solve using substitution:

4x- 2y = 6 and x + y = 6


solve using elimination:

4x- 2y = 6 and x + y = 6

[tex]\large\displaystyle\text{$\begin{gathered}\sf 6x+-2y^{2}+4xy^{2}+3x^{2} +5xy^{2} \end{gathered}$}[/tex]

[tex]\large\displaystyle\text{$\begin{gathered}\sf Group\:like\:terms \end{gathered}$}[/tex]

[tex]\large\displaystyle\text{$\begin{gathered}\sf =3x^2+6x-2y^2+4xy^2+5xy^2 \end{gathered}$}[/tex]

[tex]\large\displaystyle\text{$\begin{gathered}\sf Sum\:similar\:elements:\:4xy^2+5xy^2=9xy^2 \end{gathered}$}[/tex]

[tex]\boxed{\large\displaystyle\text{$\begin{gathered}\sf 3x^2+6x-2y^2+9xy^2 \end{gathered}$} }[/tex]

Answer:

To solve this problem we first subtract 3 from both sides, giving the inequality -cw+3-3<= 15-3. We then simplify the equation to -cw<= 12. Next, we divide both sides by -c and flip the inequality. We flip the inequality because we are dividing by a negative. Now we have the inequality -cw/-c >= 12/-c. Lastly, we simplify to w >= -12/c.

For a population where the distribution is unknown, the sampling distribution of the sample mean will be b which is approximately normal for all sample sizes.

Given options regarding sample sizes.

We have to choose the correct option which shows the sample mean characteristics when the distribution is unknown.

Based on the central limit theorem the sampling distribution of the sample mean for either skewed variable ir normally distributed variable can be approximated given the mean and standard deviation.

The central limit theorem is said to be  true when n greater than or equal to 30.

When n is greater than 30 ,z test is used, when n is less than 30 ,t test is used.

Hence for a population where the distribution is unknown ,the sampling distribution of the sample mean will be approximately normal for all sample sizes.

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Question is incomplete as it includes options in a right way:

1)exactly normal for large sample,

2) approximately normal for all sample sizes,

3) exactly normal for all sample sizes.

Answer: Read the explanation

Step-by-step explanation:

If the points of a figure are all moved the same, they are congruent.

Point A is moved 9 points right, and 7 points down.

Point B is moved 9 points right, and 7 points down.

Point C is moved 9 points right, and 7 points down.

So, they are congruent.

AB will be an Identity matrix.

As it is given in the description itself, if the answer to a matrix multiplication problem is an identity matrix, then each of the two matrices is an inverse matrix of the other.

Therefore, AB will be an Identity matrix.

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Answer:

AB= I

ABA=A

BBA=B

BBAA=I

Step-by-step explanation:

just took the test on edge. 2022

Answer:

Answer:

this graph has an x-intercept values of -1 and 2

Based on definition of unit circle and angle properties on Cartesian plane, we find the following results: A: π/5, B: 3π/7, C: 4π/3.

Units circles are commonly used to understand angles and trigonometric functions in a simple way. Vectors in a unit circle are ordered pairs of polar form: (x, y) = (cos θ, sin θ).

To solve this problem, we must take these tips into account:

Then, we have the following results: A: π/5, B: 3π/7, C: 4π/3.

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Answer: Option (4)

Step-by-step explanation:

From the diagram, we know that

[tex]\sin 60^{\circ}=\frac{BC}{15}\\\\\cos 60^{\circ}=\frac{AB}{15}[/tex]

This means we can eliminate options 1 and 2.

Now, if we multiply both sides by 15, we get

[tex]15\cos 60^{\circ}=7.5[/tex].

This gives us Option (4).

Answer:

Step-by-step explanation:

already

The equation of the graph is [tex]f(x) = -\sqrt{x -2[/tex]

The graph is added as an attachment

The form of the graph is

[tex]f(x) = a\sqrt{x + b[/tex]

The graph passes through the points (2, 0) and (6, -2).

So, we have:

[tex]0 = a\sqrt{2 + b[/tex] and [tex]-2 = a\sqrt{6 + b[/tex]

Solve for b in [tex]0 = a\sqrt{2 + b[/tex]

Divide both sides by a

[tex]0 = \sqrt{2 + b[/tex]

Square both sides

0 = 2 + b

Subtract 2 from both sides

b = -2

Substitute b = -2 in [tex]-2 = a\sqrt{6 + b[/tex]

[tex]-2 = a\sqrt{6 -2[/tex]

[tex]-2 = a\sqrt{4[/tex]

Evaluate the square root

-2 = 2a

Divide by 2

a = -1

Substitute b = -2 and a = -1 in [tex]f(x) = a\sqrt{x + b[/tex]

[tex]f(x) = -\sqrt{x -2[/tex]

Hence, the equation of the graph is [tex]f(x) = -\sqrt{x -2[/tex]

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Figure 1 was translated using the rule (x', y') ⇒ (x -9, y + 2) to produce figure 2.

Transformation is the movement of a point from its initial location to a new location. Types of transformation are translation, reflection, rotation and dilation.

Translation is the movement of a point either up, down, left or right on the coordinate plane.

Figure 1 was translated 9 units left and 2 units up using the rule (x', y') ⇒ (x -9, y + 2) to produce figure 2.

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During the month of May, there were 130 births, of which the newborn death rate is 38.4615.

According to the question,

There were 130 births, of which 127 were full-term births and three were premature births. There were five newborn deaths.

In order to find the newborn death rate we have the formula:

=  [tex]\frac{number of death under 28 days of age }{Total live births in the same year}[/tex]  × 1000

= [tex]\frac{5}{130}[/tex] × 1000

=[tex]\frac{5000}{130}[/tex]

=38.4615

Hence, the new born death rate is 38.4615.

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The lengths of the other two sides of the right triangle are 12 and 13

From the question, we are to determine the lengths of the other sides of the triangle

From the given information,

The other sides have lengths that are consecutive integers

Thus,

If the length of the other side is x

Then,

The hypotenuse will be x + 1

By the Pythagorean theorem, we can write that

(x+1)² = x² + 5²

(x+1)(x+1) = x² + 25

x² + x + x + 1 = x² + 25

x² - x² + x + x = 25 - 1

2x = 24

x = 24/2

x = 12

∴ The other leg of the right triangle is 12

Hypotenuse = x + 1 = 12 + 1 = 13

Hence, the lengths of the other two sides are 12 and 13

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Answer:

x = 8

Step-by-step explanation:

complementary angles sum to 90°

sum the 2 angles and equate to 90

5x + 50 = 90 ( subtract 50 from both sides )

5x = 40 ( divide both sides by 5 )

x = 8

The length and the width of the rectangle are 10 inches and 6 inches respectively.

In the question, we are given that the length of a rectangle exceeds its width by 4 inches, and the area is 60 square inches.

We are asked for the length and the width of the rectangle.

We assume the width (w) of the rectangle to be x inches.

Its length (l), exceeds its width (w) by 4 inches.

Thus, its length (l) = x + 4 inches.

Now, the area can be calculated using the formula, A = l*w, where A is its area, l is its length, and w is its width.

Thus, the area = (x + 4)x = x² + 4x.

But, we are given that the area is 60 square inches.

Putting the value, we get a quadratic equation:

x² + 4x = 60.

or, x² + 4x - 60 = 0,

or, x² + 10x - 6x - 60 = 0,

or, x(x + 10) - 6(x + 10) = 0,

or, (x - 6)(x + 10) = 0.

By the zero-product rule, we get:

Either, x - 6 = 0, or, x = 6,

or, x + 10 = 0, or, x = -10, but this is not possible as the width of a rectangle cannot be negative.

Thus, the width = x = 6 inches.

The length = x + 4 = 10 inches.

Thus, the length and the width of the rectangle are 10 inches and 6 inches respectively.

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Answer:

r=8.74038744 m
and surface area=1303.76211 m2

Step-by-step explanation:

Considering the given proportions, the correct statements are:

A proportion is a fraction of a total amount, and the measures are related using a rule of three.

The table gives these following proportions:

Hence the correct statements are:

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The recursive formula for the geometric sequence is given as follows:

D.

A geometric sequence is a sequence in which the result of the division of consecutive terms is always the same, called common ratio q.

The nth term of a geometric sequence is given by:

[tex]a_n = a_1q^{n-1}[/tex]

In which [tex]a_1[/tex] is the first term.

With a recursive formula, it is given by:

[tex]a_n = a_{n-1} \times q[/tex]

For this problem, the first term and the common ratio are:

[tex]a_1 = 9, q = -\frac{1}{3}[/tex]

Then the recursive formula is:

D.

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[tex]\frac{7}{30}[/tex] units of time is left.

To find how much time is left:

Given - Tony is given [tex]\frac{9}{10}[/tex] hour to mow a lawn. he only uses [tex]\frac{2}{3}[/tex]  the given time to mow the lawn.

Simplify subtract   [tex]\frac{9}{10}[/tex]  by  [tex]\frac{2}{3}[/tex]  as follows:

[tex]\frac{9}{10}-\frac{2}{3} =\frac{27-20}{30} =\frac{7}{30}[/tex]

Therefore, [tex]\frac{7}{30}[/tex] units of time is left.

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Answer:

Step-by-step explanation:

The "zero product principle" or "zero product rule" tells you a product will be zero if and only if one or more of the factors is zero. This fact is used to solve quadratic equations by factoring.

Factoring the equation y = ax² +bx +c to the form y = a(x -r)(x -s) allows you to immediately identify the solutions of y=0 as x=r and x=s. These are the values of x that make the factors zero, hence making the product zero.

Finding the values of x that satisfy ax² +bx +c = 0 by rearranging it to the form a(x -r)(x -s) = 0 is called "solving by factoring."

When the process of "completing the square" is applied to the standard-form quadratic y = ax² +bx +c, the result is a formula for the two solutions to y = 0:

  [tex]x = \dfrac{-b\pm\sqrt{b^2-4ac}}{2a}[/tex]

This quadratic formula tells you the solutions based on the coefficients of the original equation, so does not require rearranging the equation in any way.

4) [tex]A_{QRST} = A_{Q'R'S'T'} = 9[/tex].

5) The areas of the rectangles QRST and Q'R'S'T' are the same since the translation of the geometric loci conserved the Euclidean distance.

6) x = 1, w = 3, y = - 1/4, z = 1/3

Rigid transformations are transformations applied on geometric loci such that Euclidean distance is conserved. In this question we have applications of translations, a kind of rigid transformation.

Exercise 4

In this part we must determine the areas of rectangles QRST and Q'R'S'T':

Rectangle QRST

A = RS · QT

A = 3 · 3

A = 9

Rectangle Q'R'S'T'

Q'(x, y) = (2, - 3) + (- 3, - 3)

Q'(x, y) = (- 1, - 6)

R'(x, y) = (2, 4) + (- 3, - 3)

R'(x, y) = (- 1, 1)

S'(x, y) = (5, 4) + (- 3, - 3)

S'(x, y) = (2, 1)

T'(x, y) = (5, - 3) + (- 3, - 3)

T'(x, y) = (2, - 6)

A = R'S' · Q'T'

A = 3 · 3

A = 9

The rectangles QRST and Q'R'S'T' have both an area of 9 square units.

Exercise 5

The areas of the rectangles QRST and Q'R'S'T' are the same since the translation of the geometric loci conserved the Euclidean distance.

Exercise 6

In this case, we must solve the following equations:

PQ = A'(x, y) - A(x, y)

(4, 1) = (2 · x + 1, 4) - (- 1, w)

(4, 1) = (2 · x + 2, 4 - w)

(4, 1) = (2 · x, - w) + (2, 4)

(2, - 3) = (2 · x, - w)

(x, w) = (1, 3)

PQ = B'(x, y) - B(x, y)

(4, 1) = (3, 3 · z) - (8 · y - 1, 1)

(4, 1) = (2 - 8 · y, 3 · z)

(4, 1) = (- 8 · y, 3 · z) + (2, 0)

(2, 1) = (- 8 · y, 3 · z)

(y, z) = (- 1/4, 1/3)

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Answer:b

Step-by-step explanation:goooooooo

The percent of the time Nicholas earned is the percent of the time 25%

The 5 values of the given box plot are;

The minimum fee = 20

In the first quartile, the 25th percentile point, Q₁ = 25

In the median or second quartile, the fiftieth percentile factor, Q₂ = 30

The 1/3 quartile, the 75th percentile point, Q₃ = 40

The maximum value = 55

The range = The most value - The minimal fee

The range = 55 - 20 = 35

We are aware that Nicholas earned $25 or less from the minimum value up to the first quartile, Q₁, which is the 25th percentile point, in which we've got 25 percent of the statistics points.

Consequently, the percentage of the time Nicholas earned $25 or much less is 25 percent of the time.

In mathematics, a percentage is a variety of ratios that can be expressed as a fraction of 100. If we have to calculate the percent of various, divide the wide variety by way of the whole and multiply by way of a hundred. For this reason, the shared approach is a component in line with a hundred. The phrase according to cent means in keeping with one hundred.

A relative cost indicates the hundredth component of any amount. One percent (symbolized 1%) is the hundredth part; for this reason, a hundred percent represents the whole lot and two hundred percent specifies two times the given amount.

Multiply the entire number amount through the decimal equal to the proportion. The end result is the share portion quantity. (consequently, this answers the question “How a whole lot is 24 percentage of 500,” you examine that 24 percent of 500 is a hundred and twenty).

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Answer:

Step-by-step explanation:

Rectangles have 2 pairs of equal sides that means:

2(4x) and 2(3x+2)

8x and 6x+4

8x+ (6x + 4) = 14x + 4

a. Sean drank at a rate of 5 milliliters per second.

b. It took Sean 55 s to drink all the slushy.

Since Sean darnak at a constant rate and originally there were 275 milliliters of slushy in the cup. After 13 seconds, 210 milliliters of slushy remained.

The rate at which Sean drank, r = Change in volume of slushy/time for change

= (275 mL - 210 mL)/13 s

= 65 mL/13 s

= 5 mL/s

So, Sean drank at a rate of 5 milliliters per second.

The time it takes Sean to drink all the slushy is given by

T = V/r where

So, T = V/r

= 275 mL/5 mL/s

= 55 s

So, it took Sean 55 s to drink all the slushy.

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Answer:

10

Step-by-step explanation:

It's just symmetry. You see that the geometrical construction above has been rotated, so its properties will remain the same.

The number of ways pets can be arranged in group according to the species is  in a row 288 ways.

Pets can be grouped by permutation concept as follows.

Total number of pets = 10

Number of dogs = 4

Number of cats = 3

Number of alpacas = 2

Number of bunny = 1

The number of ways pets can be arranged in group according to the species in a row as,

⇒ (4!)(3!)(2!)(1!)

⇒ (24)(6)(2)(1)

⇒ 288

Hence we can conclude that the number of ways pets can be arranged in group according to the species in a row is 288 ways.

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