Answer:
1.52 g/mL
Explanation:
The formula for finding the density of an object is d = m/v, or density = mass divided by volume.
Therefore, we can input the two values and solve for d.
d = 220/145
d = 44/29
d ≈ 1.52 g/mL
A pool is 41.4 m long and 28.2 m wide. If the average depth of water is 5.00 ft, what is the mass (in kg) of water in the pool? Enter your answer in scientific notation. The density of water is 1.0 g/mL.
Answer:
[tex]m=1.779x10^{6}kg[/tex]
Explanation:
Hello,
In this case, mass and volume define density as shown below:
[tex]\rho =\frac{m}{V}[/tex]
Whereas the mass is computed by:
[tex]m=\rho *V[/tex]
Thus, knowing the dimensions of the pool, we compute its volume:
[tex]V=41.4m*28.2m*(5.00ft*\frac{1m}{3.281ft} )=1779.15m^3[/tex]
But in cubic centimetres:
[tex]V=1779.15m^3*\frac{1x10^6cm}{1m^3} \\\\V=1.779x10^{9}cm^3[/tex]
Therefore, the mass in kilograms turns out:
[tex]m=1\frac{g}{cm^3} *1.779x10^{9}cm^3*\frac{1kg}{1000g}\\ \\m=1.779x10^{6}kg[/tex]
Regards.
How much would it cost to drive from San Jose to Las Vegas (847 miles) is gasoline cost
$3.20 per gallon and your car gets 28 miles per gallon?
Answer:
$96.8
Explanation:
divide 847 by 28 because each gallon gets the car 28 miles and there's 847 miles in total and you get 30.25 and you multiple that by the cost so it be 30.25×3.20=$96.8
QUESTION 4 What is the maximum pressure (in Torr) that will afford a N2 molecule a mean-free-path of at least 1.00 m at 25 oC
Answer:
Maximum pressure P = 4.9 × 10⁻⁵ Pa
Explanation:
From the information given, the mean free path can be expressed with the formula:
[tex]\lambda = \dfrac{RT}{\sqrt{2} \pi \times d^2 \times N_A \times P}[/tex]
Making Pressure P the subject of the formula because we intend to find the maximum pressure, we have:
[tex]P= \dfrac{RT}{\sqrt{2} \pi \times d^2 \times N_A \times \lambda }[/tex]
At standard conditions
R = gas constant = 8.314 J/mol.K
T = temperature at 25°C = (273 + 25) = 298 K
π = pi = 3.14
d = (364× 10⁻¹²m)²
[tex]N_A[/tex] = avogadro's number = 6.023 × 10²³
λ = mean free path = 1.0 m
[tex]P= \dfrac{RT}{\sqrt{2} \pi \times d^2 \times N_A \times \lambda }[/tex]
[tex]P= \dfrac{8.314 \ J/mol.K \times 298 \ K}{\sqrt{2}\times (3.14) \times (364 \times 10^{-12} \ m) ^2 \times 6.023 \times 10^{23}/mol \times 1.0 \ m }[/tex]
P = 0.007 kg/m.s²
P = 0.007 Pa
[tex]P = 0.007 Pa \times \dfrac{0.007 \ torr}{1 \ Pa}[/tex]
P = 4.9 × 10⁻⁵ Pa
Obtain a box of breakfast cereal and read the list of ingredients. What are four chemicals from the list? a. monoglycerides.b. cocamide DEA.c. folic acid.d. iron.e. chromium ion.f. peroxide.g. lauryl glucoside.h. disodium phosphate.
Answer:
The options are a, c, d and h
Explanation:
The following ingredients can be found in a packaged food cereal
Monoglycerides are used as emulsifiers and they are also added to cereals to improve there texture and shelf-life.
Folic acid or folate is a vitamin that most cereals are fortified with to act as dietary supplement.
Iron is an essential mineral element, meaning your body needs it (basically for blood production). Cereals are usually fortified with iron for this reason.
Disodium phosphate is also a food additive used to improve the quality of food and is also found in cereals.
If you put 5.0 mL of alcohol into 100.0 mL of water, what is the solvent and what is the solution?
i need to know the measurements of this to the appropriate amount of significant figures
Answer:
[See Below]
Explanation:
25 ml.
