrac{1}{2}\\[/tex]
Focus: (7 + [tex]\frac{1}{2}[/tex] , -3) = (7.5, -3)
How many points are needed to define a plane?
Answer:
3
Step-by-step explanation:
Answer:
5
Step-by-step explanation:
5
Where v is the final velocity (in m/s), u is the initial velocity (in m/s), a is the acceleration (in m/s²) and s is the distance (in meters). Find v when u is 8 m/s, a is 3 m/s², and s is 19 meters. A. 15 m B. 130−−−√ m C. 178−−−√ m D. 13 m
Answer:
C. 178−−−√ m
Step-by-step explanation:
Given the following :
v = final velocity (in m/s)
u = initial velocity (in m/s)
a = acceleration (in m/s²)
s = distance (in meters).
Find v when u is 8 m/s, a is 3 m/s², and s is 19 meters
Using the 3rd equation of motion :
v^2 = u^2 + 2as
v^2 = 8^2 + 2(3)(19)
v^2 = 64 + 114
v^2 = 178
Take the square root of both sides :
√v^2 = √178
v = √178
What is the sign of y + x?
y
0
Choose 1 answer:
Positive
B
Negative
Zero
Answer:
C
Step-by-step explanation:
As y is zero, y/x will be zero
Please help!! Graph a line with a slope of 1/4 that contains the point (6,3).
Silly comments will the reported!!! Please explain if possible!!
Answer ASAP, Will give brainliest!!
Answer:
First. 115°
Second. 65°
Third. 65°
Fourth. 7
Fifth. 425.25
First
angle DAB = angle ADC (since this is an isosceles trapezoid)
Second
In a trapezoid adjacent angle are supplmentary (that is their sum is 180°)
180-115 is 65°
Third
(Same reason as second)
Fourth
The side 3x+4 is same as the opposite side
So 3x + 4 = 25
on solving you get x = 7 in
Fifth
[tex]area \: = \frac{1}{2} \times length \: of \: the \: perpendicular \: (b1 + b2)[/tex]
area = 1/2 × 13.5 (20+43)
area = 1/2 × 13.5 × 63
Thus area is 425.25
Answer:
Step-by-step explanation:
1)As ABCD is isosceles trapezium,
∠ADC= ∠DAB
∠ADC = 115°
2) AD //BC
∠ADC + ∠DCB = 180° {co interior angles}
115 + ∠DCB = 180
∠DCB = 180 - 115
∠DCB = 65°
3) As ABCD is isosceles trapezium,
∠CBA = ∠DCB
∠CBA = 65°
4) As ABCD is isosceles trapezium, non parallel sides are congruent.
AB = DC
3x + 4 = 25 in
3x = 25 - 4
3x = 21
x = 21/3
x = 7 in
5) height = 13.5 in
a= 43 in
b= 20 in
Area of trapezium = [tex]\frac{(a+b)*h}{2}\\[/tex]
[tex]= \frac{(43 +20)*13.5}{2}\\\\=\frac{63*13.5}{2}\\\\\\= 425.25 in^{2}[/tex]
If two of the ordered pairs was removed which two data points will cause the correlation to decrease the most? Select Two points
1) Data point A
2) Data point B
3) Data point C
4) Data point D
Answer:
1. Data point A
4. Data point D
Step-by-step explanation:
In a scatter plot, the closer the clustered data points are close to the best line of fit, the greater the correlation that would exist between the two variables.
If we are to draw a best line of fit in the scatter plot that is shown above, the closest data points amongst data points A, B, C, D, and E, that would be close to the best line of fit are data points A and D.
Therefore, removing data point A and point D would cause the correlation to decrease the most.
Helppp plssss help meeee
Answer:
C. $1,260
Step-by-step explanation:
80 × 14.5 = 1,160
2,500 × 0.04 = 100
Answer:
C. $1260
Step-by-step explanation:
how to solve this equation
x2-5x=0
Answer:
x = 5
Step-by-step explanation:
x² - 5x = 0
(x² - 5x) /x = 0/x
x²/x - 5x/x = 0
x - 5 = 0
x = 5
Check:
x² - 5x = 0
5² - 5*5 = 0
25 - 25 = 0
The solution to the equation is:
x = 0 or x = 5
How to solve the equation?A quadratic equation is an algebraic equation of the second degree in x. The quadratic equation in its standard form is ax² + bx + c = 0, where a and b are the coefficients, x is the variable, and c is the constant term.
