Draw the major 1,2- and 1,4-addition products that form as a result of the following reaction between one equivalent each of 2,4-hexadiene and HBr.

Answer:

1.81 x 10²² atoms O

Explanation:

To find the number of oxygen atoms, you need to (1) convert grams CaCO₃ to moles CaCO₃ (via molar mass), then (2) convert moles CaCO₃ to moles O (via mole-to-mole ratio from formula subscripts), and then (3) convert moles O to atoms O (via Avogadro's Number). It is important to arrange the conversions in a way that allows for the cancellation of units. The final answer should have 3 sig figs to match the amount of sig figs in the given value.

Molar Mass (CaCO₃): 40.078 g/mol + 12.011 g/mol + 3(15.998 g/mol)

Molar Mass (CaCO₃): 100.083 g/mol

1 CaCO₃ = 1 Ca and 1 C and 3 O

Avogadro's Number:

6.022 x 10²³ atoms = 1 mole

1.00 g CaCO₃           1 mole                 3 moles O           6.022 x 10²³ atoms
----------------------  x  ------------------  x  ----------------------  x  ------------------------------  =
                                100.083 g          1 mole CaCO₃                 1 mole

=  1.81 x 10²² atoms O

Answer:

when an electron move closer to the nucleus the magnitude of energy of the nucleus increases

Answer:

Ethylene oxide

Explanation:

Ethylene oxide is an organic compound with the formula C2H4O. It is a cyclic either and the simplest epoxied: a three-membraned ring consisting of one oxygen atom and two carbon atoms!

Moles of diprotic acid present were:

A mole of diprotic acid contains 0.0023 moles [tex]H_{2}A[/tex].

Law of dilution:

Titrations are conducted using the law of dilution.

The number of moles of solute divided by the arrangement's volume in liters is known as molarity.

The number of moles per liter of solution is referred to as molarity. Additionally, we write it as M. Furthermore, we employ the following equation to determine molarity:

Molarity = moles of solute/liter of solution.

Calculation:

Moles of acid = moles of base

n = M/V

Moles of [tex]H_{2}A[/tex] = Moles of NaOH used

Therefore,  0.100 x 0.02258L = 0.0023 mol [tex]H_{2}A[/tex]

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The two elements that have the same properties as sodium are potassium  and rubidium .

The periodic table is an arrangement of the elements in order of increasing atomic number.

From the list, the two elements that have the same properties as sodium are potassium  and rubidium .

Proton has an atomic number of 20 and a mass number of 40. The number of electrons is the same as the number of protons. Given that the atomic number is the number of protons present, we have 20 electrons and 20 protons.

Number of neutrons = Mass number  - Number of protons

= 40 - 20 = 20 neutrons

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The mass of benzoic acid is 0.244 g.

Here use the concept of molarity.

The amount of a substance in a specific volume of solution is known as its molarity (M). The moles of a solute per liter of a solution is known as molarity.

                            Molarity = no. of moles/volume (in L)

Given,

Molarity, M = 0.100 M

Volume, V = 20.00 mL = 20.0 × 10⁻³

To calculate,

Mass of benzoic acid C₇H₆O₂ =?

We know that,

Molecular mass of benzoic acid, C₇H₆O₂  = 122

No. of moles = weight/ molecular mass

The formula is modified as,

Molarity = weight of cholesterol/ (molecular mass) (Volume)

Put the values in the formula,

0.100 = Mass of benzoic acid/ (122) (20 × 10⁻³)

Mass of benzoic acid = 0.100 (122)(20 × 10⁻³)

                                    = 244 × 10⁻³

                                    = 0.244 g

Hence, the mass of benzoic acid is 0.244 g.

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Metal that won't be oxidized:

Metal that will not be able to oxidize by any of the other metals is gold.

What causes oxidation to happen?

This chemical reaction might take place in the air or after the metal has been in contact with acids or water. The most prevalent example is corrosion of steel, which occurs when the iron molecules on the surface of steel change into iron oxides, most frequently Fe2O3 and Fe3O4.

If you've ever seen a rusted-out vehicle or corroded metal bits, you've witnessed oxidation in action.

