Every year the Lee family has a big family dinner, and everyone brings a mug to exchange. The mugs are put on wooden hangers on the wall, and each wooden hanger can hold 12 mugs. Last year the family had 15 mugs to hang up. This year the Lee family filled three wooden hangers. How many more mugs were brought to the Lee family dinner this year compared to the previous year? *

Answers

Answer 1

Answer:

21 more mugs were brought this year than last year.

Step-by-step explanation:

We can solve by subtracting the initial amount of mugs from the final amount of mugs.

To find the amount of mugs hung up this year, we will use the equation: m = 12w where m = the number of mugs & w = the number of wooden hangers. The 12 represents the amount of mugs per wooden hanger.

We can plug in 3 for w since 3 wooden hangers were filled up and we would get 12(3) = m = 36 mugs

Now we subtract last year's total mugs hung up from this year's total mugs hung up.

We end up with 36 - 15 = 21


Related Questions

Find the missing value can someone help me get this

Answers

Answer:

-3

Step-by-step explanation:

-5 = -8 - (- 3)

the answer is -3 lololol

Trigonometric ratios
class 9
please answer my questions​

Answers

Step-by-step explanation:

Hi there!

Please see the answer in the picture.

Hope it helps!

1. Approach

One is given a trigonometric equation with and one is asked to prove that it is true. Using the attached image, combined with the knowledge of trigonometry, one can evaluate each trigonometric function. Then one can simplify each ratio to solve. To yield the most accurate result, one has to each of the ratios in a fractional form, rather than simplifying it into a decimal form. Remember the right angle trigonometric ratios, these ratios describe the relationship between the sides and angles in a right triangle. Such ratios are as follows,

[tex]sin(\theta)=\frac{opposite}{hypotenuse}\\\\cos(\theta)=\frac{adjacent}{hypotenuse}\\\\tan(\theta)=\frac{opposite}{adjacent}\\\\csc(\theta)=\frac{hypotenuse}{opposite}\\\\sec(\theta)=\frac{hypotenuse}{adjacent}\\\\cot(\theta)=\frac{adjacent}{opposite}[/tex]

Please note that the terms (opposite) and (adjacent) are relative to the angle uses in the ratio, however the term (hypotenuse) refers to the side opposite the right angle, this side never changes its name. Use these ratios to evaluate the trigonometric functions. Then simplify to prove the identity.

2. Problem (9)

[tex]\frac{sin(60)+cos(30)}{1+sin(30)+cos(60)}=sin(60)[/tex]

As per the attached image, the following statements regarding the value of each ratio can be made:

[tex]sin(60)=\frac{\sqrt{3}}{2}\\\\cos(30)=\frac{\sqrt{3}}{2}\\\\sin(30)=\frac{1}{2}\\\\cos(60)=\frac{1}{2}[/tex]

Substitute,

[tex]\frac{sin(60)+cos(30)}{1+sin(30)+cos(60)}=sin(60)[/tex]

[tex]\frac{\frac{\sqrt{3}}{2}+\frac{\sqrt{3}}{2}}{1+\frac{1}{2}+\frac{1}{2}}=\frac{\sqrt{3}}{2}[/tex]

Simplify,

[tex]\frac{\frac{\sqrt{3}}{2}+\frac{\sqrt{3}}{2}}{1+\frac{1}{2}+\frac{1}{2}}=\frac{\sqrt{3}}{2}[/tex]

[tex]\frac{\frac{2\sqrt{3}}{2}}{1+\frac{1}{2}+\frac{1}{2}}=\frac{\sqrt{3}}{2}[/tex]

[tex]\frac{\frac{2\sqrt{3}}{2}}{1+1}=\frac{\sqrt{3}}{2}[/tex]

[tex]\frac{\sqrt{3}}{1+1}=\frac{\sqrt{3}}{2}[/tex]

[tex]\frac{\sqrt{3}}{2}=\frac{\sqrt{3}}{2}[/tex]

Thus, this equation is true.

2. Problem (10)

Use a similar strategy to evaluate this equation,

[tex]\frac{1-cos(30)}{sin(30)}=\frac{1-cot(60)}{1+cot(60)}[/tex]

Use the attached image to evaluate the ratios.

