Find A ∩ B if A = {4, 7, 10, 13, 17} and B = {3, 5, 7, 9}. a.{3, 4, 5, 7, 9, 10, 13, 17} b.Ø c.{7}

Answer:

6 more

Step-by-step explanation:

Find 56% of 75 first

75/x=100/56

(75/x)*x=(100/56)*x      

75=1.78571428571*x      

(1.78571428571) to get x

75/1.78571428571=x

42=x

x=42

Then Find 80% of 60

60/x=100/80

(60/x)*x=(100/80)*x    

60=1.25*x      

60/1.25=x

48=x

x=48

Subtract 48 by 42

=6

Answer:

51

Step-by-step explanation:

=====================================================

The reference angle has AC = 12.3 as the opposite side and BC = 8.4 as the adjacent side. The tangent ratio ties the opposite and adjacent sides together.

--------

tan(angle) = opposite/adjacent

tan(theta) = AC/BC

tan(theta) = 12.3/8.4

theta = arctan(12.3/8.4)

theta = 55.6697828044967

theta = 55.7 degrees approximately

--------

arctan is the same as inverse tangent which is written as [tex]\tan^{-1}[/tex]

make sure your calculator is in degree mode

Answer:

3000 students

Step-by-step explanation:

If 48% of the students are female, and there are 1440 female students, we can set up a percentage proportion, assuming x is the total amount of students.

[tex]\frac{1440}{x} = \frac{48}{100}[/tex]

We can use the cross products property to find the value of x.

[tex]1440\cdot100=144000\\\\144000\div48=3000[/tex]

Hope this helped!

Let daughter be x years old. Then, Shyam is (x + 28) years old.

So,

x(x + 28) = 204

=> x² + 28x = 204

=> x² + 28x - 204 = 0

=> x² - 6x + 34x - 204 = 0

=> x(x-6) + 34(x-6)

=> (x - 6) (x + 34) = 0

=> x - 6 = 0 or x + 34 = 0

=> x = 6 or x = -34

Since any age cannot be negative, daughter's age is 6 years old.

Answer:

2n+2

Step-by-step explanation:

-n -3 + 3n +5

Combine like terms

-n +3n      -3 +5

2n             +2

Answer:

2n+2

Step-by-step explanation:

which of the following isthe√×51? answer is A .0-1

Answer:

C

Step-by-step explanation:

In the equation y = -x - 4, the gradient is -1.

While in the second equation,

5x + 5y = 20

y = -x + 4

So the gradient is -1 too

Both sides are not perpendicular to each other because if you apply the formula, m1m2 = -1, and if substitute both gradient, (-1)(-1) = 1 ≠ -1

Therefore, no they are not perpendicular but parallel instead.

Answer: C

Step-by-step explanation:

Look above fool

Answer:

answer is 7

Step-by-step explanation:

z-(3÷3-1)

make y = 3

z = 7

7 - (3÷3-1)

7 - 0

= 7

I hope it answers your question.

Answer: its 7

have a good day gang

Answer:

Answer to number 3:

Yes, because these two are similar triangles for sure so all their respective angles are equal in measure, and two pairs of sides are congruent to each other, so the third one must be congruent too.

Answer:

Parallel: AC and DB, BA and CD

Perpendicular: AC and CD, DB and CD, DB and BA, BA and AC

Neither: None

Step-by-step explanation:

Step 1: Find Slopes

Let's first find the slopes of each side of the rectangle, as that will helps us determine which sides are parallel, perpendicular, or neither.

Recall that the formula for finding the slope between two points is [tex]\frac{y_2 - y_1}{x_2-x_1}[/tex] where [tex](x_1, y_1)[/tex] and [tex](x_2,y_2)[/tex] are the coordinates of the two points. To avoid confusion, I will be taking the first point I list as [tex](x_1,y_1)[/tex] and the second point as [tex](x_2,y_2)[/tex].

Slope of [tex]BA[/tex]:

[tex]\frac{-7-(-3)}{-1-(-4)}\\=\frac{-7+3}{-1+4} \\= -\frac{4}{3}[/tex]

Slope of [tex]AC[/tex]:

[tex]\frac{-4-(-7)}{3-(-1)} \\=\frac{-4+7}{3+1} \\=\frac{3}{4}[/tex]

Slope of [tex]CD[/tex]:

[tex]\frac{0-(-4)}{0-3} \\=\frac{4}{-3} \\=-\frac{4}{3}[/tex]

Slope of [tex]DB[/tex]:

[tex]\frac{-3-0}{-4-0} \\=\frac{-3}{-4} \\=\frac{3}{4}[/tex]

Step 2: Determine which sides are parallel, perpendicular, or neither

Now that we found the slopes of the sides, we can determine which sides are parallel, perpendicular, or neither.

