Calculate the molar mass of powdered fruit drink mix, made from sucrose (c12h22o11). appreciate it.

Answers

Answer 1

molar mass of sucrose is 342 g/mol.

Concept:

It is the substance's molecular mass. M is the abbreviation for it, and g/mol is the standard unit for measuring molar mass.

Given:

Sucrose (C12H22O11)

Find:

Calculate the molar mass of the powdered fruit drink mix, made from sucrose (C12H22O11).

Solution:

The molar mass of carbon = 12 g/mol

The molar mass of hydrogen = 1 g/mol

The molar mass of oxygen = 16 g/mol

Thus, the molar mass of sucrose can be calculated as:

C12H22O11 12 C + 22 H + 11 O

= 12 12 g/mol + 22 * 1 g/mol + 11 * 16 g/mol

= 144 g/mol + 22 g/mol + 176 g/mol = 342 g/mol

Therefore, the molar mass of sucrose is 342 g/mol.

Hence, the molar mass of the powdered fruit drink mix, made from sucrose

Hence, the molar mass of the powdered fruit drink mix, made from sucrose(C12H22O11) is 342 g/mol.

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Related Questions

The function of the heat exchanger in a nuclear reactor is to...
Select one:
a. prevent the leakage of radiation into the environment.
b. convert water into steam, which turns a turbine.
c. cool the reactor water.
d. absorb neutrons to slow down the chain reaction.

Answers

Answer:

cool the tractor water system

How many grams of CO2 will be produced when 8.50 g of methane react with 15.9 g of O2, according to the following reaction? CH4(g) +2 O2(g) = CO2(g) +2 H2O(g)

Answers

Taking into account the reaction stoichiometry, 10.93 grams of CO₂ are formed when 8.50 g of methane react with 15.9 g of O₂.

Reaction stoichiometry

In first place, the balanced reaction is:

CH₄ + 2 O₂  → CO₂ + 2 H₂O

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

CH₄: 1 mole O₂: 2 molesCO₂:  1 moleH₂O: 2 moles

The molar mass of the compounds is:

CH₄: 16 g/moleO₂: 32 g/moleCO₂:  44 g/moleH₂O: 18 g/mole

Then, by reaction stoichiometry, the following mass quantities of each compound participate in the reaction:

CH₄: 1 mole ×16 g/mole= 16 gramsO₂: 2 moles ×32 g/mole= 64 gramsCO₂:  1 mole ×44 g/mole= 44 gramsH₂O: 2 moles ×18 g/mole=36 grams

Limiting reagent

The limiting reagent is one that is consumed first in its entirety, determining the amount of product in the reaction. When the limiting reagent is finished, the chemical reaction will stop.

Limiting reagent in this case

To determine the limiting reagent, it is possible to use a simple rule of three as follows: if by stoichiometry 16 grams of CH₄ reacts with 64 grams of O₂, 8.50 grams of CH₄ reacts with how much mass of O₂?

[tex]mass of O_{2} =\frac{8.50 grams of CH_{4}x64 grams of O_{2} }{16grams of CH_{4}}[/tex]

mass of O₂= 34 grams

But 34 grams of O₂ are not available, 15.9 grams are available. Since you have less mass than you need to react with 8.50 grams of CH₄, O₂ will be the limiting reagent.

Mass of CO₂ formed

The following rule of three can be applied: if by reaction stoichiometry 64 grams of O₂ form 44 grams of CO₂, 15.9 grams of O₂ form how much mass of CO₂?

[tex]mass of CO_{2} =\frac{15.9 grams of O_{2}x44 grams of CO_{2} }{64grams of O_{2}}[/tex]

mass of CO₂= 10.93 grams

Then, 10.93 grams of CO₂ are formed when 8.50 g of methane react with 15.9 g of O₂.

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How many moles of solute particles are present in 1 l (exact) of aqueous 0.057 m hno3?

Answers

The total number of moles of solute particles present in 1L (exact) of aqueous 0.057 m hno3 is 0.166 mol

Initial moles of HNO3 = 1Lx 0.083 mol HNO3/1 L

The HNO3 is a strong acid that can be completely dissociated in the following way.

