Can you have p and KE with 0 kg mass why or why not?

Answer:

answer is 66 kilograms-force = 647.2389 newtons

Explanation:

Answer:

[tex]\boxed {\boxed {\sf 646.8 \ Newtons }}[/tex]

Explanation:

Weight in Newtons can be found by multiplying the mass times the acceleration of gravity.

[tex]W=m*g[/tex]

The mass of the man is 66 kilograms on Earth.

Earth has an acceleration of gravity that is 9.8 meters per square second.

[tex]m= 66 \ kg \\g=9.8 \ m/s^2[/tex]

Substitute the values into the formula.

[tex]W=66 \ kg *9.8 \ m/s^2[/tex]

Multiply.  

[tex]W=646.8 \ kg*m/s^2[/tex]

1 kg * m/s² is equal to 1 Newton, therefore our answer of 646.8 kg *m/s² is also equal to 646.8 Newtons, or N.

[tex]W=646.8 \ N[/tex]

The man's weight in Newtons in 646.8 Newtons.

Answer : 16 m/s east

Explanation: Trust the process!!

From the frame of reference of runner 1, the velocity of runner 2 will be D) 16 m/s east

The relative velocity is defined as the velocity of an object with respect to another observer

When two bodies are moving in opposite directions , relative velocity get added and if bodies are moving in same direction , relative velocity will get subtracted .

From the frame of reference of runner 1, the velocity of runner 2 will be

v (relative) = v1 + v1

v1 = velocity of runner 1  = 11m/s west

v2 = velocity of runner 2 = 5m/s

v = 11 + 5 = 16 m/s

correct answer will be O D. 16 m/s east as runner 2 is running in east direction

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Answer:

A cell is the basic block of life and is always changing to fit its environment.

Explanation:

A cell is the basic founding block of a living organisms. In other words, a cell is the basic membrane  unit which contains fundamental molecules of life. It is the cell that all living things are composed of.

The cell always changes with the surroundings and environment and it adapts to it. The cells requires a constant adjustments as the conditions inside and the outside the cells changes to keep a stable internal environment. Because the environment internally and externally is always changing, the cell continuously make adjustments to stay at or the near the set point.

Answer:

Alot of god dam rabbits

Explanation:

Answer:

million rabbits becauseeverything

Answer:

HCI

Explanation:

I dont know what you mean by coefficient but that's the thing you would see in the periodic table

Answer:

Explanation:

The gravitational force between two objects becomes weaker if the two objects are moved apart and stronger if they are brought closer together; that is, the force depends on the distance between the objects.

The gravitational force between two objects as the bodies become closer to each other increases.

Gravitational force is force of attraction between two masses. Gravitational force(F) between two bodies is directly proportion to the product of masses(m₁,m₂) of two bodies and inversely proportional to square of distance(r) between them. mathematically it is written as,

F ∝ m₁.m₂

F ∝ 1/r²

F = G m₁,m₂÷r²

where G is gravitational constant, whose value is 6.6743 × 10⁻¹¹ m³ kg-1s⁻².

Force is expressed in Newton N in SI unit. its dimensions are [M¹L¹T⁻²].

As distance decreases the Force increases

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Answer:

I think A. would be brighter

Explanation:

Circuit A has only one bulb so it gets 100% of the electricity

Circuit B has two bulbs which means that they only get 50% of the electricity because it has to be split equally.

Hope it helps!

Answer is c, they are equal:

Explanation:

The initial vertical velocity of a ball thrown horizontally with an initial velocity of 20 m/s from the top of a 60 m high tower is 0 m/s (option a).  

The ball is thrown horizontally, so its velocity will have only components in the x-direction (horizontal). The components of the initial velocity in the y-direction (vertical) will be zero.    

For a ball's velocity to have components in the vertical and horizontal direction, the ball must be thrown at a certain angle to the ground, describing a parabolic movement.

In a parabolic movement, the vertical and horizontal components of the velocity would be:

[tex] v_{x} = v_{i}cos(\theta) [/tex]

[tex] v_{y} = v_{i}sin(\theta) [/tex]

Where:

[tex] v_{i} [/tex]: is the initial velocity

θ: is the angle

Therefore, the initial vertical velocity of the ball is zero (option a).

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The distance traveled by the train is 900 m.

The given parameters:

The distance traveled by the train is calculated as follows;

[tex]s = ut + \frac{1}{2} at^2\\\\s = (15 \times 20) + (0.5 \times 3 \times 20^2)\\\\s = 900 \ m[/tex]

Thus, the distance traveled by the train is 900 m.

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Answer:

900m

Explanation:

Use the equation: acceleration (a) = change in velocity (v – u) / time taken (t)

Rearrange to solve for the final velocity (v):

v = u + at

Substitute in values and solve:

v = 15 m/s + 3 m/s2 × 20 s = 75 m/s

Rearrange the equation for uniform acceleration (v2 – u2 = 2as) to solve for distance (s):

s = (v2 – u2) / 2a

s = ((75 m/s)2 – (15 m/s)2) / (2 × 3 m/s2)

s = (5,625 m2/s2 – 225 m2/s2) / 6 m/s2

s = 5400 m2/s2 / 6 m/s2

s = 900 m

Answer:

speed of rocket=615.38m/s

Explanation:

Answer:

chickens

Explanation:

Answer:

The force that is “left over” after all of the forces acting on an object are cancelled and/or combined is called the net force. A 3 N force and a 7 N force act in the same direction on a box. A 3 N force and a 7 N force act in opposite directions on a box.

Answer:

A. Cue, White Ball, Blue Ball

Explanation:

Visualize in which order things are being hit

Answer:

A. 1.71 m

B. 2.66 m

Explanation:

A. Determination of the height of the pier.

We'll begin by calculating the time taken for the ball to get to the water

This can be obtained as follow:

Horizontal velocity (u) = 1.27 m/s,

Horizontal distance (s) = 0.75 m

Time (t) =?

s = ut

0.75 = 1.27 × t

Divide both side by 1.27

t = 0.75 / 1.27

t = 0.59 s

Finally, we shall determine the height of the pier as follow:

Acceleration due to gravity (g) = 9.8 m/s²

Time (t) = 0.59 s

Height of pier (h) =?

h = ½gt²

h = ½ × 9.8 × 0.59²

h = 4.9 × 0.3481

h = 1.71 m

Thus, the height of the pier is 1.71 m

B. Determination of the horizontal distance.

Horizontal velocity (u) = 4.50 m/s

Time (t) = 0.59 s

Horizontal distance (s) =?

s = ut

s = 4.5 × 0.59

s = 2.66 m

Thus, if the ball moved at a velocity of 4.50 m/s off the pier, it will land at a distance of 2.66 m from the end of the pier.

Answer:

this is the answer according to my calculations

Explanation:

0.001.9

Answer: kinetic energy is Energy of motion.

Explanation:

Answer: A car initially traveling at 60 km/h accelerates at a constant rate of 2.0 m/s2. A spaceship far from any star or planet accelerates uniformly from 72 m/s to 160 m/s .

Explanation: i hoped that helped you.

Answer:  If you move a magnet quickly through a coil of copper wire, the electrons will move - this produces electricity.

Explanation:

Answer:

Explanation:

The mass of the object can be found by using the formula

[tex]m = \frac{f}{a} \\ [/tex]

f is the force

a is the acceleration

From the question we have

[tex]m = \frac{147}{9.8} \\ [/tex]

We have the final answer as

Hope this helps you

Answer: correct me if i'm wrong but is it 0.361N

Answer:

A toaster because you plug it up for electric energy and heat to toast it

Answer:

False.

Explanation:

The layer beneath the another rock will be older. The sequence will not matter in the layers of the rock. The layer inside will be older than the upper layer. This is called law of Superposition. Sedimentary rocks forms the youngest layer of the rocks.

Answer:

Mechanical waves

Electromagnetic waves

Matter waves

Longitudinal waves

Transverse waves

Surface waves

Explanation:

Pls give Brainliest!!

Answer:

1) τ = I α    whereby the torque is provided by the angular acceleration

2)  L = 216 Kg m² / s

Explanation:

1) Let's start with Newton's second law

       F = m a

multiply by the arm or perpendicular distance

       F r = m a r

if the distance is not perpendicular a way of realizing the relations using the vector product

      τ = F r = F x r

the bold are vectors.  The angular and linear acceleration are related

       a = α r=

      τ = m (α r) r

      τ = (m r²) α

the inertia of the rotational motion is

        I = m r²

we substitute

       τ = I α

whereby the torque is provided by the angular acceleration.

As an example we have:

* a spinning disk

* a ball rotating in the air

* a pulley

2) The rotational momentum is

           L = I w

the moment of inertia of a rod that through its center

           I = m L²

we substitute

           L = m L² w

let's calculate

          L = 6 1.5 2 16

          L = 216 Kg m² / s

La cantidad de movimiento angular de la varilla uniforme es 18 kilogramos-metro cuadrado por segundo.

1) La relación entre el momento de torsión ([tex]M[/tex]), una variable cinética y relacionada con la aplicación de una fuerza externa cuya línea de proyección no cruza el centro de masa del objeto, y la aceleración angular ([tex]\alpha[/tex]), una variable cinemática, es la resistencia del cuerpo a rotar, la cual es función de su masa y su geometría, representada por la variable de momento de inercia.

A continuación, presentamos tres ejemplos del concepto:

2) Asumamos que la varilla uniforme es de masa constante, con una rotación a velocidad angular constante y con un centro de rotación localizado en el centro geométrico de la varilla. La cantidad de movimiento es expresada mediante la siguiente ecuación:

[tex]L = I\cdot \omega[/tex] (1)

Donde:

El momento de inercia de una varilla uniforme con centro de rotación en el centro queda expresado por la siguiente fórmula:

[tex]I = \frac{1}{12}\cdot m\cdot L^{2}[/tex] (2)

Donde:

Al aplicar (2) en (1), tenemos la expresión resultante:

[tex]L = \frac{1}{12} \cdot m\cdot L^{2}\cdot \omega[/tex] (3)

Si sabemos que [tex]m = 6\,kg[/tex], [tex]L = 1.5\,m[/tex] y [tex]\omega = 16\,\frac{rad}{s}[/tex], entonces la cantidad de movimiento angular es:

[tex]L = \frac{1}{12}\cdot (6\,kg)\cdot (1.5\,m)^{2}\cdot \left(16\,\frac{rad}{s} \right)[/tex]

[tex]L = 18\,\frac{kg\cdot m^{2}}{s}[/tex]

La cantidad de movimiento angular de la varilla uniforme es 18 kilogramos-metro cuadrado por segundo.

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