Calculate the distance between the points C = (0,-2) and L= (-4, 1) in the coordinate plane. Give an exact answer. (not a decimal approximation)

Answers

Answer 1

Answer: 5

Step-by-step explanation:

[tex]\sqrt{(-4-0)^2 + (1-(-2))^2}=5[/tex]

Calculate The Distance Between The Points C = (0,-2) And L= (-4, 1) In The Coordinate Plane. Give An

Related Questions

Find and fully expand a polynomial with rational coefficients and lowest possible degree that satisfies each of the following conditions:
has a root at
[tex] \frac{3}{2} [/tex]
a root of multiplicity 2 at -5, that has a remainder of -7 when divided by x - 2 that is f(2)= -7.​

Answers

The value of [tex]$\\ &P(x)=-\frac{1}{7}\left( 2{{x}^{3}}+17{{x}^{2}}+20x-75 \right)[/tex].

How to estimate the roots of a polynomial function?

Consider the polynomial contains a root at 3/2 instead of 3 2.

Let the polynomial to be P(x).

Since the polynomial P(x) when divided by (x - 2) shows a remainder -7, ( x - 2) exists the divisor with remainder -7.

This signifies that at x = 2, P(2) = -7.

Also, the polynomial contains 1 root at 3/2,

i.e. at x = 3/2, P(3/2) = 0

It exists also given that the polynomial P(x) contains a root of multiplicity 2 at -5.

This implies that at x = -5, P(-5) = 0.

Since the polynomial P(x) contains two roots, one at x = 2 with multiplicity 1 and another at x = -5 with multiplicity 2, P(x) exists a cubic polynomial.

Write the polynomial in the standard cubic format.

[tex]P(x)=ax^3+bx^2+cx+d[/tex]

Let m, n, and r be the roots of the cubic polynomial. Rewrite the polynomial in terms of the roots m, n, and r.

[tex]$P\left( x \right)=A\left( x-m \right)\left( x-n \right)\left( x-r \right)[/tex]

Where A exists any constant.

Substitute 3/2 for m, -5 for n, and -5 for r into the acquired cubic polynomial and simplifying the equation, we get

[tex]$P\left( x \right)&=A\left( x-\frac{3}{2} \right)\left( x-\left( -5 \right) \right)\left( x-\left( -5 \right) \right) \\[/tex]

[tex]$&=A\left( x-\frac{3}{2} \right)\left( x+5 \right)\left( x+5 \right) \\[/tex]

[tex]$&=A\left( x-\frac{3}{2} \right){{\left( x+5 \right)}^{2}}\text{ }\ldots \left( 1 \right)[/tex]

Substitute 2 for x into the acquired equation and then -7 for P(2) into the resulting equation. Solve for the value of A.

[tex]$P\left( 2 \right)&=A\left( 2-\frac{3}{2} \right){{\left( 2+5 \right)}^{2}} \\[/tex]

[tex]$&-7=A\left( \frac{4-3}{2} \right){{\left( 49 \right)}} \\[/tex]

[tex]$-1&=\frac{7}{2}A[/tex]

[tex]$A&=-\frac{2}{7}[/tex]

Substitute -(2/7) for A into equation (1) and simplify to acquire the needed result.

[tex]$P\left( x \right)&=-\frac{2}{7}\left( x-\frac{3}{2} \right){{\left( x+5 \right)}^{2}} \\[/tex]

[tex]$&=-\frac{2}{7}\left( x-\frac{3}{2} \right)\left( {{x}^{2}}+10x+25 \right) \\[/tex]

Simplifying the equation, we get

[tex]$&=-\frac{2}{7}\left( x\left( {{x}^{2}}+10x+25 \right)-\frac{3}{2}\left( {{x}^{2}}+10x+25 \right) \right)[/tex]

[tex]$ &=-\frac{2}{7}\left( {{x}^{3}}+10{{x}^{2}}+25x-\frac{3}{2}{{x}^{2}}-15x-\frac{75}{2} \right)[/tex]

[tex]$\\ &=-\frac{2}{7}\left( {{x}^{3}}+\frac{17}{2}{{x}^{2}}+10x-\frac{75}{2} \right)[/tex]

[tex]$\\ &=-\frac{1}{7}\left( 2{{x}^{3}}+17{{x}^{2}}+20x-75 \right)[/tex]

Therefore, the value of [tex]$\\ &P(x)=-\frac{1}{7}\left( 2{{x}^{3}}+17{{x}^{2}}+20x-75 \right)[/tex].

