Consider the following two questions designed to assess quantitative literacy: a. What is 15% of 1000? b. A store is offering a 1596 off sale on all TVs. The most popular television is normally priced at $1000. How much money would a customer save on the television during this sale? Suppose the first question is asked of 200 randomly selected college students, with 165 answering correctly; the second one is asked of a different random sample of 200 college students, resulting in 142 correct responses. Carry out a test of hypotheses at significance level 0.05 to decide if the true proportion of correct responses to the question without context exceeds that for the one with context. (Use p1 for the true proportion students who answered the question without context correctly and p2 for the true proportion of students who answered the question with context correctly.) Carry out a test of hypotheses at significance level 0.05 to decide if the true proportion of correct responses to the question without context exceeds that for the one with context.

Answers

Answer 1

Answer:

The calculated value of z= 2.7225 falls in the critical region therefore we reject the null hypothesis and conclude that at the  5% significance level, true proportion of correct responses to the question without context exceeds that for the one with context.

Step-by-step explanation:

a: 15 % of 1000= 150

b. 15.96 % of $ 1000= $ 159.6

The customer would pay = $ 1000- $ 159.6= $ 840.4 and save $ 159.6

Formulate the hypotheses as

H0: p1= p2   true proportion of correct responses to the question without context is equal that for the one with context.

Ha : p1≠ p2

We choose the significance level ∝= 0.05

The critical value for two tailed test at alpha=0.05 is ± 1.96

The test statistic is

Z = p1-p2/ √pq (1/n1+ 1/n2)

p1= true proportion students who answered the question without context correctly  = 165/200=0.825

p2=  true proportion of students who answered the question with context correctly = 142/200= 0.71

p = an estimate of the common rate on the assumption that the two proportions are same.

p = n1p1+ n2p2/ n1 + n2

p =200 (0.825) + 200 (0.71) / 400

p=  165+ 142/400= 307 /400 =0.7675

now q = 1-p= 1- 0.7675= 0.2325

Thus

z= 0.825- 0.71/ √0.7675*0.2325( 1/200 + 1/200)

z= 0.115/√ 0.17844( 2/200)

z= 0.115/0.04224

z= 2.7225

The calculated value of z falls in the critical region therefore we reject the null hypothesis and conclude that at the  5% significance level, true proportion of correct responses to the question without context exceeds that for the one with context.


Related Questions



A family are going away for the weekend. They look at a road map to see where their hotel is.
The scale used is 1:250,000
The distance to their hotel measures 8.5 cm on the map.
What is the actual distance?
km

Answers

Answer:

106.25km

Step-by-step explanation:

8.5cm = 0.000085km

map:real life

1:1250000

0.000085km : 0.000085km * 1250000 = 106.25km

The ratio of frogs to toads was 3 to 7. If there were 1280 frogs and toads in all, how many were frogs?

Answers

Answer:

348 frogs

Step-by-step explanation:

ratio = 3:7

total of ratio = 10

frogs = 3/10 × 1280 = 348 frogs

Answer:

let the ratio be 3x and 7x.

3x+7x=1280

10x=1280

x=128

Now

frogs =3x=3*128=384

toads =7x=7*128=896

Find two positive numbers satisfying the given requirements. The sum of the first and twice the second is 400 and the product is a maximum.

Answers

Answer:

100 and 200

Step-by-step explanation:

Let the first number be 'a' and the second number be 'b'. If the sum of the first and twice the second is 400 then;

a+2b = 400 ....

From the equation above, a = 400 - 2b ... 2

If the product of the numbers is a maximum then;

ab = (400-2b)b

let f(b) be the product of the function.

f(b) = (400-2b)b

f(b) = 400b-2b²

For the product to be at the maximum then f'(b) must be equal to zero i.e f'(b) = 0

f'(b)= 400-4b = 0

400-4b = 0

400 = 4b

b = 400/4

b = 100

Substituting b= 100 into the equation a = 400 - 2b to get a;

a = 400 - 2(100)

a = 400 - 200

a = 200

The two positive integers are 100 and 200.

What is the range of the function in the graph?