[tex]cos(30)=\frac{\sqrt{3}}{2}\\\\sin(30)=\frac{1}{2}\\\\cot(60)=\frac{1}{\sqrt{3}}[/tex]

Substitute,

[tex]\frac{1-cos(30)}{sin(30)}=\frac{1-cot(60)}{1+cot(60)}[/tex]

[tex]\frac{1-\frac{\sqrt{3}}{2}}{\frac{1}{2}}=\frac{1-\frac{1}{\sqrt{3}}}{1+\frac{1}{\sqrt{3}}}[/tex]

Simplify,

[tex]\frac{1-\frac{\sqrt{3}}{2}}{\frac{1}{2}}=\frac{1-\frac{1}{\sqrt{3}}}{1+\frac{1}{\sqrt{3}}}[/tex]

[tex]\frac{\frac{2-\sqrt{3}}{2}}{\frac{1}{2}}=\frac{1-\frac{1}{\sqrt{3}}}{1+\frac{1}{\sqrt{3}}}[/tex]

[tex]\frac{\frac{2-\sqrt{3}}{2}}{\frac{1}{2}}=\frac{\frac{\sqrt{3}-1}{\sqrt{3}}}{1+\frac{1}{\sqrt{3}}}[/tex]

[tex]\frac{\frac{2-\sqrt{3}}{2}}{\frac{1}{2}}=\frac{\frac{\sqrt{3}-1}{\sqrt{3}}}{\frac{\sqrt{3}+1}{\sqrt{3}}}[/tex]

[tex]2-\sqrt{3}=\frac{\frac{\sqrt{3}-1}{\sqrt{3}}}{\frac{\sqrt{3}+1}{\sqrt{3}}}[/tex]

[tex]2-\sqrt{3}=\frac{\sqrt{3}-1}{\sqrt{3}}*\frac{\sqrt{3}}{\sqrt{3}+1}}[/tex]

[tex]2-\sqrt{3}=\frac{\sqrt{3}-1}{\sqrt{3}+1}[/tex]

Rationalize the denominator,

[tex]2-\sqrt{3}=\frac{\sqrt{3}-1}{\sqrt{3}+1}[/tex]

[tex]2-\sqrt{3}=\frac{\sqrt{3}-1}{\sqrt{3}+1}*\frac{\sqrt{3}-1}{\sqrt{3}-1}[/tex]

[tex]2-\sqrt{3}=\frac{(\sqrt{3}-1)^2}{3-1}[/tex]

[tex]2-\sqrt{3}=\frac{3-2\sqrt{3}+1}{2}[/tex]

[tex]2-\sqrt{3}=\frac{4-2\sqrt{3}}{2}[/tex]

[tex]2-\sqrt{3}=2-\sqrt{3}[/tex]

Therefore, this equation is also true.

The area of a square field is 60025 square metre. Find the perimeter of the field. With explanation .

Answers

Answer: P≈2.4×10 power5

Step-by-step Explanation: P=4a=4·60025=2.401×10 power5

Answer:

[tex]\huge \boxed{\mathrm{980 \ m}}[/tex]

Step-by-step explanation:

The formula for the area of a square is:

[tex]A=s^2[/tex]

The area is given as 60025 m².

We need to find the length of each side.

[tex]60025=s^2[/tex]

Take the square root of both sides.

[tex]s=245[/tex]

The side length is 245 m.

The formula for the perimeter of a square is:

[tex]P=4s[/tex]

Plug in the value for the side length.

