Cho A=( căn x -4x /1-4x -1) : (1+2x/1-4x -2căn x/ 2căn x -1 -1)

Answer:

x = 38.7

Step-by-step explanation:

Since this is a right triangle, we can use trig functions

tan theta = opp / adj

tan x = 8/10

taking the inverse tan of each side

x = tan ^-1 (8/10)

x=38.65980825

To the nearest tenth

x = 38.7

9514 1404 393

Answer:

Step-by-step explanation:

The coefficient of a term is its constant multiplier. The exponent is the power to which the base is raised.

The term 4·b^(-3) has an exponent of -3, a base of b and a coefficient of 4.

The exponent is -3; the coefficient is 4.

Answer:

exponent = -3           coefficent = 4

Step-by-step explanation:

Answer:

L = 29,550 mm (as per BS8110 the length is to the nearest 25)

Step-by-step explanation:

Lets make it so simple and easy.

Let A = 600mm

Let B = 300mm

Let C = 16 as number turns

Let d = 20mm

L = [tex]\sqrt{(3.14 * (600 - 20))^{2} + 300^{2}[/tex]  x 16

L = 29,550 mm (as per BS8110 the length is to the nearest 25)

9514 1404 393

Answer:

Step-by-step explanation:

The reduced side ratios, shortest to longest are ...

  AC : AT : CT = 8 : 9 : 15

  OD : OG : DG = 5 : 6 : 10

These are different ratios, so the triangles are not similar.

Answer:

It will be irrational

Step-by-step explanation:

irrational+rational=irrational

Answer:

March through August

Step-by-step explanation:

Ok, in order to solve this problem, we must start by building an equation to solve. The original equation was:

[tex]S=56.9-40.7cos (\frac{\pi}{6}t)[/tex]

and we need to figure out the months when the sales exceed 7700 units. Since the equation is given in hundreds of units, we need to divide those 7700 units into one hundred to get 77 hundred units. So we can go ahead and substitute that value in the equation:

[tex]77=56.9-40.7cos (\frac{\pi}{6}t)[/tex]

if you wish you can rewrite the equation so the variable is on the left side of it but it's up to you. So you get:

[tex]56.9-40.7cos (\frac{\pi}{6}t)=77[/tex]

and now we solve for t

[tex]-40.7cos (\frac{\pi}{6}t)=77-56.9[/tex]

[tex]-40.7cos (\frac{\pi}{6}t)=20.1[/tex]

[tex]cos (\frac{\pi}{6}t)=\frac{20.1}{-40.7}[/tex]

[tex]cos (\frac{\pi}{6}t)=-0.4938[/tex]

[tex]\frac{\pi}{6}t=cos^{-1}(-0.4938)[/tex]

[tex]\frac{\pi}{6}t=2.087[/tex]

[tex]t=\frac{2.087(6)}{\pi}[/tex]

[tex]t=3.98 months[/tex]

but there is a second answer to this problem. Notice that the function cos can be 2.87 at [tex]2\pi-2.087=4.1962 rad[/tex] as well, so we repeat the process:

[tex]\frac{\pi}{6}t=4.1962[/tex]

[tex]t=\frac{4.1962(6)}{\pi}[/tex]

[tex]t=8.014 months[/tex]

So now we need to determine on which period of times the number of items sold exceed 77 hundred units so we build different intervals for us to test:

(1,3.98)  (3.98,8.014) and (8,014, 13)

and find a test value for each of the intervals and test it.

(1,3.98) t=2

[tex]S=56.9-40.7cos (\frac{\pi}{6}(2))[/tex]

S=36.55

this is less than 77 so this is not our answer.

(3.98,8.014) t=5

[tex]S=56.9-40.7cos (\frac{\pi}{6}(5))[/tex]

S=92.15

this is more than 77 so this is our answer.

(8.014,13) t=10

[tex]S=56.9-40.7cos (\frac{\pi}{6}(10))[/tex]

S=36.55

this is less than 77 so this is not our answer.

so, since our answer is the interval (3.98,8.014)

this means that between the months of march and august we will be sellin more than 7700 units.

Answer:

[tex]\theta[/tex] =2mπ + π/3 for m ∈ Z.

Step-by-step explanation:

Given the equation [tex]2sin\theta - \sqrt{3} = 0[/tex], we are to find all the values of [tex]\theta[/tex] that satisfies the equation.

