Find the area of the triangle ABC given A = 30°, b = 5, and c = 2 [tex]\frac{1}{2}[/tex]

[tex]\frac{1}{2}[/tex]
3[tex]\frac{1}{8}[/tex]
4[tex]\frac{1}{8}[/tex]
12[tex]\frac{1}{2}[/tex]

Answer:

32

Step-by-step explanation:

the country would need 30 to 33 trees

Answer:

the answer is 5×3+11×5 feet

Answer:

4th option

Step-by-step explanation:

An equilateral triangle has 3 congruent sides

Divide the perimeter by 3 for length of side

[tex]\frac{15x^3+33x^5}{3}[/tex]

= [tex]\frac{15x^3}{3}[/tex] + [tex]\frac{33x^5}{3}[/tex]

= 5x³ + 11[tex]x^{5}[/tex] ← length of 1 side

Answer:

Step-by-step explanation:

The rule that makes a relation NOT a function is if there are shared x values. This function has 2 points with the same x value:

(7, 4) and (7, 6). The sharing of these x-values (or the repeating of them) within the same relation makes this NOT a function. The last choice is the one you want. Just remember that a relation is only a function if there are no shared x-values. The y-values don't matter to this at all. A relation would be a function if it were made up of the following coordinates:

(1, 2), (2, 2), (3, 2), (4, 2), (5, 2), etc. Again, as long as the x-values don't repeat, the relation is a function.

Problem 2

Josh forgot to apply the square root to 16 when he went from [tex](x-3)^2 = 16[/tex] to [tex]x-3 = 16[/tex]

Also, he forgot about the plus/minus.

This is what his steps should look like

[tex]x^2 - 6x - 7 = 0\\\\x^2 - 6x = 7\\\\x^2 - 6x +9= 7+9\\\\(x-3)^2= 16\\\\x-3= \pm\sqrt{16}\\\\x-3= 4 \text{ or } x-3= -4\\\\x= 7 \text{ or } x= -1\\\\[/tex]

There are two solutions and they are x = 7 or x = -1. To check each solution, you plug it back into the original equation

Let's try out x = 7

x^2 - 6x - 7 = 0

7^2 - 6(7) - 7 = 0

49 - 42 - 7 = 0

0 = 0 ... solution x = 7 is confirmed. I'll let you check x = -1

====================================================

Problem 3

We will have

a = 1, b = -4, c = 3

plugged into the quadratic formula below to get...

[tex]x = \frac{-b\pm\sqrt{b^2-4ac}}{2a}\\\\x = \frac{-(-4)\pm\sqrt{(-4)^2-4(1)(3)}}{2(1)}\\\\x = \frac{4\pm\sqrt{4}}{2}\\\\x = \frac{4\pm2}{2}\\\\x = \frac{4+2}{2} \ \text{ or } \ x = \frac{4-2}{2}\\\\x = \frac{6}{2} \ \text{ or } \ x = \frac{2}{2}\\\\x = 3 \ \text{ or } \ x = 1\\\\[/tex]

The two solutions are x = 3 or x = 1. You would check this by plugging x = 3 back into the original expression x^2 - 4x + 3. The result should be zero. The same applies to x = 1 as well.

Hello!

Answer:

[tex]\huge\boxed{V = 60 m^{3}}[/tex]

Formula for the volume of a triangular pyramid:

V = 1/3(bh)

The base is a triangle, so b = 1/2(b · h)

Solve for the base:

b = 1/2(8 · 5)

b = 1/2(40)

b = 20 m²

Solve for the volume:

V = 1/3(20 · 9)

V = 1/3(180)

V = 60 m³.

Hope this helped you!

Answer:

60 cubic meters

Step-by-step explanation:

I used the formula V = 1/3 AH to figure it out

Answer:

WY= 25

XY= 23

VZ=36

so,

WY/XY = YZ/VZ

25/23 = YZ/25 (then do cross multiply)

25×25 = 23 × YZ

625= 23 × YZ

625/23= YZ

27,17= YZ

#i'm indonesian

#hope it helps.

