B=(2x+3)(4x^2-6x+9)-2(4^3-1)

Answer:

3x+2=2190

3x=2190-2

3x=2188

x=2188÷3

x=729

Answer:

(C) reflection of f(x) = 5x² across the x-axis and translated down 2 units

The height of the rectangular cereal box is 40 cm.

Volume of a rectangular prism = lwh

where

Therefore,

10000 = 25 × 10 × h

10000 = 250h

h = 10000 / 250

h = 40 cm

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The graph of the circle equation is graph (d)

The equation is given as:

x^2 + y^2 - 4x + 9y -7 = 0

Rewrite as:

x^2 - 4x + y^2 + 9y = 7

Express (x^2 - 4x) and (y^2 + 9y) as perfect squares.

So, we have:

(x - 2)^2 + (y + 3)^2 = 7 + 4 +  20.25

Evaluate the sum

(x - 2)^2 + (y + 3)^2 = 31.25

A circle equation is represented as:

(x - h)^2 + (y - k)^2 = r^2

Where

Center = (h, k)

Radius = r

So, we have:

(h, k) = (2, -3)

r^2 = 31.25

r = 5.5

The circle that has a center of (2, -3) and a radius of 5.5 is graph d

Hence, the graph of the circle equation is graph (d)

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Answer: 1

Step-by-step explanation: Any number raised to zero is always 1.

The formula for the velocity, v is √2E/m

Kinetic energy is half the mass multiplied by the square of the speed of the object

It is written thus;

Kinetic energy = 1/ 2 × m × v²

To solve for 'v' mean that we should make 'v' the subject of formula

E = 1/ 2 mv²

E = [tex]\frac{mv^2}{2}[/tex]

cross multiply

[tex]2E = mv^2[/tex]

To make 'v' the subject, we have

[tex]v = \sqrt{\frac{2E}{m} }[/tex]

Thus, the formula for the velocity, v is √2E/m

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Answer:

I think glide reflection

Step-by-step explanation:

a certain video on yt had explained the examples of similar look alike this picture

The approximate length of side AB is 14.0. The correct option is B. 14.0 units

From the question, we are to determine the measure of side AB

First, we will determine the measure of angle A

A + B + C = 180° (Sum of angles in a triangle)

A + 65° + 35° = 180°

A = 180° - 65° - 35°

A = 80°

Now, using the law of sines

c/sinC = a/sinA

c = AB

a = BC =  24

Thus,

c/sin35° = 24/sin80°

c = (24×sin35°)/sin80°

c = 13.978

c ≈ 14.0

∴ AB = 14.0

Hence, the approximate length of side AB is 14.0. The correct option is B. 14.0 units

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Answer:

1

Step-by-step explanation:

When dividing fractions i use the method KFC(keep flip change) :

Keep the first fraction :

[tex]\frac{14a^{2} }{10b^{2} }[/tex]

Flip the second fraction :

[tex]\frac{15b^{2} }{21a^{2} }[/tex]

Change the function :

÷ → ×

Now write your new equation :

[tex]\frac{14a^{2} }{10b^{2} }[/tex] ×  [tex]\frac{15b^{2} }{21a^{2} }[/tex]

Now multiply the numerators together and the denominators together :

14a² × 15b²  = 210a²b²

10b² × 21a² = 210a²b²

Now make this into a fraction again :

210a²b² / 210a²b²

Anything divided by itself is always 1 so :

210a²b² / 210a²b² = 1

Hope this helped and have a good day

Answer: 24

Step-by-step explanation:

1. Number Them

Elf and Dwarf = 1

Hobbit = 2

Wizard = 3

Man = 4

* Elf and Dwarf are put together so that they are always sitting together

2. Multiply

1 x 2 x 3 x 4 = 24

Answer:

The answer would be 36cm².

Step-by-step explanation:

⇒ Two prisms are similar.

⇒ Scale factor = 3:8

⇒ The ratio of the surface area is 9:64.

⇒ So S₁ : S₂ = 9:64

⇒ S₁ : 256 = 9:64

⇒ S₁ = 36cm²

This would mean that the answer is 36 centimeters ² (squared).

Answer: reflection across x axis and y axis?

Step-by-step explanation: repost question with the possible answers!

