Can someone help me with this page I don’t know how to do this type of math

Can Someone Help Me With This Page I Dont Know How To Do This Type Of Math

Answers

Answer 1
2a+4=10
subtract 4 from 10 and you get 6, then you divide by 2 and a=3

4b-3=17 same here
you do the opposite sign so you add 3 to 17 and you get 20 then you divide by 4 and b=5

3c+5=11
subtract 5 from 11 you get 6 then you divide by 3 and c=2

Related Questions

If cot^(4)x − cot^(2)x = 1, then the value of cos^(4)x + cos^(2)x is

Answers

Answer:

1

Step-by-step explanation:

[tex]cot^4x-cot^2x=1\\cot^4x=1+cot^2x\\cot^4x=cosec^2x\\ cos^4xsin^2x=sin^4x\\cos^4x=\frac{sin^4x}{sin^2x}\\cos^4x=sin^2x[/tex]------- (1)

Putting the value of [tex]cos^4x[/tex] in the equation:

[tex]cos^4x+cos^2x\\sin ^2x +cos^2x\\1[/tex]            (Using the identity [tex]cos^2x +sin^2x=1)[/tex]

I need help ASAP!! Finding the angle Please help me

Answers

Answer:

Does the answer help you?

[tex]\\ \sf\longmapsto Sin\Theta=\dfrac{P}{H}[/tex]

[tex]\\ \sf\longmapsto sin\Theta=\dfrac{49}{52}[/tex]

2decimal places:-

[tex]\\ \sf\longmapsto sin\Theta=0.94[/tex]

[tex]\\ \sf\longmapsto sin\Theta=sin71°[/tex]

[tex]\\ \sf\longmapsto \Theta=71°[/tex]

Or

[tex]\\ \sf\longmapsto cos19°[/tex]

1decimal place:-

[tex]\\ \sf\longmapsto sin\Theta=0.9[/tex]

[tex]\\ \sf\longmapsto sin\Theta=sin70[/tex]

[tex]\\ \sf\longmapsto \Theta=70°[/tex]

Or

[tex]\\ \sf\longmapsto cos20°[/tex]

550
Х
X =
degrees
Jejdjsjsjs

Answers

Answer:

35⁰

Step-by-step explanation:

180-90-55=35⁰

there is a right angle

The angle sum property of a triangle:

The total measure of the three angles of a triangle is 180°

[tex]\rm\large\rightarrow \: \: x \: + \: 55 \degree \: + \: 90 \degree \: = \: 180 \degree[/tex]

[tex]\rm\large\rightarrow \: \: x \: + \: 145 \degree \: = \: 180 \degree[/tex]

[tex]\rm\large\rightarrow \: \: x \: = \: 180 \degree \: - \: \: 145 \degree [/tex]

[tex]\rm\large\rightarrow \: \: x \: = \: 35 \degree[/tex]

What are three collinear points on line l?

points A, B, and F
points A, F, and G
points B, C, and D
points B, F, and G

Answers

Answer:

Points A, F, and G are three collinear points on line l.

Step-by-step explanation:

Answer:

Points A, F and G

Step-by-step explanation:

Which is most applicable when continuous inspection is used? I-chart, P-chart, c-chart C-bar chart

Answers

There are various charts which represents mathematical and statistical data with graphical representation.

The correct answer for the given question is ,

I - Chart

Since this chart is used to present data for continuous inspection.

The charts are used for representation of inspected data in to structure way which helps understand the changes easily.

I chart is usually used when there is continuous inspection for the data. This type of chart used to monitor the process when measuring data at regular intervals.

Learn more at https://brainly.com/question/24366019

Multiply. Write your answer in scientific notation

Answers

Answer:

3×3×10^5×10^2

9×10^5-2

9×10³

What is the volume of the following rectangular prism?

Answers

Answer:

1/10 units ^3

Step-by-step explanation:

The formula for the volume is given by

V = Bh where B is the area of the base and h is the height

V = 3/20 units ^2 * 2/3 units

   = 3/20 * 2/3

  = 1/10 units ^3

Due to employee safety negligence at a nuclear waste facility, 2000 tons of a radioactive element is spilled into the nearby pond. The half-life of the radioactive element is 36 days. In order to be declared safe for swimming, based on its size and the amount of water, there must be less than 100 tons of the material found in the pond. How long, to the nearest day, until it is safe to swim again?

