Which rule describes the composition of transformations that maps δbcd to δb"c"d"? translation of 5 units x, negative 6 units y composition reflection across y = negative x reflection across y = negative x composition translation of 5 units x, negative 6 units y. translation of 6 units x, negative 5 units y composition reflection across the y-axis reflection across the y-axis composition translation of 6 units x, negative 5 units y
The rule which describe the composition of transformations that
maps ΔBCD to ΔB"C"D" is:
Reflection across the y-axis composition translation of 6 units x,
negative 5 units y ⇒ last answer
Step-by-step explanation:
Let us revise the reflection across the y-axis , horizontal translation
and vertical translation
1. If point (x , y) is reflected across the y-axis, then its image is (-x , y)
2. If point (x , y) is translated h units to the right, then its image is
(x + h , y), if translated h units to the left, then its image is (x - h , y)
3. If point (x , y) is translated k units up, then its image is (x , y + k),
if translated k units down, then its image is (x , y - k)
∵ The vertices of triangle BCD are (1 , 4) , (1 , 2) , (5 , 3)
∵ The vertices of triangle B'C'D' are (-1 , 4) , (-1 , 2) , (-5 , 3)
∵ The x-coordinates of the vertices of Δ B'C'D' have the same
magnitude of x-coordinates of Δ BCD and opposite signs
∴ Δ B'C'D' is the image of Δ ABC after reflection across the y-axis
∵ The vertices of triangle B'C'D' are (-1 , 4) , (-1 , 2) , (-5 , 3)
∵ The vertices of triangle B''C''D'' are (5 , -1) , (5 , -3) , (1 , -2)
∵ The image of -1 is 5 and the image of -5 is 1
∴ The x-coordinates of the vertices of triangle B'C'D' are added by 6
∵ The image of 4 is -1 , image of 2 is -3 and the image of 3 is -2
∴ The y-coordinates of the vertices of triangle B'C'D' are subtracted
by 5
∴ Δ B"C"D" is the image of Δ B'C'D' by translate 6 units to the right
and 5 units down ⇒ (x + 6 , y - 5)
The rule which describe the composition of transformations that
maps ΔBCD to ΔB"C"D" is:
Reflection across the y-axis composition translation of 6 units x,
negative 5 units y
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The composition of transformations that maps BCD to B"C"D" is described by the following rule:
Composition translation of 6 units x, negative 5 units y across the y-axis last response
Let us rewrite the y-axis reflection, horizontal translation, and vertical translation.
1. If point (x, y) is mirrored across the y-axis, the image of that point is (-x , y)
2. If point (x, y) is translated h units to the right, its image is (x + h, y), and if it is translated h units to the left, its image is (x + h, y) (x - h , y)
3. If point (x, y) is translated k units up, its image is (x, y + k), but if it is translated k units down, its image is (x , y - k)
∵ Triangle BCD has (1, 4) vertices, (1, 2) vertices, and (5, 3) vertices. Triangle B'C'D' has (-1, 4) vertices, (1, 2) vertices, and (5, 3) vertices. The x-coordinates of the B'C'D' vertices have the same magnitude as the x-coordinates of BCD and opposite signs. B'C'D' is the picture of ABC after it has been reflected across the y-axis.
The vertices of triangle B'C'D' are (-1, 4), (-1, 2), (-5, 3), (1, -2)
The vertices of triangle B"C"D" are (5, -1), (5, -3), (1, -2)
The x-coordinates of the triangle B'C'D' vertices are added by 6.
The image of 4 is -1, the image of 2 is -3, and the image of 3 is -2.
The y-coordinates of triangle B'C'D' vertices are subtracted by 5.
∴ Δ B"C"D" is the image of Δ B'C'D' by translating 6 units to the right
and 5 units down ⇒ (x + 6 , y - 5)
The rule which describe the composition of transformations that
maps ΔBCD to ΔB"C"D" is:
Reflection across the y-axis composition translation of 6 units x,
negative 5 units y
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what is the area for the green square?
Select the correct answer.
A container is made by cutting off the bottom of a cone. The container has a diameter of 30 centimeters and a height of 20 centimeters. The
small cone that was removed has a diameter of 10 centimeters and a height of 6 centimeters.
