Can a triangle be formed with sides of 15 8 and 7?

In a direct relationship, Y increases when X increases. On a graph, a direct relationship always has a positive slope. Inverse relationship: An inverse relationship means that the variables change in opposite directions: one increases while the other decreases, and vice versa.

Now, According to the question:

Let's know:

Direct relationship:

A direct relationship means that both variables increase together or both decrease together.

In a direct relationship, Y increases when X increases.

On a graph, a direct relationship always has a positive slope.

Inverse relationship:

An inverse relationship means that the variables change in opposite directions: one increases while the other decreases, and vice versa.

In an inverse relationship, Y decreases when X increases.

On a graph, an inverse relationship always has a negative slope.

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Answer: x = 2+4y (I think, please tell me if I'm wrong)

Step-by-step explanation: Hope this helps

The simplified fraction is -x²(x + y)/y for the given expression.

A fraction is defined as a numerical representation of a part of a whole that represents a rational number.

The fraction is given in the question, as follows;

{(x³ -xy²)/y}/{y/x - 1}

{x(x² -y²)/y}/{(y - x)/x}

{x(x - y)(x + y)/y}/{(y - x)/x}

Reciprocal the terms in the above fraction,

{x(x - y)(x + y)/y} × {x/(y - x)}

{x(x - y)(x + y)/y} × {-x/(x - y)}

Reduce the same term in the expression,

{x(x + y)/y} × {-x}

-x²(x + y)/y

This is the simplified fraction.

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The newspaper staff surveys random students from every grade in the school.

Group sampling

In cluster sampling, a population is divided into clusters, which are smaller groups. They then choose a sample at random from these clusters. Often employed to investigate huge populations, particularly those that are extensively geographically distributed, cluster sampling is a probability sampling technique.

What kind of cluster sampling is that?

Single-stage cluster sampling illustration In order to give education, an NGO wishes to compile a sample of girls from five nearby communities. The NGO selects towns (clusters) at random to create a sample using single-stage sampling and then provides assistance to the girls who are denied schooling in those places.

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Answer:

f^-1(x) = (x+8)/4

Step-by-step explanation:

To find the inverse function,

FIRST, change f(x) to y.

f(x)=4x-8

y = 4x - 8

SECOND, switch the x and the y.

x = 4y - 8

NEXT, solve for y.

x = 4y - 8

add 8 to both sides.

x + 8 = 4y

divide both sides by 4.

(x+8)/4 = y

LAST, rewrite using f^-1(x) in place of y

f^-1(x) = (x+8)/4

If you have better functionality (than me typing on my phone) use a -1 exponent beside the f. Also, put the x+8 on top of the fraction with the 4 on the bottom of the fraction. Then you won't need the parenthesis around the x+8

The distance between the two points (3, 4) and (0, 0) is 25 units.

Regardless of direction, an object's total velocity determines its distance.

Distance is the amount of space an object has traveled, regardless of where it began or concluded.

Knowing how far an object is from us allows us to estimate its actual size.

The following formula is typically used to determine the distance between two points: d=((x2 - x1)2 + (y2 - y1)2)

So, the distance formula is thus:

d=((x2 - x1)2 + (y2 - y1)2)

Points are: (3, 4) and (0, 0)

Now perform the computation shown below by plugging the numbers into the formula above:

d=((x2 - x1)2 + (y2 - y1)2)

d=((0 - 3)2 + (0 - 4)2)

d=((3)2 + (4)2)

d=(9+16)

d=25 units

Therefore, the distance between the two points (3, 4) and (0, 0) is 25 units.

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a. The scale factor is solved to get 3

b. There 9 copies of the of the original shape in the scaled image

c. the top has 2 and a remaining part shaded and labelled O which is joined to the part labelled P at the base to form 3

The middle has 3 while the last has 3 and the part labelled P

3 + 3 + 2 + 1 = 9

Scale factors are used to increase or decrease image. The situation of increment is usually called magnifying.

For the given graph the values with prime is assumed to be the the image while the the values without prime represent the original shape.

Taking a point of reference say CB and C'B'.