Answers

How long, to the nearest day, until it is safe to swim again will be 156 days

Let x represent number of day until it is safe to swim again

First step

=2000 *1/2^x

100=2000 *0.5^x

0.05=0.5^x

Second step

Log 0.05=xLog 0.5

Log 0.05/L0g 0.5=x

x=36 days* Log 0.05/L0g 0.5

x=36 days*43.22

x=156 days

Inconclusion How long, to the nearest day, until it is safe to swim again will be 156 days

Learn more about  radioactive element here:

https://brainly.com/question/13812761

She walks to her school at a distance of 800m from her house in 55 seconds. On reaching, she finds that the school is closed and comes back by car with her friend and reaches home in 25 seconds. Find her average speed in m/s

Answers

Answer:

per second she was walking 14.54m roughly and driving is 32m per second therefore the average is 23.27m/s

Step-by-step explanation:

divide both sides by 55 to get one.

divide both sides by 25 to get one

THEN

to find the average you simply add them and divide by two which is 46.54 which divided by two is roughly 23.27.

Parabolic microphones are used for field audio during sports events. The microphones are manufactured such that the equation of their cross section is x=1/34y^2, in inches. The feedhorn part of the microphone is located at the focus

a. How far is the feedhorn from the edge of the parabolic surface of the microphone?

b. What is the diameter of the microphone? Explain your reasoning

c. If the diameter is increased by 5 inches, what is the new equation of the cross section of the microphone?​

Answers

Answer:

a. 8.5 in.

b. 34 in

c. x = 1/39 x^2.

Step-by-step explanation:

Part a.

x = 1/34 y^2

y^2 = 34x

Comparing with y^2 = 4px where p is the focus:

4p = 34

p = 8.5 in.

Part b.

The diameter = 4p = 34 in.

Part c.

Diameter = 4p = 34 + 5 = 39 in

The new equation is x = 1/39 x^2.

Suppose you roll a fair six-sided die 25 times. What is the probability that you roll 5 or more 6’s on that die?

A. 0.3883

B. 0.5937

C. 0.5

D. 0.4063

Answers

Answer:

D. P(5+ 6's) = 0.4063

Step-by-step explanation:

Binomial distribution.

For the distribution to be applicable, the experiment must

1. Have a know and constant number of trials

2. Probability of success of each trial remains constant (and known if available)

3. Each trial is a Bernoulli trial, i.e. with only two outcomes, success or failure.

4. Independence between trials.

Let  

n = number of trials  = 25

p = probability of success of each trial  = 1 / 6

x = number of successes  (0 ≤ x ≤ n)  = 5

C(n,x) = number of combinations of picking x identical objects out of n

Applying binomial distribution

P(x,n) = probability of x successes in an experiment of n trials.

= C(n,x) * p^x * (1-p)^(n-x)

For n = 25 trials with probability of success (roll a 6) = 1/6

and x = 5,6,7,8,...25

It is easier to calculate the complement by

P(5+ 6's) = 1 - P(<5 6's)

= 1 - ( P(0,25) + P(1,25) + P(2,25) + P(3,25) + P(4,25) )

1- (

    P(0,25) = C(25,0) * (1/6)^0 * (5/6)^25 = 0.0104825960103961

    P(1,25) = C(25,1) * (1/6)^1 * (5/6)^24 = 0.05241298005198051

     P(2,25) = C(25,2) * (1/6)^2 * (5/6)^23 = 0.1257911521247532

    P(3,25) = C(25,3) * (1/6)^3 * (5/6)^22 = 0.1928797665912883

    P(4,25) = C(25,4) * (1/6)^4 * (5/6)^21 = 0.2121677432504171

)

= 1 - 0.59373

= 0.40626

= 0.4063 (to 4th decimal place)

4 Points
is
For the function y = 3x + 5
what is the output of the
function if the input is 10?

Answers

Answer:

[tex]35[/tex]

Step-by-step explanation:

One is given the following function ([tex]y=3x+5[/tex]). The given problem asks one to find the output of the function when the input is (10). Keep in mind, a general rule for dealing with functions is that, when present, the variable (x) represents the input. Whereas the variable (y) represents the output. Thus, if one were to substitute (10) in place of (x), and simplify: the result one would get is the output. Apply this idea to the given scenario:

[tex]y=3x+5[/tex]

[tex]y=3(10)+5[/tex]

[tex]y=30+5[/tex]

[tex]y=35[/tex]

The difference of two trinomials is x2 − 10x + 2. If one of the trinomials is 3x2 − 11x − 4, then which expression could be the other trinomial? 2x2 − x − 2 2x2 + x + 6 4x2 + 21x + 6 4x2 − 21x – 2

Answers

Answer:

[tex]4x^2-21x-2[/tex]

Step-by-step explanation:

Given that:

Difference of two trinomials is [tex]x^2 - 10x + 2[/tex]

One of the two trinomials is  [tex]3x^2 - 11x - 4[/tex]

To find:

The other trinomial = ?

Four options are:

[tex]2x2 - x - 2 \\2x2 + x + 6 \\4x2 + 21x + 6\\ 4x2 - 21x - 2[/tex]

Solution:

Let the two trinomials be A and B.

Given A - B = [tex]x^2 - 10x + 2[/tex]

B = [tex]3x^2 - 11x - 4[/tex]

We have to find the other trinomial A.

A - B = [tex]x^2 - 10x + 2[/tex]

A - ([tex]3x^2 - 11x - 4[/tex]) = [tex]x^2 - 10x + 2[/tex]

[tex]\Rightarrow[/tex] A = [tex]x^2 - 10x + 2[/tex] + ([tex]3x^2 - 11x - 4[/tex])

[tex]\Rightarrow[/tex] A = [tex]4x^2-21x-2[/tex]

So, the correct answer is [tex]4x^2-21x-2[/tex].

Which Property of real numbers does this equation show? 4 x 1 = 4

Answers

Answer:

This is multiplicative identity in which 4✖️1=4

Step-by-step explanation:

Hope it will help you:)

How to do this question plz answer me step by step plzz plz ​

Answers

Answer:

194.25meters

Step-by-step explanation:

The distance around the running track is calculated as:

Perimeter of the first semi circle + Perimeter of the second circle +50m + 50m

Semi circle has a length or diameter of = 30m

r = 30/2 = 15m

Perimeter of a circle = 2πr

Hence for a semi circle = 2πr/2 = πr

Perimeter of the first semi circle = π × 15

= 47.123889804m

Perimeter of the second semi circle is the same hence,

π × 15 = 47.123889804m

The distance around the running track

= 47.123889804m + 47.123889804m + 50m + 50m

= 194.24777961m

Approximately= 194.25meters.

Show that the equations x^2-7x+6=0 and y^2-14y+40=0 form a rectangle.Also find the joint equations of diagonals.

Answers

Answer:

1) The region between the four lines x = 6, x = 1, y = 4 and y = 10 describing both equations is a rectangle

2) The joint equations of diagonals are;

5·y = 56 - 6·x and 5·y = 6·x + 14.

Step-by-step explanation:

The equations are;

x² - 7·x + 6 = 0......................(1)

y² - 14·y + 40 = 0.................(2)

Factorizing equation (1) and equation (2) , we get

x² - 7·x + 6 = (x - 6)·(x - 1) = 0

Which are vertical lines at points x = 6 and x = 1

For equation (2) , we get

y² - 14·y + 40 = (y - 10)·(y - 4) = 0

Which are horizontal lines at point y = 4 and y = 10

The region between the four lines x = 6, x = 1, y = 4 and y = 10 describing both equations is a rectangle

2) The points of intersection of the equations are;

(1, 4), (1, 10), (6, 4), and (6, 10)

The end point of the diagonals are;

(1, 10), (6, 4) and  (1, 4), (6, 10)

The slope of the diagonals are;

(10 - 4)/(1 - 6) = -6/5 and (4 - 10)/(1 - 6) = 6/5

The equation of one of the diagonals are then, y - 10 = -6/5×(x - 1)

y = -6/5·x + 6/5 + 10 = -6/5·x + 56/5

5·y = 56 - 6·x

The other diagonal is therefore;

y - 4 = 6/5×(x - 1)

y = 6/5·x - 6/5 + 4 = 6/5·x + 14/5

5·y = 6·x + 14.