Answer:

[tex]\huge \boxed{13.04}[/tex]

Step-by-step explanation:

The triangles are congruent, we can use ratios to solve.

WY/XY = (WY+YZ)/VZ

Let the length of YZ be x.

25/23 = (25+x)/35

Cross multiply.

23(25+x) = 25 × 35

575 + 23x = 875

Subtract 575 from both sides.

575 + 23x - 575 = 875 - 575

23x = 300

Divide both sides by 23.

(23x)/23 = 300/23

x = 13.0434782609...

Answer:

--1-- (of set 23456)

2   4

5 3

 6

--2-- (of set 23456)

2   3

5 4

 6

--3-- (of set 23456)

2   5

6 3

 4

--4-- (of set 23456)

2   3

6 5

 4

--5-- (of set 23456)

3   5

4 2

 6

--6-- (of set 23456)

3   2

4 5

 6

--7-- (of set 23456)

3   6

5 2

 4

--8-- (of set 23456)

3   2

5 6

 4

--9-- (of set 23456)

3   5

6 4

 2

--10-- (of set 23456)

3   4

6 5

 2

--11-- (of set 23456)

4   5

3 2

 6

--12-- (of set 23456)

4   2

3 5

 6

--13-- (of set 23456)

4   6

5 3

 2

--14-- (of set 23456)

4   3

5 6

 2

--15-- (of set 23456)

5   4

2 3

 6

--16-- (of set 23456)

5   3

2 4

 6

--17-- (of set 23456)

5   6

3 2

 4

--18-- (of set 23456)

5   2

3 6

 4

--19-- (of set 23456)

5   6

4 3

 2

--20-- (of set 23456)

5   3

4 6

 2

--21-- (of set 23456)

6   5

2 3

 4

--22-- (of set 23456)

6   3

2 5

 4

--23-- (of set 23456)

6   5

3 4

 2

--24-- (of set 23456)

6   4

3 5

 2

--1-- (of set 34567)

3   5

6 4

 7

--2-- (of set 34567)

3   4

6 5

 7

--3-- (of set 34567)

3   6

7 4

 5

--4-- (of set 34567)

3   4

7 6

 5

--5-- (of set 34567)

4   6

5 3

 7

--6-- (of set 34567)

4   3

5 6

 7

--7-- (of set 34567)

4   7

6 3

 5

--8-- (of set 34567)

4   3

6 7

 5

--9-- (of set 34567)

4   6

7 5

 3

--10-- (of set 34567)

4   5

7 6

 3

--11-- (of set 34567)

5   6

4 3

 7

--12-- (of set 34567)

5   3

4 6

 7

--13-- (of set 34567)

5   7

6 4

 3

--14-- (of set 34567)

5   4

6 7

 3

--15-- (of set 34567)

6   5

3 4

 7

--16-- (of set 34567)

6   4

3 5

 7

--17-- (of set 34567)

6   7

4 3

 5

--18-- (of set 34567)

6   3

4 7

 5

--19-- (of set 34567)

6   7

5 4

 3

--20-- (of set 34567)

6   4

5 7

 3

--21-- (of set 34567)

7   6

3 4

 5

--22-- (of set 34567)

7   4

3 6

 5

--23-- (of set 34567)

7   6

4 5

 3

--24-- (of set 34567)

7   5

4 6

 3

Step-by-step explanation:

This javascript code is extremely brute-force, but it does the job:

function checkIfInSet(i, set) {

   return i.toString().split('').sort().join('') === set;

}

function checkIfMagic(s) {

   return (parseInt(s[0]) + parseInt(s[1]) == parseInt(s[3]) + parseInt(s[4]))

}

function printMagic(s) {

   console.log(`${s[0]}   ${s[4]}`);

   console.log(` ${s[1]} ${s[3]}`);

   console.log(`  ${s[2]}\n`);

}

function checkSet(set) {

   let counter = 1;

   for(let i=1; i<99999; i++) {

       if (checkIfInSet(i, set) && checkIfMagic(i.toString())) {

           console.log(`--${counter++}-- (of set ${set})`);

           printMagic(i.toString());

       }

   }

}

checkSet('23456');

checkSet('34567');

Answer:

see explanation

Step-by-step explanation:

Since (k, 3) lies on each of the lines, the point satisfies the equations.

