At a coffee shop, the manager recorded the number of customers who visited the store at the end of each hour. The graph shows the recordings for a 24-hour period. The function describing this graph is a transformation of the parent sine function, y=sin(x)
Which value is closest to the amplitude of the transformed function?

O 83 customers
O 27 customers
O 54 customers
O 30 customers

Answer:

B

Step-by-step explanation:

Answer:

1/25

Step-by-step explanation:

Answer:

I think it may be 1/1225

Step-by-step explanation:

first chance is 2/50 and second chance is 1/49 as one card decrease at first. So multiplying it we get 1/1225.

The arithmetic average return is probably too high for longer periods and the geometric average is probably too low for shorter periods.

When we look at historical returns, the difference between the geometric and arithmetic average returns isn't too hard to understand.

To put it slightly differently, the geometric average tells you what you actually earned per year on average, compounded annually. The arithmetic average tells you what you earned in a typical year. You should use whichever one answers the question you want answered. A somewhat trickier question concerns forecasting the future, and there's a lot of confusion about this point among analysts and financial planners.

Now, If we have estimates of both the arithmetic and geometric average returns, then the arithmetic average is probably too high for longer periods and the geometric average is probably too low for shorter periods.

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The dimensions of the rectangle having greatest area in the piece of plexiglass which is a semicircle is [tex]2\sqrt{2}[/tex] and  [tex]\sqrt{2}[/tex].

Given radius of piece of plexiglass which is a semi circle equal to 2m.

We  have to find the dimensions of the rectangle which is inscribed in the semi circle.

Draw a rectangle in a semicircle.

Suppose the length of rectangle be x and width be y.

Draw a line from the center to the vertex of the rectangle which forms a right angled triangle with sides x,y and 2.

[tex](x/2)^{2} +y^{2} =2^{2}[/tex]

y=[tex]\sqrt{16-x^{2} }/2[/tex]

Area of rectangle=2xy

=x[tex]\sqrt{16-x^{2} }[/tex]/2

Finding the derivative of area

d A/dx=1/2[x(-2x)/2[tex]\sqrt{16-x^{2} }[/tex]+[tex]\sqrt{16-x^{2} }[/tex]]

d A/dx=0

1/2[[tex]-2x^{2} /2\sqrt{16-x^{2} }+\sqrt{16-x^{2} } ][/tex]=0

Solving for x

[tex]\sqrt{16-x^{2}[/tex]=[tex]x^{2} /\sqrt{16-x^{2} }[/tex]

16-[tex]x^{2}[/tex]=[tex]x^{2}[/tex]

16=2[tex]x^{2}[/tex]

[tex]x^{2}[/tex]=8

x=2[tex]\sqrt{2}[/tex]

put the value of x in y=[tex]\sqrt{16-x^{2} }/2[/tex] to get the value of y

y=[tex]\sqrt{16-8} /2[/tex]

=[tex]\sqrt{8} /2[/tex]

= 2[tex]\sqrt{2} /2[/tex]

=[tex]\sqrt{2}[/tex]

Hence the dimensions of rectangle which is in a semi circle of radius 2 is [tex]\sqrt{2} and 2\sqrt{2}[/tex].

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The probability that more than 5 students will pass their exam is 0.0188416.

The probability that a student passes their examination = 40% = 0.4

The probability that more than 5 students pass their statistics exam = Probability that 6 students pass their exam + Probability that 7 students pass their exam

The probability that 6 students pass their exam =

[tex]7C_{6} (0.4)^{6} (0.6)^{1}\\=7(0.4)^6(0.6)\\=0.0172032[/tex]

The probability that 7 students pass their exam =

[tex]7C_{7} (0.4)^{7} (0.6)^{0}\\=(0.4)^7\\=0.0016384[/tex]

The probability that more than 5 students pass their statistics exam = 0.0172032 + 0.0016384

= 0.0188416

Therefore, we have found the probability that more than 5 students will pass their exam to be 0.0188416.

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like the place where you are applying TURNED TRIANGLE.

coz literrally it means that if the trianlge has for example angle a on its right side then we turn the triangle as a whole and make the turn such that angle a is anywhere else but not on our right side....