Recall that parallel lines have the same slope. [tex]\bf AC[/tex] and [tex]\bf DB[/tex], along with [tex]\bf BA[/tex]and [tex]\bf CD[/tex], have the same slope, so they are parallel. No other pair of sides has the same slope, so these are our only parallel pairs.

For two lines to be perpendicular, the product of their slopes must be [tex]-1[/tex]. [tex]\bf AC[/tex] and [tex]\bf CD[/tex], [tex]\bf DB[/tex] and [tex]\bf CD[/tex], [tex]\bf DB[/tex] and [tex]\bf BA[/tex], and [tex]\bf BA[/tex] and [tex]\bf AC[/tex] [tex]\bf[/tex]meet that criteria, so they are perpendicular. No other pair of sides meets the criteria, so these are our only perpendicular pairs. Hope this helps!

Answer:

x = 1

y = -1

Step-by-step explanation:

3x + 5y = -2

7x - 8y = 15

=> -8y = 15 - 7x

=> -y = 15/8 - 7/8x

=> y = -15/8 + 7/8x

3x + 5(-15/8 + 7/8x) = -2

=> 3x -75/8 + 35/8x = -2

=> 24/8x - 75/8 + 35/8x = -16/8

=> 59/8x - 75/8 = -16/8

=> 59/8x = 59/8

=> x = 59/8 x 8/59

=> x = 472/472

=> x = 1

x = 1

So, 3x + 5y = -2

=> 3 (1) + 5y = -2

=> 3 + 5y = -2

=> 5y = -5

=> y = -5/5

=> y = -1

So, x = 1

=>  y = -1

Answer:

soln

let one side be c

let another side be d

then

40=d(vertically opposite angle)

5a =c(vertically opposite angle)

again

c+90=180(being linear pair)

or, c=180-90

therefore, c=90

finally

let c be a

5a=5×90

=450

Answer:

a = 10

Step-by-step explanation:

CF is a straight line , so the 3 angles on it sum to 180° , then

∠ BOA = 180° - (90 + 40)° = 180° - 130° = 50°

∠ DOE = ∠ BOA ( vertical angles ) , then

5a = 50 ( divide both sides by 5 )

a = 10

Answer:

D

Step-by-step explanation:

x is greater than 12:

[tex]x>12 \text{ or } 12<x[/tex]

and x is less than or equal to 3 times the value of y:

[tex]12<x\leq 3y[/tex]

We can divide everything by 3:

[tex]4<\frac{x}{3} \leq y[/tex]

Answer:

3(6)

??

Step-by-step explanation:

Answer:

B

Step-by-step explanation:

If we count the number of points we find out that there are 36 employees

so the fraction must go like x/36

x is the numbers of dots that are less than a 1/2 which are 1/8, 1/4 and 3/8

so x=6

6/36

1/6

so option B

Answer:

[tex] (x+4)^2=4[/tex]

Step-by-step explanation:

[tex]x^2+8x+12=0\\

\implies (x^2+8x+16)+12=16\\

\implies (x+4)^2=16-12\\

\implies \boxed{(x+4)^2=4}[/tex]

Answer:

(x +4)^2 = 4

Step-by-step explanation:

if we add 4 to the expression x^2 + 8x + 12 we will have a perfect square which is shown as (x +4)^2

so (x +4)^2 = 4 is equivalent to the expression x^2 + 8x + 12

Answer:

because of its bark

Step-by-step explanation:

the answers have corresponding letters so answer the questions and put the letter next to the question above the answer

some of the answers are repeated

Answer: B) different y intercepts; same end behavior

=======================================================

Explanation:

The graph shows the y intercept is 4 as this is where the green curve crosses the vertical y axis.

The y intercept of g(x) is 6 which can be found by plugging x = 0 into the g(x) function

g(x) = 4(1/4)^x + 2

g(0) = 4(1/4)^0 + 2

g(0) = 6

So we can see the y intercepts are different.

----------

However, the end behaviors are the same for each function. The left side of f(x) goes up forever to positive infinity. The same is true for g(x). You could use a graphing calculator or a table to see this. As x heads to negative infinity, y goes to positive infinity.

In terms of symbols, [tex]x \to -\infty, y \to \infty[/tex]

----------

For the right side of f(x), it slowly approaches the horizontal asymptote y = 2. It never actually reaches this y value. The same happens with g(x). The portion 4(1/4)^x gets smaller but never gets to 0 so overall 4(1/4)^x+2 gets closer to 2. We can say that as x approaches infinity, y approaches 2.

In terms of symbols, [tex]x \to \infty, y \to 2[/tex]

Answer:

A- True

Step-by-step explanation:

If you search a picture of the graph then you will see it as well!!! Hope this helps!!!!

Answer:

100%+15% = 115%

proportionally:

x - 100%

161 - 115%

x = (161 * 100%) / 115% = 140

Answer:

[tex]\Large\boxed{140}[/tex]

Step-by-step explanation:

[tex]\sf Let \ x \ be \ the \ number.[/tex]

[tex]\sf x \ increased \ by \ 15\% \ is \ 161.[/tex]

[tex]x \times (1+15\%)=161[/tex]

[tex]x \times (1+0.15)=161[/tex]

[tex]x \times (1.15)=161[/tex]

[tex]\displaystyle \frac{x \times (1.15)}{1.15}=\frac{161}{1.15}[/tex]

[tex]x=140[/tex]

Answer:

262 pennies

Step-by-step explanation:

If Layla already has 388 pennies and she needs 600 pennies total, all she needs to do is is take the amount she already has away from 600:

Answer:

see below (I hope this makes sense!)

Step-by-step explanation:

Constants, as the name suggest, stay constant, meaning that their value never changes. For example, 2 will always be 2 and 9.4 will always be 9.4. On the other hand, the values of variables can change. Take, for example, the variable 2x. When x = 1, 2x = 2 and when x  =2, 2x = 4 so the value of 2x can change depending on what x is. You can't combine constants and variables because they are not like terms, basically, one can change and the other can't and you cannot combine terms that are not like each other.

Answer:

181.8yd

Step-by-step explanation:

Step-by-step explanation:

526 133 3821

P: 12345

j _o _I _n g _I _r l

o. n z-oo-o-m

Answer:

Step-by-step explanation:

Let (a, b) represent the coordinates of point Q on line x -2y -4 = 0. Then we know that ...

  a -2b -4 = 0

  a -2b = 4

__

If P is the midpoint of QR, then ...

  R = 2P -Q = 2(1, 1) -(a, b) = (2 -a, 2 -b)

We know this point satisfies the equation for the other line:

  x + y = 5

  (2 -a) +(2 -b) = 5

  a + b = -1 . . . . . . . . . . . rearrange to standard form

__

To find the solution to these two equations, we can subtract the first from the second:

  (a +b) -(a -2b) = (-1) -(4)

  3b = -5

  b = -5/3

  a = -1 -1b = -1 -(-5/3) = 2/3

The point Q is (a, b) = (2/3, -5/3).

The point R is ...

  R = (2 -a, 2 -b) = (2 -2/3, 2 -(-5/3)) = (4/3, 11/3)

The exact coordinates of Q and R are ...

  Q(2/3, -5/3), R(4/3, 11/3)

_____

Comment on the GeoGebra solution

The points can be found by reflecting either line across point P. Where that reflected line intersects the other line is one of the points of interest. Of course, the other is its reflection in P. You may recognize the equation for line b' (hidden in the diagram) as matching the second equation we derived above.

Answer:

57 units^2

Step-by-step explanation:

First find the area of the triangle on the left

ABC

It has a base AC which is  9 units and a height of 3 units

A = 1/2 bh = 1/2 ( 9) *3 = 27/2 = 13.5

Then find the area of the triangle on the right

DE

It has a base AC which is  6 units and a height of 1 units

A = 1/2 bh = 1/2 ( 6) *1  = 3

Then find the area of the triangle on the top

It has a base AC which is  3 units and a height of 3 units

A = 1/2 bh = 1/2 ( 3) *3  = 9/2 = 4.5

Then find the area of the rectangular region

A = lw = 6*6 = 36

Add them together

13.5+3+4.5+36 =57 units^2

Answer:

Total Area = 57 sq. units

Step-by-step explanation:

will make it simple and short

Total Area = A1 + A2 + A3

A1 = (7 + 6) * 6/2 = 39 sq. units  (area of a trapezoid)

A2 = 1/2 (9 * 3) = 13.5 sq. units (area of a triangle)

A3 = 1/2 (3 * 3) = 4.5 sq. units  (area of a triangle)

Total Area = 39 + 13.5 + 4.5 = 57 sq. units

Answer:

x < -6

Step-by-step explanation:

-2x - 4 > 8

-2x > 12

x < -6, you have to flip the inequality when you multiply or divide by a negative

Answer:

a

Step-by-step explanation:

[tex]f(g(h(x)))=f(g(\sqrt x))=f(\sqrt x-1)=\boxed{(\sqrt x-1)^4+4}[/tex]

This is because

[tex]h(x)=\sqrt x[/tex]

[tex]g(x)=x-1[/tex]

[tex]\implies g(h(x))=\sqrt x-1[/tex]

(that is, replace any instance of x in the definition of g with √x )

and

[tex]f(x)=x^4+4[/tex]

[tex]\implies f(\sqrt x-1)=(\sqrt x-1)^4+4[/tex]

(replace any x in f with √x - 1)

Also acceptable:

[tex](\sqrt x-1)^4+4=((\sqrt x)^4-4(\sqrt x)^3+6(\sqrt x)^2-4\sqrt x+1)+4[/tex]

[tex]=\boxed{x^2-4x\sqrt x+6x-4\sqrt x+5}[/tex]

(assuming x is not negative)