At 7.1 Hz a 200-turn, flat coil of cross sectional area of 300.0 cm2 be rotated in a uniform 30.0-mt magnetic field to have a maximum value of the induced emf equal to 8.0 v
What is magnetic field?An electric charge, an electric current, and magnetic materials are all affected magnetically by a magnetic field, which is a vector field. A force perpendicular to the magnetic field and its own velocity acts on a moving charge in a magnetic field.
Given,
number of turns is N = 200 turns
cross-sectional area is A = 300 cm² = 300 x 10⁻⁴ m²
the magnitude of magnetic field strength is B = 30 x 10⁻³ T
the maximum value of the induced emf is E = 8 V
Now,
Maximum induced emf is, E = NBAω
where,
ω is the angular velocity (ω = 2πf)
Now,
E = NBA2πf
where,
f is minimum frequency
So, f = E / (NBA2π)
f = 8 / (200 x 30 x 10⁻³ x 300 x 10⁻⁴ x 2 x 3.142)
f = 7.073 Hz
f = 7.1 Hz
∴ the minimum frequency of the coil is 7.1 Hz.
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an automobile with a mass of 1325 kg has 3.02 m between the front and rear axles. its center of gravity is located 1.78 m behind the front axle. the automobile is on level ground. (a) determine the magnitude of the force from the ground on each front wheel (assuming equal forces on the front wheels). 2665.79 correct: your answer is correct. n (b) determine the magnitude of the force from the ground on each rear wheel (assuming equal forces on the rear wheels).
The magnitude of the force from the ground on each front wheel is 2775N.
Let us call the force on the front axle F and the force on the rear axle R.
We know that
⇒ F + R= total weight of vehicle = 1360 * 9.80 = 13328 Newtons
And using torques, you know that force on the front axle * distance to the center of mass = force on the rear axle * distance to the center
of mass
or F *1.78 = R * (3.05 - 1.78)
So
1.4016F = R
Then.
F + 1.4016 F = 13328
F = 5550 N and R = 13328 - 5550 = 7778N
So the force on each front tire is 5550 /2 = 2775N
And the force on each rear tire is 7778 /2 = 3889N
Force is a push or pulls upon an item because of the object's interaction with some other object. Pressure is a power that can exchange the motion of an object. A force can reason an object with mass to alternate its speed, i.e., to boost up. pressure also can be described intuitively as a push or a pull. A force has each significance and course, making it a vector amount.
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consider two cars moving along the same straight road in opposite directions. car a has a mass of 500kg500kg and has a constant speed of 20m/s20m/s ; car b has a mass of 800kg800kg and a constant speed of 15m/s15m/s . what can you say about the net forces on the cars?
The net force on both the cars car a and car B will be zero.
According to the first law of motion stated by Newton,
An object would continuously written it's state of motion or rest if the net force on the object is zero. It means that, no matter how many forces are working on the body if they all cancel out each other and the net force becomes zero the body will continue it's same state.
Also according to second law of Newton,
The force is rate of change of momentum with respect to time.
F = ma
Here, both the cars the car A of mass 500 kg and the car B of mass 800 kg are moving with a constant velocity of 20 m/s and 15 m/s respectively.
If the velocity of the car is not changing with time it means that there is no acceleration on the body.
If there is no acceleration on the body, then there is no net force on the body.
So, we can conclude hair that the net force on the cards is zero.
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55. A 500 gram ball begins from rest and rolls down a 30° frictionless incline.
a. What is the ball's acceleration?
b. What is the ball's velocity after 15 seconds?
Acceleration : a. F=ma, mg cos(90°-θ)= ma, g cos (90°-θ)= a, g sin(θ) = a, g sin(30°)= a
b. v= u+(a*t), u=0, v= (a*t), v= ( g sin(30°) * 15 ).
What is Acceleration?
