Factor this polynomial.
-3x²-5x-2

A. (-3x+2)(x+1)

B. (3x-2)(x-1)

C. (3x+2)(x-1)

D. -1(3x+2)(x+1)

Answer: 384 feet

Step-by-step explanation:

     We will simplify and solve -16t² + 160t when t is equal to 4.

-16t² + 160t

-16(4)² + 160(4)

384 feet

Answer:

Step-by-step explanation:

**Note: The polynomial in question is -16t² + 160t, as clarified in the discussion under the question.**

Since there is a polynomial to find the height given a certain time, the height is a function of time.

This function would be h(t) = -16t² + 160t, so plugging in 4 for t would give the height.

[tex]h(4) = -16(4)^2+160(4)[/tex]

[tex]-16(16)+160(4)[/tex] [Squaring 4]

[tex]-256 + 640[/tex] [Multiplying]

[tex]384[/tex] [Combining both terms]

Hence, the height of the firework after 4 seconds is 384 feet.

Answer:

the value of the variable x is 16

Step-by-step explanation:

[tex]given \: expression \\ \frac{5}{8}x = \frac{1}{2} x + 2 \\ substract \: \frac{1}{2} x from \: both \: sides \\ \frac{5}{8}x - \frac{1}{2} x = \frac{1}{2} x - \frac{1}{2} x + 2 - \frac{1}{2} x \\ factor \: out \: common \: x \\ x( \frac{5}{8} - \frac{1}{2} ) = \frac{1}{8} \\ simplify \\ \frac{1}{2} x + 2 - \frac{1}{2} x \: \frac{1}{2} x - \frac{1}{2} x = 0 = 2 \\ \frac{1}{8} x = 2 \\ multiply \: both \: sides \: by \: 8 \\ 8. \frac{1}{8} x = 2.8 \\ simplify \\ x = 16.[/tex]

Hello, the solution is in this photo.

The correct answer is 300

Answer:

300cm^2

Step-by-step explanation:

Replace pie by 3. 3(10)^2 which equals to 300cm^2. 10 is radius.

1) Difference of  the populations  of Germany and  Brazil = 1.16 X 10^8

2) Difference of  the populations  of Brazil and the  United States = 1.2 X 10^8

3) Sum of the  populations of  Brazil and  Germany = 2.76 X 10^8

4) Sum of the  populations of  the United States  and Brazil = 5.12 X 10^8

According to the statement

we have given that the populations of  three countries which are

United States is 3.16 × 10^8 and  Brazil is 1.96 × 10^8 and Germany is 8.0 × 10^7

And we have to arrange the sums and differences in increasing order of their values.

so, we have to find the

a) the difference of  the populations  of Germany and  Brazil

So,

Difference of  the populations  of Germany and  Brazil =  1.96 X 10^8 - 8 X 10^7 = 116000000 = 1.16 X 10^8

And then we have to find the

b) the sum of the  populations of  the United States  and Brazil

So,

Sum of the  populations of  the United States  and Brazil = 3.16 X 10^8 + 1.96 X 10^8 = 512000000 = 5.12 X 10^8

And then we have to find the

c) the difference of  the populations  of Brazil and the  United States

So,

Difference of  the populations  of Brazil and the  United States = 3.16 X 10^8 - 1.96 X 10^8 = 120000000 = 1.2 X 10^8

And then we have to find the

d) the sum of the  populations of  Brazil and  Germany

So,

Sum of the  populations of  Brazil and  Germany:  1.96 X 10^8 + 8 X 10^7 = 276000000 = 2.76 X 10^8

NOW, we arrange the sum and difference in increasing order of their values.

So,

1) Difference of  the populations  of Germany and  Brazil = 1.16 X 10^8

2) Difference of  the populations  of Brazil and the  United States = 1.2 X 10^8

3) Sum of the  populations of  Brazil and  Germany = 2.76 X 10^8

4) Sum of the  populations of  the United States  and Brazil = 5.12 X 10^8

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Let’s start by stating the formula for the area of a rectangle,

A=LW

the letter a represents area, l represents length, and w represents width.