CB = 2

C'B' = 6

solving for the factor, assuming the factor is k

2k = 6

k = 6/2 = 3

b. The area of the original shape is solved using the formula for area of trapezoid

= 0.5 (sum of parallel lines) * height

= 0.5 * (2 + 4) * 2

= 6 square units

area of the image

= 0.5 * (6 + 12) * 6

= 54 square units

the number of the original shape in the scaled copy

= area of the image / area of the original shape

= 54 / 6

= 9

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Answer:

Option A: 3x^2 - 4x + 5

Step-by-step explanation:

As you can see in the image, only option A (black dashed) matches the equation (solid red). The others (purple, green, and orange dashed) do not match.

To translate a graph left and right, you need to shift the graph horizontally. To shift the graph left, subtract the desired amount from the x-values and keep the y-values the same. To shift the graph right, add the desired amount to the x-values and keep the y-values the same.

To translate a graph left and right, you need to shift the graph horizontally. This means that the values on the x-axis will be changed while the values on the y-axis will remain the same. To shift the graph left, subtract the desired amount from the x-values and keep the y-values the same. This will move the graph to the left on the x-axis. To shift the graph right, add the desired amount to the x-values and keep the y-values the same. This will move the graph to the right on the x-axis. Both of these processes can be used to shift the graph to the desired position on the x-axis.

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If you want to compare values, use a pie chart — for relative comparison — or bar charts — for precise comparison. If you want to compare volumes, use an area chart or a bubble chart. If you want to show trends and patterns in your data, use a line chart, bar chart, or scatter plot.

Now, According to the question:

How to Choose the Right Data Visualization

Hence, If you want to compare values, use a pie chart — for relative comparison — or bar charts — for precise comparison. If you want to compare volumes, use an area chart or a bubble chart. If you want to show trends and patterns in your data, use a line chart, bar chart, or scatter plot.

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The distance traveled by Juan in miles is 441 miles.

Distance is the total length of a path that an object has taken to get from one place to another. The route from the starting point to the ending point might or might not be straight. Distance is a scalar quantity with only magnitude and no direction.

Total distance travelled by the object. This depends on the entire route taken, not just the beginning and ending locations. The distance travelled is always a positive number. a scalar quantity with distance units.

Distance = speed × time

Given speed = 49 miles per hour

Time = 9 hours

Distance = 49 × 9

= 441 miles

Thus, the distance traveled by Juan in miles is 441 miles.

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The number of seeds that can be sown in a given area depends on the size and spacing of the seeds.

What is the area of the square?

A square is a 2D figure in which all the sides are of equal measure. Since all the sides are equal, the area would be length times width, which is equal to side × side. Hence, the area of a square is a side square.

It is not possible to determine which field will be able to sow more seeds without additional information.

The square field has an area of 100 square meters,

while the rectangular field has an area of 40 square meters, but the perimeter of the rectangular field is not given and it is not possible to calculate it.

Hence, The number of seeds that can be sown in a given area depends on the size and spacing of the seeds, as well as the type of soil and other environmental factors.

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The linear inequality y⩾2x–4 can be expressed in the standard form of an inequality as y-2x⩾–4.

This means that the y-value must be greater than or equal to the result of the calculation 2x–4. To solve this inequality, we can substitute an x-value and calculate the corresponding y-value. For example, if we choose an x-value of 1, then we can calculate the y-value as y = 2x–4 = 2(1)–4 = –2. Therefore, the ordered pair (1,2) is a solution to the linear inequality, as the y-value (2) is greater than or equal to the result of the calculation 2x–4 (–2). The ordered pair (1,1) is not a solution to the linear inequality, as the y-value (1) is less than the result of the calculation 2x–4 (–2). The ordered pair (2,–3) is not a solution to the linear inequality, as the y-value (–3) is less than the result of the calculation 2x–4 (–4). The ordered pair (2,4) is a solution, as the y-value (4) is greater than or equal to the result of the calculation 2x–4 (–4).

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PQRS has four right angles, ABCDE is a pentagon and ABC measure greater than 0 but less than 900.

What is quadrilateral?

Quadrilaterals are typically four-sided closed shapes, and there are numerous varieties of them. Square, rectangle, rhombus, kite, and trapezoid are the most typical shapes. Four closed sides make up a quadrilateral. Quadrilaterals are the following figures: a four-sided figure. The form features a single set of parallel sides and no right angles.

If a figure is a rectangle, then it has four right angles. Figure PQRS is a rectangle.

• Figure PQRS has four right angles.

If a convex polygon is a pentagon, then the sum of the measures of its interior angles is 540°.  

• Figure ABCDE is a pentagon.

If an angle is acute, then its measure is greater than 0 but less than 90. ABC is an acute angle.

• ABC measure greater than 0 but less than 900

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When the values of x and y are replaced into a linear inequality in two variables, such as Ax + By > C, the solution is an ordered pair (x, y) .

In mathematics, an inequality is a connection between two expressions or values that is not equal. As a result, inequality results from imbalance. In mathematics, an inequality establishes a connection between two non-equal numbers. Egality is different from inequality. Use the not equal sign, which is most frequently used, when two values are not equal (). Values of any size can be contrasted using various inequalities. By changing the two sides until only the variables are left, many straightforward inequalities can be resolved. But a lot of factors support inequality: On either side, negative values are split or added. 

given

Rule 1: An inequality sign remains unaltered when the same amount is added to or subtracted from both sides.

Rule 2: The inequality sign remains constant when both sides are multiplied or divided by a positive number.

When the values of x and y are replaced into a linear inequality in two variables, such as Ax + By > C, the solution is an ordered pair (x, y) .

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The domain of the function modeling the distance swam by a swimmer as a function of time would be all positive real numbers greater than or equal to zero, representing the time spent swimming in the race.

This is because the time spent swimming in a race cannot be negative and must be greater than or equal to zero, which represents the start of the race. The domain of a function defines the set of all possible input values (in this case, time) for which the function produces a valid output (distance). In this case, the domain would be all positive real numbers greater than or equal to zero, since these are the only valid input values that can be used to calculate the distance swam by a swimmer during a race.

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Step-by-step explanation:

lets calculate each of the gradients(m & n)

for m; x1 = 6,x2 = 2,y1 = 8,y2 = 1

[tex]gradient = \frac{y2 \\ - y1}{x2 - x1} [/tex]

[tex]m = \frac{1 \\ - 8}{2 - 6} = \frac{ - 7}{ - 4} [/tex]

[tex]m = \frac{7 \\ }{4} [/tex]

now lets calculate the gradient for m

x1=9, x2=2, y1=10, y2=6

[tex]n = \frac{ \\ 6 - 10}{2 - 9} [/tex]

[tex]n = \frac{ - 4 \\ }{ - 7} [/tex]

[tex]n = \frac{4 \\ }{7} [/tex]

for parallelism

m1 = m2

[tex] \frac{4}{7 \\ } = \frac{7}{4} [/tex]

therefore it is not parallel

for perpendicularism

[tex] \frac{ - 1 \\ }{ \frac{4}{7} } = \frac{ - 7}{4} [/tex]

[tex] \frac{ - 1}{ \frac{7}{4} } = - \frac{ 4}{7} [/tex]

therefore it is perpendicular

The mean weight of the team was found to be 222.47 pounds. The standard deviation was 28.32 pounds. 3 standard deviations below the mean were 136.83 pounds. Player A was approximately 0.20 standard deviations above the mean.

(i) Mean:

mean = (sum of all weights) / (number of weights) = (177 + 203 + 211 + 211 + 232 + 205 + 185 + 185 + 178 + 210 + 206 + 212 + 184 + 174 + 185 + 242 + 188 + 212 + 215 + 247 + 241 + 223 + 220 + 260 + 245 + 259 + 278 + 270 + 280 + 295 + 275 + 285 + 290 + 272 + 273 + 280 + 285 + 286 + 200 + 215 + 185 + 230 + 250 + 241 + 190 + 260 + 250 + 302 + 265 + 290 + 276 + 228) / (55) = 222.47

So, the mean weight of the team members of Football Team A was approximately 222.47 pounds.

(ii) Standard deviation:

We need to calculate the deviation from the mean for each weight and then find the square of the deviations. We can then find the sum of the squared deviations, divide by the number of weights minus 1, and then find the square root of the result.

Deviation from the mean:

177 - 222.47 = -45.47,

203 - 222.47 = -19.47,

211 - 222.47 = -11.47, and so on till,

228 - 222.47 = 5.53

Squared deviation:

(-45.47)^2 = 2070.5489,

(-19.47)^2 = 379.3409,

(-11.47)^2 = 131.4409, and so on till,

(5.53)^2 = 30.6409.

Sum of squared deviations:

sum = 2070.5489 + 379.3409 + 131.4409 + ... + 30.6409

sum = 30589.6409

standard deviation = square root of [(sum of squares of deviations from the mean) / (number of observations - 1)]

standard deviation = square root of [(30589.6409) / (55 - 1)]

standard deviation = 28.32

So, the standard deviation of the weights of the team members of Football Team A was approximately 28.32 pounds.

(iii) 3 standard deviations below the mean:

3 standard deviations below the mean = mean - (3 * standard deviation) = 222.47 - (3 * 28.32) = 136.83

So, a weight that is 3 standard deviations below the mean is approximately 136.83 pounds.

(iv) Player A's weight in terms of standard deviations:

Player A's weight = 228 pounds

Player A's deviation from the mean = 228 - 222.47 = 5.53

Player A's weight in terms of standard deviations = 5.53 / 28.32 = 0.20

So, Player A was approximately 0.20 standard deviations above the mean.

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Complete question: Following are the published weights (in pounds) of all of the team members of Football Team A from a previous year. 177; 203; 211; 211; 232; 205; 185; 185; 178; 210; 206; 212; 184; 174; 185; 242; 188; 212; 215; 247; 241; 223; 220; 260; 245; 259; 278; 270; 280; 295; 275; 285; 290; 272; 273; 280; 285; 286; 200; 215; 185; 230; 250; 241; 190; 260; 250; 302; 265; 290; 276; 228; 265 Assume the population was Football Team A. Find the following. (Round your answers to two decimal places.) (i) the population mean (ii) the population standard deviation (iii) the weight that is 3 standard deviations below the mean (iv) When Player A played football, he weighed 228 pounds. How many standard deviations above or below the mean was he?

The total number of tickets is 200 tickets.

A ratio or value that may be stated as a fraction of 100 is called a percentage. And it is represented by the symbol '%'.

Given;

On Monday,

the theater club sells 30 tickets for the school play.

On Tuesday,

they sell 20 tickets.

On those two days,

they sell 30 + 20 tickets and that is 25% of total tickets.

So, total number of tickets,

here, 25%  = 50

So, 25 x 4 = 100% = 50 x 4 = 200 tickets.

Therefore, 200 tickets are the total number of tickets.

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The number of outcomes in n is 2,361,222. The concept used in this problem is known as combinatorics, which is a branch of mathematics that deals with counting and arranging objects.

The problem is asking for the number of ways to choose 5 cards from a deck of 52 cards, such that none of the cards are of the same suit.

To solve the problem, we use the formula for counting the number of ways to choose k items from a set of n items without replacement, which is:

(n choose k) = n! / (k! * (n-k)!)

Where n! represents the factorial of n, which is the product of all positive integers less than or equal to n.

This can be calculated as (52 choose 5) - (13 choose 1 * 39 choose 4) - (13 choose 2 * 26 choose 3) - (13 choose 3 * 13 choose 2) - (13 choose 4 * 13 choose 1) = 2, 598, 960 - 13 * 9, 615 - 78 * 1, 030 - 286 * 78 - 715 * 13 = 2, 598, 960 - 125, 995 - 79, 380 - 22, 068 - 9, 295 = 2, 361, 222

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We can draw the graph a linear equation 3x + 2y = 6 by isolating y then putting the different value of x to find the value of y.

We have to explain, how we graph a linear equation 3x + 2y = 6.

The given linear equation is 3x + 2y = 6.

To graph the linear equation, we have to first isolate the y.

Subtract 3x on both side, we get

2y = 6 - 3x

Divide by 2 on both side, we get

y = [tex]\frac{6 - 3x}{2}[/tex]

Now we finding the value of y in the different value of value of x

x         0         2

y         3         0

Now we draw that points.

The graph of the given linear equation is given below:

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The complete question is:

How do you graph a linear equation 3x + 2y = 6?

The first digit is 3 and the second 4 so the original number is 34

What is an order of an equation?

The highest-order derivative that a differential equation has is used to define the equation's order. The highest-order derivative of a differential equation is defined as its degree, which is expressed as a power.

Here, We

Let the first digit be a

Let the second digit be b

a + b = 7....(1)

The first order value:

a is a counting in tens. So actual value is 10(a)

b is counting in units. So actual value is 1(b)

10a + b...(2)

The second order value:

b is a counting in tens. So the actual value is 10(b)

a is counting in units. So actual value is 1(a)

10b + a....(3)

Now, we subtract equation(3) from (2) and we get

= (10b + a) -(10a + b) = 9

= 9b - 9a = 9

= b - a = 1...(4)

From equation(1)

a = 7 - b

Now, we put the value of a in equation(4) and we get

= b - (7-b) = 1

= b - 7 + b = 1

= 2b = 8

b = 4

Now, substitute the value of b in equation (1) and we get

a = 3

Hence, The first digit is 3 and the second 4 so the original number is 34

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The measure of the central angle sub tended by the arc is 20.62 degree.

Now, According to the question:

The given data is:

A circle has a diameter of 24 centimeters,

and the length of an arc is 36 centimeters.

To find the measure of the central angle sub tended by the arc.

We know that in a circle of radius 'r' unit, if an arc of length 'l' unit

subtends an angle θ radian at the center, then θ= 1/r

Therefore,

Diameter = 24 then, r = Diameter/2

Radius = 12cm. , Length of an arc = 36cm

θ = 36/100 radian = [tex]\frac{180}{\pi }[/tex] × [tex]\frac{36}{100}[/tex] degree = (180 × 36 x 7)/(22 × 100)

= 20.62 degree.

Hence,  the measure of the central angle sub tended by the arc is 20.62 degree.

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Answer:

Answer option 2 is right

Step-by-step explanation:

You're assuming that there were 10 people asked in 8th grade, but the decimal values indicate a percentage of the people asked not the exact value unless an amount is given.

Answer:

Step-by-1step explanation:

The surprising discovery of utilising arithmetic to reduce the risk of divorce is based on the Gottman Group's scale of points, which distinguishes between High Risk and Low Risk of Divorce.

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Answer:

156.8 - 9.92 = 146.88

Step-by-step explanation:

So, The probability that randomly chosen Sample of so residents from each of the two states. The proportion of women in Alaska logger than in Rhodes island is 0.3556.

Given that based on the latest U.S census Count, only 48% of Alaskans are females white 51.7% of Rhode islanders are female.

Let x denote the females in Alaska and y denote the females in Rhode island.

Since, 48% Alaskans ore females.

So, P(x)=0.48

And 51.7 \% of Rhode islanders are females

So, P(y)=0.517.

Now, randomly chosen sample of so residents

from each of the two states.

Now, randomly chosen sample of residents from each of the two states.

So, [tex]x \sim[/tex] {Binomial}(50 , 0.48)

Ana, [tex]y \sim[/tex] Binomial (50, 0.517 )

E(x)=50 *  0.48=24

E(y)=50 * 0.517=25.85

V or (x)=50 * 0.48(1-0.48)=12.48

[tex]Voo_0[/tex](y)=50 * 0.57(1-0.517)=12.4856

Now, we have to find the probability that the proportion of women in Alaska is larger than in Rhode island.

i.e,

[tex]P(x > y) \\= P(x-y > 0)[/tex]

Using normal approximation

[tex]$$=p\left[z > \frac{0-(24-25.85)}{\sqrt{12.48-12.4856}}\right]$$[/tex]

[tex]=P(z > 0.3703) \quad[\text { where } z \sim N(0,1)] \\ =0.3556 \quad \text { (from } z \text { table) }[/tex]

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[tex]x^y^z[/tex]   , [tex]|x|[/tex]  are the output of 1st 2 question and for the second question

the final computation SquareRoot(RaiseToPower(x*y, z)) is doing this:

[tex]\sqrt{(xy)^z}[/tex]

float x , float y , float z

x = Get new line of  input

y = Get new line of  input

z = Get new line of  input

Place RaiseToPower(x, y) in the output.

Place RaiseToPower(x, RaiseToPower(y, z)) to get output

Put abs(x) to output

where abs(x) is absolute value of x

Place SquareRoot(RaiseToPower(x*y, z)) to get disired output

The very first three lines of code simply declare the float type (a number with decimal points) data type of the x, y, and z variables.

After the initial three lines, the user's input is asked in the following three lines.

Coral's Put instruction is used to output an expression for display on the console.

I'm using Coral's built-in RaiseToPower math function to instruct the interpreter to output the value of x raised to the power of y to the console for the initial Put command.

Although the subsequent calculation RaiseToPower(x, RaiseToPower(y, z)) appears to be nested, it actually performs this: [tex]x^y^z[/tex]

The next computation is AbsoluteValue(x) is doing this [tex]|x|[/tex]

And the final computation SquareRoot(RaiseToPower(x*y, z)) is doing this:

[tex]\sqrt{(xy)^z}[/tex]

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