I believe the explanation is clear, if not do contact me

Answer:

57?

Step-by-step explanation:

On purchasing a cell phone, Tia got an offer and got the cell phone for 35% less than the tag price. If she saved 140 on that cell phone. Then price on the tag is 400.

Since, the cell pone is sold with 35% discount on it.

Tia got that phone at selling price with 35% discount on tag price. Also, she saved around 140 on buying the cell phone.

Therefore, the discount on the cell phone on the tag price is her saving on buying the cell phone.

Hence,

35% discount on tag price=Saved amount

(35/100)×T=140

where T is the tag price.

T=(140×100)35

T=14000/34

T=400

Therefore, on buying the cell phone with 35% discount on tag price costs around 140. Then the tag price is 400.

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Answer: [tex]\triangle XYZ \sim \triangle GFH[/tex] by AA.

Step-by-step explanation:

Finding the third angle in triangle XYZ,

[tex]m\angle YXZ=180^{\circ}-77^{\circ}-48^{\circ}=55^{\circ}[/tex],

Thus, [tex]\triangle XYZ \sim \triangle GFH[/tex] by AA.

Let [tex]a,b,c[/tex] denote the amounts (in liters) of the 20%, 30%, and 60% acid solutions, respectively. These quantities then contain [tex]0.20a[/tex], [tex]0.30b[/tex], and [tex]0.60c[/tex] liters of acid.

The chemist wants to end up with a total volume of 54 liters, so

[tex]a + b + c = 54[/tex]

and a concentration of 45% acid. This comes out to 0.45×54 = 24.3 total liters of acid, so

[tex]0.20a + 0.30b + 0.60c = 24.3[/tex]

He will also use twice as much of the 60% solution as the 30% solution, so

[tex]c = 2b[/tex]

Substitute this into the first two equations and solve for [tex]a,b[/tex].

[tex]\begin{cases} a + 3b = 54 \\ 0.20a + 1.50b = 24.3 \end{cases}[/tex]

Eliminating [tex]b[/tex], we have

[tex](a + 3b) - 2 (0.20a + 1.50b) = 54 - 2(24.3) \implies 0.60a = 5.4 \implies \boxed{a = 9}[/tex]

Solve for [tex]b[/tex].

[tex]9+3b=54 \implies 3b=45 \implies \boxed{b=15}[/tex]

Solve for [tex]c[/tex].

[tex]c = 2(15) \implies \boxed{c=30}[/tex]

a = 9, b = 15 and c = 30 liters of each solution should be used.

According to the question:

Let a, b, and c stand for the relative volumes (in liters) of the 20 percent, 30 percent, and 60 percent acid solutions. The amount of acid in these amounts is 0.20a, 0.30b, and 0.60c liters.

a+b+c = 54 because the chemist wishes to have a final volume of 54 liters.

and a concentration of 45% acid. This comes out to 0.45×54 = 24.3 total liters of acid, so

0.20a + 0.30b + 0.60c = 24.3

Additionally, he will consume twice as much of the 60% solution as the 30% solution, thus c = 2b.

Substitute this into the first two equations and solve for a,b

a + 3b = 54

0.20a + 1.50b = 24.3

[tex](a+3 b)-2(0.20 a+1.50 b)=54-2(24.3) \\0.60 a=5.4[/tex]

a = 9.

9+3b = 54

3b = 45

b = 15.

c = 2(15)

c = 30.

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Answer:

Hello!

independent variable: variable in an experiment that is changed e.g. a plant's exposure to light

dependent variable: variable in an experiment that is measured e.g. a plant's height

The question is just asking to identify these variables.

Hope this helps! Feel free to ask further questions if need be.

The equilibrium level if autonomous expenditures are $2,000 and the mpe is 0. 5 is $4000.

From the information given, the autonomous expenditures are $2,000 and the mpe is 0. 5.

Here, the equilibrium level will be:

= 2000/(1 - 0.5)

= 2000/0.5

= 4000

In conclusion, the correct option is $4000.

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The law of sines cannot be used to calculate the side c.

