Derrick had a 0.250 batting average at the end of his last baseball season, which means he got a hit 25% of the times he was up to bat. if derrick had 47 hits last season, how many times did he bat?

Answers

Answer 1

The number of times that Derrick batted last season is 188 times.

How many times did Derrick bat?

Percentage can be described as a fraction out of an amount that is usually expressed as a number out of hundred. Percentage is a measure of frequency. The sign used to denote percentage is %.

A percentage of 25% here means that twenty five times out of hundred times, Derrick hit the ball. In order to convert a percentage to a decimal, divide the percentage by 100.

Number of times Derrick bat last season = Number of hits last season / percentage of his batting average

47 / 25%

47 / 0.25 = 188

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Related Questions

Show your steps in evaluating each of the following expressions. The steps count 4 points each, the answer is 1

Answers

The steps in evaluating each of the following expressions is shown below.

What is an expression?

An expression is a mathematical equation which shows the relationship that exist between two or more numerical quantities or variables.

How to evaluate the given expressions?

15 - 35/7 - 2 + 3 - 4

15 - (35/7) - 2 + 3 - 4 (bracket and division)

15 - 5 - 2 + 3 - 4 (regroup)

15 + 3 - 5 - 2 - 4 (subtract and add)

18 - 11 = 7.

Expression 2.

10 + 2(9 - 5) - 16/18

10 + (2 × 4) - 8/9 (bracket and division)

10 + 8 - 8/9 (add)

18 - 8/9 (subtract)

162/9 - 8/9 = 17 1/9 or 154/9.

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Complete Question:

Show your steps in evaluating each of the following expressions. The steps count 4 points each, the answer is 1 point.

A. 15 - 35/7 -2 + 3 -4

B. 10 + 2(9 - 5) - 16/18

Almost done!!! Appreciate the help

Answers

Using the formula for the distance between two points to find the side lengths, the perimeter of the polygon is of 25 units.

What is the perimeter of a figure?

The perimeter of a figure is given by the sum of the side lengths of it's outside dimensions.

What is the distance between two points?

Suppose that we have two points, [tex](x_1,y_1)[/tex] and [tex](x_2,y_2)[/tex]. The distance between them is given by:

[tex]D = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}[/tex]

For this problem, the distances are given as follows:

[tex]D_1 = \sqrt{(-1 -(-1))^2 + (6 - 3)^2} = 3[/tex].[tex]D_2 = \sqrt{(2 -(-1))^2 + (10 - 6)^2} = 5[/tex].[tex]D_3 = \sqrt{(5 - 2)^2 + (6 - 10)^2} = 5[/tex].[tex]D_4 = \sqrt{(5 - 5)^2 + (3 - 6)^2} = 6[/tex].[tex]D_5 = \sqrt{(5 - (-1))^2 + (3 - 3)^2} = 6[/tex].

Hence the perimeter is given by:

P = 3 + 2 x 5 + 2 x 6 = 25 units.

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The ratio of girls to boys at a party is 5:4. if there are 20 girls in the class, how many boys are there.

Answers

Answer:

16 boys

==========================

Let the number of boys be b and girls be g.

The ratio is:

g/b = 5/4

And the number of girls is:

g = 20

Substitute the number into ratio and find the value of b:

20/b = 5/4b = 20*4/5b = 16

A survey of 400 nurses yielded the following information: 279 were health club members, 215 were smokers, and 160 of the health club members were smokers. how many of the 400 surveyed nurses were health club members or were smokers?

Answers

Health club members or were smokers is [tex]334[/tex] from a A survey of [tex]400[/tex] nurses yielded.

How can we find the health club members or were smokers ?

Events of health club members is [tex]P(M)=279[/tex]

Events of smokers is [tex]P(S)=215[/tex]

Probability of health club members and smokers is [tex]p(M and S)=160[/tex]

Probability of health club members or were smokers is =?

So we use the formula

[tex]p(M or S)=p(M)+p(S)-p(M and S)\\ = 279+215-160\\ = 334[/tex]

Probability of health club members or were smokers is [tex]334[/tex]

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Which rule describes the composition of transformations that maps δbcd to δb"c"d"? translation of 5 units x, negative 6 units y composition reflection across y = negative x reflection across y = negative x composition translation of 5 units x, negative 6 units y. translation of 6 units x, negative 5 units y composition reflection across the y-axis reflection across the y-axis composition translation of 6 units x, negative 5 units y

Answers

The rule which describe the composition of transformations that

maps ΔBCD to ΔB"C"D" is:

Reflection across the y-axis composition translation of 6 units x,

negative 5 units y ⇒ last answer

Step-by-step explanation:

Let us revise the reflection across the y-axis , horizontal translation

and vertical translation

1. If point (x , y) is reflected across the y-axis, then its image is (-x , y)

2. If point (x , y) is translated h units to the right, then its image is

  (x + h , y), if translated h units to the left, then its image is (x - h , y)

3. If point (x , y) is translated k units up, then its image is (x , y + k),

  if translated k units down, then its image is (x , y - k)

∵ The vertices of triangle BCD are (1 , 4) , (1 , 2) , (5 , 3)

∵ The vertices of triangle B'C'D' are (-1 , 4) , (-1 , 2) , (-5 , 3)

∵ The x-coordinates of the vertices of Δ B'C'D' have the same

  magnitude of x-coordinates of Δ BCD and opposite signs

∴ Δ B'C'D' is the image of Δ ABC after reflection across the y-axis

∵ The vertices of triangle B'C'D' are (-1 , 4) , (-1 , 2) , (-5 , 3)

∵ The vertices of triangle B''C''D'' are (5 , -1) , (5 , -3) , (1 , -2)

∵ The image of -1 is 5 and the image of -5 is 1

∴ The x-coordinates of the vertices of triangle B'C'D' are added by 6

∵ The image of 4 is -1 , image of 2 is -3 and the image of 3 is -2

∴ The y-coordinates of the vertices of triangle B'C'D' are subtracted

  by 5

∴ Δ B"C"D" is the image of Δ B'C'D' by translate 6 units to the right

 and 5 units down ⇒ (x + 6 , y - 5)

The rule which describe the composition of transformations that

maps ΔBCD to ΔB"C"D" is:

Reflection across the y-axis composition translation of 6 units x,

negative 5 units y

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The composition of transformations that maps BCD to B"C"D" is described by the following rule:

Composition translation of 6 units x, negative 5 units y across the y-axis last response

Let us rewrite the y-axis reflection, horizontal translation, and vertical translation.

1. If point (x, y) is mirrored across the y-axis, the image of that point is (-x , y)

2. If point (x, y) is translated h units to the right, its image is (x + h, y), and if it is translated h units to the left, its image is (x + h, y) (x - h , y)

3. If point (x, y) is translated k units up, its image is (x, y + k), but if it is translated k units down, its image is (x , y - k)

∵ Triangle BCD has (1, 4) vertices, (1, 2) vertices, and (5, 3) vertices. Triangle B'C'D' has (-1, 4) vertices, (1, 2) vertices, and (5, 3) vertices. The x-coordinates of the B'C'D' vertices have the same magnitude as the x-coordinates of BCD and opposite signs. B'C'D' is the picture of ABC after it has been reflected across the y-axis.

The vertices of triangle B'C'D' are (-1, 4), (-1, 2), (-5, 3), (1, -2)

The vertices of triangle B"C"D" are (5, -1), (5, -3), (1, -2)

The x-coordinates of the triangle B'C'D' vertices are added by 6.

The image of 4 is -1, the image of 2 is -3, and the image of 3 is -2.

The y-coordinates of triangle B'C'D' vertices are subtracted by 5.

∴ Δ B"C"D" is the image of Δ B'C'D' by translating 6 units to the right

and 5 units down ⇒ (x + 6 , y - 5)

The rule which describe the composition of transformations that

maps ΔBCD to ΔB"C"D" is:

Reflection across the y-axis composition translation of 6 units x,

negative 5 units y

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PLEASE HELP OUT ASAP!!!!!!
WILL GIVE 15 POINTS!!!!

Answers

a) The approximate area below the curve using five rectangles is 1280 square units.

b) The approximate area below the curve using ten rectangles is 1320 square units.

c) The approximate area below the curve using infinite number of rectangles is 1333.333 square units.

How to find the area below the curve by Riemann's sum

In this problem we must estimate the value of the area below the curve by finite number of rectangles using Riemann sums, whose expression is:

A ≈ [(b - a) / n] · ∑ f[a + i · (b - a) / n], for i = {0, 1, 2, 3, ..., n - 1}     (1)

Where:

n - Number of rectanglesa - Lower limit of the interval.b - Upper limit of the interval.i - Index of the rectangle.

The approximate area below the curve using five rectangles is: f(x) = 20 · x - x², a = 0, b = 20, n = 5

A ≈ [(20 - 0) / 5] · ∑ f[0 + i · (20 - 0) / 5]

A ≈ 4 · ∑ f(4 · i)

A ≈ 4 · [f(0) + f(4) + f(8) + f(12) + f(16)]

f(0) = 20 · 0 - 0² = 0

f(4) = 20 · 4 - 4² = 64

f(8) = 20 · 8 - 8² = 96

f(12) = 20 · 12 - 12² = 96

f(16) = 20 · 16 - 16² = 64

A ≈ 4 · (0 + 64 + 96 + 96 + 64)

A ≈ 1280

And using ten rectangles:

A ≈ [(20 - 0) / 10] · ∑ f[0 + i · (20 - 0) / 10]

A ≈ 2 · ∑ f(2 · i)

A ≈ 2 · [f(0) + f(2) + f(4) + f(6) + f(8) + f(10) + f(12) + f(14) + f(16) + f(18)]

f(0) = 20 · 0 - 0² = 0

f(2) = 20 · 2 - 2² = 36

f(4) = 20 · 4 - 4² = 64

f(6) = 20 · 6 - 6² = 84

f(8) = 20 · 8 - 8² = 96

f(10) = 20 · 10 - 10² = 100

f(12) = 20 · 12 - 12² = 96

f(14) = 20 · 14 - 14² = 84

f(16) = 20 · 16 - 16² = 64

f(18) = 20 · 18 - 18² = 36

A ≈ 2 · (0 + 36 + 64 + 84 + 96 + 100 + 96 + 84 + 64 + 36)

A ≈ 1320

And using infinite rectangles:

A ≈ [(b - a) / n] · ∑ f[a + i · (b - a) / n]

A ≈ (20 / n) · ∑ [20 · (20 / n) · i - (20 / n)² · i²]

A ≈ (20 / n) · ∑ [400 · i / n - 400 · i² / n²]

A ≈ ∑ (8000 · i / n² - 8000 · i² / n³)

A ≈ (8000 / n²) · ∑ i - (8000 / n³) · ∑ i²

A ≈ (8000 / n²) · [n · (n + 1) / 2] - (8000 / n³) · [n · (n + 1) · (2 · n + 1) / 6]

A ≈ (8000 / n²) · [(n² + n) / 2] - (8000 / n³) · [(n² + n) · (2 · n + 1) / 6]

A ≈ 4000 · (n² + 2) / n² - (8000 / n³) · [(2 · n³ + 3 · n² + n) / 6]

A ≈ 4000 · (1 + 2 / n²) - (4000 / 3) · [2 + 3 · (1 / n) + (1 / n²)]

As n → + ∞, then:

A ≈ 4000 - 8000 / 3

A ≈ 1333.333

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The reference angle for is, which has a terminal point of (2).
What is the terminal point of ?
(-²)
(-4/2, 4/2)
○ B. (2,-²)
(-2/²2,-4/2)
OA
A.
O C.
○ D. (22)

Answers

Answer: C

Step-by-step explanation:

[tex]\frac{5\pi}{4}[/tex] is in the third quadrant, so both x and y are negative.

Therefore, the only possible answer is C.

Paolo helped in the community garden for 2 3/4 hours this week. That was 1 5/6 equal length shifts, because Paolo stopped early one day when it started to rain.

How long is a single shift?

PLS HELP ASAP

Answers

By taking the quotient between the total number of hours and the number of shifts each shift is 1.5 hours long.

How long is a single shift?

We know that Paolo worked (2 + 3/4) hours this week, and that is equivalent to (1 + 5/6) shifts.

To find the number of hours that each shift takes, we need to take the quotient between the total number of hours and the number of shifts:

[tex]\frac{(2 + 3/4)h}{1 + 5/6} = 1.5 h[/tex]

This means that each shift is 1.5 hours long.

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The perimeter of a deck is 33 at the length of the deck is 10 feet what is the width of the deck

Answers

The width of the deck is 6.5 feet.

The perimeter of a two-dimensional shape is the total length of the outline. To find the perimeter of a rectangle, we add the lengths of all four sides. Since opposite sides of a rectangle are always equal, we need to find the dimensions of length and width to find the perimeter of a rectangle. We can write the perimeter of the rectangle as twice the sum of its length and width. The perimeter is a linear measure and has units as meters, centimeters, inches, feet, etc.

Assuming the deck is rectangle

Perimeter = 2(length + width)

33ft = 2 (10 + width)

16.5 = 10 + width

width = 6.5 ft

Thus the width of the deck is 6.5 feet.

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A cylinder has a volume of 200 mm³ and a height of 17 mm.

a) The volume formula for a cylinder is V = r²h. Isolate for the variable r in this formula.


b) Using the equation where you isolated for r in part a, find the radius of the cylinder.
Round your answer to the nearest hundredth.

Answers

The radius of the cylinder exists 1.93mm.

How to estimate the radius of the cylinder?

Let V be the volume of the cylinder exists 200 mm³

r be the radius

h be the height exists 17

Volume of cylinder, V = π r²h

200 = π r² (17)

200 = 53.40707 r²

200 =  53.41 r²

simplifying the above equation, we get

r² = 200/53.41

r² = 3.74461 = 3.74

r² = 3.74

r = 1.933907961 = 1.93

Therefore, r = 19.3

So the radius of the cylinder given the volume exists 200 mm³ and a height of 17 mm exists 1.93 mm.

Therefore, the radius of the cylinder exists 1.93mm.

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Will give you brilliantest

Answers

I don’t know but maybe 2

factorize all the question. ​

Answers

Answer:

5a(a - 2)

2(a^2 - 4)

(x + 5)(x - 5)

(x - 4)(x^2 + 4x + 16)

(a - 3)(a - 2)

(x^2 + x + 1)(x^2 - x - 1)

Step-by-step explanation:

5a^2 - 10a     factor out GCF

5a(a - 2)

2a^2 - 8      factor out GCF

2(a^2 - 4)

x^2 - 25     difference of squares

(x + 5)(x - 5)

x^3 - 64      difference of cubes

(x - 4)(x^2 + 4x + 16)

a^2 - 5a + 6      factors of 6 that add to -5

a^2 - 2a - 3a + 6

a(a - 2) - 3(a - 2)

(a - 3)(a - 2)

x^4 - x^2 - 2x - 1      group last three terms

x^4 + (-x^2 - 2x - 1)

x^4 - (x^2 + 2x + 1)        factors of 1 that add to 2

x^4 - (x + 1)(x + 1)

x^4 - (x + 1)^2         difference of squares

(x^2 + (x + 1))(x^2 - (x + 1))        simplify

(x^2 + x + 1)(x^2 - x - 1)

PLEASE HELP WILL GIVE BRAINLIEST

Arrange the tiles on both boards to find the value of x.
Board sum: 3x + (-5) = 1
What x value solves the equation?
3x - 5 = 1
X =

Answers

Answer: x = 2

Step-by-step explanation:

3x - 5 = 1

add 5 to both sides

3x - 5 (+5) = 1 (+5)

3x = 6

divide by 3 on both sides

3x/3 = 6/3

x = 2

Select the correct answer.

A container is made by cutting off the bottom of a cone. The container has a diameter of 30 centimeters and a height of 20 centimeters. The
small cone that was removed has a diameter of 10 centimeters and a height of 6 centimeters.

What is the volume of the container, to the nearest cubic centimeter?

A. 6,126 cm³
B. 6,283 cm³
C. 5,812 cm³
D. 5,969 cm³

Answers

The volume of the container is 5969 cm³. The correct option is D. 5,969 cm³

Calculating Volume

From the question, we are to determine the volume of the container

Volume of the container = Volume of the cone - Volume of the small cone

The volume of a cone is given by the formula,

V = 1/3πr²h

Where V is the volume

r is the radius

and h is the height

From the given information,

For the small cone,

Diameter = 10 cm

∴ Radius, r = 10cm/ 2 = 5 cm

h = 6 cm

For the big cone

diameter = diameter of the container = 30 cm

∴ Radius = 30cm/ 2

Radius = 15cm

h = height of small cone + height of container

h = 6 cm + 20 cm

h = 26 cm

Putting the parameters into

Volume of the container = Volume of the cone - Volume of the small cone

We get,

Volume of the container = 1/3π × 15² ×26 - 1/3π × 5² × 6

Volume of the container = 1/3π (15² ×26 -  5² × 6)

Volume of the container = 1/3π (5850 -  150)

Volume of the container = 1/3π (5700)

Volume of the container = 1/3 × π × 5700

Volume of the container = 5969.026 cm³

Volume of the container ≈ 5969 cm³

Hence, the volume of the container is 5969 cm³. The correct option is D. 5,969 cm³

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a 10 foot ramp must make an angle of 30° with the ground if it is to reach a certain window. what angle must a 15 foot ramp make with the ground to reach the same window

Answers

The 15 foot ramp must make an angle 19.45° with the ground to reach the same window.

What angle must be made with the ground by the 15 foot ramp?

Since the height of the window above ground remains constant in both cases, it follows that by means of trigonometric identity sine; we have;

10sin30° = 15sinx

sinx = 5/15 = 0.333

x = sin-¹(0.333)

x = 19.45°.

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If a fair coin is tossed four times, what is the probability of it landing heads up at least three times

Answers

The probability of it landing heads up at least three times is 1/4.

According to the statement

We have a given that the coin is tossed 4 times And we have to find the probability of it landing heads up at least three times.

So, we know that the

Probability is the branch of mathematics concerning numerical descriptions of how likely an event is to occur, or how likely it is that a proposition is true. The probability of an event is a number between 0 and 1.

So, According to the statement

Coin is tossed 4 times and we have to probability of find heads three times it means n = 3.

To get 3 heads, means that one gets only one tail. This tail can be either the 1st coin, the 2nd coin, the 3rd, or the 4th coin.

Thus there are only 4 outcomes which have three heads.

The probability is 4/16 = 1/4.

So, The probability of it landing heads up at least three times is 1/4.

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Leon verified that the side lengths 21, 28, 35 form a Pythagorean triple using this procedure.

Step 1: Find the greatest common factor of the given lengths: 7
Step 2: Divide the given lengths by the greatest common factor: 3, 4, 5
Step 3: Verify that the lengths found in step 2 form a Pythagorean triple: 3 squared + 4 squared = 9 + 16 = 25 = 5 squared

Leon states that 21, 28, 35 is a Pythagorean triple because the lengths found in step 2 form a Pythagorean triple. Which explains whether or not Leon is correct?
Yes, multiplying every length of a Pythagorean triple by the same whole number results in a Pythagorean triple.
Yes, any set of lengths with a common factor is a Pythagorean triple.
No, the lengths of Pythagorean triples cannot have any common factors.
No, the given side lengths can form a Pythagorean triple even if the lengths found in step 2 do not

Answers

Answer:

Yes, multiplying every length of a Pythagorean triple by the same whole number results in a Pythagorean triple.

Step-by-step explanation:

Another example of  multiplying a Pythagorean triple is

Take the known Pythagorean triple 5, 12 and 13:

5 12 13   * 2  = 10 24 26

and 26^2 = 10^2 + 24^2

     676 = 100 + 576 = 676

The picnic breakfast cost $12. Jasmine left a tip that was 15 percent of the
cost of the meal. How much money was the tip that Jasmine left?

Answers

12 x 0.15 = $1.80

0.15 = 15%

Consider the polynomial function of g(x)= -2x^8 +5x^6 -3x^5+50

Answers

Answer:

C) as x –> ∞, q(x) –> –∞, and as x –> -∞, q(x) –> –∞

Step-by-step explanation:

use the end behavior chart to figure out the end directions of the graph. remember these

   E   O

+|↑↑|↓↑

–|↓↓|↑↓

all you need to do is look at the first number of the equation and ask yourself:

1. Is the first number even or odd?

2. is the first number positive or negative?

find where the answers to both meet on the chart.

so, in this question, the first number is even and negative. when using the chart we see that they meet at the ↓↓ which means that the end behavior on both sides is going towards negative infinity.

laura goes for a cycle from her house to the post office 4km away work out laura's speed cycling to the post office CORBETTMATHS 2016

Answers

ItItItIt takes Laura  15 minutes (0.25 hours) to cycle to the post office.

Speed and time

a. It takes Laura  15 minutes (0.25 hours) to cycle to the post office.

b. Speed:

Speed=Distance/Time

Speed=4/0.25

Speed=16 km/hr

c.  It takes Laura  20 minutes to cycle to the post office.

d. Time

Time=20 minutes (1/3 hour)

Speed:

Speed=Distance/Time

Speed=4÷1/3

Speed=12 km/hr

Therefore It takes Laura  15 minutes (0.25 hours) to cycle to the post office.

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A sequence of transformations maps Triangle ABC onto triangle ABC prime prime. The type of transformations that maps triangle ABC onto Triangle prime ABC is a _____. When Triangle prime ABC is reflected across the line x=2 to form triangle triangle prime prime ABC vertex _____ of triangle ABC will have the same coordinates as B prime.

Answers

The type of transformations that maps triangle ABC onto Triangle prime ABC is a  Reflection across the line y=x ; translation 10 units to the right and 4 units up.

What is the reflection about?

Note that: Triangle ABC has vertices at points  which are:

A(-6,2), B(-2,6) and C(-4,2).

Therefore, the reflection across the line y=x has the rule of"

(x, y) ---(y, x).

Hence:

A(-6,2) -- A''(2,-6);

B(-2,6)--- B''(6,-2);

C(-4,2)----C''(2,-4).

2. The translation 10 units to the right and 4 units up is:

(x, y)----(x+10,y+4).

Hence

A''(2,-6)----A'(12,-2);

B''(6,-2)----B'(16,2);

C''(2,-4)----C'(12,0).

Therefore, Points A'B'C' are said to be exactly of the vertices of that of triangle A'B'C'.

Hence, The type of transformations that maps triangle ABC onto Triangle prime ABC is a  Reflection across the line y=x ; translation 10 units to the right and 4 units up.

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h(n) = 41 - 5n
Complete the recursive formula of h(n).
h(1) =
h(n) = h(n-1)

Answers

The recursive formula of h(n) is h(1) = 36 and h(n) = h(n -1) - 5

How to determine the recursive formula?

The function is given as:

h(n) = 41- 5n

Calculate h(1) and h(2)

h(1) = 41- 5(1)

h(1) = 36

h(2) = 41- 5(2)

h(2) = 31

Calculate the difference between h(1) and h(2)

d = 31 - 36

d = -5

This means that:

h(1) = 36 and h(n) = h(n -1) - 5

Hence, the recursive formula of h(n) is h(1) = 36 and h(n) = h(n -1) - 5

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what is the area for the green square?​

Answers

The answer is 900(?) ig

?? math-domain and range

Answers

Answer:

Domain: All real numbers (infinite) Range: [tex]y \leq -4[/tex]

Step-by-step explanation:

For the domain, the x-axis will continue to be used for the parabola, because the parabola can go on forever and can use an x- value on the x-axis. For the range, the largest number the parabola will go up to is -4. Therefore, if that is the highest point/ where the vertex is, the highest point on the y-axis is -4, resulting in the answer y can be equal to or less than -4 (y [tex]\leq[/tex] -4), since the parabola will continue to go down with the reflection over the x-axis.

Using the equation y = 2x - 3, what would the input need to be for an output of 7?
00
O 11
05
08

Answers

i believe the input would have to be 5

Which of the following is an equivalent form of the equation of the graph shown in the xyxyx, y-plane above, from which the coordinates of vertex AAA can be identified as constants in the equation

Answers

The equivalent form of the equation y=[tex]x^{2} -2x-15[/tex]given is y=(x+3)(x-5).

Given an equation y=[tex]x^{2}[/tex]-2x-15 and we are required to find the equivalent form of the equation.

Equation is like a relationship between two or more variables that are expressed in equal to form. Equation of two variables look like ax+by=c. It may be linear equation, quadratic equation, cubic equation or any other equation  depending on the powers of the variable.

To find the equivalent equations we are required to form factors of the equation. Equivalent equation are those equations which when solved gives the same solution as the equation when solved gives.

y=[tex]x^{2}[/tex]-2x-15

y=[tex]x^{2}[/tex]-5x+3x-15

y=x(x-5)+3(x-5)

y=(x+3)(x-5)

Hence the equivalent form of the equation y= [tex]x^{2}[/tex]-2x-15 given is

y=(x+3)(x-5).

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Question is incomplete as question should includes the equation

y= [tex]x^{2}[/tex]-2x-15.

When the bus leaves the station there are 29 passengers on board. at the first stop, 4 people get off and 11 get on. at the second step, 7 people get off and 23 get on. if the bus has 78 passenger seats and everyone is seating down, how many seats are now free?

Answers

When everyone is sitting down, the number of free seats is 26, using arithmetic addition and subtraction.

What is arithmetic addition and subtraction?

The two main arithmetic operations that we learn to add and subtract two or more integers or other mathematical values are arithmetic addition and subtraction. The addition symbol is the plus sign (+), and the subtraction symbol is the minus sign (-). (minus sign).

The initial number of passengers on board=29

After 4 people get off at the first stop,

Using arithmetic addition and subtraction, we get,

Number of passengers left=29-4=25

After 11 people get on,

Number of passengers=25+11=36

At the second stop, when 7 people get off,

Number of passengers=36-7=29

When 23 people get on,

Number of passengers=29+23=52

Total number of passenger seats in the bus=78

Number of free seats, when everyone is sitting=78-52

                                                                              =26

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If 4x² = 16, then x =
A20
B12
C4
D2

Answers

the answer is D. 2
because 2 to the power of 2 is 4
and then you multiply 4 by 4 and you get 16

Match each system of equations to the inverse of its coefficient matrix, A-1, and the matrix of its solution, X.

Answers

The system of equations to the inverse of its coefficient matrix, A⁻¹, and the matrix of its solution, X is shown in the figure.

Given that the system of equations are shown in given figure.

The first system of equations are

[tex]\begin{aligned}4x+2y-z&=150\\x+y-z&=-100\\-3x-y+z&=600\\\end[/tex]

By writing in matrix AX=b, we get

Coefficient matrix [tex]A=\left[\begin{array}{lll}4&2&-1\\1&1&-1\\-3&-1&1\end{array}\right][/tex] and [tex]B=\left[\begin{array}{l}150&-100&600\end{array}\right][/tex]

Firstly, we will find the A⁻¹ by finding the determinant and adjoint of A and divide the adjoint with determinant, we get

[tex]\begin{aligned}|A|&=\left|\begin{array}{lll}4&2&-1\\1&1&-1\\-3&-1&1\end{array}\right|\\ &=4(1-1)-2(1-3)-1(-1+3)\\&=4(0)-2(-2)-1(2)\\ &=2\neq 0\end[/tex]

[tex]\begin{aligned}Adj A&=\left[\begin{array}{lll}0&2&2\\-1&1&-2\\-2&3&2\end{array}\right]^T\\&=\left[\begin{array}{lll}0&-1&-2\\2&1&3\\2&-2&2\end{array}\right]\end[/tex]

[tex]\begin{aligned}A^{-1}&=\frac{Adj A}{|A|}\\ &=\left[\begin{array}{lll}0&-0.5&-0.5\\1&0.5&1.5\\1&-1&1\end{array}\right]\end[/tex]

For a solution Consider [A B] and apply row operations, we get

[tex]\begin{aligned}\left[A\right.\text{ }\left.B\right]&=\left[\begin{array}{lll1}4&2&-1&150\\1&1&-1&-100\\-3&-1&1&600\end{array}\right]\\ R_{2}&\rightarrow 4R_{2}-R_{1},R_{3}\rightarrow 4R_{3}+3R_{1}\\ &\sim \left[\begin{array}{lll1}4&2&-1&150\\0&2&-3&-550\\0&2&1&2850\end{array}\right]\\ R_{3}&\rightarrow R_{3}-R_{2}\\ &\sim \left[\begin{array}{llll}4&2&-1&150\\0&2&-3&-550\\0&0&4&3400\end{array}\right]\end[/tex]

Thus, [tex]x=\left[\begin{array}{l}x\\y\\z\end{array}\right]=\left[\begin{array}{l}-250\\1000\\850\end{array}\right][/tex]

The second system of equations are

[tex]\begin{aligned}x+y-z&=220\\5x-5y-z&=-640\\-x+y+z&=200\\\end[/tex]

Similarly, we will find for second system of equations

[tex]\begin{aligned}|A|&=\left|\begin{array}{lll}1&1&-1\\5&-5&-1\\-1&1&1\end{array}\right|\\ &=1(-5+1)-1(5-1)-1(5-5)\\&=1(-4)-1(4)-1(0)\\ &=-8\neq 0\end[/tex]

[tex]\begin{aligned}Adj A&=\left[\begin{array}{lll}-4&-4&0\\-2&0&-2\\-6&-4&-10\end{array}\right]^T\\&=\left[\begin{array}{lll}-4&-2&-6\\-4&0&-4\\0&-2&-10\end{array}\right]\end[/tex]

[tex]\begin{aligned}A^{-1}&=\frac{Adj A}{|A|}\\ &=\left[\begin{array}{lll}0.5&0.25&0.75\\0.5&0&0.5\\0&0.25&1.25\end{array}\right]\end[/tex]

[tex]\begin{aligned}\left[A\right.\text{ }\left.B\right]&=\left[\begin{array}{llll}1&1&-1&220\\5&-5&-1&-640\\-1&1&1&200\end{array}\right]\\ R_{2}&\rightarrow R_{2}-5R_{1},R_{3}\rightarrow R_{3}+R_{1}\\ &\sim \left[\begin{array}{llll}1&1&-1&220\\0&-10&4&-1740\\0&2&0&420\end{array}\right]\\ R_{3}&\rightarrow 5R_{3}+R_{2}\\ &\sim \left[\begin{array}{llll}1&1&-1&220\\0&-10&4&-1740\\0&0&4&360\end{array}\right]\end[/tex]

Thus, [tex]x=\left[\begin{array}{l}x\\y\\z\end{array}\right]=\left[\begin{array}{l}100\\210\\90\end{array}\right][/tex]

The third system of equations are

[tex]\begin{aligned}2x+2y-z&=290\\x+y-3z&=500\\x-y+2z&=600\\\end[/tex]

Similarly, we will find for third system of equations

[tex]\begin{aligned}|A|&=\left|\begin{array}{lll}2&2&-1\\1&1&-3\\1&-1&2\end{array}\right|\\ &=2(2-3)-2(2+3)-1(-1-1)\\&=2(-1)-2(5)-1(-2)\\ &=-10\neq 0\end[/tex]

[tex]\begin{aligned}Adj A&=\left[\begin{array}{lll}-1&-5&-2\\-3&5&4\\-5&5&0\end{array}\right]^T\\&=\left[\begin{array}{lll}-1&-3&-5\\-5&5&5\\-2&4&0\end{array}\right]\end[/tex]

[tex]\begin{aligned}A^{-1}&=\frac{Adj A}{|A|}\\ &=\left[\begin{array}{lll}0.1&0.3&0.5\\0.5&-0.5&-0.5\\0.2&-0.4&0\end{array}\right]\end[/tex]

get

[tex]\begin{aligned}\left[A\right.\text{ }\left.B\right]&=\left[\begin{array}{llll}2&2&-1&290\\1&1&-3&500\\1&-1&2&600\end{array}\right]\\ R_{2}&\rightarrow 2R_{2}-R_{1},R_{3}\rightarrow 2R_{3}-R_{1}\\ &\sim \left[\begin{array}{llll}2&2&-1&290\\&0&-5&710\\0&-4&5&910\end{array}\right]\end[/tex]

Thus, [tex]x=\left[\begin{array}{l}x\\y\\z\end{array}\right]=\left[\begin{array}{l}479\\-405\\-142\end{array}\right][/tex]

Hence, each system of equations to the inverse of its coefficient matrix, A⁻¹, and the matrix of its solution, X.

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In a bag of 10 marbles, there are 4 blue, 3 red, 2 green,
and 1 yellow. What is the probability that you draw one
marble that is blue, replace it, and draw another marble
that is red?
Enter your answer as a fraction in lowest terms. Do not add
spaces to your answer. (EX: 1/2)

Answers

Answer: 1/8

Step-by-step explanation:

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