If an object's velocity changes, it is said to have been accelerated. An object's velocity can change depending on whether it moves faster or slower or in a different direction. A falling apple, the moon orbiting the earth, and a car stopped at a stop sign are a few instances of acceleration. Through these illustrations, we can see that acceleration happens whenever a moving object changes its direction or speed, or both.
Therefore, the acceleration and velocity are solve.
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the amount of net force required to keep a 15-kg object moving rightward with a constant velocity of 3 m/s is .
The net force required to move the object of mass 15 kg and constant velocity is 0N
The mass of the object = 15 kg
The object is moving with a constant velocity = 3 m/s.
The net force required to move the object can be calculated by using the formula,
F = ma
where F is the force
m is the mass
a is the acceleration.
The acceleration is nothing but a rate of change of velocity (i.e. a = v/t). But for a constant velocity, the acceleration will be zero. Because there will be no change in velocity.
Therefore, the net force is
F = 15 x 0
= 0 N
Therefore, the net force is 0 N
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in hydrogen fusion, four protons crash into each other to produce a helium nucleus. but the helium nucleus (and other particles created in the reaction, such as neutrinos) is less massive than the protons that form it. what happens to the missing mass?
Missing mass converted into energy.
How does the fusion of four hydrogen atoms into helium atoms occur?Four hydrogen nuclei (photons) combine to form a helium nucleus in the fundamental hydrogen fusion cycle. In the star's core, throughout this fusion cycle, energy is released; in other words, energy is released during this process.
Compared to the original four protons that joined together, the final helium-4 atom weighs less (see E=mc2). Because of this, the mass-energy equivalence of their interaction causes an excess of energy to be released from the Sun as heat and light.
The sun and the stars are propelled by fusion. In one instance of this kind of reaction, two hydrogen atoms combine to create an atom of helium. During the process, a portion of the hydrogen's mass is transformed into energy.
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an engineer is working on determining the speed limit for a curved stretch of road. she knows the coefficient of friction between the wheels and the road is 0.7 when the road is dry and 0.3 when the road is wet. she also knows that the mass of the vehicle does not matter, but completes her calculations for a 700kg car. in order to set a speed limit that is safe under any conditions, should she perform her calculations with the coefficient of friction for wet or dry pavement?
The speed limit for a curved stretch of road with the coefficient of friction between the wheels and the road is 0.7 when the road is dry and 0.3 when the road is wet is √ 2.94 r m / s
Fc = m ac
Ff = μ N
N = m g
Fc = Centripetal force
m = Mass
ac = Centripetal acceleration
Ff = Frictional force
μ = Co-efficient of friction
N = Normal force
μ = 0.3 ( Wet value to taken to provide zero skidding under any condition)
g = 9.8 m / s²
The only force that is providing the centripetal force is frictional force.
m ac = μ m g
ac = 0.3 * 9.8
ac = 2.94 m / s²
ac = v² / r
2.94 = v² / r
v = √ 2.94 r m / s
Therefore, the speed limit for the curved stretch of road is √ 2.94 r m / s. She should perform her calculations with the coefficient of friction for wet pavement.
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observed voltages not being shared identify components in parallel in a series-parallel circuit. group of answer choices true false
In a parallel circuit, each component is subject to the same voltage.
Is the voltage the same in a series-parallel circuit?In a series circuit, the current flowing through each component is the same, and the voltage across the circuit equals the sum of the voltages across each component. The voltage across each component in a parallel circuit is the same, and the total current is the sum of the currents flowing through all of the components. In a series circuit, the components share the supply voltage. The voltage of the supply is equal to the sum of the voltages across components connected in series. There are two or more paths for current to travel through in a parallel circuit. Each element of the parallel circuit has the same voltage applied to it. The total amount of current coming from the source
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allison has to design a device that converts energy between two different forms. she decides she wants to convert electrical energy into motion and sound. which invention should she model her design after?
The motor is an excellent invention for Allison to use as a model for her device.
People use both interchangeably, but the difference is that motors run on electricity and engines run on combustion. The engine converts various forms of fuels into mechanical force, while the motor transforms electrical energy into mechanical energy.