The given parameters are:

A = 27.5°, a = 15.0 cm, b = 36.4 cm

Based on the above values,

The law of sines cannot be used to calculate the side c.

This is so because the angle C is not given

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The simplified form is [tex]6x^{3}[/tex].

What are indices in maths?

The equation is -

[tex]\sqrt{\frac{2160x^{3} }{60x^{2} } }[/tex]

We can rewrite this using property of multiplication to obtain

[tex]\sqrt{\frac{2160}{60} * \frac{x^{8} }{x^{2} } }[/tex]

We simplify variable expression in the radicand using

[tex]\frac{a^{m} }{a^{n} } = a^{m - n}[/tex]

[tex]\sqrt{36 * x^{8 - 2} }[/tex]

[tex]\sqrt{36 * x^{6} }[/tex]

[tex]\sqrt{36 * (x^{3})^{2} }[/tex]

[tex]\sqrt{36} * \sqrt{(x^{3})^{2} }[/tex]

[tex]6 * x^{3}[/tex]

Therefore,  the simplified form is [tex]6x^{3}[/tex]

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Step-by-step explanation:

3 - 11x

x is "a number".

so, the request is to multiply it by 11 and subtract the result from 3.

The perimeter of the rectangle that has a length of 5 3/5 inches, and the width as half of its length is 16.8 inches. Hence, option A is the right choice.

The perimeter of any object is the total sum length of its boundary.

The perimeter of a rectangle with length l units and width w units is given as:

Perimeter = 2(l + w) units.

In the question, we are given that the length of a rectangle is 5 3/5 inches and its width is half of its length. We are asked to find the perimeter of the rectangle.

The length of the given rectangle (l) = 5 3/5 inches = 28/5 inches.

The width of the given rectangle (w) = Half of length = 1/2 * 28/5 inches = 14/5 inches.

Thus, the perimeter of the rectangle = 2(l + b) = 2(28/5 + 14/5) inches,

or, the perimeter = 2(42/5) inches,

or, the perimeter = 84/5 inches,

or, the perimeter = 16.8 inches.

Thus, the perimeter of the rectangle that has a length of 5 3/5 inches, and the width as half of its length is 16.8 inches. Hence, option A is the right choice.

The given question is incorrect. The correct question is:

"The length of a rectangle is 5 3/5 inches. the width of the rectangle is half of its length. what is the perimeter of the rectangle?

(a) 16.8 inches

(b) 8.4 inches

(c) 2.8 inches

(d) 15.68"

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The truck travelled 0.42 miles per minute

The given parameters are:

Distance = 75 miles

Time = 3 hours

Convert time to minutes

Time = 3 * 60 minutes

Time = 180 minutes

The speed is calculated as:

Speed = Distance/Time

This gives

Speed = 75 miles/180 minutes

Evaluate

Speed = 0.42 miles per minutes

Hence, the truck travelled 0.42 miles per minute

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Answer:

A= 16

P=16

Step-by-step explanation:

A=h^bxb/ 2

P= side+base+side

Ratio scale of measurement for the following variable, The weight of a group of dieters.

Ratio measurement scale of ratio variables include height, weight, and distance. The ratio scale allows for the addition, subtraction, division, and multiplication of data. Additionally, ratio scales have a "real zero," which sets them apart from interval scales. The ratio scale is used to determine weight. The ratio is identical to the interval scale, with the exception that 0 on the scale denotes the absence of anything. serval scales can depict values lower than zero and do not hold a true zero. For instance, you can gauge temperatures as low as -10 degrees Celsius. Contrarily, ratio variables are always greater than zero. Height and weight are measured starting at 0 and never below it. Because they are numbers as we typically think of them, ratio scales are the simplest to comprehend. On a ratio scale, the distance between consecutive numbers is equal, and a score of zero indicates that there is no presence of the thing being measured. The majority of ratio scales are counts of items.

