Answers
A general cosine function (we could also use a sine function) is written as:
y = A*cos(k*x + p) + M
We will find that the function of the graph is:
f(x) = 2*cos(2*x + 2.09) - 2
Let's return to the general function:
y = A*cos(k*x + p) + M
A is the amplitude, it defines the distance between the value of a maximum and the value of the minimum, such that A is exactly half of that difference.
Here we can see that the maximum is 0, and the minimum is -4
The differene is: 0 - (-4) = 4
Then:
A = 4/2 = 2
f(x) = 2*cos(k*x + p) + M.
M is the midline, this is, the horizontal line that cuts the graph in two halves. Here we can see that the midline is x = -2, then:
M = -2
f(x) = 2*cos(k*x + p) - 2
p is the phase shift.
In the graph, we can see that f(0) = -3, so we have:
f(0) = 2*cos(0 + p) - 2 = -3
cos(p) = -1/2
p = Acos(-1/2) = 2.09
Then we have:
f(x) = 2*cos(k*x + 2.09) - 2
Finally, k is related to the frequency of the function.
We can see that the function does a complete cycle at x = pi
This means that:
f(x) = f(x + pi)
Knowing that the period of a cosine function is 2*pi, then:
k*(x + pi) = k*x + 2*pi
k = 2
Then the equation of the graph is:
f(x) = 2*cos(2*x + 2.09) - 2
If you want to learn more, you can read:
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Answer(s):
[tex]\displaystyle y = 2sin\:(2x + 1\frac{1}{4}\pi) - 2 \\ y = 2cos\:(2x - 1\frac{1}{4}\pi) - 2[/tex]
Step-by-step explanation:
[tex]\displaystyle y = Asin(Bx - C) + D \\ \\ Vertical\:Shift \hookrightarrow D \\ Horisontal\:[Phase]\:Shift \hookrightarrow \frac{C}{B} \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \\ Amplitude \hookrightarrow |A| \\ \\ Vertical\:Shift \hookrightarrow -2 \\ Horisontal\:[Phase]\:Shift \hookrightarrow \frac{C}{B} \hookrightarrow \boxed{-\frac{5}{8}\pi} \hookrightarrow \frac{-1\frac{1}{4}\pi}{2} \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \hookrightarrow \boxed{\pi} \hookrightarrow \frac{2}{2}\pi \\ Amplitude \hookrightarrow 2[/tex]
OR
[tex]\displaystyle y = Acos(Bx - C) + D \\ \\ Vertical\:Shift \hookrightarrow D \\ Horisontal\:[Phase]\:Shift \hookrightarrow \frac{C}{B} \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \\ Amplitude \hookrightarrow |A| \\ \\ Vertical\:Shift \hookrightarrow -2 \\ Horisontal\:[Phase]\:Shift \hookrightarrow \frac{C}{B} \hookrightarrow \boxed{\frac{5}{8}\pi} \hookrightarrow \frac{1\frac{1}{4}\pi}{2} \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \hookrightarrow \boxed{\pi} \hookrightarrow \frac{2}{2}\pi \\ Amplitude \hookrightarrow 2[/tex]
You will need the above information to help you interpret the graph. First off, keep in mind that although this looks EXACTLY like the cosine graph, if you plan on writing your equation as a function of sine, then by all means, go for it, but be careful and follow what is explained here. Now, as you can see, the photograph on the right displays the trigonometric graph of [tex]\displaystyle y = 2sin\:(2x - 1\frac{1}{4}\pi) - 2,[/tex] in which you need to replase “cosine” with “sine”, then figure out the appropriate C-term that will make the graph horisontally shift and map onto the cosine graph [photograph on the left], accourding to the horisontal shift formula above. Also keep in mind that the −C gives you the OPPOCITE TERMS OF WHAT THEY REALLY ARE, so you must be careful with your calculations. So, between the two photographs, we can tell that the sine graph [photograph on the right] is shifted [tex]\displaystyle \frac{\pi}{4}\:unit[/tex] to the right, which means that in order to match the cosine graph [photograph on the left], we need to shift the graph BACKWARD [tex]\displaystyle \frac{\pi}{4}\:unit,[/tex] which means the C-term will be negative. Now, BEFORE we go any further, we must remember that this particular cosine graph [thank goodness it is a cosine graph we are working with] ALREADY has a horisontal shift and does not have a single crest oscıllαtıng about any endpoint on the y-axis. So, in this case we need to figure out how far the FIRST oscıllαtıng crest is from the origin, and that obviously would be [tex]\displaystyle \frac{5}{8}\pi\:units.