[tex]2sin\theta - \sqrt{3} = 0\\\\2sin\theta = \sqrt{3} \\\\sin\theta = \sqrt{3}/2 \\\\\theta = sin{-1} \sqrt{3}/2 \\\\\theta = 60^0[/tex]

General solution for sin[tex]\theta[/tex] is [tex]\theta[/tex] = nπ + (-1)ⁿ ∝, where n ∈ Z.

If n is an even number say 2m, then [tex]\theta[/tex] = (2m)π + ∝ where ∝ = 60° = π/3

Hence, the general solution to the equation will be [tex]\theta[/tex] = 2mπ + π/3 for m ∈ Z.

9514 1404 393

Answer:

  (√65)/7

Step-by-step explanation:

We can use the relation between the secant and the tangent:

  sec(θ)² = tan(θ)² +1

  sec(θ) = √(1 + (-4/7)²) = √(65/49)

  sec(θ) = (√65)/7 . . . . . . secant is positive in the 4th quadrant

Answer:

-27

Step-by-step explanation:

Let x = 6 and y = -3

[tex]-(6)+7(-3)\\-6-21\\-27[/tex]

A(t) = 100t^2 + 500t + 625

3,025 square pixels

Answer:

A(t) equals 100t²+ 500t + 625.

The area of the square image after 3 seconds is 3,025 square pixels.

Answer: 5 and 6

Step-by-step explanation:

X^2 - 11 = (X-1)^2

X^2 - 11 = X^2-2X+1

X^2 - X^2 + 2X = 11+1

2X = 12

X = 6

The preceding number is 5

(6)(6)=36 and (5)(5)=25

36-25=11

The number required is 6

If the number is multiplied by itself, it becomes x²

If the result is 11 greater than the preceding number when it is multiplied by itself is expressed as:

x² - 11  = (x - 1)²

x² - 11 = x² - 2x + 1

2x = 11 + 1

2x = 12

x = 6

Hence the number required is 6

Learn more on equation here: https://brainly.com/question/2972832

Answer: [tex]-44\dfrac{4}{9}[/tex]

Step-by-step explanation:

The given expression: [tex]-36\dfrac{4}{9}-(-10\dfrac{2}{9})-(18\dfrac{2}{9})[/tex]

Here, [tex]36\dfrac{4}{9}=\dfrac{36\times9+4}{9}=\dfrac{328}{9}[/tex]

[tex](10\dfrac{2}{9})=\dfrac{92}{9}\\\\(18\dfrac{2}{9})=\dfrac{9\times18+2}{9}=\dfrac{164}{9}[/tex]

That is

[tex]-36(\dfrac{4}{9})-(-10\dfrac{2}{9})-(18\dfrac{2}{9}) = -\dfrac{328}{9}-(-\dfrac{92}{9})-\dfrac{164}{9}\\\\=-\dfrac{328}{9}+\dfrac{92}{9}-\dfrac{164}{9}\\\\=\dfrac{-328+92-164}{9}\\\\=\dfrac{-400}{9}\\\\=-44\dfrac{4}{9}[/tex]

13x - 4[x + (3 - x)] =

= 13x - 4(x + 3 - x) =

= 13x - 4 · 3 = 13x - 12

C.

Answer:

13x -12

Step-by-step explanation:

13 x - 4[ x + (3 - x )].

Combine like terms inside the brackets

13 x - 4[ 3 -0x]

13x - 4[3]

Multiply

13x -12

Answer:

69.76

Step-by-step explanation:

The mean is the average of the numbers. It can be gotten by adding all the numbers, then divide by how many numbers available.

Variance (σ2) measure the spread between numbers in a data set. That is, it measures how far each number in the set is from the mean .

mean value can be computed using below expression

= ∑x(i)P(x(i))

= 3(0.10)+11(0.30)+19(0.20)+27(0.40)

= 18.2

Therefore, the mean value is 18.2

The variance can be calculated using below expression

variance

= ∑(x(i)-mean)^2 P(x(i))

= (3-18.2)^2 (.10) + (11-18.2)^2 (.30) + (19-18.2)^2 (.20)+(27-18.2)^2(0.40)

= 69.76

Therefore, the variance Vale is 69.76

Answer:

40 years old

Step-by-step explanation:

Answer:

0.70 = 7/10

Step-by-step explanation:

Answer:

70/100 or 7/10 (Simplified)

Step-by-step explanation:

0.70 is basically .70 of 1. You can wrote this as a fraction, 70/100. If you divide 70 by 100, it gives you .70.