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Answer: -x

Apply Multiplicative Distribution Law:- 1/5 * 5x - 1/5 * 20 - 1/2 * 4x - 1/2 *(-8)

Determine the sign for multiplication or division: 1/5 * 5x - 1/5 * 20 - 1/2 * 4x + 1/2 * 8

Cross out the common factor: x - 1/5 * 20 - 1/2 * 4x + 1/2 * 8

Cross out the common factor: x - 4 - 1/2 * 4x + 1/2 * 8 - 4 - 2x + 1/2 * 8

Cross out the common factor: x - 4 - 2x + 1/2 * 8

Cross out the common factor:  x - 4 - 2x + 4

Reorder and gather like terms: (x - 2x) + (- 4 + 4)

Collect coefficients for the like terms: (1 - 2) * x + (- 4 + 4)

Calculate the sum or difference :  - x + (- 4 + 4)

The sum of two opposites equals 0: -x

Answer: -x

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Answer:

D) Substitute 5 into each expression and evaluate them.

Step-by-step explanation:

Answer:

A

Step-by-step explanation:

The function has vertical asymptotes at x=7 and x=-3, so the denominator needs to have factors (x-7) and (x+3).

This eliminates all the options except for A.

The equation of the graphed parabola is y=a[tex](x+3)^{2}[/tex]-4.

Given that parabola is plotted, concave up , with vertex located at coordinates (-3,-4).

We are required to find the equation of the graphed parabola.

The equation of a quadratic function of vertex (h,k) is given by:

y=a[tex](x-h)^{2}[/tex]+k

In the above equation a is the leading coefficient.

We have been given point (-3,-4).

We have to just put the value of h=-3 and k=-4 and the required equation will be as under:

y=a[tex](x+3)^{2}[/tex]-4

Hence the equation of the parabola which is plotted, concave up, with vertex located at coordinates (-3,-4) is y=a[tex](x+3)^{2}[/tex]-4.

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Answer: -3/2

Step-by-step explanation:

we could use the two points (2,3) and (0,4) from the graph

y2-y1/x2-x1

= 0-3/4-2

= -3/2

[tex]\frac{97}{100}[/tex] probability that a randomly chosen college student either has a job or lives on campus.

What is probability?

To find the probability that a randomly chosen college student either has a job or lives on campus:

Given: 85% of college students have a job, 54% live on campus, and 42% have a job and live on campus.

So, out of 100 students, 42 students either has a job or live on campus.

43 college students have a job and 12  live on campus.

So, 43 + 42 + 12 = 85 + 54 - 42

85 + 12 = 139 - 42

97 = 97

Therefore, [tex]\frac{97}{100}[/tex] probability that a randomly chosen college student either has a job or lives on campus.

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Answer:

t = 60/n

Step-by-step explanation:

The original equation we know is y = k/n

Since 12 people can assemble the set in 5 hours, when y is 5, n will be 12.

We can now input that value into the equation.

--> 5 = k/12

--> 5(12) = k/12 (12)

--> 60 = k

--> k = 60

The equation to represent the situation can be written as:

t = 60/n

and that is our final answer!

12 people can assemble in 5hours

So

Equation

Or

There were 74 problems in the test.

Let the student got total number of problems in the test to be X.

Percentage of correct answer = 39 %

⇒ 61% of X were incorrect

⇒61/100 x X = 45

⇒61X = 45x100

⇒X = 4500/61

⇒X=73.77

After rounding off 73.77, we get 74.

Hence, we can say that there were total of 74 problems in the test.

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Answer:

Step-by-step explanation:

hello :

P(A ∩ B)=P(A)×P(B)=1/2×1/3 = 1/6

Answer: 21 units²

Step-by-step explanation:

Since there is a pair of parallel sides, this figures is a trapezoid. The formula for the area of a trapezoid is [tex]\frac{1}{2}(a+b)h[/tex], where a and b are the parallel sides and h is the height.

Here, a and b are 5 and 9, while 3 is the height. Let's put all 3 values into the formula.

[tex]A=\frac{1}{2}(5+9)*3[/tex]

[tex]A=\frac{1}{2}(14)*3[/tex] [Adding in the parentheses]

[tex]A=7*3[/tex] [Multiplying one-half by 14]

[tex]A=21[/tex] [Multiplying 7 and 3]

The area is 21 units².