Complete the function to replace any period by an exclamation point. Ex: "Hello. I'm Miley. Nice to meet you." becomes:


"Hello! I'm Miley! Nice to meet you!"

#include

#include

using namespace std;

void MakeSentenceExcited(char* sentenceText) {


/* Your solution goes here */

}


int main() {

const int TEST_STR_SIZE = 50;

char testStr[TEST_STR_SIZE];

strcpy(testStr, "Hello. I'm Miley. Nice to meet you.");

MakeSentenceExcited(testStr);


cout << testStr << endl;


return 0;


}

Answer:

Which sentence best matches the context of the word reticent as it is used in the following example?

We could talk about anything for hours. However, the moment I brought up dating, he was extremely reticent about his personal life.

Explanation:

Which sentence best matches the context of the word reticent as it is used in the following example?

We could talk about anything for hours. However, the moment I brought up dating, he was extremely reticent about his personal life.

Answer:

91919.18182

Explanation:

Answer:

HOPE IT HELPS .

Answer:

The completed program is

def color_translator(color):

      if color == "red":

             hex_color = "#ff0000"

      elif color == "green":

             hex_color = "#00ff00"

      elif color == "blue":

             hex_color = "#0000ff"

      else:

             hex_color = "unknown"

      return hex_color

Explanation:

Since the parameter in the above function is color,

This variable will serve as the name of a color and it'll be used in the conditional statements to check if the name of color is any of red, green and blue;

And that is why we have

if color == "red":

elif color == "green":

elif color == "blue":

The variable used to hold the color codes, hex_color, will be returned at the end of the function and that's why we have

return hex_color

When the program is tested with print(color_translator("blue")) and others, it prints the desired output

Answer:

tput cup 10 15

Explanation:

tput is a command for command line environments in Linux distributions. tput can be used to manipulate color, text color, move the cursor and generally make the command line environment alot more readable and appealing to humans. The tput cup 10 15 is used to move the cursor 10 rows down and 15 characters right in the terminal

Answer:

Polymorphism

Explanation:

If we use polymorphism so we can apply the names that could be easy to remember for the methods' purpose.

The information regarding the polymorphism is as follows:

Therefore we can conclude that If we use polymorphism so we can apply the names that could be easy to remember for the methods' purpose.

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Explanation:

the perimeter of an aluminium sheet is 120 CM if its length is reduced by 10% and its breadth is increased by 20% the perimeter does not change find the measure of the length and the breadth of the sheet

Answer: Yes, clicking adds/popups like the one in the image could cause your computer/electronic to catch viruses/malware.

Explanation: The cause to this is when you click an ad/popup you're exposing yourself to a potential dangerous/visious site. You're unaware to where the popup could bring you, and for all we know it could bring us to a fake site for a download which is really a visious malware to be downloaded to your device.

Answer:

Top to down approach

Explanation:

Answer:

Using the terminal in linux OS to configure a static ip address, gateway and subnet mask.

Explanation:

-Enter the terminal in the linux environment and use the ifconfig eth0 or -a to bring up the main network interface and other network interfaces.

- for static network configuration, use;

  - ifconfig eth0 10.254.1.42  

  - ifconfig eth0 netmask 255.255.0.0

  - ifconfig eth0 broadcast 10.254.255.255

- and add a default gateway with;

 -  route add default gw 10.254.0.1  eth0.

