Answer: False
Step-by-step explanation:
Primary technology skills are simply the skills which are vital in order to attain success in online education. It should be noted that technical skills are knowledge and abilities that are related to information technology which are needed to do certain tasks.
It should be noted that online education is the form of education that is delivered and being administered through the internet.
For one to learn online, it should be noted that being able to open and close windows is a primary technology skill.
Therefore, the statement in the question is false.
Answer: F
I already did the test
Plz help 7th grade math picture below
Answer: balance is -44 dollars
This indicates he owes 44 dollars
=======================================================
Explanation:
21 + (-30) = -9 is the balance if we don't account for the overdraft fee
If we do account for the overdraft fee, then -9 + (-35) = -44 is the bank balance.
Note how I'm using negative values to indicate balances in which Nick owes money, rather than it's the amount of money he has. So he owes the bank $44.
------------
A slightly different way to get the answer is to say
21-30 = -9
-9-35 = -44
This is because adding a negative is the same as subtraction.
match each statement to the reasons given for the geometric proof.
Given: ABCD is a parallelogram
Prove: Diagonals bisect each other(AE=CE and BE = DE
Answer: 5, 3, 1, 2, 6, 4
Step-by-step explanation:
The proof should be written as follows (which is a different order than provided):
Statement Reason
1. ABCD is a parallelogram 1. Given
2. AB||DC and AD||BC and AB ≅ DC 2. Definition of parallelogram
3. ∠ABD ≅ ∠CDB 3. Alternate Interior Angles Theorem
4. ∠DEC ≅ ∠BEA 4. Vertical Angles Theorem
5. ΔABE ≅ ΔCDE 5. AAS Congruency Theorem
6. AE = CE and BE = DE 6. CPCTC
This is the order provided in your question:
5. ΔABE ≅ ΔCDE 5. AAS Congruency Theorem
3. ∠ABD ≅ ∠CDB 3. Alternate Interior Angles Theorem
1. ABCD is a parallelogram 1. Given
2. AB||DC and AD||BC and AB ≅ DC 2. Definition of parallelogram
6. AE = CE and BE = DE 6. CPCTC
4. ∠DEC ≅ ∠BEA 4. Vertical Angles Theorem
g find the 2 components of vector b = 2i + j - 3k, one parallel to a = 3i - j and another one perpendicular to a
Answer:
The components of [tex]\vec{b}[/tex] parallel and perpendicular to [tex]\vec {a}[/tex] are [tex]\vec {b}_{\parallel} = \frac{3}{2}\,i-\frac{1}{2}\,j[/tex] and [tex]\vec b _{\perp} = \frac{1}{2}\,i+\frac{3}{2}\,j-3\,k[/tex], respectively.
Step-by-step explanation:
Let be [tex]\vec b = 2\,i+j-3\,k[/tex] and [tex]\vec a = 3\,i-j[/tex], the component of [tex]\vec b[/tex] parallel to [tex]\vec a[/tex] is calculated by the following expression:
[tex]\vec b_{\parallel} = (\vec b \bullet \hat{a}) \cdot \hat{a}[/tex]
Where [tex]\hat{a}[/tex] is the unit vector of [tex]\vec a[/tex], dimensionless and [tex]\bullet[/tex] is the operator of scalar product.
The unit vector of [tex]\vec a[/tex] is:
[tex]\hat{a} = \frac{\vec {a}}{\|\vec a\|}[/tex]
Where [tex]\|\vec {a}\|[/tex] is the norm of [tex]\vec a[/tex], whose value is determined by Pythagorean Theorem.
