Eleanor scores 680 on the mathematics part of the SAT. The distribution of SAT math scores in recent years has been Normal with mean 527 and standard deviation 118.
Gerald takes the ACT Assessment mathematics test and scores 27. ACT math scores are Normally distributed with mean 20 and standard deviation 3.
1. What is Elanor's standardized score?
Round to 2 decimal places.
3. What is Gerald's standardized score?
Round to 2 decimal places.
4. Assuming that both tests measure the same kind of ability, who has the higher score?
i. Gerald.
ii. Elanor.
iii. They both did equally well.

Answer:

[tex] b = 2.7 [/tex]

Step-by-step explanation:

Given:

< C = 53°

< B = 80°

a = 2

Required:

Find b

Solution:

The question given suggests we are given measures for a ∆.

To find side b, which corresponds to angle B, first, we'd find angle A, which corresponds to side a, then apply the Law of sines to find side b.

=> A = 180 - (53 + 80) = 47°

Law of Sines: [tex] \frac{a}{sin(A} = \frac{b}{sin(B} [/tex]

Plug in the values into the formula

[tex] \frac{2}{sin(47} = \frac{b}{sin(80} [/tex]

Cross multiply

[tex] 2*sin(80) = b*sin(47) [/tex]

Divide both sides by sin(47) to make b the subject of formula

[tex] \frac{2*sin(80)}{sin(47} = b [/tex]

[tex] 2.69 = b [/tex]

[tex] b = 2.7 [/tex] (nearest tenth)

Answer:

D) (-4,8)

Step-by-step explanation:

Multiply both coordinates by -2

Answer:

(-4,8)

Step-by-step explanation:

I found a school pdf with the answer key to this exact equation and thats the answer

Answer:

p=0,83641536

Step-by-step explanation:

Let's calculate the probability that all 4 marbles are yellow:

p=26/40*25/39*24/38*23/37 ( no replacement)

=0,1635846372688....

probability that at least one of the marbles is green= 1-p

=0,83641536...

Answer:

a) 952

b) 136

Step-by-step explanation:

Ratio of b:g = 3:4, based on this we have:

Number of spectacle wearers:

Number of those not wearing spectacles:

And this number equals to 612, then we can find the value of x:

a) Total number of pupils:

b) The difference in the number of boys and girls:

Answer:

total number of students: 952

number of girls more than boys :136 more girls

Step-by-step explanation:

1/3 of boys +3/8 girls= spectacles

612 people do not wear spectacles

3:4= boys: girls

total number of students

3+4=7

boys + girls = total ratio

7= total ratio

1/3×3=1 3/8×4=3/2

1+3/2=5/2

7-5/2=9/2 9/2=612 students

If 9/2=612 Then 7=?

7= 7÷ 9/2×612

=952 people

Girls more than boys

if 7= 952

3= 3/7 × 952=408 boys

if 7 = 952

4= 4/7 ×952=544girls

Girls - boys

544- 408 = 136 girls

Answer: А.

The function f intersects the x-axis at two points, and the function g never intersects the x-axis.

Step-by-step explanation:

In the graph we can see f(x), first let's do some analysis of the graph.

First, f(x) is a quadratic equation: f(x) = a*x^2 + b*x + c.

The arms of the graph go up, so the leading coefficient of f(x) is positive.

The vertex of f(x) is near (-0.5, -2)

The roots are at x = -2 and x = 1. (intersects the x-axis at two points)

Now, we know that:

g(x) has a positive leading coefficient, and a vertex at (0, 3)

As the leading coefficient is positive, the arms go up, and the minimum value will be the value at the vertex, so the minimum value of g(x) is 3, when x = 0.

As the minimum value of y is 3, we can see that the graph never goes to the negative y-axis, so it never intersects the x-axis.

so:

f(x) intersects the x-axis at two points

g(x) does not intersect the x-axis.

The correct option is A.

Answer:

The answer is A.) The function f  intersects the x-axis at two points, and the function g never intersects the x-axis.

Step-by-step explanation:

I took the test and got it right.

[tex]\displaystyle\\(a+b)^n\\T_{r+1}=\binom{n}{r}a^{n-r}b^r\\\\\\(x+2)^7\\a=x\\b=2\\r+1=5\Rightarrow r=4\\n=7\\T_5=\binom{7}{4}x^{7-4}2^4\\T_5=\dfrac{7!}{4!3!}\cdot x^3\cdot16\\T_5=16\cdot \dfrac{5\cdot6\cdot7}{2\cdot3}\cdot x^3\\\\T_5=560x^3[/tex]

Answer:

[tex]\large \boxed{560x^3}[/tex]

Step-by-step explanation:

[tex](x+2)^7[/tex]

Expand brackets.

[tex](x+2) (x+2) (x+2) (x+2) (x+2) (x+2) (x+2)[/tex]

[tex](x^2 +4x+4) (x^2 +4x+4) (x^2 +4x+4)(x+2)[/tex]

[tex](x^4 +8x^3 +24x^2 +32x+16)(x^3 +6x^2 +12x+8)[/tex]

[tex]x^7 +14x^6 +84x^5 +280x^4 +560x^3 +672x^2 +448x+128[/tex]

The fifth term is 560x³.

Question is not complete, so i have attached it.

Answer:

Length = 30 inches

Width = 22 inches

Step-by-step explanation:

Let the width of rectangular sheet be x inches.

Let the length of the sheet be (x + 8) inches.

Now, after she cuts 4 inches squares from each corner, she will get a box of length: x + 8 - 4 - 4 = x inches , width: (x - 8) inches and height 4 inches.

Now, volume of a cube is;

V = lwh

Thus;

V = x(x - 8)(4)

We are told that the volume of the box is 2640 in³

Thus;

x(x - 8)(4) = 2640

Divide both sides by 4 to get;

x(x - 8) = 660

x² - 8x - 660 = 0

Using quadratic formula, we have;

x = 30 or - 22.

We will use x = 30 as the other one is negative.

Since we earlier deduced that she will get a box of will get a box of length: x inches , width: (x - 8) inches

Thus,

Length = 30 inches

Width = 30 - 8 = 22 inches

We have [tex]f\left(f^{-1}(x)\right) = x[/tex] for inverse functions [tex]f(x)[/tex] and [tex]f^{-1}(x)[/tex]. Then if [tex]f(x) = 2x+5[/tex], we have

[tex]f\left(f^{-1}(x)\right) = 2f^{-1}(x) + 5 = x \implies f^{-1}(x) = \dfrac{x-5}2[/tex]

Then

[tex]f^{-1}(8) = \dfrac{8-5}2 = \boxed{\dfrac32}[/tex]

Answer:

x = 9

this is a ratio problem. You can see that 12/6 = 2, so you can also take 18/2 to get 9.

Answer:

the answer is 6

Step-by-step explanation:

Because 6 and x are corresponding angle so that means no matter what ( if u want the answer to how long the line is or what degree the angle is ) the answer is always going to be the same as the one above ( which is 6 )

Hop this helpssss

Answer:

True

Step-by-step explanation:

Both happened in different times and are seprate events

Answer:

(a) 1155.84

(b) 48.2%

(c) D

Step-by-step explanation:

The number of total responses is, N = 38,528.

(a)

It is provided that 3% answered with "a lot".

Compute the actual number of responses consisting of "a lot" as follows:

n (a lot) = N × P (a lot)

            = 38528 × 0.03

            = 1155.84

Thus, the actual number of responses consisting of "a lot" is 1155.84.

(b)

The number of responses consisting of "very little or none" is,

n (very little or none) = 18,566

Compute the percentage of responses consisted of "very little or none" as follows:

[tex]P(\text{very little or none})=\frac{n(\text{very little or none})}{N}[/tex]

                                  [tex]=\frac{18566}{38528}\\\\=0.481883\\\\\approx 0.482[/tex]

The percentage is: 0.482 × 100% = 48.2%.

Thus, the percentage of responses consisted of "very little or none" is 48.2%.

(c)

As the sample size increases the sample statistic value gets closer and closer to the actual population parameter value.

Thus, making the sample statistic an unbiased estimator of the population parameter.

And proving that the sample is a true representative of the population.

Thus, the correct option is (D).

Answer:

n=39/5

Step-by-step explanation:

24=5(n-3)

24=5n-15

-5n= -15-24

-5n=39

n= 39/5

Answer:

5.3 days

Step-by-step explanation:

Let us assume the loss of ability to recall a learned material = 100%

Formula to calculate number of days = time(t) =

t = t½ × Log½(Nt/No)

Nt = Ending Amount

No = Beginning Amount

t½ = Half life

t = Time elapsed

Therefore, we have the following values from the questions:

Half life (t½)= 35 days

Initial or beginning amount = 100%

Ending amount = 90%

t = t½ × Log½ (Nt/No)

t = 35 × Log ½(90/100)

t = 5.3201082705768 days

Approximately = 5.3 days

Answer:

Step-by-step explanation:

Given the total number of students in the school to be 2229 students. If among a sample of 452 students from this school district, 163 have mathematics scores below grade level, then we can determine the number of students in this school district with mathematics scores below grade level based on the sample scores using ratio.

Let the number of students in this school district with mathematics scores below grade level be x. The ratio of the students with math score below grade level to total population will be x:2229

Also, the ratio of the sample students with math score below grade level to sample population will be 163:452

On equating both ratios, we will have;

x:2229 =  163:452

[tex]\dfrac{x}{2229} = \dfrac{163}{452}\\ \\cross\ multiplying;\\\\\\452*x = 2229*163\\\\x = \dfrac{2229*163}{452}\\ \\x = \frac{363,327}{452}\\ \\x = 803.8\\\\x \approx 804[/tex]

Hence the estimate of the number of students in this school district with mathematics scores below grade level based on the sample is 804

Answer:

The  t-statistic is [tex]t = 0.6956[/tex]

Step-by-step explanation:

From the question we are told that

     The population mean is  [tex]\mu = 22 \ minutes[/tex]

       The standard deviation is  [tex]s = 7.043[/tex]

       The  given data is  23, 35, 17, 30, 20, and 19.

Generally the sample mean is mathematically evaluated as

      [tex]\= x = \frac{23+ 35+17+ 30+ 20+ 19 }{6}[/tex]

     [tex]\= x =24[/tex]

The t-statistic is mathematically evaluated as

       [tex]t = \frac{ \= x - \mu }{\frac{s}{ \sqrt{n} } }[/tex]

=>   [tex]t = \frac{ 24 - 22 }{\frac{ 7.043}{ \sqrt{6} } }[/tex]

=>   [tex]t = 0.6956[/tex]

Answer: 0.70

Step-by-step explanation:

Answer:

3

Step-by-step explanation:

2(4x-3)-8=4+2x

8x - 6 - 8 = 4 + 2x

8x - 2x = 4 + 6 + 8

6x = 18

x = 18/6

x = 3

Answer:

[tex]2(4x - 3) - 8 = 4 + 2x \\ 2 \times 4x + 2 \times - 3 - 8 = 4 + 2x \\ according \: to \: bodmas \: first \: \times then + or - \\ so \\ 8x - 6 - 8 = 4 + 2x \\ 8x - 14 = 4 + 2x \\ 8x - 2x = 4 + 14 \\ 6x = 18 \\ x = \frac{18}{6} \\ x = 3 \\ thank \: you[/tex]

THIS IS THE COMPLETE QUESTION BELOW

The demand equation for a product is p=90000/400+3x where p is the price (in dollars) and x is the number of units (in thousands). Find the average price p on the interval 40 ≤ x ≤ 50.

Answer

$168.27

Step by step Explanation

Given p=90000/400+3x

With the limits of 40 to 50

Then we need the integral in the form below to find the average price

1/(g-d)∫ⁿₐf(x)dx

Where n= 40 and a= 50, then if we substitute p and the limits then we integrate

1/(50-40)∫⁵⁰₄₀(90000/400+3x)

1/10∫⁵⁰₄₀(90000/400+3x)

If we perform some factorization we have

90000/(10)(3)∫3dx/(400+3x)

3000[ln400+3x]₄₀⁵⁰

Then let substitute the upper and lower limits we have

3000[ln400+3(50)]-ln[400+3(40]

30000[ln550-ln520]

3000[6.3099×6.254]

3000[0.056]

=168.27

the average price p on the interval 40 ≤ x ≤ 50 is

=$168.27

Answer:

We have the magnitude, M, and the angle A.

(The angle is always measured from the +x-axis)

Then we have that:

x = M*cos(A)

y = M*sin(A)

in this case:

M = 9m

A = -80°

x = 9m*cos(-80°) = 1.562

y = 9m*sin(-80) = -8.86m

Now, the component parallel to the x axis is:

x = 9m*cos(-80°) = 1.562 m

And the slope of something parallel to the x-axis is always zero, as this is a constant line.

Answer:

the next one is .857 I hope this helps you :)

[tex]\\ \sf\longmapsto XY+YZ=XZ[/tex]

[tex]\\ \sf\longmapsto 7a+5a=6a+24[/tex]

[tex]\\ \sf\longmapsto 12a=6a+24[/tex]

[tex]\\ \sf\longmapsto 12a-6a=24[/tex]

[tex]\\ \sf\longmapsto 6a=24[/tex]

[tex]\\ \sf\longmapsto a=\dfrac{24}{6}[/tex]

[tex]\\ \sf\longmapsto a=5[/tex]

Value of a is 4 and value of YZ is 20 units

Step-by-step explanation:

Given:

Y is between point X and Z

Value of line XY = 7a

Value of line YZ = 5a

Value of line XZ = 6a + 24

Find:

Value of "a" and line YZ

Computation:

We know that

XY + YZ = XZ

So,

7a + 5a = 6a + 24

12a = 6a + 24

6a = 24

a = 4

Value of a = 4

So,

Value of line YZ = 5a

By putting value of a

Value of line YZ = 5(4)

Value of line YZ = 20 units

Learn more;

https://brainly.com/question/18983323?referrer=searchResults

Step-by-step explanation:

2 cups of water used with 4 packs

therefore for 12 we use x cups of water

2:4

X :12

therefore 6'cups of water?

Answer:

Step-by-step explanation:

[tex]4 + \frac{4}{4} [/tex]

= 4 + 1

= 5 (Ans)

Answer:

The [tex]L_{ACL}[/tex] of the player is  [tex]L_{ACL} = 56.82 \ mm[/tex]

Step-by-step explanation:

From the question we are told that

       The relationship between the length [tex]L_{ACL}[/tex] to the height is  

            [tex]L_{ACL} = 0.04606h - (41.29 \ mm)[/tex]

       The height of the basketball player  is  [tex]h = 2.13 \ m = 2130 \ mm[/tex]

Substituting the value of height of the basket ball player in to the model we have the [tex]L_{ACL}[/tex] of the player is

          [tex]L_{ACL} = 0.04606 (2130) - (41.29 ) \ mm[/tex]

         [tex]L_{ACL} = 56.82 \ mm[/tex]

Answer:

I don't know what you think about it is not going to be a great day of school and I don't know what you think about it is not going to be a great day of school

Answer:

B

Step-by-step explanation:

we take the only point we know

(0,20)

in A when x =0

[tex]f(x)=e^{20x} =e^{20*0}=1[/tex]

in B when x=0

[tex]f(x)=20e^x=20e^0=20*1=20[/tex]

fits

in C

[tex]f(x)=20^x=20^0=1[/tex]

in D

[tex]f(x)=20^{20x}=20^{20*0}=20^0=1[/tex]

so the only choice is B

Answer:

the Sum

hope this helps

Answer:

5 a) Total = 20.83 hrs = 20 hrs and 50 mins  (1250mins total)

5 b) Total = 96 meters. = 0.096km in 8 hrs.

Step-by-step explanation:

1km = 1000 meters

5 mins = 4 meters

1000/4 = 250 multiplier

250 x 5mins = 1250 minutes

1250/60 = 20hrs + 50 minutes

50 / 60 =  0.83 = 20.83hrs

b)  8 hrs = 8 x 60 = 480 minutes

480/5 = 24 multiplier of 4 meters

24 x 4 = 96 meters

Answer:

It looks like 6 and one eighth of an inch.