If you want to simplify it, it becomes 7/10, and if you divide 7 by 10, it also gives you 0.70.

Depends if you want your fraction simplified or not.

have a great day.

The volume of the cone, when the base area is 12 ft² and the height is 6 ft, is approximately 24 ft³.

To find the volume of the cone when the base area is 12 ft² and the height is 6 ft, we need to first determine the variation constant relating the volume, base area, and height.

Let's denote the volume of the cone as V, the base area as A, and the height as h. According to the problem, the volume varies jointly with the base area and the height.

Therefore, we can write the following equation:

V = k * A * h

Here k is the variation constant we want to find.

Given one set of values: when A = 15 ft² and h = 2 1/2 ft, V = 12.5 ft³.

Substitute these values into the equation and solve for k:

12.5 ft³ = k * 15 ft² * (2.5 ft)

Now, we can solve for k:

k = 12.5 ft³ / (15 ft² * 2.5 ft)

k = 0.3333 ft

Now that we have the value of the variation constant (k), we can find the volume when A = 12 ft² and h = 6 ft:

V = k * A * h

V = 0.3333 ft * 12 ft² * 6 ft

V = 23.9996 ft³

Therefore, the volume of the cone is 24 ft³.

Learn more about the volume of the cone here:

brainly.com/question/1578538

#SPJ4

The correct question is as follows:

The volume of a cone varies jointly with the base (area) and the height. The volume is 12.5 ft³ when the base (area) is 15 ft² and the height is 2 1/2 ft. Find the volume of the cone (after finding the variation constant) when the base (area) is 12 ft² and the height is 6 ft.

Answer:

what do you mean ?? i don't understand it con you tell us the question

Answer:

We conclude that the rate of smoking among those with four years of college is less than the 27% rate for the general population.

Step-by-step explanation:

We are given that a survey showed that among 785 randomly selected subjects who completed four years of college, 144 of them are smokers.

Let p = population proportion of smokers among those with four years of college

So, Null Hypothesis, [tex]H_0[/tex] : p [tex]\geq[/tex] 27%      {means that the rate of smoking among those with four years of college is more than or equal to the 27% rate for the general population}

Alternate Hypothesis, [tex]H_A[/tex] : p < 27%      {means that the rate of smoking among those with four years of college is less than the 27% rate for the general population}

The test statistics that will be used here is One-sample z-test for proportions;

                             T.S.  =  [tex]\frac{\hat p-p}{\sqrt{\frac{p(1-p)}{n} } }[/tex]  ~   N(0,1)

where, [tex]\hat p[/tex] = sample proportion of smokers = [tex]\frac{144}{785}[/tex] = 0.18

           n = sample of subjects = 785

So, the test statistics =  [tex]\frac{0.18-0.27}{\sqrt{\frac{0.27(1-0.27)}{785} } }[/tex]

                                     =  -5.68

The value of z-test statistics is -5.68.

             P-value = P(Z < -5.68) = Less than 0.0001

Now, at a 0.01 level of significance, the z table gives a critical value of -2.3262 for the left-tailed test.

Since the value of our test statistics is less than the critical value of z, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region.

Therefore, we conclude that the rate of smoking among those with four years of college is less than the 27% rate for the general population.

Answer:

The null hypothesis [tex]\mathtt{H_0 : \mu = 26500}[/tex]

The alternative hypothesis [tex]\mathtt{H_1 : \mu \neq 26500}[/tex]

Step-by-step explanation:

The summary of the given statistics is:

Population Mean = 26,500

Sample Mean = 30,150

Standard deviation = 10560

sample size = 24

The objective is to state the null hypothesis and the alternate hypothesis.

An hypothesis is a claim with  insufficient information which tends to be challenged into  further testing and experimentation in order to determine if such claim is significant or not.

The null hypothesis is a default hypothesis where there is no statistical significance between the two variables in the hypothesis.

The alternative hypothesis is the research hypothesis that the  researcher is trying to prove.