The component of [tex]\vec{b}[/tex] parallel to [tex]\vec {a}[/tex] is:
[tex]\|\vec {a}\| = \sqrt{3^{2}+(-1)^{2}+0^{2}}[/tex]
[tex]\|\vec {a}\| = \sqrt{10}[/tex]
[tex]\hat{a} = \frac{1}{\sqrt{10}} \cdot (3\,i-j)[/tex]
[tex]\hat{a} = \frac{3}{\sqrt{10}}\,i -\frac{1}{\sqrt{10}} \,j[/tex]
[tex]\vec{b}\bullet \hat{a} = (2)\cdot \left(\frac{3}{\sqrt{10}} \right)+(1)\cdot \left(-\frac{1}{\sqrt{10}} \right)+(-3)\cdot \left(0\right)[/tex]
[tex]\vec b \bullet \hat{a} = \frac{5}{\sqrt{10}}[/tex]
[tex]\vec b_{\parallel} = \frac{5}{\sqrt{10}}\cdot \left(\frac{3}{\sqrt{10}}\,i-\frac{1}{\sqrt{10}}\,j \right)[/tex]
[tex]\vec {b}_{\parallel} = \frac{3}{2}\,i-\frac{1}{2}\,j[/tex]
Now, the component of [tex]\vec {b}[/tex] perpendicular to [tex]\vec{a}[/tex] is found by vector subtraction:
[tex]\vec{b}_{\perp} = \vec {b}-\vec {b}_{\parallel}[/tex]
If [tex]\vec b = 2\,i+j-3\,k[/tex] and [tex]\vec {b}_{\parallel} = \frac{3}{2}\,i-\frac{1}{2}\,j[/tex], then:
[tex]\vec{b}_{\perp} = (2\,i+j-3\,k)-\left(\frac{3}{2}\,i-\frac{1}{2}\,j \right)[/tex]
[tex]\vec b _{\perp} = \frac{1}{2}\,i+\frac{3}{2}\,j-3\,k[/tex]
What is the quotient of 3,968 ÷ 32?
Answer:
124
Step-by-step explanation:
you just add 32 till u get 3968
Answer: The quotient of 3,968 ÷ 32= 124
What number should be added to 77 to make the sum 0? (5 points)
77
-77
0
-76
Answer:
-77
Step-by-step explanation:
77+77=154 wrong
77+(-77)=0 right
77+0=77 wrong
77+(-76)=1 wrong
Answer:
b. -77
Step-by-step explanation:
Need help now Please help
Answer:
D is the correct answer.
Answer:
d
Step-by-step explanation:
taisha ran faster than 15.02 but slower than 14.65
An Olympic swimming pool is 50 m long, 25 m wide, and 1.5 m deep. How many Olympic pools would be filled by the dollar bills spent by the U.S. federal government in 2011
Answer:
Number of dollars bills that can be fitted in Olympic pool = 1.67 billion.
Step-by-step explanation:
The dimensions of a dollar bill are 15.5956 cm by 6.6294 cm by 0.010922 cm. The U.S. federal government spent $3.8 trillion in fiscal year 2011.
An Olympic swimming pool is 50 m long, 25 m wide, and 1.5 m deep. How many Olympic pools would be filled by the dollar bills spent by the U.S. federal government in 2011
From above,
The volume for the dimension of the dollar bill = 15.5956 cm × 6.6294 cm × 0.010922 cm
The volume for the dimension of the dollar bill = 1.12922 cm³
The volume for the dimension of the dollar bill = 1.12922 × 10⁻⁶ m³
The volume of the pool = 50 m × 25 m × 1.5 m
The volume of the pool = 1875 m³
Number of dollars bills that can be fitted in pool = volume of the pool/volume of the dimension of dollar bills
Number of dollars bills that can be fitted in Olympic pool =1875 m³ / 1.12922 × 10⁻⁶ m³
Number of dollars bills that can be fitted in Olympic pool = 1,660,438,180
Number of dollars bills that can be fitted in Olympic pool = 1.67 billion.
In the U.S., 79,816,000 people age 25 and over have completed at least a bachelor’s degree. This is 36% of the population. How many people are age 25 and over in the U.S.?
Answer:
79,816,000 people
Step-by-step explanation:
Given:
People Age 25 above = 79,816,000 people
Required
Determine the population of people over 25
The first statement of the question reads:
"In the U.S., [tex]79,816,000[/tex] people age 25 and over......"
This statement answers your question;
Hence;
Required Population = 79,816,000 people
Find the value of x.
X = [?]°
68.5°
Х
49.5°
Answer:
[tex] \boxed{ \bold {\huge{ \boxed{ \sf{x = 62°}}}}}[/tex]
Step-by-step explanation:
Sum of angle of triangle = 180 °
Create an equation :
[tex] \sf{x + 68.5 + 49.5 = 180°}[/tex]
Add the numbers
⇒[tex] \sf{x + 118 = 180}[/tex]
Move 118 to right hand side and change it's sign
⇒[tex] \sf{x = 180 - 118}[/tex]
Subtract 118 from 180
⇒[tex] \sf{x = 62°}[/tex]
Hope I helped!