Read this for the next two problems: When a 125 g obsidian rock is placed into a graduated
cylinder, the water level rises from the 15 mL to the 47 mL mark.
29. What is the rocks volume?
a) 62 mL
b) 32 mL
c) 15 mL
d) 47 mL
30. What is the rocks density?
a) 0.25 g/mL b) 1 g/mL
c) 2.0 g/mL d) 3.9 g/mL
31. If you add a mass of 3.7 g to a mass of 9.495 9. the sum with the correct number of
significant digits is
a) 13.29 b) 13.209 c) 13.199 d) 13.1959
Answer:
29. Option (b) 32 mL
30. Option (d) 3.9 g/mL
31. Option (d) 13.195 g
Explanation:
29. Determination of the volume of the rock.
Volume of water = 15 mL
Volume of water + Rock = 47 mL
Volume of Rock =.?
Volume of Rock = (Volume of water + Rock) – (Volume of water)
Volume of Rock = 47 – 15
Volume of Rock = 32 mL
30. Determination of the density of the rock.
Density of a substance is simply defined as the mass of the substance per unit volume of the substance. It can be represented mathematically as:
Density (D) = mass (m) /volume (V)
D = m/V
With the above formula, the density of the rock can be obtained as follow:
Mass (m) of Rock = 125 g
Volume (V) of Rock = 32 mL
Density (D) =?
D = m/V
D = 3.9 g/mL
Therefore, the density of the rock is 3.9 g/mL.
31. Determination of the sum of 3.7 g and 9.495 g.
The sum of 3.7 g and 9.495 g can be obtained as follow:
3.7 g + 9.495 g = 13.195 g
The moon appears larger than most of the planets in our solar system because ______?
its closer than us than the planets
:)
modern commercial airlines are largely made of aluminum, and light and strong metal. But the fact that aluminum is cheap enough that airplanes can be made out of it is a bit of historical luck. before the discovery of the Hall-Heroult process in 1886, aluminum was as rare and expensive as gold. What would happen if airplanes had to be made of steel? The fuselage of a Boeing 787, which can carry 400 passengers, is approximately a hollow aluminum cylinder without ends, 70.7 m long, 6.5 m wide, and 2.5 mm thick. Suppose this fuselage was made of steel (density 7.87 g/cm^{3}) instead of aluminum (density 2.7g/[tex]cm^{3}), and let's say the average passenger has a mass of 81 kg. We'll also assume the engines can't lift any greater mass than they already do. Calculate the number of passengers that the Boeing 747 could carry if its fuselage was made of steel.
Answer:
170 passenger . ( approx )
Explanation:
Total volume of metal making fuselage = π ( r₂² - r₁² ) l
r₂ is outer radius of cylindrical tube like fuselage
= 6.5 / 2 + .0025 = 3.2525 m
r₁ is inner radius of cylindrical tube like fuselage
= 6.5 / 2 = 3.25 m
l = 70.7 m
Total volume of fuselage = π ( r₂² - r₁² ) l
= 3.14 x 70.7 x ( 3.2525² - 3.25² )
= 221.998 ( 10.57875 - 10.5625)
= 3.60747 m³
If it is made of aluminium , its mass
= volume x density
= 3.60747 x 2700 kg
= 9740.16 kg
weight of passenger = 81 x 400 = 32400 kg
Total mass = 32400 + 9740.16
= 42140.16 kg
If it is made of iron , its mass
= volume x density
= 3.60747 x 7870 kg
= 28390.79 kg
If number of passenger required be n
81 n + 28390.79 = 42140.16 ( as per condition given )
n = 170 passenger . ( approx )
PLEASE ANSWER FAST!
A sphere with a mass of 12 g has a radius measuring 2 cm. What is its density?
Answer:
0.36 g/cm3 I hope this helps
Answer:
0.36 hope it helped
Explanation:
Give a systematic name for the following compound: CH3CH2CHCH2CHCH3, with a CH3 group attached to the third (from left to right) carbon and a Br atom attached to the fifth carbon.
Answer:
2-bromo-4 methylheane
Explanation:
Numbering from right to left, the bromine atom falls on the second (2) carbon, while the methyl branch on the 4th.