We have:
x²-5x = 0
We can solve the equation as follow:
x²-5x = 0
Factorize:
x(x - 5) = 0
x = 0 or (x -5) = 0
x = 0 or x = 5
Learn more about quadratic equation on:
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If graphs have a linear equations in a system are concurrent having the same slope and the same y-intercept what does that mean about possible solutions
Answer:
Infinite Amount of Solutions
Step-by-step explanation:
Since we have concurrent systems (same slope + same y-int), we know that the systems of equations would be the exact same line. If that is the case, the we would know that ANY value input would work. You could even test it mathematically, and it would give you infinite amount of solutions.
PLEASE HELP WILL MARK BRAINLIEST
Answer:
C
Step-by-step explanation:
Its the only answer where the y intercept is 16.
We know its 16 because the line crosses the y axis at 16
Help me!!! Please to solve this problem of o. Math
a) Given a function f(x) = 2x + 3. Find (a) f(1), (b) f(-5), (c) f(a), (d) f(a + 2) (e) f(b)?
b) let f(x) = x + 4 define a function in the closed interval of -55x55, find f(-2), f(3) and f(7).
a:-
f(x)=2x+3
[tex]\\ \rm\Rrightarrow f(1)=2(1)+3=2+3=5[/tex]
[tex]\\ \rm\Rrightarrow f(-5)=2(-5)+3=-10+3=-7[/tex]
[tex]\\ \rm\Rrightarrow f(a)=2a+3[/tex]
[tex]\\ \rm\Rrightarrow f(a+2)=2(a+2)+3=2a+4+3=2a+7[/tex]
[tex]\\ \rm\Rrightarrow f(b)=2b+3[/tex]
b:-
f(x)=x+4
[tex]\\ \rm\Rrightarrow f(-2)=(-2)+4=2[/tex]
[tex]\\ \rm\Rrightarrow f(3)=3+4=7[/tex]
[tex]\\ \rm\Rrightarrow f(7)=7+4=11[/tex]
Step-by-step explanation:
[tex]thank \: you[/tex]
Find the values of the unknown angles marked with letters. 50 points!!!!!!!
a ?
b ?
c ?
d ?
Answer:
a = 115°, alternate interior angles are congruentb = 70°, same as abovec = 180° - 115° = 65°, angles forming a straight angle are supplementaryd = 180° - 70° = 110°, same as aboveC:-
[tex]\\ \sf\longmapsto c+115=180[/tex]
[tex]\\ \sf\longmapsto c=180-115[/tex]
[tex]\\ \sf\longmapsto c=65°[/tex]
D:-
[tex]\\ \sf\longmapsto d+70=180[/tex]
[tex]\\ \sf\longmapsto d=180-70[/tex]
[tex]\\ \sf\longmapsto d=110°[/tex]
What number must be added to the expression for it to equal zero? (–6.89 + 14.52) + (–14.52)
Answer:
The number to be added is 6.89
Step-by-step explanation:
Here, we want to know what number must be added to the expression to make it equal to zero.
Let the number be x
Thus;
-6.89 + 14.52 -14.52 + x = 0
-6.89 + x = 0
x = 6.89
can any one help me in this..???? please
Answer:
(i) a1/a2 =/ b1/b2
(ii) a1/a2=b1/b2 =/ c1/c2
(iii) a1/a2=b1/b2=c1/c2
Step-by-step explanation:
=/ means not equal to.
graphical repesentation of
1.intersecting lines
2.coincident lines
3.parallel lines
a1/a2 and next two slots is basically dividing the coefficents if each equation.
for eg. 1. a1/a2= 2/4=1/2 and so on.
parallel lines are inconsistent whereas intersecting and coincident lines are consistent.