The joint equations of diagonals are therefore;

5·y = 56 - 6·x and 5·y = 6·x + 14.

Graph the relation shown in the table. Is the relation a function? Why or why not?

Answers

Answer:

Not a function fails the vertical line test

Step-by-step explanation:

This is not a function.  The value of x = -1  goes to two different values of y

This would fail the vertical line test

Answer:

the first one

Step-by-step explanation:

use the vertical line test. the horizontal line would intersect at two points.

Graph y=2x+4………………………………

Answers

Answer:

Step-by-step explanation:

The time required to drive a fixed distance varies inversely as the speed. It takes 2 hr at a speed of 200 km/h to drive a fixed distance. How long will it take to drive the same distance at a speed of 80 km/h?

Answers

Answer:

5 hours

Step-by-step explanation:

From the question, we are told that:

Time required to drive a fixed distance varies inversely as the Speed

T ∝ 1/S

k = proportionality constant hence,

T =k × 1/S

T = k/S

Step 1

Find k

It takes 2 hr at a speed of 200 km/h to drive a fixed distance

T = 2 hours, S = 200km/h

T = k/S

2 = k / 200

k = 2 × 200

k = 400

Step 2

How long will it take to drive the same distance at a speed of 80 km/h?

S = 80km/h

T = k/S

k = 400

T = 400/80

T = 5

Therefore, it takes 5 hours to drive the same distance at a speed of 80km/hr

HAI HELP ME ASAP PLEASE

Answers

Answer:

Y/X = 2/3 x^2 + 16/3

Y= 2/3 x^3 + 16/3 x

Just replace y with y/X and X with x^2

) What should be subtracted from -5/3 to get 5/6?

Answers

Answer:

[tex]-\frac{5}{2}[/tex]

Step-by-step explanation:

Step 1: Put this into an equation

[tex]-\frac{5}{3} - x = \frac{5}{6}[/tex]

Step 2: Solve for x

[tex]-x = \frac{5}{6} + \frac{5}{3}[/tex]

[tex]-x = \frac{5}{2}[/tex]

[tex]x =- \frac{5}{2}[/tex]

Therefore you need to subtract [tex]-\frac{5}{2}[/tex] from [tex]-\frac{5}{3}[/tex] to get [tex]\frac{5}{6}[/tex]

Answer:i don’t know

Step-by-step explanation:I’m sorry dude I have no idea I tried doing it in the browser and I could not find an answer sorry

If the ratio of two supplementary angles is 10 to 47, calculate the measure of the larger of the two angles.

Answers

Answer:

a) 148.52

Step-by-step explanation:

If sum of two angles is 180, then they are supplementary

Ratio = 10 : 47

Smaller angle = 10x

Larger angle = 47x

10x + 47x = 180

57x = 180

Divide  both sides by 57

x = 180/57

x = 3.16

Larger angle = 47x = 47 * 3.16 = 148.52

Find the exact value of cos A in simplest radical form.

Answers

Answer:

[tex] \cos(A) = \frac{2 \sqrt{6} }{7} [/tex]

Step-by-step explanation:

Since we are finding cos A we have

[tex] \cos(A) = \frac{AC}{AB} [/tex]

From the question

AC = √96

AB = 14

Substitute the values into the above formula

That's

[tex] \cos(A) = \frac{ \sqrt{96} }{14} [/tex]

We have the final answer as

[tex] \cos(A) = \frac{2 \sqrt{6} }{7} [/tex]

Hope this helps you

Each student of a class contributed as many 5 rupees as the numbers of the students in the class.Find the number of the students in the class if the total collection was RS 10125.