Answers

Answer:

b=70

Step-by-step explanation:

The range is the value that the output takes

In this graph, the output is constant at 70

The output value is b

b=70

Solve for x

Answer choices:
4
5
8
3
2

Answers

opposite angles are equal

[tex]\\ \sf\longmapsto 13x+19=84[/tex]

[tex]\\ \sf\longmapsto 13x=84-19[/tex]

[tex]\\ \sf\longmapsto 13x=65[/tex]

[tex]\\ \sf\longmapsto x=\dfrac{65}{13}[/tex]

[tex]\\ \sf\longmapsto x=5[/tex]

Answer:

[tex]\boxed {\boxed {\sf x=5}}[/tex]

Step-by-step explanation:

We are asked to solve for x.

We are given a pair of intersecting lines and 2 angles measuring (13x+19)° and 84°. The angles are opposite each other, so they are vertical angles. This means they are congruent or have the same angle measure.

Since the 2 angles are congruent, we can set them equal to each other.

[tex](13x+19)=84[/tex]

Solve for x by isolating the variable. This is done by performing inverse operations.

19 is being added to 13x. The inverse operation of addition is subtraction. Subtract 19 from both sides of the equation.

[tex]13x+19-19= 84 -19[/tex]

[tex]13x= 84 -19[/tex]

[tex]13x=65[/tex]

x is being multiplied by 13. The inverse operation of multiplication is division. Divide both sides by 13.

[tex]\frac {13x}{13}= \frac{65}{13}[/tex]

[tex]x= \frac{65}{13}[/tex]

[tex]x= 5[/tex]

For this pair of vertical angles, x is equal to 5.

how do you calculate the population mean

Answers

Add up all the numbers then divide how many ever digits there are

A speedboat moves at a rate of 25 km/hr in still water. How long will it take
someone to ride the boat 87 km downstream if the river's current moves at a rate of
4 km/hr?

Answers

Answer:

3 hours

Step-by-step explanation:

Downstream, the speeds add up:

25 + 4 = 29 km/h

It will take:

87/29= 3 hrs

To ride 87 km.

Need Help
Please Show Work​

Answers

Answer:

-36

Step-by-step explanation:

3*12=36

she is going down (negative) so, it is -36

not sure if this is what you are asking for, if not try this

0-12-12-12=-36

HELP PLEASE!

The length of a rectangle is 2V5. The width of the same rectangle is 5V5. Find the perimeter and area of the rectangle.

Answers

Answers:

[tex]\text{Perimeter} = 14\sqrt{5}\\\\\text{Area} = 50\\\\[/tex]

=======================================================

Work Shown:

[tex]L = 2\sqrt{5} = \text{length}[/tex]

[tex]W = 5\sqrt{5} = \text{width}[/tex]

P = perimeter

[tex]P = 2*(L+W)\\\\P = 2*(2\sqrt{5}+5\sqrt{5})\\\\P = 2*(7\sqrt{5})\\\\P = 14\sqrt{5}\\\\[/tex]

-------------

A = area

[tex]A = L*W\\\\A = (2\sqrt{5})*(5\sqrt{5})\\\\A = (2*5)(\sqrt{5}*\sqrt{5})\\\\A = 10\sqrt{5*5}\\\\A = 10\sqrt{25}\\\\A = 10*5\\\\A = 50\\\\[/tex]

Area=5rad5 times 2rad5 equals 50 Bc rad 5 times rad 5 is rad 25 or 5 and 2 timers 5 is ten so now it is 5 times 10=50

The quadrilaterals JKLM and PQRS are similar. Find the length x of SP

Answers

Answer:

4.8

Step-by-step explanation:

The scale factor is (3.6)/3=1.2. Hence x/4=1.2, x=4.8

You are to manufacture a rectangular box with 3 dimensions x, y and z, and volume v=8000. Find the dimensions which minimize the surface area of this box.

Answers

Answer:

20 by 20 by 20

Step-by-step explanation:

Let the total surface of the rectangular box be expressed as S = 2xy + 2yz + 2xz

x is the length of the box

y is the width and

z is the height of the box.

S = 2xy + 2yz + 2xz ... 1

Given the volume V = xyz = 8000 ... 2

From equation 2;

z = 8000/xy

Substituting into equation 1;

S = 2xy + 2y(8000/xy)+ 2x(8000/xy)

S = 2xy+16000/x+16000/y

Differentiating the resulting equation with respect to x and y will give;

dS/dx = 2y + (-16000x⁻²)

dS/dx = 2y - 16000/x²

Similarly,

dS/dy = 2x  + (-160000y⁻²)

dS/dy = 2x - 16000/y²

Note that at the turning point, ds/dx = 0 and ds/dy = 0, hence;

2y - 16000/x² = 0 and 2x - 16000/y² = 0

2y = 16000/x² and 2x = 16000/y²

2y = 16000/(8000/y²)²

2y = 16000×y⁴/64,000,000

2y = y⁴/4000

y³ = 8000

y =³√8000

y = 20

Given 2x = 16000/y²

2x = 16000/20²

2x = 16000/400

2x = 40

x = 20

Since Volume of the box is V = xyz

8000 = 20(20)z

8000 = 400z

z = 8000/400

z = 20

Hence, the dimensions which minimize the surface area of this box is 20 by 20 by 20.

The dimensions which minimize the surface area of this box is 20 *20* 20. This can be calculated by using surface area and volumes.

The calculation for total surface area:

Let the total surface of the rectangular box be expressed as:

S = 2xy + 2yz + 2xz

where,

x is the length of the box

y is the width and

z is the height of the box.

S = 2xy + 2yz + 2xz .................(1)

Given:

Volume V = xyz = 8000 .............(2)

From equation 2;

z = 8000/xy

Substituting into equation 1;

S = 2xy + 2y(8000/xy)+ 2x(8000/xy)

S = 2xy+16000/x+16000/y

Differentiating the resulting equation with respect to x and y will give;

dS/dx = 2y + (-16000x⁻²)

dS/dx = 2y - 16000/x²

Similarly,

dS/dy = 2x  + (-160000y⁻²)

dS/dy = 2x - 16000/y²

Note that at the turning point, ds/dx = 0 and ds/dy = 0, hence;

2y - 16000/x² = 0 and 2x - 16000/y² = 0

2y = 16000/x² and 2x = 16000/y²

2y = 16000/(8000/y²)²

2y = 16000×y⁴/64,000,000

2y = y⁴/4000

y³ = 8000

y =³√8000

y = 20

Given 2x = 16000/y²

2x = 16000/20²

2x = 16000/400

2x = 40

x = 20

Since, Volume of the box is V = xyz

8000 = 20(20)z

8000 = 400z

z = 8000/400

z = 20

Hence, the dimensions which minimize the surface area of this box is 20*20*20.

Find more information about Surface area here:

brainly.com/question/1090412


a) which function has the graph with the greatest y intercept?
b) which functions have graphs with slopes less than -3
c) which functions graph is the least steep?​

Answers

Answer:

a =4,b=2, c=3

Step-by-step explanation:

Make a substitution to express the integrand as a rational function and then evaluate the integral. (Remember to use absolute values where appropriate. Use C for the constant of integration.)
2 sec^2(t)/tan^2(t) + 14 tan(t) + 48 dt

Answers

Complete the square in the denominator to get

tan²(t ) + 14 tan(t ) + 48 = tan²(t ) + 14 tan(t ) + 49 - 1

… = (tan(t ) + 7)² - 1

Substitute u = tan(t ) + 7 and du = sec²(t ) dt. Then the integral becomes

[tex]\displaystyle \int \frac{2\sec^2(t)}{\tan^2(t)+14\tan(t)+48} \,\mathrm dt = 2 \int \frac{\mathrm du}{u^2-1}[/tex]

Separate the integrand into partial fractions:

[tex]\dfrac1{u^2-1} = \dfrac12 \left(\dfrac1{u-1}-\dfrac1{u+1}\right)[/tex]

Then we get

[tex]\displaystyle \int \frac{2\sec^2(t)}{\tan^2(t)+14\tan(t)+48} \,\mathrm dt =  \int \left(\frac1{u-1}-\frac1{u+1}\right)\,\mathrm du \\\\ =\ln|u-1|-\ln|u+1| + C \\\\ = \ln\left|\frac{u-1}{u+1}\right|+C \\\\ = \boxed{\ln\left|\frac{\tan(t)+6}{\tan(t)+8}\right|+C}[/tex]

trig..experts...help! Will give brainly!

Answers

Answer:

Step-by-step explanation:

189² = 215² + 123² - 2(215)(123)cos x°

35,721 = 46,225 + 15,129 - 52,890 cos x°

35,721 = 61,354 - 52,890 cos x°

52,890 (cos x° ) = 25,633

cos x° = 25,633 ÷ 52,890 ≈ 0.4846

x° ≈ 61.01°

PLEASE HELP! You do not have to answer all questions but can someone explain to me on where I am even suppose to begin? I don't even know how to answer a single one of these questions.