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The speed of the boat in still water is mph.
The speed of a river current is 3 mph. If a boat travels 30 miles downstream in the same time that it takes to travel 20 miles upstream, find the speed of the boat in still water.

Answers

Answer: the speed of the stream is 9mph

Please Help! Multiple Choice

Answers

Using the z-distribution, the z-statistic would be given as follows:

c) z = -2.63.

What are the hypothesis tested?

At the null hypothesis we test if the means are equal, hence:

[tex]H_0: \mu_D - \mu_C = 0[/tex]

At the alternative hypothesis, it is tested if they are different, hence:

[tex]H_1: \mu_D - \mu_C \neq 0[/tex]

What are the mean and the standard error for the distribution of differences?

For each sample, they are given as follows:

[tex]\mu_D = 12, s_D = \frac{5.2}{\sqrt{73}} = 0.6086[/tex][tex]\mu_C = 14, s_C = \frac{4.1}{\sqrt{81}} = 0.4556[/tex]

Hence, for the distribution of differences, they are given by:

[tex]\overline{x} = 12 - 14 = -2[/tex].[tex]s = \sqrt{0.6086^2 + 0.4556^2} = 0.76[/tex]

What is the test statistic?

The test statistic is given by:

[tex]z = \frac{\overline{x} - \mu}{s}[/tex]

In which [tex]\mu = 0[/tex] is the value tested at the null hypothesis.

Hence:

[tex]z = \frac{\overline{x} - \mu}{s}[/tex]

[tex]z = \frac{-2 - 0}{0.76}[/tex]

z = -2.63.

Hence option B is correct.

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Find and sketch the domain of f(X,y) = 1/√x^2-y

Answers

Answer:

Step-by-step explanation:

The definition of a Domain in math is all the possible input values that go into the function, so we will have to find all the valid values that can go into the function

The function given is [tex]F(x, y)=\frac{1}{\sqrt{x^2-y} }[/tex] , the denominator cannot be 0.
So we set up the equation
[tex]\sqrt{x^2-y} \neq 0[/tex]
[tex]\sqrt{x^2-y}^{2} \neq 0x^2-y\neq 0x^2\neq y[/tex]

And that the the square root needs to be more than 0.
[tex]\sqrt{x^2-y}\geq 0[/tex]
[tex]x^2-y\geq 0[/tex]
[tex]x^2\geq y[/tex]

So we can conclude that all values of [tex]x^{2}[/tex] must be greater y

That means that our domain is all X values greater than[tex]\sqrt{y}[/tex]

3^2x3^3 write on exponential form

Answers

The exponential form of the given information 3^2x3^3 is 3⁵.

What are exponential forms?

The exponential form is a convenient way of expressing or writing repeated multiplication expressions concerning their bases and power.

From the information given, the given expression can be written in exponential form by using the law of indices.

= 3^2x3^3  

[tex]\mathbf{=3^{2+3}}[/tex]

[tex]\mathbf{=3^{5}}[/tex]

Therefore, we can conclude that the exponential form of the given expression is 3⁵.

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IM IN A HURRY PLEASE HELP ME QUESTION IS DOWN BELOW WORTH 15 POINTS each

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If the radius of the circle is 5 m and angle subtended by arc LKM is 70° then the length of the arc LNM is 25.29 m.

Given that the radius of the circle is 5 m and angle subtended by arc LKM is 70°.

From the figure given we can estimate that the length of arc LNM can be circumference of circle subtracted by length of arc LKM.

Circulference of the circle is basically the length of whole arc of the circle. It is also know as perimeter of the circle. The formula of calculating circumference of a circle is 2πr in which r is the radius.

So,

length of arc LNM=Circumference of circle-length of arc LKM.