What is the volume of the container, to the nearest cubic centimeter?
A. 6,126 cm³
B. 6,283 cm³
C. 5,812 cm³
D. 5,969 cm³
The volume of the container is 5969 cm³. The correct option is D. 5,969 cm³
Calculating VolumeFrom the question, we are to determine the volume of the container
Volume of the container = Volume of the cone - Volume of the small cone
The volume of a cone is given by the formula,
V = 1/3πr²h
Where V is the volume
r is the radius
and h is the height
From the given information,
For the small cone,
Diameter = 10 cm
∴ Radius, r = 10cm/ 2 = 5 cm
h = 6 cm
For the big cone
diameter = diameter of the container = 30 cm
∴ Radius = 30cm/ 2
Radius = 15cm
h = height of small cone + height of container
h = 6 cm + 20 cm
h = 26 cm
Putting the parameters into
Volume of the container = Volume of the cone - Volume of the small cone
We get,
Volume of the container = 1/3π × 15² ×26 - 1/3π × 5² × 6
Volume of the container = 1/3π (15² ×26 - 5² × 6)
Volume of the container = 1/3π (5850 - 150)
Volume of the container = 1/3π (5700)
Volume of the container = 1/3 × π × 5700
Volume of the container = 5969.026 cm³
Volume of the container ≈ 5969 cm³
Hence, the volume of the container is 5969 cm³. The correct option is D. 5,969 cm³
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The ratio of girls to boys at a party is 5:4. if there are 20 girls in the class, how many boys are there.
Answer:
16 boys
==========================
Let the number of boys be b and girls be g.
The ratio is:
g/b = 5/4And the number of girls is:
g = 20Substitute the number into ratio and find the value of b:
20/b = 5/4b = 20*4/5b = 16Show your steps in evaluating each of the following expressions. The steps count 4 points each, the answer is 1
The steps in evaluating each of the following expressions is shown below.
What is an expression?An expression is a mathematical equation which shows the relationship that exist between two or more numerical quantities or variables.
How to evaluate the given expressions?15 - 35/7 - 2 + 3 - 4
15 - (35/7) - 2 + 3 - 4 (bracket and division)
15 - 5 - 2 + 3 - 4 (regroup)
15 + 3 - 5 - 2 - 4 (subtract and add)
18 - 11 = 7.
Expression 2.10 + 2(9 - 5) - 16/18
10 + (2 × 4) - 8/9 (bracket and division)
10 + 8 - 8/9 (add)
18 - 8/9 (subtract)
162/9 - 8/9 = 17 1/9 or 154/9.
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Complete Question:
Show your steps in evaluating each of the following expressions. The steps count 4 points each, the answer is 1 point.
A. 15 - 35/7 -2 + 3 -4
B. 10 + 2(9 - 5) - 16/18
PLEASE HELP WILL GIVE BRAINLIEST
Arrange the tiles on both boards to find the value of x.
Board sum: 3x + (-5) = 1
What x value solves the equation?
3x - 5 = 1
X =
Answer: x = 2
Step-by-step explanation:
3x - 5 = 1
add 5 to both sides
3x - 5 (+5) = 1 (+5)
3x = 6
divide by 3 on both sides
3x/3 = 6/3
x = 2
laura goes for a cycle from her house to the post office 4km away work out laura's speed cycling to the post office CORBETTMATHS 2016
ItItItIt takes Laura 15 minutes (0.25 hours) to cycle to the post office.
Speed and timea. It takes Laura 15 minutes (0.25 hours) to cycle to the post office.
b. Speed:
Speed=Distance/Time
Speed=4/0.25
Speed=16 km/hr
c. It takes Laura 20 minutes to cycle to the post office.
d. Time
Time=20 minutes (1/3 hour)
Speed:
Speed=Distance/Time
Speed=4÷1/3
Speed=12 km/hr
Therefore It takes Laura 15 minutes (0.25 hours) to cycle to the post office.