Next let’s substitute known values.

A=x(x+10)

Next let’s use the distributive property

A=(x(x))+(10(x))

Now simplify.

A=x^2 + 10x

So the equation for the area of this rectangle is A=x^2+10x

I believe this is the most simplified answer, please tell me if I am wrong and I will redo my work.

The value of the t test is 13.36, we have to conclude that there is sufficient evidence that suggests that insurance adjustment was greater than $2400.

H0: u = 24000

H1: u > 24000

we have n = 84 homes

bar x = 27500

s = 2400

Next we have to find the test statistic

The formula for this is given as

[tex]t = \frac{x-u}{s/\sqrt{n} }[/tex]

When we out in the values we would have

[tex]t = \frac{27500-24000}{2400/\sqrt{84} }[/tex]

This would give us the answeer of the t test as

t test = 13. 3658

We have alpha = 0.02

the degree of freedom = 84 - 1 = 83

we have to find tα/2, df

=  ±2.0865

Given that the value of the test statistic is greater than critical value we would have to then reject the null hypothesis.

Hence the conclusion that we can make is that there is sufficient evidence that suggests that insurance adjustment was greater than $2400.

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Answer:

First function:

Zeros = 6 and -6. Y-intercept = (0,72). X-intercepts = (6,0) and (-6,0).

Second function:

Zeros = 3 and -3. Y-intercept = (0, -27). X-intercepts: (3, 0) and (-3, 0).

Step-by-step explanation:

The zeros are x-intercept numbers.

The y-intercept can be found when the function is in standard form. Plug in 0 for x, then solve.

Hope this helps!

Answer:

1. x₁ = 6, x₂ = -6

2. x₁ = 3, x₂ = -3

Step-by-step explanation:

Given functions:

[tex]1)\ f(x) = -2(x-6)(x+6)[/tex]

[tex]2)\ f(x)=(x-3)(3x+9)[/tex]

..................................................................................................................................................

Zero Product Property: If m • n = 0, then m = 0 or n = 0.

Standard Form of a Quadratic: ax² + bx + c = 0.

..................................................................................................................................................

1. f(x) = -2(x - 6)(x + 6)

Step 1: Set the function to zero.

[tex]\implies 0 = -2(x-6)(x+6)[/tex]

Step 2: Divide both sides of equation by [tex]-2[/tex].

[tex]\implies \dfrac{0}{-2} = \dfrac{-2(x-6)(x+6)}{-2}[/tex]

[tex]\implies 0=(x-6)(x+6)[/tex]

Step 3: Apply the Zero Product Property.

[tex]x_1 \implies x-6=0[/tex]

[tex]x_2 \implies x+6=0[/tex]

Step 4: Solve for x in both equations.

[tex]x-6+6=0+6 \implies \boxed{x_1 = 6}[/tex]

[tex]x+6-6=0-6 \implies \boxed{x_1 = -6}[/tex]

The zeros (x-intercepts) of this function are: [tex]x_1=6,\ x_2=-6[/tex].

.................................................................................................................................................

2. f(x) = (x - 3)(3x + 9)

Step 1: Set the function to zero.

[tex]\implies 0 = (x - 3)(3x + 9)[/tex]

Step 2: Apply the Zero Product Property.

[tex]x_1 \implies x-3=0[/tex]

[tex]x_2 \implies 3x + 9=0[/tex]

Step 3: Solve for x in both equations.

[tex]x-3+3=0+3 \implies \boxed{x_1 = 3}[/tex]

[tex]3x=-9 \implies \dfrac{3x}{3}=\dfrac{-9}{3} \implies \boxed{x_1 = -3}[/tex]

The zeros (x-intercepts) of this function are: [tex]x_1=3,\ x_2=-3[/tex].

..................................................................................................................................................

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P ( work/ senior ) = 0.14

The attached table

required

P ( work/ senior )

This is calculated using:

P ( work/ senior ) = n ( work/ senior )/ n ( senior ).

n ( work/ senior ) = 5

n ( senior ) = 25 + 5 + = 35

So:

P ( work/ senior ) = 5/35

P ( work/ senior ) = 0.14

Add 25+5+5 (because that is all the numbers in the 'Seniors' row) and then take the 5 that is in the 'Work' column and put that over 25. (5/25 fraction as a percent is 14).