[tex]P=4(245)[/tex]

[tex]P=980[/tex]

The perimeter of the field is 980 m.

find the value s of.. a and b if 0 and 2 are the zeros of the polynomial p(x) =2xcube minus 5xsquare plus ax plus b find the third zero of the polynomial ​

Answers

Answer:

a = 2, b = 0 , x = [tex]\frac{1}{2}[/tex]

Step-by-step explanation:

Given that x = 0 and x = 2 are zeros of p(x) , then

p(0) = 0 and p(2) = 0

p(0) = 2(0)³ - 5(0)² + a(0) + b = 0 , that is

0 - 0+ 0 + b = 0, then b = 0

p(2) = 2(2)³ - 5(2)² + 2a + b = 0 , that is

16 - 20 + 2a + 0 = 0

- 4 + 2a = 0 ( add 4 to both sides )

2a = 4 ( divide both sides by 2 )

a = 2

Then

p(x) = 2x³ - 5x² + 2x ← factor out x from each term

      = x(2x² - 5x + 2)

      = x(2x - 1)(x - 2)

To find zeros equate p(x) to zero

x(2x - 1)(x - 2) = 0

Equate each factor to zero and solve for x

x = 0

x - 2 = 0 ⇒ x = 2

These are the 2 zeros already known (given)

2x - 1 = 0 ⇒ 2x = 1 ⇒ x = [tex]\frac{1}{2}[/tex] ← third zero of p(x)

       

please answer if you can

Answers

Step-by-step explanation:

denominator

add numerator

pls help with this question

Answers

Try this

(x^2 + x - 12) + (x^2 - 8x + 16)

2y - 1

√36

i wanted to help you! :)

Answer:

[tex]\frac{3}{3}[/tex] = 1   (everything basically cancels)

Step-by-step explanation:

We can calculate EEE, the amount of euros that has the same value as DDD U.S. Dollars, using the equation E=\dfrac{17}{20}DE= 20 17 ​ DE, equals, start fraction, 17, divided by, 20, end fraction, D. How many euros have the same value as 111 U.S. Dollar? euros How many U.S. Dollars have the same value as 111 euro? dollars

Answers

Answer: 1 U.S.dollar  = 0.85 euro.

1 euro = 1.18 dollars.

Step-by-step explanation:

The given equation: [tex]E=\dfrac{17}{20}D[/tex]

, where 'E' is the amount of euros that has the same value as 'D' U.S. Dollars.

At D= 1,

[tex]E=\dfrac{17}{20}=0.85\text{ euro}[/tex]

i.e. 1 U.S.dollar  = 0.85 euro.

At E= 1 , we have

[tex]1=\dfrac{17}{20}D\\\\\Rightarrow\ D= 20/17\approx1.18\text{ dollars}[/tex]

Hence, 1 euro = 1.18 dollars.

Answer it answer it answer it.

Answers

Answer:

Option C. P = 3/q

Step-by-step explanation:

To know the the correct answer to the question, do the following:

Let us assume a certain number for P say 2 and 3, and then, find the corresponding value for q in each case to see which will give a decreased value for q.

Option A

When P = 2, q =.?

P = 3q

2 = 3q

Divide both side by 3

q = 2/3

When P = 3, q =.?

P = 3q

3 = 3q

Divide both side 3

q = 3/3

q = 1

From the above illustration, we can see that as P increase, q also increase.

Option B

When P = 2, q =.?

P – 3 = q

2 – 3 = q

q = – 1

When P = 3, q =.?

P – 3 = q

3 – 3 = q

q = 0

From the above illustration, we can see that as P increase, q also increase.

Option C

When P = 2, q =.?

P = 3/q

2 = 3/q

Cross multiply

2 × q = 3

Divide both side by 2

q = 3/2

q = 1.5

When P = 3, q =.?

P = 3/q

3 = 3/q

Cross multiply

3 × q = 3

Divide both side by 3

q = 3/3

q = 1

From the above illustration, we can see that as P increase, q decreases.

Option D.

When P = 2, q =.?

1/p = 3/q

1/2 = 3/q

Cross multiply

1 × q = 2 × 3

q = 6

When P = 3, q =.?

1/p = 3/q

1/3 = 3/q

Cross multiply

1 × q = 3 × 3

q = 9

From the above illustration, we can see that as P increase, q also increase.

Now, haven done the above, only option C gives a decreased value for q as the value of P increases.

c  

this before

Step-by-step explanation:

what is the x intercept for y=(2x(x-3))/(x-1). ?

my answer sheet says it is supposed to be -0.5​

Answers

Answer:

( 0,0) and (3,0)

Step-by-step explanation:

y=(2x(x-3))/(x-1)

Set y = 0

0 =(2x(x-3))/(x-1)

Multiply each side by x-1, which makes x not equal to 1

0 =(2x(x-3))

Using the zero product property

2x=0  x-3 =0

x=0   x= 3

The x intercepts are x=0   x= 3

( 0,0) and (3,0)

factorise the following 1. x²-2x+15.... 2. y²-19y+90​

Answers

Answer:

1. x²-2x+15

This can't be factored, I've tried multiple ways now, but it just can't be factored.

2. y²-19y+90​

Let's factor y^2−19y+90

y^2−19y+90

The middle number is -19 and the last number is 90.

Factoring means we want something like

(y+_)(y+_)

Which numbers go in the blanks?

We need two numbers that...

   Add together to get -19

   Multiply together to get 90

Can you think of the two numbers?

Try -9 and -10:

   -9+-10 = -19

   -9*-10 = 90

Fill in the blanks in

(y+_)(y+_)

with -9 and -10 to get...

(y-9)(y-10)

Answer:

(y−9) (y−10)

The common difference of an ap is -2 find its sum of first term is hundred and last term is -10 with full solution

Answers

Answer:

2520

Step-by-step explanation:

The n th term of an AP is

[tex]a_{n}[/tex] = a₁ + (n - 1)d

where a₁ is the first term and d the common difference.

To find the number of terms given [tex]a_{n}[/tex] = - 10 , d = - 2 and a₁ = 100, then

100 - 2(n - 1) = - 10 ( subtract 100 from both sides )

- 2(n - 1) = - 110 ( divide both sides by - 2 )

n - 1 = 55 ( add 1 to both sides )

n = 56 ← number of terms

Given n, a₁ and a₅₆ , then the sun of the terms is

[tex]S_{56}[/tex] = [tex]\frac{n}{2}[/tex] (a₁ + a₅₆ )

      = [tex]\frac{56}{2}[/tex] (100 - 10) = 28 × 90 = 2520

T. For a science experiment, Katie had
to cool one sample bacteria to -52°C.
She had to cool a second sample
bacterium to -79°C. What is the
difference in the two temperatures?
Please help me figure out the equation too.

Answers

Answer:

Step-by-step explanation:

A "difference" indicates subtraction is being used. The difference between these 2 numbers is found the same way we find the distance between 2 points on a number line. Since both the difference and the distance have to be positive numbers, the formula to find it is

|a - b| which is the absolute value of a - b.

If a = -52 and b = -79:

| -52 - (-79) | = | -52 + 79 | = 27 OR

If a = -79 and b = -52:

| -79 - (-52) | = | -79 + 52 | = | -27 | = 27

find the lower quartile for the data {47.2, 33.8, 43, 62, 5.8, 9, 61.4, 30.8, 68.2, 51.6, 13.2, 17.4, 64.2, 50.6, 29.4, 40.4}

Answers

Answer:

The lower quartile is 23.4

Step-by-step explanation:

The given data are;

47.2, 33.8, 43, 62, 5.8, 9, 61.4, 30.8, 68.2, 51.6, 13.2, 17.4, 64.2, 50.6, 29.4, 40.4

Rearranging the data, we have;

5.8, 9, 13.2, 17.4, 29.4, 30.8, 33.8, 40.4, 43, 47.2, 50.6, 51.6, 61.4, 62, 64.2, 68.2

The lower quartile, Q₁, is the (n + 1)/4 th term which is (16 +1)/4 = 4.25th term

However since we have an even set of numbers, we place a separator at the middle and we look for the median of the left half as follows

5.8, 9, 13.2, 17.4, 29.4, 30.8, 33.8, 40.4║ 43, 47.2, 50.6, 51.6, 61.4, 62, 64.2, 68.2

We have two numbers (17.4 + 29.4) at the median of the left set of numbers, we find the average of the two numbers to get the lower quartile

The lower quartile is therefore = (17.4 + 29.4)/2 = 23.4.

PLEASE HELP ME FAST...
I will mark you a BRAINLEST​

Answers

Answer: Hi!

Row A: 7, 11, 15, 19, 23

Row B: 51, 42, 33, 24, 15

Row C: 4, 8, 16, 32, 64

Row D: 64, 32, 16, 8, 4

(If you notice, Row C and Row D are just swapped in order!)

Hope this helps!

Hi there! Hopefully this helps!

--------------------------------------------------------------------------------------------------------------

A's rule, add 4: 7, 11, 15, 19, 23

B's rule, Subtract 9: 51, 42, 33, 24, 15

C's rule, Multiply by 2: 4, 8, 16, 32, 64

D's rule, Divide by 2: 64, 32, 16, 8, 4

the king needs a 10th graders help DX

Answers

Answer:

12) 1/8 inch =  0.125 inch

    = 0.003175 m

    = 3.175 x 10-3 m

    = 0.3175 cm

13) 2 is rational and  π  is  irrattional.  π   is approximately   3.14 and is the bigger of two

14) C= 40,005,306.33 m

  = 4.0005 x 107 m

15)  12,615,800,000

= 1.26158 x 1010

=126158 x 105

16) Let's take speed of ant as 1Km/h=1000m/h. Then time 1666.875 days

Step-by-step explanation:

Can someone please do this for me please

Answers

Answer:

r=-11

Step-by-step explanation:

7r+2=5(r-4)

7r+2=5r-20

2r=-22

r=-11

I hope it helps you!!have a good day

round 1.89 to one decimal place

Answers

Answer:

1.9

Step-by-step explanation:

You round when the numbers behind the decimal are 5 or greater. This being said, you need to round from the number furthest away from the decimal. In this case it would be 9. 9 is greater than 5 so we round 8 up to 9 and get rid of the number behind it. We are left with 1.9

For a ,a relationship to be a function, which values cannot repeat: the x-
values or the y-values? *

Answers

Answer:

              The  x - values

The y-values repeat in various functions (for example: quadratic function: y=x²; y=4 for x=2 and for x=-2)  

Complete the sequence
8,27,64,125,.........
Just next letter

Answers

Answer:

216.

Step-by-step explanation:

These numbers are perfect cubes starting with 2^3.

2^3, 3^3,  4^3,  5^3 so the next one is 6^3, which is 216.

Sammy and Hannah are finalists in a cooking competition. For the final round, each of them will randomly select a card without replacement that will reveal what their star ingredient must be. Here are the available cards:
Cabbage
Spinach
Kale
Leeks
Carrots
Turnips

Cabbage


Leeks




Spinach


Carrots




Kale


Turnips




Sammy and Hannah both want to get leeks as their star ingredient. Sammy will draw first, followed by Hannah.
What is the probability that NEITHER contestant draws leeks?
Round your answer to two decimal places.

Answers

The probability that neither of them draws the Leeks card is P = 4/6 = 0.667

Here we can assume that all the cards have the same probability of being randomly drawn.

The cards are:

Cabbage Spinach Kale Leeks Carrots Turnips

So we have 6 cards. We want to find the probability that neither contestant draws the "Leeks" card.

Sammy draws first, the probability of drawing the Leeks card will be equal to the quotient between the number of Leeks cards (one) and the total number of cards (6).

Then the probability of drawing the leeks card is p = 1/6

This means that the probability of NOT drawing the leeks card is:

q = 1 - 1/6 = 5/6.

Now draws Hanna, now there are 5 cards in the deck (because one was already drawn). With the same approach as before, the probability of drawing the Leeks card is p = 1/5, then the probability of NOT drawing the card is:

q = 1 - 1/5 = 4/5.

The joint probability (this is, the probability of both of these events to happen together) is just the product of the individual probabilities.

Then the probability that neither of them draws the Leeks card is:

P = (4/5)*(5/6) = 4/6 = 0.667

If you want to learn more about probability, you can read:

https://brainly.com/question/24349426

What if the following choices will simplify 7-5(3)^2
answers:
1)18
2)12
3)-38
4)None of the choices are correct

Answers

Answer:

-38

Step-by-step explanation:

7-5(3)^2

PEMDAS

Since there are no parentheses to execute

Exponents next

7-5(3)^2

7-5*9

Multiply and divide next

7 - 45

-38

What is the ratio DE of the length of to the length of BC?