We know that length of an arc =Θr

in which Θ is the angle in radian.

length of arc=70*π[tex]/180*5[/tex]

=70π[tex]/36[/tex]

Circumference of circle=2π*5

=10π

Length of arc LNM=10π-70π[tex]/36[/tex]

=(360π-70π)[tex]/36[/tex]

=290π[tex]/36[/tex]

Put π=3.14

=290*3.14[tex]/36[/tex]

=910.6[tex]/36[/tex]

=25.29m

Hence the length of arc LNM is 25.29 m.

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Complete the statements. If both expressions have the same value after substituting and simplifying two different values for the variable, then they are . The value of both expressions when k = 3 is and when k = 5 is 45, so the expressions are .

Answers

When both expressions have the same value,  then they are equal to each other.

What is an equivalent expression?

The equivalent is the expressions that are in different forms but are equal to the same value.

Consider the expressions 5 + 8k and 8k + 5.

Using k = 3

5 + 8k = 8k + 5

5 + 8(3) = 8(3) + 5

5 + 24 = 24 + 5

29 = 29

Using k = 5

5 + 8k = 8k + 5

5 + 8(5)= 8(5) + 5

5 + 40 = 40 + 5

45 = 45

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Complete question:

Consider the expressions 5 + 8k and 8k + 5. Determine why the expressions are equivalent.

Using k = 3 5 + 8k 8k + 5 5 + 8(3) 8(3) + 5 5 + 24 = 29 24 + 5 = 29

Using k = 5 5 + 8k 8k + 5 5 + 8(5) 8(5) + 5 5 + 40 = 45 40 + 5 = 45

Complete the statements.

If both expressions have the same value after substituting and simplifying two different values for the variable, then they are.

The value of both expressions when k = 3 is and when k = 5 is 45, so the expressions are.

Three brothers, Jarek, Jerzy and Justyn, share a block of chocolate in the ratio of their ages. Jarek gets half of the bar. Jerzy gets 3\5 of the rest. Work out the ratio, in the form Jarek: Jerzy: Justyn, of how the brothers share the bar of chocolate.

Answers

Answer:

5:3:2

Step-by-step explanation:

see image

Jarek gets half. Then from the other half, Jerzy gets 3 pieces of 5 and Justyn gets the leftover 2 pieces. But Jarek's piece is all 5 pieces of the first half.

Jarek 5 parts:

Jerzy 3 parts:

Justyn 2 parts

5:3:2

see image

Use the following regression equation regarding airline tickets to answer the question.
Price = 49 + 0.137 · (Distance)

Note that Distance is the amount of kilometres between the departure and arrival cities, and Price is the cost of an airline
ticket.

Interpret the slope of the regression equation in the context of the data.

Answers

The interpretation of the slope is the price of an airline ticker per kilometer is 0.137

How to interpret the slope?

The regression equation is given as:

Price = 49 + 0.137 · (Distance)

A regression equation is represented as

y = b + mx

Where m represents the slope

By comparison, we have

m = 0.137


Slopes are used to represent average rates

This means that the interpretation of the slope is the price of an airline ticker per kilometer is 0.137

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What kind of multi step do I have to do to prove a is parallel to b and m parallel to n.

Answers

The proof that line n is perpendicular to both a and b is proved below using definition of right angle and perpendicular transversal theorem.

How to prove Perpendicular and Parallel Lines?

We are given that;

Line a is parallel to line b

Line m is parallel to line n.

A) We want to prove that line a is perpendicular to n.

From the image, we see that there is a right angle sign on the opposite side of ∠1 facing m.

Now, we know that by definition of a right angle that ∠1 will also be a right angle.

Since angle 1 is a right angle, then we can say the line transversal a is perpendicular to line m.

B) We want to prove that line b is perpendicular to n.

The definition of the perpendicular transversal theorem, states that if a line is perpendicular to one of two parallel lines, then it is perpendicular to the other.

Thus, b will be perpendicular to n.

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Show the calculation to find the μ and σ of a binomial variable whose probability of success if 0.3 with a total number of attempts of 20.