Answers

Step-by-step explanation:

For problems 1 through 15, evaluate the function at the given x value.

1. f(5) = 2(5) − 1 = 9

2. f(3) = 3² − 3(3) − 1 = -1

3. f(0) = 2(0) + 5 = 5

So on and so forth.

Then, match each answer with the corresponding letter.

The answer to #1 was 9.  9 corresponds to the letter A.

The answer to #2 was -1.  -1 corresponds to the letter C.

The answer to #3 was 5.  5 corresponds to the letter P.

Finally, write each letter with its corresponding problem number.

So everywhere you see a 1, write A.

Everywhere you see a 2, write C.

Everywhere you see a 3, write P.

Continue until every blank has a letter and the problem is solved.

Answer:

For problems 1 through 15, evaluate the function at the given x value.

1. f(5) = 2(5) − 1 = 9

2. f(3) = 3² − 3(3) − 1 = -1

3. f(0) = 2(0) + 5 = 5

So on and so forth.

Step-by-step explanation:

Hi! Can you help me answer this?

Answers

Answer:

[tex]C'(x)=-\frac{148}{x^2}[/tex]

[tex]R'(x)=-0.06[/tex]

Step-by-step explanation:

Marginal average Cost function:

[tex]\frac{d}{dx}(\frac{148+6.3x}{x})=-\frac{148}{x^2}[/tex]

Marginal average Revenue function:

[tex]\frac{d}{dx}(\frac{3x-0.06x}{x})=-0.06[/tex]

Answer:

Step-by-step explanation:

yess

what is 11.3 minus 2.564

Answers

the answer would be 8.736

Quadrilateral RSTV is dilated with respect to the origin by a scale factor of 1.5 to produce quadrilateral R'S'T'V' . Vertex R is located at (6, -9). Which ordered pair represents R' after the dilation?

Answers

Answer:

(9, -13.5)

Step-by-step explanation:

It's given in the question that a quadrilateral RSTV is dilated with a scale factor of 1.5 with respect to the origin to form R'S'T'V'.

Rule for dilation is,

(x, y) → (kx, ky)

where 'k' is the scale factor.

If vertex R of the quadrilateral is (6, -9),

By the given rule of dilation,

R(6, 9) → R'[(1.5 × 6), -(1.5 × 9)]

           → R'(9, -13.5)

Therefore, Option given in bottom right (9, -13.5) will be the answer.

5 times 3 times 2

show work

Answers

Answer:

30

Step-by-step explanation:

5x3=p

px2 = a

5x3 = 15 x 2 = 30

Answer:

5 times 3 times 2=30

Step-by-step explanation:

5×3=15×2=30

Simplify: 41a-2b + 3c) + 11a

Answers

Step-by-step explanation:

41a+11a-2b+3c

52a-2b+3c

Step-by-step explanation:

(41a-2b+3c) +11a

open the bracket

41a-2b+3c+11a

collect like terms

41a+11a-2b+3c

52a-5bc

so final answer is 52a-5bc

because they are not like terms they are unlike terms

The image below is a triangle drawn inside a circle with center O:

A triangle is shown inscribed inside a circle. The leg of the triangle labeled 8 inches passes through the center of the circle, O. The other two legs are labeled as 4 inches and 5 inches.

Which of the following expressions shows the area, in square inches, of the circle?

(π = 3.14)

Answers

Answer:

26

Step-by-step explanation:

Answer: 3.14 · 4²

Step-by-step explanation:

A = π · r²

A = 3.14 · 4²

Hope this helps!

Find the surface area of the figure and round your answer to the nearest tenth if necessary

Answers

Answer:

351.86

Step-by-step explanation:

the formula is

surface area=2πrh+2πr²

r= radius

h=height

Type the correct answer in each box. Use numerals instead of words,
The domain of this function is {-12, -6, 3, 15).
y = -32 +7
Complete the table based on the given domain.
y
6
0
5
15
15
Reset
Next

Answers

Answer:

x = -6,3,15,-12; y = 11,5,-3,15

Step-by-step explanation:

Domain is the x value, so plugged in the x values into the equation and got the y values or range.

Answer:

 x:  y:

-6  11

3       5

15 -3

-12    15

write each equation explicitly in terms of x. then indicate whether the equation is a function.
y^2-x^2+1=50

Answers

Answer:

Hello,

Step-by-step explanation:

[tex]y^2-x^2+1=50\\y^2=x^2+49\\2\ functions \ :\\\\y=\sqrt{x^2+49} \\\\or\\\\y=-\sqrt{x^2+49} \\[/tex]

Using function concepts, it is found that:

The explicit equation in terms of x is given by: [tex]y = \pm \sqrt{x^2 + 49}[/tex]The equation is not a function, as there are multiple outputs for a single input.

----------------------

The expression is given by:

[tex]y^2 - x^2 + 1 = 50[/tex]

In terms of x, the equation is given by:

[tex]y^2 = 50 + x^2 - 1[/tex]

[tex]y^2 = x^2 + 49[/tex]

[tex]y = \pm \sqrt{x^2 + 49}[/tex]

----------------------

An equation is a function if for each value of the input, there is only one output.

Testing the input x = 0:

[tex]y = \pm \sqrt{0^2 + 49}[/tex]

[tex]y = \pm \sqrt{49}[/tex]

[tex]y = \pm 7[/tex]

Two output values for one input, thus, it is not a function.

A similar problem is given at https://brainly.com/question/24603090

A fair die is tossed once, what is the probability of obtaining neither 5 nor 2?​

Answers

Answer:

4/6 or 66.666...%

Step-by-step explanation:

If you want to find the probability of obtaining neither a 5 nor a 2 you find how many times they occur and add them together in this case 5 occurs once and 2 also occurs once out of 6 numbers so 1/6 + 1/6 equals 2/6, you now know that 4/6 of them won't be a 5 nor a 2 and because it is a fair die the likelihood of it falling on a number is the same for all sides so the answer is 4/6 or 66.67%.

Which of the following represents the largest number?
A. 1.75 * 10^6
B .1.25 * 10^6
C. 2.75 * 10^5
D. 3.82 * 10^5

Answers

Answer:

A

Step-by-step explanation:

A 1.75 * 10^6 = 1750000

B  1.25 * 10^6 = 1250000

C 2.75*10^5  = 275000

D 3.82*10^5 = 82000

option A (1.75 * 10⁶) represents the largest number among the given options.

To determine which of the given numbers represents the largest number, we can compare the exponents of 10 in each option.

A. 1.75 * 10⁶

B. 1.25 * 10⁶

C. 2.75 * 10⁵

D. 3.82 * 10⁵

Comparing the exponents:

A: 10⁶

B: 10⁶

C: 10⁵

D: 10⁵

Since both options A and B have an exponent of 10⁶, we need to compare the coefficients.

1.75 is greater than 1.25, so option A (1.75 * 10⁶) represents the largest number among the given options.

Therefore, the answer is A. 1.75 * 10⁶.

Learn more about exponents here

https://brainly.com/question/5497425

#SPJ2

Reduce 24/64 to its lowest terms.

Answers

Answer:

[tex]\frac{3}{8}[/tex]

Step-by-step explanation:

To simplify the fraction [tex]\frac{24}{64}[/tex], we need to find its greatest common factor.

Both 24 and 64 are divisible by 2, but that's not the biggest.

Both 24 and 64 are divisible by 4, but that's not the biggest either.

Both 24 and 64 are divisible by 8, and that's the highest we can go.

So:

[tex]\frac{24\div8}{64\div8} = \frac{3}{8}[/tex].

Hope this helped!

Assume you are selling pizzas at $ 8 per pizza. Your fixed costs (rent, salaries, and utilities) are $4,438/month. The food costs and other variable costs are 40 percent of the selling price. What is your break-even point in units if you need to make 25% target return on the sales revenue? (enter only the value)

Answers

A company breaks even for a given period when sales revenue and costs incurred during that period are equal. Thus the break-even point is that level of operations at which a company realizes no net income or loss.

A company may express a break-even point in dollars of sales revenue or number of units produced or sold. No matter how a company expresses its break-even point, it is still the point of zero income or loss.

In order to grasp the concept of breakeven, it’s important to understand that all costs are not created equal: Some are fixed, and some are variable. Fixed Costs are expenses that are not dependent on the amount of goods or services produced by the business. They are things such as salaries or rents paid per month. If you own a car, then your car payment and insurance premiums are fixed costs because you pay them every month whether you drive your car or not. Variable Costs are volume related and are paid per quantity or unit produced. For your car, your variable costs are things like gas, maintenance, or tires because you only incur these costs when you drive your car. The more miles you drive, the more your gas expenses go up—such costs vary with the level of activity.

