On dividing polynomial p(x) by a linear binomial, X - a, we get a quotien
statements must be proven true for the remainder theorem to be true

Answer:

c=80

Step-by-step explanation:

Based on my reading the critical damping occurs when the discriminant of the quadratic characteristic equation is 0.

So let's see that characteristic equation:

20⁢r^2+c⁢r+80⁢=0

The discriminant can be found by calculating b^2-4aC of ar^2+br+C=0.

a=20

b=c

C=80

c^2-4(20)(80)

We want this to be 0.

c^2-4(20)(80)=0

Simplify:

c^2-6400=0

Add 6400 on both sides:

c^2=6400

Take square root of both sides:

c=80 or c=-80

Based on further reading damping equations in form

a⁢y′⁢′+b⁢y′+C⁢y=0

should have positive coefficients with b also having the possibility of being zero.

Answer:

[tex]x = 7[/tex]

Step-by-step explanation:

We can solve the equation [tex]5x+3+8x-4=90[/tex] by isolating the variable x on one side. To do this, we must simplify the equation.

[tex]5x+3+8x-4=90[/tex]

Combine like terms:

[tex]13x - 1 = 90[/tex]

Add 1 to both sides:

[tex]13x = 91[/tex]

Divide both sides by 13:

[tex]x = 7[/tex]

Hope this helped!

Answer:

x = 7

Step-by-step exxplanation:

5x + 3 + 8x - 4 = 90

5x + 8x = 90 - 3 + 4

13x = 91

x = 91/13

x = 7

probe:

5*7 + 3 + 8*7 - 4 = 90

35 + 3 + 56 - 4 = 90

Answer:

288 ft³

Step-by-step explanation:

Volume of the pyramid,

base area × height × (1/3)

= (9×8)×12/3

= 72×4

= 288 ft³

Answer:

16 ft

Step-by-step explanation:

Each edge of wall = √256 ft = 16 ft

Answer:

(9,4) and (12,5)

Step-by-step explanation:

x-3y=-3

Complete Question

Find the indicated area under the curve of the standard normal​ distribution, then convert it to a percentage and fill in the blank.

About_____% of the area is between z = - 2.2 and z = 2.2 (or within 2.2 standard deviations of the mean).

About_____% of the area is between z = - 2.2 and z = 2.2 (or within 2.2 standard deviations of the mean).

Answer:

About 97.219% of the area is between z = - 2.2 and z = 2.2 (or within 2.2 standard deviations of the mean).

Step-by-step explanation:

From the question given we can see that they both are the same so 1  will just solve one

   Now the area under this given range can be represented mathematically as

  [tex]P ( -2.2 < z < 2.2) = P(z < 2.2 ) - P(z < -2.2 )[/tex]

Now  from the z-table  

        [tex]p(z < 2.2 ) = 0.9861[/tex]

and

        [tex]p(z < - 2.2 ) = 0.013903[/tex]

So

     [tex]P ( -2.2 < z < 2.2) = 0.9861 - 0.013903[/tex]

     [tex]P ( -2.2 < z < 2.2) = 0.97219[/tex]

So converting to percentage  

     [tex]P ( -2.2 < z < 2.2) = 0.97219 * 100[/tex]

    [tex]P ( -2.2 < z < 2.2) = 97.219 \%[/tex]

Answer:

Hey there!

Point K has coordinates of (-2, -5)

Hope this helps :)

Answer:

Point K

Step-by-step explanation:

Since they're asking us to find (-2,-5) first we need to move 2 points to the left and then 5 points down.