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h(n) = 41 - 5n
Complete the recursive formula of h(n).
h(1) =
h(n) = h(n-1)
The recursive formula of h(n) is h(1) = 36 and h(n) = h(n -1) - 5
How to determine the recursive formula?The function is given as:
h(n) = 41- 5n
Calculate h(1) and h(2)
h(1) = 41- 5(1)
h(1) = 36
h(2) = 41- 5(2)
h(2) = 31
Calculate the difference between h(1) and h(2)
d = 31 - 36
d = -5
This means that:
h(1) = 36 and h(n) = h(n -1) - 5
Hence, the recursive formula of h(n) is h(1) = 36 and h(n) = h(n -1) - 5
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At a coffee shop, the manager recorded the number of customers who visited the store at the end of each hour. The graph shows the recordings for a 24-hour period. The function describing this graph is a transformation of the parent sine function, y=sin(x)
Which value is closest to the amplitude of the transformed function?
O 83 customers
O 27 customers
O 54 customers
O 30 customers
Answer:
Step-by-step explanation:
The amplitude of a sine function is equal to one-half the distance between the maximum and minimum values of the function.
In this case, the maximum value is approximately 84 customers, and the minimum value is approximately 30 customers
Therefore, the value that is closest to the amplitude of the transformed function is 27 customers.
A sequence of transformations maps Triangle ABC onto triangle ABC prime prime. The type of transformations that maps triangle ABC onto Triangle prime ABC is a _____. When Triangle prime ABC is reflected across the line x=2 to form triangle triangle prime prime ABC vertex _____ of triangle ABC will have the same coordinates as B prime.
The type of transformations that maps triangle ABC onto Triangle prime ABC is a Reflection across the line y=x ; translation 10 units to the right and 4 units up.
What is the reflection about?Note that: Triangle ABC has vertices at points which are:
A(-6,2), B(-2,6) and C(-4,2).
Therefore, the reflection across the line y=x has the rule of"
(x, y) ---(y, x).
Hence:
A(-6,2) -- A''(2,-6);
B(-2,6)--- B''(6,-2);
C(-4,2)----C''(2,-4).
2. The translation 10 units to the right and 4 units up is:
(x, y)----(x+10,y+4).
Hence
A''(2,-6)----A'(12,-2);
B''(6,-2)----B'(16,2);
C''(2,-4)----C'(12,0).
Therefore, Points A'B'C' are said to be exactly of the vertices of that of triangle A'B'C'.
Hence, The type of transformations that maps triangle ABC onto Triangle prime ABC is a Reflection across the line y=x ; translation 10 units to the right and 4 units up.
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A super sundae ice cream cone has a radius of 0. 5 in and a depth of 4 in. A wonderful waffle cone has a radius 0. 9 in and a depth of 3 in. Which cone holds more ice cream?
The wonderful waffle cone holds more ice cream than super sundae cone.
In this question,
The ice cream cone is the shape of hemisphere at the top and cone shape at the bottom.
Volume of ice cream cone = volume of hemisphere + volume of cone
Volume of ice cream cone = [tex]\frac{2}{3}\pi r^{3} +\frac{1}{3} \pi r^{2} h[/tex]
Volume of super sundae cone:
Radius of hemisphere = height of hemisphere = 0.5 in
Depth of the ice cream cone = 4 in
Volume of super sundae cone = [tex]\frac{2}{3}\pi (0.5)^{3} +\frac{1}{3} \pi (0.5)^{2} (4)[/tex]
⇒ [tex]\frac{2}{3}(3.14)(0.125) +\frac{1}{3} (3.14)(0.25)(4)[/tex]
⇒ 0.2616+1.0466
⇒ 1.3082 ≈ 1.31 cubic in.
Volume of wonderful waffle cone:
Radius of hemisphere = height of hemisphere = 0.9 in
Depth of the ice cream cone = 3 in
Volume of wonderful waffle cone = [tex]\frac{2}{3}\pi (0.9)^{3} +\frac{1}{3} \pi (0.9)^{2} (3)[/tex]
⇒ [tex]\frac{2}{3}(3.14)(0.729) +\frac{1}{3} (3.14)(0.81)(3)[/tex]
⇒ 1.526+2.5434
⇒ 4.0694 ≈ 4.07 cubic in.
Thus volume of wonderful waffle cone > volume of super sundae cone.
Hence we can conclude that the wonderful waffle cone holds more ice cream than super sundae cone.