Metals that don't oxidize:

In their native condition, noble metals like platinum or gold resist oxidation. Ruthenium, rhodium, palladium, silver, osmium, and iridium are more examples of these metals. Humans have developed a wide variety of corrosion-resistant alloys, including brass and stainless steel.

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Answer:

Sarif should wear protective gloves, protective clothing.

Explanation:

Answer: a. 1-chloro-4-methylpent-2-yne - [tex]C_6H_9Cl[/tex]

              b. 5-chloro-2-methylpent-3-yne - [tex]C_6H_7Cl[/tex]

              c. sec-butyl chloromethyl acetylene - [tex]C_{12}H_{21}ClO_2[/tex]

              d.1-chloro-4,4-dimethylbut-2-yne - [tex]C_6H_9Cl[/tex]

What is the full name of IUPAC?

The full name of IUPAC is International Union of Pure and Applied Chemistry.

The compound's name is typed out first, followed by the base name and the substituents in alphabetical order (derived from the number of carbons in the parent chain). Between numbers and letters are separated by dashes and commas, respectively. The name has no spaces.

Therefore, a. 1-chloro-4-methylpent-2-yne - [tex]C_6H_9Cl[/tex]

              b. 5-chloro-2-methylpent-3-yne - [tex]C_6H_7Cl[/tex]

              c. sec-butyl chloromethyl acetylene - [tex]C_{12}H_{21}ClO_2[/tex]

              d.1-chloro-4,4-dimethylbut-2-yne - [tex]C_6H_9Cl[/tex]

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The time taken for the reaction to reach equilibrium in this concentration versus time graph is 4.5 seconds and is denoted as option D.

This refers to the duration in which a certain action or activity takes place with its unit being seconds.

From the graph we can deduce that:

This therefore means that the time taken for the reaction to reach equilibrium in this concentration versus time graph is 4.5 seconds.

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Answer: 4.5 is right just took the test.

Explanation:

NaBrO₃ (sodium bromate) is an ionic compound. It consists of a metal (sodium, Na) and a polyatomic ion (bromate, BrO₃⁻).

Ionic compounds are compounds composed of positive and negative ions held together by electrostatic forces. They are formed through the transfer of electrons between atoms, resulting in the formation of positively charged cations and negatively charged anions.

In an ionic compound, the cations are typically metal ions, while the anions are usually nonmetal ions or polyatomic ions. The transfer of electrons occurs from the metal atom(s) to the nonmetal atom(s), resulting in the formation of a crystal lattice structure.

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A primary election is the type of election in which candidates from the same party compete against one another to try to win the party's nomination.

A formal procedure of communal decision-making, an election that's how a population chooses a person or people to hold public office.

A general election would be one that takes place simultaneously throughout all constituencies, usually the day before or within a few days. When a member dies or resigns, elections may be conducted just for that constituency to replace the vacancy.

For positions with fixed terms, such as that of the president, governor, or legislator, primaries are frequently held. There are normally no special primaries for positions that could be replaced without holding a new election, including such a prime minister.

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The main constituent of gallstones is cholesterol. Cholesterol may have a role in heart attacks and blood clot formation. Its elemental percentage composition is 83.87% C, 11.99% H, and 4.14% O. It has a molecular weight of 386.64 amu. Empirical formula is C₃H₄O₁ and Molecular formula is 7(C₃H₄O₁).

Empirical formula is the simplest whole number ratio of atoms present in given compound.

Element   %   Atomic mass   Relative no. of atoms  Simplest whole ratio

C            83.87       12                     [tex]\frac{83.87}{12}[/tex] = 6.98                   [tex]\frac{6.98}{0.25}[/tex] = 3

H            11.99         1                       [tex]\frac{11.99}{1}[/tex] = 11.09                  [tex]\frac{11.09}{0.25}[/tex] = 4

O            4.14          16                      [tex]\frac{4.14}{16}[/tex] = 0.25                    [tex]\frac{0.25}{0.25}[/tex] = 1

Thus the empirical formula is C₃H₄O₁.

Molecular formula = Empirical formula × n

n = [tex]\frac{\text{Molecular weight}}{\text{Empirical formula weight}}[/tex]

  = [tex]\frac{386.64}{56}[/tex]

  = 7

Molecular formula = Empirical formula × n

                               = 7 (C₃H₄O₁)

Thus from the above conclusion we can say that The main constituent of gallstones is cholesterol. Cholesterol may have a role in heart attacks and blood clot formation. Its elemental percentage composition is 83.87% C, 11.99% H, and 4.14% O. It has a molecular weight of 386.64 amu. Empirical formula is C₃H₄O₁ and Molecular formula is 7(C₃H₄O₁).

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The density of the helium gas is 0.487 g/L

Calculation,

According to Ideal gas equation,

PV = nRT             ...(I)

The values of some terms are given as,

P is the pressure = 3 atm

V is the volume = ?

T is the temperature = 27°C = 27°C + 273 = 300 K

R is the universal gas constant = 0.0821 L∙atm∙mol−1∙K−1

n is the number of moles of helium = given mass of helium/molar mass of helium

n is the number of moles of helium = 1 g/ 4 g/mole = 0.25 mole

So, by putting the value of all data given in the equation (i) we get,

3 atm × V = 0.25 mol ×0.0821 L∙atm∙mol−1∙K−1×300 K

V =  0.25 mol ×0.0821 L∙atm∙mol−1∙K−1×300 K/3 atm

V = 2.05 L

The formula of density = given mass /volume = 1g/2.05 L = 0.487 g/L

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The total percent yield:

After the combustion reaction with methane, the percent yield was 66.7%.  

Combustion of Methane:

The other reactant, air's excess oxygen, is always present, making methane the limiting reactant. As a result, the amount of CH₄ burned will determine how much CO₂ and H₂O are produced.

The following chemical process produces carbon dioxide from methane:

CH₄ + 2O₂ ⇒ CO₂ + 2H₂O

Calculations:

1. Theoretical quantity of carbon dioxide:

All calculations will be based on the amount of methane because the problem specifies that it is the limiting reagent:

12.0g of CH₄ × (1 mol of CH₄/16g CH₄) × (1 mole of CO₂/1 mole of CH₄) × (44g CO₂/1 mole of CO₂)

= 33g of CO₂

2. Percent yield:

= Actual yield/Theoretical yield × 100

= 22.0g/33g × 100

= 66.7%

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Based on the melting points of both substances in comparison, my guess is Sodium chloride and glucose are the mystery compounds.This is further explained below.

Generally, Salt's chemical name is sodium chloride. It is an electrolyte's job to keep your body's fluid balance in check.

In conclusion, Sodium chloride and glucose are the likely candidates based on their relative melting points.

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Answer:

               b option is correct

Explanation:

The limiting reactant will be Fe.

They are reactants that are available in limited quantities, as compared to other reactants, during the course of reactions.

From the equation of the reaction: [tex]4Fe + 3O_2 --- > 2Fe_2O_3[/tex]

The mole ratio of Fe to O2 is 4:3.

Thus, for 0.25 mol Fe, 0.25 x 3/4 = 0.1875 mol of O2 is required.

With 0.5 mol of O2 available, it means oxygen is in excess while Fe is limited in availability.

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The limiting reactant from the calculations is Fe.

The limiting reactant is the reactant that is present in the least amount in solution. Now we have the equation as; 4Fe+ 3O2 → 2Fe2O3

If 4 moles of Fe reacts with 3 moles of O2

0.25 mol of Fe  reacts with  0.25 mol *  3 moles/4 moles

= 0.1875 moles of O2

It then follows that the limiting reactant is Fe.

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You can use mass percent composition as a conversion factor between grams of a constituent element and grams of the compound. The conversion factor in each mass percent composition are (a) 11.19 g H‚ 100 g H₂O (b) 53.29 g O‚100 g fructose (c) 84.12 g C‚100 g octane (d) 52.14 g C‚100 g ethanol

The percent by mass of each element present in a compound is called Mass Percent.

(a) Water is 11.19% hydrogen by mass.

Here it is given mass of hydrogen is 11.19 %. That means 11.19 % of solute should be added in 100 g H₂O.

(b) Fructose, also known as fruit sugar, is 53.29% oxygen by mass.

Here it is given mass of oxygen is 53.29 %. That means in 53.29% of solute should be added in 100 g fructose.

(c) Octane, a component of gasoline, is 84.12% carbon by mass.

Here it is given mass of carbon is 84.12 %. That means in 84.29% of solute should be added in 100 g Octane.

(d) Ethanol, the alcohol in alcoholic beverages, is 52.14% carbon by mass.

Here it is given mass of carbon is 52.14 %. That means in 52.14% of solute should be added in 100 g Ethanol.

Thus from the above conclusion we can say that You can use mass percent composition as a conversion factor between grams of a constituent element and grams of the compound. The conversion factor in each mass percent composition are (a) 11.19 g H‚100 g H2O (b) 53.29 g O‚100 g fructose (c) 84.12 g C‚100 g octane (d) 52.14 g C‚100 g ethanol

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Disclaimer: The question was given incomplete on the portal. Here is the complete question.

Question: You can use mass percent composition as a conversion factor between grams of a constituent element and grams of the compound. Write the conversion factor (including units) inherent in each mass percent composition.

(a) Water is 11.19% hydrogen by mass.

(b) Fructose, also known as fruit sugar, is 53.29% oxygen by mass.

(c) Octane, a component of gasoline, is 84.12% carbon by mass.

(d) Ethanol, the alcohol in alcoholic beverages, is 52.14% carbon by mass.

The liberated electron will have 10.28 eV kinetic energy.

Given that light of frequency 3.62 × [tex]10^{15}[/tex] Hz strikes a surface of copper metal with work function([tex]W_{0}[/tex]  = 4.70 eV).

The incident (photon) energy given as hf (Planck's Constant time's frequency) minus the energy that "binds" the electron to the metal (the work function) will equal the maximum kinetic energy of the emitted electron.

K.E. = hf − ϕ

Where K = Kinetic energy

h = Planck's constant = 6.62607015 × [tex]10^{-34}[/tex] J s

f = frequency = 3.62 × [tex]10^{15}[/tex] Hz

ϕ = 4.70 eV = 4.7 × 1.6 × [tex]10^{-19}[/tex] = 7.52 × [tex]10^{-19}[/tex]

K.E. = 6.62607015 × [tex]10^{-34}[/tex] × 3.62 × [tex]10^{15}[/tex] - 7.52 × [tex]10^{-19}[/tex]

       = 6.62607015 × 3.62 × [tex]10^{-19}[/tex] - 7.52 × [tex]10^{-19}[/tex]

       = 23.98 × [tex]10^{-19}[/tex] - 7.52 × [tex]10^{-19}[/tex]

K.E. = 16.46 × [tex]10^{-19}[/tex] J = 10.28 eV

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Answer:

0.25 moles

Explanation:

To find the number of moles, you need to use a variation of the Ideal gas Law. The manipulated equation looks like this:

P₁ / n₁ = P₂ / n₂

In this formula, "P₁" and "n₁" represent the initial pressure and number of moles. "P₂" and "n₂" represent the final pressure and number of moles. You can find the final amount of moles by plugging the given values into the equation and simplifying.

P₁ = 10.0 atm                      P₂ = 2.5 atm

n₁ = 1 mole                          n₂ = ? moles

P₁ / n₁ = P₂ / n₂                                                <----- Equation

(10.0 atm) / (1 mole) = (2.5 atm) / n₂               <----- Insert values

10.0 = (2.5 atm) / n₂                                        <----- Divide 1 from 10.0

(10.0) x n₂ = 2.5 atm                                       <----- Multiply both sides by n₂

n₂ = 0.25                                                        <----- Divide both sides by 10.0

Answer:

positron

Explanation:

PET scanning works by injecting a radioactive material, called a tracer, into the body. The tracer emits a positron inside the body, and the positron collides with electrons in the body, thereby annihilating and releasing two gamma rays that travel in opposite directions.

An increase in pH will directly stimulate the peripheral chemoreceptors to increase ventilation.

Chemoreceptor can be stimulated by change in the chemical composition of their immediate environment .There are many types of chemoreceptor spread throughout the body which help to control different process including taste, smell and breathing. An increase in body temperature increases the rate from peripheral chemoreceptor neurons.

The chemoreceptor is also known as chemosensor. The chemoreceptor is a specialized sensory receptor which transduces a chemical substance ( endogenous or induced ) to generate a biological signal. The two types of chemoreceptor is peripheral and central.

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More acid solution has red colour, more basic solution has purple colour whereas neutral solution has green colour.

As the solution becomes more acidic, the color of the solution changes from green toward red.

As the solution becomes more basic, the color changes of the solution from green toward purple.

Green color of the solution represents a neutral solution having pH 7.

So we can conclude that More acid solution has red colour, more basic solution has purple colour whereas neutral solution has green colour.

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Answer:

There are millions of organic compounds but only thousands of inorganic compounds because:

a. organic compounds were formed by living things.

b. there is more carbon on Earth's surface than any other element.

c. atoms of elements other than carbon never combine with themselves.

d. carbon atoms can combine with up to four other atoms, including other carbon atoms.

Answer: 2Al(s) + 3CuSO4(aq) → Al2(SO4)3(aq) + 3Cu(s)

Explanation: The quantities of aluminum and copper sulfate used as reactants will be such that the copper sulfate will be in excess. Thus, the aluminum will be the limiting factor in determining the number of moles (gram-atoms) of products that will be formed.

Answer:

0.702 L H₂O

Explanation:

To find the volume of water needed to dilute the stock solution, you need to (1) find the moles of the stock solution (via molarity formula), then (2) find the volume of the diluted solution (via molarity formula), and then (3) find the volume of water needed.

(Step 1)

Molarity (M) = moles / volume (L)                 <----- Molarity formula

5 M = moles / 0.500 L                                  <----- Insert values

2.5 = moles HCl                                           <----- Multiply both sides by 0.500

(Step 2)

Molarity = moles / volume                           <----- Molarity formula

2.08 M = 2.5 moles / volume                      <----- Insert values

(2.08 M) x volume = 2.5 moles                   <----- Multiply both sides by volume

volume = 1.20 L                                           <----- Divide both sides by 2.08

(Step 3)

Diluted Volume = 1.20 L

Stock Volume = 0.500 L

Water Volume = ? L

Diluted Volume = Stock Volume + Water Volume

1.20 L =  0.500 L + Water Volume

0.702 L = Water Volume

The mass of oxygen collected from the thermal decomposition of potassium chlorate at a temperature of 297 K and 762 mmHg is 0.16 g

We'll begin by obtaining the number of mole of oxygen gas produced from the reaction. This can be obtained by using the ideal gas equation as illustrated below:

PV = nRT

739.6 × 0.128 = n × 62.363 × 297

Divide both sides by 62.363 × 297

n = (739.6 × 0.128) / (62.363 × 297)

n = 0.0051 mole

Thus, the number of mole of oxygen gas produced is 0.0051 mole

Haven obtain the number of mole of oxygen gas produced, we can determine the mass of the oxygen produced as follow:'

Mole = mass / molar mass

0.0051 = mass of oxygen / 32

Cross multiply

Mass of oxygen = 0.0051 × 32

Mass of oxygen = 0.16 g

Thus, we can conclude that the mass of oxygen gas collected is 0.16 g

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Entropy directs to the degree of disorderliness in a system. Generally, solids have a greater degree of order when corresponded to gas in which the molecules/particles move randomly in all directions.

The transformation in entropy from solid to gaseous phase is a positive change. Because there is increase disorderliness of the system.

A campfire is an illustration of entropy. The solid wood burns and becomes ash, smoke and gases, all of which applied energy outwards more efficiently than the solid fuel. Ice melting, salt or sugar dissolving, constructing popcorn and boiling water for tea are processed with growing entropy in your kitchen.

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Answer:

Pink

Explanation:

Phenolphthalein is often used as an indicator in acid–base titrations. For this application, it turns colorless in acidic solutions and pink in basic solutions.

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Answer:

pink

Explanation:

Phenolphthalein is often used as an indicator in acid–base titrations. For this application, it turns colorless in acidic solutions and pink in basic solutions.