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By the definition of inverse functions, we will get:

[tex]arcsin(-1) = -pi/2[/tex]

The function arcsin(x) is the inverse of the sine function, such that, if:

[tex]sin(x) = y\\\\arcsin(y) = x[/tex]

Now, we know that:

[tex]sin( -pi/2) = -1[/tex]

Where pi = 3.14

Then, using the above rule:

[tex]arcsin(-1) = -pi/2[/tex]

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The solutions are { -1,-11}

Lets solve the given equation:

x^2 + 11x + 121/4 = 125/4

Subtracting 125/4 from both sides:

=>x^2 + 11x + 121/4-125/4= 125/4 -125/4

=> x^2 + 11x - (-4/4) = 0

=> x^2 +11x -(-1) = 0

=>x^2 + 11 x + 1 = 0

This is a quadratic equation so we will use the determinant (b^2-4ac)

a = 1

b = 11

c = 1

b^2-4ac = 11^2-4*1*1 = 117

So this equation has two solutions:

x = (-b -/+ √(b^2-4ac) ) / 2a

x = (-11 -/+ √(117) ) / 2

x = (-11 -/+ 3√(13))/ 2

x = -0.91 or x = -10.9

x = -1 or x = -11 ( rounding off)

hence the solutions are { -1,-11}.

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The area of the paper that remains is 391.04 cm²

From the question, we are to calculate the area of the remaining part of the paper

Area of the paper that remains = Area of rectangle - 2×Area of semicircle

Area of the paper that remains = (l×w) - 2(πr²/2)

Area of the paper that remains = (l×w) - (πr²)

Where l is the length of the paper

w is the width if the paper

and r is the radius of the semicircle

From the given information,

l = 37 cm

w = 16 cm

r = w/2 = 16/2 = 8 cm

Putting the parameters into the equation,

Area of the paper that remains = (37×16) - (3.14(8)²)

Area of the paper that remains = 592 - (3.14×64)

Area of the paper that remains = 592 - 200.96

Area of the paper that remains = 391.04 cm²

Hence, the area of the paper that remains is 391.04 cm²

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Answer:

D. continuous

Hugh bough 4 books.

What is linear equation ?

The cost of magazines =

3.95(3) + 8.95b = 47.65

11.85 + 8.95b = 47.65

Subtract 11.85 from both sides.

8.95b = 35.8

Divide 8.95 from both sides.

b = 4

Therefore, Hugh bough 4 books.

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The complete question is -

Hugh bought some magazines that cost $3.95 each and some books that cost $8.95 each. He spent a total of $47.65. If Hugh bought 3 magazines, how many books did he buy? The equation that models the problem is 3.95m + 8.95b = 47.65, where m is the number of magazines and b is the number of books.

Pedro can sell enough by combining the sales of 40 plates of garlic shrimp and 80 dishes of spicy shrimp to reach his objective.

Near the shore, Pedro runs a shrimp delivery business.

He offers spicy shrimp for $6 a plate and garlic shrimp for $8 per plate.

Pedro wants to make at least $800 per day but only stocks enough shrimp to sell a maximum of 120 plates.

We need to ascertain,

Which dish combining hot shrimp and garlicky shrimp can Pedro sell to reach his objective?

In response to the query,

Let's sell the x dishes of garlic shrimp.

And plates of hot shrimp were sold.

Pedro has 120 dishes' worth of shrimp in stock each day.

Then,

Shrimp sold daily total is equal to the sum of plates of garlic shrimp and spicy shrimp.

                           X + Y = 120

Furthermore, He offers $6spicy and $8garlic shrimp, per plate.

To make at least $800 is what he wants to do.

Then,

the sum of the price of the spicy shrimp per plate and the price of the garlic shrimp per plate,

                             8X + 6Y = 800

When the two equations are solved,

                              X + Y = 120

                           8X + 6Y = 800

From equation 1,

                             Y = 120 - X

In equation 2, replace x with its value.