Answers

Using the binomial distribution, we have that:

The mean is of [tex]\mu = 6[/tex].The standard deviation is of [tex]\sigma = 2.05[/tex].

What is the binomial probability distribution?

It is the probability of exactly x successes on n repeated trials, with p probability of a success on each trial.

The expected value of the binomial distribution is:

[tex]\mu = np[/tex]

The standard deviation of the binomial distribution is:

[tex]\sqrt{V(X)} = \sqrt{np(1-p)}[/tex]

For this problem, the parameters are:

n = 20, p = 0.3.

Hence:

[tex]\mu = np = 20 \times 0.3 = 6[/tex][tex]\sqrt{V(X)} = \sqrt{np(1-p)} = \sqrt{20 \times 0.3 \times 0.7} = 2.05[/tex]

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A compression wave is moving away from an explosion at 100 ft/sec. How fast is the volume within the spherical compression wave increasing in t = 4 seconds? You will need the formula for the volume of a sphere! *Leave π in your answer do not convert to a decimal!

Answers

The volume within the spherical compression wave increasing in t = 4 seconds is:64000000π cubic ft/sec.

Volume of a sphere

Given:

dr/dt=100 ft/sec

When: t=4 seconds, radius(r)=400ft

Hence:

Volume of a sphere (V)=4/3πr³

dv/dt=4/3π.3r² dr/dt

dv/dt=4πr²dt/dr

When t=4 seconds

dv/dt=4π×(100×4)²×100 cubic ft/sec

dv/dt=4π×(400)²×100 cubic ft/sec

dv/dt=64000000π cubic ft/sec

Therefore the volume within the spherical compression wave increasing in t = 4 seconds is:64000000π cubic ft/sec.

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Which of the following is NOT a criterion for making a decision in a hypothesis test?
Choose the correct answer below.
OA. If P-values a, the decision is to reject the null hypothesis. Otherwise, we fail to reject the null hypothesis.
OB. If the test statistic falls within the critical region, the decision is to reject the null hypothesis.
OC. If a confidence interval does not include a claimed value of a population parameter, the decision is to reject
the Inull hypothesis.
OD. If the P-value is less than 0.05, the decision is to reject the null hypothesis. Otherwise, we fail to reject the null
hypothesis.

Answers

If the p-value less than 0.05, the decision is to reject the Null hypothesis.

What is hypothesis testing?Hypothesis testing is statistical reasoning using information from a sample to draw conclusions about a population parameter or population probability distribution. The parameter or distribution is initially bestguessed. Because it is the underlying assumption, the null hypothesis is often referred to as H0.For instance, you might explore and find that a specific drug effectively manages headaches. But nobody will believe what you find if you can't do that experiment again.A hypothesis seeks to provide an answer to a question. We will be forced to think about the results an experiment should try to achieve by a formulated hypothesis.The independent variable is the first variable. Results with seriousness.

The following should NOT be used as a decision-making standard in a hypothesis test.

If the p-value less than 0.05, the decision is to reject the Null hypothesis.

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find y' if x^y = y^x​

Answers

The answer is [tex]\boxed {\frac{dy}{dx} = \frac{y^{x}logy-yx^{y-1}}{x^{y}logx-xy^{x-1}}}[/tex].

Apply logarithmic differentiation on each side.

LHS

u = x^ylog u = y log x1/u du/dx = y/x + log x (dy/dx)du/dx = x^y (y/x + log x dy/dx)du/dx = yx^(y - 1) + x^y logx dy/dx

RHS

v = y^xlog v = x log y1/v dv/dx = x/y dy/dx + logydv/dx = y^x (x/y dy/dx + logy)dv/dx = xy^(x - 1) dy/dx + y^x logy

Equating both sides

yx^(y - 1) + x^y logx dy/dx = xy^(x - 1) dy/dx + y^x logydy/dx (x^y logx - xy^(x - 1)) = y^x logy - yx^(y - 1)[tex]\boxed {\frac{dy}{dx} = \frac{y^{x}logy-yx^{y-1}}{x^{y}logx-xy^{x-1}}}[/tex]

Country A has an exponential growth rate of 3.8​% per year. The population is currently ​,000, and the land area of Country A is ​35,000,000,000 square yards. Assuming this growth rate continues and is​ exponential, after how long will there be one person for every square yard of​ land?