Answer:

Yes , it satisfies the hypothesis and  we can conclude that c = 1 is an element of [0,2]

c = 1 ∈ [0,2]

Step-by-step explanation:

Given that:

[tex]f(x) = 4x^2 -3x + 2, [0, 2][/tex]

which is read as the function of x = 4x² - 3x + 2 along the interval [0,2]

Differentiating the function with respect to x is;

f(x) = 8x - 3

Using the Mean value theorem to see if the function satisfies it, we have:

[tex]f'c = \dfrac{f(b)-f(a)}{b-a}[/tex]

[tex]8c -3 = \dfrac{f(2)-f(0)}{2-0}[/tex]

since the polynomial function is differentiated in [0,2]

[tex]8c -3 = \dfrac{(4(2)^2-3(2)+2)-(4(0)^2-3(0)+2)}{2-0}[/tex]

[tex]8c -3 = \dfrac{(4(4)-3(2)+2)-(4(0)-3(0)+2)}{2-0}[/tex]

[tex]8c -3 = \dfrac{(16-6+2)-(0-0+2)}{2-0}[/tex]

[tex]8c -3 = \dfrac{(12)-(2)}{2}[/tex]

[tex]8c -3 = \dfrac{10}{2}[/tex]

8c -3  = 5

8c = 5+3

8c = 8

c = 8/8

c = 1

Therefore, we can conclude that c = 1 is an element of [0,2]

c = 1 ∈ [0,2]

Answer:

.02

Step-by-step explanation:

2 is in "Hundredths' place in .826

So, the number is multiplied with 1/100 or .01

=> 2 x 1/100

=> 2/100

=> .02

=> 2 x .01

=> .02

The value of 2 in .826 is .02

Answer:

The probability that the box will contain less than the advertised weight of 453 g is 0.00034.

Step-by-step explanation:

Let X represent the weight (in grams) of cereal in a box of Lucky Charms.

It is provided that X follows a Normal distribution with parameters, μ = 470 and σ = 5.

Compute the probability that the box will contain less than the advertised weight of 453 g as follows:

[tex]P(X<453)=P(\frac{X-\mu}{\sigma}<\frac{453-470}{5})[/tex]

                  [tex]=P(Z<-3.4)\\=0.00034[/tex]

*Use the z-table.

Thus, the probability that the box will contain less than the advertised weight of 453 g is 0.00034.

Answer:

y = -4x - 6.

Step-by-step explanation:

We are given (-5, -3), (-1, -2), and (3, -1) for points of a line. First, we need to find the slope.

(-2 - -3) / (-1 - -5) = (-2 + 3) / (-1 + 5) = 1 / 4.

A perpendicular bisector would have a slope of -4, which is the negative reciprocal of 1/4.

Now that we have the slope, we can say that the equation is y = -4x + b. To find what is b, we can say that y = -2 and x = -1.

-2 = -4(-1) + b

-2 = 4 + b

b + 4 = -2

b = -6

So, the equation of the perpendicular bisector is y = -4x - 6.

Hope this helps!

Answer:

y = -4x - 6.

Step-by-step explanation:

Just took the test and got it right

Answer:

Base area=5*12=60

Height is 4

Perimeter or the base is 2*(12+5)=34

Surface area is 2B+Ph=120+136=256

Answer:

26.75 units²

Step-by-step explanation:

This shape can be split into 3 triangles and a square. Find the area of each shape then add them all up.

[tex]A(Square)=2(2)=4\\\\A(Triangle)=\frac{1}{2}(2)(2)=2\\\\A(Triangle)=\frac{1}{2}(5)(2)=5\\\\A(Triangle)=\frac{1}{2}(9)(3.5)=15.75\\\\A(Shape)=4+2+5+15.75=26.75[/tex]

Therefore, the area of the shape is 26.75 units².

Answer:

A) 4x^2+20x+25=(2x)^2+2*(2x)*5+5^2=(2x+5)^2

Area=(side)^2, side=sqrt(area)=sqrt((2x+5)^2)=2x+5

B) 4x^2-9y^2=(2x-3y)(2x+3y), these are the dimensions of the rectangle

A) The length of each side of the square is (2x + 5).

B) The dimensions of the rectangle are (2x - 3y) and (2x + 3y).

