Below are three different arrangements of two mirrors near a source of
light. For each arrangement, a light ray is drawn from the source to the
first mirror. In which of these arrangements would the light eventually
travel parallel to, but in the opposite direction to, the original light. [This
type of device is called a retro-reflector.]
A.
B.
C.
Answers
In arrangement B) , mirrors are placed mutually perpendicular to each other .
A retroreflector is a device or surface that reflects radiation back to its source with minimum scattering.
When two mirrors are placed perpendicular to each other , and if a light ray that strikes an object consisting of two mutually perpendicular reflective surfaces is reflected back exactly parallel to the direction to the source it came from.
out of all arrangements , it can be observed that in arrangement B) , mirrors are placed mutually perpendicular to each other .
hence , correct option will be
option B
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Related Questions
An apple with mass M is hanging at rest from the lower end of a light vertical rope. A dart of mass M/4 is shot vertically upward, strikes the bottom of the apple, and remains embedded in it.
Answers
The apple moves a height of h = [tex]\frac{v^{2} }{50 g}[/tex] because of its collision with the dart.
How do we calculate height?we can calculate the height of an object using the distance and angle.
In order to calculate the height of an apple with mass M is hanging at rest from the lower end of a light vertical rope. A dart of mass M/4 is shot vertically upward, strikes the bottom of the apple, and remains embedded in it.
We first calculate the velocity that the final mass gets once the collision takes place, in order to do this, we use momentum conservation.
pi = Pf = (5/4)Mv
We get the value for the velocity of the final mass, v , once the collision has been produced.
Once we have pi, with this final velocity, we can calculate the final height that the mass will get, to do this we use energy conservation.
An instant after the collision, the mass has kinetic energy, and we say that that is our altitude zero, but when the mass gets to its higher altitude, the kinetic energy is zero and the potential energy is different than zero, and we will write as follows:
Ei = Ef = (1/2) (5/4 M (V/5)² =(5/4 M)g*h
Equating and solving for height, we will get as the apple moves a height of h = [tex]\frac{v^{2} }{50 g}[/tex] because of its collision with the dart.
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If it takes more force for an object with more mass to accelerate because it has more inertia and objects with less mass have more acceleration (because a∝1/m in Newton's Second Law F=ma), then why do objects with more mass and objects with less mass accelerate at the same rate towards Earth (about 9.8m/s^2)?
Answers
Explanation:
Gravity is the only force acting on an object in free-fall. According to Newton's second law, the force is equal to mg, so the mass is taken into account there.
Patrick walks 6 meters to the south, 3 meters west, 2 meters to the north, and 5 meters to the east. Which of the following is true?
A. His displacement was 4 meters.
B. His distance traveled was 6 meters.
C. His distance traveled was 16 meters.
D.His displacement was 17 meters.
Answers
Basically the answer is C, because the addition is 6+3+2+5 = 16. As we know that the distance traveled is the addition of all the magnitudes of distance it took us to get from a starting point to the ending point.
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A solid, horizontal cylinder of mass 12.2 kg and radius 1.00 m rotates with an angular speed of 5.50 rad/s about a fixed vertical axis through its center. A 0.250-kg piece of putty is
dropped vertically onto the cylinder at a point 0.900 m from the center of rotation and sticks to the cylinder. Determine the final angular speed of the system.
rad/s
PRACTICE ANOTHER
Answers
The final angular speed of the system that contains a solid, horizontal cylinder of mass 12.2 kg and radius 1.00 m rotates with an angular speed of 5.50 rad/s about a fixed vertical axis through its center is 5.33 rad / s
Let M and R be mass and radius of the cylinder. Let m and r be mass and distance of piece of putty.
M = 12.2 kg
R = 1 m
ω = 5.5 rad / s
m = 0.25 kg
r = 0.9 m
According to law of conservation of angular momentum,
1 / 2 M R² ω = ( 1 / 2 M R² + m r² ) ω'
1 / 2 * 12.2 * 1 * 5.5 = [ ( 1 / 2 * 12.2 * 1 ) + ( 0.25 * 0.9² ) ] ω'
ω' = 33.55 / 6.3
ω' = 5.33 rad / s
Therefore, the final angular speed of the system is 5.33 rad / s
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Q10. In an ideal situation without any air resistance, any free-falling body will fall at the same rate of acceleration, regardless of its mass, and thus would simultaneously hit the
ground if released from the same height. However, in real-life scenarios, air resistance plays a vital role in determining the fall rate of any object. Which parameters would affect
the fall if air drag is also considered? Choose all possible answers.
