Blood is maintained at a pH of 7.4 by the primary buffers in the plasma and secondary buffers in the erythrocytes. The plasma contains carbonic acid/bicarbonate as one of its primary buffers. The pK for this buffer system is 6.3. H2CO3 → H+ + HCO3-Required:What is the ratio of bicarbonate to carbonic acid in normal blood plasma?

Answers

Answer 1

Answer:

74.456.6.4.7.5.3.33-6.57

Explanation:


Related Questions

What volume is show in this picture?

Answers

Answer:

millileter????

MgSO4(aq) + 2NaOH(aq) Mg(OH)2(s) + Na2SO4(aq) i. Write the complete ionic equation from the balanced equation. (3 points) Please help!

Answers

Answer:

Mg²⁺(aq) + SO₄²⁻(aq) + 2Na⁺(aq) + 2OH⁻(aq) → Mg²⁺(aq) + 2OH⁻(s) + 2Na⁺(aq) + SO₄²⁻(aq)

Explanation:

The complete ionic equation is the chemical equation where the chemical species in the aqueous phase (aq) are written as ions.

In the reaction:

MgSO₄(aq) + 2NaOH(aq) → Mg(OH)₂(s) + Na₂SO₄(aq)

MgSO₄ dissociates in Mg²⁺ and SO₄²⁻, NaOH in Na⁺ and OH⁻, Mg(OH)₂ doesn't dissociate because is as solid and NaSO₄ dissociates in Na⁺ and SO₄²⁻ ions.

That means the complete ionic equation is:

Mg²⁺(aq) + SO₄²⁻(aq) + 2Na⁺(aq) + 2OH⁻(aq) → Mg²⁺(aq) + 2OH⁻(s) + 2Na⁺(aq) + SO₄²⁻(aq)

if a mixture of 90 g of hydrogen sulfide and 70.5 g of chromium oxide are allowed to raeact what mass of water can be formed

Answers

Answer:

24.84 g

Explanation:

The balanced reaction equation is;

Cr2O3(s) + 3H2S(g) ⟶Cr2S3(s) + 3H2O(l)

We must first determine the limiting reactant

For chromium III oxide;

Amount of chromium III oxide = mass/molar mass = 70.5g/ 151.99 g/mol = 0.46 moles

If 1 mole of chromium III oxide yields 3 moles of water

0.46 moles of chromium III oxide yields 0.46 × 3 = 1.38 moles of water

For hydrogen sulphide

Amount of hydrogen sulphide = mass/molar mass = 90g/ 34 gmol-1 = 2.64 moles

If 3 moles of H2S yields 3 moles of water

2.64 moles of H2S yields 2.64 × 3/3 = 2.64 moles of water

Hence chromium III oxide is the limiting reactant.

Mass of water produced= 1.38 moles × 18gmol-1= 24.84 g

14 oz (ounces) is the same as how many lbs (pounds)?

Answers

Answer:

0.875 Pounds

Explanation:

Formula  is

Just divide the mass value by 16

Calculate the pH and the pOH of an aqueous solution that is 0.020 M in HCl(aq) and 0.085 M in HBr(aq) at 25 °C.

Answers

[H+] = 0.030 + 0.085 = 0.115M
pH = -log(0.115) <<< use a calculator
pOH = 14 - pH <<< just subtract

pH(HCl) = 1.5 => pOH = 12.5
pH(HBr) = 1.1 => pOH = 12.9

define what is halflife​

Answers

Answer: the time taken for the radioactivity of a specified isotope to fall to half its original value.

Explanation:

Answer:

Half-life is the time required for a quantity to reduce to half of its initial value. The term is commonly used in nuclear physics to describe how quickly unstable atoms undergo, or how long stable atoms survive, radioactive decay.

Which of the following statements is not true for an exothermic reaction?a. The temp. of the surroundings increasesb. The temp of the reaction systems increasesc. The products have a higher heat content than the reactantsd. Heat passes from the reaction system to the surroundingse. The enthalpy change for the reaction is negative

Answers

Answer:

The products have a higher heat content than the reactants

Explanation:

Recall that the change in enthalpy for a reaction is obtained from

∆Hreaction= enthalpy of products - enthalpy of reactants

For an exothermic reaction, enthalpy of reactants > enthalpy of products, hence ∆Hreaction is negative.

This implies that the heat content of reactants is greater than that of products for an exothermic reaction. Hence the option selected in the answer is false as written.

How many significant figures are in the quantity 12.0 mL?
O A. 1
B. 2
C. 3
O D. 12

Answers

Answer:

C. 3

Explanation:

12.0 - 3 significant figures 1,2 and 0, because 0 is after decimal point.

What is the wavelength, in nanometers, of light with a frequency of 5.89 x 10¹⁴ s⁻¹?

Answers

Answer:

≅ 50, 909 nm

Explanation:

Wavelength, λ = [tex]\frac{speed}{freq}[/tex]

Given:

speed of light = [tex]3*10^{8} m/s[/tex]

f = 5.89 × [tex]10^{14}[/tex]

∴ λ = 3×[tex]10^{8}[/tex] / 5.89 × [tex]10^{14}[/tex]

= 0.0000509 m ≅ 50, 909 nm

Let me know if you need further assistance

Suppose you obtain 0.500 g of a compound after synthesis with the following solubility: In ethanol 4.24g/100 mL at 78 ⁰C and 0.30g/100 mL at 0 ⁰C. Performing recrystallization to purify the compound using 10 mL of ethanol, what would you expect the theoretical yield from the experiment to be? Show your calculations. (6 points)

Answers

Answer:

0.394g

Explanation:

At 78°C, you can dissolve, in 10mL of ethanol, 0.424g of the compound will dissolve. Then, you must filter the solution.

You take the filtrate of the solution in ethanol and cool it to 0°C. Om mL, only 0.03g of the compound will remain in solution. The other part is the purified compound.

Its mass (Theoretical yield) is:

0.424g - 0.030g =

0.394g

calculate the potential of the electrochemical cell and determine if it is spontaneous as written at

Answers

Hello. This question is incomplete. The full question is:

Calculate the potential of the electrochemical cell and determine if it is spontaneous as written at 25 ∘C . Cu(s) || Cu2+(0.14 M) ‖‖ Fe2+(0.0040 M) || Fe(s) E∘Cu2+/Cu=0.339 VE∘Fe2+/Fe=−0.440 V Ecell= V Is the electrochemical cell spontaneous or not spontaneous as written at 25 ∘C ? not spontaneous spontaneous

Answer:

Ecell = -0.825v

Negative results indicate that the electrochemical cell is not spontaneous.

Explanation:

You will find the result by doing the following calculation:

Cu2 + = 0.14M

Fe2 + = 0.0040M

Eº Cu2 + / Cu = 0.339V

Eº Fe2 + / Fe = -0.440V

Electron change ............ n = 2

Cu // Cu2 + (0.14M) // Fe2 + (0.0040M) / Fe (s)

Cu + Fe2 + ----> Fe (s) + Cu2 + (aq)

You should now use the formula =

Eºcell = Eº anode - Eº cathode ------> Eº = Eº (Fe2 + / Fe) - Eº (Cu2 + / Cu)

Eº Cell = -0.440 - 0.339 = -0.779V

E cell = EºCell - (0.0591 / n) log (Cu2 + / Fe2 +)

E cell = -0.779 - (0.0591 / 2) log (0.14 / 0.0040)

Ecell = -0.825

Why is a 9-v transistor battery used as the source of electrical power for electrolysis rather than the power supply that plugs into the wall electrical current?

Answers

Answer:

The 9-v transistor battery is a direct current source, while the power supply from the wall socket is an alternating current source.

Explanation:

A direct current (DC) is one that flows continuously without any minimum and maximum values. This is majorly obtained from generators, batteries or cells etc.

An alternating current (AC) is a type that flows in a sinusoidal manner, having minimum and maximum value with respect to its flowing frequency. An example is the one obtained from the wall electrical source , generators etc.

An alternating current is not mainly used for electrolysis because of its nature. It would cause a switch of the electrodes in every cycle. Therefore, a direct current source is used.

The 9-v transistor battery is a direct current source, while the power supply from the wall is an alternating current source.

Write the volume of the liquid, in milliliters, using the proper number of significant figures.Express your answer with the appropriate units.

Answers

Answer:

19.5 mL

Explanation:

For molecules with multiple ionizable groups, such as glycine, which of the following statements is true?1. At a pH near the pI, nearly all the molecules carry a net positive charge.2. At pH near the pI, nearly all the molecules carry no net charge.3. At a pH near the pI, nearly all the molecules carry a net negative charge.4. When the pH is near the pI, the solution is near its

Answers

Answer:

2. At pH near the pI, nearly all the molecules carry no net charge

Explanation:

The general equilibrium for a molecule with multiple ionizable groups could be:

H₃A⁺ ⇄ H₂A + H⁺ ⇄HA⁻ + H⁺⇄A²⁻ + H⁺

Where each equilibrium has its own pKa

The equilibriums in which H₂A are involved (The neutral molecule), are used to determine the isoelectrical point.

The isoelectrical point is defined as the value of pH in which the molecule has no net charge.

Thus, true option is:

2. At pH near the pI, nearly all the molecules carry no net charge

HELP! I WILL GIVE BRAINIEST AND 20 POINTS what is a hypothesis? give an example of a hypothesis

Answers

Answer:

By definition:

A supposition or proposed explanation made on the basis of limited evidence as a starting point for further investigation.A proposition made as a basis for reasoning, without any assumption of its truth.

Example:

If I study hard in school, I will get good grades.

Perform the calculation, rounding your answer to the proper number of significant figures.
0.8730 divided by 9.650 =

Answers

Answer:

Hey!

0.8730 / 9.650 = 8.42445

Explanation:

8.42445 TO 2 s.f... (best option for rounding)

= 8.4

ANSWER = 8.4 (2 s.f)

HOPE THIS HELPS!!

A reagent bottle contains a stock solution of 0.90% by mass of sodium chloride, NaCl.
The density of the solution is 1.00 g cm ?. Calculate
(i) the mole fraction of NaCl
(ii) the molality of NaCl solution
(111) the volume of the stock solution required to prepare 100 mL of 0.01 M NaCl
solution.​

Answers

Answer:

I. 2.79x10⁻³

II. 0.155m

III. 6.49mL of the solution you must add from the stock solution

Explanation:

A solution of 0.90% by mass NaCl means that, in 100g of solution, you have 0.90g of NaCl. In other words, there are 0.90g of NaCl + 99.1g of water.

I. Mole fraction of NaCl is the ratio between moles of NaCl and total moles of solution.

Moles NaCl:

0.90g * (1mol / 58.44g) = 0.0154 moles NaCl

Moles water:

99.1g water * (1mol / 18.01g) = 5.50 moles water.

Total moles = 5.50 +0.0154 moles = 5.518 moles

Mole fraction NaCl: 0.0154 / 5.518 moles =

2.79x10⁻³

II. Molality is the ratio between moles of solute (NaCl) and kg of solvent.

There are 99.1g of water = 0.0991kg.

Molality is: 0.0154 moles / 0.0991kg

0.155m

II. 100mL of a 0.01M are:

100mL = 0.100L * (0.01 mol / L) = 1x10⁻³ moles of NaCl

In 100g = 100mL (Density of 1g/mL) there are 0.0154 moles. To have 1x10⁻³ moles you need:

1x10⁻³ moles of NaCl * (100mL / 0.0154 moles) =

6.49mL of the solution you must add from the stock solution

I. Mole fraction of NaCl is 2.79x10⁻³

II. Molarity of NaCl solution is 0.155m

III. 6.49mL of the stock solution required to prepare 100 mL of 0.01 M NaCl  solution.​

What does % by mass mean?

A solution of 0.90% by mass NaCl means that, in 100g of solution, you have 0.90g of NaCl.

Or

There is 0.90g of NaCl + 99.1g of water.

We need to find:

I. Mole fraction of NaCl:

Mole fraction can is the ratio of moles of Solute  to the total number of moles of the solutes and the solvent.

Moles of  NaCl(solute) = 0.90g * (1mol / 58.44g) = 0.0154 moles NaCl

Moles of  water(solvent) = 99.1g water * (1mol / 18.01g) = 5.50 moles water.

Total moles = 5.50 +0.0154 moles = 5.518 moles

Mole fraction of NaCl =  [tex]\frac{0.0154}{ 5.518} =2.79 * 10^{-3}[/tex]

II. Molality is a measure of the number of moles of solute(NaCl) in a solution corresponding to 1 kg or 1000 g of solvent

Since, 99.1g of water = 0.0991kg.

Molality of NaCl = [tex]\frac{0.0154 moles}{0.0991 kg}=0.155m[/tex]

III. 100mL of a 0.01M is:

100mL = 0.100L * (0.01 mol / L) = 1x10⁻³ moles of NaCl

In 100g = 100mL (Density of 1g/mL) there are 0.0154 moles. To have 1x10⁻³ moles you need:

1x10⁻³ moles of NaCl * [tex]\frac{100 mL}{0.0154 moles}[/tex] = 6.49mL of the solution you must add from the stock solution

Learn more:

https://brainly.com/question/15063496

identify balance chemical equation from the following
C+O2=CO2
H2+O2=H2O
2PbO+C=Pb+CO2
Fe2O3+2Al=Al2CO3+2Fe​

Answers

Answer:

C+O2=CO2

Explanation:

no.of atoms on reactant side= no.of atoms on product side

how can chemistry help solve a crime ?
plz helppp

Answers

Chemistry is vital in forensic science (used to solve crimes). With chemistry, forensic scientists demonstrate what happened on a molecular level. Chemical analysis can reveal how long ago a person died, what weapon was used, the kind of tape or rope used to tie someone up, etc. They also analyze drugs/controlled substances taken from scenes and people to identify and sometimes quantify these materials.

Is a Animal and Plant cell living

Answers

Yes Animal and plant are cell living

Imagine that you're doing an experiment to determine how the running speed
of a hamster depends on the weight of the hamster. When plotting your data,
what variable should be on the y-axis?
A. Speed of hamster
B. Color of hamster
C. Weight of hamster
D. Type of hamster

Answers

C.) Weight of the hamster
C. Weight of a hamster

Using standard reduction potentials from the ALEKS Data tab, calculate the standard reaction free energy for the following redox reaction. Round your answer to significant digits. N2H4 + 4OH + 2Cl2

Answers

Answer:

-973 KJ

Explanation:

The balanced reaction equation is;

N2H4(aq) + 2Cl2(g) + 4OH^-(aq)---------> 4Cl-(aq) + 4H ^+(aq) + 4OH^-(aq) + N2(g)

Reduction potential of hydrazine = -1.16 V

Reduction potential of chlorine = 1.36 V

From;

E°cell= E°cathode - E°anode

E°cell= 1.36 - (-1.16)

E°cell= 2.52 V

∆G°=- nFE°cell

n= number of moles of electrons = 4

F= Faraday's constant = 96500 C

E°cell = 2.52 V

∆G°=- (4 × 96500 × 2.52)

∆G°= -972720 J

∆G°= -972.72 KJ

A statement that can be proven by observation or measurement is known as a(n):
a.
opinion
b.
value
c.
fact
d.
belief


Please select the best answer from the choices provided

A
B
C
D

Answers

The correct answer for this question is that a statement that can be proven by observation or measurement is known as a fact. The other possible answers here simply refer to idea that different individuals can place value on, but that are not necessarily known to be true.

A technician is installing a liquid cooling system for a high-end gaming PC. Which of the following liquids is MOST likely used for cooling?A. Iodine
B. Mercury
C. Thermal paste
D. Oil

Answers

The most likely liquid would be D

How many L are in 0.74 CL ?

Answers

Answer:

0.0074 cL

7.4 x 10⁻³ cL

Explanation:

Step 1: Find conversion

1 liter (L) = 100 centiliters (cL)

Step 2: Set up dimensional analysis

[tex]0.74cL(\frac{1L}{100cL} )[/tex]

Step 3: Multiply and cancel out units

cL and cL cancel out.

We are left with L.

0.74/100 = 0.0074 cL or 7.4 x 10⁻³ cL

nder what reaction conditions does the electrophilic chlorination of aromatic compounds usually occur

Answers

Answer:

Cl2/FeCl3

Explanation:

The electrophilic chlorination of aromatic compounds proceeds in the presence of Cl2/FeCl3.

The function of the Lewis acid FeCl3 is to 'activate' the chlorine molecule towards electrophilic substitution. This occurs by the formation of a 'chlorine cation' which attacks the aromatic ring followed by deprotonation of the aromatic ring to retain the aromaticity of the compound.

The change that happen the piece of paper during the burning process?​

Answers

Answer:  Chemical

Explanation:

When paper is burned, it creates a chemical change.

Answer:

Explanation:

Hey, there!!

The answer is chemical change.

When the paper is burned it changes into an ash. Which is a chemical change. { as it can't be reversed }.

Hope it helps...

Convert 1,650,000 centimeters to kilometers.

Answers

Answer:

16.5

Explanation:

Answer:

is your answer is 16.5 km

Which ester, when treated with NaOEt, gives this Claisen condensation product? 1. (CH_3)_2CHCH_2CO_2CH_2CH_3 2. (CH_3)_2CHCH_2CH_2CO_2CH_2CH_3 3. (CH_3)_2CHCH_2CH_2CH_2CO_2CH_2CH_3 4. CH_3CH_2CH(CH_3)CH_2CO_2CH_2CH_3

Answers

Answer:

( CH_3) _2CHCH_2CH_2CO_2CH_2CH

he solubility of oxygen gas in water at 25 °C and 1.0 atm pressure of oxygen is 0.041 g/L. The solubility of oxygen in water at 2.5 atm and 25 °C is ________ g/L.

Answers

Answer:

0.1025 g/L

Explanation:

From the question above,

The solubility of oxygen gas in water at 25°c and 1.0 atm pressure is 0.041g/L

Henry's law states at a constant temperature the solubility of a gas is proportional to the pressure

Since the temperatures are both similar (25°c) then, the solubility of oxygen in water at 2.5 atm can be calculated as follows

= 0.041/1.0 × 2.5

= 0.041×2.5

= 0.1025 g/L

Hence the solubility of oxygen in water at 2.5 atm and 25°c is 0.1025 g/L

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