- Now verify the settings with the ifconfig eth0 command.

bạn tìm ra cách giải chưa chỉ mình với

thanks b

The properties and origin of the Cartesian product as stated in the paragraph

is true, and the correct option is option;

a. True

The reason why the above option is correct is stated as follows;

In set theory, the Cartesian product of two number sets such as set A and set

B which can be denoted as lists of numbers is represented as A×B and is the

set of all ordered pair or points (a, b), with a being located in A and b located

in the set B, which can be expressed as follows;

[tex]\left[\begin{array}{c}A&x&y\\z\end{array}\right] \left[\begin{array}{ccc}B(1&2&3)\\\mathbf{(x, 1)&\mathbf{(x, 2)}&\mathbf{(x, 3)}\\\mathbf{(y, 1)}&\mathbf{(y, 2)}&\mathbf{(y, 3)}\\\mathbf{(z, 1)}&\mathbf{(z, 2)}&\mathbf{(z, 3)}\end{array}\right]}[/tex]

The name Cartesian product is derived from the name of the philosopher,

scientist and mathematician Rene Descartes due to the concept being

originated from his analytical geometry formulations

Therefore, the statement is true

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Answer:

Los riesgos de las nuevas tecnologías se multiplican a medida que nos hacemos dependientes de ellas. También lo hacen a medida que sustituyen a otras formas de contacto social más cercanas

Los riesgos de las nuevas tecnologías son grandes desconocidos. El mal uso de las redes sociales y de Internet en los ordenadores y en el teléfono móvil, entre otros factores, supone un peligro real para todos los estratos de población, pero en especial para los más jóvenes. Pensemos, ¿realmente somos conscientes de los riesgos que suponen las nuevas tecnologías? ¿Sabemos cómo utilizarlas para no ponernos en riesgo?

Cabe destacar que las denominadas nuevas tecnologías de la información y de la comunicación (TICs) son un distintivo de la época actual y se han convertido en herramientas esenciales en las diferentes áreas de la vida. Esto es, para el área académica, laboral, social, de ocio…

En la mayoría de los ámbitos están presentes las TICS, pues incluyen las diferentes herramientas con las que nos manejamos hoy en día: servicios de contacto electrónico (e-mails, servicios de mensajería instantánea, chats), los teléfonos móviles, tablets y ordenadores, las plataformas online de difusión de contenidos, las redes sociales, entre otros..

Explanation:

Answer:

Explanation:

Depending on the software that Raj was using to create his project he should first see if the software itself saved the project. Usually many software such as those included in the Microsoft Office Suite save the file automatically every 5 minutes or so in case of a power outage or abrupt closure of the file. If this is not the case he should try and do a system restore with the unlikely hope that it restores an older version of his project.

In a situation like this, it would be advisable for Raj to contact IT personnels and seek if the files could be retrieved.

These way, the files could be retrieved and avoid losing his work.

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Answer:

Data-driven Website

Explanation:

A Data-driven website is a type of website that is continually updated by its administrators so as to meet users' needs. It is opposed to a static website whose information remains the same and is never changed once uploaded.

The data-driven website is used in a platform where information has to be continually updated. An example is an online platform where people place orders for goods and services. There are usually changing prices and new goods continually uploaded. So, to keep the consumers updated, the administrators of such platforms would use a data-driven platform.

Answer:

gigahertz

Explanation:

The clock speed measures the number of cycles your CPU executes per second, measured in GHz (gigahertz)

[tex]\sf{}[/tex]

Explanation:

The speed of a computer is measured in gigahitrz

Answer:

function Rectangle(width=1, height= 1 ) {

    this.width= width;

    this.height= height;

    this.getArea= ( ) = > {return width * height};

    this.getPerimeter= ( ) = >{ return 2( height + width)};

}

var rectangleOne= new Rectangle(4, 40)

var rectangleTwo= new Rectangle(3.5, 35.9)

console.log(rectangleOne.width, rectangleOne.height, rectangleOne.getArea( ), rectangleOne.getPerimeter( ) )

console.log(rectangleTwo.width, rectangleTwo.height, rectangleTwo.getArea( ), rectangleTwo.getPerimeter( ) )

Explanation:

This is a Javascript class definition with a constructor specifying arguments with default values of one for both width and height, and the getArea and getPerimeter methods.

