can someone helpp cuz this is confusing me

Let's see

seven eighths means 7/8

So

Forty two eighths

Answer:

x = 6

Step-by-step explanation:

35 - 2x = 23

35 - 23 - 2x = 0

35 - 23 = 2x

12 = 2x

x = 6

35- 2x = 23

Subtract 35 from both sides.

Subtract 35 from 23 to get −12.

Divide both sides by −2.

Divide −12 by −2 to get 6.

Answer:After dialation

A'=6,24

B'=12,12

C'=-12,6

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The amount of the galleys or the number of galleys.

If given the amount of galleons, you can find the amount of galleys by dividing the number of given galleons by 5.

If given the amount of galleys, you can find the amount of galleons by multiplying the number of given galleys by 5.

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Answer:

10 unit^2.

Step-by-step explanation:

The base of the triangle (CE)

= 6 - 2 = 4 units

The height = 5

Area = 1/2 * 4 * 5

= 10 unit^2.

Answer:

10

Step-by-step explanation:

area = hight ×base÷2

hight = 5-0

= 5

base = 6-2

= 4

area = 4×5÷2

=10

The total amount in the investment account is $3031.00

The given parameters are

Principal, P = $2800

Rate, r = 5.5%

Time = 18 months i.e. 1.5 years

The amount is then calculated as:

A = P + PRT

This gives

A = 2800 + 2800 * 5.5% * 1.5

Evaluate

A = 3031

Hence, the total amount in the investment account is $3031.00

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The volume of the balloon is 1441.64cm³.

The radius of the balloon is given as 7cm. Also, the equation to calculate the volume is given as c³/6π²

The circumference c will be:

= 2πr = 2 × 22/7 × 7

= 44

The volume will be:

= c³/6π²

= 44³/(6 × 3.14²)

= 85284/(59.1576)

= 1441.64

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The value of x when y =2 is 8

The inverse proportion to the square of x represented as:

k = yx^2

Where

k represents the constant of proportion

When y = 2, x = 8.

So, we have:

k =2 * 8^2

k =128

Substitute k = 128 in k = yx^2

So, we have:

yx^2 = 128

When y = 2, we have:

2x^2 = 128

Divide by 2

x^2 = 64

Take the square roots

x = 8

Hence, the value of x when y =2 is 8

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The length of the diagonal and the shorter base are 17. 24 feet and 18. 7 feet long respectively.

The cosine rule is given as;

[tex]c = \sqrt{a^2 + b^2 - 2ab cos \alpha }[/tex]

c = length of the diagonal

a = base length = 22 feet

b = 7 feet

[tex]c = \sqrt{7^2 + 22^2 - 2 * 7 * 22 cos 40}[/tex]

[tex]c = \sqrt{533 - 308 * 0. 7660}[/tex]

[tex]c = \sqrt{533 - 235. 93}[/tex]

[tex]c = \sqrt{297. 072}[/tex]

[tex]c = 17. 24[/tex] feet

Using sine rule

[tex]\frac{a}{sin A } = \frac{c}{sin C}[/tex]

[tex]\frac{a}{sin 70} = \frac{17. 24}{sin 40}[/tex]

Cross multiply

[tex]a[/tex] × [tex]sin 60[/tex] = [tex]c[/tex] × [tex]sin 70[/tex]

[tex]a[/tex] × [tex]0. 8660[/tex] = [tex]17. 24[/tex] × [tex]0. 9397[/tex]

[tex]a = \frac{16. 20}{0. 8660}[/tex]

a = 18. 7 feet long

Thus, the length of the diagonal and the shorter base are 17. 24 feet and 18. 7 feet long respectively.

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The statement that is true about Sheila's savings plan is that; C.

Sheila must save $60 per month to achieve her goal.

The price of bathroom remodeling is $ 810.

After 13 months , she has saved $ 510

This means that she has a $300 shortage to cover in 5 months.

This means that she need to save :

$300/5  = $60 / month in order to achieve her goal

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Answer: C

Step-by-step explanation: edge

Answer:

6b-4b=a+3a

2b=4a

4a=2b

a=2b/4

a=b/2

The algebraic equation to represent the given situation is as follows,

y = 4 + 2x

What is an algebraic equation?

The term "algebraic equation" refers to a formulation of the equality of two expressions using the algebraic operations of addition, subtraction, multiplication, division, raising to a power, and extraction of a root on a set of variables.

An expression that includes variables, constants, and algebraic operations is known as an algebraic expression in mathematics (addition, subtraction, etc.).

Forming the Algebraic Equation

Number of book present on the shelf initially = 4

It is given that 2 books are added per minute to the shelf.

If x is the number of minutes, then the books added will be 2x.

If y is the total number of books present on the shelf, then the algebraic equation is given as,

y = Number of books initially present on the shelf  + 2x

⇒ y = 4 + 2x

Thus, y = 4 + 2x is the required algebraic equation.

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Answer:

Step-by-step explanation:

Givens

line: 5y + 2x =  10

point (-2 , 5)

Discussion and Solution

You have to rearrange the given line to get the slope. It isn't nice, but it's not impossible.

5y + 2x = 10                            Subtract 2x from both sides

5y + 2x - 2x = -2x + 10           Simplify

5y = - 2x + 10                          Divide by 5

5y/5 = -2x/5 + 10/5                 Simplify

y = -0.4x + 2            

So the new equation is going to have a slope of - 0.4

So far what you have is

y =  - 0.4x + b

Now use the point to find the y intercept. What you should be thinking about the point is that when x = -2 then y = 5. Substitute that into the new equation.

5 = -0.4*-2 + b

5 = 0.8 + b                                Subtract 0.8 from both sides

5 - 0.8 = 0.8 - 0.8 + b               Simplify

4.2 = b

Answer

y = -0.4x + 4.2

Answer:

72

Step-by-step explanation:

This shape is a prism; it's a 3-D shape with 6 sides. Basically, it's a box.

All 6 sides are rectangles.

Surface area means that we'll find the area of all 6 rectangles and add them up.

There's a front and back, left and right, and a top and bottom.

The area of a rectangle is length×width or base×height.



The front and back are identical.

Area = length×width

Area = 6×3 = 18

Since the front and back are the same, two of the rectangles have area = 18.



The left and right are the same:

Area = 3 × 2

Area = 6

Two faces have area = 6.

The top and bottom are the same.

Area = 6 × 2

Area = 12

Again, two faces have area = 12.

To find the total surface area, add up all 6 areas.

A =18+18+6+6+12+12

A = 72

Using the z-distribution, considering the standard 95% confidence level, the margin of error is of 0.0486 = 4.86%.

A confidence interval of proportions is given by:

[tex]\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}[/tex]

The margin of error is:

[tex]M = z\sqrt{\frac{\pi(1-\pi)}{n}}[/tex]

In which:

In this problem, we have a 95% confidence level, hence[tex]\alpha = 0.95[/tex], z is the value of Z that has a p-value of [tex]\frac{1+0.95}{2} = 0.975[/tex], so the critical value is z = 1.96.

The sample size and the estimate are given by:

[tex]n = 350, \pi = \frac{240}{350} = 0.6857[/tex]

Hence the margin of error is:

[tex]M = z\sqrt{\frac{\pi(1-\pi)}{n}}[/tex]

[tex]M = 1.96\sqrt{\frac{0.6857(0.3143)}{350}}[/tex]

M = 0.0486 = 4.86%.

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Answer:

99% - 0.06

95% - 0.05

90% - 0.04

Step-by-step explanation: i got it right

The width of the delivery box is 9 inches.