[/tex] Though, sinse we want the sine equation of this graph, it must be “negative”; so, by perfourming your calculations, you will arrive at [tex]\displaystyle \boxed{-\frac{5}{8}\pi} = \frac{-1\frac{1}{4}\pi}{2},[/tex] in which the value of C is [tex]\displaystyle -1\frac{1}{4}\pi.[/tex] So, the sine equation of the cosine graph, accourding to the horisontal shift, is [tex]\displaystyle y = 2sin\:(2x + 1\frac{1}{4}\pi) - 2.[/tex] Now, with all that being said, in this case, sinse you ONLY have a graph to wourk with, you MUST figure the period out by using wavelengths. So, looking at where the graph hits [tex]\displaystyle [\frac{7}{8}\pi, -2],[/tex] from there to [tex]\displaystyle [-\frac{\pi}{8}, -2],[/tex] they are obviously [tex]\displaystyle \pi\:units[/tex] apart, telling you that the period of the graph is [tex]\displaystyle \pi.[/tex] Now, the amplitude is obvious to figure out because it is the A-term, but of cource, if you want to be certain it is the amplitude, look at the graph to see how low and high each crest extends beyond the midline. The midline is the centre of your graph, also known as the vertical shift, which in this case the centre is at [tex]\displaystyle y = -2,[/tex] in which each crest is extended two units beyond the midline, hence, your amplitude. So, no matter how far the graph shifts vertically, the midline will ALWAYS follow.
**As you can see, this is one of those moments where you will really need to be careful because if you notised, both equations have OPPOCITE horisontal shifts and C-values. Now, the ONLY TIME this occurs is when all crests in a SINUSOIDAL graph cycle half-way in between endpoints. Your best bet is to jot this down for when you see graphs like these in the future.
I am delighted to assist you at any time.
Related Questions
Given 12 consecutive integers, how many ways can three of these integers be selected to give a sum which divides by 4.
Disclaimer: A lot of points to be given, Full explanation required. Not only answer. Remember the sum of the number must be divisible by 4. I think modular arithmetic is the way to solve it, but who knows???
Answers
Answer:
55 waysStep-by-step explanation:
Out of 12 consecutive integers:
3 - divide by 4, so the remainder is 0 3- give remainder of 1 3- give remainder of 2 3 - give remainder of 3Sum of 3 integers will be divisible by 4 if the remainders are:
0 - 0 - 0 ⇒ 1 combination 0 - 1 - 3 ⇒ 3*3 = 9 combinations 0 - 3 - 1 ⇒ 3*3 = 9 combinations 1 - 1 - 2 ⇒ 2*3 = 6 combinations 1 - 2 - 1 ⇒ 2*3 = 6 combinations 2 - 1 - 1 ⇒ 2*3 = 6 combinations 3 - 0 - 1 ⇒ 3*3 = 9 combinations 3 - 1 - 0 ⇒ 3*3 = 9 combinationsSo total number of combinations is:
1 + 9*4 + 6*3 = 55Christine, Dale, and Michael sent a total of 71 messages during the weekend. Dale sent 9 fewer messages than Christine. Michael sent 2 times as many messages as Christine. How many messages did they each send?
Answers
Answer:
Micheal sent 40 messages, Christine sent 20, and Dave sent 11.
Step-by-step explanation:
Christine, Dale, and Michael sent a total of 71 messages
C + D + M = 71
Dale sent 9 fewer messages than Christine
D = C - 9
Michael sent 2 times as many messages as Christine
M = 2C
Plug-in the numbers.
C + C - 9 + 2C = 71
4C - 9 = 71
4C = 80
C = 20
Now, plug in to other equations for other results.
D = (20) - 9
D = 11
M = 2(20)
M = 40
Micheal sent 40 messages, Christine sent 20, and Dave sent 11.
Verify?
40 + 20 + 11 = 71.
Anyone here that can help me with?