They operate using principles of electromagnetism, which shows that a force is applied when an electric current is present in a magnetic field. This force creates a torque on a loop of wire present in the magnetic field, which causes the motor to spin and perform useful work.
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a uniform tin film of alcohol lies on a flat glass plate. when monochromatic light, whose wavelength can be changed, is incident normally, the refected light is a minimum for a wavelngth of 512 nm and a maximum for a wavelength of 635 nm. what is the minimum t hickness of the film
This is also known as the cut and weight method for determining the average thickness of plastic sheets.
The calculator below uses the formula (volume) x (density) = (weight) to calculate the theoretical thickness of a plastic film. "Film" is generally less than 1 mm thick, so the unit is μm. (If it is 1 mm or more, it is called a "sheet.") Generally, the micrometer method (JIS-C-2151) is used. Using a micrometer, measure the specified number of specified points in the width direction and length direction of the film. Film thickness has a significant impact on coating quality and cost. Measuring it and knowing which gauge to use is routine for every coater. Film thickness plays an important role in product quality, process control, and cost control and can be measured by various instruments.
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two cars, car x and car y, are moving with the same velocity, and slam on the brakes coming to a stop. car x is more massive than car y. for which car is the amount of work done by friction in stopping it the highest?
The amount of work done by friction in stopping the car is given as
Wx > Wy.
There are two cars moving with the same velocity
car X is more massive than car Y
mass of car X = Mx
mass of car Y = My
here given, Mx > My
The distance travelled will be the same as the initial velocity, and it is independent of mass.
Let, μ be the coefficient of kinetic friction
work done by the frictional force is given as:
F = μMg
Fx = μMxg
Fy = μMyg
W = F.s
Wx = μMxg.s
Wy = μMyg.s
Wx > Wy
The amount of work done by friction in stopping the car is given as
Wx > Wy.
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An aluminum tube of 3-in. Outside diameter is to carry a load P of 10 kips having an eccentricity e = 0. 6 in. Knowing that the stock of tubes available for use are made of aluminum alloy 2014-T6 and have wall thicknesses in increments of 116 in. Up to 12 in. , determine the lightest tube that can be used. Use the interaction method of design with an allowable stress in bending of 25 ksi. (Input the final answer as a fraction. )
The Method of Interaction It's a cooperative method for more effective teamwork.
Explain about the Interaction Method?
A combination of hardware and software components that enables computer users to carry out a single job is known as an interaction technique, user interface technique, or input technique.
Four fundamental interaction tasks exist: position, text, select, and quantify. These can be carried out using a variety of hardware and software tools, each of which has been given a category based on its capabilities and qualities.
An interaction occurs when two or more factors have an impact on one another. If one investigates each of their effects independently, they may not have as strong an impact on a result as they might if they occur simultaneously and interact. Caffeine and painkillers are an example of such interaction.
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a block of mass 0.260 kg is placed on top of a light, vertical spring of force constant 5 025 n/m and pushed downward so that the spring is compressed by 0.106 m. after the block is released from rest, it travels upward and then leaves the spring. to what maximum height above the point of release does it rise? (round your answer to two decimal places.)
A block of mass 0.260 kg is placed on top of a light, vertical spring of force constant 5 025 n/m and pushed downward. After the block is released, the spring will travel upward to the maximum height of 10.86 meters.
The relation between the potential energy on a string and the length it stretches is given by:
E = 1/2 . kx²
Where:
k = spring constant
x = spring stretch or compression
In the given problem:
k = 5,025 N/m
x = 0.106 m
Hence,
E = 1/2 . 5025 . (0.106)²
m . g . h = 1/2 . 5025 . (0.106)²
Where;
m = mass
h = height from the release point.
Hence,
0.260 x 10 x h = 28.23
h = 10.86 m
Therefore, the spring will travel upwards up to 10.86 m
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a proton moves in the direction shown in a uni- form magnetic field. at this instant, which arrow points in the direc- tion of the force on the proton by the magnetic field?