Substitute x = k, y = 3 into each and solve for k

y = 3x + 1

3 = 3k + 1 ( subtract 1 from both sides )

2 = 3k ( divide both sides by 3 )

k = [tex]\frac{2}{3}[/tex]

-------------------------------------------------------

y = 4x - 2

3 = 4k - 2 ( add 2 to both sides )

5 = 4k ( divide both sides by 4 )

k = [tex]\frac{5}{4}[/tex]

--------------------------------------------------------

y = [tex]\frac{1}{2}[/tex] x

3 = [tex]\frac{1}{2}[/tex] k ( multiply both sides by 2 to clear the fraction )

k = 6

---------------------------------------------------------

2x + 3y = 4

2k + 3(3) = 4

2k + 9 = 4 ( subtract 9 from both sides )

2k = - 5 ( divide both sides by 2 )

k = - [tex]\frac{5}{2}[/tex]

Answer:

a union b= {1,2,3,4,5}

a intersection b ={2,3}

Step-by-step explanation:

The union of two sets A and B is a set that contains all the elements of A and B and is denoted by A U B

the set composed of all elements that belong to both A and B is A intersection B (A ∩ B)

Answer:

140

Step-by-step explanation:

Lowest common denominator 4 , 7 ,5 , 2  and 1

= 4 * 7 * 5

= 140

Answer:

1

Step-by-step explanation:

Since usually common denominator is usually used with fractions (in this case), we can find out it's one because of how no numbers (except for 2 and 4) go into each other without a remainder except for one, so one would be the correct answer

Answer:

18 inches by 36 inches.

Step-by-step explanation:

Since we have given that

The generic version was basedOn the brand name and was 2/3

And given Dimensions of generic version is given by 12inches ×24inches

If we use the first dimensions of 12inches we have

12=2/3 × brand

12×3/2 = brand

=18inches= brand

we use the first dimensions of 24 inches we have

24=2/3 × brand

24×3/2 = brand

=36 inches= brand

brand= 36 inches

Therefore,the dimensions of brand name will be 18 inches by 36 inches.

Answer:

a. The coordinates of the first train are (-12,6).  The coordinates of the second train are (20,35).

b. The slope of the line for the first train is [tex]-\frac{1}{2}[/tex].  The slope is neither horizontal or vertical.  It slopes diagonally downward from left to write since the slope is negative.  In slope-interdept form, it is written as [tex]y=-\frac{1}{2} x[/tex].  In standard form, it is written as [tex]x+2y=0[/tex].   The slope of the line for the second train is [tex]\frac{7}{4}[/tex].  The slope is neither vertical or horizontal.  It slopes diagonally upward from left to right since the slope is positive.  In slope-intercept form, it is written as [tex]y=\frac{7}{4}x[/tex].  In standard form, it is written as [tex]-7x+4y=0[/tex].

c. The equarion of a line in slope-intercept form of the new track would be [tex]y=-\frac{1}{2} x+2[/tex].

Step-by-step explanation:

a.  The way to find the coordinates is either to picture a coordinate grid in your head or to have one out in front of you for a visual.  The first train travels 12 miles west, or 12 units to the left (-12), and 6 miles north, or 6 units up (6).  On a coordinate plane, that would be marked as (-12,6).  The second train travels 20 miles east, or 20 units to the right (20), and 35 miles north, or 35 units up (35).  On a coordinate plane that would be marked as (20,35).  This means that the coordinates of the first train would be (-12,6), and the coordinates of there second train would be (20,35).