Answer:

Following are the code to this question:

f1=input('Input first file name: ')#defining f1 variable that input file 1

f2=input('Input second file name: ')#defining f2 variable that input file 2

file1=open(f1,'r')#defining file1 variable that opens first files by using open method  

file2=open(f2,'r')#defining file1 variable that opens second files by using open method  

d1=file1.readlines()#defining d1 variable that use readlines method to read first file data

d2=file2.readlines()#defining d2 variable that use readlines method to read second file data

if d1==d2:#defining if block that check file data

   print('Yes')#when value is matched it will print message yes  

   exit# use exit keyword for exit from if block

for j in range(0,min(len(d1),len(d2))):#defining for loop that stores the length of the file  

   if (d1[j]!=d2[j]):#defining if block that check value is not matched

       print('No')#print the message "NO"

       print("mismatch values: ",d1[j]," ",d2[j])#print file values

Output:

please find the attached file.

Explanation:

code description:

Answer:

first = input("enter first file name: ")

second = input("enter second file name: ")

file_one = open(first, 'r')

file_two = open(second, 'r')

if file_one.read() == file_two.read():

  print("Both files are the same")

else:

  print("Different files")

file_one.close()

file_two.close()

Answer: Find answers in the attachments

Explanation:

Answer:

Sequence of popped values: h,s,f.

State of stack (from top to bottom): m, d

Explanation:

Assuming that stack is  initially empty. Suppose that p contains the popped values. The state of the stack is where the top and bottom are pointing to in the stack. The top of the stack is that end of the stack where the new value is entered and existing values is removed. The sequence works as following:

push(d) -> enters d to the Stack

Stack:  

d ->top

push(h) -> enters h to the Stack

Stack:

h ->top

d ->bottom

pop() -> removes h from the Stack:

Stack:

d ->top

p: Suppose p contains popped values so first popped value entered to p is h

p = h

push(f) -> enters f to the Stack

Stack:

f ->top

d ->bottom

push(s) -> enters s to the Stack

Stack:

s ->top

f

d ->bottom

pop() -> removes s from the Stack:

Stack:

f ->top

d -> bottom

p = h, s

pop() -> removes f from the Stack:

Stack:

d ->top

p = h, s, f

push(m) -> enters m to the Stack:

Stack:

m ->top

d ->bottom

So looking at p the sequence of popped values is:

h, s, f

the final state of the stack:

m, d

end that is the top of the stack:

m

Answer:

Here is the corrected code: The screenshot of the program along with its output is attached. The comments are written with each line of the program for better understanding of the code.

CarRental.java

public class CarRental  {  //class name

//below are the data members name, zipcode, size, dFee, days and total

String name;  

int zipcode;

String size;

double dFee;

int days;

double total;  

public String getName()  {  //accessor method to get the name

return name; }

public int getZipcode()  { //accessor method to get the zipcode

return zipcode; }

public String getSize() {  //accessor method to get the size

return size; }

public int getDays() {  //accessor method to get the days

return days;  }

public CarRental(String size)  {  //constructor of CarRental class

if(size.charAt(0)=='e')  // checks if the first element (at 0th index) of size data member is e

     dFee = 29.99;  // sets the dFee to 29.99

  else if(size.charAt(0)=='m')  // checks if the first element (at 0th index) of size data member is m

     dFee = 38.99;  // sets the dFee to 38.99

  else   // checks if the first element (at 0th index) of size data member is f

     dFee =43.50;  // sets the dFee to 43.50

   }

public void calculateTotal(int days) {  //method calculateTotal of CarRental

total = dFee*days;  }  //computes the rental fee

public void print()   {  //method to display the total rental fee

System.out.println("Your rental total cost is: $" + total);  } }

Explanation:

LuxuryCarRental.java

import java.util.*;

public class LuxuryCarRental extends CarRental {  //class LuxuryCarRental that is derived from class CarRental

public LuxuryCarRental(String size, int days) {  // constructor of LuxuryCarRental

super(size);}   //used when a LuxuryCarRental class and CarRental  class has same data members i.e. size

public void calculateTotal() {  //overridden method

super.calculateTotal(days); // used because CarRental  and LuxuryCarRental class have same named method i.e.  calculateTotal

dFee = 79.99;  //sets the rental fee at $79.99 per day

total = dFee;  }  //sets total to rental fee value

public void print(){  //overridden method

   int chauffeur;  // to decide to include chauffeur

Scanner keyboard = new Scanner(System.in);  //used to take input from user

System.out.println("Do you want to add a chauffeur for $200? Enter 0 for"

+ " yes and 1 for no");  // prompts the user to respond to the option of including a chauffeur at $200 more per day

chauffeur = keyboard.nextInt();   //reads the input option of chauffeur from user

if(chauffeur==1)  //if user enters 1 which means user does not want to add a chauffeur

total = dFee;  //then set the value of dFee i.e.  $79.99  to total

else  //if user enters 0 which means user wants to add a chauffeur

total = dFee + 200;  //adds 200 to dFee value and assign the resultant value to total variable

System.out.println("Your rental total cost is: $" + total);  }  } //display the total rental fee

UseCarRental.java

import java.util.*;

public class UseCarRental{ //class name

public static void main(String[] args){ //start of main() function body

String name, size; // declare variables

int zipcode, days; //declare variables

Scanner keyboard = new Scanner(System.in); // to take input from user

System.out.println("Enter total days you plan on renting: "); //prompts user to enter total days of rent

days = keyboard.nextInt(); // reads value of days from user

System.out.println("Enter your name: "); //prompts user to enter name

name = keyboard.next(); //reads input name from user

System.out.println("Enter your billing zipcode: "); // prompts user to enter zipcode

zipcode = keyboard.nextInt(); //reads input zipcode from user

System.out.println("Enter the size of the car: "); // prompts user to enter the value of size

size = keyboard.next(); //reads input size from user

CarRental economy = new CarRental(size); //creates an object i.e. economy of class CarRental

economy.calculateTotal(days); //calls calculateTotal method of CarRental using instance economy

economy.print(); //calls print() method of CarRental using instance economy

LuxuryCarRental fullsize = new LuxuryCarRental(size, days);  //creates an object i.e. fullsize of class LuxuryCarRental

fullsize.calculateTotal();  //calls calculateTotal method of LuxuryCarRental using instance fullsize

fullsize.print(); }} //calls print() method of LuxuryCarRental using instance fullsize      

Answer:

The output is "a pineapple is larger than a blueberry ".

Explanation:

In the given  C language code Enum, typedef, and two methods "printfruit and compareFruit" is declared, that can be defined as follows:

558c::d367:7c8e:1216:0:66be

Answer:

The program is as follows:

import random

print("Rock\nPaper\nScissors")

points = int(input("Points to win the game: "))

player_point = 0; computer_point = 0

while player_point != points and computer_point != points:

   computer = random.choice(['Rock', 'Paper', 'Scissors'])

   player = input('Choose: ')

   if player == computer:

       print('A tie - Both players chose '+player)

   elif (player.lower() == "Rock".lower() and computer.lower() == "Scissors".lower()) or (player.lower() == "Paper".lower() and computer.lower() == "Rock".lower()) or (player == "Scissors" and computer.lower() == "Paper".lower()):

       print('Player won! '+player +' beats '+computer)

       player_point+=1

   else:

       print('Computer won! '+computer+' beats '+player)

       computer_point+=1

print("Player:",player_point)

print("Computer:",computer_point)

Explanation:

This imports the random module

import random

This prints the three possible selections

print("Rock\nPaper\nScissors")

This gets input for the number of points to win

points = int(input("Points to win the game: "))

This initializes the player and the computer point to 0

player_point = 0; computer_point = 0

The following loop is repeated until the player or the computer gets to the winning point

while player_point != points and computer_point != points:

The computer makes selection

   computer = random.choice(['Rock', 'Paper', 'Scissors'])

The player enters his selection

   player = input('Choose: ')

If both selections are the same, then there is a tie

   if player == computer:

       print('A tie - Both players chose '+player)

If otherwise, further comparison is made

   elif (player.lower() == "Rock".lower() and computer.lower() == "Scissors".lower()) or (player.lower() == "Paper".lower() and computer.lower() == "Rock".lower()) or (player == "Scissors" and computer.lower() == "Paper".lower()):

If the player wins, then the player's point is incremented by 1

       print('Player won! '+player +' beats '+computer)

       player_point+=1

If the computer wins, then the computer's point is incremented by 1

   else:

       print('Computer won! '+computer+' beats '+player)

       computer_point+=1

At the end of the game, the player's and the computer's points are printed

print("Player:",player_point)

print("Computer:",computer_point)

Answer:

The answer varies from person to person.

Explanation:

All kinds of people are using Word, so people would recognize if the answer if plagiarized. So, simply answer truthfully; no matter h1ow embarrasing.

The Microsoft word skills that I will need to improve upon the most is how to be faster when typing.

It should be noted that the Microsoft word skill that I am mostly confident in performing is the creation of word documents and text formatting.

Lastly, Microsoft word processing skills have affected my overall writing skills on the job as it has helped in improving my writing and grammar.

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Answer:

Here is the Python program:

import keyword  #module that contains list of keywords of python

filename = input("Enter Python source code filename: ") # prompts user to enter the filename of a source code

code = open(filename, "r") # opens the file in read mode

keywords = keyword.kwlist #extract list of all keywords of Python and stored it into keywords

dictionary = dict() #creates a dictionary to store each keyword and its number of occurrence in source code

for statement in code: # iterates through each line of the source code in the file

   statement = statement.strip() # removes the spaces in the statement of source code  

   words = statement.split(" ") #break each statement of the source code into a list of words by empty space separator

   for word in words:# iterates through each word/item of the words list  

       if word in keywords:#checks if word in the code is present in the keywords list of Python  

           if word in dictionary: #checks if word is already present in the dictionary

               dictionary[word] = dictionary[word] + 1 #if word is present in dictionary add one to the count of the existing word

           else: #if word is not already present in the dictionary  

               dictionary[word] = 1 #add the word to the dictionary and set the count of word to 1

for key in list(dictionary.keys()): #iterates through each word in the list of all keys in dictionary  

   print(key, ":", dictionary[key])# prints keyword: occurrences in key:value format of dict

Explanation:

The program is well explained in the comments attached with each line of the program.  

The program prompts the user to enter the name of the file that contains the Python source code. Then the file is opened in read mode using open() method.

Then the keyword.kwlist statement contains the list of all keywords of Python. These are stored in keywords.

Then a dictionary is created which is used to store the words from the source code that are the keywords along with their number of occurrences in the file.

Then source code is split into the lines (statements) and the first for loop iterates through each line and removes the spaces in the statement of source code .

Then the lines are split into a list of words using split() method. The second for loop is used to iterate through each word in the list of words of the source code. Now each word is matched with the list of keywords of Python that is stored in keywords. If a word in the source code of the file is present in the keywords then that word is added to the dictionary and the count of that word is set to 1. If the word is already present in the dictionary. For example if there are 3 "import" keywords in the source code and if 1 of the import keywords is already in the dictionary. So when the second import keyword is found, then the count of that keyword is increased by 1 so that becomes 2.

Then the last loop is used to print each word of the Python that is a keyword along with its number of occurrences in the file.

The program and its output is attached in a screenshot. I have used this program as source code file.

Answer:

micro processor

Explanation:

Answer:

The sternum or breastbone is a long flat bone located in the central part of the chest.

The sternum or breastbone is a long flat bone located in the central part of the chest.