8X + 6Y = 800

8(120 - Y) + 6Y = 800

960 - 8Y + 6Y = 800

- 2Y = - 160

Y = 160/2

Y = 80

In equation 1, replace y with its value.

X + Y = 120

X + 80 = 120

X = 120 - 80

X = 40

In order to achieve his objective, Pedro sold a combination of 40 plates of garlic shrimp and 80 dishes of spicy shrimp.

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Answer:

Step-by-step explanation:

Make equations

8x+6y≥800

x+y≤120

Graph the system of equations and see which answer falls in the shaded area

Answer: 90 Garlic, 25 Spicy

Answer:

18 stamps of 13 cent

24 stamps of 18 cent

Step-by-step explanation:

we have to solve the following system:

x + y = 42              equation (1)

13x + 18y = 666     equation (2)

(1) ⇒ y = 42 - x

We substitute y by 42 - x in equation (2) :

13x + 18(42 - x) = 666

⇔ 13x + 756 - 18x = 666

⇔ -5x + 756 = 666

⇔ -5x = 666 - 756

⇔ -5x = -90

⇔ x = 18

…………………………

Then

y = 42 - x

  = 42 - 18

  = 24

Answer:

tan 33° = 0.6494

C = 65°

Step-by-step explanation:

Use a calculator.

tan 33° = 0.6494

cos C = 0.4226

Use the inverse cosine function on a calculator.

C = 65°

By this equation y = 1,716 - 112x he find that how much money he still owes after each month of the plan.

According to the statement

Jonathan bought a new computer for $1,716

He will pay $143 a month for 12 months.

Total amount he will for 12 months is 143(`12)

Now,

y = the money he still owes

x = the number of months (from x = 0 to x = 12)

y = 1,716 - 112x

So, By this equation y = 1,716 - 112x he find that how much money he still owes after each month of the plan.

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Answer:

80

Step-by-step explanation:

Answer:

80 balls

Step-by-step explanation:

Julie's brother's balls x 20 = Julie's balls

4 x 20 = 80

Brainliest, please :)

Step-by-step explanation:

vat of a cap=13/100*452

=58.76

price after vat=58.76+452=510.76

price after vat of 5 cap = 510.76*5=2553.8

Gradient = rise/ run

rise is d

run is the difference in our x coordinates of c & e

(or c - e)

So, it's d/C - e

(3rd option)

Hope this helps!

Answer:

3rd option

Step-by-step explanation:

calculate the slope m using the slope formula

m = [tex]\frac{y_{2}-y_{1} }{x_{2}-x_{1} }[/tex]

with (x₁, y₁ ) = E (e, 0 ) and (x₂, y₂ ) = (c, d )

m = [tex]\frac{d-0}{c-e}[/tex] = [tex]\frac{d}{c-e}[/tex]

Answer:

Yes

Step-by-step explanation:

As the Average speed increases, the amount of distance covered will increase. As the average speed decreases, the amount of distance traveled will decrease as well over a certain period.

The distance between the helicopter and the first home is 369. 87 m

The distance between the helicopter and the first home can be found using sine law,

Hence,

180 - 72 - 49 = 59 degrees.

Therefore,

420 / sin 59 = A / sin 49°

where

cross multiply

420 sin 49 = A sin 59°

A = 420 sin 49 / sin 59

A = 316.978023694 / 0.8571673007

A = 369.869339199

A = 369. 87 m

Therefore, the distance between the helicopter and the first home is 369. 87 m

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The ordered pairs from the options given that is from the table is: D. (6,5).

An ordered pair is written in the form, (x, y). The first number in the bracket is the x-value on the table, and the second number is its corresponding y-value form the table.

From the table given, the ordered pairs are: (3, 4), (4, 4), (5, 2), and (6, 5).

The number pair from the table from the given options is: D. (6,5).

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The answers to the quadrilateral are ONM, NOM, and alternate interior angles.

Based on the SSS postulate, the two triangles △MLO and △ONM are congruent since three sides of △MLO are respectively equal to the three sides of △ONM.

Based on CPCTC, all of the corresponding angles of △MLO and △ONM are congruent as well since the two triangles are congruent, that is,  

∠LMO≅∠NOM and ∠NMO≅∠LOM.

Since the pair ∠LMO and ∠NOM as well as ∠NMO and ∠LOM are angles on the inner side of two lines but on opposite sides of the transversal MO, these pairs of angles are also alternate interior angles.

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Answer:    ONM

                 NOM

                alternate interior angles

Step-by-step explanation:  Complete the paragraph proof.

We are given that MN ≅ LO and ML ≅ NO. We can draw in MO because between any two points is a line. By the reflexive property, MO ≅ MO. By SSS, △MLO ≅ △

✔ ONM

. By CPCTC, ∠LMO ≅ ∠

✔ NOM

and ∠NMO ≅ ∠LOM. Both pairs of angles are also

✔ alternate interior angles

, based on the definition. Based on the converse of the alternate interior angles theorem, MN ∥ LO and LM ∥ NO. Based on the definition of a parallelogram, MNOL is a parallelogram.

Using proportions to find the radius of figure 2, we have that:

A proportion is a fraction of a total amount, and the measures are related using a rule of three. Due to this, relations between variables, either direct or inverse proportional, can be built to find the desired measures in the problem.

The rule of three to find the radius of figure 2 is given as follows:

[tex]\frac{5}{9} = \frac{r}{4.5}[/tex]

Applying cross multiplication:

9r = 4 x 4.5

r = 4 x 4.5/9

r = 2 in

The circumference of a circle of radius r is given by:

[tex]C = 2\pi r[/tex]

In this problem, we have that r = 2 inches, hence:

[tex]C = 2\pi \times 2 = 4\pi[/tex]

The area of a circle of radius r is given by pi multiplied by the radius squared, as follows:

[tex]A = \pi r^2[/tex]

Hence:

[tex]A = 4\pi[/tex]

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Answer: First one is 5, Second is 6.25

Step-by-step explanation: Correct on Edmentum/Plato

The purpose of the coordinate graphing system described by Descartes in his book "Discourse on Method" is to use algebraic methods to solve geometric problems. That is option A.

The coordinate graphing system is used on graphical systems to describe the relationship or location between two points on different axes such as X and y axis.

According to Descartes in his book "Discourse on Method" he developed a connection between Algebra and geometry.

Therefore, the main purpose for the coordinate graphing system is to use algebraic methods to solve geometric problems.

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Answer:

The answer that you are looking for is A.

Have a great day!

Step-by-step explanation:

Please mark me brainliest!

The altitudes of equal length, BE and CF gives AB = AC, from which we have;

From the given description, we have;

BE = CF

<CFB = <BEC = 90° All right angles are congruent

BC = BC by reflexive property of congruency

BC = The hypotenuse side of triangles ∆BFC and ∆CEB

Therefore;

∆BFC is congruent to ∆CEB by Right angle Hypotenuse Side, RHS, rule of congruency.

Therefore;

BF = CE by Corresponding Parts of Congruent Triangles are Congruent, CPCTC

Similarly, we have;

∆AEB is congruent to ∆AFC, by Side-Angle-Angle, SAA, rule of congruency

Which gives;

FA = AE by CPCTC

BF + FA = CE + AE, by substitution property of equality

BF + FA = AB

CE + AE = AC

Therefore;

Therefore;

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Answer:

0.42

Step-by-step explanation:

The side LO is congruent to the side MN, the diagonal LN is congruent to the diagonal MO, and the angle L is congruent to the angle M in an isosceles trapezoid, denoted by the symbols LMNO.

What are the conditions for an Isosceles Trapezoid?

The conditions listed below demonstrate that any trapezoid is an isosceles trapezoid:

When these conditions are met by the given trapezoid LMNO, it will be referred to as an isosceles trapezoid. Hence, the following conditions of trapezoid LMNO need to be fulfilled,

LN ≅ MO

LO ≅ MN

∠L ≅ ∠M

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✔ (A.) LN ≅ MO

✔ (C.) LO ≅ MN

✔ (E.) ∠L ≅ ∠M