Ethene is exposed to h2 in a solution containing a chunk of solid palladium. if it reacts successfully, the original alkene will:________

Answer:

C.) H₂O and K₂SO₄

Explanation:

This appears to be a double-displacement reaction. In these reactions, the cation of one substance is swapped with the cation of another.

So, K⁺ from KOH is swapped with the H⁺ from H₂SO₄. The new compounds should have an overall charge of 0. Therefore, it may be necessary to modify the amount of each ion (not just be 1:1).

K₂SO₄
-----> K⁺ and SO₄²⁻

-----> + 1 + 1 + (-2) = 0

H₂O

-----> H⁺ and OH⁻

-----> + 1 + (-1) = 0

Answer:

1) a) 1.81  × 10²³ molecules (b) 1.93  × 10²³ molecules (c) 0.66× 10²³ molecules

2) a) 0.45× 10²³ions  (b) 0.84× 10²³ions (c) 3.6 × 10²³ions

Explanation:

1) Number of molecules:

The given problem will solve by using Avogadro number.

It is the number of atoms , ions and molecules in one gram atom of element, one gram molecules of compound and one gram ions of a substance.

The number 6.022 × 10²³ is called Avogadro number.

a) 16g of H₂CO₃

Number of moles = mass/ molar mass

Number of moles = 16 g/ 62.03 g/mol

Number of moles = 0.3 mol

1 mol = 6.022 × 10²³ molecules

0.3 mol ×  6.022 × 10²³ molecules /1 mol

1.81  × 10²³ molecules

b) 20g of HNO₃

Number of moles = mass/ molar mass

Number of moles = 20 g/ 63.01 g/mol

Number of moles = 0.32 mol

1 mol = 6.022 × 10²³ molecules

0.32 mol ×  6.022 × 10²³ molecules /1 mol

1.93  × 10²³ molecules

c) 30g of C₆H₁₂O₆

Number of moles = mass/ molar mass

Number of moles = 20 g/ 180.156 g/mol

Number of moles = 0.11 mol

1 mol = 6.022 × 10²³ molecules

0.11 mol ×  6.022 × 10²³ molecules /1 mol

0.66× 10²³ molecules

2. Calculate the number of ions in the following compounds:

a) 10g of AlCl₃

Number of moles = mass/ molar mass

Number of moles = 10g/ 133.34 g/mol

Number of moles = 0.075 mol

1 mol = 6.022 × 10²³ ions

0.075 mol ×  6.022 × 10²³ ions/1 mol

0.45× 10²³ions

b) 30g of BaCl₂

Number of moles = mass/ molar mass

Number of moles = 30g/ 208.23 g/mol

Number of moles = 0.14 mol

1 mol = 6.022 × 10²³ ions

0.14 mol ×  6.022 × 10²³ ions/1 mol

0.84× 10²³ions

c) 58 g of H2SO4

Number of moles = mass/ molar mass

Number of moles = 58g/ 98.079 g/mol

Number of moles = 0.59 mol

1 mol = 6.022 × 10²³ ions

0.59 mol ×  6.022 × 10²³ ions/1 mol

3.6 × 10²³ions

Explanation:

Let's check the equation

[tex]\sf NH_3+H^+\leftrightharpoons NH_4^+H_2O[/tex]

As per Le ch a.tlers principle

So

If we remove NH_4+

Water would increase

Option C

Answer:

Any base with an ability to dissolve in water are called alkalis. All alkalis are bases, however, not all bases are alkalis.

The concentration of the acetic acid before titration is 0.128M

For weak acid and strong base titration-

Moles of acetic acid =  moles of NaOH

Given concentration of NaOH = 0.1067M

Volume of NaOH = 30.07ml = 0.03007L

Using the formula, Concentration = Moles/Volume

Moles of NaOH = concentration X volume = 0.1067 X 0.03007 = 0.0032

Therefore, moles of acetic acid  = 0.0032mole

Using the formula, Concentration = Moles/Volume

Concentration of acetic acid =  0.0032/0.025 = 0.128M

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If 30.0 mL of 0.150 M CaCl₂ is added to 38.5 mL of 0.100 M AgNO3. The mass of the AgCl precipitate is 0.552 g.

Stoichiometry helps us use the balanced chemical equation to measure quantitative relationships and it is to calculate the amounts of products and reactants that are given in a reaction.