Used the concept of a quadratic equation that states,

An algebraic equation with the second degree of the variable is called a Quadratic equation.

Given that,

Part A: The area of a square is [tex](4x^2 + 20x + 25)[/tex] square units.

Part B: The area of a rectangle is [tex](4x^2 - 9y^2)[/tex] square units.

A) Now the length of each side of the square is calculated by factoring the area expression completely,

[tex](4x^2 + 20x + 25)[/tex]

[tex]4x^2 + (10 + 10)x + 25[/tex]

[tex]4x^2 + 10x + 10x + 25[/tex]

[tex]2x (x + 5) + 5(2x + 5)[/tex]

[tex](2x + 5) (2x+5)[/tex]

Hence the length of each side of the square is (2x + 5).

B) the dimensions of the rectangle are calculated by factoring the area expression completely,

[tex](4x^2 - 9y^2)[/tex]

[tex](2x)^2 - (3y)^2[/tex]

[tex](2x - 3y) (2x + 3y)[/tex]

Therefore, the dimensions of the rectangle are (2x - 3y) and (2x + 3y).

To learn more about the rectangle visit:

https://brainly.com/question/2607596

#SPJ4

Answer:

+3.464; -3.464

Step-by-step explanation:

call A = y + 2x + 1 = 0 => y = (1 - 2x)

call B: 4y - 4(x^2) - 12x = -7

=> replace y from A to B =>

=> get delta Δ = (-4^2) - 4*(-4 * 11) = 192

=> Δ > 0 => got 2 No

=> x1 = [tex]\frac{-4 + \sqrt{192} }{2 * -4}[/tex] = [tex]\frac{1 - 2\sqrt{3} }{2}[/tex] = -1.232

=> x2 = [tex]\frac{-4 - \sqrt{192} }{2 * -4}[/tex]=[tex]\frac{1 + 2\sqrt{3} }{2}[/tex]= 2.232

=> replace x from B into A

=> y1 = (1 - 2x) = (1 - 2 * -1.232) = 3.464

=> y2 = (1 - 2x) = (1 - 2 * 2.232) = - 3.464

Answer:

X-4x+11=8

-3x+12-8=0

-3x+4=0

3x=4

X=4/3

Answer:

x = 4/3 or 1.3

Step-by-step explanation:

Combine like terms

8 = -3x + 12

Move the terms

3x = 12 - 8

Calculate

3x = 4

Divide both sides by 3

x = 4/3

or

x = 1.3

Answer:

The number is - 14.5

Step-by-step explanation:

Let the number be x.

ATQ, 15+2x=-14, x=-29/2=-14.5

Answer:

1/9

Step-by-step explanation:

2/6*1/6=2*1/6*6 or 1/9.

Answer:

1/18

Step-by-step explanation:

1. multiply across

2*1 and 6*6

2/36

2. divide by 2 to simplify

2/2 and 36/2

1/18

Answer:

When all possible differences between pairs of population means are evaluated not with an F test, but with a series of regular t tests, the probability of at least one:

A. type I error is larger than the specified level of significance.

B. type II error is larger than the specified level of significance.

C. type I error is smaller than the specified level of significance.

D. type II error is smaller than the specified level of significance.

Answer :  Type I error is larger than the specified level of significance.( A )

Step-by-step explanation:

An F test is a test that is used to test whether the variances between pairs of populations are equal while a T test is a test used to check if a pair of population are equal not considering the fact that the variances of the population are different .

When a T test is used to evaluate all possible differences between pairs of population instead of F test there is a probability of atleast one type 1 error larger than the specified level of significance.

Answer:

Step-by-step explanation:

Take the beginning number and add or subtract each transaction to get a new balance. For example,

                  349.45

-     23.42 = 326.03

-     14.95  = 311.08

+   276.50 = 587.58

-    219.93 =  367.65

-       76.84 = 290.81

Answer:

2

Step-by-step explanation:

It is the only one that makes sense

Answer:

B

Step-by-step explanation:

The inequality will be 35000-320m>0

Answer:

Solution ( Second Attachment ) : - 2.017 + 0.656i

Solution ( First Attachment ) : 16.140 - 5.244i

Step-by-step explanation:

Second Attachment : The quotient of the two expressions would be the following,

[tex]6\left[\cos \left(\frac{2\pi }{5}\right)+i\sin \left(\frac{2\pi \:}{5}\right)\right][/tex] ÷ [tex]2\sqrt{2}\left[\cos \left(\frac{-\pi }{2}\right)+i\sin \left(\frac{-\pi \:}{2}\right)\right][/tex]

So if we want to determine this expression in standard complex form, we can first convert it into trigonometric form, then apply trivial identities. Either that, or we can straight away apply the following identities and substitute,

( 1 ) cos(x) = sin(π / 2 - x)

( 2 ) sin(x) = cos(π / 2 - x)

If cos(x) = sin(π / 2 - x), then cos(2π / 5) = sin(π / 2 - 2π / 5) = sin(π / 10). Respectively sin(2π / 5) = cos(π / 2 - 2π / 5) = cos(π / 10). Let's simplify sin(π / 10) and cos(π / 10) with two more identities,

( 1 ) [tex]\cos \left(\frac{x}{2}\right)=\sqrt{\frac{1+\cos \left(x\right)}{2}}[/tex]

( 2 ) [tex]\sin \left(\frac{x}{2}\right)=\sqrt{\frac{1-\cos \left(x\right)}{2}}[/tex]

These two identities makes sin(π / 10) = [tex]\frac{\sqrt{2}\sqrt{3-\sqrt{5}}}{4}[/tex], and cos(π / 10) = [tex]\frac{\sqrt{2}\sqrt{5+\sqrt{5}}}{4}[/tex].

Therefore cos(2π / 5) = [tex]\frac{\sqrt{2}\sqrt{3-\sqrt{5}}}{4}[/tex], and sin(2π / 5) = [tex]\frac{\sqrt{2}\sqrt{5+\sqrt{5}}}{4}[/tex]. Substitute,

[tex]6\left[ \left\frac{\sqrt{2}\sqrt{3-\sqrt{5}}}{4}+i\left\frac{\sqrt{2}\sqrt{5+\sqrt{5}}}{4}\right][/tex] ÷ [tex]2\sqrt{2}\left[\cos \left(\frac{-\pi }{2}\right)+i\sin \left(\frac{-\pi \:}{2}\right)\right][/tex]

Remember that cos(- π / 2) = 0, and sin(- π / 2) = - 1. Substituting those values,

[tex]6\left[ \left\frac{\sqrt{2}\sqrt{3-\sqrt{5}}}{4}+i\left\frac{\sqrt{2}\sqrt{5+\sqrt{5}}}{4}\right][/tex] ÷ [tex]2\sqrt{2}\left[0-i\right][/tex]

And now simplify this expression to receive our answer,

[tex]6\left[ \left\frac{\sqrt{2}\sqrt{3-\sqrt{5}}}{4}+i\left\frac{\sqrt{2}\sqrt{5+\sqrt{5}}}{4}\right][/tex] ÷ [tex]2\sqrt{2}\left[0-i\right][/tex] = [tex]-\frac{3\sqrt{5+\sqrt{5}}}{4}+\frac{3\sqrt{3-\sqrt{5}}}{4}i[/tex],

[tex]-\frac{3\sqrt{5+\sqrt{5}}}{4}[/tex] = [tex]-2.01749\dots[/tex] and [tex]\:\frac{3\sqrt{3-\sqrt{5}}}{4}[/tex] = [tex]0.65552\dots[/tex]

= [tex]-2.01749+0.65552i[/tex]

As you can see our solution is option c. - 2.01749 was rounded to - 2.017, and 0.65552 was rounded to 0.656.

________________________________________

First Attachment : We know from the previous problem that cos(2π / 5) = [tex]\frac{\sqrt{2}\sqrt{3-\sqrt{5}}}{4}[/tex], sin(2π / 5) = [tex]\frac{\sqrt{2}\sqrt{5+\sqrt{5}}}{4}[/tex], cos(- π / 2) = 0, and sin(- π / 2) = - 1. Substituting we receive a simplified expression,

[tex]6\sqrt{5+\sqrt{5}}-6i\sqrt{3-\sqrt{5}}[/tex]

We know that [tex]6\sqrt{5+\sqrt{5}} = 16.13996\dots[/tex] and [tex]-\:6\sqrt{3-\sqrt{5}} = -5.24419\dots[/tex] . Therefore,

Solution : [tex]16.13996 - 5.24419i[/tex]

Which rounds to about option b.

Answer:

Solution : Option B

Step-by-Step Explanation:

We have the following system of equations at hand here.

{ x = 5 cot(t), y = - 3csc(t) + 4 }

Now instead of isolating the t from either equation, let's isolate cot(t) and csc(t) --- Step #1,

x = 5 cot(t) ⇒ x - 5 = cot(t),

y = - 3csc(t) + 4 ⇒ y - 4 = - 3csc(t) ⇒ y - 4 / - 3 = csc(t)

Now let's square these two equations. We know that csc²θ - cot²θ = 1, so let's subtract the equations  as well. --- Step #2

( y - 4 / - 3 )² = (csc(t))²

- ( x - 5 / 1 )² = (cot(t))²  

___________________

(y - 4)² / 9 - x² / 25 = 1

And as we are subtracting the two expressions, this is an example of a hyperbola. Therefore your solution is option b.

The given equation is in the form ax^2+bx+c = 0 with

D = discriminant

D = b^2 - 4ac

D = 4^2 - 4(2)(1-3m)

D = 16 - 8(1-3m)

D = 16 - 8 + 24m

D = 24m + 8

D > 0

24m + 8 > 0

24m > -8

m > -8/24

m > -1/3

As long as m is larger than -1/3, then the discriminant is positive. There are infinitely many solutions to pick from.

Answer: 0.129

Step-by-step explanation:

Let [tex]\overline{X}[/tex] denotes a random variable that represents the mean weight of babies born.

Population mean : [tex]\mu= \text{3316 grams,}[/tex]

Standard deviation: [tex]\text{324 grams}[/tex]

Sample size = 83

Now, the probability that the mean weight of the sample babies would differ from the population mean by greater than 54 grams will be :

[tex]P(|\mu-\overline{X}|>54)=1-P(\dfrac{-54}{\dfrac{324}{\sqrt{83}}}<\dfrac{\overline{X}-\mu}{\dfrac{\sigma}{\sqrt{n}}}<\dfrac{-54}{\dfrac{324}{\sqrt{83}}})\\\\=1-[P(-1.518<Z<1.518)\ \ \ [Z=\dfrac{\overline{X}-\mu}{\dfrac{\sigma}{\sqrt{n}}}]\\\\=1-[P(Z<1.518)-P(z<-1.518)]\\\\=1-[P(Z<1.518)-(1-P(z<1.518))]\\\\=1-[2P(Z<1.518)-1]=2-2P(Z<1.518)\\\\=2-2(0.9355)\ [\text{By z-table}]\\\\=0.129[/tex]

hence, the required probability =  0.129

Answer:

the nearest hundred is 50

9514 1404 393

Answer:

  16 mi/h

Step-by-step explanation:

The time for a given leg of the trip is the distance divided by the speed. If t is the speed in traffic, the total trip time is ...

  16/t +47/(t+31) = 2

Multiplying by t(t+31), we get ...

  16(t +31) +47t = 2(t)(t+31)

  2t^2 -t -496 = 0 . . . . put in standard form

  (2t +31)(t -16) = 0 . . . . factor

The positive solution is t = 16.

Johhny's average speed in traffic was 16 mph.