Emma rents a car from a company that rents cars by the hour. She has to pay an initial fee of $75, and then they charge her $9 per hour. Write an equation for the total cost if Emma rents the car for ℎ hours. If Emma has budgeted $250 for the rental cars, how many hours can she rent the car? Assume the car cannot be rented for part of an hour.

The complete table is

x    y

0    0.75

3     3.75

9     9.75

An equation is a mathematical statement that is made up of two expressions connected by an equal sign.

Substitution means putting numbers in place of letters to calculate the value of an expression or equation.

According to the given question.

We have values of x.

Also, one rule that y is 0.75 greater than x.

So, we have a equation for finding the value of y  i.e.

[tex]y = x + 0.75..(i)[/tex]

For finding the value of y

At x = 0, substitute x = 0 in equation (i)

[tex]y = 0 + 0.75\\\implies y = 0.75[/tex]

At x = 3, substitute x = 3 in equation (i)

[tex]y = 3+0.75\\\implies y = 3.75[/tex]

At x = 9, substitute x = 9 in equation (i)

[tex]y = 9+0.75\\\implies y = 9.75[/tex]

Hence, the complete table is

x    y

0    0.75

3     3.75

9     9.75

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9514 1404 393

Answer:

  A. y = -2x +13

  B. y = 8x -7

Step-by-step explanation:

A. We can read the y-intercept of the secant line from the graph. It is 13.

The slope can also be read from the graph, but we choose to use the slope formula:

  m = (y2 -y1)/(x2 -x1)

  m = (19 -9)/(-3 -2) = 10/-5 = -2

Then the slope-intercept formula for the line is ...

  y = mx + b . . . . . . line of slope m and y-intercept b

  y = -2x +13

__

B. The vertex of the given parabola is (0, 1). We notice that when x=1 (1 unit right of the vertex), y = 3 (2 units up from the vertex). This tells us the vertical scale factor of the parabola is 2. That means the vertex form equation is ...

  y = a(x -h)^2 +k . . . . . . . . vertex (h, k), scale factor 'a'

  y = 2(x-0)^2 +1 . . . . . . . use known values for (h, k)

  y = 2x^2 +1

The derivative of this is ...

  y' = 4x

So, at x=2, the given point A, the slope of the tangent line is ...

  m = y' = 4(2) = 8

We have a point and the slope, so we can write the point-slope form of the equation for the tangent line:

  y -9 = 8(x -2)

Rearranging to slope-intercept form, this is ...

  y = 8x -7

__

Additional comment

You can also read the slope of the tangent line from the graph. The line also goes through the point (1, 1), so has a rise of 8 for a run of 1. The y-intercept can be found from ...

  b = y -mx = 9 -8(2) = -7

This lets you write the equation of the tangent line directly from the graph.

That is, the parameters of both lines can be read from the graph, so there is very little "development" required.

Corresponding Index is one which creates a random matrix index based on the values.

The random consistency index has values lesser than 1 therefore the value for the random matrix of 7 the consistency index will be 0.58.

Random Index maximum value will be 0 and its minimum value will be 0.01. The values will depend on the matrix consistency Index.

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Step-by-step explanation:

x - 5 < 2 (y - 8) • 1/4

x - 5 < (y - 8) / 2

2 (x - 5) < y - 8

2x - 10 < y - 8

2x - 10 + 8 < y

y > 2x - 2

graph 2x - 2 and shade the section above

The graph of (y - 8)² > 4x - 20 is the same as the graph of x - 5 < 1/4(y - 8)²

The inequality of the graph is given as:

x - 5 < 1/4(y - 8)²

Multiply both sides by 4

4x - 20 < (y - 8)²

Rewrite the inequality as:

(y - 8)² > 4x - 20

Hence, the graph of (y - 8)² > 4x - 20 is the same as the graph of x - 5 < 1/4(y - 8)²

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Answer:

seeed

Step-by-step] explanation:

ddd~!`

Answer:

C

Step-by-step explanation:

Let the first term be a and the common ratio be r.

ATQ, ar^4=24 and ar^6=144, r=sqrt(6) and a=24/(sqrt(6))^2=24/36=2/3

Hi there! :)

Answer:

[tex]P(heads) = \frac{1}{8}[/tex]

Step-by-step explanation:

Probability of a coin landing on heads:

[tex]P(heads) = \frac{1}{2}[/tex]

Find the probability of getting heads 3 times:

[tex]\frac{1}{2} * \frac{1}{2} * \frac{1}{2} = \frac{1}{8}[/tex]

Therefore, the probability of the coin showing heads for 3 tosses is:

[tex]P(heads) = \frac{1}{8}[/tex]

Answer:

Central Angle

Step-by-step explanation:

Obtuse Angle is over 90 but under 180.

Central angle is like a acute angle.

Answer:

the profit is $8

Step-by-step explanation:

so Susan started with 0, lost 11, equals -11

earned 18, =7

lost 7, =0

earned 8, =$8 for the final answer

Answer:

V≈50.27cm³

Step-by-step explanation:

Using the formulas

V=πr2h

3

l=r2+h2

Solving forV

V=1

3πr2l2﹣r2=1

3·π·42·52﹣42≈50.26548cm³

Answer:

$69,361.23

Step-by-step explanation:

[tex] A = P(1 + \dfrac{r}{n})^{nt} [/tex]

[tex] A = 10000(1 + \dfrac{0.09}{2})^{2 \times 22} [/tex]

[tex]A = 10000(1.045)^{44}[/tex]

[tex] A = 69361.23 [/tex]

Answer: $69,361.23

Answer:

x = π/12 and x = π/4.

Step-by-step explanation:

2sin^2(2x) + 1 = 3sin(2x)

2sin^2(2x) - 3sin(2x) + 1 = 0

(2sin(2x) - 1)(sin(2x) - 1) = 0

2sin(2x) - 1 = 0

2sin(2x) = 1

sin(2x) = 1/2

When there is a variable n = π/6, sin(π/6) = 1/2 [refer to the unit circle].

2x = π/6

x = π/12

sin(2x) - 1 = 0

sin(2x) = 1

When there is a variable n = π/2, sin(π/2) = 1 [refer to the unit circle].

2x = π/2

x = π/4

Hope this helps!

Step-by-step explanation:

[tex] \frac{2}{4} + 5 \times 36 + 2 \frac{6}{3} [/tex]

[tex] = \frac{1}{2} + 180 + 2 \times \frac{2}{1} [/tex]

[tex] = \frac{1}{2} + 180 + 4[/tex]

[tex] = \frac{1 + 360 + 8}{2} [/tex]

[tex] = \frac{369}{2} [/tex]

[tex] = 184 \frac{1}{2} \: or \: 184.5(ans)[/tex]

Answer:

3.25 US Quarts

Step-by-step explanation:

Answer:

A. 149

Step-by-step explanation:

When a quadrilateral is inscribed in a circle, the sum of the opposite angles in the quadrilateral equal (180) degrees. Applying this theorem here, one can state the following:

c + 31 = 180

Inverse operations,

c + 31 = 180

c = 149

Thus, option (A) is the correct angles: ( c = 149°)

In provided diagram angle WXY = angle YXZ

Angle WXY =( 7x-7)°

Angle YXZ = ( 5x +3)°

We have to find out the value of Angle WXZ

→ 7x-7 = 5x +3

→ 7x - 5x = 7+3

→ 2x = 10

→ x = 10/2

→ x = 5 .

Putting the value of x .

→ Angle WXY = 7(2)-7

→ 14-7 = 7°

→ Angle YXZ = 5(2)+3

→ 10+3 = 13°

Angle WXZ = 13° + 7 ° → 20°

So 20° is the required answer .

Answer:

SI

Step-by-step explanation:

Answer:

Step-by-step explanation:

This is a straight proportion problem.

15/42 = x/140                 Cross Multiply

15*140 = 42 * x

2100 = 42x                    Divide by 42

2100/42 = x            

x = 50 ml of HCl will be needed.

Answer:

Given numbers

Inorder to find the difference between them we have to substarct them.

[tex]\\ \sf\longmapsto 5907-5429[/tex]

[tex]\\ \sf\longmapsto 478[/tex]

Answer:

478

Step-by-step explanation:

To solve the problem

5907 -

5429 =

478

Answer:

7.88 or 7.9

Step-by-step explanation:

To find the mean, we need to do:

=> (12 + 10 + 11 + 8 + 6 + 5 + 3 + 7 + 9) / 9

=> 71/9

=> 7.88 or 7.9

I divided the sum of all numbers by 9 because we added 9 numbers.

Answer:

answer is A

Step-by-step explanation:

option A is the answer

Complete Question

The complete question is shown on the first uploaded image

Answer:

The cost to buy 100 shares in ODX group Inc and 300 shares   peer Comms Lts is  

         [tex]C = \$ 775[/tex]

Step-by-step explanation:

   From the chat we that the cost of 100  ODX shares is  [tex]\$175[/tex]

    The cost of 100 peer Comms Lts  is  [tex]\$ 200[/tex]

Hence the cost 300 peer Comms Lts  is  [tex]k = 3 * 200 = \$ 600[/tex]

Now  the cost of  100 shares in ODX group Inc and 300 shares of  peer Comms Lts  is mathematically evaluated as

           [tex]C = 175 + 600[/tex]

           [tex]C = \$ 775[/tex]

The cost to buy 100 shares in ODX group Inc and 300 shares in peer comm LTD is $775.

Given in question the graph here is missing.

We have to calculate the total cost of 100 shares in ODX group Inc and 300 shares in peer comms limited in year 5.

From the graph it is clear that, the x axis shows the no. of year and y axis shows the cost of 100 shares for each type.

From graph, the cost of 100 shares of ODX group in year 5 is $175.

And the cost of 100 shares of peer comm Ltd in year 5 is $ 200.

So the total cost of 300 shares of  peer comm Ltd in 5 year is $([tex]200\times3[/tex]) or $600.

Now final cost of 100 shares in ODX group Inc and 300 share in peer comm Ltd is [tex]($600+$175)[/tex] dollars.

Hence the cost to buy 100 shares in ODX group Inc and 300 shares in peer comm LTD is $775.

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Answer:

210.33 cm^2

Step-by-step explanation:

We know that 6 equilateral triangles makes one hexagon.

Also, an equilateral triangle has all its sides equal.

If the tile of each side of the triangular tile measure 9 cm, then the height of the triangular tiles can be gotten using Pythagoras's Theorem.

The triangle formed by each tile can be split along its height, into two right angle triangles with base (adjacent) 4.5 cm and slant side (hypotenuse) of 9 cm. The height  (opposite) is calculated as,

From Pythagoras's theorem,

[tex]hyp^{2} = adj^{2} + opp^{2}[/tex]

substituting, we have

[tex]9^{2} = 4.5^{2} + opp^{2}[/tex]

81 = 20.25 + [tex]opp^{2}[/tex]

[tex]opp^{2}[/tex] = 81 - 20.25 = 60.75

opp = [tex]\sqrt{60.75}[/tex] = 7.79 cm  this is the height of the right angle triangle, and also the height of the equilateral triangular tiles.

The area of a triangle = [tex]\frac{1}{2} bh[/tex]

where b is the base = 9 cm

h is the height = 7.79 cm

substituting, we have

area = [tex]\frac{1}{2}[/tex] x 9 x 7.79 = 35.055 cm^2

Area of the hexagon that will be formed = 6 x area of the triangular tiles

==> 6 x 35.055 cm^2 = 210.33 cm^2

Answer:

19.5 pounds

Step-by-step explanation:

1 foot = 12 inches

3 inches = 3/12 = 0.25 feet

3 feet 3 inches = 3.25 feet

then:

24 pounds is 4 feet

A pounds is 3.25 feet

A = 24*3.25/4

A = 19.5 pounds

Answer:

19.50 pounds

Step-by-step explanation:

1 foot = 12 inches

3 inches = 3/12 = 0.25 feet

3 feet 3 inches = 3.25 feet

then:

24 pounds is 4 feet

A pounds is 3.25 feet

A = 24*3.25/4

A = 19.50 pounds

Answer:

(C) 18

Step-by-step explanation:

We can create a systems of equations. Assuming [tex]m[/tex] is Michelle's age, [tex]j[/tex] is Joan's age, and [tex]r[/tex] is Ryan's age, the equations are:

[tex]m = j + 7[/tex]

[tex]j = r-3[/tex]

[tex]m+j+r = 64[/tex]

We can use substitution, since we know the "values" of m and j.

[tex](j+7)+(r-3)+r = 64\\(j+7)+(2r-3)=64\\2r + j + 4 = 64\\2r + j = 60\\\\[/tex]

[tex]r = 21, j = 18[/tex]

So we know that Joan is 18 years old.

Hope this helped!

Answer:

Step-by-step explanation:

Form a set of values we get

n = 17

And with the help of a calculator

μ₀ = 438,47

σ  = 14,79

Normal Distribution is :  N ( 438,47 ; 14,79 )

c)

CI = 95 % means  α = 5 %    α/2 = 2,5 %    α/2 = 0,025

and as n < 30  we should use t-student distribution with n -1 degree of freedom  df = 16.  t score for 0,025 and 16 s from t-table 2,120

By definition:

CI = [  μ₀  ±  t α/2 ; n-1 * σ/√n ]

CI = [  μ₀  ± 2,120* 14,79/√17 ]

CI = [  μ₀  ±  7,60 ]

CI = [ 438,47 ± 7,60 ]

CI = [  430,87 ; 446,07 ]

95% confidence interval for true average degree of polymerization is  [430.87 ; 446.07] and this interval suggest that 441 is a plausible value for true average degree of polymerization and also this interval does not suggest that 451 is a plausible value.

Given :

The total number of values given is, n = 17

Mean, [tex]\mu_0=438.47[/tex]

Standard Deviation, [tex]\sigma = 14.79[/tex]

The normal distribution is given by: N (438.47 ; 14.79)

If Cl  is 95% then [tex]\alpha[/tex] is 5% and [tex]\alpha /2[/tex] is 2.5%

[tex]\alpha /2 = 0.025[/tex]

Now, use t-statistics distribution with (n-1) degree of freedom df = 16

So, the t score for 0.025 and 16 s from t-table 2.120.

[tex]\rm Cl = [\mu_0 \pm t_{\alpha /2};(n-1)\times \dfrac{\sigma}{\sqrt{n} }][/tex]

[tex]\rm Cl = [\mu_0 \pm 2.120\times \dfrac{14.79}{\sqrt{17} }][/tex]

[tex]\rm Cl = [\mu_0 \pm 7.60][/tex]

Cl = [430.87 ; 446.07]

Yes, the interval suggests that 441 is a plausible value for true average degree of polymerization.

No, the interval does not suggest that 451 is a plausible value.

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Answer:

The desired sample size is 97.

Step-by-step explanation:

Assume that 50% people in the community that supports the political candidate.

It is provided that the candidate wants a 10% margin of error (MOE) at a 95% confidence level.

The confidence interval for the population proportion is:

[tex]CI=\hat p\pm z_{\alpha/2}\sqrt{\frac{\hat p(1-\hat p)}{n}}[/tex]

Then the margin of error is:

[tex]MOE= z_{\alpha/2}\sqrt{\frac{\hat p(1-\hat p)}{n}}[/tex]

Compute the critical value of z as follows:

[tex]z_{\alpha/2}=z_{0.05/2}=z_{0.025}=1.96[/tex]

*Use a z-table.

Compute the sample size as follows:

[tex]MOE= z_{\alpha/2}\sqrt{\frac{\hat p(1-\hat p)}{n}}[/tex]

       [tex]n=[\frac{z_{\alpha/2}\times \sqrt{\hat p(1-\hat p)} }{MOE}]^{2}[/tex]

          [tex]=[\frac{1.96\times \sqrt{0.50(1-0.50)} }{0.10}^{2}\\\\=[9.8]^{2}\\\\=96.04\\\\\approx 97[/tex]

Thus, the desired sample size is 97.