1. The local ice cream shop has had a great month in sales. Based on the Information below, calculate the operating ratio.
cost of goods sold = $2,500.00
net sales = $18,200.00
operating expenses = $4,350.00
O 62 percent
O 38 percent
O 71 percent
O 32 percent
The operating ratio of the local ice cream shop is 38 percent
The cost of goods sold is $2,500
The net sales is $18,200
The operating expenses is $4,350
The operating ratio can be calculated as follows
= cost of goods sold+ operating expenses/total revenue
= 2500+4,350/18,200
= 6,850/18,200
= 0.376×100
= 37.6
= 38%
Hence the operating ratio is 38%
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In a competition, four of the participants have completed their performances. Their scores are 9.61, 9.66, 9.64, and 9.60. The highest score wins. Which score will enable the last participant to win the competition?
9.67
9.65
9.62
9.06
For some reason, the scores your teacher gave you and the answer choices don't match up. I'm not sure why this is. Perhaps some kind of typo. Please double check and get back to me.
Weekly wages at a certain factory are
normally distributed with a mean of
$400 and a standard deviation of $50.
Find the probability that a worker
selected at random makes between
$350 and $400.
Answer:
0.34134
Step-by-step explanation:
in other to solve for this question we would be using the z score formula
z = (x - μ) / σ
x = raw score
μ = mean
σ = standard deviation
the question tells us to find the probability that a worker selected at random makes between $350 and $400
let x1 = 350 and x2= 400 with the mean μ = 400 and standard deviation σ = $50.
z1 = (x1 - μ) / σ = (350-400) / 50 = -1
z2 = (x2 - μ) / σ = (400 - 400) / 50 = (0/50) = 0
from tables, P(z <= -1) = 0.15866
P(z <= 0) = 0.5
then the probability would give us, P(-1 ≤ z ≤ 0) =0.5 - 0.15866 =
0.34134
that explains that the probability that a worker selected at random makes between $350 and $400 = 0.34134
Solve for x. 3:12 = x:16
Answer:
[tex]x = 4[/tex]
Step-by-step explanation:
We can represent each ratio as a fraction, then use the cross products property to find the value of x.
[tex]\frac{3}{12} = \frac{x}{16} \\\\\\16\cdot3=48\\\\48\div12=4[/tex]
Hope this helped!
Given only a compass and straightedge, Greeks were able to construct only
regular polygons and circles, thus leaving many constructions impossible to
complete.
A. True
B. False
A regular heptagon (7-sided figure) cannot be constructed with a compass and straightedge.
there were 54 marbles in total the ratio of green to blue is 7:2 work out the number of green marbles
Answer:
42 green marbles
Step-by-step explanation:
sum the parts of the ratio, 7 + 2 = 9 parts
Divide the number of marbles by 9 to find the value of one part of the ratio.
54 ÷ 9 = 6 ← value of 1 part of the ratio , then
7 parts = 7 × 6 = 42 ← number of green marbles
X+a=3/4
How do I solve for x first then a
Answer:
[tex]x + a = \frac{3}{4} \\ x = \frac{3}{4} - a[/tex]
for a:
[tex]a = \frac{3}{4} - x[/tex]
[tex]\\ \sf \longmapsto x+a=\dfrac{3}{4}[/tex]
[tex]\\ \sf \longmapsto x=\dfrac{3}{4}-a[/tex]
[tex]\\ \sf \longmapsto x=\dfrac{3-4a}{4}[/tex]
And
[tex]\\ \sf \longmapsto a=\dfrac{3}{4}-x[/tex]
[tex]\\ \sf \longmapsto a=\dfrac{3-4x}{4}[/tex]
!helppppppppp meeeeeeee emmmmmm!
Answer & Step-by-step explanation:
Take the last expression:
[tex](3*3)*(4*4)[/tex]
This can be simplified using exponents. [tex]x*x=x^2[/tex] :
[tex]3^2*4^2[/tex]
So, take the two numbers within the parentheses from the first expression and write separately, including the exponent with each. Do this with the next problem:
[tex](5*6)^3=5^3*6^3[/tex]
:Done
ZA and ZB are vertical angles. If m_A = (7x– 20)° and m_B = (6x – 1)º,
then find the measure of ZA.
[tex]\\ \sf\longmapsto 7x-20=6x-1[/tex]
[tex]\\ \sf\longmapsto 7x-6x=-1+20[/tex]
[tex]\\ \sf\longmapsto x=-19[/tex]
Now
[tex]\\ \sf\longmapsto m<A=7x-20=7(-19)-20=133-20=113[/tex]
PLS HELP ME ON THIS QUESTION I WILL MARK YOU AS BRAINLIEST IF YOU KNOW THE ANSWER PLS GIVE ME A STEP BY STEP EXPLANATION WHILE ANSWERING THE QUESTION!!