When the proton starts to move upward the direction of the magnetic force changes and when the proton moves straight up the magnetic force turns to the left.
The direction of the force is perpendicular to the direction of the magnetic field and current, as given by Fleming's left-hand rule. Here the magnetic field is to the right and the direction of the current is upward. Protons feel a force on themselves due to the magnetic field. The force on the proton is proportional to the proton's magnetic flux density and velocity.
The velocity and momentum of a proton are affected by the force acting on it. If the velocity of a charged particle is perfectly parallel to the magnetic field, the magnetic field exerts no force on the particle, so the velocity remains constant. The momentum of a proton moving freely in a magnetic field is the product of the proton's mass and the proton's velocity. As the speed of a proton moving in a magnetic field changes, so does the momentum of the proton.
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a longitudinal wave is observed. Exactly 6 crests are observed to move past a given point in 9.1 s. Its wavelength is 2.4 m and its frequency is 0.66 HZ. What is the speed of the wave.
The speed of the longitudinal wave is given or computed as 1.584 or approximately 1.6m/s.
What is a wave?A wave is a propagating dynamic disturbance of one or more variables in physics, mathematics, and related sciences. Periodic waves occur when values oscillate repeatedly about an equilibrium value at a certain frequency.
Longitudinal waves are those in which the medium's vibration is parallel to the wave's travel direction and the medium's displacement is parallel to the wave's propagation direction.
A longitudinal wave is an example of one. P-waves of ultrasonography from earthquakes
Compression, rarefaction, wavelength, amplitude, period, and frequency are all important characteristics of a longitudinal wave.
To estimate the above answer multiply wavelength and frequency to get the speed of a wave.
That is:
2.4 x 0.66
= 1.584
If the frequency is not given, one can divide 6 crests by 9.1 seconds to determine the frequency.
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va car with a mass of 950-kg and a speed of 22 m/s approaches the intersection from the west. a 1300-kg minivan traveling 15 m/s approached the intersection from the south. after the collision two cars move together. what is their speed and direction of the velocity?
The final speed of the car and minivan is 17.95 m/s
The mass of the car = 950 kg
The speed of the car = 22 m/s
The mass of the minivan = 1300 kg
The speed of the minivan = 15 m/s
The final speed of the car and minivan can be found using the conservation of momentum formula,
[tex]\displaystyle m_{1}v_{i1 } + m_{2}v_{i2} = m_{1}v_{f1} + m_{2}v_{f2}[/tex]
where [tex]\dispplaystyle m_{1}[/tex] is the mass of the car
[tex]\dispplaystyle m_{2}[/tex] is the mass of the minivan
[tex]\dispplaystyle v_{i1}[/tex] and [tex]\dispplaystyle v_{i2}[/tex] is the initial speed of the car and minivan respectively.
[tex]\dispplaystyle v_{f1}[/tex] and [tex]\dispplaystyle v_{f2}[/tex] is the final speed of the car and minivan respectively.
As the two cars move together, they would have the same final speed, i.e.
[tex]\dispplaystyle v_{f1} = \dispplaystyle v_{f2} = \dispplaystyle v_{f}[/tex]
Thus, the above equation becomes,
[tex]\displaystyle m_{1}v_{i1 } + m_{2}v_{i2} = (m_{1} + m_{2})v_{f}[/tex]
Let us substitute the known values in the above equation, we get
(950 x 22) + (1300 x 15) = (950 + 1300) [tex]\displaystyle v_{f}[/tex]
20,900 + 19.500 = 2,250 [tex]\displaystyle v_{f}[/tex]
40,400 = 2,250[tex]\displaystyle v_{f}[/tex]
40,400 / 2,250 = [tex]\displaystyle v_{f}[/tex]
= 17.95 m/s
Therefore, the final speed is 17.95 m/s
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50 POINTS!
Write a paragraph that answers the questions below:
If there is a situation that would require a person to use self defense, what offensive strategies would you recommend they use?