Answers

Answer:

1:4

Step-by-step explanation:

so we are comparing the arc lengths to get the ratio of DE:BC

[tex] \beta \div 360 \times 2 \times \pi \times r[/tex]

to get arc length BC as

[tex] \beta \times \pi \times r \div 90[/tex]

and for DE as

[tex] \beta \times \pi \times r \div 360[/tex]

so divide DE by BC where beta pi r will cancel out. and you remain with 1/4 Wich will translate to 1:4

Donny has three times as many candy canes as Marc. Marc has thirty more candy canes than Bob. They have 500 candy canes altogether. How many candy canes does Donny have?

Answers

Answer:

318

Step-by-step explanation:

Bob=x

Marc=x+30

Donny=3(x+30)

x+x+30+3x+90=500

5x=500-120

5x=380

x=76

Bob has x = 76

Marc has x+30=106

Donny has 3*112=318

318+106+76=500

Y=-5x+30 x=10 what is the solution to the system of equations 1)(-20,10) 2)(10,-20) 3)(10,4) 4)(4,10)

Answers

Answer:

            2) (10, -20)

Step-by-step explanation:

y = - 5x + 30  and  x = 10  ⇒  y = -5•10 + 30 = -50 + 30 = -20

x = 10  and y = -20   ⇒  (10, -20)

Answer:

Its B. (10, –20)

Step-by-step explanation:

I just took the quiz on edge

Help me pls pls help me

Answers

Answer:

F. 1/2

Step-by-step explanation:

If the ratio of team assistants to players are 1/6 and there are 36 players that means that there are 6 team assistants. If we do the ratio of coaches to assistant that would be 3/6 or F. 1/2

Rick is driving to his uncle's house in Greensville, which is 120 miles from Rick's town. After covering x miles, Rick sees a sign stating that Greensville is 20 miles away. Which equation, when solved, will give the value of x?

Answers

Answer:

The equation which will give the value of x when solved is C. x + 20 = 120

x=100

Step-by-step explanation:

Total distance=120 miles

Distance covered=x miles

Distance remaining=20 miles

The equation is

Total distance=Distance covered + distance remaining

120 miles= x miles + 20 miles

120 miles - 20 miles = x miles

100 miles =x miles

Check:

Total distance=Distance covered + distance remaining

120 miles = 100 miles + 20 miles

120 miles =120 miles

The equation which will give the value of x when solved is C. x+20=120

Which set of integers are in the right order from least to greatest?

1-10], -3, 2,7
7, 1-10], -3,2
2, -3, 7, 1-10
-3, 2, 7, 1-10

Answers

Answer:

1-10, -3, 2, 7

im sorry if i give a wrong answer

(SAT Prep) Find the value of x

Answers

25°+x=45°+15°25°+x=60°x=60°-25°x=35°

I hope it will be helpful andplease mark this answer as brainlist

Answer:

55°

Step-by-step explanation:

It should be:

x - 25 = 45 - 15x = 30 + 25x = 55

Please answer this question now

Answers

Answer:

AB = 72°

Step-by-step explanation:

The inscribed angle ADC is half the measure of its intercepted arc, thus

56° = [tex]\frac{1}{2}[/tex] ( m ABC ) ← multiply both sides by 2

112° = ABC

ABC = AB + BC = AB + 40, so

AB + 40 = 112 ( subtract 40 from both sides )

AB = 72°

The perimeter of a square is numerically equals to its area. Find its side and area.

Answers

Answer:

4 and 16 units²

Step-by-step explanation:

The perimeter of a square of side s = 4s and area = s² , equating gives

s² = 4s ( subtract 4s from both sides )

s² - 4s = 0 ( factor out s from each term on the left )

s(s - 4) = 0

Equate each factor to zero and solve for s

s = 0

s - 4 = 0 ⇒ s = 4

However, s > 0, thus s= 4

That is side = 4 units and area = 4² = 16 units²

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