Answers
Answer:
D. 16 years old
Step-by-step explanation:
Step 1: Let T be Tien's age and J as Jordan's age (today),
[tex]T=\frac{1}{4}J[/tex]
Step 2: Let T be Tien's age and J as Jordan's age (in 2 years),
[tex]T+2=\frac{1}{3} (J+2)[/tex]
[tex]T=\frac{1}{3}(J+2)-2[/tex]
Step 3: As their age differences will always be similar we can have the two equations above equal to find Jordan's age,
[tex]\frac{1}{4} J=\frac{1}{3}(J+2)-2\\\frac{1}{4}J-\frac{1}{3}J=\frac{2}{3} -2 \\-\frac{1}{12}J= -\frac{4}{3} \\\\J=16[/tex]
For what value of x is the rational expression below equal to zero?
x-4/(x+5)(x-1)
O A. -5
O B. 4
C. -4
O D. 1
Answers
Answer:
x=4
Step-by-step explanation:
(x-4)/(x+5)(x-1)
For this to be equal to zero, the numerator must be zero and the denominator not equal to zero
x-4 = 0
x=4
Please Help! Select the correct systems of equations. Which systems of equations intersect at point A in this graph?
Answers
Answer:
The systems of equation satisfying the problem are
Y= 4x+9
Y= -3x-5
Y= 2x+5.
Y= 5x+11
Y= 3x+7
Y= -x-1
Step-by-step explanation:
From the graph in the figure
The point A ; x= -2,y=1
So the equations that will interest at point A are the equations that both pass through the point A.
To know the equations that pass through the point A we solve them simultaneously.
For
Y = 10x-1
Y= -3x-5
0= 13x +4
X= -4/13..... definitely not this one
For
Y= 4x+9
Y= -3x-5
0= 7x +14
-14= 7x
-2= x
Substituting the value of x into Y= 4x+9
Y= 4x+9
Y= 4(-2)+9
Y = -8+9
Y= 1
So it's definitely this one
Let's check to know if there is any more
Y = 2x+5
Y= x-1
0= x +6
Definitely not this one
For
Y= 2x+5.
Y= 5x+11
0 = 3x+6
-6= 3x
-2= x
Y= 2x+5.
Y=2(-2)+5
Y= 1
Definitely this one
For
Y= 3x+7
Y= -x-1
0 = 4x +8
-8= 4x
-2= x
Y= -x-1
Y= -(-2)-1
Y= +2-1
Y= 1
Definitely this one too
The correct options are system of equations shown by options (B)[tex]Y= 4x+9 \ and \ y = -3x-5[/tex]
(D) [tex]y= 2x+5 and \ y= 5x+11[/tex]
and (E) [tex]y= 3x+7 \ and\ y= -x-1[/tex].
Given, Coordinates of point A is (-2,1).
We have to find which systems of equations intersect at point A in this graph.
The system of equation which satisfy the point A(-2,1) will intersect at point A.
On putting the value of x=-2 and y= 1, in 1st pair
the equation doesn't satisfy.
similarly checking all the options, we find that the below system equations intersect at point A.
[tex]Y= 4x+9 \ and y = -3x-5 \\y= 2x+5 and \ y= 5x+11\\y= 3x+7 \ and y= -x-1[/tex]
Hence the correct options are system of equations shown by options (B), (D) and (E).
For more details follow the link:
https://brainly.com/question/1680887
can someone explain this please?
Answers
Answer:
Hey there!
Our equation can be: 2y+3=4y+2
Hope this helps :)
Answer:
2y+3=4y+2
I hope you got it..
what is the cost of paving a driveway that is 18m long and 4 m wide, if the paving costs $35 per square metre?
Answers
Answer:
$2520
Step-by-step explanation:
→ Work out the area of the drive way
18 m × 4 m= 72 m²
→ Multiply the area by the cost per square metre
72 m² × $35 = $2520
The cost of paving a driveway that is 18m long and 4 m wide, if the paving costs $35 per square metre is $2520.
To calculate the cost of paving the driveway, you need to find the total area of the driveway and then multiply it by the cost per square meter.
The total area of the driveway can be calculated using the formula:
Area = length × width.
Given that the driveway is 18 meters long and 4 meters wide, the area would be:
Area = 18m × 4m
Area = 72 square meters.
Now, find the cost of paving the driveway by multiplying the area by the cost per square meter:
Cost = Area × Cost per square meter
Cost = 72 square meters × $35/square meter
Cost = $2520.
So, the cost of paying the driveway would be $2520.
To learn more on Area click:
https://brainly.com/question/20693059
#SPJ4
What is the volume of a right square pyramid with a height of 3cm and a base that measures 8cm by 8cm?