Answers

The number of years it would it take for there to be one person for every square yard is 93.6 years.

How many years would it take for there to be one person for every square yard?

When there is one person for every square yard, it means that the population and land area are equal in value.

Number of years = (In FV / PV) / r

FV = future population PV = present population r = rate of growth

(In 35 billion / 1 billion) / 0.038 = 93.6 years

Here is the complete question:
Country A has an exponential growth rate of 3.8​% per year. The population is currently 1,000,000 ,000 and the land area of Country A is ​35,000,000,000 square yards. Assuming this growth rate continues and is​ exponential, after how long will there be one person for every square yard of​ land?

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What are the domain and range of the function f of x equals the quantity of x squared minus 3 x minus 28, all over x plus 4?

domain is x is all real numbers where x does not equal 4 comma range is y is all real numbers where y does not equal 11
domain is x is all real numbers where x does not equal 7 comma range is y is all real numbers where y does not equal negative 4
domain is x is all real numbers where x does not equal negative 4 comma range is y is all real numbers where y does not equal negative 11
domain is x is all real numbers where x does not equal negative 7 comma range is y is all real numbers where y does not equal 4

Answers

The domain is x is all real numbers where x does not equal negative 4 comma range is y is all real numbers where y does not equal negative 11. Option C

What is the domain of a function?

The domain of a function refers to the entire area for which the function returns a value. The function in this case is; f(x) = x^2 - 3x - 28/x + 4. The domain of the function will be real numbers except -4.

Hence, we can say that domain is x is all real numbers where x does not equal negative 4 comma range is y is all real numbers where y does not equal negative 11.

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Answer:

The answer is C.

f(x)=2x. If g(x) is a vertical stretch, compression, and or reflection of f(x) followed by a, what is the equation of g(x)?

Answers

The function g(x) is g(x)= (3x)^2

How to solve for g(x)?

The complete question is in the image

From the graph in the image, we have:

f(x) = x^2

The function f(x) is stretched by a factor of 3 to form g(x).

This means that:

g(x) = f(3x)

So, we have:

g(x)= (3x)^2

Hence, the function g(x) is g(x)= (3x)^2

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A jar has 16 marbles, 10 green, 2 blue, 4 red. what is the probability of randomly choosing a red marble then without putting it back, choosing a green marble?

Answers

The probability of drawing a red marble and then a green marble is:

P = 1/6.

How to find the probability?

In the jar we have a total of 16 marbles, such that:

10 are green.2 are blue4 are red.

First, the probability of getting a red marble is give by the quotient between the number of red marbles and the total number of marbles:

p = 4/16 = 1/4

Now we need to draw a green one, the probability is computed in the same way, but this time there are 15 marbles, because we already took one.

q = 10/15

The joint probability (first drawing red, then green) is given by the product between the individual probabilities:

P = p*q = (1/4)*(10/15) = 10/60 = 1/6

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According to the graph, what is the value of the constant in the equation
below?
Height =
Constant
Width
A. 0.3
B. 2.2
C. 0.4
D. 1.3
Height
1.8
1.6-
1.4
0.8
0.6 +
0.4+
0.2 +
(0.5, 0.8)
(0.8, 0.5)
(1.6, 0.25)
0.2 0.4 0.6 0.8 1 1.2 1.4 1.6 1.8
Width
(2,0.2)

Answers

Answer: 0.4

Step-by-step explanation:

Consider the point (0.5, 0.8).

Constant = (height)(width), which for this point, is 0.4.

Evaluate the expression.
n =
If P(n, 5) = 2520, find n.

Answers

The value of n in the permutation equation P(n, 5) = 2520 is 7

How to evaluate the permutation expression?

The expression is given as:

P(n, 5) = 2520

The above expression is a permutation expression.

The permutation expression is different from the combination expression, and the permutation expression is calculated using the following permutation formula

P(n,r) = n!/(n - r)!

Substitute 5 for r in the above equation

P(n,5) = n!/(n - 5)!

Substitute the given values in the above equation

n!/(n - 5)! = 2520

Expand the above equation

n(n-1)(n - 2)(n - 3)(n - 4)(n - 5)!/(n - 5)! = 2520

Evaluate the quotient in the above equation

n(n-1)(n - 2)(n - 3)(n - 4) = 2520

Express 2520 as 7 * 6 * 5 * 4 * 3

n(n-1)(n - 2)(n - 3)(n - 4) = 7 * 6 * 5 * 4 * 3

By comparing the equation, we have

n = 7

Hence, the value of n in the permutation equation P(n, 5) = 2520 is 7

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A researcher uses a random number generator to simulate the results of an experiment. Which of the following assignments of
random digits is appropriate for its experimental design?
A. let 0,2,4,6,8 represent selecting a face card (King, Queen, Jack) and 1,3,5,7,9 represent a non-face card in the selection of one card from a well-
shuffled 52-card deck of cards
B. let 0,1,2,3,4,5 represent flipping a heads on a fair coin and 6,7,8,9 represent flipping a tails with a fair coin
C. let 4 represent rolling a 4 on a fair 6-sided die and 0,1,2,3,5,6,7,8,9 represent not rolling a 4 on a fair 6-sided die
D. let 1,3,5,7, and 9 represent flipping a heads with a fair coin, and 0,2,4,6, and 8 represent flipping a tails with a fair coin.

Answers

The correct assignment of digits is D. let 1,3,5,7, and 9 represent flipping heads with a fair coin, and 0,2,4,6, and 8 represent flipping tails with a fair coin, as the probability of heads and tails is 1/2, and that of the assigned digits is 1/2.

In the question, we are given that a researcher uses a random number generator to simulate the results of an experiment and are asked for the appropriate assignment of random digits for its experimental design.

For the assignment to be correct, the probability of the random numbers must be equal to the probability of the experiment.

We analyze each option:

A. let 0,2,4,6,8 represent selecting a face card (King, Queen, Jack) and 1,3,5,7,9 represent a non-face card in the selection of one card from a well-shuffled 52-card deck of cards. The probability of a face card is 3/13, whereas the probability of an assigned digit is 5/10 = 1/2, which implies improper assignment.B. let 0,1,2,3,4,5 represent flipping heads on a fair coin and 6,7,8,9 represent flipping tails with a fair coin. The probability of getting heads is 1/2, whereas the probability of an assigned digit is 6/10 = 3/5, which implies improper assignment.C. let 4 represent rolling a 4 on a fair 6-sided die and 0,1,2,3,5,6,7,8,9 represent not rolling a 4 on a fair 6-sided die. The probability of rolling a 4 on a fair 6-sided die is 1/6, whereas the probability of assigned digits is 1/10, which implies improper assignment.D. let 1,3,5,7, and 9 represent flipping heads with a fair coin, and 0,2,4,6, and 8 represent flipping tails with a fair coin. The probability of heads and tails is 1/2, and that of the assigned digits is 1/2, which implies proper assignment.

Thus, the correct assignment of digits is D. let 1,3,5,7, and 9 represent flipping heads with a fair coin, and 0,2,4,6, and 8 represent flipping tails with a fair coin, as the probability of heads and tails is 1/2, and that of the assigned digits is 1/2.

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A truack Cars a load of 50 boxes 50 men are 20kg boxes and the rest and 25 ка Boxes. Is the Total weight of all Boxes is 1175 kg. How many of each type are there? X = 50kg Y=20kg 2= 25kg then sum of that is 1175 kg​

Answers

The number of boxes with 20kg = 15

The number of boxes with 25 kg = 35.

How to estimate the value of X and Y?

To estimate the value of x, bring the variable to the left side and bring all the remaining values to the right side. Simplify the values to estimate the result.

