Convert 16,000 feet per second into kilometers per hour. step by step​

Answer:

16

Step-by-step explanation:

4 * sqrt( a^2 - b^2)

Let a = -5 and b =3

4 * sqrt( (-5)^2 - 3^2)

Do the squaring first

4 * sqrt( 25 - 9)

Subtract inside the square root

4 * sqrt( 16)

Take the square root

4 * 4

Multiply 16

Answer:

[tex]\Large \boxed{16}[/tex]

Step-by-step explanation:

[tex]4\sqrt{a^2-b^2 }[/tex]

[tex]\sf Plug \ in \ the \ values \ for \ a \ and \ b.[/tex]

[tex]4\sqrt{-5^2-3^2 }[/tex]

[tex]4\sqrt{25-9 }[/tex]

[tex]4\sqrt{16}[/tex]

[tex]4 \times 4=16[/tex]

Answer:

10.2

Step-by-step explanation:

Length of arc=(2*pi*r)*(theta/360)

Length of arc=(2*pi*3)*(195/360)=10.2

Answer:

Step-by-step explanation:

Total number of people = 800

To find the number of unemployed people we must first find the total percentage of the pie chart

That's

25 + 10 + 5 + 60 = 100%

5 % out of the 100% are unemployed

To find the number of unemployed people divide 5 % by the total percentage that's 100% and multiply them by the total number of people

That's

[tex] \frac{5}{100} \times 800[/tex]

5 × 8

We have the final answer as

Hope this helps you

Answer: 0.2358

Step-by-step explanation:

Using Normal Distribution, under the  standard normal curve

The area to the right of z is given by P(Z>z)=1-P(Z<z)

So, the area to the right of z= 0.72 under the  standard normal curve would be:

P(Z>0.72)=1-P(z<0.72)

=1-0.7642   [By using p-value table]

= 0.2358

Hence, the area to the right of z= 0.72 under the  standard normal curve is 0.2358 .

Answer:

Lol yu lateee das "who i smoke by yung ace"

Step-by-step explanation:

Answer:

woogle said woo hoo  by rock a teens

Step-by-step explanation:

Answer:

Because it is not an equation.

Step-by-step explanation:

[tex] log(x) \times log(2) \\ = log(x + 2) [/tex]

Answer:

The two odd numbers are 15 and 17

Step-by-step explanation:

Given

Let the odd numbers be represented with x and y

Let x be the greater number

[tex]x + 5y = 92[/tex]

Required

Find x and y

Since x and y are consecutive odd numbers and x is greater, then

[tex]x = y + 2[/tex]

Substitute y + 2 for x in [tex]x + 5y = 92[/tex]

[tex]y + 2 + 5y = 92[/tex]

Collect Like Terms

[tex]y + 5y = 92 - 2[/tex]

[tex]6y = 90[/tex]

Divide both sides by 6

[tex]\frac{6y}{6} = \frac{90}{6}[/tex]

[tex]y = \frac{90}{6}[/tex]

[tex]y = 15[/tex]

Substitute 15 for y in [tex]x = y + 2[/tex]

[tex]x = 15 + 2[/tex]

[tex]x = 17[/tex]

Hence; the two odd numbers are 15 and 17

Answer:

Maths

Step-by-step explanation:

Answer:

The two odd numbers are 15 and 17

Step-by-step explanation:

Given

Let the odd numbers be represented with x and y

Let x be the greater number

Required

Find x and y

Since x and y are consecutive odd numbers and x is greater, then

Substitute y + 2 for x in  

Collect Like Terms

Divide both sides by 6

Substitute 15 for y in  

Hence; the two odd numbers are 15 and 17

Answer:

E(w) = 1600000

v(w) = 240000

Step-by-step explanation:

given data

sequence = 1 million iid  (+1 and +2)

probability of transmitting a +1 =  0.4

solution

sequence will be here as

P{Xi = k } = 0.4              for k = +1

                  0.6              for k = +2

and define is

x1  + x2 + ................ + X1000000

so for expected value for W

E(w) = E( x1  + x2 + ................ +  X1000000 )   ......................1

as per the linear probability of expectation

E(w) = 1000000 ( 0.4 × 1 + 0.6 × 2)

E(w) = 1600000

and

for variance of W

v(w) = V ( x1  + x2 + ................ + X1000000 )    ..........................2

v(w) = V x1  + V x2 + ................  + V  X1000000

here also same as that xi are i.e d so cov(xi, xj ) = 0 and i ≠ j

so

v(w) = 1000000 ( v(x) )

v(w) = 1000000 ( 0.24)

v(w) = 240000

9514 1404 393

Answer:

  125.6 cm²

Step-by-step explanation:

The relevant area formula is ...

  Area = (1/2)ac·sin(B)

  Area = (1/2)(13 cm)(21 cm)·sin(67°) ≈ 125.6 cm²

Answer:

y = - [tex]\frac{4}{3}[/tex] x

Step-by-step explanation:

1). [tex]y_{1}[/tex] = [tex]m_{1}[/tex] [tex]x_{1}[/tex] + [tex]b_{1}[/tex]  

[tex]y_{2}[/tex] = [tex]m_{2}[/tex] [tex]x_{2}[/tex] + [tex]b_{2}[/tex]

[tex]y_{1}[/tex] ⊥ [tex]y_{2}[/tex]  if  [tex]m_{2}[/tex] = - [tex]\frac{1}{m_{1} }[/tex]

2). ( [tex]x_{3}[/tex] , [tex]y_{3}[/tex] )

y - [tex]y_{3}[/tex] = m( x - [tex]x_{3}[/tex] )

~~~~~~~~~~~~~~~~~~

y = [tex]\frac{3}{4}[/tex] x + 7

[tex]m_{1}[/tex] = [tex]\frac{3}{4}[/tex]

[tex]m_{2}[/tex] = - [tex]\frac{4}{3}[/tex]

( 3, - 4 )

y - ( - 4) = - [tex]\frac{4}{3}[/tex] ( x - 3 )

y + 4 = - [tex]\frac{4}{3}[/tex] x + 4

y = - [tex]\frac{4}{3}[/tex] x

Answer:

Hey There!! The answer to this is (6, 10) There are no answer choices, so I will just list a few. But first, we need to create the equation.

Plugging in (5,7) into the equation y=mx+b, we can solve for b since all of the other variables are known, with m=3 as the slope.

So, 7=3*5+b

7=15+b

b = -8

y=3x-8 is your equation.

So, you can plug in any value of x you get a certain value of y.

(1,-5), (2,-2), (3,1), (4,4), (5,7), (6,10), (7,13) Thus, for The correct option (6, 10). Hope It Helped!~ ♡

ItsNobody~ ☆

Answer:

y=3x-8

Step-by-step explanation:

We can start by writing the equation of the line in point-slope form.

Point-slope form is y-y1=m(x-x1)

This is where:

y1= y-coordinate of a given point on the line

m= slope of the line

x1= x-coordinate of a given point on the line

The given point in this example is (5,7)

A point is (x-coordinate, y-coordinate)

Therefore,

y1=7

m=3

x1=5

Plug that into the form.

y-7=3(x-5)

We can now simplify that to slope-intercept form,since that is most standard.

y-7=3(x-5)

Start by distributing the right side.

y-7=3x-15

Add 7 to both sides.

y=3x-8

Answer:

consistent independent

Step-by-step explanation:

This is a graph of consistent independent equations

The lines cross and there is one solution

Inconsistent equations never cross and there is no solutions

Consistent dependent equations are equations of the same line

Answer:

Linear

Step-by-step explanation:

This is a graph of linear system of equation.

The two lines represent different equations connected with each other.

They intersect at a common point showing the solution to the system of equation.

Answer:

7

Step-by-step explanation:

The following range includes numbers from negative infinity to 8. But, 8 isn't included, because there is a parentheses not a bracket. So, basically you can have 7.9999999. But, it asks for an integer, so it is 7.

The largest integer which belongs to the interval: (−∞, 8) is 7

To determine the largest integer, we will first ascertain what the use of parentheses and brackets denote.

The use of parentheses ( ) stands for open interval, that is, the extreme numbers of the set are not included.

If the brackets [ ] were used instead, that will be closed interval, that is, the extreme numbers of the set are included.

Since ( ) were used in the question, that means the extreme numbers −∞ and 8 are NOT included in the set.

Now, let us define an integer.

An integer is a positive or negative whole number or zero.

Hence, the integers in the set will include: −∞+1, −∞ + 2, ... 5, 6, and 7.

The largest integer here is 7

Hence, the largest integer which belongs to the interval: (−∞, 8) is 7

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Answer:

5

Step-by-step explanation:

Just multiply 5/7 by 7 since his dog retrieved 5/7 out of the 7 ducks he shot.

Answer:

5

Step-by-step explanation:

7*5/7

7 represents the # of ducks

5/7 represents the # of ducks that were recovered

The question asks the number of ducks that were recovered so you should multiply the total # of ducks there are by the fraction that were recovered.

Answer:

840 ( D )

Step-by-step explanation:

GIVEN DIGITS : 1,2,3,4,5,6,7,8  

Number of odd numbers = 4

Number of even numbers = 4

therefore the number of odd numbers with 4 different digits can be formed by the same way the number of even numbers ( without repetition )

Hence the number of ways odd numbers with 4 different digits = Total number of ways of forming 4 digit numbers / 2

8*7*6*5 = 1680 / 2 =  840 ways

Step-by-step explanation:

f(1) = 3×1 - 1 = 2

f(4) = 3×4 - 1 = 12-1 = 11

so, the functional value changes 11-2=9 units on an x interval of 4-1=3 units length.

the average change rate is the total change across the x interval relative to the interval length.

that is

9/3 = 3

which is the slope (= the factor of x) in the line equation.

for a line its change rate for any point is the same constant. and that is therefore automatically also the average change rate across an interval of x values.

if the change rate would be different for different parts of the function, it would not be a straight line.

Answer:

3

Step-by-step explanation:

The average rate of f(x) in the closed interval [ a, b ] is

[tex]\frac{f(b)-f(a)}{b-a}[/tex]

Here [ a, b ] = [ 1, 4 ] , then

f(b) = f(4) = 3(4) - 1 = 12 - 1 = 11

f(a) = f(1) = 3(1) - 1 = 3 - 1 = 2

average rate of change = [tex]\frac{11-2}{4-1}[/tex] = [tex]\frac{9}{3}[/tex] = 3

Answer:

V = 2143.57 cm^3

Step-by-step explanation:

The volume of a sphere is

V = 4/3 pi r^3

The diameter is 16 so the radius is 1/2 of the diameter or 8

V = 4/3 ( 3.14) (8)^3

V =2143.57333

Rounding to the nearest hundredth

V = 2143.57 cm^3

Answer:

2143.57 cm^3

Step-by-step explanation:

V = 4/3 * 3.14 * r^3

r = 1/2 * 16 = 8

So V = 4/3 * 3.14 * 8^3

= 2143.57 cm^3.

Answer:

28

Step-by-step explanation:

We need to find the value of [tex]\Sigma_{x=0}^3\ 2x^2[/tex]

We know that,

[tex]\Sigma n^2=\dfrac{n(n+1)(2n+1)}{6}[/tex]

Here, n = 3

So,

[tex]\Sigma n^2=\dfrac{3(3+1)(2(3)+1)}{6}\\\\\Sigma n^2=14[/tex]

So,

[tex]\Sigma_{x=0}^3\ 2x^2=2\times 14\\\\=28[/tex]

So, the value of [tex]\Sigma_{x=0}^3\ 2x^2[/tex] is 28. Hence, the correct option is (d).

Step-by-step explanation:

I think this might be the correct answer

The number of pupils that like neither tasty-time nor ice cream is 6 if in a class of 70 pupils, 36 like tasty time, 34 like ice cream, 6 like both tasty times.

It is defined as the diagram that shows a logical relation between sets.

The Venn diagram consists of circles to show the logical relation.

We have:

In a class of 70 pupils, 36 like tasty time, 34 like ice cream, 6 like both tasty time.

Total = 70 pupils

Number of like tasty time = 36

Number of like ice cream = 34

Number of like both = 6

Let x be the total number of pupils that like neither tasty-time nor ice cream

The number of pupils that like ice cream only =  34 - 6 = 28

The number of pupils that like tasty-time only = 36 - 6 = 30

From the Venn diagram:

28 + 30 + 6 + x = 70

x = 70 - 64

x = 6

Thus, the number of pupils that like neither tasty-time nor ice cream is 6 if in a class of 70 pupils, 36 like tasty time, 34 like ice cream, 6 like both tasty times.

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=========================================================

Explanation:

The original line has a given slope of -6/13. The opposite reciprocal is 13/6. We flip the fraction and the sign from negative to positive.

With any two perpendicular slopes, they always multiply to -1

(-6/13)*(13/6) = (-6*13)/(13*6) = -78/78 = -1

--------------------

Since the perpendicular slope is 13/6, we need to see which of the four answer choices produces a slope of 13/6. Use the slope formula.

This is something you do through trial and error. You could start with A and work your way to D, or just pick at random. I'll go through each one by one starting at choice A.

---------------------

Let's try choice A

m = (y2 - y1)/(x2 - x1)

m = (2 - (-4))/(-7 - 13)

m = (2 + 4)/(-7 - 13)

m = 6/(-20)

m = -3/10, we can see that choice A is not the answer, since we want m = 13/6 instead.

-----------------------

Let's try choice B

m = (y2 - y1)/(x2 - x1)

m = (2 - (-4))/(-7 - 6)

m = (2 + 4)/(-7 - 6)

m = 6/(-13)

m = -6/13, that doesn't work either

------------------------

Let's try choice C

m = (y2 - y1)/(x2 - x1)

m = (-7 - 6)/(-4 - 2)

m = -13/(-6)

m = 13/6, we found the answer

------------------------

For the sake of completeness, here is what choice D would look like

m = (y2 - y1)/(x2 - x1)

m = (-4 - 9)/(-4 - 6)

m = -13/(-10)

m = 13/10, which isn't the slope we want

Answer:

2^(1/6) (cos(-pi/12)+i sin(-pi/12))

2^(1/6) (cos(3pi/12)+i sin(3pi/12))

2^(1/6) (cos(7pi/12)+i sin(7pi/12))

2^(1/6) (cos(11pi/12)+i sin(11pi/12))

2^(1/6) (cos(5pi/4)+i sin(5pi/4))

2^(1/6) (cos(19pi/12)+i sin(19pi/12))

Step-by-step explanation:

Let's convert to polar form.

-2i=2(cos(A)+i sin(A) )

There is no real part so cos(A) has to be zero and since we want -2 and we already have 2 then we need sin(A)=-1 so let's choose A=-pi/2.

So z=2(cos(-pi/2)+i sin(-pi/2)).

There are actually infinitely many ways we can write this polar form which we will need.

z=2(cos(-pi/2+2pi k)+i sin(-pi/2+2pi k))

where k is an integer

Now let's find the 6 6th roots or z.

2^(1/6) (cos(-pi/12+2pi k/6)+i sin(-pi/12+2pi k/6))

Reducing

2^(1/6) (cos(-pi/12+pi k/3)+i sin(-pi/12+pi k/3))

Plug in k=0,1,2,3,4,5 to find the 6 6th roots.

k=0:

2^(1/6) (cos(-pi/12+pi (0)/3)+i sin(-pi/12+pi (0)/3))

=2^(1/6) (cos(-pi/12)+i sin(-pi/12))

k=1:

2^(1/6) (cos(-pi/12+pi/3)+i sin(-pi/12+pi/3))

2^(1/6) (cos(3pi/12)+i sin(3pi/12))

k=2:

2^(1/6) (cos(-pi/12+2pi/3)+i sin(-pi/12+2pi/3))

2^(1/6) (cos(7pi/12)+i sin(7pi/12))

k=3:

2^(1/6) (cos(-pi/12+3pi/3)+i sin(-pi/12+3pi/3))

2^(1/6) (cos(11pi/12)+i sin(11pi/12))

k=4:

2^(1/6) (cos(-pi/12+4pi/3)+i sin(-pi/12+4pi/3))

2^(1/6) (cos(15pi/12)+i sin(15pi/12))

2^(1/6) (cos(5pi/4)+i sin(5pi/4))

k=5:

2^(1/6) (cos(-pi/12+5pi/3)+i sin(-pi/12+5pi/3))

2^(1/6) (cos(19pi/12)+i sin(19pi/12))

Step-by-step explanation:

{ x| x all real numbers}

The domain of f(x) = 5x – 7 will be all real numbers, as the function is a straight line, with no discontinuities, thus undefined at no value of x.

The domain of the function f(x) = 5ˣ - 7 is {x | x is a real number}.

A function is a relation from a set A to a set B where the elements in set A only maps to one and only one image in set B. No elements in set A has more than one image in set B.

Given function is,

f(x) = 5ˣ - 7

The domain of the function is the set of all values of x such that the function is defined.

If we use any number for x, the function will be defined.

So the domain is the set of all real numbers.

So the correct option is last one {x | x is a real number}.

Hence the domain of the given function is {x | x is a real number}.

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Answer:

The two lines do not intersect, and are parallel to one another on a graph.

Step-by-step explanation:

A system of equations consists of two or more equations with two or more variables. The solution to these variables must satisfy all of the variables in the equations in the system at the same time. Usually, all the equations in the system are considered and solved simultaneously. A linear equation might have a unique solution, an infinite solution, or no solution at all.

A system with exactly one solution is called a consistent system, and it is said to be independent, and the graph of its lines intersects at the point that is the solution to the equations. A system with an infinite number of solution is said to be dependent and the lines are coincident on a graph.

If a system has no solution, it is said to be inconsistent . The graphs of the lines do not intersect, and the lines are parallel to one another on the graph.

For two lines of linear equations to have no solution, they must be parallel to each other i.e they must have the same slope.

The standard form of writing linear equation is expressed as y = mx + b

m is the slope of the line

b is the y-intercept

For two lines of linear equations to have no solution, they must be parallel to each other i.e they must have the same slope.

For instance, the system of equations y = 2x + 7 and y = 2x - 3 have no solutions because they have the same slope.

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Answer:

the other person is right

you should try putting the WHOLE question

Step-by-step explanation:

Answer:

B. domain {-2, 0, 2}, range {-1, 0, 1}

Step-by-step explanation:

The x values and y values as ordered pairs would be: (-2,-1), (0,0), (2,1)

The domain is the all of the values of x and the range is all the values of y.

Answer: It is a weak negative correlation and it is not likely causal.

Step-by-step explanation:

Given: The number of times a player has golfed in one's lifetime is compared to the number of strokes it takes the player to complete 18 holes. The correlation coefficient relating the two variables is -0.26.

Variables : "number of times a player has golfed in one's lifetime" and "number of strokes it takes the player to complete 18 holes".

Since -0.26 is more closer to 0 as compared to 1 , so it describes a weak negative correlation.

Also, it is not likely causal as number of times a player has golfed in one's lifetime not cause number of strokes it takes the player to complete 18 holes.

Answer: B) It is a weak negative correlation, and it is likely casual

Correct on edge 2020!

Answer:

ring volume is 12cm3

Step-by-step explanation:

Lr ccm=volume of water and ring - Volume of water

ring cubic centimeters =x

x=9.2cm*4.5cm*7cm - 8.8cm*4.5cm*7cm

x=289.2cm3 - 277.2cm3

x=12cm3

Answer:

The number to be multiplied is the "multiplicand"

Step-by-step explanation:

a base when it is written in exponential notation

The first, second, third and fourth order Maclaurin polynomials of f(x)=arctan(x) are:

So let's start by finding the first order maclaurin polynomial:

f(x)=f(0)+f'(0)x

so let's find each part of the function:

f(0)=arctan(0)

f(0)=0

now, let's find the first derivative of f(x)

f(x)=arctan(x)

This is a usual derivative so there is a rule we can use here:

[tex]f'(x)=\frac{1}{x^{2}+1}[/tex]

so now we can find f'(0)

[tex]f'(0)=\frac{1}{(0)^{2}+1}[/tex]

f'(0)=1

So we can now complete the first order Maclaurin Polynomial:

f(x)=0+1x

which simplifies to:

f(x)=x

Now let's find the second order polynomial, for which we will need to get the second derivative of the function:

[tex]f(x)=f(0)+f'(0)x+\frac{f''(0)}{2!}x^{2}[/tex]

so:

[tex]f'(x)=\frac{1}{x^{2}+1}[/tex]

we can rewrite this derivative as:

[tex]f'(x)=(x^{2}+1)^{-1}[/tex]

and use the chain rule to get:

[tex]f''(x)=-1(x^{2}+1)^{-2}(2x)[/tex]

which simplifies to:

[tex]f''(x)=-\frac{2x}{(x^{2}+1)^{2}}[/tex]

now, we can find f''(0):

[tex]f''(0)=-\frac{2(0)}{((0)^{2}+1)^{2}}[/tex]

which yields:

f''(0)=0

so now we can complete the second order Maclaurin polynomial:

[tex]f(x)=0+1x+\frac{0}{2!}x^{2}[/tex]

which simplifies to:

f(x)=x

Now let's find the third order polynomial, for which we will need to get the third derivative of the function:

[tex]f(x)=f(0)+f'(0)x+\frac{f''(0)}{2!}x^{2}+\frac{f'''(0)}{3!}x^{3}[/tex]

so:

[tex]f''(x)=-\frac{2x}{(x^{2}+1)^{2}}[/tex]

In this case we can use the quotient rule to solve this:

Quotient rule: Whenever you have a function in the form , then it's derivative is:

[tex]f'(x)=\frac{p'q-pq'}{q^{2}}[/tex]

in this case:

p=2x

p'=2

[tex]q=(x^{2}+1)^{2}[/tex]

[tex]q'=2(x^{2}+1)(2x)[/tex]

[tex]q'=4x(x^{2}+1)[/tex]

So when using the quotient rule we get:

[tex]f'(x)=\frac{p'q-pq'}{q^{2}}[/tex]

[tex]f'''(x)=\frac{(2)(x^{2}+1)^{2}-(2x)(4x)(x^{2}+1)}{((x^{2}+1)^{2})^{2}}[/tex]

which simplifies to:

[tex]f'''(x)=\frac{-2x^{2}-2+8x^{2}}{(x^{2}+1)^{3}}[/tex]

[tex]f'''(x)=\frac{6x^{2}-2}{(x^{2}+1)^{3}}[/tex]

now, we can find f'''(0):

[tex]f'''(0)=\frac{6(0)^{2}-2}{((0)^{2}+1)^{3}}[/tex]

which yields:

f'''(0)=-2

so now we can complete the third order Maclaurin polynomial:

[tex]f(x)=0+1x+\frac{0}{2!}x^{2}-\frac{2}{3!}x^{3}[/tex]

which simplifies to:

[tex]f(x)=x-\frac{1}{3}x^{3}[/tex]

Now let's find the fourth order polynomial, for which we will need to get the fourth derivative of the function:

[tex]f(x)=f(0)+f'(0)x+\frac{f''(0)}{2!}x^{2}+\frac{f'''(0)}{3!}x^{3}+\frac{f^{(4)}(0)}{4!}x^{4}[/tex]

so:

[tex]f'''(x)=\frac{6x^{2}-2}{(x^{2}+1)^{3}}[/tex]

In this case we can use the quotient rule to solve this:

[tex]f'(x)=\frac{p'q-pq'}{q^{2}}[/tex]

in this case:

[tex]p=6x^{2}-2[/tex]

p'=12x

[tex]q=(x^{2}+1)^{3}[/tex]

[tex]q'=3(x^{2}+1)^{2}(2x)[/tex]

[tex]q'=6x(x^{2}+1)^{2}[/tex]

So when using the quotient rule we get:

[tex]f'(x)=\frac{p'q-pq'}{q^{2}}[/tex]

[tex]f^{4}(x)=\frac{(12x)(x^{2}+1)^{3}-(6x^{2}-2)(6x)(x^{2}+1)^{2}}{((x^{2}+1)^{3})^{2}}[/tex]

which simplifies to:

[tex]f^{4}(x)=\frac{12x^{3}+12x-6x^{3}+12x}{(x^{2}+1)^{4}}[/tex]

[tex]f^{4}(x)=\frac{6x^{3}+24x}{(x^{2}+1)^{4}}[/tex]

now, we can find f^{4}(0):

[tex]f^{4}(x)=\frac{6(0)^{3}+24(0)}{((0)^{2}+1)^{4}}[/tex]

which yields:

[tex]f^{4}(0)=0[/tex]

so now we can complete the fourth order Maclaurin polynomial:

[tex]f(x)=0+1x+\frac{0}{2!}x^{2}-\frac{2}{3!}x^{3}+\frac{0}{4!}x^{4}[/tex]

which simplifies to:

[tex]f(x)=x-\frac{1}{3}x^{3}[/tex]

you can find the graph of the four polynomials in the attached picture.

So the first, second, third and fourth order Maclaurin polynomials of f(x)=arctan(x) are:

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