b. The way to find slope is to find [tex]\frac{delta "x"}{delta "y"}[/tex].  "Delta" means "the change in".  The equation would be [tex]m=\frac{y_{2}-y_{1} }{x_{2}-x_{1} }[/tex].  So, let's find the slope of the first train's travel path.  We'll use the origin, (0,0), and the stopping point, (-12,6), as our coordinates to find the slope.  [tex]\frac{0-6}{0-(-12)}=\frac{0-6}{0+12}=\frac{-6}{12}=\frac{-1}{2}=-\frac{1}{2}[/tex].  That makes the slope of the first train's travel path to be (-1/2).  Now, let's find the slope of the second train's travel path.  We'll use the origin, (0,0), and the stopping point, (20,35), as our coordinates to find the slope.  [tex]\frac{0-35}{0-20}=\frac{-35}{-20}=\frac{35}{20}=\frac{7}{4}[/tex].  That makes the slope of the second train's travel path to be (7/4).  They want to know the equation of the travel path line in slope-intercept form and in standard form, and what the line looks like.  To start off, any vertical line would be undefined, and that would be if the slope was a fraction with a denominator of zero, which doesn't occur for either train path.  A horizontal line  would be if the slope was zero itself and the trains were not moving, but the trains are moving, so that's not possible either.  The way to determine theway a slope is diagonally is to look at whether the slope is positive or negative.  The first train's path slopes negatively, so it moves diagonally downward from left to right, or diagonally upward from right to left (both the same thing).  The second train's path slopes positively, so it moves diagonally upward from left to right, or diagonally downward from right to left.  Finally, the equations for this part of the question.  For both trains, the origin is the y-intercept, so the y-intercept does not have to be written in the slope-intercept equation.  The slope-intercept form of an equation of a line is [tex]y=mx+b[/tex] where "m" is the slope and "b" is the y-intercept.  The "b" value is 0, so that will not be written.  The slope for the first train is (-1/2), so the slope-intercept form of the first train's travel path is y=(-1/2)x.  The slope of the second train is (7/4), so the slope-intercept form for this train's path is y=(7/4)x.  As for standard form, subtract the "mx" value from both sides, and set the equation equal to 0. Also, get rid of any fractions. So, for the first train, standard form would be x+2y=0.  And for the second train, standard form would be -7x+4y=0.

c.  Parallel means having the same slope but a different y-intercept.  The second train station would be placed two miles north, or two units up, from the first train station.  The first train station is at (0,0), so the second train station would be placed at (0,2).  That makes 2 the y-intercept for if the first train had taken the second train station's travel route.  The slope for the intitial route was (-1/2), so that will stay the same.  Therefore, the equation of thr route taken if the first train had come out of the second train station, if it was already built, would be y=(-1/2x)+2.

Answer:

y= -13x+77

Step-by-step explanation:

Parallel lines do not share any points but have the same slope.

First, put the equation y-5=-13(x+2) into slope-intercept form.

y= -13x-21

Slope= -13x

Y-Intercept= (0,-21)

Now that we know the slope...

y-(-1)=-13(x-6)

becomes

y+1=-13x+78

y-1=-13x+78-1

y=-13x+77

Answer:

Hello,

answer 22

Step-by-step explanation:

[tex]\dfrac{1}{j} +\dfrac{1}{k} =\dfrac{1}{3} \\\\\dfrac{k+j}{j*k} =\dfrac{1}{3} \\\\\\3k+3j=j*k\\\\k(3-j)=-3j\\\\k=\dfrac{3j}{j-3} \\\\k=\dfrac{3j-9+9}{j-3} \\\\k=3+\dfrac{9}{j-3} \\\\\\j-3\ must\ be \ a divisor\ of\ 9 ==> 1,3,9\\\\j-3=1 ==> j=4 , k=3+\dfrac{9}{1} =12\\\\j-3=3 ==> j=6 , k=3+\dfrac{9}{3} =6\\\\j-3=9 ==> j=12 , k=3+\dfrac{9}{9} =4\\\\\sum\ k=12+6+4=22\\[/tex]

The sum of all possible values for k is 22.

The fractional bar is a horizontal bar that divides the numerator and denominator of every fraction into these two halves.

Given:

1/j + 1/k= 1/3

Simplifying the fraction

(k+ j)/ kj= 1/3

3k + 3j = kj

k(3- j) = -3j

k = -3j/ (3- j)

k= 3j/ (j-3)

k = 3j + 9 - 9 / (j-3)

k = 3 + 9/ (j-3)

Since (j-3) must be divisor of 9.

j- 3 = 1---> j=4, k= 3 +9 = 12

j- 3 = 3---> j=6, k= 3 +9/3 = 6

j- 3 = 9---> j=12, k= 3 +9/9 = 4

So, The sum is = 12+ 6 + 4 = 22

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Answer:

The latest time Ruth's family can start their tour in order to make it to dinner on time is 2:50 P.M

Step-by-step

Change:

7h10= 430 mins

1 hour and 25 minutes= 85 mins

2 hours and 5 mintues= 125 mins

- Total time Ruth wants to do before his dinner reservations:

85+ 125+ 50= 260 (mins)

- The latest time Ruth's family can start their tour in order to make it to dinner on time:

430- 260= 170 (mins)

Change: 170 mins= 2 hours and 50 minutes

Good luck!

The missing probability P(A∪B) will be 37/50.

Probability refers to a possibility that deals with the occurrence of random events.

The probability of all the events occurring need to be 1.

Given information;

P(A)= 7/20,

P(B)=3/5,

P(A∩B) =21/100 ,

We need to find the missing probability P(A∪B).

We know that

P(A∪B)= P(A) + P(B) + P(A∩B)

P(A∪B) = 7/20 + 3/5 + 21/100

P (A U B) = 37/50

Therefore, the missing probability P(A∪B) will be 37/50.

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Answer:

-8x + 12

Step-by-step explanation:

Distribute -4 to the parentheses:

-4(2x - 3)

-4(2x) = -8x

-4(-3) = 12

-8x + 12

Answer:

-8x +12

Step-by-step explanation:

-4(2x-3)

Distribute

-4* 2x -4 *-3

-8x +12

Answer:

8/10

Step-by-step explanation:

10x10 is 100 8x10 would be 80 so 80/100=8/10

Answer:

8/10 = 4/5

Step-by-step explanation:

0.8 is 8-10th which means 8 divided by 10

reducing 8/10 to its lowest term since 8 and 10 has 2 as common factor, then

(8=2*4)/(10=2*5)

if 2 cancels out, then you are left with 4/5

Answer:

-3 or -1 is a valid value for x

Step-by-step explanation:

We start by cross multiplying;

So the expression becomes;

x^2 + 5x + 6 = 1(x + 3)

x^2 + 5x + 6 = x + 3

x^2 + 5x -x + 6-3 = 0

x^2 + 4x + 3 = 0

x^2 + x + 3x + 3 = 0

x(x + 1) + 3(x + 1) = 0

(x + 3)(x + 1) = 0

x + 3 = 0 or x + 1 = 0

x = -3 or x = -1

Answer:  [tex](x-3)^2 + (y-2)^2 = 16[/tex]

Explanation:

The center of this circle is point A(3,2). These coordinates are the (h,k) values.

The radius is r = 4

Plug those three items into the template [tex](x-h)^2 + (y-k)^2 = r^2[/tex] to arrive at the final answer shown above.

Answer:

C

Step-by-step explanation:

Games lost=Games won - 4

Games lost=46-4=42

Answer:

C

Step-by-step explanation:

Answer:

B

Step-by-step explanation:

The lower quartile range is shown by the bottom of the box which is at 10.

The median is shown in the middle line, which is closer to 18 than 18.5.

The upper quartile range in the end of the box, which is at 22!

(You can also look at the picture attached if that helps.)

Answer:

A

Step-by-step explanation:

[tex] \frac{2003}{n} = z + \frac{23}{n} [/tex]

where z is an integer

[tex]2003 = nz + 23[/tex]

[tex]nz = 1980[/tex]

[tex]nz = {2}^{2} \times {3}^{2} \times 5 \times 11[/tex]

possible values of n

n= {1980, 990, 660, 495, 396, 330, 198, 180, 165, 132, 99, 90, 60, 45, 36, 30, 20, 18, 15, 5, 3}

cardinality of n=21

Answer:

a = x

b = 5

Step-by-step explanation:

for the polynomial x² + 10x + 25, b = 5 and a = x.

In the polynomial x² + 10x + 25, we can observe that the first term, x², is the square of x, and the last term, 25, is the square of 5. This suggests that the polynomial follows the perfect square trinomial identity.