Weight of the object.
>>
Shape of the object.
Density of the air.
Velocity of the object.
Submit
Answers
Velocity of the object parameters would affect the fall if air drag is also considered.
What is velocity in physics with example?Velocity can be defined as the rate at which that moves in a specific direction. as the velocity of a car driving north on a road or the pace at which a rocket takes off. Because the velocity vector is scalar, its integrand magnitude will always equal the motion's speed.
Can velocity be negative?A moving object has a negative velocity when it is moving in the wrong direction. If an object is slowing down, its generate and evaluate is pointing away from the direction in which it is moving (in this case, a positive acceleration).
What is the principle of velocity?An object must move at a constant speed and direction in order to have a constant velocity. The object can only travel in a straight line if the direction is constant. So, motion in a single direction at a constant speed is defined as having a constant velocity.
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A cylinder is rolling along the ground at 2m/s . It comes to a hill and starts going up.Assuming no losses to friction, how high does it get before it stops
Answers
The maximum height reached by the cylinder at the given initial velocity is 0.2 m.
What is the maximum height travelled by the cylinder?
The maximum height travelled by the cylinder is calculated by applying the following kinematic equation as shown below.
v² = u² - 2gh
where;
u is the initial velocity of the cylinderv is the final velocity of the cylinder at the maximum heighth is the maximum height travelled by the cylinderg is acceleration due to gravityAt maximum height, the final velocity of the cylinder = 0
v² = u² - 2gh
0 = u² - 2gh
2gh = u²
h = u²/2g
h = (2²) / (2 x 9.8)
h = 0.2 m
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What is the critical angle for light traveling from ice (n=1.309) into air?
a. 39.8⁰
c. 59.8⁰
b. 49.8⁰
d.
69.8°
Answers
Answer:
b. 49.8
Explanation:
θc = sin^-1(1/1.309) = 49.81
A body of mass 2kg falls freely from rest through a height 8m onto a hard floor bounces back to a height of 2m. calculate the change of momentum, if the bady is in contact with the floor for 0.1s, what is the force exerted on the body? (g=10ms^2)
Answers
The force exerted on the body is 12.66 N.
Linear momentum, translational momentum, or clearly momentum is the made of the mass and velocity of an item. it's miles a vector amount, possessing significance and a path. If m is an object's mass and v is its speed.
Given;
mass = 2 kg
height = 8m
bounce height = 2 m
let velocity just before striking the floor is initial velocity 12.65 m/s
the potential energy at 8 m = mgh
= 2 ×10× 8
= 160 J
same converted into kinetic energy 160 J = 1/2 mv²
V² = 320/2
v = 12.65 m/s
Final velocity
mgh = 1/2 mv²
2×10×2 = 1/2×2 × v²
v² = 6.32 m/s
Acceleration = change in velocity per unit of time
= - 6.32 - (-12.65) = 6.33 m/s² / 0.1
Force = mass × acceleration
= 2 × 6.33 m/s²
= 12.66 N
Momentum may be described as a mass in motion. All objects have mass; so if an object is transferring, then it has momentum - it has its mass in movement. the quantity of momentum that an item has depends upon variables: how an awful lot of stuff is moving and the way speedy the stuff is moving.
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A rod slides along a metal frame. The earth’s magnetic field is 3.5 × 10−5 T at right angles to the plane of the frame. The rod is of length 0.23 m inside the frame and moves at 0.68 m/s. What is the motional EMF produced by the rod? Answer in units of V.
Answers
The motional EMF produced by the rod is 5.474 × 10⁻⁶ V.
What is electromotive force?When no current is flowing, electromotive force (EMF) equals the terminal potential difference.
Despite the fact that both EMF and terminal potential difference (V) are expressed in volts, they are not the same thing. EMF is the quantity of energy (E) that the battery supplies to each coulomb of charge (Q) that passes through.
Given parameters:
The earth’s magnetic field; B= 3.5 × 10⁻⁵ T
The length of the rod; l = 0.23 m.
Speed of the rod; v = 0.68 m/s.
So, the motional EMF produced by the rod = Blv
= 3.5 × 10⁻⁵ × 0.23 × 0.68
= 5.474 × 10⁻⁶ V.
Hence, motional EMF produced by the rod is 5.474 × 10⁻⁶ V.
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explain the impact covid had had on the rate of cardiovascular disease
Answers
The inner walls of veins and arteries can be affected by coronavirus infection, which can result in blood vessel inflammation, harm to extremely small vessels, and blood clots leading to the risks of cardiovascular diseases.
How covid had an impact on the rate of cardiovascular diseases?The mechanisms by which the COVID-19 pandemic might change trends in cardiovascular health have been the subject of numerous ideas. People with COVID-19 have a worse prognosis when they have established CVD and atherosclerosis cardiovascular disease risk factors.
Like other viral illnesses, such as some flu strains, the coronavirus may directly infect and harm the heart's muscular tissue. The body's immune system's response could also indirectly harm and inflame the heart.Less oxygen can enter the circulation as the virus induces inflammation plus fluid to clog the air sacs of the lungs. Blood pumping through the body requires more effort from the heart, which can be problematic for those who already have heart disease.Therefore, covid had a great impact on cardiovascular diseases and increased the overall disease rate.
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1. What is the definition of work done?
2. What is the unit for energy?
3.
The engine of Tilly's car exerts a force of 750N. How much
energy would be transferred by the engine if the car moved a
distance of 100m?
4.
Rehana is holding an object of weight 50N is raised by a height
of 200cm. What is the work done in raising the object?
5.
700J of energy is used by Ikram to move a distance of 10m.
What is the force exerted by the person as they walk the
distance?
6. Hifza has a weight of 200N. Aymen has a weight of 350N. If
1000) of energy is used to raise each object, which object will
gain the most height?
Answers
The combination of a force's constituent acting inside the displacement's direction as well as its magnitude would be known as the work done mostly via force.
1) Work is done when an applied force produces mobility in a body.
Mathematically , Work = Force x displacement
2) Unit for energy is Joule.
3) Energy can be calculated by such as:
Work = F s
750 x 100 = 75000J would be transferred by engine if car moved a distance of 100m.
4)For the case of Rehana : 200 cm converted to 2m .
again using same concept , W=FS
50 x 2=100J of work done in raising the object.
Energy consumed = 700 J
Distance (Displacement) = 10 m
7) We know work done is also a type of energy which tells the energy consumed by anything in order to move a distance, We know
⇒ Work done = Force × Displacement
⇒ 700 = F × 10
⇒ F = 70 newton
Hence, The force exerted by the person as walked the distance is 70 newton.
6) For the hifza case:- 200N will take more height because it is lighter than 350N so we can do it upward and downward as it is lighter and the energy used is 1000J .
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How much energy must a stove transfer to completely heat 1g of liquid water from 1o C to 25o C?
Answers
The energy needed by a stove to transfer heat completely to 1 g of liquid water fro 1 °C to 25 °C is 100.37 J.
What is energy?Energy is the ability or the capacity to do work.
To calculate the amount of energy, we use the formula below.
Formula:
Q = cm(t₂-t₁).............. Equation 1Where:
Q = Amount of energyc = Specific heat capacity of the waterm = mass of the watert₂ = Final temperaturet₁ = Initial temperatureFrom the question,
Given:
m = 1 g = 0.001 kgc = 4182 J/kg°Ct₁ = 1 °Ct₂ = 25 °CSubstitute these values into equation 1
Q = 0.001(4182)(25-1)Q = 100.37 JHence, The energy required is 100.37 J.
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Taking into account the definition of calorimetry, the energy that a stove must transfer to completely heat 1 g of liquid water from 1 °C to 25 °C is 100.416 J.
Definition of calorimetryCalorimetry is the measurement and calculation of the amounts of heat exchanged by a body or a system.
When heat added or removed from a substance causes a temperature change in it without affecting its molecular structure, it is called sensible heat.
So, the expression that allows to calculate heat exchanges is:
Q = c× m× ΔT
where:
Q is the heat exchanged by a body of mass m.c is the specific heat substance.ΔT is the temperature variation.Energy in this caseIn this case, you know:
Q= ?c= 4.184 J/gCm= 1 gΔT= Tfinal - Tinitial= 25 C - 1 C= 24 CReplacing in the definition of calorimetry:
Q = 4.184 J/gC× 1 g× 24 C
Solving:
Q= 100.416 J
Finally, the energy needed is 100.416 J.
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If 600 J of energy of chemical energy is contained inside the gasoline in a gas tank, how much work can the engine perform on the car? What kinetic energy can be achieved?
Answers
Kinetic energy will be 600J. According to law of conservation energy: All the energy in a system will simply change the state, and no more nor less energy will be created or lost during the operation of the system. In this case, then all 600J of energy will be transformed during the operation of car.
This chemical energy, what is it?kinetic energy, Chemical compounds' bonds contain energy. Chemical reactions have the potential to release chemical energy, frequently in the form of heat; these kinds of reactions are referred to as exothermic. Some of the energy from reactions that need heat input to continue may be stored as chemical energy in newly formed bonds.
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34. An object with mass 5.00 kg is being pushed up an inclined plane with a constant force F. The plane makes an angle of 30.0with respect to the horizontal . The object is moving with constant velocity . The coefficient of kinetic friction between the object and the surface is 0.300 . What is the magnitude of this force ?
Answers
The magnitude of the force is 12.73N.
What is force?
this can be defined as a push or pull in a particular direction. It is calculated using the formula:
F=m*a
Where,
m=mass of the object
a=acceleration
What is magnitude of force?
This is the quantity or strength of the force. It is calculated using the formular:
Normal Force, N=m*g*Cos θ
From the question given:
m =5.00kg
Cos θ= 30°
g=9.8m/s²
Coefficient of Friction, μ=Frictional force/Normal force
=F/N
coefficient kinetic friction, μ=0.300
Magnitude of Force F= Coefficient of Friction*Normal Force
=μN
=μmg Cos θ
F= 0.300*5.00*9.8*Cos30°
F=0.300*5.00*9.8*0.8660
The magnitude of Force,F=12.73N
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Aside from density, what other information from the table of planetary data can help someone decide if a planet is terrestrial, jovian, or dwarf?
Answers
Jovian planets are less dense than terrestrial planets.
The ratio of these two characteristics—an object's mass divided by its volume is that determines its density.The Jovian planets lack solid surfaces, in contrast to the terrestrial planets that make up our inner solar system—Mercury, Venus, Earth, and Mars. They are made mostly of hydrogen and helium instead, with minute amounts of other gases like methane, ammonia, water, and others in their atmospheres.
Terrestrial planets formed from metal and rock-based planetesimals, but they were ultimately too small to hold much of the solar nebula's rich hydrogen and helium gas. The Jovian planets, on the other hand, originated distant from the Sun where there were abundant ices and rocks.
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science class is conducting an investigation to see how gravity affects objects of different masses. They drop three balls from the same height. They
me how long it takes the balls to hit the ground. What are the students comparing? (1 point)
O the time it takes for each ball to fall
O the height from which each ball is dropped
O the gravitational attraction of each ball
O the mass of each ball
Answers
Answer:
the gravitational attraction of each ball, so technically the others too lol
Explanation: If it isn't already obvious, the hammer will fall to the ground more quickly than the feather, and since there is no air resistance the most logical answer would be A
2) Calculate the Energy of each of the following
a) Radio waves with a wavelength of 3.0 x 10¹¹ nm (6.626 x 10-28 J)
b) Microwaves with a wavelength of 3.0 x 107 nm (6.626 x 10-24 J)
c) X-Ray at 1nm (1.99 x 10-¹6J)
d) Violet at 400nm (4.97 x 10-¹⁹ J)
e) Red at 700nm (2.84 x 10-¹⁹J)
f) Gamma rays at 1nm (1.98 x 10-¹6J)
Answers
The energy, E of the given waves are as follows:
a. Energy, E = 6.63 * 10⁻²⁸ J
b. Energy, E = 6.63 * 10⁻²⁴ J
c. Energy, E = 1.99 * 10⁻¹⁶ J
d. Energy, E = 4.97 * 10⁻¹⁹ J
e. Energy, E = 2.84 * 10⁻¹⁹J
f. Energy, E = 1.99 * 10⁻¹⁶ J
What is the formula to calculate the energy of a wave?The formula to calculate the energy of a wave s given below as follows:
Energy, E = hc / λwhere;
h is Planck's constant = 6.63 * 10⁻³⁴ Js
c is the velocity of light = 3.0 * 10⁸ m/s
λ is the wavelength of the light
The energies of the waves are calculated as follows:
a. λ = 3.0 x 10¹¹ nm or 3.0 * 10² m
E = 6.63 * 10⁻³⁴ * 3.0 * 10⁸ / 3.0 * 10²
E = 6.63 * 10⁻²⁸ J
b. λ = 3.0 x 10⁷ nm or 3.0 x 10⁻² m
E = 6.63 * 10⁻³⁴ * 3.0 * 10⁸ / 3.0 * 10⁻²
E = 6.63 * 10⁻²⁴ J
c. λ = 1 nm or 1.0 x 10⁻⁹ m
E = 6.63 * 10⁻³⁴ * 3.0 * 10⁸ / 1.0 x 10⁻⁹ m
E = 1.99 * 10⁻¹⁶ J
d. λ = 400 nm or 4.0 x 10⁻⁷ m
E = 6.63 * 10⁻³⁴ * 3.0 * 10⁸ / 4.0 x 10⁻⁷ m
E = 4.97 * 10⁻¹⁹ J
e. λ = 700 nm or 7.0 x 10⁻⁷ m
E = 6.63 * 10⁻³⁴ * 3.0 * 10⁸ / 7.0 x 10⁻⁷ m
E = 2.84 * 10⁻¹⁹J
f. λ = 1 nm or 1.0 x 10⁻⁹ m
E = 6.63 * 10⁻³⁴ * 3.0 * 10⁸ / 1.0 x 10⁻⁹ m
E = 1.99 * 10⁻¹⁶ J
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An SUV crashes into a wall. The mass of the vehicle is 2,150 kg and the crumple zone rigidity is 342 kN. Assuming the safety cell is perfectly rigid, what will be the acceleration of the SUV during a crash as the crumple zone is collapsing?
Answers
The acceleration of the SUV during crash as the crumple zone is collapsing is 0.0063 m/s².
What is acceleration?Acceleration is the ratio of the force on a body to the mass of the body.
To calculate the acceleration of the SUV, we use the formula below.
Formula:
F = ma............ Equation 1Where:
F = Crumple zone rigiditym = Mass of the vehiclea = Acceleration of the SUVMake a the susbject of the equation
a = F/m................. Equation 2From the question,
Given:
m = 2150 kgF = 342 kN = 342000 NSubstitute these values into equation 2
a = 2150/342000a = 0.0063 m/s²Hence, the acceleration of the SUV is 0.0063 m/s².
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In the article the study author recommends going on a photo hunt what was the purpose of this activity with choices becoming less introvered
Becoming less neurotic
Becoming more extroverted
Becoming more assertive
Answers
In the article the study author recommends going on a photo hunt and the purpose of this activity is Becoming more assertive.
What is the reason why the author gave the recommedation about going for the photo hunt ?The reason why the author gave the recommedation about going for the photo hunt is that the activity can bring about assertiveness which has not been seen in the participants before.
It should be noted that with the assertion, there will be display of confident as well as forceful personality as they are taking part in the photo hunt, because it involves the activity whereby the participants will be competing with themselves in the collection of the greatest number of objects which is been goteen from the predetermined list.
In conclsion, the recomedation about going to the photo hunts by te author was made so that they can become more assertive.
Therefore , the last option is correct.
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A 5 -kg ball hangs at one end of a string that is attached to a support on a railroad boxcar. When the boxcar
accelerates to the right, the string makes an angle of 30° with the vertical. The acceleration of gravity is 9.8 m/s
and air resistance is negligible. Find the acceleration of the boxcar
Answers
The acceleration of the boxcar is 5.586m/s².
Explain what an acceleration is.We refer to any process where the velocity changes as acceleration. You can only accelerate by changing your speed, direction, or both since velocity is a function of both speed and direction.
Positive acceleration is a property of objects that are accelerating and moving in the right direction. In the first illustration, positive acceleration was demonstrated by the moving car. The acceleration is occurring in the same direction that the vehicle is moving forward and accelerating.
θ = ma/mg
tanθ = a/g
a = tanθ g
a = tan 30×9.8
a = 0.57×9.8
a = 5.586m/s².
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Consider a wooden cylinder of density 0.75g/cm³ floating in water with its axis perpendicular to the surface and the height is 15cm. How much of the cylinder will be under water?. If the radius were 10cm, how much would be under water? Suppose the cylinder is completely submerged and anchor in the water by a string, for the cylinder nof 10cm radius, what will be the force on the string?. Where g=9.8m/s, density of water=1g/cm³.
Answers
6923 N is the force on the string, Where g=9.8m/s, density of water=1g/cm³.
volume=2πrh
volume= 942 cm³
density= mass/volume
mass=density× volume
mass=0.75g/cm³× 942 cm³
mass=706 kg
F= mg
F=706×9.8
F= 6923 N
Every action that attempts to maintain, modify, or change the motion of a body is referred to as a force in mechanics. In his Principia Mathematica, Isaac Newton frequently used his three laws of motion to demonstrate the concept of force (1687).
According to Newton's first law, a body will remain in either its resting or equally moving condition along a straight route in the absence of an external force. The second law states that when an external force acts on a body, the body accelerates (changing velocity) in the direction of the force.
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2. The total mass of a boy and his bike is 45 kg. The boy rides his bike at a velocity of -5.0 m/s. What is
the boy's momentum?
Answers
The correct answer is momentum of boy = 225 Kg. m /s
What is momentum?
Momentum is the product of the units of mass and velocity is the unit of Momentum.
To get the value the momentum, formula: P=mv, where P is the momentum.
Given, total mass and boy = 45 Kg., Velocity = -5 m/s
Momentum = Mass x Velocity = 45 Kg. x 5 m/s = 225 Kg. m / s
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Astronauts in training are subjected to extreme acceleration forces by the centripental forces in againt centrifuge the radius of the centrifuge appriximately 5m calculate the approximate centripetal force on an astronaut of mass 80Kg if the centrifuge rotates once every 2s
Answers
The approximate centripetal force on an astronaut of mass 80Kg if the centrifuge rotates once every 2s is 3.94 KN
ac = v² / r
v = 2 π r / T
ac = Centripetal acceleration
v = Linear / Tangential velocity
T = Time period
r = Radius
r = 5 m
T = 2 s
v = 2 * 3.14 * 5 / 2
v = 15.7 m / s
ac = 15.7 * 15.7 / 5
ac = 49.298 m / s²
Fc = m ac
m = Mass
m = 80 kg
Fc = 80 * 49.298
Fc = 3943.8 N
Fc = 3.94 KN
Therefore, the approximate centripetal force on the astronaut is 3.94 KN
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If I wanted to increase the current, but maintain the voltage in a USB 3.1 port that provides a current of 0.9 A and a voltage of 5 V, to which I have connected a device with 4 ohms of resistance, how would I have to associate several USB ports to achieve this?
Answers
To achieve an increase in the current delivered in the USB 3.1 port, at a constant voltage, the several USB ports must be connect in parallel to each other. This will ensure an increase in current and constant voltage.
What is the relationship between current and resistance?According to ohms Law the current flowing through an ohmic conductor is directly proportional to the voltage across the conductor.
V = IR
where;
I is the current in the circuitR is the resistance across the circuitV is the voltage across the circuitI = V/R
To increase the current at a constant voltage, the resistance must decrease.
In a parallel circuit, the current flowing in each circuit component is different while the voltage drop in each circuit component is the same.
Thus, to increase the current delivered in the USB port, and maintain the initial voltage, the several USB ports must be connect in parallel to each other.
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What does an old sandwich rotting in a trashcan and building a tower out of magnetic blocks have in common
Answers
An old sandwich rotting in a trashcan and building a tower out of magnetic blocks both are undergoing chemical changes.
What are chemical changes?Chemical changes are said to occur when a substance combines with another to form a new substance, called chemical synthesis or, alternatively, chemical decomposition into two or more different substances.
Examples of chemical changes include burning of wood, cooking of pasta, rusting of metal , and rotting of sandwiches.
In conclusion, chemical changes involve the formation of new substances while Physical change is a temporary change.
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Two objects have a gravitational force of attraction to each other, equal to 10 Newtons. What is their gravitational force if the distance between them is halved?
I have the answer, however I do not know how to get to it. Please explain.
Answers
The gravitational force when the distance between them is halved is 40 N
How to determine the gravitational force?Newton's law of universal gravity states as follow:
F = GM₁M₂ / r²
Where
F is the force of attraction K is the electrical constant M₁ and M₂ are the masses of the objects r is the distance apartFinding a relationship between force and distance, the following were obtained:
F = GM₁M₂ / r²
Cross multiply
Fr² = GM₁M₂
GM₁M₂ = constant
F₁r₁² = F₂r₂²
Now, we can obtain the new gravitational force of as illustrated below:
Initial gravitational force (F₁) = 10Initial distance (r₁) = rNew distance (r₂) = 1/2r = 0.5rNew gravitational force (F₂) =?F₁r₁² = F₂r₂²
10 × r² = F₂ × (0.5r)²
10r² = F₂ × 0.25r²
Divide both side by 0.25r²
F₂ = 10r² / 0.25r²
F₂ = 10 / 0.25
F₂ = 40 N
Thus, the gravitaional force is 40 N
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Which has the most momentum?
C: 150 g object at 5 m/s
D: 200 kg object at 2 m/s
A: 50 kg object at 5 m/s
B: 100 kg object at 10 m/s
Answers
Option D) 200 kg object at 2 m/s has the highest momentum.
What is momentum?
Momentum is calculated using Newtonian mechanics by multiplying an object's mass by its velocity.As a vector quantity with both a magnitude and a direction, it has both. Considering that an object's mass is m and its speed is v (also a vector quantity),Momentum formula, P = mv
p = momentum
m = mass \ velocity
The newton-second is a unit of measurement for momentum in the International System of Units (SI), and the kilogram metre per second (kg m/s) is its SI counterpart.
A) 50 kg object at 5 m/s
m = 50 kg
v = 5 m/s
Momentum, p = m x v
= 50 x 5
= 250 kg m/s
B) 100 kg object at 10 m/s
m = 100 kg
v = 10 m/s
Momentum, p = m x v
= 100 x 10
= 1000 kg m/s
C) 150 g object at 5 m/s
m = 150 g
= 0.15 kg
v = 5 m/s
Momentum, p = m x v
= 0.15 x 5
= 0.75 kg m/s
D) 200 kg object at 2 m/s
m = 200 kg
v = 2 m/s
Momentum, p = m x v
= 200 x 2
= 400 kg m/s
Hence, Option B has the highest momentum.
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what is the work done by a 20 newton force applied at an angle of 45.0° to move a box horizontal distance of 40 meters
Answers
The work done by a 20-newton force applied at an angle of 45.0° is 565.69 J.
Calculation:-
Force = 20 N
distance = 40 meters
angle = cos 45°
Work done = F.d cosθ
= 20×40 × 1/√2
= 800 / √2
= 565.69 J
Force is a push or pulls upon an item because of the object's interaction with some other object. pressure is a power that can exchange the motion of an object. A force can reason an object with mass to alternate its speed, i.e., to boost up. pressure also can be described intuitively as a push or a pull. A force has each significance and course, making it a vector amount.
The phrase 'Force' has a unique meaning. At this degree, it is absolutely appropriate to describe a force as a push or a pull. A force is not something that an object consists of or 'has in it. A force is exerted on one object through another. The concept of a force isn't always restricted to living matters or non-living matters.
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Part G
List several examples of applied force, normal force, and friction?
Answers
Examples of following forces mentioned -
Normal Force :- Book kept on the table , Girl standing on floor, ...infact every object experience a normal force in the universe.Applied Force :- this term literally means force responsible for the movements in the object or changes in the object , like throwing stones , playing ball , pushing an object , moving a pen from desk to chair..etc...Friction force :-Force responsible for the resistance in the flow of system's work , For example air resistance a type of obstruction experienced in air when a Paper ball is thrown from terrace of a society , Viscosity of honey is also an example of liquid friction / viscous drag...Sometimes friction is useful for the stability of universe. But some times its necessary. It is due to this force we walk without collapsing into the core of earth as earth is a market of gravitational field. To substantiate the field effect , friction is necessary to necessitate the life in planet. Rubbing of hands in winter season is also another example.To Know more about different forces -
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If the maximum tension the rope can with- stand before breaking is 132.3 N, what is the maximum tangential speed the ball can have?
Answer in units of m/s.
Answers
The Maximum tangential speed the ball can have would be = 5.3m/s.
What is tangential speed?A tangential speed is defined as the speed of an object that has an angular velocity with respect to an instantaneous velocity.
The formula used to calculate the maximum tension;
T = mv²/r
Where T = Maximum tension = 132.3N
M = mass= 4kg
r = radius = 0.86m
V= tangential speed = x
Make v the subject of formula;
V = √Tr/m
V = √ 132.3 × 0.86/4
V = √113.778/4
V= √28.4445
V = 5.3 m/s.
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Complete question:
An athlete swings a 4.00 kg ball horizontally on the end of a rope. The ball moves in a circle of radius 0.860 m at an angular speed of 0.660 rev/s. If the maximum tension the rope can withstand before breaking is 132.3 N, what is the maximum tangential speed the ball can have?