What defensive strategies would you recommend they use?
Based on the videos, which move(s) look most effective for offense if there is a situation that would need self defense?
Based on the videos, which move(s) look most effective for defense if there is a situation that would need self defense?
If a person is forced to utilize self-defense, the offensive techniques that should be recommended are as follows:
Take the initiative.I would advise them to employ the following defense strategies:
Keeping your head safeKeeping your elbow between you and the evil person.Based on the films, the move(s) that appear to be the most successful for the offense in a circumstance requiring self-defense are to target the problem rather than the person.
What is an offensive strategy?An aggressive competitive strategy is a form of company strategy that involves actively pursuing industry changes.
Companies that go on the offensive typically make acquisitions and invest extensively in R&D and technology in order to remain ahead of the competition.
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a 10-kg object is on a table, the coefficient of static and kinetic friction between the object and the table is 0.4 and 0.2, respectively. calculate the frictional force applied on the object if a horizontal force of 50n is applied on the object? (free-fall acceleration g
The frictional force applied on the object if a horizontal force of 50N is applied on the object is 19.6 N
N = m g
N = Normal force
m = Mass
g = Acceleration dur to gravity
m = 10 kg
g = 9.8 m / s²
N = 10 * 9.8
N = 98 N
f = μ N
f = Frictional force
μ = Co-efficient of friction
For static friction,
μ = 0.4
f = 0.4 * 98
f = 39.2 N
For kinetic friction,
μ = 0.2
f = 0.2 * 98
f = 19.6 N
Since Applied force of 50 N is greater than the static frictional force of 39.2 N, the frictional force acting on the object is frictional force.
Therefore, the frictional force applied on the object is 19.6 N
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what is the approximate mass of the most massive stars left on the main sequence of this star cluster?
The approximate mass of a star cluster whose most massive stars left on main-sequence star is RMC 136a1 with the estimated mass of RMC 136a1 is 315 solar masses, a solar mass is equal to the mass of the sun. In general, it takes a very long time for stars to form.
It is also assumed that the stars in the cluster are homogeneous or have properties similar to each other. The amount of time a star stays in a staging or sequencing stage is determined by its mass.
A star cluster is one of two different forms of stellar assemblages that are bound together by the gravitational attraction of their individual members, who are linked together physically by a shared origin.
Therefore, a study of the system by the Hubble Space Telescope found that the cluster is made up of over 200 extremely bright stars. The biggest one was called RMC 136a1. The estimated mass of R136a1 is 315 solar masses, where 1 solar mass equals the solar mass
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Subduction zones are associated with
Group of answer choices below
A. divergent boundaries.
B. transform boundaries.
C. convergent boundaries.
D. none of these
Subduction zones are associated with convergent boundaries.
option C is the correct answer.
What is subduction zone?
Subduction zones are plate tectonic boundaries where two plates converge or meet together, and one plate is pushed below the other plate due to underlying forces.
The following are characteristics of subduction zones;
In a subduction zone, at least one of the converging plates must be cold and dense. The more dense plate is usually the older oceanic plate.One plate must bend and move beneath the other plate. That is one plate must be on top while the other plate must be below.Convection currents, or cycling, in the mantle, must be moving downwards, pulling on the denser plate.Subduction zones is usually associated with some geo-hazards, such as;
earthquakes and volcanoesThus, we can conclude that the main feature or characteristics of subduction zones is convergent boundaries resulting from the convergent plates.
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a 5.0- kg box is pulled by a horizontal force f applied to the top of the box. when the box meets a low doorstep, it begins to rotate around it. the box is 60 cm wide and 100 cm high. what minimum magnitude of the force f is needed to cause this movement?
The minimum magnitude of the force f is 21 N needed to cause the movement of a 5 kg box pulled by a horizontal force.