The middle term, 10x, can be rewritten as 2ab, where a represents x and b represents a term that when squared equals the last term, 25.

In this case, b = 5, because 5² = 25.

To find a, we can take the square root of the first term, x². The square root of x² is x, so a = x.

Therefore, for the polynomial x² + 10x + 25, b = 5 and a = x.

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The coordinates of the foot of the perpendicular drawn from the point (6, 3) to the line by segment joining (4,1) and (8,3). is (6.4, 2.2)

What is an equation?

An equation is an expression that shows the relationship between two or more numbers and variables.

The equation of the line passing through (4,1) and (8,3) is:

y - 1 = [(3 - 1)/(8 - 4)](x - 4)

y = 0.5x - 1

The line perpendicular to y = 0.5x - 1 has a slope of -2. It passes the point (6, 3), hence:

y - 3 = -2(x - 6)

y = -2x + 15

The line y = 0.5x - 1 and y = -2x + 15 intersect at point (6.4, 2.2)

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Answer:

4x(x - 1)

Step-by-step explanation:

Factor the numerator and denominator

64[tex]x^{5}[/tex] - 64x ← factor out 64x from both terms

= 64x([tex]x^{4}[/tex] - 1) ← difference of squares

= 64x(x² - 1)(x² + 1) ← x² - 1 is also a difference of squares

= 64x(x - 1)(x + 1)(x² + 1)

---------------------------------

(8x² + 8)(2x + 2) ← factor out 8 and 2 from each factor

= 8(x² + 1) × 2(x + 1)

= 16(x² + 1)(x + 1)

Then expression can be written as

[tex]\frac{64x(x-1)(x+1)(x^2+1)}{16(x^2+1)(x+1)}[/tex] ← cancel (x² + 1) and (x + 1) on numerator/ denominator

= [tex]\frac{64x(x-1)}{16}[/tex] ← cancel common factor 16 on numerator/ denominator

= 4x(x - 1)

Answer:

A

Step-by-step explanation:

f(x) = x+4 when x is equal to or less than - 2. f(-4)=0

Answer:

61

Step-by-step explanation:

to calculate the 20th term you use the formula

Tn=a+(n-1)d where a stands for the first term,n the number of terms and d the common difference.in this case the first term is 4 the common difference is 3 cause they were adding 3 to go to the next term.. therefore the solution will be:

Tn=4+(20-1)3

=4+19×3

=4+57

=61

the 20th term is 61

I hope this helps

Answer:

WX=10; VW=22; WY=20; VX=32; WZ=30;VY=42

Step-by-step explanation:

1)WX=XY=XZ/2=20/2=10

2)VW=VZ-WX-XY-YZ=VZ-3*WX=52-3*10=52-30=22

3)WY=WX+XY=2*WX=2*10=20

4)VX=VW+WX=22+10=32

5)WZ=WX+XY+YZ=3*WX=3*10=30

6)VY=VZ-YZ=52-10=42

The points V, W, X, Y and Z are collinear. The indicated lengths are

[tex]WX=10\\VW=22\\WY=20\\VX=32\\WZ=30\\VY=42[/tex]

Given :

points V, W, X, Y and Z are collinear, VZ= 52, XZ =20, and WX=XY=YZ

Lets make diagram using the given information

The diagram is attached below

XY=YZ

XZ=20, so [tex]XY+YZ=20\\Both XY and YZ are same\\XY+XY=20\\2XY=20\\Divide \; by \; 2\\XY=10[/tex]

[tex]WX=XY=YZ \\XY=10\\WY=10\\YZ=10\\[/tex]

Now we find out VW

[tex]VW+WX+XY+YZ=52\\VW+10+10+10=52\\VW+30=52\\Subtract \; 30\\VW=52-30\\VW=22[/tex]

Now we find the indicated length

[tex]WX =10[/tex]

[tex]VW=22\\WY=WX+XY=10+10=20\\VX=VW+WX=22+10=32\\WZ=WX+XY+YZ=10+10+10=30\\VY=VW+WX+XY=22+10+10=42[/tex]

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