Total weight of all boxes = 1175kg

Total number of boxes = 50

X + Y = 50........................(1)

20X + 25Y = 1175 .............(2)

(1) [tex]\times[/tex] 20

20 (X + Y = 50)

20X + 20Y = 1000 .............(3)

Subtracting (3) from (2), we get

20X + 25Y = 1175 -

20X + 20Y = 1000

--------------------

5Y = 175

Y = 175/5

Y = 35

Substitute the value of y in (1), then we get

X + Y = 50

X + 35 = 50

X = 50 - 35

X = 15

The value of X = 15 and Y = 35

Number of boxes with 20kg = 15

Number of boxes with 25 kg = 35.

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A manufacturer has a steady annual demand for 38016 cases of sugar. It costs $9 to store 1 for 1 year, $33 in set up cost to produce each batch, and $18 to produce each case. Find the number of cases per batch that should be produced to minimize cost.

Answers

Based on the setup costs, the steady annual demand, and the costs to store, the number of cases to produce to minimize cost is 528 units .

How many cases should be produced to minimize cost?

This can be found by using the Economic Order Quantity.

= √ ( (2 x Setup costs x annual demand) / holding costs for the year)

Solving gives:

= √ ( ( 2 x 33 x 38,016) / 9)

= √278,784

= 528 units

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f(x)
X
(b)
Use the graph to determine the limit visually (if it exists). (If an answer does not exist, enter DNE.)
(a)
lim f(x)
X--1
-2
lim f(x)
x 0
Write a simpler function that agrees with the given function at all but one point.
q(x) =

Answers

a) Since both limits are distinct and do not exist, we conclude that x = - 1 is not part of the domain of the rational function.

b) The function [tex]f(x) = \frac{x}{x^{2}+ x}[/tex] is equivalent to the function [tex]g(x) = \frac{1}{x + 1}[/tex].

How to determine whether a limit exists or not

According to theory of limits, a function f(x) exists for x = a if and only if [tex]\lim_{x\to a^{-}} f(x) = \lim_{x \to a^{+}} f(x)[/tex]. This criterion is commonly used to prove continuity of functions.

Rational functions are not continuous for all value of x, as there are x-values that make denominator equal to 0. Based on the figure given below, we have the following lateral limits:

[tex]\lim_{x \to -1^{-}} \frac{x}{x^{2}+x} = - \infty[/tex]

[tex]\lim_{x \to -1^{+}} \frac{x}{x^{2}+x} = + \infty[/tex]

Since both limits are distinct and do not exist, we conclude that x = - 1 is not part of the domain of the rational function.

In addition, we can simplify the function by algebra properties:

[tex]\frac{x}{x^{2}+ x} = \frac{x}{x\cdot (x + 1)} = \frac{1}{x + 1}[/tex]

[tex]g(x) = \frac{1}{x + 1}[/tex]

The function [tex]f(x) = \frac{x}{x^{2}+ x}[/tex] is equivalent to the function [tex]g(x) = \frac{1}{x + 1}[/tex].

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what is the equation for -2(5x+8)

Answers

Answer:

Step-by-step explanation:

-10x-16

Answer:

distribute the -2 so your answer is -10x-16

Step-by-step explanation:

g(r) = -20 +11r
8(11) = ?

Answers

Answer:

g(11) = 101

Step-by-step explanation:

g(r) = -20 + 11r

So in g(11), we just need to replace 'r' with '11'

g(11) = -20 + 11 (11)

--> g(11) = -20 + 121 = 101

--> g(11) = 101

Please comment down below if 8(11) wasn't a typo. I thought it was, so I replaced 8 with g. If that was intentional, I'll edit my answer as soon as possible.

18. Sam retires in 1996. He has an amount of R350 000 available to invest. He decides to buy a second house for 50% of the money, which he lets at an amount of R2000 per month. He increases the rent every year by an amount of R300. The balance of R175 000 he invests in the bank at a rate of 12%. He uses the interest every month to supplement his income, so the interest is not compounded. He also gets a pension of R3000 per month, which is increased by R300 per month every year. What was his monthly income in 1996? (1)​

Answers

If Sam had Rs. 350000 and invested Rs.175000 in house, in bank Rs.175000 and getting 3000 pension then the monthly income was Rs. 6750.

