What is the slope of the equation y =5/4x-7/4?

Answer:

B

Step-by-step explanation:

the value of the x should be the same if we want to verify whether x+2 is a factor of f(x)

so if x=-2 ,f(-2) = 29

x+2=0 f(0) = 1

f(0) [tex]\neq[/tex] f(-2) ,so x+2 is not a factor

what it actually means it that if we move the graphic of f(x) to left along to x axis 2 units, the graphic of new one cannot coincide with the original one.

Answer:

circle

Step-by-step explanation:

any point on the circumference of a circle is equidistant from the centre.

The function for the given graph is f(x) = (x - 4)(x + 2)(x + 4).

In the given graph,

The points that lie on the x-axis are (-4, 0), (-2, 0), and (4, 0) where y-coordinate is 0 and the x coordinates are -4, -2, and 4.

On solving the given functions,

Option A:

f(x) = (x - 4)(x + 2)(x + 4)

Since y = 0 consider f(x) becomes 0

So,

(x - 4)(x + 2)(x + 4) = 0

According to the zero product rule,

x - 4 = 0, x + 2 = 0, and x + 4 = 0

⇒ x = 4, x = -2 and x = -4.

Thus, option A represents the function of the given graph.

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Disclaimer: The question given on the portal was incomplete. Here is the complete question.

Question:

Select the correct answer. which equation could represent the graphed function (given in the figure below)?

Step-by-step explanation:

(a) The value of the unknown length, a, is 18 cm
(b) The value of the unknown angle measurement, θ, is 39°

From the question, we are to determine the unknown length and angle measurement

(a)

A + B + C = 180° (Sum of angles in a triangle)

A = 180° - (B + C)

A = 180° -(68° + 59°)

A = 53°

Using the law of sines

[tex]\frac{a}{sin A}=\frac{c}{sin C}[/tex]

[tex]\frac{a}{sin 53^\circ}=\frac{19.5}{sin 59^\circ}[/tex]
[tex]a=\frac{19.5 \times sin 53^\circ}{sin 59^\circ}[/tex]

[tex]a= 18.168[/tex]

[tex]a \approx 18 cm[/tex]

(b)

[tex]\frac{sin A}{a}=\frac{sin B}{b}[/tex]

[tex]\frac{sin \theta}{15}=\frac{sin 57^\circ}{20}[/tex]

[tex]sin \theta=\frac{15 \times sin 57^\circ}{20}[/tex]

[tex]sin \theta=0.6290[/tex]

[tex]\theta=sin ^{-1} (0.6290)[/tex]

[tex]\theta=38.976 ^\circ[/tex]

[tex]\theta \approx 39^\circ[/tex]

Hence, the value of the unknown length, a, is 18 cm
The value of the unknown angle measurement, θ, is 39°

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Quadratic expressions are mathematical expressions that have the power of one of its alphabets being equal to and not more than two. The given expression in the question can be simplified as 81[tex]x^{4}[/tex] + 162[tex]x^{3}[/tex]  - 45[tex]x^{2}[/tex] - 54x - 112

Algebraic expressions are mathematical expressions that consist of given number(s) and alphabet(s). When the power (exponential) of one of the alphabets is given as two, then the expression can be classified as a quadratic expression.

Thus the given expansion of the quadratic expression can be simplified as follows:

([tex]9x^{2}[/tex] + 9x - 4)([tex]9x^{2}[/tex] + 9x - 10) - 72

But,

([tex]9x^{2}[/tex] + 9x - 4)([tex]9x^{2}[/tex] + 9x - 10) = [tex]9x^{2}[/tex]([tex]9x^{2}[/tex] + 9x - 10) + 9x([tex]9x^{2}[/tex] + 9x - 10) - 4([tex]9x^{2}[/tex] + 9x - 10)

               = 81[tex]x^{4}[/tex] + 81[tex]x^{3}[/tex] - 90[tex]x^{2}[/tex] + 81[tex]x^{3}[/tex] + 81 [tex]x^{2}[/tex] - 90x - 36 [tex]x^{2}[/tex] + 36x - 40

               = 81[tex]x^{4}[/tex] + 162[tex]x^{3}[/tex]  - 45[tex]x^{2}[/tex] - 54x - 40

So that we have;

(81[tex]x^{4}[/tex] + 162[tex]x^{3}[/tex]  - 45[tex]x^{2}[/tex] - 54x - 40) - 72  = 81[tex]x^{4}[/tex] + 162[tex]x^{3}[/tex]  - 45[tex]x^{2}[/tex] - 54x - 40 -72

                  = 81[tex]x^{4}[/tex] + 162[tex]x^{3}[/tex]  - 45[tex]x^{2}[/tex] - 54x - 112

Thus the simplification of the given expression is 81[tex]x^{4}[/tex] + 162[tex]x^{3}[/tex]  - 45[tex]x^{2}[/tex] - 54x - 112

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The number of individuals who participated in the entire experiment was 80.