In the middle of the chest, there is a long, flat bone known as the sternum or breastbone. It forms the front of the rib cage and is joined to the ribs by cartilage, assisting in the protection of the heart, lungs, and major blood arteries from harm. It is one of the longest and largest flat bones in the body, somewhat resembling a necktie. The manubrium, body, and xiphoid process are its three regions.

Therefore, the sternum or breastbone is a long flat bone located in the central part of the chest.

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#SPJ2

Answer:

python is probably the best is you are a begginer

java and C++ are good too

Answer:

Following are the algorithm to this question:

Explanation:

In the RSA algorithm can be defined as follows:  

In this algorithm, we select two separate prime numbers that are the "P and Q", To protection purposes, both p and q combines are supposed to become dynamically chosen but must be similar in scale but 'unique in length' so render it easier to influence. Its value can be found by the main analysis effectively.  

Computing N = PQ.  

In this, N can be used for key pair, that is public and private together as the unit and the Length was its key length, normally is spoken bits. Measure,

[tex]\lambda (N) = \ lcm( \lambda (P), \lambda (Q)) = \ lcm(P- 1, Q - 1)[/tex]  where [tex]\lambda[/tex] is the total function of Carmichaels. It is a privately held value. Selecting the integer E to be relatively prime from [tex]1<E < \lambda (N)[/tex]and [tex]gcd(E, \lambda (N) ) = 1;[/tex] that is [tex]E \ \ and \ \ \lambda (N)[/tex].  D was its complex number equivalent to E (modulo [tex]\lambda (N)[/tex] ); that is d was its design multiplicative equivalent of E-1.  

It's more evident as a fix for d provided of DE ≡ 1 (modulo [tex]\lambda (N)[/tex] ).E with an automatic warning latitude or little mass of bigging contribute most frequently to 216 + 1 = 65,537 more qualified encrypted data.

In some situations it's was shown that far lower E values (such as 3) are less stable.  

E is eligible as a supporter of the public key.  

D is retained as the personal supporter of its key.  

Its digital signature was its module N and the assistance for the community (or authentication). Its secret key includes that modulus N and coded (or decoding) sponsor D, that must be kept private. P, Q, and [tex]\lambda (N)[/tex] will also be confined as they can be used in measuring D. The Euler totient operates [tex]\varphi (N) = (P-1)(Q - 1)[/tex] however, could even, as mentioned throughout the initial RSA paper, have been used to compute the private exponent D rather than λ(N).

It applies because [tex]\varphi (N)[/tex], which can always be split into  [tex]\lambda (N)[/tex], and thus any D satisfying DE ≡ 1, it can also satisfy (mod  [tex]\lambda (N)[/tex]). It works because [tex]\varphi (N)[/tex], will always be divided by [tex]\varphi (N)[/tex],. That d issue, in this case, measurement provides a result which is larger than necessary (i.e. D >   [tex]\lambda (N)[/tex] ) for time - to - time). Many RSA frameworks assume notation are generated either by methodology, however, some concepts like fips, 186-4, may demand that D<   [tex]\lambda (N)[/tex]. if they use a private follower D, rather than by streamlined decoding method mostly based on a china rest theorem. Every sensitive "over-sized" exponential which does not cooperate may always be reduced to a shorter corresponding exponential by modulo  [tex]\lambda (N)[/tex].

As there are common threads (P− 1) and (Q – 1) which are present throughout the [tex]N-1 = PQ-1 = (P -1)(Q - 1)+ (P-1) + (Q- 1))[/tex], it's also possible, if there are any, for all the common factors [tex](P -1) \ \ \ and \ \ (Q - 1)[/tex]to become very small, if necessary.  

Indication: Its original writers of RSA articles conduct their main age range by choosing E as a modular D-reverse (module [tex]\varphi (N)[/tex]) multiplying. Because a low value (e.g. 65,537) is beneficial for E to improve the testing purpose, existing RSA implementation, such as PKCS#1, rather use E and compute D.