Answers
Answer:
64 cm^3
Step-by-step explanation:
Volume of a square pyramid is given by (side)^2*(height)/3. The volume of the pyramid in question is (8)^2*(3)/3=64 cm^3
4. Suppose you make $12 an hour as a lifeguard at the community pool during the summer. Let h
represent the number of hours you work in a week. Write an expression that represents the
amount of money you earn in a week and evaluate it for ) = 15.
O 12.; $180
O 12 + 1; $27
7(12.1); $1,260
O5(127); $900
Answers
Answer:
Option A
Step-by-step explanation:
Expression: y = 12h
If h = 15, then:
y = 12(15)
y = $180
Option A
b - 8 = 9
---------------
Answers
Answer:
b-8=9
b=9+8
b=17
Step-by-step explanation:
hope it will help you mark me as a brilliant.
Answer:
b=17
Step-by-step explanation:
b-8=9
first isolate the variable by adding 8 to both sides
this gives us
b=17
If EH = 76, calculate DI.
Answers
Answer:
DI = 38
Step-by-step explanation:
Δ EHC and Δ DIC are similar and ratios of corresponding sides are equal, that is
[tex]\frac{DI}{EH}[/tex] = [tex]\frac{DC}{EC}[/tex] , substitute values
[tex]\frac{DI}{76}[/tex] = [tex]\frac{1}{2}[/tex] ( cross- multiply )
2DI = 76 ( divide both sides by 2 )
DI = 38
Line m and point P are shown below. Part A: Using a compass and straightedge, construct line n parallel to line m and passing through point P. Leave all construction marks. Part B: Explain the process that you used to construct line n.
Answers
Answer:
see the attached
Step-by-step explanation:
In the attachment, we will refer to the circles, bottom-to-top, as circles 1, 2 and 3. The black points of intersection, bottom-to-top, will be referred to by the letters A, B, C, D. The transversal line through the white point (W) and pink point (P) will be line q.
Step 1. Draw line q through point P so it intersects line m at some convenient point. Label that point W.
Step 2. Choose an arbitrary radius for your compass. Here, we have chosen it to be the length WB. It happens to be less than half the length of WP, but that is not a requirement.
Step 3. Draw an arc of the chosen radius centered at W and intersecting line q and line m. Label the intersection points A (on line m) and B (on line q). These intersection points are on circle 1.
Step 4. Draw an arc of the same radius centered at P. It should be a long enough arc that it would intersect the proposed line parallel to m. Label the intersection point on line q with label C. This intersection point is on circle 3.
Step 5. Adjust the compass width (radius) to the distance from A to B. This is the radius of circle 2.
Step 6. Draw an arc centered at C so that it intersects the arc of Step 4. This is circle 2, and you want it to intersect circle 3. Label that point of intersection D.
Step 7. Draw line PD parallel to m.
_____
The point of the construction is to create congruent alternate interior angles AWB and CPD, so that lines AW and PD are parallel.
Harold used 6 centimeters of tape to wrap 3 presents. What is the unit rate?
Answers
Answer:
2cm/present is the unit rate
[tex]\huge\text{Hey there!}[/tex]
[tex]\huge\text{Harold used \underline{\underline{6 centimeters of tape}} to wrap}\\\huge\text{\underline{\underline{3 presents}}. \underline{\underline{\underline{What is the unit rate?}}}}[/tex]
[tex]\huge\boxed{\star \ Formula: \mathsf{\dfrac{a}{b}= unit\ rate \ }\star}[/tex]
[tex]\huge\boxed{\mathsf{Equation\boxed{\rightarrow}\ \dfrac{6}{3} = \boxed{unit\ rate}}}[/tex]
[tex]\huge\boxed{\mathsf{\dfrac{6}{3} = \boxed{\bf unit\ rate}}}\\\\\\\huge\boxed{\mathsf{ 6 \ \boxed{\div} \ 3\ \boxed{= } \ \bf\boxed{\bf unit\ rate}}}\\\\\\\\\huge\boxed{\boxed{=} \bf \ 2}[/tex]
[tex]\huge\boxed{\star\ \textsf{Therefore, the UNIT RATE IS: \bf \boxed{\bf 2}}\ \star}[/tex]
[tex]\boxed{\boxed{\huge\text{Answer: the unit rate is \bf \boxed{\underline{\underline{\underline{\underline{\bf 2}}}}}}}}\huge\checkmark\\\\\huge\text{Good luck on your assignment \& enjoy your day!}\\\\\\\\\huge\boxed{\frak{Amphitrite1040:)}}[/tex]
I need help FAST!!!Make sure you can explain the problem
Answers
Answer:
AB is not a tangent to the circle
Step-by-step explanation:
The angle between a tangent and the radius at the point of contact = 90°
Using Pythagoras' identity to determine if the triangle is right at A
If the square of the longest side is equal to the sum of the squares on the other 2 sides then A is right.