The balanced chemical equation is the equation in which the number of atoms on the reactant side is equal to the number of atoms on the product side in an equation.

Now we have to write the balanced equation

2AgNO₃ + CaCl₂ →  2AgCl + Ca(NO₃)₂

Molecular Weight of CaCl₂ = 110.98 g/mol

Molecular Weight of AgNO₃ = 170.01 g/mol

Molecular Weight of AgCl = 143.45 g/mol

Here,

Volume of CaCl₂ = 30.0 mL = 0.03L

Volume of AgNO₃ = 38.5 mL = 0.0385 L

Now find the number of moles

Number of moles = Volume × Molarity

Number of moles of CaCl₂ = 0.03 L × 0.150

                                             = 0.00456 mol

Number of moles of AgNO₃ = 0.0385 L × 0.100

                                               = 0.00385 mol

The stoichiometric ratio of AgNO₃ to CaCl₂ is 2:1.

= [tex]\frac{0.00385}{2}[/tex]

= 0.001925 mol                      

According to Stoichiometry Mass of AgCl

[tex]= 0.0385 \times \frac{0.1}{1\ \text{mol}} \times \frac{2\ \text{mol} AgCl}{2\ \text{mol} AgNO_3} \times \frac{143.4\ g}{1\ \text{mol}}[/tex]

= 0.552 g AgCl

Thus from the above conclusion we can say that If 30.0 mL of 0.150 M CaCl₂ is added to 38.5 mL of 0.100 M AgNO3. The mass of the AgCl precipitate is 0.552 g.

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The pH of buffered solution is:

The two buffered solutions have 'equal' pH values.

Comparison between two buffer solutions:

To compare the pH of two different buffer solutions with different concentrations, Henderson-Hasselbalch equation is used.

pH = pKa + log [tex]\frac{Salt}{Acid}[/tex]

pKa of HOAc = 4.76

In solution 1:

Concentration of salt= 5 M

Concentration of acid= 5 M

Putting the values in the equation,

pH = 4.76 + log [tex]\frac{5}{5}[/tex]

pH = 4.76 + log1

pH = 4.76

In solution 2:

Concentration of salt= 0.050 M

Concentration of acid= 0.050 M

Putting the values in the equation,

pH = 4.76 + log[tex]\frac{0.050}{0.050}[/tex]

pH = 4.76 + log1

pH = 4.76

As the ratio  [tex]log\frac{salt}{acid}[/tex] is the same for the different solutions.

Therefore, the pH of the solution remains the same in both the buffer solutions even if the two solutions have different concentrations.

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A steel cylinder contains a mixture of nitrogen, oxygen, and carbon dioxide gases. The total pressure in the tank is 2710 torr. The pressure exerted by the nitrogen and oxygen is 930 and 850 torr, respectively.  27.1 torr is the partial pressure of the carbon dioxide in the mixture.

Dalton's Law of partial pressure states that the total pressure exerted by non reacting gaseous mixture at a constant temperature and given volume is equal to the sum of partial pressure of all gases.

It is expressed as:

[tex]P_{A} = X_{A} P_{T}[/tex]

where,

[tex]P_{A}[/tex] = Partial pressure of gas A

[tex]X_{A}[/tex] = Mole fraction of gas A

[tex]P_{T}[/tex] = Total pressure

Mole Fraction of Nitrogen

= [tex]\frac{930}{930 + 850}[/tex]

= 0.52

Mole Fraction of Oxygen

= [tex]\frac{850}{850 + 930}[/tex]

= 0.47

Now,

Mole fraction of nitrogen + Mole fraction of oxygen + Mole fraction of carbon dioxide = 1

⇒ 0.52 + 0.47 + Mole fraction of carbon dioxide = 1

⇒ 0.99 + Mole fraction of carbon dioxide = 1

⇒ Mole fraction of carbon dioxide = 1 - 0.99

⇒ Mole fraction of carbon dioxide = 0.01

Now put the value in above expression we get

[tex]P_{A} = X_{A} P_{T}[/tex]

     = 0.01 × 2710

     = 27.1 torr

Thus from the above conclusion we can say that A steel cylinder contains a mixture of nitrogen, oxygen, and carbon dioxide gases. The total pressure in the tank is 2710 torr. The pressure exerted by the nitrogen and oxygen is 930 and 850 torr, respectively.  27.1 torr is the partial pressure of the carbon dioxide in the mixture.

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The compound that is formed is calcium hydroxide.