The systematic naming (IUPAC) of haloalkanes follows the alphabetical rule in naming the substituents, be it alkyl groups or halogens.
I hope the explanation would suffice.
a strong acid will react with a molecule of water to form a(n) _ ion
Answer:
hydroxide ion
Explanation:
acids produce hydrogen ion when dissolved in water
Calculate the pH of a buffer solution prepared by mixing 200 mL of 0.10 M NaF and 100 mL of 0.050 M HF.
Answer:
[tex]pH=3.74[/tex]
Explanation:
Hello,
In this case, by using the Henderson-Hasselbach equation one could compute the pH considering that the pKa of hydrofluoric acid, HF, is 3.14:
[tex]pH=pKa+log(\frac{[base]}{[acid]} )[/tex]
Whereas the concentration of the base and acid are computed by considering the mixing process with a total volume of 300 mL (0.3 L):
[tex]n_{HF}=0.1L*0.05mol/L=0.005molHF\\\\n_{NaF}=0.2L*0.1mol/L=0.02molNaF[/tex]
[tex][HF]=\frac{0.005molHF}{0.3L}=0.017M[/tex]
[tex][NaF]=\frac{0.02molHF}{0.3L}=0.067M[/tex]
Therefore, the pH turns out:
[tex]pH=3.14+log(\frac{0.067M}{0.017M} )\\\\pH=3.74[/tex]
Regards.
what could cause a test tube to crack?
Answer:
heated test tube in cold water
The pH of a solution is 8.83±0.048.83±0.04 . What is the concentration of H+H+ in the solution and its absolute uncertainty?
Answer:
The concentration of [tex]H^{+}[/tex] is 1.48 × [tex]10^{-9}[/tex] M
The absolute uncertainty of [tex][{H^{+}][/tex] is ±0.12 × [tex]10^{-9}[/tex] M
The concentration of [tex]H^{+}[/tex] is written as 1.48(±0.12) × [tex]10^{-9}[/tex] M
Explanation:
The pH of a solution is given by the formula below
pH = [tex]-log_{10}[{H^{+}][/tex]
∴ [tex][H^{+}] = 10^{-pH}[/tex]
where [tex][{H^{+}][/tex] is the [tex]H^{+}[/tex] concentration
From the question,
pH = 8.83±0.04
That is,
pH =8.83 and the uncertainty is ±0.04
First, we will determine [tex][{H^{+}][/tex] from
[tex][H^{+}] = 10^{-pH}[/tex]
[tex][{H^{+}] = 10^{-8.83}[/tex]
[tex][{H^{+}] = 1.4791[/tex] × [tex]10^{-9}[/tex] M
[tex][{H^{+}] = 1.48[/tex] × [tex]10^{-9}[/tex] M
The concentration of [tex]H^{+}[/tex] is 1.48 × [tex]10^{-9}[/tex] M
The uncertainty of [tex][{H^{+}][/tex] ( [tex]U_{[H^{+}] }[/tex] ) from the equation [tex][H^{+}] = 10^{-pH}[/tex] is
[tex]U_{[H^{+}] } = 2.303 \\[/tex] × [tex]{[H^{+}] }[/tex] × [tex]U_{pH }[/tex]
Where [tex]U_{[H^{+}] }[/tex] is the uncertainty of [tex][{H^{+}][/tex]
[tex]U_{pH }[/tex] is the uncertainty of the pH
Hence,
[tex]U_{[H^{+}] }[/tex] = 2.303 × 1.4791 × [tex]10^{-9}[/tex] × 0.04
[tex]U_{[H^{+}] }[/tex] = 1.36 × [tex]10^{-10}[/tex] M
[tex]U_{[H^{+}] }[/tex] = 0.12 × [tex]10^{-9}[/tex] M
Hence, the absolute uncertainty of [tex][{H^{+}][/tex] is ±0.12 × [tex]10^{-9}[/tex] M
How does ionization of a given molecule affect its distribution between the organic and aqueous layer
Answer:
Ionized molecules will be found in the aqueous layer
Explanation:
The principle of solvent extraction involves the partitioning of a substance between an aqueous layer and an organic layer. The aqueous layer is polar in nature while the organic layer is nonpolar in nature.