Best regards!!
The length of a rectangle is four times its width. If the area of the rectangle is 324m^2, find its perimeter.
Answer:
[tex]perimeter=90[/tex]
Step-by-step explanation:
We know that the length is four times the width, so:
[tex]l=4w[/tex]
We also know the area, which is 324 m². The formula for area:
[tex]A=l*w[/tex]
Insert the known values:
[tex]324=(4w)*w[/tex]
Solve for w. Simplify by removing parentheses:
[tex]324=4w*w\\324=4w^2[/tex]
Divide 4 from both sides to isolate the variable:
[tex]\frac{324}{4}=\frac{4w^2}{4} \\\\81=w^2[/tex]
Find the square root of both sides:
[tex]\sqrt{81} =\sqrt{w^2} \\\\w=9[/tex]
The width is 9 m.
We know the width. Now find the length by using the area formula and inserting known values:
[tex]324=l*9[/tex]
Solve for l. Divide both sides by 9:
[tex]\frac{324}{9}=\frac{l*9}{9}\\\\ l=36[/tex]
The length of the rectangle is 36. (You can check: 4 times 9 is 36)
Now find the perimeter:
[tex]P=2l+2w[/tex]
Insert values:
[tex]P=2(36)+2(9)\\\\P=72+18\\\\P=90[/tex]
The perimeter is 90 m.
Jada is evaluating 8 × 3 × 4. She doesn't know the product of 24 and 4 off the top of her head, so she decides to multiply 3 by 4 first. Which property is Jada using? PLEASE HELP!!
Answer: Associative property
Step-by-step explanation:
From the question, we are informed that Jada is evaluating 8 × 3 × 4 and that she doesn't know the product of 24 and 4 off the top of her head, so she decides to multiply 3 by 4 first.
The property that Jada is using is the Associative property. This has to do with regrouping of the numbers and then multiplying the numbers in different groups.
PLS PLS HELP WILL GIVE 50 POINTS TO BRAINLIEST How do you find the radius of a circle with the equation: 03.5 (x+2.2)^2 + 3.5 (y−11.1)^2 − 21 = 0
Answer: r=√6 or r≈2.45.
Step-by-step explanation:
To find the radius, you first need to know the equation of a circle.
Equation of a circle: [tex](x-h)^2+(y-k)^2=r^2[/tex]
Now that we know the equation of the circle, we can use it to find the radius of the given equation.
3.5(x+2.2)²+3.5(y-11.1)²-21=0
So far the equation looks pretty similar with the exception of the bolded areas. To get rid of them, we need to use our algebraic properties.
3.5(x+2.2)²+3.5(y-11.1)²-21=0 [add both sides by 21]
3.5(x+2.2)²+3.5(y-11.1)²=21 [factor out 3.5]
3.5((x+2.2)²+(y-11.1)²)=21 [divide both sides by 3.5]
(x+2.2)²+(y-11.1)²=6
Now, our equation is the same as the one posted above. You may think that 6 is our radius, but if you look closely, the equation is equal to r². Therefore, 6 is actually r², not r.
r²=6 [square root both sides]
r=√6
Finally, we have the final answer, r=√6 or r≈2.45.
Find the differential of each function. (a) y = tan( 5t ) dy = Correct: Your answer is correct. (b) y = 5 − v2 5 + v2
Answer:
[tex](a)[/tex] [tex]dy = 5sec^2(5t) \ dt[/tex]
[tex](a) \ dy = \frac{-20v}{(5+v^2)^2} \ dt[/tex]
Step-by-step explanation:
Given;
(a) y = tan(5t)
[tex](b) \ y = \frac{5-v^2}{5+v^2}[/tex]
Solving for (a)
y = tan(5t)
let u = 5t
⇒y = tan(u)
du/dt = 5
dy/du = sec²u
[tex]\frac{dy}{dt} =\frac{dy}{du} *\frac{du}{dt} \\\\\frac{dy}{dt} = sec^2(u)*5\\\\\frac{dy}{dt} = 5sec^2(u)\\\\\frac{dy}{dt} = 5sec^2(5t)[/tex]
[tex]dy = 5sec^2(5t) \ dt[/tex]
Solving for b;
let u = 5 - v²
du/dv = -2v
let v = 5+ v²
dv/du = 2v
[tex]\frac{dy}{dv} = \frac{vdu - udv}{v^2} \\\\\frac{dy}{dv} = \frac{-2v(5+v^2) - 2v(5-v^2)}{(5+v^2)^2}\\\\\frac{dy}{dv} = \frac{-10v-2v^3-10v+2v^3}{(5+v^2)^2}\\\\[/tex]
[tex]\frac{dy}{dv} = \frac{-10v-10v}{(5+v^2)^2}\\\\\frac{dy}{dv} = \frac{-20v}{(5+v^2)^2}\\\\dy = \frac{-20v}{(5+v^2)^2} dt[/tex]
Find the equation of a line containing the given points (4,3) and (8,1). Write the equation in slope-intercept form. Please give step by step explanation.