HNO3→H  +  NO

1 mol   1 mol 1 mol

The HNO3 is dissociated into two particles (Kt and NO3). So that,

total moles particles = 0.083 mol (K) + 0.083 mol (NO) = 0.166 mol

The number of moles of solute = mass of solute ÷ molar mass of solute, where mass is measured in grams and molar mass (defined as the mass of one mole of a substance in grams) is measured in g/mol.

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The half-life of cesium-137 is 30 years. Suppose we have a 150 mg sample. (a) Find the mass (in mg) that remains after t years.

Answers

The half-life of cesium-137 is 30 years. Suppose we have a 150 mg sample. The masses (in mg) that remains after t years A=150/2^t/30yrs

what do you mean by half-life?

A substance's half-life is the amount of time it takes for half of it to decompose.

What is a half-life example?

Half-life is the length of time it takes for half of an unstable nucleus to go through its decay process. A radioactive element's half-life decay time varies depending on the element. For instance, carbon-10 has a half-life of only 19 seconds, making it impossible to discover in nature. On the other hand, uranium-233 has a half-life of almost 160000 years.

When n half-lives have passed, the formula for estimating the amount still left is:-

A=A°/2^n

where,

A=initial amount

A°=remaining amount

n=t/t_{1/2}

A=150/2^t/30yrs

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- According to collision theory, what is not a factor that determines if two molecules will bind?
A. The direction the molecules are facing.
B. The speed the molecules are traveling.
C. The specific heat of the molecules.
D. What element the molecules are.

Answers

The factor which will not determines if two molecules will bind according to collision theory is the direction the molecules are facing

What is collision theory?

Collision theory is a theory which describes of predicting the rate at which chemical reactions occurs between atoms and molecules of elements.

So therefore, the factor which will not determines if two molecules will bind according to collision theory is the direction the molecules are facing

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Bonding gels and _____ are designed specifically to improve adhesion of light cured gels to the natural nail plate. glossing gels self-leveling gels gel primers building gels

Answers

Bonding gels and gel primers are designed specifically to improve adhesion of light cured gels to the natural nail plate and is therefore denoted as option C.

What is Adhesion?

This is defined as the tendency of particles or substance which have dissimilar origins to stick to one another. A common adhesive is referred to as glue, cement etc  and ensures there is enough resistance for their separation in case of the presence of any type of external force or stimuli acting on them.

Gel primer is referred to a vital used in makeup and serves as a form of foundation before they are applied on the skin of individuals so as to enable it stick and also look more presentable.

This is therefore the reason why gel primers was chosen as the most appropriate choice.

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What are the correct half reactions for the following reaction:
Zn + 2 HCI -> H₂ +zncl2

Answers

Answer:

Zn(s) + 2H+(aq) => Zn²+(aq) + H2 (g)

Explanation:

The equation Zn + 2 HCI -> H₂ +zncl2 on reduction and oxidation, it results as below;

2H+ + 2e- => H2 ; reductionZn => Zn²+ + 2e- ; oxidation

The equations above are half cell.

On combination of the above half cell reaction equations gives;

Zn(s) + 2H+(aq) => Zn²+(aq) + H2 (g).

Therefore, the half reaction equation for Zn + 2 HCI -> H₂ +zncl2 is given by;

Zn(s) + 2H+(aq) => Zn²+(aq) + H2 (g).

A solid form of matter in which there is long range repeating order is called ________

Answers

Answer: A solid form of matter in which there is long-range repeating order is called crystalline.

Explanation:

A solid is crystalline if it has long-range order. Once the positions of an atom and its neighbors are known at one point, the place of each atom is known precisely throughout the crystal.

Blank + 3Fe, reaction arrow, Fe3O4+4H2
How to complete this equation so that it is a Single displacement reaction

Answers

The complete reaction equation is [tex]3Fe + 4H_2O -- > Fe_3O_4 + 4H_2[/tex]

What are single displacement reactions?

They are reactions in which one of the elements in a reactant is displaced by another element in the product.

In the reaction leading to the production of [tex]Fe_3O_4[/tex], Fe displaced H atoms from [tex]H_2O[/tex].

Thus, the equation of the reaction is as follows:

[tex]3Fe + 4H_2O -- > Fe_3O_4 + 4H_2[/tex]

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A student started with 0.3295 g of copper. The mass of filter paper and copper (II) oxide product was found to be 0.5723 g, and that of the filter paper alone was 0.2568 g. Calculate the percent yield of copper (II) oxide.

Answers

The percent yield will be 95.75%

Percent yield

Mass of copper = 0.3295 g

Mass of filter paper + copper (II) oxide = 0.5723

Mass of filter paper only = 0.2568

Mass of copper (II) oxide = 0.5723 - 0.2568 = 0.3155

Percent yield = yield/total x 100%

                      = 0.3155/0.3295 x 100% = 95.75%

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The solubility of pbso₄ in water at 25 °c is 7. 9 × 10⁻⁴ m. What is ksp for pbso₄?.

Answers

ksp = 2S²

= 2 [ 7.9* 10-⁴ moldm-³ ]²

= 124.82 * 10-⁸ mol² dm-⁶

The term Ksp denotes the solubility product. It is generally used to predict the precipitation of reactions. The  Ksp of PbSO₄ is  6.24 × 10⁻⁷.

What is solubility product?

The solubility product of a sparingly soluble salt is defined as the product of the molar concentrations of its ions in a saturated solution of it at a given temperature. By knowing the solubility product of a substance, it is possible to predict whether a substance precipitate out or not.

In short, the precipitation of an ionic substance from the solution occurs when the ionic product exceeds the value of its solubility product at that temperature.

Here PbSO₄ dissociates as:

PbSO₄ → Pb²⁺ (aq) + SO₄²⁻ (aq)

Ksp = [Pb²⁺] [SO₄²⁻ ]

= [7. 9 × 10⁻⁴] [7. 9 × 10⁻⁴]

= 6.24 × 10⁻⁷

Thus the value of Ksp is  6.24 × 10⁻⁷.

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4- The equilibrium constant for the reaction A (g) B (g) is 10. A reaction mixture initially contains [A]

Answers

The initial concentration in the reaction mixture will contain [A] = 0.1 M and [B] = 1.0 M

Below is the reaction

A(g) → B(g)

And the equilibium constant will be explained in terms of [A] and [B]:

Keq = 10 = [B]/[A]

If the first conditions are that [A] = 1.1 M and [B] = 0.0 M, the conditions at equilibrium is:

[A] = 1.1M - x

[B] = 0.0M + x

Now we rewrite Keq:

Keq = 10 = [0.0 +x] / [1.1 -x]

at the end we got it  for x:

10 = [0.0 +x] / [1.1 -x]

10 * (1.1-x) = x

11 - 10x = x

11 = 11x

x = 1

equilibrium, the concentrations are:

[A] = 1.1 M - 1 = 0.1 M

[B] = 0.0 M + 1 = 1.0 M

Thus, the concentration of A is 0.1 M and the concentration of B is 1M.

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One of the product chemicals is aluminum chloride, which is an eye and skin irritant that can cause chemical burns. What will prevent you from coming into contact with this hazard

Answers

One of the product chemicals is aluminum chloride, which is an eye and skin irritant that can cause chemical burns. Wear safety glasses, Avoid contact with water or moisture and Avoid dust formation will prevent you from coming into contact with this hazard.

What is Aluminum Chloride ?

Aluminum chloride is also called Aluminum trichloride. The formula of Aluminum chloride is AlCl₃. Aluminum chloride is a poor conductor of electricity in molten state. It is a powerful Lewis acid. It has very low melting point and boiling point.  

What will prevent you from coming into contact with this hazard ?

To prevent from this hazard follows these rules:

Wear safety glassesWear Impervious gloves Avoid contact with water or moisture. Avoid dust formation

Thus from the above conclusion we can say that One of the product chemicals is aluminum chloride, which is an eye and skin irritant that can cause chemical burns. Wear safety glasses, Avoid contact with water or moisture and Avoid dust formation will prevent you from coming into contact with this hazard.

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In your reaction you started with a solution that was approximately 8 M acetic acid and 4 M isopentyl alcohol. Use the equilibrium expression for this reaction to calculate the final concentrations of water, isopentyl acetate, isopentyl alcohol, and acetic acid (you'll need to use the quadratic equation to solve this expression) assuming that the equilibrium constant is 4.2. Calculate the percent yield of isopentyl acetate to which this value would correspond.

Answers

The final concentrations of water, isopentyl acetate, isopentyl alcohol, and acetic acid obtained on using equilibrium expression are 3.4M, 3.4M, 0.6M , 4.6M

Using ICE table:-

      Acetic acid  +  Isopentyl alcohol   ------>    Isopentyl acetate +  water

I         8M                   4M                                           0                           0

C        8-x                   4-x                                          +x                          +x                      

E        8-x                   4-x                                          +x                          +x

Equilibrium constant (Keq) = 4.2

On using the equilibrium expression -

Keq = [Product] / [Reactant]

Keq = x^2 / (8-x) (4-x )

4.2  =  x^2 / 32 - 8x - 4x + x^2

    x =  3.4

Concentration of acetic acid  = 8-x = 8-3.4 = 4.6M

Concentration of isopentyl alcohol = 4-x = 4-3.4 = 0.6M

Concentration of isopentyl acetate = x = 3.4M

Concentration of water = x = 3.4M

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Ammonia, NH3, undergoes reaction with oxygen to form nitrogen and water. When 7.00 x 1022 molecules of ammonia react with 6.00 x 1022 molecules of oxygen, what mass of nitrogen results (grams)

Answers

Amount of nitrogen produced = 1.624 g

To calculate the moles, we use the equation:    

4NH3(g) + 3 O2 (g) ---> 2 N2 (g) + 6 H2O (g)                           ....(1)

For ammonia:

Putting values in above equation, we get:

Moles of ammonia = 7.00 x 1022 / 6.023 * 10 ^23 = 0.116 mol

Moles of oxygen = 6.00 x 1022 / 6.023 * 10 ^23 = 0.099 mol

For the reaction:

4NH3(g) + 3 O2 (g) ---> 2 N2 (g) + 6 H2O (g)

By Stoichiometry of the reaction,

4 moles of ammonia combine with 3 moles of Oxygen

Thus 0.116 moles of ammonia will combine with= 3/4 * 0.116 = 0.087 of oxygen

Thus ammonia is the limiting reagent as it limits the formation of product.

4 moles of ammonia produces 2 moles of nitrogen

0.132 moles of ammonia will produce=2/4 * 0.116 = 0.058 of nitrogen

Molar mass of nitrogen =  28 g/mol

Amount of nitrogen produced=

No of moles * molar mass = 0.058 * 282 = 1.624 g

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Tin and oxygen can combine to form two compounds of different combining proportions. Resulting formulas of these compounds include
a. Sn2O and SnO2 d. SnO and SnO3
b. SnO and SnO2 e. SnO2 and SnO4
c. SnO4 and SnO
???

Answers

Answer:

B.) SnO and SnO₂

Explanation:

Tin can either exist as Sn²⁺ or Sn⁴⁺ when ionized. Oxygen always exists as O²⁻ when ionized.

When ions combine, sometimes there needs to be different amounts of each ion in order to create an overall charge of 0. In one combination of the ions (Sn²⁺ and O²⁻), there only needs to be one atom of each ion. In another combination (Sn⁴⁺ and O²⁻), you need to have more anions to balance the high positive charge of the cation.

SnO
-----> Sn²⁺ and O²⁻

-----> +2 + (-2) = 0

SnO₂

-----> Sn⁴⁺ and O²⁻

-----> +4 + (-2) + (-2) = 0

Given the balanced equation: 2KClO3 --> 2KCl 3O2 What type of reaction is represented by this equation

Answers

The correct option is (2) decomposition.

In the balanced equation 2KClO3==> 2KCl + 3O2, as there is a reduction of oxygen therefore it is decomposition reaction.

What is decomposition reaction?

A chemical reaction that results in the breakdown of one reactant into two or more reactants is known as a decomposition reaction.

The general equation for decomposition is-

AB -> A + B

Where A & B are now the product molecules and AB is the parent (reactant) molecule.

Some key features of the decomposition reaction are-

A combination reaction is the opposite of the a decomposition reaction. In such reactions, a single product is created form two or even more reactants.Decomposition processes are not always endothermic. Both endothermic and exothermic reactions can take place during decomposition. This one is more typical than the former, though.Extraction of metal from their ores is a significant use of decomposition processes. For instance, by putting calamine through a breakdown reaction, zinc can be extracted. The same process can be used to make sodium form sodium chloride (NaCl).A type of decomposition reaction known to be a double decomposition reaction involves the exchange of positive and negative ions between two constituent reactants to create two new molecules.

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The complete question is-

Given the balanced equation:

2KClO3==> 2KCl + 3O2

Which type of reaction is represented by this equation?

(1) synthesis

(2) decomposition

(3) single replacement

(4) double replacement

chemical engineer has determined by measurements that there are moles of nickel in a sample of nickel tetracarbonyl. How many moles of oxygen are in the sample

Answers

A chemical engineer has determined by measurements that there are 7.0 moles of carbon in a sample of nickel tetracarbonyl. 7 moles of oxygen are in the sample.

What is Stoichiometry ?

Stoichiometry helps us use the balanced chemical equation to measure quantitative relationships and it is to calculate the amounts of products and reactants that are given in a reaction.

What is Balanced Chemical Equation ?

The balanced chemical equation is the equation in which the number of atoms on the reactant side is equal to the number of atoms on the product side in an equation.

According to Stoichiometry

[tex]7\ \text{mol C} \times \frac{1\ \text{mol O}}{1\ \text{mol C}}[/tex]

= 7 mol O

Thus from the above conclusion we can say that A chemical engineer has determined by measurements that there are 7.0 moles of carbon in a sample of nickel tetracarbonyl. 7 moles of oxygen are in the sample.

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Disclaimer: The question was given incomplete on the portal. Here is the complete question.

Question: This is the chemical formula for Nickel Tetracarbonyl (a powerfully poisonous liquid used in Nickel Refining).

Ni(CO)₄

A chemical engineer has determined by measurements that there are 7.0 moles of carbon in a sample of nickel tetracarbonyl. How many moles of oxygen are in the sample ?

________ are weak bonds that are not strong enough to hold atoms together to form molecules but are strong enough to form bonds within and around large molecules.

Answers

Hydrogen bonds are weak bonds that are not strong enough to hold atoms together to form molecules but are strong enough to form bonds within and around large molecules.

The hydrogen bond is weak bond.The hydrogen bond  is electrostatic force of attraction between hydrogen atom and more electronegative atoms or group ( like Florine , oxygen or nitrogen) which is contently bonded.The hydrogen bond is occur in polar , contently bond atoms in different molecules.Example is H-O-H or [tex]NH_{3}[/tex]The positively charged hydrogen side of one water molecule is bond with negatively charged oxygen side of another molecule.

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Receiving an electrical shock when you forget to turn off the power before working on an electrical socket is an example of a negative punishment. please select the best answer from the choices provided t f

Answers

Answer:

TRUE

Explanation

Negative punishment's or  reinforcement .

Negative reinforcement comes as a result of failing to take the necessary precautional measures , whether intentional or unintentional .

Forgetting is a natural circumstance hence if one forgets it means in the first place he has by passed the protocols anyway and he has to take the consequences  .

Sometimes it may be ignorance since it is in common knowledge to turn off  any machine and if possible you should unplug it from the power supply to avoid any shocks which may even be fatal if the source of power does not have mechanisms to control such situations i.e. shocks and power surges .

Psychological when one gets such a punishments he will always remember the ordeal since it inflicted pain on him and he will always take precautional measures before handling an electronic or power sources .

Answer:false

Explanation:

Carbon has six protons; therefore, its mass number is six.
a. true
b. false

Answers

Answer:

B.) False

Explanation:

The mass number is determined by adding the number of protons and neutrons in an element's nucleus. Since carbon has 6 protons and 6 neutrons, the mass number is 12.

The atomic number is determined by the number of protons in an element's nucleus. Since carbon has 6 protons, the atomic number is 6.

5.690x10^3 miles to meters and give sig figs
Please help!

Answers

The equivalent of 5.690 × 10³ miles in metres is 9157167 metres. Details about metres and miles can be found below.

How to convert miles to metres?

Miles and metres are both units for measuring distance between two bodies or locations.

However, they can be converted interchangeably as follows:

1 mile = 1609.34 metres

According to this question, 5.690 × 10³ miles can be converted to metres as follows;

5.690 × 10³ × 1609.34 = 9157167 metres.

Therefore, the equivalent of 5.690 × 10³ miles in metres is 9157167 metres.

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Noble gases have __ values of ionization energy due to their complete outermost shells

Answers

Answer:

high

Explanation:

The energy needed to ionize a neutral atom is known as ionization energy. An atom must have one or more electrons removed from its valence shell in order to get ionized and become a cation. Alternately, you must produce an anion by adding one or more electrons to the valence shell. The energy needed for ionization will be lower the fewer electrons are supplied or withdrawn. As a result, atoms having an incomplete valence shell have a tendency to ionize more quickly and with less energy. However, entire valence shell atoms will require a large amount of ionization energy. As a result, noble gases need significant energy to ionize since they contain a full valence shell, are extremely stable, and do not tend to ionize easily.

Given an end diastolic volume (EDV) of 120 ml / beat and an end systolic volume (ESV) of 50 ml / beat, the stroke volume (SV) would be ________.

Answers

70 ml would be the stroke volume (SV) every beat.

Given,

End Diastolic Volume(EDV) = 120 ml/beat

End Systolic Volume(ESV) = 50 ml/beat

According to the formula

Stroke volume = End Diastolic Volume(EDV) - End Systolic Volume(ESV)

Stoke volume = 120 ml/beat - 50 ml/beat

Stroke volume = 70 ml/beat

The amount of blood in the ventricles just before the heart contracts is known as end-diastolic volume.

End-systolic volume (ESV) is the amount of blood in a ventricle at the point where systole, or contraction, ends and diastole, or filling, begins.

At any time during the cardiac cycle, the ESV has the lowest blood volume in the ventricle.

The amount of blood that is pumped out of the left ventricle of the heart with each systolic cardiac contraction is referred to as the stroke volume.

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Consider the balanced chemical equation when 18.3 g Al is reacted with 113 g I₂ to form AlI₃(g).
What is the mass in grams of the excess Al remaining after the partial reaction of 18.3 g Al with 113 g I₂?
2 Al(s) + 3 I₂(g) → 2 AlI₃(g)

Answers

Answer:

10.3 g Al

Explanation:

To find the excess mass of Al, you need to (1) convert grams I₂ to moles I₂  (via molar mass), then (2) convert moles I₂ to moles AlI₃ (via mole-to-mole ratio from equation coefficients), then (3) convert moles AlI₃ to grams AlI₃ (via molar mass). Now that you have the actual amount of AlI₃ produced, you need to (4) convert grams AlI₃ to moles AlI₃ (via molar mass), then (5) convert moles AlI₃ to moles Al (via mole-to-mole ratio from equation coefficients), and then (6) convert moles Al to grams Al (via molar mass). Now that you know the amount of Al actually needed to produce the product, you need to (7) find the excess mass of Al.

Molar Mass (Al): 26.982 g/mol

Molar Mass (I₂): 2(126.90 g/mol)

Molar Mass (I₂): 253.8 g/mol

Molar Mass (AlI₃): 26.982 g/mol + 3(126.90 g/mol)

Molar Mass (AlI₃): 407.682 g/mol

2 Al(s) + 3 I₂(g) -------> 2 AlI₃(g)

 113 g I₂           1 mole             2 moles AlI₃          407.682 g
-------------  x  ----------------  x  ----------------------  x  -------------------  =  121 g AlI₃
                       253.8 g             3 moles I₂               1 mole

121 g AlI₃           1 mole                2 moles Al           26.982 g
---------------  x  ------------------  x  ---------------------  x  -----------------  =  8.01 g Al
                        407.682 g          2 moles AlI₃           1 mole

Starting Amount - Mass Needed = Excess

18.3 g Al - 8.01 g Al = 10.3 g Al

Assume there is an equal mass of each gas at a given temperature and pressure. Arrange the following gases based on the amount of volume they occupy, from the largest to the smallest volume.

Answers

At a given temperature and pressure, the arrangement of gases based on the amount of volume they occupy, from the largest to the smallest volume is CH[tex]_{4}[/tex] < NH[tex]_{3}[/tex] < Ar < SO₂ < Cl₂ .

According to Avogadro's law, all gases with an identical volume and the same temperature and pressure have an equal number of molecules.

If the temperature and pressure are constant, the volume and amount (in moles) of an ideal gas for a given mass are directly proportional.

The volume of gas ∝ No. of moles of gas

It means that the more the no. of moles of gas, the greater will be the volume of gas.

Now, No. of moles = Given mass/ Molar mass

Given,

There is an equal mass of each gas at a given temperature and pressure.

So,

No. of moles is inversely proportional to the Molar mass of the gas.

Therefore we can conclude that the less the molar mass of gas, the more will be the no. of moles and the higher will be the volume of that gas.

The gas with the least molar mass will occupy the highest volume.

The molar mass of [tex]CH_{4}[/tex] = 16g/mol

The molar mass of [tex]NH_{3}[/tex] = 17g/mol

The molar mass of [tex]Cl_{2}[/tex] = 70g/mol

The molar mass of Ar = 40g/mol

The molar mass of [tex]SO_{2}[/tex] = 64g/mol

Arrangement of gases on basis of molar mass

Cl₂ < SO₂ < Ar < [tex]NH_{3}[/tex] < [tex]CH_{4}[/tex]

So Arrangement on basis of decreasing volume

[tex]CH_{4} < NH_{3} < Ar < SO_{2} < Cl_{2}[/tex]

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By replacing hardware safety features with software controls in the therac-25 machine, aecl was able to?

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Therac-25, AECL was able to reduce costs by replacing hardware safety features with software controls.

the Therac-25 was a laptop-controlled radiation therapy machine produced by Atomic energy state Canada limited in 1982 after the Therac-6 and Therac-20 units. It was involved in at least six accidents between 1985 and 1987, in which patients were given massive overdoses state radiation.

The Therac-25 machine was a state-of-the-art linear accelerator developed by using the company Atomic strength Canada restricted (AECL) and a French company CGR to provide radiation treatment to cancer sufferers. The Therac-25 become the most computerized and complicated radiation therapy device state its time.

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What best defines an extensive property of a substance? (4 points) A property that is observable A property that is measurable A physical property that depends on the sample size A physical property that is not dependent on sample size

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Answer:

A physical property that depends on the sample size 

Explanation:

Control rods in a nuclear reactor...
Select one:
a. remove heat from the reactor core.
b. provide fuel for the reaction.
c. control a chain reaction by absorbing neutrons.
d. prevent the leakage of radiation into the environment.

Answers

Control rods in a nuclear reactor control a chain reaction by absorbing neutrons. Option C

What are control rods?

The control rods are rods that are inserted into the nuclear reactor in order to absorb the neutrons thereby preventing the nuclear reaction from going out of hand.

Hence, control rods in a nuclear reactor control a chain reaction by absorbing neutrons. Option C

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It takes 38. 6 kj of energy to vaporize 1. 00 mol of ethanol (mw: 46. 07 g/mol). What will be δssys for the vaporization of 11. 0 g of ethanol at 78. 4 °c?

Answers

Answer:

9.21 kJ is the enrgy required to vaporize 11.0 grams of ethanol.

Explanation:

Energy of vaporization can be stated as 38.6 kj/mole for ethanol.  ["It takes 38. 6 kj of energy to vaporize 1. 00 mol of ethanol"]

11.0 grams of ethanol is not 1 mole.  Calculate the moles of ethanol by dividing t=it's mass by its molar mass:

(11.0 grams)/(46.07 g/mole) = 0.2388 moles ethanol

(0.2388 moles ethanol)*(38.6 kj/mole) = 9.21 kJ is the enrgy required to vaporize 11.0 grams of ethanol.

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