Before we turn to the calculation of the break-even point, it’s also important to understand contribution margin.

Solve the equation for x. √x+5-3=4​

Answers

answer: x = 14

Explanation:

Sqrt x + 5 - 3 = 4
Sqrt x + 2 = 4

Square both sides
x + 2 = 4^2
x + 2 = 16
x = 16 - 2
x = 14

Check:

Sqrt 14 + 5 - 3 = 4
Sqrt 16 = 4
4 = 4

Answer:

x=4

Step-by-step explanation:

To solve for x, we must get x by itself on one side of the equation.

[tex]\sqrt{x} +5-3=4[/tex]

First, we can combine like terms on the left side. Subtract 3 from 5.  

[tex]\sqrt{x} +(5-3)=4[/tex]

[tex]\sqrt{x} +2=4[/tex]

2 is being added on to the square root of x. The inverse of addition is subtraction. Subtract 2 from both sides of the equation.

[tex]\sqrt{x} +2-2=4-2[/tex]

[tex]\sqrt{x} = 4-2[/tex]

[tex]\sqrt{x} =2[/tex]

The square root of x is being taken. The inverse of a square root is a square. Square both sides of the equation.

[tex](\sqrt{x} )^{2} =2^2[/tex]

[tex]x=2^2[/tex]

Evaluate the exponent.

2^2= 2*2 =4

[tex]x=4[/tex]

Let's check our solution. Plug 4 in for x and solve.

[tex]\sqrt{x} +5-3=4[/tex]

[tex]\sqrt{4} +5-3=4[/tex]

[tex]2+5-3=4[/tex]

[tex]7-3=4[/tex]

[tex]4=4[/tex]

Our solution checks out, so we know x=4 is correct.

) A jar contains 4 white balls and 6 black balls. A ball is chosen at random, and its color noted. The ball is then replaced, along with 3 more balls of the same color. Then, another ball is drawn at random from the jar. (a) Find the chance that the second ball drawn is white. (b) Given that the second ball drawn is white, what is the probability that the first ball drawn is black

Answers

Answer:

The answer is "[tex]\bold{\frac{2}{5}\ \ and \ \ \frac{6}{13}}[/tex]".

Step-by-step explanation:

You have 4/10 opportunities to choose a white ball, and there'll be 7 white balls and 6 black balls out of 13, and so the second time they choose a white one is 7/13, as well as the second time they choose a black, 6/13. people will also have a 4/10 chance.  

There are 6/10 chances which users pick its black ball and 4 white balls would still be picked, but 9 black balls and out 13 balls and thus, its second and third time you select the white one is 4/13 but you are likely to pick a black for the second time is 9/13.  

Taking the diagram of the next tree. The very first draw is marked with a and the second draw is marked with b.

[tex]\to P(a) = \frac{4}{10}\ \ \ \ \ \ \ \ \ P(b) = \frac{6}{10}\\\\\to P(\frac{a2}{a1}) = \frac{7}{13} \ \ \ \ \ \ \ \ \ \ P(\frac{a}{b}) = \frac{4}{13}\\\\\to P(\frac{b2}{a1}) = \frac{6}{13} \ \ \ \ \ \ \ \ \ \ P(\frac{b2}{b1}) = \frac{9}{13}[/tex]

Calculating the second drawn ball is white:

[tex]\to P(b2)=P(a)P(\frac{a2}{b1})+P(b)P(\frac{a}{b})\\[/tex]

              [tex]=\frac{4}{10}\frac{7}{13}+\frac{6}{10}\frac{4}{13}\\\\=\frac{28}{130}+\frac{24}{130}\\\\=\frac{28+24}{130}\\\\=\frac{52}{130}\\\\=\frac{2}{5}\\\\[/tex]

In point b:

[tex]\to P(\frac{b}{a1})= \frac{P(B)P(\frac{a}{b})}{P(a)P(\frac{a2}{b1})+P(b)P(\frac{a}{b})\\}[/tex]

              [tex]=\frac{\frac{6}{10} \frac{4}{13}}{\frac{52}{130}}\\\\=\frac{\frac{24}{130}}{\frac{52}{130}}\\\\=\frac{24}{130} \times \frac{130}{52}\\\\=\frac{24}{52}\\\\=\frac{6}{13}\\[/tex]

Other Questions
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