If the function is

[tex]y = 4 e^x \cos(3x)[/tex]

then we have derivatives

[tex]Dy = 4 e^x \cos(3x) - 12 e^x \sin(3x)[/tex]

[tex]D^2y = -32 e^x \cos(3x) - 24 e^x \sin(3x)[/tex]

Now consider the linear ODE

[tex]aD^2y + bDy + cy = 0[/tex]

Substituting [tex]y[/tex] and its derivatives reduces the equation to

[tex](-32a + 4b + 4c) \cos(3x) + (-24a - 12b) \sin(3x) = 0[/tex]

Now,

[tex]-24a - 12b = 0 \implies b = -2a[/tex]

[tex]-32a + 4b + 4c = 0 \implies c = 10a[/tex]

Then the minimal ODE with the given solution is

[tex]aD^2y -2a Dy + 10ay = 0[/tex]

or

[tex]\boxed{D^2y  -2 Dy + 10y = 0}[/tex]

Answer:

Arithmetic

Step-by-step explanation:

Arithmetic Sequence is a sequence that has common difference - a common difference is same difference in a sequence. If we take next term to subtract the previous term and you keep getting same difference or value then that's a common difference. It can be mathematically expressed as an equation of:

[tex]\displaystyle{d=a_{n+1}-a_n}[/tex]

Now, I'll show why the sequence is arithmetic - take the sequence to subtract for common difference:

Notice how we keep getting -16 after subtracting previous term with next term. Hence this sequence is arithmetic sequence for sure!

Geometric Sequence is a sequence with common ratio - a common ratio is similar to common difference except ratio is all about division. Since common difference is expressed as subtraction of next term and previous term then common ratio is division of next term and previous term which can be mathematically expressed as:

[tex]\displaystyle{r = \dfrac{a_{n+1}}{a_n}}[/tex]

However this sequence is not geometric sequence because if you divide next term with previous term then you'll keep getting difference result and common ratio means having same ratio or constant ratio for entire sequence.

Now see why this sequence cannot be geometric sequence:

Notice that none of values are equal and thus, this sequence doesn't have common ratio which leads to not being geometric sequence.

Answer:

[tex]2 \tan (6x)+2 \sec (6x)+\text{C}[/tex]

Step-by-step explanation:

Fundamental Theorem of Calculus

[tex]\displaystyle \int \text{f}(x)\:\text{d}x=\text{F}(x)+\text{C} \iff \text{f}(x)=\dfrac{\text{d}}{\text{d}x}(\text{F}(x))[/tex]

If differentiating takes you from one function to another, then integrating the second function will take you back to the first with a constant of integration.

Given indefinite integral:

[tex]\displaystyle \int \dfrac{12}{1-\sin (6x)}\:\:\text{d}x[/tex]

[tex]\boxed{\begin{minipage}{5 cm}\underline{Terms multiplied by constants}\\\\$\displaystyle \int a\:\text{f}(x)\:\text{d}x=a \int \text{f}(x) \:\text{d}x$\end{minipage}}[/tex]

If the terms are multiplied by constants, take them outside the integral:

[tex]\implies 12\displaystyle \int \dfrac{1}{1-\sin (6x)}\:\:\text{d}x[/tex]

Multiply by the conjugate of 1 - sin(6x) :

[tex]\implies 12\displaystyle \int \dfrac{1}{1-\sin (6x)} \cdot \dfrac{1+\sin(6x)}{1+\sin(6x)}\:\:\text{d}x[/tex]

[tex]\implies 12\displaystyle \int \dfrac{1+\sin(6x)}{1-\sin^2(6x)} \:\:\text{d}x[/tex]

[tex]\textsf{Use the identity} \quad \sin^2 x+ \cos^2 x=1:[/tex]

[tex]\implies \sin^2 (6x) + \cos^2 (6x)=1[/tex]

[tex]\implies \cos^2 (6x)=1- \sin^2 (6x)[/tex]

[tex]\implies 12\displaystyle \int \dfrac{1+\sin(6x)}{\cos^2(6x)} \:\:\text{d}x[/tex]

Expand:

[tex]\implies 12\displaystyle \int \dfrac{1}{\cos^2(6x)}+\dfrac{\sin(6x)}{\cos^2(6x)} \:\:\text{d}x[/tex]

[tex]\textsf{Use the identities }\:\: \sec \theta=\dfrac{1}{\cos \theta} \textsf{ and } \tan\theta=\dfrac{\sin \theta}{\cos \theta}:[/tex]

[tex]\implies 12\displaystyle \int \sec^2(6x)+\dfrac{\tan(6x)}{\cos(6x)} \:\:\text{d}x[/tex]

[tex]\implies 12\displaystyle \int \sec^2(6x)+\tan(6x)\sec(6x) \:\:\text{d}x[/tex]

[tex]\boxed{\begin{minipage}{5 cm}\underline{Integrating $\sec^2 kx$}\\\\$\displaystyle \int \sec^2 kx\:\text{d}x=\dfrac{1}{k} \tan kx\:\:(+\text{C})$\end{minipage}}[/tex]

[tex]\boxed{\begin{minipage}{6 cm}\underline{Integrating $ \sec kx \tan kx$}\\\\$\displaystyle \int \sec kx \tan kx\:\text{d}x= \dfrac{1}{k}\sec kx\:\:(+\text{C})$\end{minipage}}[/tex]

[tex]\implies 12 \left[\dfrac{1}{6} \tan (6x)+\dfrac{1}{6} \sec (6x) \right]+\text{C}[/tex]

Simplify:

[tex]\implies \dfrac{12}{6} \tan (6x)+\dfrac{12}{6} \sec (6x)+\text{C}[/tex]

[tex]\implies 2 \tan (6x)+2 \sec (6x)+\text{C}[/tex]

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Substitute [tex]y=6x[/tex] and [tex]dy=6\,dx[/tex] to transform the integral to

[tex]\displaystyle \int \frac{12}{1-\sin(6x)} \, dx = 2 \int \frac{dy}{1 - \sin(y)}[/tex]

Now substitute [tex]t=\tan\left(\frac y2\right)[/tex] and [tex]dt=\frac12 \sec^2\left(\frac y2\right) \, dy[/tex] to transform this to

[tex]\displaystyle 2 \int \frac{dy}{1 - \sin(y)} = 2 \int \frac1{1-\frac{2t}{1+t^2}}\cdot\frac{2\,dt}{1+t^2} = 4 \int \frac{dt}{(t-1)^2}[/tex]

Finally, substitute [tex]s = t-1[/tex] and [tex]ds=dt[/tex] to get

[tex]\displaystyle 4 \int \frac{dt}{(t-1)^2} = 4 \int \frac{ds}{s^2} = -\dfrac4s + C[/tex]

Now recover the antiderivative in terms of [tex]x[/tex].

[tex]\displaystyle \int \frac{12}{1-\sin(6x)} \, dx = -\frac4s + C \\\\ ~~~~~~~~ = -\frac4{t-1} + C \\\\ ~~~~~~~~ = -\frac4{\tan\left(\frac y2\right) - 1} + C \\\\ ~~~~~~~~ = \boxed{-\frac4{\tan(3x) - 1} + C}[/tex]

Answer:

482.84u², 42.5cm², 51.5ft²

Step-by-step explanation:

1) A = 2(1 + √2)a²

A = 2(1 + √2)(80 / 8)²

A = 482.84units²

2) Square = 5²

Square = 25

T1 = 3 x 5 / 2

T1 = 7.5

T2 = 4 x 5 / 2

T2 = 10

Total = 10 + 7.5 + 25

Total = 42.5cm²

3) Rect = 4(8 + 3)

Rect = 44

T1 = 2 x 3 / 2

T1 = 3

T2 = 3 x 3 / 2

T2 = 4.5

Total = 3 + 4.5 + 44

Total = 51.5ft²

The value is 52. 674

We have;

4(3) / 4(8) +.9(7.8 x 7.45)

From BODMAS, we have that we must must open up the bracket

= [tex]\frac{12}{32} + 0. 9 (58. 11)[/tex]

Divide the fraction to get decimals

= [tex]0. 375 + 52. 299[/tex]

Add the decimals

= [tex]52. 674[/tex]

Thus, the value is 52. 674

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If the sample size of population is 24 then the number of degrees of freedom for reading the t  value is 23 which is option c.

Given sample size of 24,mean 23.

We have to determine the number of degrees of freedom which will be used to find the critical values of t.

Degree of freedom is the number of values in the final calculation of a statistic that are free to vary means that can change their values in the formula of calculating t.

t=(X-μ)/s/[tex]\sqrt{n}[/tex]

where X is sample mean ,

μ is hypothsised population mean

s is sample standard deviation

n is sample size.

Degree of freedom=n-1

In this question n is 24 so the degree of freedom =24-1=23.

Hence the number of degrees of freedom for reading the t value is 23.

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New mean is 2.53% larger than the original mean.

What is mean?

Mean is nothing but the average of the given set of values. It denotes the equal distribution of values for a given data set.

We can find the percentage larger is the mean of the new list in comparison with the original as shown below:

Given, set of number 55, 70, 81, 83, 88, 91

Median= (81+83)/2

= 164/2

= 82

Mean = (55+70+81+83+88+91)/6

= 468/6

= 78

New value which is added = 82*1.12

= 91.84

New Mean = (55+70+81+83+88+91+91.84)/7

= 559.84/7

= 79.97

Increase in mean = 79.97-78

=1.97

increase percentage (1.97/78) *100

= 2.53%

Hence, new mean is 2.53% larger than the original mean.

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Company's average operating assets for last year is $193000, company's margin is 15%, return on investment is 42%, company's residual income for last year is $521000.

Given the balance sheet and income statement of Joel de Paris and we have to calculate company's average operating assets for last year, company's margin,return on investment and company's residual income for last year.

1) Company's average operating assets=

(beginning operating assets+closing operating assets)/2

={(2562000-349000-253000)+(2634000-434000-25000)}/2

=(1910000+1950000)/2

=3860000/2

=$1930000

2)Company's margin= net operating income/ sales

=810000/540400

=15%

3)Turnover=sales/average inventory

=540400/1930000*100

=27.9%

=28%

4) Return on investment=margin* turnover

=15% of 28%

=42%.

Hence company's average operating assets for last year is $193000, company's margin is 15%, return on investment is 42%, company's residual income for last year is $521000.

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The question is incomplete and the information of question is in figure.

Use the rules of exponents to simplify the expression.

[tex]\large\displaystyle\text{$\begin{gathered}\sf (C^{4})^{3} \end{gathered}$}[/tex]

To raise a power to another power, multiply the exponents.

[tex]\large\displaystyle\text{$\begin{gathered}\sf C^{4\times3} \ \to \ Multiply \end{gathered}$}[/tex]

[tex]\boxed{\large\displaystyle\text{$\begin{gathered}\sf C^{12} \end{gathered}$}}[/tex]

Therefore, the correct option is "C".

The relationship between the natural variation and specifications is quantified by a measure known as the Process capability index.

According to the questions,

The relationship between the natural variation and specifications is quantified by a measure known as the Process capability index.

Process capability index refers to the capability of a process to deliver output which lies within the specifications limits that are desired.

Hence, the relationship between the natural variation and specifications is quantified by a measure known as the Process capability index.

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The angle m∠MLP in the rhombus is 56 degrees.

A rhombus has all its sides equal to each other.  The diagonals of a rhombus are angle bisectors.

Therefore,

m∠MLP = m∠MLO / 2

m∠MLO = 112°

m∠MLP = 112 / 2

Therefore,

m∠MLP = 56 degrees.

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Answer:

B. 56

Step-by-step explanation:

trust

Answer:

15

Step-by-step explanation:

First side is 20

Second side is 20 * (3/2), as it is 1 and 1 half times longer than the first

Second side is 30(as calculated above)

65-20-30 = 15

The explanation regarding the vector is illustrated below.

It should be noted that vector A with components a, b, c, can be written as (a, b, c) or in terms of unit vectors as ai + bj + ck.

In this case, the letters I, j, and k are the standard symbols for the unit vectors in the x, y, and z directions.

Therefore, if A = (3,4,5( you can write A = 3i + 4j + 5k.

If B = (1, 1, 1), you can write B = I + j + k.

Then A - B is the vector whose component are the difference in each components.

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Using the mean concept, the average collection for a student in this school was of $16.13.

The mean of a data-set is given by the sum of all observations in the data-set divided by the number of observations.

The number of students is given as follows:

82 + 74 + 96 + 99 = 351.

The sum is:

82 x 26.75 + 74 x 12.25 + 96 x 15.50 + 99 x 10.85 = $5662.15

Hence the mean is:

M = $5662.15/351 = $16.13.

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Answer: [tex]y+5=-2(x+4)[/tex]

Step-by-step explanation:

See attached image.

The area of the polygon is 4 square units

The vertices are given as:

(1, 2), (3, 2), (3, 0), and (1, 0)

The area is then calculated as:

A = 0.5 * |x1y2 - x2y1 +x2y3 - x3y2 + ....... |

So, we have:

A = 0.5 * |1 * 2 - 3 * 2 + 3 * 0 - 2 * 3 + 3 * 0 - 0 * 1 + 1 * 2 - 0 * 1|

Evaluate

A = 0.5 * |-8|

Remove the absolute bracket

A = 0.5 * 8

This gives

A = 4

Hence, the area of the polygon is 4 square units

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The best object-oriented program design for this car dealership's software program is to use a single class Car, with three instance variables (fields):

A class can be defined as a user-defined blueprint (prototype) or template that is typically used by software programmers to create objects and define the data types, categories, and methods that should be associated with these objects.

In object-oriented programming (OOP) language, a class that is written or created to implement an interface in a software would most likely implement all of that interface's method declarations without any coding error.

In this scenario, the best object-oriented program design for this car dealership's software program is to use a single class Car, with three instance variables (fields):

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Complete Question:

A car dealership needs a program to store information about the cars for sale. For each car, they want to keep track of the following information: number of doors (2 or 4), whether the car has air conditioning, and its average number of miles per gallon. Which of the following is the best design?

(A) Use four unrelated classes: Car, Doors, AirConditioning, and MilesPerGallon.

(B) Use a class Car with three subclasses: Doors, AirConditioning, and MilesPerGallon.

(C) Use a class Car, with fields: numDoors, hasAir, and milesPerGallon.

(D) Use a class Car, with subclasses of Doors, AirConditioning, and MilesPerGallon.

(E) Use classes: Doors, AirConditioning, and MilesPerGallon, each with a subclass Car.