A data set with less variation will have a smaller ____________________.
A. minimum
B. median
C. mean
D. interquartile range
Answer:
c. mean
Step-by-step explanation:
the data set that has less variation will have smaller distribution over a large area or variation measures.
Answer:
D. Interquile Range
Step-by-step explanation:
The datasets that have less variation are those that have smaller dispersion or variation measures.
Some of these measures of variance are variance, standard deviation, mean absolute deviation, range and interquartile range. Among the options shown, the only one that is used as a measure of variation is the interquartile range. The interquartile range is the difference between the third quartile and the first quartile of a data distribution. In other words, the interquartile range measures the range between the central 50% of the data.
Which expression is equivalent to 18 – 20?
[tex]\huge\text{Hey there!}[/tex]
[tex]\huge\boxed{\mathsf{18 - 20}}\\\huge\boxed{=\mathsf{18 + (-20)}}\\\huge\boxed{\mathsf{= -2}}\\\huge\boxed{\textsf{Answer: 18 + (-20)}}\huge\checkmark\\\\\huge\text{Good luck on your assignment \& enjoy your day!}\\\\\huge\boxed{\frak{Amphitrite1040:)}}[/tex]
I need helps will give you a good rating.
Answer: x = 3
Step-by-step explanation:
Sqrt(x+7) - 1 = x
Sqrt(x+7) = x + 1
x+7 = x^2 + 1
x = x^2 - 6
x=3
What is the multiplicity of each of the roots of the graph of
f(x) = 2x4 + 12x} + 16x2 – 12x – 18?
A.-3, multiplicity 2; -1, multiplicity 1; 1, multiplicity 1
B.-3, multiplicity 2; 1, multiplicity 2
C.-3, multiplicity 1; -1, multiplicity 1; 1, multiplicity 1
D.-3, multiplicity 2; -1, multiplicity 3; 1, multiplicity 1
Answer:
The correct option is;
C. -3, multiplicity 2; -1, multiplicity 1; 1, multiplicity 1
Please find attached the required function graph
Step-by-step explanation:
To solve the equation f(x) = 2·x⁴ + 12·x³ + 16·x² -12·x - 18, by graphing the function, we have;
x [tex]{}[/tex] F(x)
-4[tex]{}[/tex] 30
-3[tex]{}[/tex] 0
-2[tex]{}[/tex] 6
-1[tex]{}[/tex] 0
0 [tex]{}[/tex] -18
1[tex]{}[/tex] 0
2[tex]{}[/tex] 150
The shape of a graph with multiplicity of 2
Given that the graph bounces of the horizontal axis at the y-intercept at point x = -3, the factor (x - 3) must be a quadratic of the form (x - 3)², thereby having a multiplicity of 2 in the solution which are;
x = 1, -1, and, giving
(x - 1)·(x + 1)·(x - 3)² = 0
Therefore, the correct option is -3, multiplicity 2; -1, multiplicity 1; 1 multiplicity 1.
Answer:
C
Step-by-step explanation:
WORKED EXAMPLES
Try Vertical Angle Problems
ZC and Dare vertical angles.
m_C=° and mZD=(-3x +80)°
What is mZC
Enter your answer in the box.
Answer:
M<C = 20°
Step-by-step explanation:
Because they’re vertical angles, that means they’re equal to each other so:
m<C = m<D
x = -3x + 80
x + 3x = 80
4x = 80
x = 20
Since m<C equals x, that means m<C is 20°
What is the length of segment AB
A) 3
B) [tex]\sqrt{20}[/tex]
C) [tex]\sqrt{41}[/tex]
D) 9
Answer: [tex]\large \boldsymbol {C) \ AB=\sqrt{41} }[/tex]
Step-by-step explanation:
The formula for the distance between points:[tex]\bf AB= \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}[/tex] Coordinates of point A (0;5 ); coordinates of point B(4;0)[tex]\bf AB= \sqrt{(0-4)^2+(5-0)^2} =\sqrt{16+25} =\sqrt{41}[/tex]