Given that  volume of delivery box is 756 cubic inches,length is 6 inches less than twice the width, height is 2 inches less than width.

let width be x

Length = 2x- 6

Height = x - 2

Width = x

We can find the value of x by putting values one by one and then we will be able to get the value of  x which is width.

Because the delivery box is cuboid in shape so the volume is equal to product of length,breadth and height.

When x=7: Volume=7 x (7 - 2) x (2x7 - 6) = 7 x 5 x 8 = 280

When x=9,Volume will be 9 x (9 - 2) x (2x9 - 6) = 9 x 7 x 12 = 756

Therefore, the width of the delivery box is 9 inches.

Hence the width of the delivery box is 9 inches.

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Using the binomial distribution, the probabilities are given as follows:

The formula is:

[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]

[tex]C_{n,x} = \frac{n!}{x!(n-x)!}[/tex]

The parameters are:

The values of the parameters for this problem are:

n = 10, p = 0.4.

The probability that more than 4 weigh more than 20 pounds is:

[tex]P(X > 4) = 1 - P(X \leq 4)[/tex]

In which:

[tex]P(X \leq 4) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4)[/tex]

Then:

[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]

[tex]P(X = 0) = C_{10,0}.(0.4)^{0}.(0.6)^{10} = 0.0061[/tex]

[tex]P(X = 1) = C_{10,1}.(0.4)^{1}.(0.6)^{9} = 0.0403[/tex]

[tex]P(X = 2) = C_{10,2}.(0.4)^{2}.(0.6)^{8} = 0.1209[/tex]

[tex]P(X = 3) = C_{10,3}.(0.4)^{3}.(0.6)^{7} = 0.2150[/tex]

[tex]P(X = 4) = C_{10,4}.(0.4)^{4}.(0.6)^{6} = 0.2502[/tex]

Hence:

[tex]P(X \leq 4) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) = 0.0061 + 0.0403 + 0.1209 + 0.2150 + 0.2502 = 0.6325[/tex]

[tex]P(X > 4) = 1 - P(X \leq 4) = 1 - 0.6325 = 0.3675[/tex]

0.3675 = 36.75% probability that more than 4 weigh more than 20 pounds.

The probability that fewer than 3 weigh more than 20 pounds is:

P(X < 3) = P(X = 0) + P(X = 1) + P(X = 2) = 0.0061 + 0.0403 + 0.1209 = 0.1673

0.1673 = 16.73% probability that fewer than 3 weigh more than 20 pounds.

For more than 7, the probability is:

[tex]P(X > 7) = P(X = 8) + P(X = 9) + P(X = 10)[/tex]

[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]

[tex]P(X = 8) = C_{10,8}.(0.4)^{8}.(0.6)^{2} = 0.0106[/tex]

[tex]P(X = 9) = C_{10,9}.(0.4)^{9}.(0.6)^{1} = 0.0016[/tex]

[tex]P(X = 10) = C_{10,10}.(0.4)^{10}.(0.6)^{0} = 0.0001[/tex]

Since P(X > 7) < 0.05, it would be unusual if more than 7 of them weigh more than 20 pounds.

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The statement that correctly describes the horizontal asymptote of g(x) is:

Limit of g (x) as x approaches plus-or-minus infinity = 6, so g(x) has an asymptote at y = 6.

In this problem, the function is:

[tex]g(x) = \frac{42x^3 - 15}{7x^3 - 4x^2 - 3}[/tex]

The horizontal asymptote is given as follows:

[tex]y = \lim_{x \rightarrow \infty} g(x) = \lim_{x \rightarrow \infty} \frac{42x^3 - 15}{7x^3 - 4x^2 - 3} = \lim_{x \rightarrow \infty} \frac{42x^3}{7x^3} = \lim_{x \rightarrow \infty} 6 = 6[/tex]

Hence the correct statement is:

Limit of g (x) as x approaches plus-or-minus infinity = 6, so g(x) has an asymptote at y = 6.

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Answer:

[tex]\sf A) \quad \begin{cases}\sf y > -5x+5\\\sf y < -5x+12\end{cases}[/tex]

B)  see below

C)  points C, E and F

Step-by-step explanation:

Given points:

A system of inequalities is a set of two or more inequalities in one or more variables.

To create a system of inequalities that only contains C and F in the overlapping shaded region, create a linear equation where points C, F and E are to the right of the line and a linear equation where points C, F, A, B and D are to the left of the line.

The easiest way to do this is to find the slope of the line that passes through points C and F, then add values to move the lines either side of the points.

[tex]\sf slope\:(m)=\dfrac{change\:in\:y}{change\:in\:x}=\dfrac{y_F-y_C}{x_F-x_C}=\dfrac{-4-1}{3-2}=-5[/tex]

Therefore:

[tex]\sf y = -5x + 5[/tex]  →  points C, F and E are to the right of the line.

[tex]\sf y=-5x+12[/tex]  →  points C, F, A, B and D are the left of the line.

Therefore, the system of inequalities that only contains points C and F in the overlapping shaded regions is:

[tex]\begin{cases}\sf y > -5x+5\\\sf y < -5x+12\end{cases}[/tex]

To graph the system of inequalities:

To verify that the points C and F are solutions to the system of inequalities created in Part A, substitute the x-values of both points into the system of inequalities.  If the y-values satisfy both inequalities, then the points are solutions to the system.

Point C (2, 1)

[tex]\implies \sf x=2 \implies 1 > -5(2)+5 \implies 1 > -5\quad verified[/tex]

[tex]\implies \sf x=2 \implies 1 < -5(2)+12\implies 1 < 2 \quad verified[/tex]

Point F (3, -4)

[tex]\implies \sf x=3 \implies -4 > -5(3)+5 \implies -4 > -10\quad verified[/tex]

[tex]\implies \sf x=3 \implies -4 < -5(3)+12\implies -4 < -3 \quad verified[/tex]

Method 1

Graph the line y = 7x - 4 (making the line dashed since it is y < 7x - 4).

Shade below the dashed line.

Points that are contained in the shaded region are the houses in which Erica is interested in living:  points C, E and F.

Method 2

Substitute the x-value of each point into the given inequality y < 7x - 4.

Any point where the y-value satisfies the inequality is a house that Erica is interested in living.

[tex]\sf Point\: A: \quad x=-5 \implies 5 < 7(-5)-4 \implies -5 < -39 \implies no[/tex]

[tex]\sf Point\: B: \quad x=-4 \implies -2 < 7(-4)-4 \implies -2 < -32 \implies no[/tex]

[tex]\sf Point\: C: \quad x=2 \implies 1 < 7(2)-4 \implies 1 < 10 \implies yes[/tex]

[tex]\sf Point\: D: \quad x=-2 \implies 4 < 7(-2)-4 \implies 4 < -18 \implies no[/tex]

[tex]\sf Point\: E: \quad x=2 \implies 4 < 7(2)-4 \implies 4 < 10 \implies yes[/tex]

[tex]\sf Point\: F: \quad x=3 \implies -4 < 7(3)-4 \implies -4 < 17 \implies yes[/tex]

Answer:

w = ±[tex]\sqrt{1/2}[/tex] or w= ±[tex]\sqrt{2}[/tex]

Step-by-step explanation:

if we say some variable y = w^2, we can rewrite the equation to:

2y^2 - 5y + 2 = 0

this can be factored into (2y-1)(y-2) = 0

putting w^2 back in the place of y, that's (2w^2 - 1)(w^2 - 2) = 0

The equation is a fourth degree polynomial, so there are four roots, or four values of w that will cause the equation to equal 0.

If 0 is multiplied by anything, the result is 0, so we set 2w^2 - 1 = 0 and solve for w, which is ±√1/2, then set w^2 - 2 = 0 to get w = ±√2 as our roots

the four solutions are ±√1/2 and ±√2

(because the positive counts as one solution and the negative another solution)

We find that the function that could be a stretch of the exponential decay is [tex]f(x) = 2\cdot \left(\frac{1}{6} \right)^{x}[/tex]. (Correct choice: C)

Exponential functions are trascedent functions whose form is described below:

[tex]y = a\cdot r^{x}[/tex]     (1)

Where:

There are two conditions for a stretch factor and exponential decay: (i) a > 1, (ii) 0 < r < 1. Thus, we find that the function that could be a stretch of the exponential decay is [tex]f(x) = 2\cdot \left(\frac{1}{6} \right)^{x}[/tex]. (Correct choice: C)

The picture is missing and it cannot be found, but statement is still solvable as there is only one choice that responds the question.

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The additional information needed to determine that ABCD is a parallelogram is: A. AB ≅ CD.

One of the criteria for proving that a quadrilateral is a parallelogram is that one of the pairs of opposite sides are congruent and also parallel to each.

We are already given that side AB is parallel to side CD, therefore, the additional information we would need to prove that quadrilateral ABCD is a parallelogram is: A. AB ≅ CD.

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Answer:

the 50th percentile = 66

The 25th percentile = 35

The 75th percentile = 85

Step-by-step explanation:

 We have 11 numbers ,so we are dealing with an odd set of values.

Also ,we notice that the numbers are already in order.

then

the 50th percentile of the set  27, 34, 35, 48, 48, 66, 75, 85, 85, 96, 99

is the 6 number in the list [ 6 = (11+1)/2 ]

Which is 66.

The 25th percentile (the median) of the set 27, 34, 35, 48, 48

is the 3rd number [ 3 = (5+1/)2 ]

Which is 35.

The 75th percentile (the median) of the set 75, 85, 85, 96, 99

is the 3rd number [ 3 = (5+1/)2 ]

Which is 85.

Answer:

3rd option

Step-by-step explanation:

y is negative below the x- axis , that is for values of x in the interval

x > - 6 and x < 6

hi

we have an aroithmetic serie of first term 1 and  pace  2

so sum of 12 first terms, namming  1 as  S1 and  12th term as  S12

S12 =  1 + 2*11 = 23

formula of summ :      number of term *  (  final term + first term) / 2

So sum of terms  from S1 +S12 =    12   ( S12 +S1 )  / 2  =  12 * ( 23+1) /2

12*  12=  144

-

The possible values of the number of dollars in the original pile of money is on the interval (200, 440)

We are told that Jeri finds a pile of money with at least $200.

Now, let x be  the additional amount over the  original amount of $200.

The greater side of the  inequality will be expressed as;

Original  pile  =  (200 + x)

After  she gives away $80 and as such she has;  (120 + x)

And  she gives (1/3)  of  this away  which means she will have;

=  (1/3) (120 + x)

Thus, she  must  have  (2/3)  of this left

=  (2/3)(120 + x) = amount in her right pocket

The lesser  side of the inequality is expressed as;

(x + 200)  -  200   =   x

Thus, we now have  that;

2[120 + x ]/3  >  x

240 + 2x  >  3x

240 > 3x - 2x

240 > x

x < 240

Thus, we can conclude that the original  amount could be on the interval   (200, 440)

The possible values of the number of dollars in the original pile of money is on the interval (200, 440)

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Answer:

0,5*0,5=0,25

Step-by-step explanation:

assuming a die of 6 faces

25

0,5 for < 4; 0,5 for < 3

The bronze-casting process that depends on a modelled original form is:  lost-wax casting.

Lost-wax casting is a bronze-casting process which is also referred to as the cire-perdue. In this type of metal casting, a wax model is created when a molten metal is usually poured into a mold. The wax model is then melted and drained.

In summary, the name for this bronze-casting process that relies on this wax model is called: lost-wax casting.

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