Determine the molarity of a solution that contains 30 moles naoh in 0.80 liters of solution?

Answers

Answer 1

Taking into account the definition of molarity,  the molarity of a solution that contains 30 moles naoh in 0.80 liters of solution is 37.5 [tex]\frac{moles}{liters}[/tex].

Definition of molarity

Molar concentration or molarity is a measure of the concentration of a solute in a solution and indicates the number of moles of solute that are dissolved in a given volume.

The molarity of a solution is calculated by dividing the moles of solute by the volume of the solution:

[tex]Molarity=\frac{number of moles}{volume}[/tex]

Molarity is expressed in units [tex]\frac{moles}{liters}[/tex].

This case

In this case, you have:

number of moles= 30 molesvolume= 0.80 L

Replacing in the definition of molarity:

[tex]Molarity=\frac{30 moles }{0.80 L}[/tex]

Solving:

Molarity= 37.5 [tex]\frac{moles}{liters}[/tex]

Finally, the molarity of a solution that contains 30 moles naoh in 0.80 liters of solution is 37.5 [tex]\frac{moles}{liters}[/tex].

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Related Questions

Which describes the law of conservation of matter?
O A. Chemical reactions cannot happen.
B. Atoms cannot be created or destroyed in a reaction.
OC. Atoms are not involved in chemical reactions.
OD. Molecules cannot change into other molecules during a reaction.
SUBMIT

Answers

Answer:

answer is B

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Insulating materials are composed of atoms with?

Answers

Insulating materials are composed of atoms with tightly bound outer electrons.

What is Insulating Material ?

The material that stop the flow of Sound, Heat and Electricity by them are called Insulating Material. Insulator are the materials whose atoms have tightly bound outer electrons because electrons are not free to shared by neighboring atoms.

Examples: Glass, Plastic, Rubber, Air and Wood.

What are the types of Insulating Material ?

There are mainly three types of Insulating Material:

Heat Insulator Electricity Insulator Sound Insulator

Thus from the above conclusion we can say that Insulating materials are composed of atoms with tightly bound outer electrons.

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Molecular weight and configurational stability of poly [(fluorophenyl) acetylene]s prepared with metathesis and insertion catalysts

Answers

A detailed article on formation of poly [(fluorophenyl) acetylene]s prepared with metathesis and insertion catalysts has been given below.

What is Molecular weight and configurational stability of poly [(fluorophenyl) acetylene]s?By polymerizing (2-fluorophenyl)acetylene, (3-fluorophenyl)acetylene, and (4-fluorophenyl)acetylene with catalysts [Rh(1,5-cyclooctadiene) OCH3]2, high-cis PFPhAs and tungsten(VI) oxychloride/tetraphenyltin, respectively, PFPhAs have been created.Size exclusion chromatography, 1H-NMR, and UV-vis methods were used to investigate the molecular weight and configurational stability of both PFPhAs series under varied circumstances at room temperature.The rate of degradation was independent of the F-position on the Ph ring for all samples while they were in the solid state and exposed to the environment. For high-cis polymers compared to their cis/trans counterparts, the rate of breakdown in the tetrahydrofuran solution increased by up to three orders of magnitude. In an aerated tetrahydrofuran solution, there was considerable cis-to-trans isomerization along with the degradation of high-cis PFPhAs.The F-position on the Ph ring showed the similar dependence on the rate of degradation and isomerization. It was proposed that cis-to-trans isomerization, which increases the amount of unpaired electrons on the main chains, hastened the degradation of high-cis PFPhAs in solution. The ortho-substituted isomers shown increased stability compared to the meta- and para-substituted isomers in both the high-cis and cis/trans series of polymers.

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Board cases involving eligibility or disciplinary issues that are resolved through a board agreed order

Answers

Board instances involving eligibility or disciplinary issues that are addressed by a board-approved order public records and accessible on the BON's web page.

BON's web page

Board Position Statements are a way to give nurses guidance on topics that are important to the Board and relate to the safety of the public, but they do not have the legal force of law. In the context of the position statement's overall intent, each position statement is intended to offer direction. Board position statements are examined every year to determine their applicability and accuracy in light of current practice, the Nursing Practice Act, and Board regulations. In January 2022, the Board conducted its most recent evaluation.

It is possible to find a concise summary of the substance of the Position Statements, although it does not include all the specifics that are included in each Position Statement.

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The molecule CH₂O contains two single bonds and one double bond. True or false

Answers

Answer:

The answer to your question is True

Explanation:

CH2O is a polar molecule. It has three polar bonds that are arranged asymmetrically, thus allowing their dipole moments to add up and give the molecule an overall dipole moment. CH2O has a central carbon atom that forms two single bonds with the two hydrogen atoms and a double bond with the oxygen atom.

I hope this helps and have a good day!

The enthalpy of vaporization of Bromine is 15.4 kJ/mol. What is the energy change when 80.2 g of Br2 condenses to a liquid at 59.5°C?

Answers

The enthalpy of vaporization of Bromine is 15.4 kJ/mol. -7.7 kJ is the energy change when 80.2 g of Br₂ condenses to a liquid at 59.5°C.

What is Enthalpy of Vaporization ?

The amount of enthalpy or energy that must be added to a liquid substance into gas substance is called Enthalpy of Vaporization. It is also known as Latent heat of vaporization.

How to find the energy change from enthalpy of vaporization ?

To calculate the energy use this expression:

[tex]Q = n \Delta H_{\text{vapo.}[/tex]

where,

Q = Energy change

n = number of moles

[tex]\Delta H_{\text{Vapo.}}[/tex] = Molar enthalpy of vaporization

Now find the number of moles

Number of moles (n) = [tex]\frac{\text{Given Mass}}{\text{Molar mass}}[/tex]

                                   = [tex]\frac{80.2\ g }{159.8\ g/mol}[/tex]

                                   = 0.5 mol

Now put the values in above formula we get

[tex]Q = - n \Delta H_{\text{vapo.}[/tex]         [Negative sign is used because Br₂ condensed here]

   = - (0.5 mol × 15.4 kJ/mol)

   = - 7.7 kJ

Thus from the above conclusion we can say that The enthalpy of vaporization of Bromine is 15.4 kJ/mol. -7.7 kJ is the energy change when 80.2 g of Br₂ condenses to a liquid at 59.5°C.

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What is the electron configuration for a calcium atom? 01s². 2s 2.2p5.3s 2.3p 5.4s¹ 02s², 2s ², 2p5.3s 2.3p 6,4s1 01s 2. 2s 2. 2p5.3s 2.3p 5, 452 Ots1,2s2, 2p5.3s 2.3p5,4s¹​

Answers

Answer:

Ca = 1s²2s²2p⁶3s²3p⁶4s²

Explanation:

Calcium is located in the second column and the 4th row of the periodic table. Thus, there are 2 valence electrons and the highest quantum number is 4. This is represented by 4s². However, all of the previous orbitals and electrons must be listed beforehand, making the entire electron configuration: 1s²2s²2p⁶3s²3p⁶4s².

What is the amount of space occupied by a sample of matter

Answers

The amount of space that matter occupies is called its volume. Solids, liquids, and gases all have volume.

If your client receives a letter from SilverScript requesting proof of Creditable Coverage, and the client has already submitted proof of creditable coverage with the enrollment application, they can ignore the letter.

Answers

If your client receives a letter from SilverScript requesting proof of Creditable Coverage, they can ignore the letter is a false statement

What is Creditable coverage?

Creditable coverage is known to be a form of an health insurance, that consist of prescription drug and also other kinds of health benefit plan that is known to meets  the minimum amount of qualifications.

Note that  the types of creditable coverage plans are group and individual health plans, student health plans,  and others.

It is not right to ignore any letter sent to you concerning the case above as it may be vital and as such, the statement of If your client receives a letter from SilverScript requesting proof of Creditable Coverage, and the client has already submitted proof of creditable coverage with the enrollment application, they can ignore the letter is a wrong/false statement.

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A certain amount of substance has a mass of 120 g and the number of moles is 2. Calculate the molar mass. Group of answer choices

Answers

Answer:

60 g / mole

Explanation:

120 g  / 2 mole   = 60  g/mole

How many moles of helium are in a
45.0 liter tank at 293 K and 15.0 atm?

Answers

Answer:

28.1 moles   (three sig digits)

Explanation:

Using Ideal Gas Law

PV = n RT      looking for 'n'   R = .082057366  L-atm/K-mole

15.0 * 45.0  = n  * .082057366 * 293

n = 28.1 Moles

The number of moles of helium that are in a 45.0-liter tank at 293 K and 15.0 atm is  28.1 Moles.

What are moles?

Moles is the measuring unit that measures the quantity of a substance. Moles is a SI unit.

Helium is the lightest gas, which is used in the tires of an airplane if it is filled in the balloons, the balloon flies in the sky.

Given the volume is 45.0 liter

The pressure is 15.0 atm.

The temperature is 293 K

To calculate the moles, we will use the formula of an ideal gas:

PV = n RT      

R = .082057366 is the gas constant.

We have to calculate the n

Putting the values in the equation

15.0 x 45.0  = n  x .082057366 x 293

n = 28.1 Moles.

Thus, the moles of helium is n = 28.1 Moles.

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What effects doing adding a solute have on the freezing point of the freezing point of a solution

Answers

Answer:

Lowers the freezing point

Explanation:

Lowers the freezing temp

"Freezing point depression is a colligative property observed in solutions that results from the introduction of solute molecules to a solvent. The freezing points of solutions are all lower than that of the pure solvent and is directly proportional to the molality of the solute."

Answer: The temperature at which the solution freezes is lowered

Explanation:

Question 7
What causes metallic bonds to form?
O The attraction between the delocalized electrons and the metal's anions
O The attraction between the delocalized electrons and the metal's valence electrons
O The attraction between the delocalized electrons and the metal's atoms
O The attraction between the delocalized electrons and the metal's cations
< Previous
N

Answers

Answer:

D.) The attraction between the delocalized electrons and the metal's cations

Explanation:

Metallic bonds form between free-floating valence electrons (delocalized electrons) and positively charged metal ions (cations). The negative charge from the electrons and the positive charge from the ions are what form the attraction.

Write the balanced chemical equation for the reaction of aqueous sodium sulfate
and solid calcium chloride to produce aqueous calcium sulfate and solid sodium
chloride

Answers

The equation of the reaction is [tex]Na_2SO_4 (aq) + CaCl_2 (s) --- > CaSO_4 (aq) +2 NaCl (s)[/tex]

What are chemical reactions?

They are reactions involving chemical reactants leading to the formation of chemical products.

The chemical formula for sodium sulfate is [tex]Na_2SO_4[/tex]

The chemical formula for calcium chloride is [tex]CaCl_2[/tex]

The two react to produce calcium sulfate  ([tex]CaSO_4[/tex]) and sodium chloride (NaCl) according to the following equation:

[tex]Na_2SO_4 (aq) + CaCl_2 (s) --- > CaSO_4 (aq) +2 NaCl (s)[/tex]

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Please help me!
List A
(a) Gas pressure
(b) One mole of substance
(c) One mole of any gas
(d) Avogadro's number
List B
(i) 6.02 × 1023
(ii) 22.4 dm³ at STP
(iii) force per unit area
(iv) 6.02 x 1023 particles

Answers

Answer:

(a) Gas pressure ---------------------> (iii) force per unit area

(b) One mole of substance -------------------> (i) 6.02 x 10²³

(c) One mole of any gas ----------------------> (ii) 22.4 dm³ at STP

(d) Avogadro's number -----------------> (iv) 6.02 x 10²³ particles

A volume measured by a graduated cylinder that was marked in 100 mL
increments would be reported to the nearest __________mL

Answers

The volume measured using such a cylinder will be reported to the nearest 10th mL.

Cylinder graduation

10 mL graduated cylinders are always read to the nearest two decimal places.

100 mL graduated cylinders are always read to the nearest 1 decimal place. The nearest 1 decimal place is the same thing as the nearest 10th.

Thus, a reading made using a 100mL increment graduated cylinder would be reported to the nearest 10th mL.

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Why has nuclear fusion been difficult to develop?
A. Fuel for nuclear fusion is very rare.
B. Fusion normally occurs in the vacuum of space and the atmosphere on Earth stops the
reaction.
C. It is hard to recreate the extremely high temperatures and pressures found inside stars.
D. An efficient shape to contain the reaction has not been found.

Answers

Answer:

C. It is hard to recreate the extremely high temperatures and pressures found inside stars.

Explanation:

Nuclear fusion occurs when atomic nuclei are forcefully combined to create a new atomic nuclei or subatomic particles. In nature, this process takes place in our Sun and other stars. Within stars, extremely high temperatures and pressures are achieved and cause nuclear fusion to occur. Humans have not yet been successful in recreating the environment necessary to mimic this process.

The graph below shows how the pH of the soil in
a farmer's field changed over a period of time.
At which point, A, B, C or D, did the farmer apply
lime to the field?

Answers

Answer:

Point B

Explanation:

From 0 - 7 on the pH scale, substances are said to be acidic. At 7, the substance is said to be neutral. From 7 - 14, substances are basic.

Lime is a basic substance. Therefore, when it is added to the soil, one should expect that the soil becomes more basic. On the graph, this should be represented by the line increasing in pH. As such, the point at which lime was added was most likely Point B.

What is rusting? Write its chemical equations.​

Answers

[tex] \huge \quad\quad \underline{ \tt{{Answer}}}[/tex]

Rusting of iron is the most familiar example of corrosion. It is a process in which an iron reacts with atmospheric oxygen and moisture to form a reddish brown substance iron oxide, which is commonly known as rust.

[tex] \: \: \: \: \: \: \: \: \: \: \: \: [/tex]

[tex]\blue{ \star}:[/tex][tex] \sf4fe+ 3O_2+ XH_2O→ 2Fe_2O_3.XH_2O[/tex]

Answer:

Rust is an iron oxide, formed by iron and oxygen reacting in the catalytic presence of water or air moisture. Rusting is an oxidation reaction. This means it involves oxygen reacting with something (in this case, iron in the presence of moisture).

The chemical formula for rusting:

4Fe + 3O2 + 6H2O → 4Fe (OH)3

Hope this helps!

- profparis

is glycine mono functional?

Answers

Answer:

Yes

Explanation:

Answer:it act as a precursor to proteins

Explanation:

A tank at is filled with of dinitrogen monoxide gas and of dinitrogen difluoride gas. you can assume both gases behave as ideal gases under these conditions. calculate the partial pressure of each gas in the tank. round each of your answers to significant digits

Answers

Partial Pressure for dinitrogen monoxide gas is 187 kPa

Partial Pressure for sulfur tetrafluoride gas is 33.4 kPa.

To calculate partial pressure first we need to calculate number of moles (n).

Mole (n) = mass/molar mass

Number of moles of dinitrogen monoxide gas= 17.7/44 gram per mole = 0.4023.

n=0.4023

Number of moles of sulfur tetrafluoride= 7.77/108.1 = 0.07188 moles.

Pressure × volume = number of moles × gas constant, R × temperature.

Pressure = n × R × T/ V.

For dinitrogen monoxide gas -

Partial Pressure = 0.4023 × 8.314 × 280.03 / 5 × 10^-3 = 187 kPa.

Partial pressure of dinitrogen monoxide gas = 187kPa.

For sulfur tetrafluoride gas-

Partial Pressure = 0.07188 × 8.314 ( × 280.03 / 5 × 10^-3) = 33.4 kPa.

Partial pressure of sulfur tetrafluoride = 33.4kPa.

So, Partial pressure of dinitrogen monoxide gas = 187kPa.

Partial pressure of sulfur tetrafluoride = 33.4kPa.

Disclaimer = This question is incomplete. Please find the full content below.

Question:

5.00L tank at 7.03°C is filled with 17.7g of dinitrogen monoxide gas and

7.77g of sulfur tetrafluoride gas

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For what mechanistic reason does g1 of lactase first act as a brønsted acid during catalysis?.

Answers

Answer:  Carboxylation of hydroquinone

Which best describes the oxidizing agent in this reaction?
Cl2(aq) + 2Br–(aq) Right arrow. 2Cl–(aq) + Br2(aq)
Bromine (Br) is the oxidizing agent because it gains an electron.
Bromine (Br) is the oxidizing agent because it loses an electron.
Chlorine (Cl) is the oxidizing agent because it gains an electron.
Chlorine (Cl) is the oxidizing agent because it loses an electron.

Answers

Answer:

» Chlorine (Cl) is the oxidizing agent because it gains an electron.

Explanation:

Oxidization is the process of losing electrons during an ionic reaction.

In the reaction above, aqueous chlorine captures the electrons of bromide ion hence becoming oxidized. In this sense, since aqueous chlorine is the one gaining electrons, it oxidizes bromide to bromine

[tex]{ \rm{Cl _{2(aq)}+ 2Br {}^{ - } _{(aq)} \dashrightarrow 2Cl {}^{ - } _{(aq)} + Br _{2( aq)}}}[/tex]

Answer:

c

Explanation:

edge 2022

Determine the limiting reagent in the following equation for the production of salt and determine the amount of NaCl produced and the mass of excess reagent. (I - 10 marks)

100g 100g
NaHCO3 + HCl —> NaCl + H2O + CO2

Answers

Answer:

Limiting Reagent: NaHCO₃

Amount of NaCl: 69.6 g NaCl

Mass of Excess Reagent: 56.6 g HCl

Explanation:

To find the mass of NaCl, you need to (1) convert mass reactant to moles reactant (via molar mass), then (2) convert moles reactant to moles NaCl (via mole-to-mole ratio from equation coefficients), and then (3) convert moles NaCl to mass NaCl (via molar mass).

Molar Mass (NaHCO₃):

22.990 g/mol + 1.008 g/mol + 12.011 g/mol + 3(15.998 g/mol)

Molar Mass (NaHCO₃): 84.003 g/mol

Molar Mass (HCl): 1.008 g/mol + 35.453 g/mol

Molar Mass (HCl): 36.461 g/mol

Molar Mass (NaCl): 22.990 g/mol + 35.453 g/mol

Molar Mass (NaCl): 58.443 g/mol

100 g NaHCO₃            1 mole                  1 mole NaCl             58.443 g
------------------------  x  ------------------  x  ---------------------------  x  ----------------  =
                                   84.003 g            1 mole NaHCO₃            1 mole

=  69.6 g NaCl

100 g HCl            1 mole               1 mole NaCl          58.443 g
----------------  x  ------------------  x  -----------------------  x  ----------------  =
                           36.461 g             1 mole HCl              1 mole

=  160 g NaCl

Since NaHCO₃ results in the smaller amount of product, it is the limiting reagent. In other words, it is used up before the HCl has the chance to completely react. Therefore, the actual amount of NaCl produced is 69.6 grams.

To find the mass of the excess reagent, you need to calculate the amount of HCl actually used in the reaction. Then, you need to subtract that value from the total amount of HCl.

69.6 g NaCl             1 mole                1 mole HCl             36.461 g
---------------------  x  ------------------  x  -----------------------  x  ----------------  =
                                58.443 g            1 mole NaCl             1 mole

=  43.4 g HCl

Amount Given - Amount Reacted = Mass Excess

100 g HCl - 43.4 g HCl = 56.6 g HCl

You need a 70% alcohol solution. On hand, you have a 135 mL of a 20% alcohol mixture. You also have 85% alcohol mixture. How much of the 85% mixture will you need to add to obtain the desired solution

Answers

To obtain the desired solution:

450 mL of 85% alcohol solution is needed to obtain the desired solution.  

Calculation:

Let x be the amount of the 85% alcohol required

The volume of the resulting 70% alcohol solution will then be = x + 135 ml

135 mL of the 20% alcohol solution contains the amount of "pure" alcohol is =  0.20×135 mL.

The 85% alcohol solution contains x mL of "pure" alcohol = 0.85× x mL.

The total amount of the "pure" alcohol is the sum

=  0.20×135 + 0.85× x mL.

It should be equal to the amount of the "pure" alcohol in the mixture, which is = 0.70× (x+135) ml.

So, your "pure alcohol" equation is,  

=  0.85× x + 0.20×135 = 0.70× (x+135)

Simplify and solve it for x:

0.85x + 0.20×135 = 0.70x + 0.70×135,

0.85x - 0.70x = 0.70×135 - 0.20×135,

0.15x = 67.5

x = 67.5/0.15

= 450mL.

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Which image best represents a solution of distilled water at pH = 7?

Answers

Answer:

nuetral

Explanation:

water has neutral

A proton exits the cyclotron 1. 0 ms after starting its spiral trajectory in the center of the cyclotron. How many orbits does the proton complete during this 1. 0 ms ?.

Answers

Orbits do the proton complete:

A proton exits the cyclotron 1. 0 ms after starting its spiral trajectory in the center of the cyclotron and 1.8 x [tex]10^{4}[/tex] orbits does the proton complete during this 1. 0 ms

Calculation:

(a) The kinetic energy of the proton is given by, K.E. = [tex]\frac{1}{2} m v^{2}[/tex]

v = [tex]\sqrt{\frac{2(K E)}{m}}[/tex]

v = [tex]\sqrt{\frac{2(6.5 \mathrm{MeV})\left(1.6 \times 10^{-19} \mathrm{~J} / \mathrm{eV}\right)}{1.672 \times 10^{-27} \mathrm{~kg}}}[/tex]= 3.5 [tex]\times 10^{7} \mathrm{~m} / \mathrm{s}[/tex]

The radius of the orbit is given by,

r = [tex]\frac{m v}{B q}=\frac{1.672 \times 10^{-27} \mathrm{~kg}\left(3.5 \times 10^{7} \mathrm{~m} / \mathrm{s}\right)}{(1.2 \mathrm{~T})\left(1.6 \times 10^{-19} \mathrm{C}\right)}[/tex] = 0.30 m

Hence, the diameter of the largest orbit just before the proton leaves the orbit is 0.60 m.

(b) The time required to complete one revolution is given by, T=[tex]\frac{2 \pi m}{B q}=\frac{2 \pi\left(1.672 \times 10^{-27} \mathrm{~kg}\right)}{(1.2 \mathrm{~T})\left(1.6 \times 10^{-19} \mathrm{C}\right)}[/tex] =5.48 x [tex]10^{-8}[/tex] s

The number of revolutions made by the proton is given by,

Tn = t

Therefore, n = t/T = [tex]\frac{1 \mathrm{~ms}}{5.48 \times 10^{-8} \mathrm{~s}}[/tex] = 1.8 x [tex]10^{4}[/tex]

Note: your question is incomplete, but most probably your full question was, A medical cyclotron used in the production of medical isotopes

accelerates protons to 6.5 MeV. The magnetic field in the

cyclotron is 1.2 T.

a. What is the diameter of the largest orbit, just before the protons

exit the cyclotron?

b. A proton exits the cyclotron 1.0 ms after starting its spiral

trajectory in the center of the cyclotron. How many orbits

does the proton complete during this 1.0 ms?

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For a second order reaction, if [A]^-1 is plotted vs. time, which corresponds to the slope of the plot?
a. 1/a
b. K
c. 1/k
d. Ln[a]
e. -k

Answers

For a second order reaction, if (A)^-1 is plotted vs. time is straight line with k= slope of the line,Plot the inverse of concentration of a reactnt verus time.

Second order reaction defined as chemical reactions which is the sum of the exponents in the rate of law of the chemical reaction is equal to two.The such reaction is written as the - r=k(A)2 or r= k(A)(B).

Second  order reaction is a type of reaction which is depend on the concentrations of one second order or two first order reactants.Reaction proceeds at rate proportional to the square of the product of the concentration of one reactant, or the product of the concentrations of two reactant.

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A 25.0 mL sample of 0.723 M HClO4 is titrated with a 0.273 M KOH solution. What is the [H ] (molarity) before any base is added

Answers

0.723 is the [H ] (molarity) before any base is added.

the balanced equation for the acid-base reaction is

KOH + HClO₄ ---> KClO₄ + H₂O

stoichiometry of KOH to HClO₄ is 1:1

The number of HClO₄ moles - 0.723 M / 1000 mL/L x 25.0 mL = 0.0181 mol

Number of KOH moles - 0.27 M/ 1000 mL/L x 80.0 mL = 0.0216 mol

KOH is a strong acid and HClO₄ is a strong base therefore complete dissociation takes place.

the acid reacts with base in a 1:1 molar ratio, there's excess base remaining.

excess OH⁻ ions - 0.0216 - 0.0181 = 0.0035 mol

concentration is calculated as the number of moles/volume

volume of solution - 25.0 + 80.0 = 105.0 mL

[OH⁻] = 0.0035 mol / 0.105 L = 0.033 M

pOH = -log [OH⁻]

pOH = -log(0.033 M)

pOH = 1.48

pH can be calculated by knowing the pOH

pH + pOH = 14

pH = 14 - 1.48 = 12.52

pH = -log [H₃O⁺]

[H₃O⁺] = antilog(-12.52)

[H₃O⁺]  = 3.0 x 10⁻¹³ M

0.723 is the [H ] (molarity) before any base is added.

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mass of an atom of element x is equivalent to the total mass of 7 hydrogen atoms. what element represent x ?

Answers

Answer:

lithium

Explanation:

The mass of hydrogen is 1 u, so the mass of element x is 7 u, which is approximately the atomic mass of lithium.

Other Questions
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