Convert 13pi/6 to a degree measure

A=390
B=2450.44
C=30
D=780

Step-by-step explanation:

L*b=1800m^2

L=2b

2b*b=1800

2b^2=1800

b^2=900

b=30m

L=2*30

=60m

Perimeter=2(l+b)

=2(60+30)

=2*90

=180m

Answer:

'y', "addition", '9'.

Step-by-step explanation:

The variable is an unknown value in an algebraic equation or expression. It is represented by a letter.

'y' would be the variable in the given equation.

The operation in the expression is addition. The '+' sign represents addition, which means 9 and 'y' would be added together to get the sum.

Constants are terms in a expression or equation that contains no variables. This means that constants are only numbers.

'9' would be the given constant in the expression.

Hope this helps.

Answer:

y

+

9

Step-by-step explanation:

Answer:

x=22.5

Step-by-step explanation:

(there's a correction in the question since the I did this one before, so I know)

(cos²x-sin²x)²-sin4x+sin²2x=0

or, cos²2x-sin4x+sin²2x=0

or, 1-sin4x=0

or, sin4x=1

or, 4x=90

or, x=22.5

Answer:

1

Step-by-step explanation:

√(4-3²+(3-3)²

√1¹+0

√1

1

Answer:

Step-by-step explanation:

Since x- coordinates are same, the distance is the difference of the y-coordinates:

Answer:

Step-by-step explanation:

Answer:

i) where the digits can repeat

1. 30

2. 50

3. 33

4. 55

5. 35

6. 53

ii) where the digits cannot be repeated

1. 30

2. 50

3. 35

4. 53

Answer:

98

Step-by-step explanation:

So we have the two functions:

[tex]g(x)=-2x-2\text{ and } r(x)=x^2-2[/tex]

And we want to find the value of r(g(4)).

To do so, first find the value of g(4):

[tex]g(x)=-2x-2\\g(4)=-2(4)-2\\[/tex]

Multiply:

[tex]g(4)=(-8)-2[/tex]

Subtract:

[tex]g(4)=-10[/tex]

Now, substitute this into r(g(4)):

[tex]r(g(4))\\=r(-10)[/tex]

And substitute this value into r(x):

[tex]r(-10)=(-10)^2-2[/tex]

Square:

[tex]r(-10)=100-2[/tex]

Subtract:

[tex]r(-10)=98[/tex]

Therefore:

[tex]r(-10)=r(g(4))=98[/tex]

Answer:

Step-by-step explanation:

Answer:

-12°C

Step-by-step explanation:

6AM = 2°C

8AM= -2°C

10AM= -6°C

12AM= -8°C

2PM= -12°C

the temperature in degrees Celsius at 2:00 pm would be -14°C.

To find the temperature in degrees Celsius at 2:00 pm, we need to determine the number of hours that have passed from 6:00 am to 2:00 pm, and then calculate the temperature decrease accordingly.

From 6:00 am to 2:00 pm, a total of 8 hours have passed (6 hours from 6:00 am to 12:00 pm, and 2 hours from 12:00 pm to 2:00 pm).

Given that the temperature drops 2 degrees Celsius each hour, we can multiply the number of hours (8) by the rate of temperature decrease (2 degrees/hour):

Temperature decrease = 8 hours × 2 degrees/hour = 16 degrees

Starting with a temperature of 2°C at 6:00 am, if the temperature drops 16 degrees Celsius over 8 hours, we can subtract 16 from the initial temperature:

Temperature at 2:00 pm = 2°C - 16°C = -14°C

Therefore, the temperature in degrees Celsius at 2:00 pm would be -14°C.

Learn more about temperature here

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Answer:

30%

Step-by-step explanation:

There are 10 possible combinations of sticks that can be drawn from a group of 5 strings

5C3 = (5*4*3)/(3*2)   = 10 combinations, which are

1,3,5 ; 1,3,7 ; 1,3,9 ; 1,5,7 ; 1,5,9 ; 1,7,9 ; 3,5,7 ; 3,5,9 ; 3,7,9 ; 5,7,9

to make a triangle, the sum of any two sides must be greater than the third side and if you look at the possible combinations there are only three cases where that is true

so the probability for drawing three sticks that would make a triangle is 3/10 or 30%

Answer:

3x^4

Step-by-step explanation:

3x • 3x • 3x • 3x = 3x^4

said like “3x to the 4th power”

Answer:

[tex](3x)^4}[/tex]

Step-by-step explanation:

further it can represent as [tex]3^{4} x^{4}[/tex]

the answer is

A. 28, 25, 22

Answer:

B. 1/2

Step-by-step explanation:

y = ax^2 + bx + c

14 = a(0)^2 + b(0) + c

c = 14

10.5 = a(1)^2 + b(1) + 14

10.5 = a + b + 14 ____(i)

8 = a(2)^2 + b(2) + 14

8 = 4a + 2b + 14

4 = 2a + b + 7 ___ (ii)

i - ii

10.5 - 4 = -a + 7

6.5 = -a + 7

a = 7- 6.5

a = 0.5

Value of a in the quadratic function is 0.5

In algebra, a quadratic function, a quadratic polynomial, a polynomial of degree 2, or simply a quadratic, is a polynomial function with one or more variables in which the highest-degree term is of the second degree

Given,

Quadratic function

y = [tex]ax^{2}+bx+c[/tex]

Consider values in the table x= 0 and  y =14

[tex]14=a(0)^{2}+b(0)+c\\ c=14[/tex]

Consider x=1 and y = 10.5

[tex]10.5=a(1^{2})+b(1)+c\\ a+b=10.5-14\\a+b=-3.5[/tex]

Consider x=2 and y =8

[tex]8=a(2^{2})+b(2)+c\\ a\\8=4a+2b+14\\4a+2b=-6\\2a+b=-3[/tex]

Subtract a + b= -3.5 from 2a + b= -3

a=-3--3.5=0.5

Hence, the Value of a in the quadratic function is 0.5

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Answer:

3 wholes 2/5

I hope this helps you!

Answer:

After 4 months Xian will have 104 stamps,

But after three months Kai will also have 104 stamps

Step-by-step explanation:

Answer:

x=2

y=3

Step-by-step explanation:

x/2+y/3=2   so      

3x/6+2y/6=12/6

then multiply by 6

3x+2y=12    

equation number 2

x/3+y/2=13/6

2x/6+3y/6=13/6

multiply by 6

2x+3y=13

so the system is now

3x+2y=12  

2x+3y=13

from the first equation 2y=12-3x,  y=6 -  3x/2

then put  y in  the second equation

2x+3*(6-3x/2)=13

2x+18-9x/2=13

2x-9x/2=13-18

4x/2-9x/2=-5

-5x/2=-5

*(-1/5)    *(-1/5)

x/2=1

*2    *2

x=2

so y=6-3*2/2=6-3

y=3

Step-by-step explanation:

Given that:

(1/2x)+(1/3y) = 2 --------(1)

(1/3x)+(1/2y) = 13/6-----(2)

Put 1/x = a and 1/y = b then

(1) becomes

(a/2 )+( b/3) = 2

⇛ (3a+2b)/6 = 2

⇛ 3a+2b = 2×6

⇛ 3a+2b = 12 --------(3)

(2) becomes

(a/3)+(b/2)=13/6

⇛ (2a+3b)/6 = 13/6

⇛ 2a+3b=13----------(4)

On adding (3)&(4) then

3a+2b=12

2a+3b=13

(+)

_________

5a+5b = 25

_________

⇛ 5a+5b = 25

⇛ 5(a+b)=25

⇛ a+b=25/5

⇛ a+b=5 -------------(5)

On subtracting (3) from (4)

2a+3b=13

3a+2b=12

(-)

_________

-a+b = 1

_________

⇛ -a+b = 1

⇛ b = 1+a --------(6)

On Substituting the value of b in (5) then

a+1+a = 5

⇛2a+1 = 5

⇛ 2a = 5-1

⇛ 2a = 4

⇛ a = 4/2

⇛ a = 2

On Substituting the value of a in (6) then

b = 1+2

b = 3

Now,

a = 2

⇛ 1/x=2

⇛ “x” = 1/2

and

b= 3

⇛ 1/y = 3

⇛“y” = 1/3

Answer:- Hence, the value of x and y with be 1/2 and 1/3 respectively.

The solution for the given problem is (1/2,1/3)

Check:-

If x = 1/2 and y = 1/3 then

LHS = (1/2x)+(1/3y)

= 1/2(1/2)+1/3(1/3)

= 1/(2/2)+1/(3/3)

= (1/1)+(1/1)

= 1+1

=2

= RHS

LHS=RHS is true

and

LHS=(1/3x)+(1/2y)

⇛ 1/3(1/2)+ 1/2(1/3)

⇛ 1/(3/2)+1/(2/3)

⇛ (2/3)+(3/2)

⇛ (4+9)/6

⇛ 13/6

⇛ RHS

LHS = RHS is true

also read similar questions: Simultaneous equations: 1. 2x+2y=10 X+2y=6 2. 3x+y=18 2x+y=13 3. X+y=1 X-y=5 4. 3x+4y=29 X-4y=-17 5. 4c+3y=11 2x+y=7

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Answer:

cos(A) = 4/5

Step-by-step explanation:

3sinA+4cosA=5

Divide by 5 on both sides

(3/5)sinA+(4/5)cosA = 1 .................(1)

from which sin(A) = 3/5, cos(A) = 4/5  by inspection, since

(3/5)^2+(4/5)^2 = 1

For more details,

Let

cos(B) = (3/5), then

sin(B) = (4/5)

Substitute in (1)

cos(B)sin(A) + sin(B)cos(A) = 1          substitute trigonometric sum

sin(A+B) = 1  => A & B are complementary

cos(A) = sin(B) = 4/5

=====================================================

Explanation:

The double tickmarks for quadrilateral MATH show that MA = TH. Since TH is 5 units long, this makes MA the same length as well.

For quadrilateral ROKS, we have RO = 15. For "MATH" and "ROKS" we have "MA" and "RO" as the first two letters of each four-letter sequence; meaning that MA and RO correspond together.

The ratio of the corresponding segments is RO/MA = 15/5 = 3.

The larger quadrilateral has each side length 3 times longer than the smaller quadrilateral's corresponding side lengths.

--------------

In short,

larger side = 3*(smaller side)

--------------

Using this scale factor of 3, we can find MH

larger side = 3*(smaller side)

RS = 3*(MH)

21 = 3*MH

3*MH = 21

MH = 21/3

MH = 7

Answer:

85 minutes

Step-by-step explanation:

425/50=8.5 10 minute increments

8.5*10= 85 minutes

Answer:

2.5 meter

Step-by-step explanation:

in a right triangle, tan of an angle  = opposite side /adjacent side

tan 70° = x/ 0.9 , multiply both sides by 0.9

0.9 * tan 70° = x, solve on a calculator

x ≈ 2.5 m

Answer:

an accounts; credit or debit.

Step-by-step explanation:

Remember, accounting involves activities done to keep financial records. Interestingly, a similar term is used to refer to the basic unit in which data are stored in an accounting system called accounts.

Also, we need to bear in mind that this financial records written as storage units would include incoming or outgoing money measurements often called debit or credit transactions in the items for which they are established.

To simplify use the distributive property first. Multiply 6 by each value inside the parentheses:

6(x-4) + 9

6x -24 + 9

Now combine like terms to get the final answer:

6x - 15

Answer:

We have,

y-y1=m(x-x1)

or,y-4=-1(x-0)

or,y-4=-x

or,x+y=4 is the required equation

Step-by-step explanation:

it it helps u ...plz mark it as brainliest

Answer:

I'm pretty sure 8 is the correct answer

Step-by-step explanation:

(-1)^(3/7)  x 128^(3/7)

-1 x 128^3/7

128^(3/7) = 8

= 8

Answer:

(4x + 1)(2x² - 5)

Step-by-step explanation:

Given

8x³ + 2x² - 20x - 5 ( factor the first/second and third/fourth terms )

= 2x²(4x + 1) - 5(4x + 1) ← factor out (4x + 1) from each term

= (4x + 1)(2x² - 5)

Answer:

blank 1 is -20-5

blank 2 is 4x+1

blank 3 is -5

blank 4 is 2x^2-5

Step-by-step explanation:

Answer:

a. grade 1 oak 519 ft.   520

b. grade 2 oak 795 ft.   800

c. grade 1 pine 323 ft.    320

d. grade 2 pine 477 ft.     480

Answer:

square: (9x^8)^2= 81x^16

square root: (9x^8)^1/2 = 3x^4

Step-by-step explanation:

the ^ mean that the following num should be like this ​⁸​

Hi

P and Q only intersect for 2 as 2 is common for P and Q . So P U Q = 2

For the diagram :

One big circle name U with 1 on the

Far corner left and 9 on the far right corner.

Then on the left, a circle within circle U with the number Of P

Same with Q on the right.

But P and Q must intersect on number 2 as 2 is in both circles.

ps : nothing oblidge you to set the number on mathematical order. Of it'esasier to do the circles, do it whatever you like as long as you respect what is said.

[tex] \LARGE{ \underline{ \boxed{ \purple{ \rm{Solution : )}}}}}[/tex]

Euclid's division lemma : Let a and b are two positive integers. There exist unique integers q and r such that

a = bq + r, 0 [tex]\leqslant[/tex] r < b

Or We can write it as,

Dividend = Divisor × Quotient + Remainder

Work out:

Given integers are 240 and 228. Clearly 240 > 228. Applying Euclid's division lemma to 240 and 228,

⇛ 240 = 228 × 1 + 12

Since, the remainder 12 ≠ 0. So, we apply the division dilemma to the division 228 and remainder 12,

⇛ 228 = 12 × 19 + 0

The remainder at this stage is 0. So, the divider at this stage or the remainder at the previous age i.e 12

[tex] \large{ \therefore{ \boxed{ \sf{HCF \: of \: 240 \: \& \: 228 = 12}}}}[/tex]

━━━━━━━━━━━━━━━━━━━━

Answer:

D

Step-by-step explanation:

The consecutive angles in a parallelogram are supplementary.

Thus statement D is not always true.