Answer:
-1/2
Step-by-step explanation:
y2-y1 1-3 -1
x2-x1 8-4 2
The graph below shows the number of pages that Victor has left to read in his book at the end of the day over seven days. Pages Left to Read in Victor’s Book On a coordinate plane, the x-axis is labeled Day and the y-axis is labeled Pages left. On day 0 there were 220 pages; Day 1, 180; Day 2, 170; Day 3, 140; Day 4, 140; Day 5, 100; Day 6, 60; Day 7, 40. Which statement is supported by the graph? Victor read 0 pages on day 4. Victor read 170 pages on day 2. Victor read the same number of pages on day 1 and on day 2. Victor read the same number of pages on day 3 and on day 4.
Answer:
C
Step-by-step explanation:
Answer:
A
Step-by-step explanation:
I had the same question and got it right
Nidhi is thinking of a number n, and she wants her sister to guess the number. Her first clue is that eight less than three times her number is between one and nineteen. Write a compound inequality that shows the range of numbers that Nidhi might be thinking of
Answer:
The range of numbers that Nidhi might be thinking of is between 3 and 9.
Step-by-step explanation:
We are given that Nidhi is thinking of a number n, and she wants her sister to guess the number.
Her first clue is that eight less than three times her number is between one and nineteen.
Let the number Nidhi is thinking be 'n'.
So, eight less than three times her number means that;
[tex](3\times \text{n}) - 8 = 3\text{n}-8[/tex]
Now, according to the question; the above equation is between one and nineteen, so;
[tex]1< 3\text{n}-8 < 19[/tex]
Adding 8 to the whole expression;
[tex]1+8< 3\text{n}-8 +8< 19+8[/tex]
[tex]9< 3\text{n}< 27[/tex]
Dividing the whole expression by 3;
[tex]\frac{9}{3} < \frac{3\text{n}}{3} < \frac{27}{3}[/tex]
[tex]3< \text{n}< 9[/tex]
Hence, the range of numbers that Nidhi might be thinking of is between 3 and 9.
solve the equation2.2^2x-7×2^x-4=0.
Answer:
2
Step-by-step explanation:
2×2^2x - 7×2^x - 4=02×(2^x)^2 - 7×2^x - 4 = 0Substitute 2^x = y, where y>0
Then we get quadratic equation:
2y^2 - 7y - 4 = 0Solving this, we get y = 4 as positive root, so;
y = 42^x = 42^x = 2^2x = 2Answer is 2
what is 57/5as a decimal
Answer:
11.4
Step-by-step explanation:
57/5 as a mixed number is 11 2/5.
2/5 of a number is also known as 4/10 or 0.4, so add that to 11 to get 11.4.
Answer:
11.4
Step-by-step explanation:
57/5 = 11.4
last year frankie deli made an 11 foot 6 inch submarine this year they plan to make another one 2 feet and 3 inches longer how many feet long will this sandwich be? anserw
Answer:
13 feet 9 inches
Step-by-step explanation:
11 feet 6 inches + 2 feet 3 inches= 13 feet 9 inches
An online merchant sells products that can be classified into the following non-intersecting categories: video games, electronics and clothing.In any given week, it is estimated that twice as many video games are sold compared to clothing items. However, the number of electronic items sold would be two-thirds of the number of video games sold, less one-fifth of the number of clothing items sold. A total of five items were independently sold in the past week.What is the probability that the five items consisted of three video games, one electronic item and one clothing item?A. 0.03B. 0.06C. 0.08D. 0.12E. 0.15
Answer:
0.15 ( E )
Step-by-step explanation:
Assuming
video game to be : V
electronics : E
clothing : C
From the content of the question
V = 2c
hence E = 2/3 V - 1/5 C
= 2/3 ( 2c ) - 1/5 c
= [tex]\frac{17c}{15}[/tex]
therefore : V = 2c and E = 17c / 15
assuming the number of clothing ( c ) = 15
V = 2*15 = 30 and E = ( 17 *15 ) / 15 = 17
Total number of items sold = V + C + E = 30 + 15 + 17 = 62
from here we can determine the probability that of the five items independently sold that there are 3 video game, 1 electronic item and 1 clothing item
attached below is the remaining part of the solution
Answer:
Step-by-step explanation:
What is the length of the line segment with endpoints (11, −4) and (−12, −4
Answer:
23 units
Step-by-step explanation:
Use the distance formula: d = [tex]\sqrt{(x2 - x1)^2 + (y2 - y1)^2}[/tex]
Plug in the 2 points:
d = [tex]\sqrt{(-12 - 11)^2 + (-4 + 4)^2}[/tex]
d = [tex]\sqrt{529}[/tex]
d = 23
So, the distance is 23 units
Answer:
length of the line segment =23
Step-by-step explanation:
[tex] (11, −4) = (x_1 , y_1) \\ (−12, −4) = (x_2 , y_2) \\ d = \sqrt{(x_2 - x_1)^{2} + (y_2 - y_1)^{2} }[/tex]
Plug in the values into the equation
[tex]d = \sqrt{( - 12 - 11)^{2} + ( - 4 - ( - 4)^{2} } [/tex]
Simply :
-12-11=- -23
-4(-4) = -4+4=0
[tex]d = \sqrt{( - 23)^{2} + {(0)}^{2} } \\ d = \sqrt{529 + 0} \\ d = \sqrt{529} \\ d = 23[/tex]
a. Guttery invested $147,000 in cash to start the business.
b. Paid $4,700 for the current month's rent.
c. Bought office furniture for $15,420 in cash.
d. Performed services for $8,500 in cash.
e. Paid $1,120 for the monthly telephone bill.
f. Performed services for $14,300 on credit.
g. Purchased a computer and copier for $35,400; paid $11,700 in cash immediately with the balance due in 30 days.
h. Received $7150 from credit clients.
i. Paid $2,700 in cash for office cleaning services for the month.
j. Purchased additional office chairs for $4,500; received credit terms of 30 days.
k. Purchased office equipment for $27,000 and paid half of this amount in cash immediately, the balance is due in 30 days.
I. Issued a check for $8,100 to pay salaries.
m. Performed services for $14,800 in cash.
n. Performed services for $16,300 on credit.
o. Collected $6,700 on accounts receivable from charge customers.
p. Issued a check for $2,250 in partial payment of the amount owed for office chairs.
q. Paid $570 to a duplicating company for photocopy work performed during the month.
r. Paid $1,090 for the monthly electric bill.
s. Guttery withdrew $7.700 in cash for personal expenses.
Required:
Prepare a trial balance, an income statement, a statement of owner's equity, and a balance sheet. Assume that the transactions to
place during the month ended June 30, 2019. Determine the account balances before you start work on the financial statements.
Analyze
< Prey
4 of 10
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Answer:
unanswerable
Step-by-step explanation:
bruh no one can answer all these questions. try making them seperatly that should help.
what is the median of 3 3 4 5 5 5 6 6 6 7 8
Answer:
5
Step-by-step explanation:
The median is the middle number of the list when put in order from smallest to largest
3 3 4 5 5 5 6 6 6 7 8
There are 11 numbers so the middle number is the 6th ( 5 on the left and 5 on the right
3 3 4 5 5 5 6 6 6 7 8
Simplify the equation 9z-3z=48
Answer: z=8
Step-by-step explanation:
9z-3z=48
6z=48 ⇔ combine like terms
z=8
Hope this helps
Answer:
z = 8
Step-by-step explanation:
9z - 3z = 48
6z = 46
z = 8
How much more gasoline will it take to fill the tank?
Answer:
I think you need to divide both fractions and see if you will get a answer from the answer choices.
Step-by-step explanation:
A manufacturer of chocolate chips would like to know whether its bag filling machine works correctly at the 420 gram setting. It is believed that the machine is underfilling the bags. A 49 bag sample had a mean of 413 grams. Assume the population variance is known to be 676 . A level of significance of 0.1 will be used. Find the P-value of the test statistic. You may write the P-value as a range using interval notation, or as a decimal value rounded to four decimal places.
Answer:
The value is [tex]p-value = 0.0297[/tex]
Step-by-step explanation:
From the question we are told that
The population mean is [tex]\mu = 420 \ g[/tex]
The The sample size is [tex]n = 49[/tex]
The sample mean is [tex]\= x = 413 \ g[/tex]
The population variance is [tex]\sigma^2 = 676[/tex]
Generally the population standard deviation is mathematically represented as
[tex]\sigma = \sqrt{\sigma^2 }[/tex]
[tex]\sigma = \sqrt{676}[/tex]
[tex]\sigma = 26[/tex]
The null hypothesis is [tex]H_o : \mu = 420 \ g[/tex]
The alternative hypothesis is [tex]H_a : \mu < 420 \ g[/tex]
Generally the test statistics is mathematically represented as
[tex]z = \frac{ \= x - \mu }{ \frac{ \sigma }{\sqrt{n} } }[/tex]
=> [tex]z= \frac{ 413 - 420 }{ \frac{ 26 }{\sqrt{49} } }[/tex]
=> [tex]z = -1.884[/tex]
The p-value is obtained from the z-table table and the value is
[tex]p-value = P(Z < -1.885) = 0.029715[/tex]
[tex]p-value = 0.0297[/tex]
a) Find a recurrence relation for the number of bit strings of length n that contain a pair of consecutive 0s.
b) What are the initial conditions?
c) How many bit strings of length seven contain two consecutive 0s?
Answer:
A) [tex]a_{n} = a_{n-1} + a_{n-2} + 2^{n-2}[/tex]
B) [tex]a_{0} = a_{1} = 0[/tex]
C) for n = 2
[tex]a_{2}[/tex] = 1
for n = 3
[tex]a_{3}[/tex] = 3
for n = 4
[tex]a_{4}[/tex] = 8
for n = 5
[tex]a_{5}[/tex] = 19
Step-by-step explanation:
A) A recurrence relation for the number of bit strings of length n that contain a pair of consecutive Os can be represented below
if a string (n ) ends with 00 for n-2 positions there are a pair of consecutive Os therefore there will be : [tex]2^{n-2}[/tex] strings
therefore for n ≥ 2
The recurrence relation for the number of bit strings of length 'n' that contains consecutive Os
[tex]a_{n} = a_{n-1} + a_{n-2} + 2^{n-2}[/tex]
b ) The initial conditions
The initial conditions are : [tex]a_{0} = a_{1} = 0[/tex]
C) The number of bit strings of length seven containing two consecutive 0s
here we apply the re occurrence relation and the initial conditions
[tex]a_{n} = a_{n-1} + a_{n-2} + 2^{n-2}[/tex]
for n = 2
[tex]a_{2}[/tex] = 1
for n = 3
[tex]a_{3}[/tex] = 3
for n = 4
[tex]a_{4}[/tex] = 8
for n = 5
[tex]a_{5}[/tex] = 19
If x = -1 and y = 6, then x + 3xy
(A) 19
(B) 17
(C) 16
(D) -16
(E) -17
Choose
Answer:
D
Step-by-step explanation:
idk I just guessed tbh
Answer:
E -17
Step-by-step explanation:
3 times -1 is -3
-3 times 6 is -18
-18 + -1 is -17 (++)
A washer and dryer cost 1019$ combined. The washer costs 69$ more than the dryer. What is the cost of the dryer?
Answer:
440.5$
Step-by-step explanation:
1019$ ÷ 2 = 509.5
509.5 - 69$ = 440.5$
12b + 9 = 12b + 11 what’s the answer
Answer: b∈∅
Step-by-step explanation:
Answer:
no solutions
Step-by-step explanation:
12b + 9 = 12b + 11
Subtract 12b from each side
12b-12b + 9 = 12b-12b + 11
9 = 11
This is never true, so there are no solutions