longest side = 15 , then 15² = 225
8² + 9² = 64 + 81 = 145 ≠ 225
Then AB is not a tangent to the circle
What is the answer please
Answers
Answer:
I think it should be (C)
Answer:
B
Step-by-step explanation:
The fastest way to solve this would to plug in a number for x such as 1 in both equations to find which 2 are equivalent.
When you plug 1 into the top equation it equals 3.5, so now we need to find the correct equation below that equals 3.5 when 1 is plugged in for x.
When you plug 1 into equation B you are also left with 3.5.
5. Write down at least five number
pairs to solve the equation
(r - 2)(s + 1) = 100.
Answers
Answer:
1. (52 - 2) (1 + 1) = 1002. (12 - 2) (9 + 1) = 1003. (6 - 2) (24 + 1) = 1004. (3 - 2) (99 + 1) = 1005. (102 - 2) (0 + 1) = 100Step-by-step explanation:
1. let r= 52 and s= 1(52 - 2) (1 + 1) = 10050 × 2 = 1002. let r= 12 and s= 9(12 - 2) (9 + 1) = 10010 × 10 = 1003. let r= 6 and s= 24(6 - 2) (24 + 1) = 1004 × 25 = 1004. let r= 3 and s= 99(3 - 2) (99 + 1) = 1001 × 100 = 1005. let r= 102 and s= 0(102 - 2) (0 + 1) = 100100 × 1 = 100[tex]\tt{ \green{P} \orange{s} \red{y} \blue{x} \pink{c} \purple{h} \green{i} e}[/tex]
The standard normal curve shown below models the population distribution of a random variable. What proportion of the values in the population does not lie between the two z-scores indicated on the diagram? z = -1.2 z = 0.85
Answers
Answer:
31.28%
Step-by-step explanation:
The z score is used in statistics to determine by how many standard deviations the raw score is above or below the mean. If the raw score is above the mean then the z score is positive while if the raw score is below the mean then the z score is negative. It is given by:
[tex]z=\frac{x-\mu}{\sigma}[/tex]
Given the z score z = -1.2 z = 0.85. From the normally distribution table, the probability that a value falls between z = -1.2 and z = 0.85 = P(z < 0.85) - P(z < -1.2) = 0.8023 - 0.1151 = 0.6872
The proportion of values that do not fall between z = -1.2 and z = 0.85 = 1 - 0.6872 = 0.3128 = 31.28%
2,000
10,000
milligrams
grams
6
7
HELPPPPPPPPP
Answers
Answer:
2000 milligrams —> 2 grams
6000 milligrams —> 6 grams
7000 milligrams —> 7 grams
10000 milligrams —> 10 grams
I hope I helped you^_^
-5x-10=10 solve for x
Answers
Answer:
x = -4
Step-by-step explanation:
-5x-10=10
Add 10 to each side
-5x-10+10=10+10
-5x = 20
Divide each side by -5
-5x/-5 = 20/-5
x = -4
Answer: x= -4
Step-by-step explanation:
[tex]-5x-10=10[/tex]
add 10 on both sides
[tex]-5x=20[/tex]
divide -5 on both sides
[tex]20/-5=-4[/tex]
[tex]x=-4[/tex]
calculate with reasons, the size of the unknown indicated angles
pls help !!
Answers
Answer:
x+125+25=180 angles of triangle
x=180-150
x=30
2t(t-1)-t+1 factorise
Answers
Answer:
this is the answer of this question
hoping it will help u
Is {3,…} a defined set
Answers
Answer:
no it's not a defined state it's undefined
Find the missing side. Round answer to the nearest tenth.
Answers
Tanθ = opposite / adjacent
[tex] \tan(32) = \frac{x}{25} \\ 0.624 = \frac{x}{25} \\ x = 15.6 \\ x = 16[/tex]
I hope I helped you ^_^
8 less than half of n
Answers
Answer:
n/2>8
Step-by-step explanation:
Half of N is N/2
And if 8 is less that half of N or N/2
then
N/2 has to be greater than 8
N/2>8
Jonah will cover a cube in wrapping paper. Each edge of the cube is 25 cm long. What is the least amount of
wrapping paper he needs to cover the cube?
15 625 square centimeters
25 square centimeters
37.5 square centimeters
42 25 square centimeters
Save and Exit
Next
Subm
MO
Answers
Answer:
3750 cm²
Step-by-step explanation:
To find the answer, we need to find the surface area of the cube. The surface area formula for a cube is 6a² where a = the length of an edge. We know that a = 25 so the surface area is 6 * 25² = 6 * 625 = 3750 cm².
Answer:
37.5 hopefully this is the answer you were looking for!
Step-by-step explanation:
I am a 2 dimensional shape that has four sides. I have two obtuse angles and two acute angles. I have two different sets of parallel sides. I also have two sides that are one length, and my other two sides are a different length.
Answers
Answer:
Quadrilateral
Step-by-step explanation:
(10 PTS) How do I solve for this? Please show work
Answers
Answer:
4
Step-by-step explanation:
8 ^ 2/3
Rewriting 8 as 2^3
( 2^3) ^ 2/3
We know that a^ b^c = a^ (b*c)
2 ^ ( 3 * 2/3)
2 ^ 2
4
Take away 3 from 8 times K
Answers
Answer:
8×k-3
Step-by-step explanation:
that would be the equation (:
Answer:
8k - 3 is the answer because they are not like terms.
root 64 divided by root 3 64
Answers
Answer:
4
Step-by-step explanation:
4x4x4=64
Answer:
0.4193
Step-by-step explanation:
Root 64=8
Root 364=19.08...in 4 s.f
8÷19.08=0.4193...in 4 significant figures (4s.f)
Carter draws one side of equilateral △PQR on the coordinate plane at points P(-3,2) and Q(5,2). Which ordered pair is a possible coordinate of vertex R?
A. (-3, -6)
B. (0, 8)
C. (1, 8.9)
D. (1, -8.9)
Answers
Step-by-step explanation:
Hey, there!!!
Let me simply explain you about it.
We generally use the distance formula to get the points.
let the point R be (x,y)
As it an equilateral triangle it must have equal distance.
now,
let's find the distance of PQ,
we have, distance formulae is;
[tex]pq = \sqrt{( {x2 - x1)}^{2} + ( {y2 - y1)}^{2} } [/tex]
[tex]or \: \sqrt{( {5 + 3)}^{2} + ( {2 - 2)}^{2} } [/tex]
By simplifying it we get,
[tex] 8[/tex]
Now,
again finding the distance between PR,
[tex] pr = \sqrt{( {x2 - x1}^{2} + ( {y2 - y1)}^{2} } [/tex]
or,
[tex] \sqrt{( {x + 3)}^{2} + ( {y - 2)}^{2} } [/tex]
By simplifying it we get,
[tex] = \sqrt{ {x}^{2} + {y}^{2} + 6x - 4y + 13 } [/tex]
now, finding the distance of QR,
[tex]qr = \sqrt{( {x - 5)}^{2} + ( {y - 2)}^{2} } [/tex]
or, by simplification we get,
[tex] \sqrt{ {x}^{2} + {y}^{2} - 10x - 4y + 29 } [/tex]
now, equating PR and QR,
[tex] \sqrt{ {x}^{2} + {y}^{2} + 6x - 4y + 13} = \sqrt{ {x}^{2} + {y}^{2} - 10x - 4y + 29 } [/tex]
we cancelled the root ,
[tex] {x}^{2} + {y}^{2} + 6x - 4y + 13 = {x}^{2} + {y}^{2} -10x - 4y + 29[/tex]
or, cancelling all like terms, we get,
6x+13= -10x+29
16x=16
x=16/16
Therefore, x= 1.
now,
equating, PR and PQ,
[tex] \sqrt{ {x}^{2} + {y}^{2} + 6x - 4y + 13 } = 8} [/tex]
cancel the roots,
[tex] {x}^{2} + {y}^{2} + 6x - 4y + 13 = 8[/tex]
now,
(1)^2+ y^2+6×1-4y+13=8
or, 1+y^2+6-4y+13=8
y^2-4y+13+6+1=8
or, y(y-4)+20=8
or, y(y-4)= -12
either, or,
y= -12 y=8
Therefore, y= (8,-12)
by rounding off both values, we get,
x= 1
y=(8,-12)
So, i think it's (1,8) is your answer..
Hope it helps...
Answer:
1,8.9
Step-by-step explanation: