Can someone help me with this problem pleaseee having a lot of trouble doing this!!!

Answer:

x ≤ 135/2

Step-by-step explanation:

x is the cost per night. You have to pay for 2 nights, and you do not want to spend more than $135 total. Another way to say that, is you want to spend less than or equal to $135.

x = cost per night

2 = number of nights

2x = total cost

Total cost must be less than or equal to $135.

2x ≤ 135

Divide each side by 2.

x ≤ 135/2

Considering the area of the rectangle, we have that the length is of 8 units and the width is of 10 units.

The area of a rectangle of length l and width w is given as follows:

A = lw.

In this problem, the area is of 80 square units, while the length and the width are consecutive even integers, hence:

Then:

l(l + 2) = 80

l² + 2l - 80 = 0

(l + 10)(l - 8) = 0.

We need the positive measure, hence:

l -  8= 0 -> l = 8 units.

w = l + 2 = 10 units.

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Using it's concepts, the domain and the range of the graph are given as follows:

In this graph, have that the function is defined for all values of x except x = -1, and assumes all real values, hence the domain and the range of the graph are given as follows:

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Answer:

Step-by-step explanation:

Substitution is a method that rewrites one of the equations in terms of one variable, and substitutes that in the other equations.

We can easily rewrite x + y = 6 by subtracting y from both sides, giving us

[tex]x = -y+6[/tex]

By putting this equation in place of x in the first equation, we can solve for y:

[tex]4(-y+6)-2y=6[/tex]

[tex]-4y+24-2y=6[/tex] [Distributing 4 into the parentheses]

[tex]-6y+24=6[/tex] [Combining like terms]

[tex]-6y = -18[/tex] [Subtracting 24 from both sides]

[tex]y=3[/tex] [Dividing both sides by -6]

Since we solved for y, we can again substitute by putting it into the second equation.

[tex]x+3=6[/tex]

[tex]x=3[/tex] [Subtracting 3 from both sides]

The solution for this system of equations is (3,3).

Elimination is another method of solving systems of equations. In this method, we multiply one equation such that when both equations are combined, only one variable is left.

We can first multiply both sides of the second equation by 2.

[tex]2x+2y=12[/tex]

Now, let's add both equations to cancel out y.

[tex]4x-2y=6[/tex]

[tex]2x+2y=12[/tex]

[tex]6x=18[/tex]

Now, we can divide 6 from both sides to get the value of x.

[tex]\frac{6x}{6} = \frac{18}{6}[/tex]

[tex]x=3[/tex]

We can now substitute this value into one of the equations to get the value of y. Here, I used the second equation.

[tex]3+y=6[/tex]

[tex]y=3[/tex]

The solution to our system of equations is (3,3).

The force is 1.6N and the distance between them is 1.3 meters

An inverse variation from force to the square of distance is represented s:

k = Fd^2

Where k represents the variation constant

When F = 10, d = 2.

So, we have:

k = 10 * 2^2

k = 40

Substitute k = 40 in k = Fd^2

Fd^2 = 40

When d = 5, we have:

F * 5^2 = 40

This gives

25F = 40

Divide by 25

F = 1.6

Hence, the force is 1.6N

In (a), we have:

Fd^2 = 40

When F = 25, we have:

25 * d^2 = 40

This gives

25d^2 = 40

Divide by 25

d^2 = 1.6

Take the square root of both sides

d = 1.3

Hence, the distance between them is 1.3 meters

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The solution to the homogenous differential equation, (11y² - xy)dx + x²dy = 0, is [tex]y = \frac{x}{11 ln (x) + C}[/tex].

A homogeneous differential equation has a homogeneous function as one of its components, if f(λx, λy) = λⁿf(x, y), for any non-zero constant λ, the function is said to be homogenous. The homogeneous differential equation's generic form is of the type f(x, y).dy + g(x, y).dx = 0. The degree of the homogeneous differential equation is the same for the equation's variables x and y.

In the question, we are asked to solve the homogeneous differential equation, (11y² - xy)dx + x²dy = 0.

The given equation can be solved as follows:

Thus, the solution to the homogenous differential equation, (11y² - xy)dx + x²dy = 0, is [tex]y = \frac{x}{11 ln (x) + C}[/tex].

The provided question is incomplete. The complete question is:

"Use the method for solving homogenous equations to solve the following differential equation.

(11y² - xy)dx + x²dy = 0".

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The vertices of abc given the transition rule (x,y)-->(x,y-3) are (-6, -10), (-3, -13) and (-5, -1)

The vertices are given as:

a (-6,-7)

b(-3,-10)

c(-5,2)

The transition rule is given as

(x,y)-->(x,y-3)

So, we have

a' = (-6, -7 - 3)

a' = (-6, -10)

b' = (-3, -10 - 3)

b' = (-3, -13)

c' = (-5, 2 - 3)

c' = (-5, -1)

Hence, the vertices of abc given the transition rule (x,y)-->(x,y-3) are (-6, -10), (-3, -13) and (-5, -1)

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The distance between points (- 3, 0, -7) and (- 8, - 9, - 11) is approximately 11.1 units and the midpoint is (x, y, z) = (- 5.5, - 4.5, - 9).

First, we find the vector between the two points by vector sum:

[tex]\vec r = (-8, -9, - 11) - (- 3, 0, -7)[/tex]

[tex]\vec r = (- 5, - 9, - 4)[/tex]

The distance between the two points is found by the following Pythagorean expression:

[tex]d = \sqrt{(-5)^{2}+(-9)^{2}+(-4)^{2}}[/tex]

d ≈ 11.1

And the midpoint is found by linear algebra:

[tex]\vec m = 0.5\cdot (-3, 0, -7) + 0.5 \cdot (-8, -9, - 11)[/tex]

[tex]\vec m = (- 1.5, 0, - 3.5) + (- 4, - 4.5, -5.5)[/tex]

[tex]\vec m = (- 5.5, - 4.5, - 9)[/tex]

The distance between points (- 3, 0, -7) and (- 8, - 9, - 11) is approximately 11.1 units and the midpoint is (x, y, z) = (- 5.5, - 4.5, - 9).

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The proportion cranberry juice should be mixed with 84 ounces of apple juice 1:5 that is 1 parts of cranberry juice and 5 parts of lemon juice.

According to the question,

A punch recipe calls for mixing 2 parts of cranberry juice with 5 parts of apple juice.

84/2 = 42

5*42=210

Hence, the proportion cranberry juice should be mixed with 84 ounces of apple juice 1:5 that is 1 part of cranberry juice and 5 parts of lemon juice.

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Consider the lengths of consecutive 1-2 blocks.

block 1 - 1, 2 - length 2

block 2 - 1, 2, 2 - length 3

block 3 - 1, 2, 2, 2 - length 4

block 4 - 1, 2, 2, 2, 2 - length 5

and so on.

Recall the formula for the sum of consecutive positive integers,

[tex]\displaystyle \sum_{i=1}^j i = 1 + 2 + 3 + \cdots + j = \frac{j(j+1)}2 \implies \sum_{i=2}^j = \frac{j(j+1) - 2}2[/tex]

Now,

[tex]1234 = \dfrac{j(j+1)-2}2 \implies 2470 = j(j+1) \implies j\approx49.2016[/tex]

which means that the 1234th term in the sequence occurs somewhere about 1/5 of the way through the 49th 1-2 block.

In the first 48 blocks, the sequence contains 48 copies of 1 and 1 + 2 + 3 + ... + 47 copies of 2, hence they make up a total of

[tex]\displaystyle \sum_{i=1}^48 1 + \sum_{i=1}^{48} i = 48+\frac{48(48+1)}2 = 1224[/tex]

numbers, and their sum is

[tex]\displaystyle \sum_{i=1}^{48} 1 + \sum_{i=1}^{48} 2i = 48 + 48(48+1) = 48\times50 = 2400[/tex]

This leaves us with the contribution of the first 10 terms in the 49th block, which consist of one 1 and nine 2s with a sum of [tex]1+9\times2=19[/tex].

So, the sum of the first 1234 terms in the sequence is 2419.

The domain of the exponential function given is the set of all real numbers while the range of the exponential function is the set of all real numbers greater than zero.

As with other exponential functions, it follows that the domain of the exponential function given is the set of all real numbers while the range of the exponential function is the set of all real numbers greater than zero.

Additionally, by observation, the function has a positive variable correlation, hence;

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Answer:A or C

Step-by-step explanation: i guessed plus 19 hours ago

The general form of the equation for the given circle centered at O(0, 0) is x^2 + y^2 = 41

The given parameters are

Center = (0, 0)

Point = (4, 5)

Rewrite the given parameters are

(a, b)= (0, 0)

(x, y) = (4, 5)

The general form of the equation for the given circle is represented as:

(x - a)^2 + (y - b)^2 = r^2

Substitute the known values in the above equation to calculate the radius r

(4 - 0)^2 + (5 - 0)^2 = r^2

Evaluate the difference

4^2 + 5^2 = r^2

Evaluate the exponent

16 + 25 = r^2

Evaluate the sum

41= r^2

Rewrite as

r^2 = 41

Substitute r^2 = 41 in (x - a)^2 + (y - b)^2 = r^2

(x - a)^2 + (y - b)^2 = 41

Substitute (a, b)= (0, 0) in (x - a)^2 + (y - b)^2 = 41

(x - 0)^2 + (y - 0)^2 = 41

Evaluate the difference

x^2 + y^2 = 41

Hence, the general form of the equation for the given circle centered at O(0, 0) is x^2 + y^2 = 41

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Answer:

[tex]T_{2} = \frac{P_{2} V_{2} T_{1}} {P_{1} V_{1}}[/tex]

Step-by-step explanation:

The Combined Gas Law expression is:

P₁V₁ / T₁ = P₂V₂ / T₂

To solve for T₂, you need to.....

[tex]\frac{P_{1} V_{1} }{T_{1} } = \frac{P_{2} V_{2} }{T_{2} }[/tex]                                  <------ Original expression

[tex]\frac{T_{2} P_{1} V_{1} }{T_{1} } = {P_{2} V_{2} }[/tex]                               <----- Multiply both sides by T₂

[tex]{T_{2} P_{1} V_{1} } = {P_{2} V_{2} T_{1}}[/tex]                          <----- Multiply both sides by T₁

[tex]T_{2} = \frac{P_{2} V_{2} T_{1}} {P_{1} V_{1}}[/tex]                                  <----- Divide both sides by P₁V₁

SOLUTION :

c² = 5² + 5²

c² = 25 + 25

c² = 50

c = √50 ft

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Answer:

[tex]\huge\boxed{\sf \{(-2,1)\}}[/tex]

Step-by-step explanation:

Given equations:

y = x + 3

y = -x - 1

By comparing the above equations, we get:

x + 3 = -x - 1

Add x to both sides

Subtract 3 to both sides

2x = -1 - 3

2x = -4

Divide 2 to both sides

x = -4/2

Substitute x = -2 in first equation.

y = x + 3

y = -2 + 3

So,

[tex]\rule[225]{225}{2}[/tex]

Answer:

[tex]x = - 2 \\ y = 1[/tex]

Step-by-step explanation:

The above are Simultaneous equations.

Simultaneous equations are two or more algebraic equations which share same variables like X,Y or X,Y and Z.

They are called simultaneous equations because they can be solved the same time.

From the question,

[tex]y = x + 3 - - - - - - (1) \\ y = - x - 1 - - - - - - (2) \\ Substitute \: equation \: (2)into \: (1) \\ - x - 1 = x + 3 \\ Collect \: liketerms \\ - x - x = 3 + 1 \\ - 2x = 4 \\ Divide \: bothsides \: by \: - 2 \\ \frac{ - 2x}{ - 2} = \frac{4}{ - 2} \\ x = - 2 \\ Substitute \: the \: value \: of \: x \: into \: equation \: (1) \\ y = x + 3 \\ y = - 2 + 3 \\ y = 1 \\ Therefore \: x = - 2 \: \: and \: y = 1[/tex]

Based on the length and width of the rectangular lawn, and the percentage the man has mowed, the strip width would be 40.5 m.

first, find the area of the lawn:

= 100 x 200

= 20,000 ft²

the area mowed is:

= 40.5% x 20,000

= 8,100 ft²

the width is therefore:

= 8,100 / 200

= 40.5 m

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Answer:

If you divide it out and it comes out a whole number unless the original set of numbers is a fraction

The coordinates of the vertex that A maps to after Daniel's reflections are (3, 4) and the coordinates of the vertex that A maps to after Zachary's reflections are (3, 2)

From the given figure, the coordinate of the vertex A is represented as:

A = (-5, 2)

The coordinates of the vertex that A maps to after Daniel's reflections

The rule of reflection across the line x = -1 is

(x, y) ⇒ (-x - 2, y)

So, we have:

A' = (5 - 2, 2)

Evaluate the difference

A' = (3, 2)

The rule of reflection across the line y = 2 is

(x, y) ⇒ (x, -y + 4)

So, we have:

A'' = (3, -2 + 4)

Evaluate the difference

A'' = (3, 4)

Hence, the coordinates of the vertex that A maps to after Daniel's reflections are (3, 4)

The coordinates of the vertex that A maps to after Zachary's reflections

The rule of reflection across the line y = 2 is

(x, y) ⇒ (x, -y + 4)

So, we have:

A' = (-5, -2 + 4)

Evaluate the difference

A' = (-5, 2)

The rule of reflection across the line x = -1 is

(x, y) ⇒ (-x - 2, y)

So, we have:

A'' = (5 - 2, 2)

Evaluate the difference

A'' = (3, 2)

Hence, the coordinates of the vertex that A maps to after Zachary's reflections are (3, 2)

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The correct option is (d).

The other beaker contains 17 cc (cubic centimetres) of the liquid.

The volume of a cube with dimensions of 1 cm ×1 cm× 1 cm is equal to one cubic centimetre (or cubic centimetre in US English) (SI unit symbol: cm³; non-SI abbreviations: cc and ccm). A millilitre's volume is equal to one cubic centimetre.

According to the question,

The total liquid is 32 in cubic centimetres which is stored in the two beakers.

In the first beaker the liquid stored is 15 cubic centimetres.

The second beaker will contain the liquid = total liquid stored in both beakers - liquid stored in the first beaker.

Liquid in second beaker = 32 - 15

                                        = 17

Therefore, the liquid stored in the second beaker is 17 cc (cubic centimetres).

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Answer:

system of equation by elimination

1 write both equation in standard form

2 make the coefficient of one variable opposites

3 add the questions relating from step to eliminate one variable

4 solve for the remaining variable

5 substitute the solution from step for into one of the original equation

The number of cuboids of dimension 2 cm x 3 cm x 4 cm, required to make a cube is 9.

Dimensions of the cuboid Deeksha made are given as 2 cm x 3 cm x 4 cm.

Thus, the volume of this cuboid = 2*3*4 cm³ = 24 cm³.

Using the formula for the volume of cuboid as the product of the three sides.

Deeksha wants to make a cube combining some number of these cuboids.

Assuming the side length of the cube to a, the volume of the cube = a³.

Assuming the number of cuboids required to make 1 cube to be n, we can write that a³ = n*(24 cm³).