All nonpolar substances are found in the organic layer while all polar substances are found in the aqueous layer. Hence, in the aqueous phase, the following species can be found; positive ions, negative ions and neutral polar molecules or ionic substances.
Abby fills a graduated cylinder with 3 mL of water. She then drops a
small rock into the cylinder, and the water level rises to the 5 ml
mark. What is the volume of the rock?
mL
Answer: 2ML
Explanation: all you needed to do was to subtract
Glucagon secretion is stimulated when blood glucose concentration decreases. which carbohydrate pathways does glucagon stimulate in liver?
A. glycogen synthesis (glycogenesis)
B. glycolysis
C. glucose uptake
D. gluconeogenesis
E. glycogenolysis
Answer:
E. glycogenolysis
Explanation:
Glycogenolysis is the process whereby excess glucose stored by the body in the form of glycogen is then converted back/broken down into glucose molecules to serve as a source of energy
Glucagon secretion is stimulated when blood glucose concentration decreases and is secreted by the pancreas. The liver then converts the glycogen into glucose for use by the body
What is the volume of a sample that has a mass of 20 g and a density of 4 g/mL?
Answer:
The volume of a sample is 5 ml.
For the neutralization reaction between methylamine and acetic acid, draw curved arrows to indicate the direction of electron flow. Draw curved arrows to show the movement of electrons in this step of the mechanism.
Answer:
This is required answer.
Explanation:
Given that,
The neutralization reaction between methylamine and acetic acid
We know that,
According to proton theory of acid and base,
An acid is a substance which denotes the hydrogen as proton.
Base is a substance which accept the proton.
We need to draw curved arrows to indicate the direction of electron flow
According to diagram,
Diagram shows the movement of electrons in this step of the mechanism.
Hence, This is required answer.
Which one of the following is an example of a covalent network solid?a.SiO2b. Kc. I2d. CaCl2e. None of these.
Answer:
SiO2
Explanation:
A covalent network solid is a solid substance held together by a network of covalent bonds. Silicon dioxide forms a three dimensional covalent network solid structure.
Silicon dioxide is comprised of a network in which each silicon atom is at the centre of a tetrahedron of four oxygen atoms. Each of the oxygen atoms is also bonded to another silicon atom, at the centre of its own tetrahedron of oxygen atoms. This gives rise to a crystalline solid structure which is hard, having a high melting point.
Acetone is a common solvent that has a density of 0.7899 g/mL. What volume of acetone, in milliliters, has a mass of 35.6 g?
volume
mL
Answer:
45.069 mL
Explanation:
mass/density=volume.
If we fill in the numbers provided, we would have:
35.6/0.7899=45.069
Don't forget to add your measurements!
45.069 mL
At 25°C, an aqueous solution containing 35.0 wt% H2SO4 has a specific gravity of 1.2563. A quantity of the 35% solution is needed that contains 195.5 kg of H2SO4.
A) Calculate the required volume (L) of the solution using the given specific gravity.
B) Estimate the percentage error that would have resulted if pure-component specific gravities of H2SO4 (SG = 1:8255) and water had been used for the calculation instead of the given specific gravity of the mixture.
Answer:
a) volume₁ = 444.6 L
b) Volume₂ = 306 L and percentage Error = 31.2%
Explanation:
Given that;
the solution contains 35.0 wt% H₂SO₄
A quantity of the 35% solution is needed that contains 195.5 kg of H₂SO₄
Lets say mass of solution containing 195.5 kg H₂SO₄ is 'A' kg
Now since the question saysm it is a 35% wt solution,
so
(35/ 100) × Akg = 195.5kg
0.35A = 195.5
A = 558.6kg
So A = 558.6 kg
therefore mass of the solution is 558.6kg
a)
also Specific gravity is 1.2563
since density of water = 1kg/ L
density of solution = SG of H₂SO₄ × density of water
therefore density of solution = 1.2563 ×1kg/ L = 1.2563 kg/ L
Now to calculate the required volume (L) of the solution
we say;
Volume of solution = mass / density
Volume = 558.6kg / 1.2563kg/L
Volume₁ = 444.6 L
b)
Now If pure-component specific gravity is to be used,
Specific Gravity = 1.8255
which means Density will be = 1.8255 kg/ L
Therefore will be
Volume = 558.6kg / 1.8255kg/L
Volume₂ = 306 L
To calculate the error
we say volume₁ - volume₂
Error = 444.6L - 306L = 138.6
So
Percent error = ( 138.6L / 444.6L) × 100
percentage Error = 31.2%
What is the major driving force for losing a proton as the last step in an electrophilic aromatic substitution reaction?