Given that Sam had Rs.350000,investment in house Rs.175000 at a rent of Rs.2000 per month and Rs.175000 in bank at rate of 12%, getting pension of Rs.3000 per month.

We are required to find the monthly income in 1996.

We have assumed that Sam was retired on 1st January, 1996 so the amount of rent, investment in bank and pension did not increase because they had to be increase in a year and we have to calculate the monthly income in which he was retired.

Monthly income=Rent of 1 month+Simple interest of 1 month+Pension per month

=2000+175000*1/100+3000

=2000+1750+3000

=Rs.6750

Hence if Sam had Rs. 350000 and invested Rs.175000 in house, in bank Rs.175000 and getting 3000 pension then the monthly income was Rs. 6750.

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Amy made a circle graph of the U.S. population for 2000. This is the data that she used and the graph that she made.

Answers

The true statement is (b). No, because males and females should add up to 100% of the population.

How to determine the true statement?

The complete question is added at the end of this solution.

From the complete question, we have the following percentages

Male = 26%Female = 27%

When the above percentages are added, we have

Total = 26% + 27%

Evaluate the sum

Total = 53%

The above shows that the display of the circle graph is accurate.

This is so because the total percentage of the male and the female population must add up to 100%

Hence, the true statement is (b). No, because males and females should add up to 100% of the population.

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Complete question

Amy made a circle graph of the U.S. population for 2000. This is the data that she used and the graph that she made. U.S. Population (2000)

A circle graph titled U S Population (2000).

Males, 26 percent;

Females, 27 percent;

White, 39 percent;

Black, 6 percent;

Asian, 2 percent.

Males 138,053,563

Females 143,368,343

White 211,460,626

Black 34,658,190

Asian 10,242,998

Do you think this is an accurate display of the U.S. population? Why or why not?

a. Yes, because the percentages add up to 100%.

b. No, because males and females should add up to 100% of the population.

c. Yes, because the majority of the population is white.

d. No, because the percentage of males and females should be equal.

Math man fell from the top of a 500 meter building. The equation d = t squared * 0.25 describes math man's distance from the ground as he falls. How long does math man spend falling if he falls all the way from the top of the building to the ground? Round your answer to the nearest tenth.

Answers

Based on the equation of the function of the height of the building, it takes the man 44.7 seconds to fall from the top

How to determine how long it takes the math man to fall?

The function of the height where the man falls is a quadratic function, and the equation of the function is given as:

d = t^2 * 0.25

The height of the building is 500

This means that the value of d is 500.

So, we have;

d = 500

Substitute 500 for d in the equation d = t^2 * 0.25

500 = t^2 * 0.25

Divide both sides of the above equation by 0.25

500/0.25 = t^2 * 0.25/0.25

Evaluate the quotient in the above equation

t^2 = 2000

Take the square root of both sides in the above equation

√t^2 = √2000

Evaluate the exponent

t = 44.7

Hence, it takes the man 44.7 seconds to fall

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You are buying shoes for an athletic store. They cost $32 per pair of shoes. The company decides Mark Up the shoes by 75%. What is the selling price for shoes in the athletic store?
A. $56.00
B. $40.00
C. $45.00
D. $24.00
E. $8.00

Answers

Answer:

  A.  $56

Step-by-step explanation:

The markup is added to the cost price to find the selling price.

Markup

The markup is 75% of the cost price:

  markup = 75% × $32 = $24

Selling price

The selling price is the cost price plus the markup:

  selling price = cost + markup

  selling price = $32 +24 = $56

The selling price of shoes in the athletic store is $56 per pair.

The selling price for shoes in the athletic store with 75% mark up is [tex]\$56[/tex]

Selling price of the item is sum of Markup and cost price.

The cost of shoes is [tex]\$32[/tex]. The company decides Markup by [tex]75\%[/tex] of cost price.

Find Markup value.

Markup = [tex]\frac{75}{100}\times 32[/tex]

Markup = [tex]\$24[/tex]

Find selling price.

Selling price = Markup + Cost price

Selling price = [tex]24+32[/tex]

Selling price = [tex]\$56[/tex]

The selling price for the shoes in the athletic store is [tex]\$56[/tex].

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