Answers

And=2025 students gave 10125 rs

just divide it by 5hope it helps...pls mark me brainliest

Answer ASAP, will give brainliest

Answers

Answer:

Step-by-step explanation:

1) Diagonal bisect the angles of Rhombus

∠CAB = ∠CAD

CAB = 71

2) ∠DAB = ∠CAB + ∠CAD

 ∠DAB = 71 + 71 = 142

In Rhombus, adjacent angles are supplementary

∠DAB + ∠ABC = 180

142 + ∠ABC = 180

           ∠ABC = 180 - 142

         ∠ABC = 38

3)  In rhombus, opposite angles are congruent

∠ADC = ∠ABC

∠ABC = 38

In rhombus, diagonal bisect angles

∠BDC = (1/2)*∠ADC

∠BDC= 38/2

BDC = 19

4) Diagonals bisect each other at 90

∠DEC = 90

5) Diagonals bisect each other

BE = DE

BE + DE = DB

7x -2 +7x -2 =24   {add like terms}

        14x - 4 =24

              14x = 24+4

              14x = 28

                 x = 28/14

                 x = 2 m

6) AB = 13m

BE = 7x - 2 = 7*2 -2 = 14 -2 = 12 m

In right angle ΔAEB,  {use Pythagorean theorem}

AE² + BE² = AB²

AE² + 12² = 13²

AE² + 144 = 169

         AE² = 169 - 144

         AE² = 25

         AE = √25

        AE = 5 m

Diagonals bisect each other

AE = EC

AC = 2*5

AC = 10 m

7)Side = 13 m

Perimeter = 4*side

                  = 4*13

 Perimeter = 52 m

8) d1 = AC = 10 m

   d2 = DB = 24 m

Area = [tex]\frac{d_{1}*d_{2}}{2}[/tex]

         [tex]=\frac{10*24}{2}\\[/tex]

          = 10 *12

          = 120 m²

36. Given that y varies directly with x,
what is the equation of direct variation
if y is 3 when x is 7?

Answers

Answer:

A. y = 3/7x

Step-by-step explanation:

Direct variation: y = kx

3 = 7k

k = 3/7

y = 3/7x

(04.01 LC) The science club surveyed 50 students about the number of science courses in which they were enrolled and the time it took them to complete their homework. Classify the random variables from the survey. (2 points) Select one: a. Number of science courses, continuous; time to complete homework, continuous b. Number of science courses, continuous; time to complete homework, discrete c. Number of science courses, discrete; time to complete homework, continuous d. Number of science courses, discrete; time to complete homework, discrete e. Unable to determine from information given

Answers

Answer:

The correct option is;

c. Number of science courses, discrete; time to complete homework, continuous

Step-by-step explanation:

There are two types of random variables, discrete random variables and continuous  random variables

Discrete random variables are variables that are always re-presentable by a finite countable number, such that discrete random variables can be taken as a count of items count

Therefore, as the number of science courses are fixed and such that a specific number can be ascribed to the courses at any time (except there are changes), is a discrete random variable

A continuous random variable is one whose possible values are infinite and are generally measurements of values of such as weight, height, time, and amount

Therefore, the time to complete the homework is a continuous random variable.

Complete the statement with always, sometimes, or never. Explain your reasoning.

An altitude is _____ the same line segment as an angle bisector.

Answers

Step-by-step explanation:

it's ur answers I hope it's helpful

How is the product of a complex number and a real number represented on the coordinate plane?

Answers

Answer:

A complex number bein scaled by a real number would NOT produce any "rotation" ... "C" should be the answer.

Step-by-step explanation:

(2 + i)(3 - i)(1 + 2i)(1 - i)(3 + i)

Answers

Answer:

50+50i

Step-by-step explanation:

Given the expression (2 + i)(3 - i)(1 + 2i)(1 - i)(3 + i), we are to take the product of all the complex values. We must note that i² = -1.

Rearranging the expression [(3 - i)(3 + i)] [(2 + i)(1 - i)](1 + 2i)

On expansion

(3 - i)(3 + i)

=  9+3i-3i-i²

= 9-(-1)

= 9+1

(3 - i)(3 + i) = 10

For the expression (2 + i)(1 - i), we have;

(2 + i)(1 - i)

= 2-2i+i-i²

= 2-i+1

= 3-i

Multiplying 3-i with the last expression (1 + 2i)

(2 + i)(1 - i)(1 + 2i)

= (3-i)(1+2i)

= 3+6i-i-2i²

= 3+5i-2(-1)

= 3+5i+2

= 5+5i

Finally,  [(3 - i)(3 + i)] [(2 + i)(1 - i)(1 + 2i)]

= 10(5+5i)

= 50+50i

Hence,  (3 - i)(3 + i)(2 + i)(1 - i)(1 + 2i) is equivalent to 50+50i

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