When limestone is decomposed at a high temperature, calcium oxide is formed as the residue.

[tex]CaCO_3 --- > CaO + CO_2[/tex]

When the calcium oxide residue is treated with water, a calcium hydroxide solution is formed.

[tex]CaO + H_2O -- > Ca(OH)_2[/tex]

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18.06 ₓ [tex]10^{23}[/tex] molecules in 3 mol of carbon dioxide (CO2).

The proportionality factor that connects the quantity of substance in a sample to the number of constituent particles in that sample is called the Avogadro constant. The reciprocal mole, which is its SI unit, is specified precisely as NA 6.02214076 × [tex]10^{23}[/tex] [tex]mol^{-1}[/tex]. It bears Amedeo Avogadro's name, an Italian scientist.

When dealing with very big quantities, chemistry uses Avogadro's number. It serves as the foundation for the mole, a unit of measurement that makes converting between moles, mass, and the number of molecules simple. The quantity, for instance, can be used to determine how many water molecules make up a single snowflake.

1 Mole is 6.02ₓ [tex]10^{23}[/tex] molecules.

Therefore 3 Moles of Carbon Dioxide ([tex]CO_{2}[/tex]) =3(6.02ₓ [tex]10^{23}[/tex])

3 Moles of Carbon Dioxide ([tex]CO_{2}[/tex]) =18.06 ₓ [tex]10^{23}[/tex]molecules of [tex]CO_{2}[/tex].

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The freezing point of a solution is -1.16°C

Calculation,

The equation which give relation between freezing point depletion and molality is,

Δ[tex]T_{f} = K_{f} .m[/tex]      ... (i)

Moles of the solute = 22.0 g / 114.23 g/mole = 0.193 mole

Mass of the solvent in g = 148 g

Mass of the solvent in kg = 0.148 kg

Molality = 0.193 mole/ 0.148 kg = 1.3 m

Now, after putting the value of  [tex]K_{f}[/tex] and m in equation (i) we get

Δ[tex]T_{f} = K_{f} .m[/tex]  

Δ[tex]T_{f}[/tex]= 5.12°C/m×1.3 m = 6.66°C

Δ[tex]T_{f}[/tex]=  [tex]T_{f}[/tex] (solvent) - [tex]T_{f}[/tex] (solution)

[tex]T_{f}[/tex] (solution) = [tex]T_{f}[/tex] (solvent)  -Δ[tex]T_{f}[/tex]= 5.5 °C - 6.66°C = -1.16°C

The freezing point of a is -1.16°C

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Answer:

0.638 M NaOH

Explanation:

To find the molarity of the solution, you need to (1) convert grams NaOH to moles NaOH (via the molar mass of NaOH) and then (2) calculate the molarity (via the molarity formula). It is important to arrange the conversions/ratios in a way that allows for the cancellation of units (the desired unit should be in the numerator).

(Step 1)

Molar Mass (NaOH): 22.990 g/mol + 15.998 g/mol + 1.008 g/mol

Molar Mass (NaOH): 39.996 g/mol

25.5 grams NaOH                 1 mole
-----------------------------  x  ----------------------------  =  0.638 moles NaOH
                                           39.996 grams

(Step 2)

Molarity = moles / volume (L)

Molarity = 0.638 moles / 1 L

Molarity = 0.638 M

CH3 is the empirical formula for the compound.

A sample of a compound is determined to have 1.17g of Carbon and 0.287 g of hydrogen.

The number of atom or moles in the compound is

1.17 g C X  1 mol of C / 12.011 g C = 0.097411 mol of C.

0.287 g H x 1 mol of  H / 1 g H = 0.28474 mol H.

This compound contains 0.097411 mol of carbon and 0.28474 mol of Hydrogen.

So we can represent the compound with the formula C0.974H0.284.

Subscripts in formulas can be made into whole numbers by multiplying the smaller subscript by the larger subscript.

we can divide 0.284 by 0.0974.

0.284 / 0.0974 = 3.

So here, Carbon is one and hydrogen is 3.

We can write the above formula as a CH3.

Hence the empirical formula for the sample compound is CH3.

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Based on the given scenario, the rate of increase in water pressure in atm/km is known to be 992 atm/km.

Pressure is known to be that kind of force that is known to often pushes water via pipes.

Note that Water pressure is a tool that is often used to know or identify the flow of water from any given tap. The amount of pressure at one's tap is said to be often dependent on how high the service tank or water tower is above one's home.