What is force and how is the magnitude of force comes out to be 21 N ?Force is the newtonian quantity which represents the product of mass and acceleration.The mass of the box is given to be 5 kg and the box is 60 cm wide and the height is 100 cm .When the block about to rotate normal shifted to the edge of the cube , mg(w/2) = Fh, F = mgx (w/2)= Fh taking g as 9.8 m/s^2.Substituting the values , F = (5 × 9.8 ( 60/2)) / 70Then the force would be , F = (5 × 9.8 × 30 ) / 70,F = 1470 / 70,F = 21 N.Hence the magnitude of the force comes out to be 21 N.Therefore when a 5 kg box is pulled by a horizontal force f applied to the top of the box, the minimum magnitude of the force f needed is 21N.To know more about force visit:
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how can an object be accelerating while maintaining a constant speed? what force or forces can cause this type of acceleration and how exactly must they be oriented relative to the motion of the object?
Even if an object's speed is constant, it can nonetheless accelerate if its direction changes.
Newton postulated that an object will only accelerate in the presence of a net or unbalanced force.
How can an object accelerate while maintaining a constant speed?An object's velocity (speed and direction) changes at a certain rate, which is called acceleration. As a result, even if an object's speed remains constant, its direction may shift, causing it to accelerate. But the acceleration of an object will be 0 if its velocity is constant.
According to Newton, an item will only accelerate if another force is operating on it that is net or imbalanced. If an imbalanced force is present, the object will accelerate and change its direction and speed, or both.
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a refrigerator delivers 81 j of energy into the kitchen during a typical period of operation. if the coefficient of performance is 11, calculate the energy extracted from inside the refrigerator during the same time period.
The energy extracted from inside the refrigerator during the same time period is 74.25 J.
Energy is the quantitative belongings this is transferred to a frame or to a physical device, recognizable within the overall performance of labor and in the form of warmth and mild. energy is a conserved amount, the law of conservation of electricity states that electricity may be transformed in shape, however no longer created or destroyed.
Calculated:-
The heat is delivered to the kitchen by the refrigerator = 81 j
The coefficient of performance of the refrigerator = 11
The heat extracted from inside the refrigerator = ?
The work done by the external agent to remove the heat = W = Qc/c
The heat delivered to the kitchen Qh = Qc + W
Qh = Qc + Qc/c
The heat extracted from inside the refrigerator is Qc = QCH/c+1
= 11 × 81 /11 +1
= 74.25 J
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What is the velocity of a 1.2 kg ball rolling with a momentum of 15.6 kg m/s?
Answer:
Velocity V = 13 m/s
Explanation:
Given:
m = 1.2 kg
p = 15.6 kg·m/s
__________
V - ?
Momentum:
p = m·V
Velocity:
V =p /m = 15.6 / 1.2 ≈ 13 m/s
fiona is trying to describe the location of some of the brightest set of stars in the northern sky, betelgeuse and rigel, to a friend. what could she have her friend look for to help find the stars?
What Fiona did, so her friend could find the stars was to give her friends knowledge about the contents of the sky, such as the shape of planets and stars. Then when you want to see the stars, you have to stay away from light pollution, so the stars can be seen clearly.
Stars are celestial bodies that emit light caused by nuclear fusion reactions that produce energy that occurs in their cores. It should be noted that 'pseudo stars' are not stars, but planets that reflect light from other stars and appear to glow in the sky like a star. A planet or planetary star is an astronomical body orbiting a star or stellar remnant that is massive enough to have its own gravity.
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the motor of a ski boat generates an average power of when the boat is moving at a constant speed of 12 . when the boat is pulling a skier at the same speed, the engine must generate an average power of . what is the tension in the tow rope that is pulling the skier?
The tension in the tow rope that is pulling the skier is 5283.33 N
since we are given the average power of 2.74 × 10^4 W., with a speed of 12 m/s. So, the tension acting on the motor at this point is :
P= T X v
T = P/v =2.74 × 10^4/ 12 =2283.33 N
For the second case, the average power is 9.20 × 10^4 W, so the tension will be :T = P/v = 9.20 × 10^4 /12 = 7666.66
so the tension in the tow rope is : 7666.66 -2283.33 = 5283.33 N
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the motor of a ski boat generates an average power of 2.74 × 10^4 W when the boat is moving at a constant speed of 12 m/s . when the boat is pulling a skier at the same speed, the engine must generate an average power of 9.20 × 10^4 W. what is the tension in the tow rope that is pulling the skier?
7) Your Grandma is following behind you on the trip to Dallas, but she refuses to drive
faster than 60 miles per hour. If she drives at that speed for the entire trip, how much
later will she arrive in Dallas
Answer:
Grandma will arive [tex]\frac{1}{2}[/tex]hr later
Explanation:
[tex]s=20\\d=210 mi|\\ s=70 mi|h \\ \\ \frac{60}{1} =\frac{210}{+} = 3.5 hrs[/tex]
Heyyyy...Please i need helppp
anticlockwise = clockwise (Force*distance)
1 * 20 = 2 * x
x = 10
The weight of the builder and new roof tiles is 640 N. The slope is at 30 degrees on the given diagram.
Draw a diagram to calculate the components of the total weight
parallel and perpendicular to the slope of the roof.
The parallel component of the total weight is 320 N.
The perpendicular component of the total weight is 554.3 N.
What is the components of the total weight?
The components of the total weight of the builder and new roof tiles can be parallel component or perpendicular component.
The parallel component of the total weight of the builder and new roof tiles is calculated as follows;
Fn ( parallel ) = W sin ( θ )
where;
W is the total weight of the builder and the new roof tileθ is the slope or angle of inclination of the total weightFn ( parallel ) = W sin ( θ )
Fn ( parallel ) = 640 sin ( 30 )
Fn ( parallel ) = 320 N
The perpendicular component of the total weight of the builder and new roof tiles is calculated as follows;
Fn ( parallel ) = W cos ( θ )
where;
W is the total weight of the builder and the new roof tileθ is the slope or angle of inclination of the total weightFn ( perpendicular ) = W cos ( θ )
Fn ( perpendicular ) = 640 cos ( 30 )
Fn ( perpendicular ) = 554.3 N
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spherical sound waves are emitted from a 0.80-w source. assuming that the energy of the waves is conserved, what is the intensity at 0.40 m from the source?
The intensity of the sound at a distance of 0.40 m from the source is 0,398 W/m²
Sound wavesSound waves are classified as a longitudinal wave where the direction of propagation is parallel to the direction of vibration.
Sound intensity is formulated as follows:
I = P / A
I = Sound Intensity (W/m²)
P = Power of the Sound Source (W)
A = Area of the field through which the sound wave passes (m²)
Since the sound wave propagates in all directions, the area of the field traversed by this sound wave will form the surface area of the sphere, then:
I = P / (4πR²)
R = Surface radius (m)
So, The intensity of the sound at a distance of 0.40 m from the source is:
I = P / A
I = P / ( 4π . R² )
I = 0,80 / ( 4π . (0,4)²)
I = 0,398 W/m²
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what is the relationship between gauge pressure and true pressure? what is the relationship between gauge pressure and true pressure? gauge pressure is larger than true pressure. gauge pressure is smaller than true pressure.
The relationship between gauge pressure and true pressure is Pg + Patm = Pabs
The pressure that is relative to atmospheric pressure is known as gauge pressure. Gauge pressure is regarded to be positive for pressures above atmospheric pressure and stated to be negative for pressures below atmospheric pressure. Atmospheric pressure is used as the reference point for gauge pressure.
It is possible to define gauge pressure as the difference between absolute pressure and atmospheric pressure.
Pg + Patm = Pabs
A pressure gauge is a device used to measure the pressure exerted by a fluid, which can be liquid or gas, per unit area. This pressure is expressed in terms of Newton per square meter or pounds per square inch. Absolute pressure is denoted as Pabs, atmospheric pressure as Patm, and gauge pressure as Pg.
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