Answer:
Explanation:
In the following reaction we have shown an example of aromatic substitution reaction .
C₆H₆ + RCl = C₆H₅R + HCl
This reaction takes place in the presence of catalyst like AlCl₃ which is a lewis acid .
First of all formation of carbocation is made as follows .
RCl + AlCl₃ = R⁺ + AlCl₄⁻
This R⁺ is carbocation which is also called electrophile . It attacks the ring to get attached with it .
C₆H₆ + R⁺ = C₆H₅R⁺H.
The complex formed is unstable , though it is stabilized by resonance effect . In the last step H⁺ is kicked out of the ring . The driving force that does it is the steric hindrance due to presence of two adjacent group of H and R⁺ at the same place . Second driving force is attack by the base AlCl₄⁻ that had been formed earlier . It acts as base and it extracts proton ( H⁺ ) from the ring .
C₆H₅R⁺H + AlCl₄⁻ = C₆H₆ + AlCl₃ + HCl .
The formation of a stable product C₆H₆ also drives the reaction to form this product .
the number of protons in an ato
Answer:
The number of protons in the nucleus of the atom is equal to the atomic number
(Z). The number of electrons in a neutral atom is equal to the number of protons .
The mass number of the atom (M) is equal to the sum of the number of protons
and neutrons in the nucleus.
The reaction between nitric oxide and oxygen is described by the following chemical equation: Suppose a two-step mechanism is proposed for this reaction, beginning with this elementary reaction: Suppose also that the second step of the mechanism should be bimolecular. Suggest a reasonable second step. That is, write the balanced chemical equation of a bimolecular elementary reaction that would complete the proposed mechanism.
Answer:
2NO(g) + O2(g) ---> 2NO2(g)
Explanation:
The mechanism for this reaction involves two elementary reactions in which both are bimolecular as shown below;
NO(g) +O2(g) ----> NO2(g) + O(g)
NO(g) + O(g) ----> NO2(g)
Hence overall balanced reaction equation;
2NO(g) + O2(g) ---> 2NO2(g)
Answer:
NO(g)+O(g)---->NO_2(g)
Explanation:
f-orbital can accommodate maximum of... electron?
Explanation:
S= 2
P=6
D=10
F= 14
F orbital holds a maximum of 14 electrons
Answer:
14.
Explanation:
The f level consists of 7 orbitals and each can accommodate up to 2 electrons.
Calculate the mass of 2.500 mol of magnesium hydroxide.
Answer:145g
Explanation:
Write the chemical symbols for three different atomic anions that all have 34 protons.
Answer:
Explanation:
First of all it should be noted that number of protons is called atomic number in chemistry. The atom that has the atomic number of 34 in the periodic table is Selenium (Se). Anions are negatively charged atoms; the negative charge means the atoms have lost electron(s) while still having the same number of protons.
From the above, we can deduce that the only atom that can have 34 protons is Se and for it to become negatively charged (anion), it must lose electron(s).
The different chemical symbols thereof will be Se⁻,Se²⁻, Se³⁻ if it loses one, two or three electrons respectively while still having the atomic number of 34
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What alkene would give the products below after reaction with O3, followed by reduction with (CH3)2S
The question is incomplete; the complete question is;
What alkene would give the products below after reaction with O3, followed by reduction with (CH3)2S? Write the condensed structural formula (CH3)2C=O and CH3-CH2-CH=O
Answer:
2-methylpent-2-ene (C6H12)
Explanation:
Ozonolysis is a wonderful method for determining the location of double bonds in an alkene since the oxygenated carbons in the carbonyl compounds formed after ozonolysis are the ones that were initially joined by the double bonds in the original alkene.
Hence if an alkene yields (CH3)2C=O and CH3-CH2-CH=O, the original alkene must be C6H12, that is, 2-methylpent-2-ene