In the question, we are informed that an Independent group experiment or between-subjects experiment comparing four treatment conditions produces 20 scores in each treatment condition.

We are asked to find the number of individuals who participated in the entire experiment.

The number of treatment conditions in the experiment is given to be 4.

The scores in each treatment condition for the experiment is given to be 20.

The total number of individuals who participated in the experiment will be the product of the number of treatment conditions in the experiment and the scores in each treatment condition for the experiment.

Thus, the number of individuals who participated in the entire experiment = 4*20 = 80.

Thus, the number of individuals who participated in the entire experiment was 80.

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The largest value of n such that the statement "at least n people in this room have birthdays falling in the same month" is always true is 5

From the given information, we have 52 people in the room

Note that there are 12 months in a year

Let's divide the number by people by the months of the year

⇒ [tex]\frac{52}{12}[/tex]

⇒ 4 remaining 4

If 48 people are evenly distributed over twelve months, then there will be four people born in each month.

The remaining four people can be placed each in any of the twelve different months.

Hence, if 52 people are evenly distributed as possible, there will be eight months with four people and four months with five people.

Thus, the largest value of n such that the statement "at least n people in this room have birthdays falling in the same month" is always true is 5

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The points which represents the vertices of the given equation are; (15, −2) and (−1, −2).

The complete question gives the equation of the ellipse as; (x-7)²/64+(y+2)²/9=1.

Since, It follows from convention that general equation of ellipse with centre as (h, k) takes the form;

(x-h)²/a² +(y-k)²/b² = 1.

Consequently, it follows from observation that the value of a and b in the given equation in the task content is; √64 = 8 and √9 = 3 respectively.

Since, 8 > 3, The vertices of the ellipse are given by; (h±a, k).

The vertices in this scenario are therefore;

(7+8, -2) and (7-8, -2).

= (15, -2) and (-1, -2).

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The volume of the frozen figure is 736 cm³

From the question, we are to determine the volume of the frozen figure

In the given diagram,

The volume of the frozen figure = a³ + 1/2(a²b)

From the given information,

a = 8 cm

b = 7 cm

∴ Volume of the frozen figure = 8³ + 1/2(8² ×7)

Volume of the frozen figure = 512 + 1/2(448)

Volume of the frozen figure = 512 + 224

Volume of the frozen figure = 736 cm³

Hence, the volume of the frozen figure is 736 cm³

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Answer:

(C)=22.5

Step-by-step explanation:

Hi! ❄

    - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - -

First, let's subtract by 23 both sides.

[tex]\sf{\dfrac{3}{2}c=15}[/tex]

Now we multiply the equation by 2.

[tex]\sf{3c=30}[/tex]. See how on the left hand side, the 3/2c*2 turned into 3c? That's because multiplication and division are operations that undo each other.

And Now we just divide by 3 both sides.

[tex]\sf{c=10}[/tex]

Hope this made sense !!

      - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - -

[tex]\star\tiny\pmb{calligraphy}\star[/tex]

Answer:

y = |x + 8|

Explanation:

Please see the table attached below.

Answer:y=|x+8|

Step-by-step explanation:

Answer:

L' (-1, 1)

M' (1, 2)

N' (1, -1)

The formula is [tex]\frac{n(n+1)(2n+1)}{6}[/tex]

What are series?

In mathematics, we can describe a series as adding infinitely many numbers or quantities to a given starting number or amount.

We will find the formula as shown as below:

Let [tex]S=1+2^2+3^2+4^2+................+n^2[/tex]

We know [tex](n+1)^3=n^3+3n^2+3n+1[/tex]

[tex](1+1)^3=1^3+3(1)^2+3(1)+1[/tex]

[tex](2+1)^3=2^3+3(2)^2+3(2)+1[/tex]

[tex](3+1)^3=3^3+3(3)^2+3(3)+1[/tex]

.

.

[tex](n+1)^3=n^3+3(n)^2+3(n)+1[/tex]

On adding

[tex]2^3+3^3+4^3......(n+1)^3=(1^3+2^3+3^3+.....+n^3)+3(1^2+2^2+.....+n^2)+3(1+2+3....n)+(1+1+1+....+1)[/tex]

[tex]2^3+3^3+4^3......(n+1)^3-(1^3+2^3+3^3+.....+n^3)=3S+\frac{3n(n+1)}{2}+(1+1+1+....+1)[/tex]

[tex](n+1)^3-1^3=3S+\frac{3n(n+1)}{2} +n[/tex]

[tex]n^3+3(n)^2+3(n)+1-1=3S+\frac{3n(n+1)}{2} +n[/tex]

[tex]2n^3+6n^2+6n=6S+3n^2+3n+2n[/tex]

[tex]6S=2n^3+3n^2+n[/tex]

[tex]6S=2n^2(n+1)+n(n+1)[/tex]

[tex]6S=(n+1)(2n^2+n)[/tex]

[tex]6S=n(n+1)(2n+1)[/tex]

[tex]S=\frac{n(n+1)(2n+1)}{6}[/tex]

Hence, the formula is [tex]\frac{n(n+1)(2n+1)}{6}[/tex]

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The volume of the shipping crate is 36 m per cube.

According to the statement

we have given that the

A rectangular-prism-shaped toy chest is 2 m by 1 m by 1 m. A shipping crate is packed with 18 of these toy chests.

And we have to find the volume of the crate.

So,

volume of toy = 2*1*1

Volume of toy = 2 meter per cube.

And Now,

The volume of shipping crate = Volume of one toy* total number of toys in crate

so, Substitute the values in the formula then

The volume of shipping crate = Volume of one toy* total number of toys in crate

The volume of shipping crate = 2*18

The volume of shipping crate = 36 m per cube.

So, The volume of the shipping crate is 36 m per cube.

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Answer:

[tex]-\frac{61}{14}[/tex]

Step-by-step explanation:

Question: 5 - 7(z+1) = 7(-9-3z)

We multiply the number in front of the bracket first, since that is multiplication.

--> 5 -7z -7 = -63 - 21z

--> -7z -2 = -63 - 21z

Now, we move all the z and all the numbers to each side.

--> -7z +21z = -63 +2

--> 14z = -61

--> z = -61/14

This cannot be simplified further, so z is -61/14.

The two possible solutions to the given equation ( 6x^2-35 = -11x ) are x = 5/3 and x = -7/2

Given the equation; 6x² - 35 = -11x

The quadratic formula is expressed as;

x = [ -b±√( b² - 4(ac)  ]/2a

First, we re-arrange our equation in the form of ax² + bx + c = 0

6x² + 11x - 35 = 0

We substitute into the formula.

x = [ -b±√( b² - 4(ac)  ]/2a

x = [ -11±√( 11² - 4( 6 × -35 )  ]/2×6

x = [ -11±√( 121 + 840 ]/12

x = [ -11±√961 ]/12

x = [ -11 ± 31 ]/12

x = (-11 + 31)/12,  (-11 + 31 )/12

x = 20/12,  -42/12

x = 5/3, -7/2

Therefore, the two possible solutions to the given equation ( 6x^2-35 = -11x ) are x = 5/3 and x = -7/2

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The percentage that the number of airlines with an average airplane age of 14 is less than the number of airlines with an average airplane age of 11 is:

B. 20%.

The percentage of an amount a over a total amount b is given by a multiplied by 100% and divided by b, that is:

[tex]P = \frac{a}{b} \times 100\%[/tex]

The percentage of airlines with an average age of 14 years is:

[tex]P = \frac{2}{15} \times 100\% = 13.33\%[/tex]

The percentage of airlines with an average age of 11 years is:

[tex]P = \frac{5}{15} \times 100\% = 33.33\%[/tex]

The difference is:

33.33% - 13.33% = 20%.

Hence option B is correct.

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Step-by-step explanation:

asleep percentage :- ( 8h /24h ) 100 % = 33.33%

awake percentage :- ( 16h / 24h ) 100 % = 66.67%

Answer:

No largest no could be 100

Step-by-step explanation:

Yes, the sum of the three numbers is 200, and the largest number can indeed be 75.

Let's assume the three numbers are:

Smallest number = 25

Middle number = x (unknown)

Largest number = 75

The sum of the three numbers is 200, so we can set up the equation:

25 + x + 75 = 200

Now, let's solve for x:

x = 200 - 25 - 75

x = 100

So, the middle number is 100.

Now, we can check if the largest number (75) is correct:

25 + 100 + 75 = 200

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Answer:

[tex]\textsf{2.} \quad y=\dfrac{35}{x}[/tex]

[tex]\textsf{3.} \quad y=-\dfrac{90}{x}[/tex]

[tex]\textsf{4.} \quad y=\dfrac{63}{x}[/tex]

[tex]\textsf{5.} \quad y=-\dfrac{112}{x}[/tex]

Step-by-step explanation:

If y is inversely proportional to x, then:

[tex]y \propto\dfrac{1}{x} \implies y=\dfrac{k}{x} \quad \textsf{(for some constant }k)[/tex]

Question 2

Substitute one of the given ordered pairs into the inverse variation equation and solve for k:

[tex]\implies 7=\dfrac{k}{5}[/tex]

[tex]\implies 7 \cdot 5=\dfrac{k}{5} \cdot 5[/tex]

[tex]\implies k=35[/tex]

Substitute the found value of k into the formula to create the inverse variation equation for the given ordered pairs:

[tex]\implies y=\dfrac{35}{x}[/tex]

Question 3

Substitute y = -15 and x = 6 into the formula and solve for k:

[tex]\implies -15=\dfrac{k}{6}[/tex]

[tex]\implies -15 \cdot 6=\dfrac{k}{6} \cdot 6[/tex]

[tex]\implies k=-90[/tex]

Substitute the found value of k into the formula to create the inverse variation equation for the given values:

[tex]\implies y=-\dfrac{90}{x}[/tex]

Question 4

Substitute one of the given ordered pairs into the inverse variation equation and solve for k:

[tex]\implies 9=\dfrac{k}{7}[/tex]

[tex]\implies 9 \cdot 7=\dfrac{k}{7} \cdot 7[/tex]

[tex]\implies k=63[/tex]

Substitute the found value of k into the formula to create the inverse variation equation for the given ordered pairs:

[tex]\implies y=\dfrac{63}{x}[/tex]

Question 5

Substitute one of the given ordered pairs into the inverse variation equation and solve for k:

[tex]\implies -16=\dfrac{k}{7}[/tex]

[tex]\implies -16 \cdot 7=\dfrac{k}{7} \cdot 7[/tex]

[tex]\implies k=-112[/tex]

Substitute the found value of k into the formula to create the inverse variation equation for the given ordered pairs:

[tex]\implies y=-\dfrac{112}{x}[/tex]

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Prediction of the value of the dependent variable outside the experimental region is called extrapolation.

According to the question,

Prediction of the value of the dependent variable outside the experimental region is called extrapolation.

Extrapolation is the statistical method beamed at understanding the unknown data from the known data.

Hence, prediction of the value of the dependent variable outside the experimental region is called extrapolation.

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Answer:

Answer:The chocolate are 0.0042 lighter than the stated on the label

Answer: 2

Step-by-step explanation:

[tex]\frac{-2-14}{2-10}=\frac{-16}{-8}=\boxed{2}[/tex]

The circumference and area of the circle are 27. 0 inches and 58. 0 inches square respectively.

The formula for circumference of a circle is given as;

Circumference = 2 π r

We have diameter = 8. 6 inches

Radius = diameter/ 2

Radius = 8.6/2 = 4. 3 inches

Circumference = 2 × 3. 14 × 4. 3 = 27. 0 Inches

The formula for area of a circle = π r ^2

Area = 3. 14 × 4. 3 × 4. 3

Area = 58. 0 Inches square

Thus, the circumference and area of the circle are 27. 0 inches and 58. 0 inches square respectively.

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The Polynomial Roots are given as follows:
 

x₁=−1.2085

x₂=0.2709+1.2576i

x₃=0.2709−1.2576i

It is to be noted that the Polynomial 3x³+ 2x2 + 3x + 6 has no real rational roots that can be found using the rational root text. Hence, this was solved using the Qubic Formulas.

The roots (also known as zeroes or solutions) of a polynomial P (x) P(x) P(x) are the x values for which P (x) P(x) P(x) equals zero.

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Answer: 12

Step-by-step explanation:

I got it right

Answer:

its not 15 points ):

Step-by-step explanation:

The permutations is computed below.

1. Evaluate 9P4

9P4 = 9!/(9 - 4)

= 9!/5!

= (9 × 8 × 7 × 6)

= 3024

2. How many ways can 5 students sit on a row of 15 chairs for a photograph?

= 15!(15 - 5)

= 15!/10!

= (15 × 14 × 13 × 12 × 11)

= 360360

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Answer: 27

Step-by-step explanation:

Mean = Sum of data/Number of data = (2 + 7 + x)/3 = 12

(x+9)/3 = 12

x+9 = 36

x = 27