Calculate the location xcm of the center of mass of the Earth-Moon system. Use a coordinate system in which the center of the Earth is at x

Answer:

1) p₀ = 45000 N / s ,   p₀ '= 1800 , b)  I = -45000 N s ,  I = 1800 Ns

Explanation:

Impulse equals the change in momentum

         I = Δp

1) the initial moment of the car

         p₀ = M v

          p₀ = 1500 30

          p₀ = 45000 N / s

the change at the moment is

          Δp = 45000

because the end the car is stopped

moment of the person

          P₀ ’= m v

         p₀ '= 60 30

          p₀ '= 1800

          D₀ '= 1800

2) of the momentum change impulse ratio

        car

              I =  Δp

              I = -45000 N s

        person

              I = Δpo '

              I = 1800 Ns

3) the object that give the momentum to stop the wall motoring

The person is stopped by the impulse given by the car

a) This area is the one that absorbs most of the vehicle impulse

be) If using a safety painter, the time during which the greater force will act, therefore the lessons decrease

c) The air bag helps reduction in the speed of the person relatively quickly.

The blue sky we observe depends upon two factors: how sunlight interacts with Earth's atmosphere, and how our eyes perceive that light.

If this helps please mark me the brainiest

how sunlight interacts with Earth's atmosphere, and how our eyes perceive that light.nation:

Answer:

d. beach is the correct answer

Beach is the most likely site for deposits in this photograph. So, the correct option is (D).

A beach is defined as a narrow strip of land separating a body of water from inland areas usually made up of small grains of sand, rocks and minerals that have been eroded by frequent pounding by wind and waves. become The beach has both sandy and rocky features.

Beaches provide protection to residents living near the sea by acting as a buffer against high winds and powerful storms or waves of rough seas which also play an important role in the economy. This is the most likely site for deposits in this photograph,

Thus, Beach is the most likely site for deposits in this photograph. So, the correct option is (D).

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Answer: 1) a = 9.61m/s² pointing to west.

             2) (a) Δv = - 37.9km/s

                  (b) a = - 6.10⁷km/years

Explanation: Aceleration is the change in velocity over change in time.

1) For the plane:

[tex]a=\frac{\Delta v}{\Delta t}[/tex]

[tex]a=\frac{125}{13}[/tex]

a = 9.61m/s²

The plane is moving east, so velocity points in that direction. However, it is stopping at the time of 13s, so acceleration's direction is in the opposite direction. Therefore, acceleration points towards west.

2) Total change of velocity:

[tex]\Delta v = v_{f}-v_{i}[/tex]

[tex]\Delta v = -17.1-(+20.8)[/tex]

[tex]\Delta v= -37.9[/tex]km/s

The interval is in years, so transforming seconds in years:

v = [tex]\frac{-37.9}{3.15.10^{-7}}[/tex]

[tex]v=-12.03.10^{7}[/tex]km/years

Calculating acceleration:

[tex]a=\frac{-12.03.10^{-7}}{2.01}[/tex]

[tex]a=-6.10^{7}[/tex]

Acceleration of an asteroid is a = -6.10⁷km/years .

Answer:

a)    A = 0.07129 m²

b)    A / A ’= 1.77

Explanation:

In this exercise we are asked to find the area in SI units, so let's start by reducing the dimensions to SI units.

width a = 8.5 inch (2.54 cm 1 inch) (1 m / 100 cm)

            a = 0.2159 m

length l = 13 inch (2.54 cm / 1 inch) (1 m / 100 cm)

              l = 0.3302 m

The area of ​​a rectangle is

            A = l a

             A = 0.3302 0.2159

             A = 0.07129 m²

b) we have a second sheet with reduced dimensions

         a ’= 3/4 a

         l ’= ¾ l

Let's find the area of ​​this glossy sheet

         A ’= l’ a ’

         A ’= ¾ l ¾ a

         A ’= 9/16 l a

To find the factor we divide the two quantities

           A / A ’= l a 16 / (9 l a

            A / A ’= 1.77

The correct answer is B. 1.3 m/s north

Explanation:

Velocity is a factor that describes how fast or slow the motion of a body occurs and its direction. Moreover, this can be calculated by dividing the total displacement into the time of movement, and the final result is expressed in units such as meters per second followed by the direction, for example, 152 m/s south. The process to calculate the velocity of the swimmer is shown below.

[tex]v = \frac{d}{t}[/tex]

[tex]v = \frac{28 meters}{22 seconds}[/tex]

[tex]v = 1.27 m/s[/tex]

This means the velocity of the swimmer is 1.27 m/s, which can be rounded as 1.3 m/s. Additionally, if the direction is considered it would be 1.3 m/s north because the swimmer went from the south of the pool to its north.

Answer:

the answer is B

Explanation:

confirmed

Answer:

bobby has a greater magnitude of velocity because because when angular speed is constant linear velocity is proportional to radius of the circular path

B. They both have same magnitude of angular velocity since the angular speed of the merrygoround is constant

C. Also they both have the same tangential acceleration because the angular speed is constant and tangential is zero for both of them

D. Centripetal acceleration of Bobby is greater

E.they both have the same angular acceleration because angular Speed I constant so angular acceleration is zero for both

Answer:

Explanation:

⁶₃Li will have 3 protons and 3 neutrons .

mass of proton in amu = 1.00727 amu

mass of neutron in amu = 1.00866 amu

mass of lithium nucleus in amu = 6.01512 amu

mass defect = 3 (  1.00727  + 1.00866 ) - 6.01512 amu

= .03267 amu

Binding energy = mass defect in amu x 931 Mev

= 30.41 MeV

binding energy per nucleon

no of nucleon = 3 + 3 = 6

binding energy per nucleon = 30.41 / 6 Mev

= 5.068 MeV .

The binding energy of  ⁶₃Li nucleus in MeV per nucleon is 5.26  MeV per nucleon.

We can see that Li has three protons and three neutrons. The total mass of the Li nucleus is obtained from;

3(1.007277) + 3(1.008665) = 3.023 + 3.026 = 6.049 amu

Actual mass of Li - 6 =  6.0151 amu

Mass defect = 6.049 amu - 6.0151 amu = 0.0339 amu

We can obtain the binding energy in MeV as follows;

Binding energy = 0.0339 amu × 931 = 31.56 MeV

The binding energy per nucleon in MeV per nucleon =  31.56 MeV/6

= 5.26  MeV per nucleon

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Answer:

Is a flame hottest when it is blue?  Is it cold today?

Explanation:

Verification questions. These are basic data collecting questions. They are useful in building knowledge.

Answer:

Explanation:

We shall convert all the displacement in vector form .

i and j represents east and north respectively .

D₁ = 4 i

D₂ = 4 j

D₃ = - 5 cos 53.1 i + 5 sin 53.1 j

= -3i + 4 j

Total displacement = D₁ + D₂ + D₃

= 4i + 4 j - 3i + 4 j

= i + 8j

magnitude of displacement = √( 1² + 8² )

= 8.06 km

velocity = 8.06 / 5

= 1.61 km / h

Direction from x axis in anticlockwise direction .

Tanθ =  8 / 1 = 8

θ = 83° north of east .

Answer:

117.8 m³/s

Explanation:

given that

the diameter of the river, d = 10 m wide

Velocity of flow of water, v, = 3 m/s

To get the discharge of a river, we have to find the area of the said river first.

Area of the river, a = area of semi circle = 1/2 * area of a circle

Area = 1/2 * πr²

Area = 1/2 * 3.142 * 5²

Area = 39.275 m²

Discharge of the river therefore is

Discharge, q = A * V, where

A is area of the river, and

V is the velocity of flow of the river.

Discharge, q = 39.275 * 3

Discharge, q = 117.825

Answer:

6787.5 V

Explanation:

From the question,

P = IV..................... Equation 1

Where P = Power, I = rms current, V = rms voltage.

make V the subject of the equation

V = P/I................. Equation 2

Given: P = 1500 W, I = 6.4/√2 = 4.525 A

Substitute these values into equation 2

V = 1500(4.525)

V = 6787.5 V

Hence the rms voltage = 6787.5 V

Answer:

v = 6.79 m/s

Explanation:

It is given that,

Mass of a train car, m₁ = 11000 kg

Speed of train car, u₁ = 21 m/s

Mass of other train car, m₂ = 23000 kg

Initially, the other train car is at rest, u₂ = 0

It is a case based on inelastic collision as both car couples each other after the collision. The law of conservation of momentum satisied here. So,

[tex]m_1u_1+m_2u_2=(m_1+m_2)V[/tex]

V is the common velocity after the collisions

[tex]V=\dfrac{m_1u_1}{(m_1+m_2)}\\\\V=\dfrac{11000\times 21}{(11000+23000)}\\\\V=6.79\ m/s[/tex]

So, the two car train will move with a common velocity of 6.79 m/s.

Answer:

Explanation:

252,000

Answer:

Explanation:

point a represents time 0 and position coordinate 30

point b represents time 10 s , and position coordinate 50 m .

time elapsed = 10 - 0 = 10 s .

displacement = 50 m - 30 m

= 20 m

average velocity = displacement / time elapsed

= 20 / 10

= 2 m /s .

Answer:

The correct answer will be "2".

Explanation:

Answer:

The final velocity of the runner at the end of the given time is 2.7 m/s.

Explanation:

Given;

initial velocity of the runner, u = 1.1 m/s

constant acceleration, a = 0.8 m/s²

time of motion, t = 2.0 s

The velocity of the runner at the end of the given time is calculate as;

[tex]v = u + at[/tex]

where;

v is the final velocity of the runner at the end of the given time;

v = 1.1 + (0.8)(2)

v = 2.7 m/s

Therefore, the final velocity of the runner at the end of the given time is 2.7 m/s.

Answer:

independent

dependent

dependent

Complete Question  

A very long, straight solenoid with a cross-sectional area of 2.39cm2 is wound with 85.7 turns of wire per centimeter. Starting at t= 0, the current in the solenoid is increasing according to i(t)=( 0.162A/s2) t2. A secondary winding of 5 turns encircles the solenoid at its center, such that the secondary winding has the same cross-sectional area as the solenoid. What is the magnitude of the emf induced in the secondary winding at the instant that the current in the solenoid is 3.2A ?

Answer:

The value  is [tex]\epsilon =  1.83 *10^{-5} \  V[/tex]

Explanation:

From the question we are told that

    The  cross-sectional area is  [tex]A = 2.39 \ cm^2 = \frac{2.39}{10000} = 0.000239 \ m^2[/tex]

    The  number of turns is  [tex]N = 85.7 \ turns/cm = 8570 \ turns / m[/tex]

    The initial time is  t = 0s

    The  current on the solenoid  is [tex]I(t)   = (0.162 \ A/s^2) t^2[/tex]

     The number of turns of the secondary winding is  [tex]n =  5 \ turns[/tex]

Generally At I =  3.2 A

        [tex]3.2 =  (0.162 )t^2[/tex]

=>       [tex]t^2  =  19.8[/tex]

=>         [tex]t =  4.4 \  s[/tex]

Generally induced emf is mathematically represented as

        [tex]\epsilon  = A *  \mu_o *  n *  N  \frac{d(I)}{dt}[/tex]

         [tex]\epsilon  =  0.000239 *  4\pi * 10^{-7} *  8570 * 5 *  (0.162) * 2t[/tex]

          [tex]\epsilon  =  0.000239 *  4\pi * 10^{-7} *  8570 * 5 *  (0.162) * 2 *  4.4[/tex]  

        [tex]\epsilon =  1.83 *10^{-5} \  V[/tex]

Answer:

Explanation:

Let the magnetic field after .37 s is B

magnetic flux associated with coil = n BA , where B is magnetic field and A is area of coil and n is no of turns

= 55 x .12 x 1.75

= 11.55 Tm²

magnetic flux after .37 s

= 55 x B x .12

= 6.6 B

rate of change of flux = (66B - 11.55)  / .37 = EMF induced

(6.6B - 11.55)  / .37 = 12.7

6.6 B - 11.55 = 4.7

6.6 B = 16.25

B = 2.46 T .

Answer:

The correct answer is:

The instantaneous speed is always equal to the magnitude of instantaneous velocity. (A)

Explanation:

Speed is the ratio of distance travelled to time. It is a scalar quantity.

Velocity is the rate of change of displacement with time. It is a scalar quantity, having both magnitude and direction

Instantaneous velocity is the rate of change of position for a very small time interval (at a particular point in time), while the instantaneous speed at any given time, is the magnitude of instantaneous velocity. Note that the velocity has both magnitude and direction, so at a particular point in time, the magnitude part of velocity is the same as the speed.

The formula of instantaneous velocity is: [tex]V_{i}=\lim_{\Delta t\rightarrow 0}\frac{ds}{dt}[/tex]

The formula of instantaneous speed is: [tex]Speed_{(i)}=\frac{ds}{dt}[/tex]

On the other hand, average speed does not equal the magnitude of average velocity, because velocity depends on displacement while speed depends on distance, and if an object in motion changes direction at any point in the motion, the velocity reduces because the angle of change in the direction will be considered, hence the speed will be greater than the velocity, therefore, the average speed is not the same as the magnitude of average velocity.

In a position-time graph, the velocity of the moving object is represented by the slope, or steepness, of the graph line. If the graph line is horizontal, like the line after time = 5 seconds in Graph 2 in the Figure below, then the slope is zero and so is the velocity. The position of the object is not changing.

Explanation:

The slope of a position time graph gives the velocity of an object. It can be calculated as follows:

[tex]v=\dfrac{dx}{dt}[/tex]

Where

[tex]dx[/tex] is the change in position

[tex]dt[/tex] is the change in time

If the position vs time graph of an object is a horizontal line, it shows that the object is at rest. At this point the object is not moving.

Answer:

If the position versus time graph of an object is a horizontal line, the object is at rest.

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Answer: a Had twice as much mass

Explanation:

The data that we have is:

"The force of gravity pulls down on your school with a total force of 400,000 newtons. "

First, remember that, by the second Newton's law that:

F = a*m

F = force

a = acceleration

m = mass

In the case of the gravitational force, the gravitational acceleration is a constant: a = 9.8m/s^2

Then, if we want to have twice as much force the only thing that we can change in the equation is the mass:

Then if the initial force is written as:

F = a*m

twice as much that force is written as:

2*F = a*x

x is a variable that represents the new mass.

We know that F = a*m

2*F = 2*a*m

2*a*m  = a*x

2*m = x

Then, if we want to have twice as much force, we should have twice as much mass.

Answer:

3.68 m/s

Explanation:

Full answer in the attached picture

Answer:

b) directional

Explanation:

The prediction that alcohol slows reaction time is Directional . This is because for alcohol to be known as one which slows reaction time means there have been various hypothesis conducted which supports this.

In this case, formulation of a null hypothesis is usually necessary which means that alcohol does not slow reaction time and another alternative hypothesis that suggests that alcohol slows reaction time.

Explanation:

Height is the x-axis, and gravitational potential energy is the y-axis.  As the height increases, the gravitational potential energy increases linearly.

Answer:

-19.9m/s²

Explanation:

Given that

vi = 14cm/s

xi = 2.94 cm

xf=-5.00 cm

t= 1.85s

So

Using xf-xi= vi t + 1/2at²

Which is = -5-2.94= 14*1.85+1/2a1.85²

= -7.94= 25.9+1.7a

-33.9= 1.7a

a= - 19.9m/s²

Answer:

Explanation:

Force = mass × acceleration

F = ma

Answer:

the speed at which a moving clock lose 4,5ns in 1.0 day is 98.58 m/s

Explanation:

Let's first find the relation for the time dilation by using the formula:

[tex]\Delta t' = \Delta t \gamma[/tex]

Making [tex]\gamma[/tex] the subject of the formula, we have:

[tex]\gamma= \dfrac{\Delta t'}{\Delta t}[/tex]

Number of day(s) = 1

1 day in seconds = 24 × 60 × 60

= 84600 seconds

[tex]\gamma= \dfrac{86400 \ s}{86400 \ s - 4.5 \ ns}[/tex]

[tex]\sqrt{1- \dfrac{v^2}{c^2} }= \dfrac{86400 \ s - 4.5 \ ns}{86400 \ s}[/tex]

[tex]\sqrt{1- \dfrac{v^2}{c^2} }= 1 - 5.4 \times 10^{-14}[/tex]

From the above equation, if we apply binomial expansion to it, we have the following,

[tex]\sqrt{1- \dfrac{v^2}{c^2} }=(1-\dfrac{v^2}{c^2})^{\frac{1}{2}}[/tex]

⇒[tex]1 -\dfrac{1}{2}(\dfrac{v^2}{c^2})[/tex]

So;

[tex]1 -\dfrac{1}{2}(\dfrac{v^2}{c^2}) = 1 - 5.4 \times 10^{-14}[/tex]

[tex]\dfrac{1}{2}(\dfrac{v^2}{c^2}) = 5.4 \times 10^{-14}[/tex]

[tex]\dfrac{v^2}{c^2} = 2 \times 5.4 \times 10^{-14}[/tex]

[tex]\dfrac{v^2}{c^2} = 1.08 \times 10^{-13}[/tex]

[tex]v^2 = 1.08 \times 10^{-13} \times c^2[/tex]

where ;

[tex]c = 3 \times 10^8 \ m/s[/tex]

[tex]v^2 = 1.08 \times 10^{-13} \times (3 \times 10^8 \ m/s)^2[/tex]

[tex]v = \sqrt{ 1.08 \times 10^{-13} \times (3 \times 10^8 \ m/s)^2}[/tex]

[tex]v = \sqrt{ 1.08 \times 10^{-13} } \times (3 \times 10^8 \ m/s)[/tex]

[tex]v =3.286 \times 10^{-7} \times (3 \times 10^8 \ m/s)[/tex]

[tex]\mathbf{v =98.58 \ m/s}[/tex]

Therefore, the speed at which a moving clock lose 4,5ns in 1.0 day is 98.58 m/s