To make this relation true, we need the right-hand side to be a perfect cube.

Prime factorizing the volume of the cuboid, we get 24 cm³ = 2³ * 3 cm³.

To make it a perfect cube, we need to multiply 3², by it.

Thus, n = 3² = 9.

Thus, the number of cuboids of dimension 2 cm x 3 cm x 4 cm, required to make a cube is 9.

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The provided question is incorrect. The correct question is:

"Deeksha made cuboid of size 2 cm x 3 cm x 4 cm. how many such

cuboids will be required to make a cube?"

Answer:

100.5 inches

Step-by-step explanation:

If each course has 3/8 inch of concrete below it  (including the bottom one)

  8 in * 12   + 3/8 in * 12 = 100 1/2 inches

The equation of a parabola whose vertex is (0, 0) and focus is (1 / 8, 0) is equal to x = 2 · y².

Herein we have the case of a parabola whose axis of symmetry is parallel to the x-axis. The standard form of the equation of this parabola is shown below:

(x - h) = [1 / (4 · p)] · (y - k)²     (1)

Where:

The distance from the vertex to the focus is 1 / 8. If we know that the location of the vertex is (0, 0), then the standard form of the equation of the parabola is:

x = 2 · y²     (1)

The equation of a parabola whose vertex is (0, 0) and focus is (1 / 8, 0) is equal to x = 2 · y².

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The statements that are true about the domain and range of the functions f(x), g(x), and h(x) include:

It should be noted that a function simply means a relation between a set of inputs to a set of possible outputs.

In this case, f(x) has a domain of all real numbers as well as g(x) which also has a domain of all real numbers.

In conclusion, the correct options are A and D.

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Answer:

A and D

Step-by-step explanation:

Edge 2022

The equation of the line in explicit form is y = - 2 · x + 5, whose implicit form is 2 · x + y = 5. (Correct choice: D)

In this question we must find the equation of the line perpendicular to the segment BC and that goes through the point A(x, y) = (1, 3). First, the slope of the line segment BC is:

m = [1 - (- 3)]/[5 - (- 3)]

m = 4/8

m = 1/2

And the slope of the line is:

m' = - 1/(1/2) = - 2

The intercept of the line is found by using the explicit form of equation of the line, m' = - 2 and (x, y) = (1, 3):

3 = - 2 · 1 + b

b = 5

The equation of the line in explicit form is y = - 2 · x + 5, whose implicit form is 2 · x + y = 5. (Correct choice: D)

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Since the geometric series has 6 terms, increases by a factor of 4, and has a sum of 1365, the value of the first term is 1.

The sum of a geometric series is given by

Sₙ = a(rⁿ - 1)/(r - 1) with r > 1 where

Now, since our Geometric Series has 6 terms, n = 6. Also, it increases by a factor of 4, so, r = 4 and has a sum of 1365, so Sₙ = 1356. So,we have that

Since we require the first term, a , making a subject of the formula, we have

a = Sₙ(r - 1)/(rⁿ - 1)

Substituting the values of the variables into the equation, we have

a = Sₙ(r - 1)/(rⁿ - 1)

a = S₆(r - 1)/(r⁶ - 1)

a = 1365(4 - 1)/(4⁶ - 1)

a = 1365(3)/(4096 - 1)

a = 4095/4095

a = 1

So, the value of the first term is 1.

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[tex] {\qquad\qquad\huge\underline{{\sf Answer}}} [/tex]

Here we go ~

[tex]\qquad \sf  \dashrightarrow \: (1.6 \times 10 {}^{5} ) \sdot(2 .3 \times {10}^{1} )[/tex]

[tex]\qquad \sf  \dashrightarrow \: (1.6 \times 2.3) \sdot(10 {}^{5} \times 10 {}^{1} )[/tex]

[tex]\qquad \sf  \dashrightarrow \: 3.68 \times 10 {}^{6} [/tex]