Therefore since 1 atm/m  = 1000 atm/km

Hence 0.992 atm/m  :

           = 0.992 x 1000

          = 992 atm/km.

Therefore, Based on the given scenario, the rate of increase in water pressure in atm/km is known to be 992 atm/km.

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Answer:

larger the intermolecular forces in a compound, the slower its evaporation rate

Explanation:

socratic

Answer:

2 FeCl3 → 2 Fe + 3 Cl2

Explanation:

2 Fe and 6 Cl on the reactants side, and 2 Fe and 6 Cl on the products side.

Answer:

Iron ore, coke and lime stone are some raw materials used for extracting iron.

Hope it helps! :)

The reaction is based on law of conservation of mass.

The balanced chemical equation is

[tex]$4 \mathrm{NaI}+\mathrm{Pb}\left(\mathrm{SO}_{4}\right)_{2} \rightarrow \mathrm{PbI}_{4}+2 \mathrm{Na}_{2} \mathrm{SO}_{4}$[/tex]

Every balanced chemical equation follows the direction of conservation of mass. This law states that mass can neither be completed nor can be destroyed but it can only be transformed from one condition to another form. This law likewise states that the total number of individual atoms on the reactant side must be comparable to the total number of individual atoms on the product side.

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Answer:

Fe(CH₂CO₂)₂, Fe₂MnO, Pb(CH₂CO₂)₄, PbMnO

Explanation:

Cations (positively charged ions) can only form ionic bonds with anions (negatively charged ions). However, you can't just simply put one cation and one anion together to form a compound. Each compound needs to been neutral, or have an overall charge of 0. When cations and anions do not have charges that perfectly cancel, you need to modify the amount of each ion in the compound.

1.) Fe(CH₂CO₂)₂

   ----> Fe²⁺ and 2 CH₂CO₂⁻

   ----> +2 + (-1) + (-1) = 0

2.) Fe₂MnO

   ----> 2 Fe²⁺ and 1 MnO⁴⁻
   ----> 2(+2) + (-4) = 0

3.) Pb(CH₂CO₂)₄
   ----> 1 Pb⁴⁺ and 4 CH₂CO₂⁻
   ----> +4 + (-1) + (-1) + (-1) + (-1) = 0

4.) PbMnO

   ----> 1 Pb⁴⁺ and 1 MnO⁴⁻

   ----> +4 + (-4) = 0

answer - Albert Einstein

explanation -

Albert Einstein is arguably the most influential scientist of the 20th century. His … general theory of relativity changed our understanding of space and time, becoming one of the two pillars of modern physics – the other being quantum mechanics.

In the electrolysis of water,  3490 hour will it take to produce 165.0 L of H2 at 1.0 atm and 273 K using an electrolytic cell through which the current is 113.0 mA.

The ideal gas law states that the pressure of gas is directly proportional to the volume and temperature of the gas.

It is expressed as

PV = nRT

where,

P = Pressure

V = Volume in liters

n = number of moles of gas

R = Ideal gas constant

T = Temperature in kelvin

Here,

P = 1.0 atm

V = 165.0 L

R = 0.0821 atm. L/mol.K (Ideal gas constant)

T = 273 K

n = ?

Now put the value in above expression, we get

PV = nRT

1.0 atm × 165.0 L = n × 0.0821 atm. L/mol.K × 273 K

165.0 atm. L = n × 22.4  atm. L/mol

[tex]n = \frac{165.0\ \text{atm. L}}{22.4\ \text{atm. L/mol}}[/tex]

n = 7.36 mol

The reaction is

2H⁺ + 2e⁻ → H₂

1 mol of electrons is produced from 96500 C

So,

[tex]96500 \frac{C}{\text{mol} \times e} \times 2e \times 7.36\ \text{mol}[/tex]

= 1,420,480 C

Convert milliampere to C/s

1mA = 0.001 C/s

113.0 mA = 113.0 × 0.001

               = 0.113 c/s

The relation between current, charge and time is expressed as:

[tex]I = \frac{Q}{t}[/tex]

where,

I = Current

Q = Charge in Coulomb

t = time

Now put the value in above formula we get

[tex]I = \frac{Q}{t}[/tex]

  [tex]= \frac{1,420,480\ C}{0.113\ C/s}[/tex]

  = 12,570,619.469 s

  = 3490 hour

Thus from the above conclusion we can say that In the electrolysis of water,  3490 hour will it take to produce 165.0 L of H2 at 1.0 atm and 273 K using an electrolytic cell through which the current is 113.0 mA.

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Answer:

Atoms gain/lose electrons and are held together by electrostatic forces.

The statement is False.

Ethanol is one of many toxic substances found in tobacco smoke.

Ethanol is used in the manufacture of drugs, plastics, lacquers, polishes, plasticizers, and cosmetics. Ethanol is utilized in remedy as a topical antiinfective, and as an antidote for ethylene glycol or methanol overdose.

Ethanol is a natural chemical compound. it's far simple alcohol with the chemical formula C₂H₆O. Its system can be additionally written as CH ₃−CH ₂−OH or C ₂H ₅OH and is frequently abbreviated as EtOH. Ethanol is a risky, flammable, colorless liquid with a characteristic wine-like smell and pungent taste.

Within the worst instances, there can also be respiratory problems, low blood strain, incontinence coronary heart troubles, blood troubles, liver damage, and loss of life. Ethanol can also dry out and worsen the skin; there may be aches, redness, and swelling. Eye publicity to ethanol also can purpose tearing, burning, and stinging.

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Pure liquids and solids at the equilibrium stage:

Pure solids and pure liquids are not included in expressions for the equilibrium constant of heterogeneous equilibria since their concentrations are constant across time. Therefore, including it in our equilibrium expression is not significant.

Equilibrium expression:

When a certain chemical reaction is in equilibrium, the rates of the forward and backward reactions are equal, which means that there is no net change in the concentrations of the reactants and products and that the reaction mixture's composition does not change.

The concentration of solid and liquid:

Solid or liquid concentration,

= No. of Moles/ Volume in L

= Mass/(Volume × molar mass)

= Density/ Molar mass

Pure solids and liquids have constant densities and molar masses at a constant temperature.

Because of this, they have constant molar concentrations, which means that they are not considered in the equilibrium constant for a heterogeneous reaction.

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XY2Z - linear

XY2Z2 - bent(120)

XY2Z3 - bent(109)

XY3Z -  trigonal pyramidal

XY3Z2 - t-shaped

XY4Z -  see-saw

XY4Z2 - square planar

XY5Z - square pyramidal

Linear shape: A linear molecule is one that has its atoms arranged in a straight line.

Bent shape: One type of bent molecular geometry features a center atom with two lone pairs of electrons and two bond pairs attached to it. Other names for it include angular and V-shaped.

Trigonal pyramidal: A trigonal pyramid is a molecular shape that resembles a tetrahedron and has one atom at the top and three at the corners of the base.

T-Shaped: When a central atom has three ligands, the structure of the molecule is said to have a T-shaped molecular geometry.

See-saw: This shape is caused by a lone pair of electrons on the central atom.

Square planar: In square planar molecular geometry, constituent atoms create the square's four corners on the same plane and surround the center atom.

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Answer:

A resistor resists extra electric current.

Answer:

Sucrose to is the substrate of the reaction because is a simple sugar( disaccharide) which produce glucose and fructose in the presence of sucrase or when it is hydrolysed.

Based on the type of experiment that is being conducted:

This is the term that is used to refer to the variable that is used to arrive at conclusions about the dependent variable.

The experiment is trying to tell us that the temperature of a material is the function of the heat applied to it and the type of material.

This is the term that is used to refer to the variable of interest. It is what is being tested in the experiment.

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The oxidation number for S in the compound SO3 is +6 (option D). Details about oxidation number can be found below.

Oxidation number of an element is the hypothetical charge of an atom within a molecule.

The oxidation number of elements in a compound adds up to the overall charge of that compound.

According to this question, O has an oxidation number of -2 in SO3, the oxidation number of S can be calculated as follows:

x - 2(3) = 0

x - 6 = 0

x = 6

Therefore, the oxidation number for S in the compound SO3 is +6.

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The answer is D: 6+

Worked for me on EDGE 2023

If the product of the process is Th-234, the we now know that the original atom must be U-238.

An alpha decay is said to occur when there is the loss of an alpha particle from an atom. Now we know that  when there is a loss of an alpha particle, the mass number is decreased by 4 four units while the atomic number is decreased by two units.

If the product of the process is Th-234, the we now know that the original atom must be U-238. It is found two places after the thorium atom in the periodic table.

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