Answer:
a) v = - 4.4168 m / s , b) V = 0
Explanation:
The average speed is the variation of the displacement in time used.
v = Δx /Δt = (x₂-x₁) / (t₂-t₁)
let's apply this equation to our case
Let's reduce the magnitudes of the system Yes
Δx = 5150 km (1000 m / 1km) = 5.15 106 m
Δt = 13.5 day (86,400 s / 1 day) = 1,166 10 6 s
a) return trip
the vector is negative because it points long towards the center of the system
v = - 5.15 106 / 1.166 106
v = - 4.4168 m / s
the negative sign indicates that he is coming back, to the lair
b) In a complete trip the distance is zero, because it is a vector, consequently the mean fickleness is also zero
V(j_ = 0
what is achmedis principle
Answer:
Archimedes principle states that when a body is partially/wholly/completely immersed in fluid (liquid or gas),it experiences an upthrust which is equal to the weight of the fluid displaced....
explain the different methods that can be used to model the motion of an object.
Answer:Even things that appear to be at rest move.
When we describe the motion of one object with
respect to another, we say that the object is moving
relative to the other object.
• A book that is at rest, relative to the table it lies
on, is moving at about 30 kilometers per second
relative to the sun.
• The book moves even faster relative to the center
of our galaxy.
Explanation:
A billiard ball moves with 3 kg⋅m/s of momentum and strikes three other billiard balls. What is the total momentum of the balls after the collision? A. less than 3 kg⋅m/s B. It depends on the mass of each ball. C. 3 kg⋅m/s D. more than 3 kg⋅m/s
Answer:
It should be C
Explanation:
It depends on the mass of each ball
Remember the formula for momentum, mass X velocity
Momentum depends on the mass of the object
The momentum of the billiard balls after the collision is 3 Kgm/s.
Let the billiard ball be B.Given the following data:
Momentum B = 3 Kgm/sTo find the momentum of the balls after the collision:
Momentum is simply a multiplication (product) of the mass of an object with its velocity. Also, momentum is a vector quantity because it has both magnitude and direction.
Mathematically, momentum is given by the formula;
[tex]Momentum = Mass[/tex] × [tex]Velocity[/tex]
[tex]Total \; momentum = Momentum \; B + Momentum \;of \;the \;other\; balls.[/tex]
Since the other billiard balls were at rest (not experience any motion), there velocities would be zero (0) m/s.
Substituting the values, we have:
[tex]Total \; Momentum = 3 + 0[/tex]
Total momentum = 3 Kgm/s.
Therefore, the momentum of the billiard balls after the collision is 3 Kgm/s.
Read more: https://brainly.com/question/23092552
Powerful sports cars can go from zero to 25 m/s (about 60 mph) in 6 seconds. What is the magnitude of the acceleration, including units
Answer:
The magnitude of the acceleration is 4.2 m/s²
Explanation:
Given;
initial velocity of the powerful sports car, u = 0
final velocity of the powerful sports car, v = 25 m/s
time of motion, t = 6 seconds
Acceleration = Δv / Δt
Δv is change in velocity
Δt is change in time
The magnitude of the acceleration of the powerful sports car during the motion is given by;
[tex]a = \frac{v-u}{t}\\\\a = \frac{25-0}{6}\\\\a = 4.2 \ m/s^2[/tex]
Therefore, the magnitude of the acceleration is 4.2 m/s²
The magnitude of the acceleration is 4.2 m/s²
The calculation is as follows:Given that
initial velocity of the powerful sports car, u = 0
final velocity of the powerful sports car, v = 25 m/s
time of motion, t = 6 seconds
Now the magnitude should be
[tex]= (25 - 0) \div 6[/tex]
= 4.2 m/s²
Learn more: https://brainly.com/question/10283285?referrer=searchResults
According to Newton's Third Law, if someone jumps off a skateboard, the
skateboard will roll backwards because
Answer:
every action has a same an equal reaction
If someone jumps off a skateboard, the skateboard will roll backwards because action and reaction are equal and opposite.
Newton's third law states that action and reaction are equal and opposite. That is, for every action there is a resulting reaction equal in magnitude to the action but opposite in direction.
If someone jumps off a skateboard, he will exert an action force downwards while the skate board exerts a reaction force upwards on him. This causes the skateboard to move backwards while he moves upwards.
Thus, if someone jumps off a skateboard, the skateboard will roll backwards because action and reaction are equal and opposite.
Learn more here: https://brainly.com/question/23772134
what do u mean by the activity series of metals ??
Answer:
An activity series is a list of substances ranked in order of relative reactivity. For example, magnesium metal can knock hydrogen ions out of solution, so it is considered more reactive than elemental hydrogen. The activity series is a useful guide for predicting the products of metal displacement reactions.
Help me please !!!!!
Answer:
confounding cause they had exposure to many programmes
Answer:
Confounding should be your answer please mark brainliest
A 145 lb diver stands at the end of a rigid 7 ft long diving board. What is the magnitude of the torque the diver exerts on the diving board
Answer:
Torque = 1015 ft.lb
Explanation:
Torque is defined as the turning effect of force. It is the force that can cause an object to rotate and gain some angular acceleration. Torque is basically an angular analog of force. The method to calculate torque is simple. Take the perpendicular distance from the line of action of force to the axis of rotation. Multiply this distance with the magnitude of force. The magnitude of this product gives the torque. Therefore,
Torque = (Force)(Perpendicular Distance)
Since, the diver is standing at the end of diving board.
Therefore,
Perpendicular Distance = 7 ft
Force = 145 lb
Therefore,
Torque = (145 lb)(7 ft)
Torque = 1015 ft.lb
The horizontal and vertical components of the initial velocity of a projectile are 50 m/s and 120 m/s respectively. What is the magnitude of the initial velocity
Answer:
50 m/s
Explanation:
In a projectile motion, acceleration is only on the vertical plane, that is, the vertical velocity is the only velocity component that undergoes acceleration under gravitational force. The horizontal component of velocity dos not change with time, and hence is the same as the initial velocity of the projectile.
Two long wires hang vertically. Wire 1 carries an upward current of 1.20 A. Wire 2, 20.0 cm to the right of wire 1, carries a downward current of 4.20 A. A third wire, wire 3, is to be hung vertically and located such that when it carries a certain current, each wire experiences no net force.
(a) Is this situation possible?
A. Yes
B. No
Is it possible in more than one way?
A. Yes
B. No
(b) Describe the position of wire 3.
distance ________ cm
direction: left of wire 1
(c) Describe the magnitude and direction of the current in wire 3.
magnitude
direction
down
Answer:
Explanation:
A, yes
b,
The force(per unit length) on wire 1 by 2 is to the left and
= μo*I1*I2/2πr
= 2*10^-7 * 1.2 * 4.2/0.20
= 5.04*10^-6N/m
From third law we have the force on wire2 by wire 1 is 5.04*10^-6N/m and to the right
So the magnitude of the force on each wire by wire 3 must be 4.2*10^-6N/m
Since the current in wire 2 is > wire 1 then wire 3 must be closer to wire 1 than 2
and wire 3 must be to the left of wire 1
Let x be the distance from wire 3 to wire 1 so x + 0.20 = distance from wire 3 to wire 2
Now μo*I1*I3/2πx = μo*I3*I2/2π(x + 0.20)
so solving for x we get
I1/x = I2/(x+0.20)
or x +0.20 = 4x
so x = 0.20/3 = 0.0667m
Now μo*I1*I3/2πx = 4.2*10^-6
so I3 = 4.2x10^-6 * 0.0667/(2.0x10^-7 * 1.2) = 1.167 A and its direction is down
Most scientific experiments are what type experiment, mostly because it is simpler and easier to test single variables? a) Natural experiment. b) Controlled experiment. c) Forced experiment. d) Redundant experiment.
Answer:
The correct answer is : option B. controlled experiments.
Explanation:
A scientific experiment which deals with a single variable at a time and compared the independent variable to a controlled variable after measuring the change in dependent variable.
It is a very simple and easy test for single variable. In these experiments subjects are divided in two groups one one, with independent variable and other variable.
Thus, the correct answer is : option B. controlled experiments.
Which of Jafar's statements are correct regarding distance and displacement?
Answer:The distance and magnitude of displacement are sometimes equal." Jafar is correct. The distance traveled and the magnitude of displacement are equal if and only if the path is a straight line in one direction.
Explanation:
A stretched string is 2.11 m long and has a mass of 19.5 g. When the string oscillates at 440 Hz , which is the frequency of the standard A pitch, transverse waves with a wavelength of 15.3 cm travel along the string. Calculate the tension T in the string.
Answer:
The tension of the string is 41.876 N
Explanation:
Given;
length of the string, L = 2.11 m
mass of the string, m = 19.5 g = 0.0195 kg
frequency of the wave, f = 440 Hz
wavelength, λ = 15.3 cm = 0.153 m
The velocity of the wave is given by;
v = fλ
v = 440 x 0.153
v = 67.32 m/s
Also the velocity of the wave is given by
[tex]v = \sqrt{\frac{T}{\mu} }[/tex]
where;
μ is mass per unit length = 0.0195 / 2.11 = 0.00924 kg/m
T is the tension of the string
T = v²μ
T = (67.32)²(0.00924)
T = 41.876 N
Therefore, the tension of the string is 41.876 N
The simplest branched-chain hydrocarbon is
A ethane
B ethene
C propane
D butane
Answer:
Butane
Explanation:
While John is traveling along a straight inter-
state highway, he notices that the mile marker
reads 241 km. John travels until he reaches
the 145 km marker and then retraces his path
to the 174 km marker.
What is John's resultant displacement from
the 241 km marker?
Answer in units of km.
Answer:
His displacement is 260 – 169 = 91 km
His distance traveled is (260 – 134) + ( 169 – 134 ) = 161 km
Explanation:
What will be the force if the particle's charge is tripled and the electric field strength is halved? Give your answer in terms of F
Answer:
1.5F
Explanation:
Using
E= F/q
Where F= force
E= electric field
q=charge
F= Eq
So if qis tripled and E is halved we have
F= (E/2)3q
F= 1.5Eq=>> 1.5F
In a particular wire in a circuit, conventional current flows in the z direction. What is the direction of electron current in the wire
Answer:
Electron current will flow in the negative z axis
Explanation:
This is because flow of conventional current is opposite that if electron current so since conventional is in +z axis electron will be -z axis
what are the x and y components of the vector that has a magnitude of 4N and a direction of 30 degrees
Answer:
We are given
vector as 4N and direction 30°
So since X-component is
adjacent /hypotenuse which is cosine we have
= 4 cos 30 = 3.46 N
And Y-component which is opposite/hypotenuse we have
= 4 sin 30 = 2N
URGENT!!!!!! Assume that a wire has 1.5 ohms of resistance. If the wire is connected to two batteries with a total voltage of 3.0 V, how much current will flow through the wire? 3.0 amps 2.3 amps 2.0 amps 1.0 amps
Answer:
2.0 amps
Explanation:
Current is the ratio of voltage to resistance:
I = V/R = (3.0)/(1.5) = 2.0
The current in the wire is 2.0 amps.
What are the magnitude and direction of the net force on the third spider (S3) when it is resting at the origin
Complete Question
The complete question is shown on the first uploaded image
Answer:
The magnitude is [tex]F_3 =0.62\ N[/tex]
Explanation:
From the question we are told that
The distance between the spiders is [tex]a =0.59\ m[/tex]
The charge on the [tex]S_1\ and\ S_3[/tex] is [tex]q_{1}=q_{3}=q =+4.9\mu \ C[/tex]
The charge on [tex]S_2[/tex] is [tex]q_2 = 4.9\mu \ C[/tex]
Given that the charge are arranged in an equilateral triangle, it implies that the angle at each vertices of the triangle is 60°
Generally the magnitude of net force on [tex]S_3[/tex] is mathematically represented as
[tex]F_3= F_{13} cos(60)+ F_{21} cos(60)[/tex]
So
[tex]F_{13} =\frac{k* q^2 }{a^2}[/tex]
Here k is the columns constant with value [tex]k = 9*10^9 \ kg\cdot m^3\cdot s^{-4} \cdot A^{-2}.[/tex]
So
[tex]F_{13}=\frac{9*10^9*((4.9*10^{-6})^2)}{0.59^2}[/tex]
=> [tex]F_{13} = 0.62 \ N[/tex]
From the diagram we see that [tex]F_{13}= F_{23} = 0.62\ N[/tex]
So
[tex]F_3=0.62cos(60)+0.62cos(60)[/tex]
[tex]F_3 =0.62\ N[/tex]
Now from the diagram the ls [tex]270^o[\tex] counterclockwise from x-axis
Explain how your weight can change even though your mass remains the same.
Answer:
See explanation below
Explanation:
Recall that Weight is a Force that results from the action of a gravitational field on our body mass. Therefore if one changes locations to places where the acceleration of gravity is different, our weight can change although the mass of our body stays the same.
For example, going to a high mountain, where the acceleration of gravity is a little smaller than at sea level, will produce such change. Also, going to another planet with different gravitational field, or going to the Moon (where the acceleration of gravity is about 1/6 of that on Earth which therefore will reduce our weight without reducing our mass)
Since weight is calculated with the equation:
Q=mg
the weight can also change when the gravitational acceleration (g) changes.
g can change at example when you travel to a different planet or (slightly) when gaining attitude on Earth (e.g. when climbing a mountain or flying on a plane you get lighter).
An electron is located on the x ‑axis at x0=−2.05×10−6 m . Find the magnitude and direction of the electric field at x=2.77×10−6 m on the x ‑axis due to this electron.
Answer:
The value is [tex]E = 62 \ N/C[/tex]
Explanation:
From the question we are told that
The initial position of the electron [tex]x_o = -2.05*10^{-6} \ m[/tex]
The position that is considered [tex]x= 2.77*10^{-6} \ m[/tex]
Generally the electric field is mathematically represented as
[tex]E = k * \frac{q}{r^2 }[/tex]
Here k is the coulombs constant with value [tex]k = 9*10^9 \ \ kg\cdot m^3\cdot s^{-4} \cdot A^{-2}.[/tex]
r is the distance covered which is mathematically represented as
[tex]r = x- x_o[/tex]
[tex]r = 2.77*10^{-6} -(-2.05*10^{-6})[/tex]
[tex]r = 4.82 *10^{-5}[/tex]
So
[tex]E = \frac{9*10^9 * 1.60*10^{-19}}{ (4.82 *10^{-6})}[/tex]
[tex]E = 62 \ N/C[/tex]
Answer:
Direction: Negative x-direction
Explanation:
The question tells you that both lie on the ‑axis, and the data indicate that the electron is in the negative ‑direction from the field point ( 0< ). Because the field produced by a negative source charge points toward the source, the field in this case points in the negative ‑direction.
An electric ceiling fan is rotating about a fixed axis with an initial angular velocity magnitude of 0.200 rev/s . The magnitude of the angular acceleration is 0.883 rev/s2 . Both the the angular velocity and angular accleration are directed counterclockwise. The electric ceiling fan blades form a circle of diameter 0.760 m .A. Compute the fan's angular velocity magnitude after time 0.204 s has passed.Express your answer numerically in revolutions per second.B. Through how many revolutions has the blade turned in the time interval 0.204 s from Part A?Express the number of revolutions numerically.C. What is the tangential speed vt of a point on the tip of the blade at time t = 0.204 s?Express your answer numerically in meters per second.D. Calculate the magnitude atat of the tangential acceleration of a point on the tip of the blade at time t = 0.204 s.Express the acceleration numerically in meters per second squared.
Answer:
(A). the angular velocity of fan is 0.380 rev/s.
(B). The number of revolution is 0.059 rad.
(C). The tangential speed of the blade is 0.907 m/s.
(D). The tangential acceleration of the blade is 2.10 m/s²
Explanation:
Given that,
Initial angular velocity = 0.200 rev/s
Angular acceleration = 0.883 rev/s²
Diameter = 0.760 m
Time = 0.204 s
(A). We need to calculate the angular velocity of fan
Using equation of angular motion
[tex]\omega_{f}=\omega_{i}+\alpha t[/tex]
Put the value into the formula
[tex]\omega_{f}=0.200+0.883\times0.204[/tex]
[tex]\omega_{f}=0.380\ rev/s[/tex]
(B). We need to calculate the number of revolution
Using formula of angular displacement
[tex]\theta=\omega_{i}t+\dfrac{1}{2}\alpha t^2[/tex]
Put the value into the formula
[tex]\theta=0.200\times0.204+\dfrac{1}{2}\times0.883\times(0.204)^2[/tex]
[tex]\theta=0.059\ rad[/tex]
(C). We need to calculate the tangential speed of the blade
Using formula of speed
[tex]v=\dfrac{d}{2}\omega_{f}[/tex]
Put the value into the formula
[tex]v=\dfrac{0.760}{2}\times0.380\times2\pi[/tex]
[tex]v=0.907\ m/s[/tex]
(D). We need to calculate the tangential acceleration of the blade
Using formula of tangential acceleration
[tex]a_{t}=\alpha r[/tex]
Put the value into the formula
[tex]a_{t}=0.883\times0.38\times2\pi[/tex]
[tex]a_{t}=2.10\ m/s^2[/tex]
Hence, (A). the angular velocity of fan is 0.380 rev/s.
(B). The number of revolution is 0.059 rad.
(C). The tangential speed of the blade is 0.907 m/s.
(D). The tangential acceleration of the blade is 2.10 m/s²
what is systematic error ?
Explanation:
Systematic error (also called systematic bias) is consistent, repeatable error associated with faulty equipment or a flawed experiment design. These errors are usually caused by measuring instruments that are incorrectly calibrated or are used incorrectly.
The gravitational pull of the sun on Earth keeps Earth orbiting around the sun. Which statement is correct about the force that Earth exerts on the sun?
A. Earth pulls the sun away from itself with a force equal to the ratio of the mass of the sun to the mass of Earth.
B. Earth pulls the sun toward itself with a force equal to the ratio of the mass of the sun to the mass of Earth.
C. Earth pulls the sun away from itself with an equal force.
D. Earth pulls the sun toward itself with an equal force,
Answer:
Earth pulls the sun towards itself with a force equal to the ratio of the mass of the sun to the mass of Earth
The Earth pulls the sun toward itself with an equal force. (Option D)
According to the 3rd Newton's Law, forces existing in the universe are shown in pairs, that is to say, for all action force, there is a corresponding reaction force of equal magnitude and opposite direction. By the Newton's Law of Gravitation we understand that gravitation between the Sun and the Earth is done because of a gravitational field created by mutual interaction, in terms of their masses and distance among them. The pair of forces is not based on direct contact.
Hence, we conclude that the Earth pulls the sun toward itself with an equal force.
We kindly invite to check this question on gravitation: https://brainly.com/question/3009841
A bus took 8 hours to travel 639 km. For the first 5 hours, it
travelled at an average speed of 72 km/h. What was the
average speed for the remaining time of the journey?
Answer:
93
Explanation:
Describe the motion of an object:
a. for which the direction of the acceleration is the same as the direction of motion of the object.
b. for which the direction of the acceleration is opposite to the direction of motion of the object.
c. for which the change in velocity is zero.
d. for which the initial velocity is zero but the acceleration is not zero.
Answer:
A. Here object is moving with increasing velocity
B. Here the object is moving with decreasing velocity that is it is decelerating
C. Here the initial and final velocity are the same so the object moves at constant velocity
D. Here the object started from rest but reached a certain velocity with time so a non zero acceleration was attained
Answer:
Answer:
A. Here object is moving with increasing velocity
B. Here the object is moving with decreasing velocity that is it is decelerating
C. Here the initial and final velocity are the same so the object moves at constant velocity
D. Here the object started from rest but reached a certain velocity with time so a non zero acceleration was attained
Explanation:
Sabiendo que la velocidad de la luz en el Cuarzo es de 194.166.099 m/s y de 203.525.090 m/s en la glicerina: a) Hallar los índices de refracción absolutos en la glicerina y en el cuarzo. b) Hallar el índice de refracción relativo del agua respecto al diamante.
Answer:
a) glycerin n = 1.5440 , quartz n = 1.4730
b) n₂₁ = 0.550
Explanation:
The refractive index is
n = c / v
where c is the speed of light in a vacuum and v the speed of light in the material medium
Let's use this expression to find the indexes of refraction
a) glycerin of v= 194166099 m / s
n = 2,998 10 8/194166099
n = 1.5440
quartz v = 203525090 m / s
n = 2,998 108/203525090
n = 1.4730
b) the relative refractive index is the relationship between the absolute refractive indices of two materials
diamond n₁ = 2.417
water n₂ = 1.33
the relative refractive index
n₂₁ = n_water / n_diamond
n₂₁ = 1.33 / 2.417
n₂₁ = 0.550
A 400 N steel ball is suspended by a light rope from
the ceiling. The tension in the rope is
Answer:
As force = tension in string so tension in string is 400N
Explanation:
Tension in the rope is "400 N".
Tension is the force developed inside a flexible material or medium, such as a cable, wire, or rope. This force depends upon the externally applied load. In the case of equilibrium, the tension in a rope or string is equal to the load applied to the rope or string, externally.
Since the steel ball and the rope system is in equilibrium in our case. Therefore, the tension in the rope must be equal to the load (weight) of the steel ball:
Tension = Weight of Steel Ball
Tension = 400 N
Learn more about Tension here:
https://brainly.com/question/19802859?referrer=searchResults
https://brainly.com/question/2008782?referrer=searchResults
The attached picture shows the tension on a steel ball hung by a rope.
Light of wavelength 3500Å is incident on two metals A and B whose work functions are 3.2 eV and 1.9 eV respectively. Which metal will emit photoelectrons?
(a) A
(b) B
(c) Both A and B
(d) Neither A nor B
Answer:
(c) Both A and B
Explanation:
Given;
wavelength of the incident light, λ = 3500 Å = 3500 x 10⁻¹⁰ m
The energy of the incident light is given by;
E = hf
where;
h is Planck's constant = 6.626 x 10⁻³⁴ J/s
f is frequency = c / λ
[tex]E = \frac{hc}{\lambda} \\\\E = \frac{(6.626*10^{-34})(3*10^8)}{3500*10^{-10}}\\\\E = 5.68 *10^{-19} \ J\\\\E = 5.68 \ eV[/tex]
Work function is the minimum amount of energy required to liberate electrons from a metal surface.
The work function of metal A is 3.2 eV and
Th e work function of metal B is 1.9 eV
Both work functions are less than the incident energy of the light calculated as 5.68eV.
Thus, both metals will emit photoelectrons.
(c) Both A and B