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The reference angle for is, which has a terminal point of (2).
What is the terminal point of ?
(-²)
(-4/2, 4/2)
○ B. (2,-²)
(-2/²2,-4/2)
OA
A.
O C.
○ D. (22)
Answer: C
Step-by-step explanation:
[tex]\frac{5\pi}{4}[/tex] is in the third quadrant, so both x and y are negative.
Therefore, the only possible answer is C.
Will give you brilliantest
Oscar bought some markers, notebooks, and packs of sticky notes for his office. He bought the same number of markers as notebooks. He bought three more packs of sticky notes than markers and notebooks combined. He paid $1.05 for each marker, $2.25 for each notebook, and the packs of sticky notes were $1.95. How many of each kind of office supply did Oscar buy if he paid $49.05 in all?
Using a system of equations, it is found that Oscar bought 6 markers, 6 notebooks and 15 packs of sticky notes.
What is a system of equations?A system of equations is when two or more variables are related, and equations are built to find the values of each variable.
In this problem, the variables are:
Variable x: Number of markers.Variable y: Number of notebooks.Variable z: Number of packs of notes.He bought the same number of markers as notebooks, hence:
x = y.
He bought three more packs of sticky notes than markers and notebooks combined, hence:
z = 3 + x + y
z = 3 + 2x.
He paid $1.05 for each marker, $2.25 for each notebook, and the packs of sticky notes were $1.95. He spent $49.05 in total, hence:
1.05x + 2.25y + 1.95z = 49.05.
Then:
1.05x + 2.25x + 1.95(3 + 2x) = 49.05.
7.2x = 43.2
x = 43.2/7.2
x = 6.
The amounts are as follows:
y = 6.z = 3 + 2(6) = 15.He bought 6 markers, 6 notebooks and 15 packs of sticky notes.
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a 10 foot ramp must make an angle of 30° with the ground if it is to reach a certain window. what angle must a 15 foot ramp make with the ground to reach the same window
The 15 foot ramp must make an angle 19.45° with the ground to reach the same window.
What angle must be made with the ground by the 15 foot ramp?Since the height of the window above ground remains constant in both cases, it follows that by means of trigonometric identity sine; we have;
10sin30° = 15sinx
sinx = 5/15 = 0.333
x = sin-¹(0.333)
x = 19.45°.
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The perimeter of a deck is 33 at the length of the deck is 10 feet what is the width of the deck
The width of the deck is 6.5 feet.
The perimeter of a two-dimensional shape is the total length of the outline. To find the perimeter of a rectangle, we add the lengths of all four sides. Since opposite sides of a rectangle are always equal, we need to find the dimensions of length and width to find the perimeter of a rectangle. We can write the perimeter of the rectangle as twice the sum of its length and width. The perimeter is a linear measure and has units as meters, centimeters, inches, feet, etc.
Assuming the deck is rectangle
Perimeter = 2(length + width)
33ft = 2 (10 + width)
16.5 = 10 + width
width = 6.5 ft
Thus the width of the deck is 6.5 feet.
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If 4x² = 16, then x =
A20
B12
C4
D2
Using the equation y = 2x - 3, what would the input need to be for an output of 7?
00
O 11
05
08
?? math-domain and range
Answer:
Domain: All real numbers (infinite) Range: [tex]y \leq -4[/tex]
Step-by-step explanation:
For the domain, the x-axis will continue to be used for the parabola, because the parabola can go on forever and can use an x- value on the x-axis. For the range, the largest number the parabola will go up to is -4. Therefore, if that is the highest point/ where the vertex is, the highest point on the y-axis is -4, resulting in the answer y can be equal to or less than -4 (y [tex]\leq[/tex] -4), since the parabola will continue to go down with the reflection over the x-axis.
The picnic breakfast cost $12. Jasmine left a tip that was 15 percent of the
cost of the meal. How much money was the tip that Jasmine left?
PLEASE ANSWER ASAP
What is the solution to the following system of equations?
Answer:
(-3, 1)
Step-by-step explanation:
the easiest thing to do is look at the graph and find the point where the two lines intersect
Leon verified that the side lengths 21, 28, 35 form a Pythagorean triple using this procedure.
Step 1: Find the greatest common factor of the given lengths: 7
Step 2: Divide the given lengths by the greatest common factor: 3, 4, 5
Step 3: Verify that the lengths found in step 2 form a Pythagorean triple: 3 squared + 4 squared = 9 + 16 = 25 = 5 squared
Leon states that 21, 28, 35 is a Pythagorean triple because the lengths found in step 2 form a Pythagorean triple. Which explains whether or not Leon is correct?
Yes, multiplying every length of a Pythagorean triple by the same whole number results in a Pythagorean triple.
Yes, any set of lengths with a common factor is a Pythagorean triple.
No, the lengths of Pythagorean triples cannot have any common factors.
No, the given side lengths can form a Pythagorean triple even if the lengths found in step 2 do not
Answer:
Yes, multiplying every length of a Pythagorean triple by the same whole number results in a Pythagorean triple.
Step-by-step explanation:
Another example of multiplying a Pythagorean triple is
Take the known Pythagorean triple 5, 12 and 13:
5 12 13 * 2 = 10 24 26
and 26^2 = 10^2 + 24^2
676 = 100 + 576 = 676
Match each system of equations to the inverse of its coefficient matrix, A-1, and the matrix of its solution, X.
The system of equations to the inverse of its coefficient matrix, A⁻¹, and the matrix of its solution, X is shown in the figure.
Given that the system of equations are shown in given figure.
The first system of equations are
[tex]\begin{aligned}4x+2y-z&=150\\x+y-z&=-100\\-3x-y+z&=600\\\end[/tex]
By writing in matrix AX=b, we get
Coefficient matrix [tex]A=\left[\begin{array}{lll}4&2&-1\\1&1&-1\\-3&-1&1\end{array}\right][/tex] and [tex]B=\left[\begin{array}{l}150&-100&600\end{array}\right][/tex]
Firstly, we will find the A⁻¹ by finding the determinant and adjoint of A and divide the adjoint with determinant, we get
[tex]\begin{aligned}|A|&=\left|\begin{array}{lll}4&2&-1\\1&1&-1\\-3&-1&1\end{array}\right|\\ &=4(1-1)-2(1-3)-1(-1+3)\\&=4(0)-2(-2)-1(2)\\ &=2\neq 0\end[/tex]
[tex]\begin{aligned}Adj A&=\left[\begin{array}{lll}0&2&2\\-1&1&-2\\-2&3&2\end{array}\right]^T\\&=\left[\begin{array}{lll}0&-1&-2\\2&1&3\\2&-2&2\end{array}\right]\end[/tex]
[tex]\begin{aligned}A^{-1}&=\frac{Adj A}{|A|}\\ &=\left[\begin{array}{lll}0&-0.5&-0.5\\1&0.5&1.5\\1&-1&1\end{array}\right]\end[/tex]
For a solution Consider [A B] and apply row operations, we get
[tex]\begin{aligned}\left[A\right.\text{ }\left.B\right]&=\left[\begin{array}{lll1}4&2&-1&150\\1&1&-1&-100\\-3&-1&1&600\end{array}\right]\\ R_{2}&\rightarrow 4R_{2}-R_{1},R_{3}\rightarrow 4R_{3}+3R_{1}\\ &\sim \left[\begin{array}{lll1}4&2&-1&150\\0&2&-3&-550\\0&2&1&2850\end{array}\right]\\ R_{3}&\rightarrow R_{3}-R_{2}\\ &\sim \left[\begin{array}{llll}4&2&-1&150\\0&2&-3&-550\\0&0&4&3400\end{array}\right]\end[/tex]
Thus, [tex]x=\left[\begin{array}{l}x\\y\\z\end{array}\right]=\left[\begin{array}{l}-250\\1000\\850\end{array}\right][/tex]
The second system of equations are
[tex]\begin{aligned}x+y-z&=220\\5x-5y-z&=-640\\-x+y+z&=200\\\end[/tex]
Similarly, we will find for second system of equations
[tex]\begin{aligned}|A|&=\left|\begin{array}{lll}1&1&-1\\5&-5&-1\\-1&1&1\end{array}\right|\\ &=1(-5+1)-1(5-1)-1(5-5)\\&=1(-4)-1(4)-1(0)\\ &=-8\neq 0\end[/tex]
[tex]\begin{aligned}Adj A&=\left[\begin{array}{lll}-4&-4&0\\-2&0&-2\\-6&-4&-10\end{array}\right]^T\\&=\left[\begin{array}{lll}-4&-2&-6\\-4&0&-4\\0&-2&-10\end{array}\right]\end[/tex]
[tex]\begin{aligned}A^{-1}&=\frac{Adj A}{|A|}\\ &=\left[\begin{array}{lll}0.5&0.25&0.75\\0.5&0&0.5\\0&0.25&1.25\end{array}\right]\end[/tex]
[tex]\begin{aligned}\left[A\right.\text{ }\left.B\right]&=\left[\begin{array}{llll}1&1&-1&220\\5&-5&-1&-640\\-1&1&1&200\end{array}\right]\\ R_{2}&\rightarrow R_{2}-5R_{1},R_{3}\rightarrow R_{3}+R_{1}\\ &\sim \left[\begin{array}{llll}1&1&-1&220\\0&-10&4&-1740\\0&2&0&420\end{array}\right]\\ R_{3}&\rightarrow 5R_{3}+R_{2}\\ &\sim \left[\begin{array}{llll}1&1&-1&220\\0&-10&4&-1740\\0&0&4&360\end{array}\right]\end[/tex]
Thus, [tex]x=\left[\begin{array}{l}x\\y\\z\end{array}\right]=\left[\begin{array}{l}100\\210\\90\end{array}\right][/tex]
The third system of equations are
[tex]\begin{aligned}2x+2y-z&=290\\x+y-3z&=500\\x-y+2z&=600\\\end[/tex]
Similarly, we will find for third system of equations
[tex]\begin{aligned}|A|&=\left|\begin{array}{lll}2&2&-1\\1&1&-3\\1&-1&2\end{array}\right|\\ &=2(2-3)-2(2+3)-1(-1-1)\\&=2(-1)-2(5)-1(-2)\\ &=-10\neq 0\end[/tex]
[tex]\begin{aligned}Adj A&=\left[\begin{array}{lll}-1&-5&-2\\-3&5&4\\-5&5&0\end{array}\right]^T\\&=\left[\begin{array}{lll}-1&-3&-5\\-5&5&5\\-2&4&0\end{array}\right]\end[/tex]
[tex]\begin{aligned}A^{-1}&=\frac{Adj A}{|A|}\\ &=\left[\begin{array}{lll}0.1&0.3&0.5\\0.5&-0.5&-0.5\\0.2&-0.4&0\end{array}\right]\end[/tex]
get
[tex]\begin{aligned}\left[A\right.\text{ }\left.B\right]&=\left[\begin{array}{llll}2&2&-1&290\\1&1&-3&500\\1&-1&2&600\end{array}\right]\\ R_{2}&\rightarrow 2R_{2}-R_{1},R_{3}\rightarrow 2R_{3}-R_{1}\\ &\sim \left[\begin{array}{llll}2&2&-1&290\\&0&-5&710\\0&-4&5&910\end{array}\right]\end[/tex]
Thus, [tex]x=\left[\begin{array}{l}x\\y\\z\end{array}\right]=\left[\begin{array}{l}479\\-405\\-142\end{array}\right][/tex]
Hence, each system of equations to the inverse of its coefficient matrix, A⁻¹, and the matrix of its solution, X.
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A survey of 400 nurses yielded the following information: 279 were health club members, 215 were smokers, and 160 of the health club members were smokers. how many of the 400 surveyed nurses were health club members or were smokers?
Health club members or were smokers is [tex]334[/tex] from a A survey of [tex]400[/tex] nurses yielded.
How can we find the health club members or were smokers ?
Events of health club members is [tex]P(M)=279[/tex]
Events of smokers is [tex]P(S)=215[/tex]
Probability of health club members and smokers is [tex]p(M and S)=160[/tex]
Probability of health club members or were smokers is =?
So we use the formula
[tex]p(M or S)=p(M)+p(S)-p(M and S)\\ = 279+215-160\\ = 334[/tex]
Probability of health club members or were smokers is [tex]334[/tex]
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Which of the following is an equivalent form of the equation of the graph shown in the xyxyx, y-plane above, from which the coordinates of vertex AAA can be identified as constants in the equation
The equivalent form of the equation y=[tex]x^{2} -2x-15[/tex]given is y=(x+3)(x-5).
Given an equation y=[tex]x^{2}[/tex]-2x-15 and we are required to find the equivalent form of the equation.
Equation is like a relationship between two or more variables that are expressed in equal to form. Equation of two variables look like ax+by=c. It may be linear equation, quadratic equation, cubic equation or any other equation depending on the powers of the variable.
To find the equivalent equations we are required to form factors of the equation. Equivalent equation are those equations which when solved gives the same solution as the equation when solved gives.
y=[tex]x^{2}[/tex]-2x-15
y=[tex]x^{2}[/tex]-5x+3x-15
y=x(x-5)+3(x-5)
y=(x+3)(x-5)
Hence the equivalent form of the equation y= [tex]x^{2}[/tex]-2x-15 given is
y=(x+3)(x-5).
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Question is incomplete as question should includes the equation
y= [tex]x^{2}[/tex]-2x-15.
factorize all the question.
Answer:
5a(a - 2)
2(a^2 - 4)
(x + 5)(x - 5)
(x - 4)(x^2 + 4x + 16)
(a - 3)(a - 2)
(x^2 + x + 1)(x^2 - x - 1)
Step-by-step explanation:
5a^2 - 10a factor out GCF
5a(a - 2)
2a^2 - 8 factor out GCF
2(a^2 - 4)
x^2 - 25 difference of squares
(x + 5)(x - 5)
x^3 - 64 difference of cubes
(x - 4)(x^2 + 4x + 16)
a^2 - 5a + 6 factors of 6 that add to -5
a^2 - 2a - 3a + 6
a(a - 2) - 3(a - 2)
(a - 3)(a - 2)
x^4 - x^2 - 2x - 1 group last three terms
x^4 + (-x^2 - 2x - 1)
x^4 - (x^2 + 2x + 1) factors of 1 that add to 2
x^4 - (x + 1)(x + 1)
x^4 - (x + 1)^2 difference of squares
(x^2 + (x + 1))(x^2 - (x + 1)) simplify
(x^2 + x + 1)(x^2 - x - 1)
A)x=45
B)x=90
C)x=20
D)x=4.5
Answer:
x=4.5
Step-by-step explanation:
We know that if all sides are congruent then all angles must also be congruent, therefore you can solve for x with the following equation:
[tex]20x=90[/tex]
Solve
[tex]x=4.5[/tex]
In circuit training, exercises are usually set up so that the same muscle group is worked in back to back exercises.
In circuit training, exercises are usually set up so that the same muscle group is worked in back to back exercises is a "false" statement.
What is circuit training?A circuit workout consists of six or more exercises that are alternated with brief rest intervals and performed for either a predetermined number of reps or a certain duration of time.
Some features of circuit training exercise are-
It is a great approach to increase muscular strength and endurance as well as cardiovascular health. Due to the brief rest times, the use of major muscles in conjunction with smaller ones, and the mix of upper, lower, and whole-body movements in circuit training, your heart rate will increase and remain elevated during the entire circuit.Once all of the selected exercises have been finished, a circuit has been completed. A single training session may involve several circuits.Benefits of doing circuit training exercise-
Training in strength.Cardiovascular Health, Time Efficiency, Friendly Environment, Avoids BoredomTo know more about the circuit training, here
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The complete question is -
In circuit training, exercises are usually set up so that the same muscle group is worked in back to back exercises.(True/False)
Please help me
The sum of an integer and its square is 210. Find the integer. Include a completer
solution
Answer:
14
Step-by-step explanation:
An integers are whole numbers and their opposites. ...-3,-2,-2,0,1,2,3...
I just played with the numbers and found that 14 + 14^2 (14 squared is 14 x 14).
14 + (14)(14) = 210
Answer:
refer to the attachment
what is the range of the function of graph?
a.) all real numbers
b.) all real numbers greater than or equal to 0
c.) all real numbers greater than or equal to 1
d.) all real numbers greater than or equal to 2
The correct answer is "all real numbers greater than or equal to 2".