The null hypothesis [tex]\mathtt{H_0 : \mu = 26500}[/tex]

The alternative hypothesis [tex]\mathtt{H_1 : \mu \neq 26500}[/tex]

The test statistic can be  computed as follows:

[tex]z = \dfrac{\overline X - \mu}{\dfrac{\sigma}{\sqrt{n}}}[/tex]

[tex]z = \dfrac{30150 - 26500}{\dfrac{10560}{\sqrt{24}}}[/tex]

[tex]z = \dfrac{3650}{\dfrac{10560}{4.8989}}[/tex]

[tex]z = \dfrac{3650 \times 4.8989 }{{10560}}[/tex]

z = 1.6933

Answer:

(-3,-3)

B=(6-9,6+3)

Answer:

Step-by-step explanation:

speed is calculated using formula v=d/t

m= 7.5m

t= 3 min

v=?

v= 7.5m/3min

v= 2.5m/min

To solve this question, we have to understand the sum of all angles of a polygon, identify the polygon and doing this, we get that the size of each of the angles are: 119º.

Sum of angles:

The sum of angles of a polygon of n sides is given by:

[tex]S_n = 180(n-2)[/tex]

Hexagon:

6 sides, thus [tex]n = 6[/tex], and:

[tex]S_n = 180(6-2) = 180*4 = 720[/tex]

Angles:

Four are 130°, 160°, 112° and 80°, the other two are equal, so both are x. Then:

[tex]130 + 160 + 112 + 80 + x + x = 720[/tex]

[tex]482 + 2x = 720[/tex]

[tex]2x = 238[/tex]

[tex]x = \frac{238}{2}[/tex]

[tex]x = 119[/tex]

Thus, the size of each of them is of 119º.

For more of the angles of a polygon, you can check https://brainly.com/question/19023938

[tex]\\ \sf\longmapsto 3x^2+5x-8-(2x^2-4x+3)[/tex]

[tex]\\ \sf\longmapsto 3x^2+5x-8-2x^2+4x-3[/tex]

[tex]\\ \sf\longmapsto 3x^2-2x^2+5x+4x-8-3[/tex]

[tex]\\ \sf\longmapsto x^2+9x-11[/tex]

Answer:

(3×2+5x-8)-(2×2-4x-3) = (6+5x-8)-(4-4x-3)

= 6+5x-8-4+4x+3

= -3+9x

Answer:

12 Twelfths (12/10)

Step-by-step explanation:

If the dinosaur ate 10 twelfths, then ate 2 twelfths, you need too add that up.

10/12 + 2/12 = 12/10.

The dinosaur ate 12/10 of a plant. (6/5 if needed to simplify)

Hope this helps!

Answer:

0/12

Step-by-step explanation:

The answer is 0/12. We know this because if there are twelve twelfths [12/12] of a plant and the stegosaurus eats ten twelfths [10/12] of a plant then it is 12 - 10 or the fraction form [12/12 - 10/12] then we subtract and we get the answer [2/12]. And then later it says the stegosaurus ate two twelfths [2/12] of a plant then we subtract 2 - 12 or [2/12 - 2/12] that would then equal 0/12.          

Answer:

It's C 20

4^2 + 8 divided by 2 = 20

Step-by-step explanation:

Answer:

Step-by-step explanation:

Whenever you add two number x and -x and it becomes 0 . IT is the identity property.

Ex:

-1/3 + 1/3 = 0

-1 + 1 = 0

-58 + 58 = 0

Answer:

Option (G)

Step-by-step explanation:

Let the length of the race = a miles

Since, Speed = [tex]\frac{\text{Distance}}{\text{Time}}[/tex]

Time taken to cover 'a' miles with the speed = 12 mph,

Time taken '[tex]t_1[/tex]' = [tex]\frac{a}{12}[/tex]

Time taken to cover 'a' miles with the speed = 11 mph,

Time taken '[tex]t_2[/tex]' = [tex]\frac{a}{11}[/tex]

Since the time taken by David to cover 'a' miles was 10 minutes Or [tex]\frac{1}{6}[/tex] hours more than the time he expected.

So, [tex]t_2=t_1+\frac{1}{6}[/tex]

[tex]\frac{a}{11}=\frac{a}{12}+\frac{1}{6}[/tex]

[tex]\frac{a}{11}-\frac{a}{12}=\frac{1}{6}[/tex]

[tex]\frac{12a-11a}{132}=\frac{1}{6}[/tex]

a = 22 mi

Therefore, distance of the race = 22 mi

Option (G) is the correct option.

Answer:

12/155

Step-by-step explanation:

Total number of cookies:

Probability of getting a peanut butter cookie at first attempt is 9 out of 31:

Probability of getting a peanut butter cookie at second attempt is 8 out of 30 as one already taken and the total number has changed as well:

Probability of getting 2 peanut butter cookies is the product of each probability we got above: